On the TIFF point -- are you using 2.7.1 patched? It is likely that the
crash is fixed there (it was intermittent and some of us never see it).
Otherwise you have not described what is 'substandard' nor given any
examples, and others are not reporting such differences. (I do have XP
and
On Thu, 31 Jul 2008, milton ruser wrote:
Dear all,
Is there a way of I deal with more than one kind of separators
when reading a asc file using scan() function?
The separators could be :, \t and ;.
Yes, pre-process the file (e.g. use a pipe connection and 'tr', or read
the file with
Hello Jason,
You are not specific enough. What do you mean by significant difference?
Let's assume that indeed the incidence in A is 6% and in B is 10% and we are
looking for Na and Nb such that with probability of at least 80% the mean of Nb
sample from B will be at least, say, 0.03 (=3%)
Hi,
How can I join two string?
frequency = 15
I want join the number frequency with a string.
Alfredo
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Is this what you want:
paste(Mystring, frequency, sep=)
---
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Alfredo Alessandrini
Sent: 31 July 2008 10:11
To: r-help@r-project.org
Subject: [R] add string
Hi,
How can I join two string?
frequency =
thanks, that workaround, well, works!
what are you working on with the rewrite? just efficiency? or major
changes in functionality/interface?
thanks,
mike
On Wed, Jul 30, 2008 at 7:10 PM, hadley wickham [EMAIL PROTECTED] wrote:
On Wed, Jul 30, 2008 at 12:41 PM, mfrumin [EMAIL PROTECTED]
The Ohri Framework - Data Mining on
Demandhttp://decisionstats.com/2008/the-ohri-framework-data-mining-on-demand/
Part of the reason SAS continues to enjoy a profitable lead is
1) Standardized language elements (Data and Procs)
2)Ease of Learning SAS
3) Output Delivery to multiple sources
4)
Dear all,
Is there a way to compute and list all combinations with replication of two
elements in sets of 8 elemnts?
For example, I've two elements, 0 and 1, and I would to get all possible
combinations with replication such as, for example, , 0001,
0010, and so on. They are 2^8
Hi everybody,
I have built a model that includes subject ID as a random effect, and has a
continous variable (time) and I want to test whether the slope of this line
differs between treatments (this is tested with the interaction between
treatment and time).
My question now is that I also want
For example, c(dog.is.an.animal, cat.is.an.animal, rat.is.an.animal). How
can I identify the common prefix is .is.an.animal and delete it to give
c(dog, cat, rat) ?
Thanks
_
[[alternative HTML version deleted]]
On Thu, 2008-07-31 at 02:29 -0700, MarinaTarantini wrote:
Dear all,
Is there a way to compute and list all combinations with replication of two
elements in sets of 8 elemnts?
For example, I've two elements, 0 and 1, and I would to get all possible
combinations with replication such as, for
Or simply
Datagrid - expand.grid(rep(list(0:1), 8))
apply(Datagrid, 1, paste, collapse = )
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel
The following warning message occurs when running the nls on some data:
~
Warning message:
In is.na(wts) : is.na() applied to non-(list or vector) of type 'NULL'
~
and I would like to know what is
On Wed, 2008-07-30 at 12:13 -0500, Marc Schwartz wrote:
on 07/30/2008 08:48 AM Wim Bertels wrote:
Hi,
does anyone know of a function to calculate odds ratios in multiway
tables (stratified) (+ the other usual statistics involved)
i mean:
say we have a table r*c*d,
For every d
On Thu, Jul 31, 2008 at 4:59 AM, Michael Frumin [EMAIL PROTECTED] wrote:
thanks, that workaround, well, works!
what are you working on with the rewrite? just efficiency? or major
changes in functionality/interface?
I've come up with a strategy that makes reshape _much_ faster - 10-20x
for
Thank you very much.
Would you talk more about that? How can I use the copula package to sample two
dependent exponentials? Which function shall I use?
Sincerely,
Yanwei Zhang
Department of Actuarial Research and Modeling
Munich Re America
Tel: 609-275-2176
Email: [EMAIL PROTECTED]
On Thu, 31 Jul 2008, Lisa Readdy wrote:
The following warning message occurs when running the nls on some data:
~
Warning message:
In is.na(wts) : is.na() applied to non-(list or vector) of type 'NULL'
sounds great. there are often times I'd like to use reshape on data frames
of hundreds of thousands or millions of rows, but I have found that it is
just too slow at this point to be convenient.
thanks again for everything,
Mike
hadley wrote:
On Thu, Jul 31, 2008 at 4:59 AM, Michael
At the risk of oversimplifying the study design, this sounds like a two
sample comparison of proportions, in which case power.prop.test() would
be the function of interest. This could also be done via Monte Carlo
simulation, which would not be difficult to implement.
Note that I am also
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Zhang Yanwei - Princeton-MRAm wrote:
| Thank you very much.
| Would you talk more about that? How can I use the copula package
to sample two dependent exponentials? Which function shall I use?
|
~ It's a big topic, and I'm not very familiar with
For example, c(dog.is.an.animal, cat.is.an.animal, rat.is.an.
animal). How can I identify the common prefix is .is.an.animal
and delete it to give c(dog, cat, rat) ?
foo - c(dog.is.an.animal, cat.is.an.animal, rat.is.an.animal)
sub(.is.an.animal, , foo)
Being pedantic, .is.an.animal is a
Somewhat coincidentally this will work if you don't supply 'data=Data'.
On Thu, 31 Jul 2008, Prof Brian Ripley wrote:
On Thu, 31 Jul 2008, Lisa Readdy wrote:
The following warning message occurs when running the nls on some data:
~
Warning
Not a direct answer to your questions, but for error-in-variables
problems, there are newer technologies than what is in NR. For example:
install.packages(simex)
library(simex)
example(simex)
Andy
From: Marc Fischer
Dear Folks,
We need to fit the model y~x assuming there are random
naw3 at duke.edu writes:
Hi,
I am reading in a CSV file of chemical reactions where the subscripts and
superscripts are encoded in angle brackets, like below:
2 HSUP+/SUP + 2 OSUB2/SUBSUP-/SUP
Is there a way to convert these to actual sub/superscripts and save them in
another excel
Hi all,
Suppose I have the following points:
x
[1] 1.376545e+00 1.017594e+00 6.734179e+00 2.537501e+00 9.614635e-02
[6] 7.078693e-03 4.067031e-02 1.527854e+00 6.795155e-03 6.247076e-04
[11] 1.934793e-06 1.442637e-02 8.432116e-02 1.126674e-03 6.476260e+00
[16] 1.472769e-01 2.247548e+00
Frank and all,
The point you were looking for was in a page that was linked from the
referenced page - I apologize for confusion. Please take a look at the
two last paragraphs here:
http://people.revoledu.com/kardi/tutorial/Bootstrap/examples.htm
Though, possibly it's my ignorance, maybe
On 7/30/08 1:59 PM, Marc Schwartz [EMAIL PROTECTED] wrote:
I (and many others) use ESS (Emacs Speaks Statistics), in which case, I
have an R source buffer in the upper frame and an R session in the lower
frame.
I also use ESS to edit my R code (inside Aquamacs Emacs), but I usually use
the
Dear Pf. Ripley,
I use the nls() function coupled with the confint() to obtain the confidence
interval of assessed parameters of fitting model.
I don't understand why the confidence intervals estimated with such a method
aren't consistent?
Regards
B. Boulinguiez
Ph.D. in Chemistry
Ecole
Amazing responses to ,y question, and very fast, thanks all of you!
Dr. Iasonas Lamprianou
Department of Education
The University of Manchester
Oxford Road, Manchester M13 9PL, UK
Tel. 0044 161 275 3485
[EMAIL PROTECTED]
- Original Message
From: Marc Schwartz [EMAIL PROTECTED]
To:
dear all,
I apologize for a second post on the same subject. I still have the
problem. I'm going to describe the problem in a different setting:
I have 3 matrix A,B,W such that
dim(A) = c(n,M)
dim(B) = c(n,M)
dim(W) = c(M,M)
what I'm searching for is an efficient computation of vector R,
On Thu, Jul 31, 2008 at 4:30 PM, Michal Figurski
[EMAIL PROTECTED] wrote:
Frank and all,
The point you were looking for was in a page that was linked from the
referenced page - I apologize for confusion. Please take a look at the two
last paragraphs here:
on 07/31/2008 07:40 AM Wim Bertels wrote:
On Wed, 2008-07-30 at 12:13 -0500, Marc Schwartz wrote:
on 07/30/2008 08:48 AM Wim Bertels wrote:
Hi,
does anyone know of a function to calculate odds ratios in multiway
tables (stratified) (+ the other usual statistics involved)
i mean:
say we have
on 07/31/2008 08:35 AM Ken Williams wrote:
On 7/30/08 1:59 PM, Marc Schwartz [EMAIL PROTECTED] wrote:
I (and many others) use ESS (Emacs Speaks Statistics), in which case, I
have an R source buffer in the upper frame and an R session in the lower
frame.
I also use ESS to edit my R code
Hi all.
I am an R newbie and trying to grasp how the simple optimization routines in
R work. Specifically, I would like some guidance on how to set up a code to
calculate the internal rate of return on an investment project
(http://en.wikipedia.org/wiki/Internal_rate_of_return).
My main problem
Hello R-User!
I have a data.frame with 82 variables (columns) and 290 rows.
The variables are set to classes factor, ordered factor and numeric.
I used the following code
Matrix.My.data-as.matrix(Df.My.Data[2:82])
Matrix.My.data.rcorr-rcorr(Matrix.My.data, type=spearman)
and got the
Alessandro alessandro.montaghi at unifi.it writes:
Hi All,
I have this question. I wish to create a kriging map with R but I haven't a
auxiliary map. I have only one txt file with X, Y and Z records.
When I use this code:
...
subground.ok - krige (Z~sqrt(X+Y), subground,
There MUST be a better way but this will work.
x - c(dog.is.an.animal, cat.is.an.animal, rat.is.an.animal)
bb - strsplit(x, \\.)
myfun - function(m) m[1]
animals - unlist(lapply(bb, myfun))
animals
--- On Thu, 7/31/08, Daren Tan [EMAIL PROTECTED] wrote:
From: Daren Tan [EMAIL PROTECTED]
Hi Everyone,
I did a quick search of the list and it looks like this may not have
been asked before... I'm trying to generate a matrix of random numbers
between 0 and 1, with 6 columns, 1 rows. About all I know is that
runif(1) gives me the random number I'm looking for.
Any help would
on 07/31/2008 12:24 PM Max wrote:
Hi Everyone,
I did a quick search of the list and it looks like this may not have
been asked before... I'm trying to generate a matrix of random numbers
between 0 and 1, with 6 columns, 1 rows. About all I know is that
runif(1) gives me the random number
Gustaf,
Summarizing things I don't understand:
- Honestly, I was thinking I can use bootstrap to obtain better
estimate of a mean - provided that I want it. So, I can't?
- If I can't obtain reliable estimates of CI and variance from a small
dataset, but I can do it with bootstrap - isn't it a
Marc,
this is very handy. My next question is, do you know a quick and easy
way to transfer all of the output to a txt file? (or .xls)?
Thanks,
-Max
Marc Schwartz explained on 07/31/2008 :
on 07/31/2008 12:24 PM Max wrote:
Hi Everyone,
I did a quick search of the list and it looks like
I am trying to do this using the copula library and find a possible way out.
library(copula)
x=mvdc(claytonCopula(.75),c(exp,exp),list(list(rate=1),list(rate=2)))
x.sample=rmvdc(x,100)
The above code gives a sample with two marginal exponential ditributions. But
what does the first argument
Hi Max,
See ?write.table. Perhaps:
MAT - matrix(runif(1 * 6), 1, 6)
# TXT format
write.table(MAT,
C:/yourmatrix.txt,col.names=FALSE,row.names=FALSE,quote=FALSE)
# XLS format
write.table(MAT,
C:/yourmatrix.xls,col.names=FALSE,row.names=FALSE,quote=FALSE,sep=\t)
HTH,
Jorge
On Thu,
?write.table
could help
PF
2008/7/31 Max [EMAIL PROTECTED]:
Marc,
this is very handy. My next question is, do you know a quick and easy way to
transfer all of the output to a txt file? (or .xls)?
Thanks,
-Max
Marc Schwartz explained on 07/31/2008 :
on 07/31/2008 12:24 PM Max wrote:
Hi All,
I wish to create a directional variograms at (0, 45, 90, 135) degrees from
north (y-axis).
v = variogram(Z~1, subground, cutoff=1800, width=80, alpha=c(0, 45, 90,
135))
90 and 45 deg. look good but I don't understand in the fit.variogram how to
create a ansi=c(X) with 90
Hello,
I would like to ask if anyone could help me. I want to save images I create
(e.g. histograms, boxplots, plots, etc.) to a file or files. Does anyone
know how to do this?
Thank you.
Aiste
[[alternative HTML version deleted]]
__
Thanks so much for the link.
Scott
Gabor Grothendieck wrote:
Vista works fine for developing packages. You might look at
http://batchfiles.googlecode.com
which has some batch files for use with Vista and R.
On Thu, Jul 24, 2008 at 9:13 PM, FScottDahlgren [EMAIL PROTECTED]
wrote:
m - runif(6)
mm - matrix(m, ncol=6)
HTH
Dave
On Thu, Jul 31, 2008 at 6:24 PM, Max [EMAIL PROTECTED] wrote:
Hi Everyone,
I did a quick search of the list and it looks like this may not have been
asked before... I'm trying to generate a matrix of random numbers between 0
and 1, with 6
On 7/31/08 11:01 AM, hadley wickham [EMAIL PROTECTED] wrote:
I think that would be a very hard task -
Well, at least medium-hard. But I think significant automatic steps could
be made, and then a human can take over for the last few steps. That's why
I was enquiring about tools rather than
Thank you both very much for your assistance. Both the suggestions worked out
in the end, and I managed to achieve what I wanted.
There is something else I want to try, which is a slight deviation on the
theme. In the code I posted, I export Intercept and Slope regression
coefficients to an o/p
?Devices for a start.
Aiste Aistike wrote:
Hello,
I would like to ask if anyone could help me. I want to save images I create
(e.g. histograms, boxplots, plots, etc.) to a file or files. Does anyone
know how to do this?
Thank you.
Aiste
[[alternative HTML version deleted]]
This is perfect, thanks! :)
Jorge Ivan Velez pretended :
Hi Max,
See ?write.table. Perhaps:
MAT - matrix(runif(1 * 6), 1, 6)
# TXT format
write.table(MAT,
C:/yourmatrix.txt,col.names=FALSE,row.names=FALSE,quote=FALSE)
# XLS format
write.table(MAT,
Hi,
Thank everyone for you help. I got my histogram written to a file. Thanks
once again.
Aiste
2008/7/31 Jian Zhang [EMAIL PROTECTED]
Hi aiste,
two easy example produce mypic.ps or mypic.pdf for you x-rnorm(50)
postscript(mypic.ps)
hist(x)
dev.off()
pdf( mypic.pdf)
hist(x)
On 7/31/2008 2:08 PM, Ken Williams wrote:
On 7/31/08 11:01 AM, hadley wickham [EMAIL PROTECTED] wrote:
I think that would be a very hard task -
Well, at least medium-hard. But I think significant automatic steps could
be made, and then a human can take over for the last few steps. That's
Hello,
I've installed an Rserve instance on a remote server. I have no problem
interfacing with it and running most commands. I have loaded some R
scripts on the remote server, and one of them contains a system command
to copy a file (created by the script) onto another server. When I run
the
Hello R-helpers,
I would like to produce a boxplot for dates, using lattice.
Here is a dummy example :
dates-as.Date(32768:32895,origin=1900-01-01)
plouf-data.frame(days=dates,group=factor(rep(1:2,times=128/2)))
bwplot(group~days,data=plouf)
# doesn't work, whereas :
Hello all,
I have a question on bpplot (or more specifically panel.bpplot used with
bwplot) from package Hmisc.
I would like to produce a box-percentile plot but vertically. And I hqve not
been able to use the horizontal argument...
using one of the examples from ?panel.bpplot :
bwplot(g
I am sorry if I misinterpreted this but this questions looks/looked very
like a very basic one about statistical inference... (have a look at the
Manuals/contributed documentation e.g. Faraway)
Lalitha Viswanath wrote:
Hi
This is not a homework assignment :)
Me and my manager are trying to
I have a large data set where one of the columns needs be a unique
identifier (ID) for each row. However for a few of the rows they have
the same ID. What I need to do is randomly draw one of the rows and
keep it in the data frame and drop all the others which have the same
ID.
For example:
v1 -
Iasonas Lamprianou said the following on 5/2/2007 8:25 AM:
Hi I am using R version 2.4.1. How can I upgrade to version 2.5 without
having to install all the packages again?
Thanks
Jason
You may find the following link relevant.
Hi everyone,
I have a rollapply statement that applies a function, in steps, over a data
matrix as follows:
#Code start
testm-rollapply(mat, 100, by=100, min, na.rm=F)
#Code end
This moves down matrix 'mat' and calculates the minimum value over a 100 row
range, every 100 rows (i.e. no
On 7/31/08 2:12 PM, Duncan Murdoch [EMAIL PROTECTED] wrote:
expression() returns a list of language objects, and we only asked for
one. We can look inside it:
Hey, cool. Now let me see if I can do anything useful with that. Thanks.
-Ken
--
Ken Williams
Research Scientist
The
Tomas Mikoviny wrote: Hi all R positive, does anyone know how to refer R in
article? thanks tomas Like this (well, almost! This is from R 2.4.1 -
2007 on the most recentversion)
citation()
To cite R in publications use:
R Development Core Team (2006). R: A language and environment for
How about making your homeworks yourselfes?
lalitha viswanath wrote:
Hi
I have a dataframe which has 3 columns of numeric data
A,B,C each of which has been obtained independent of
the other.
We are trying to find out, which of A or B cause C
i.e. We are hypothesising that C is the effect
Dear HelpeRs,
I have created a tar.gz package (the package was created on unix) and I would
like to install it in R on a Windows operating system.
As far as I know, R in Windows accepts only packages in zip file for
installation and I could not find a way to install a tar.gz file.
I would like
R-helpers,
I'm having difficulty with customizing strip names for a lattice graphic.
Here is an example using the iris data set :
xyplot(Sepal.Length+Sepal.Width~Petal.Length,groups=Species,data=iris)
## I'd like to change the 2 strip names to Length and Width for example,
this is what
on 07/31/2008 03:20 PM Economics Guy wrote:
I have a large data set where one of the columns needs be a unique
identifier (ID) for each row. However for a few of the rows they have
the same ID. What I need to do is randomly draw one of the rows and
keep it in the data frame and drop all the
On 5/2/07, Sundar Dorai-Raj [EMAIL PROTECTED] wrote:
Iasonas Lamprianou said the following on 5/2/2007 8:25 AM:
Hi I am using R version 2.4.1. How can I upgrade to version 2.5 without
having to install all the packages again?
Thanks
Jason
You may find the following link relevant.
Please find below my command inputs, subsequent outputs and errors that I've
been receiving.
crops - read.table(crop2000AD.asc, colClasses = numeric, na=-)
str(crops[1:10])
'data.frame': 2160 obs. of 10 variables:
$ V1 : num NA NA NA NA NA NA NA NA NA NA ...
$ V2 : num NA NA NA NA
It's not really equivalent, natural language has ambiguities and subtleties
that computer languages, especially functional languages, intentionally
don't have. By their nature, computer languages can be turned into parse
trees unambiguously and then those trees can be manipulated.
But in
Thanks for both replies.
Then I found the ifft2 from Matlab gives different result from fft( ,
inverse=T) from R.
An example:
in R:
temp - matrix(c(1,4,2, 20), nrow=2)
fft(temp)
[,1] [,2]
[1,] 27+0i -17+0i
[2,] -21+0i 15+0i
fft(temp,inverse=T)
[,1] [,2]
[1,] 27+0i -17+0i
on 07/31/2008 03:07 PM georgiana onicescu wrote:
Dear HelpeRs, I have created a tar.gz package (the package was
created on unix) and I would like to install it in R on a Windows
operating system. As far as I know, R in Windows accepts only
packages in zip file for installation and I could not
You are missing 'ranlib': take a closer look at the output from
configure (and the posting guide).
My guess is that either /usr/ccs/bin is not in your path or you don't have
the tools installed to build applications. This is not an R issue, and
you need to seek local Solaris help.
On Thu, 3
On Thu, Jul 31, 2008 at 1:30 PM, GOUACHE David
[EMAIL PROTECTED] wrote:
R-helpers,
I'm having difficulty with customizing strip names for a lattice graphic.
Here is an example using the iris data set :
xyplot(Sepal.Length+Sepal.Width~Petal.Length,groups=Species,data=iris)
## I'd like to
This probably has to do with your ssh configuration and nothing to do
with R. How are you starting Rserve? Is it run with the same user
privileges as when you run R manually?
Best,
Jeff
Patil, Prasad wrote on 07/31/2008 02:51 PM:
Hello,
I've installed an Rserve instance on a remote
I am getting an error allocMatrix: too many elements specified when I
am trying to create large matrix or vector (about 1 billion elements).
How can I find out limits on allocMatrix? Can I increase them?
Thanks,
Vadim.
PS: I am running R on SUSE10 on
Hi All,
I have this problem. I dont understand the right code in R when I have an
anisotropy in the semivariogram model
plot(variogram(Z~1, subground, cutoff=1800, width=80, alpha=c(45, 135, 90,
135)))
I have a good model in 90° and eventually in 90° and 45°
v = variogram(Z~1,
Hello all,
I am trying to sort rows of one matrix by rows of another. Given a1 and a2:
--
a1
[,1] [,2] [,3]
[1,]768
[2,]424
[3,]472
[4,]038
a1 -
structure(c(7, 4, 4, 0, 6, 2, 7, 3, 8, 4, 2, 8), .Dim = c(4L, 3L))
a2
[,1] [,2] [,3]
Hello. I am hoping someone will be willing to help me understand something
about hazard plots created with muhaz(...). I have some background in
statistics (minor in grad school), but I haven't been able to figure one thing
about hazard plots. I am using hazard plots to track customer
rollapply over an index. Modify this appropriately:
z - zoo(101:109, 11:19)
f - function(ix) if (ix[1] 5) min(z[ix]) else max(z[ix])
rollapply(zoo(seq_along(z)), 3, by = 3, f)
2 5 8
101 104 109
On Thu, Jul 31, 2008 at 3:36 PM, rcoder [EMAIL PROTECTED] wrote:
Hi everyone,
I have a
I used read.dta() to read in a Stata 9 dataset to R. The Sex01 variable
takes on two values in Stata: 0 and 1, and it is labeled M and F
respectively, analogous to an R factor. Thus, read.dta reads it in as a
factor.
Now, I wanted to see what this variable *really* is, in R. For instance,
Dear HelpeRs,
I have created a tar.gz package (the package was created on unix)
and I would like to install it in R on a Windows operating system.
As far as I know, R in Windows accepts only packages in zip file for
installation and I could not find a way to install a tar.gz file.
I would
I clicked Send before making sure I thanked anyone who took the time to help
me out. Â Sorry about that. Â To all who read or respond: thanks!.
- Original Message -
From: Alan Cox [EMAIL PROTECTED]
To: r-help@r-project.org
Sent: Thursday, July 31, 2008 5:29:35 PM GMT -05:00 US/Canada
On Thu, 31 Jul 2008, Vadim Kutsyy wrote:
I am getting an error allocMatrix: too many elements specified when I am
trying to create large matrix or vector (about 1 billion elements).
How can I find out limits on allocMatrix? Can I increase them?
?Memory-limits, and you cannot increase them
See ?NumericConstants.
On Thu, 31 Jul 2008, Jacob Wegelin wrote:
I used read.dta() to read in a Stata 9 dataset to R. The Sex01 variable
takes on two values in Stata: 0 and 1, and it is labeled M and F
respectively, analogous to an R factor. Thus, read.dta reads it in as a
factor.
Now, I
On 31/07/2008 4:07 PM, georgiana onicescu wrote:
Dear HelpeRs,
I have created a tar.gz package (the package was created on unix) and I would like to install it in R on a Windows operating system.
As far as I know, R in Windows accepts only packages in zip file for installation and I could not
If you're not adverse to cbind-ing a1 and a2, you can use this:
a1a2 - cbind(a1, a2)
a3 - t(apply(a1a2, 1, function(x) x[order(x[1:ncol(a1)])+ncol(a1)]))
Eric
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Timothy W. Hilton
Sent: Thursday, July 31,
On 31/07/2008 5:21 PM, Jacob Wegelin wrote:
I used read.dta() to read in a Stata 9 dataset to R. The Sex01 variable
takes on two values in Stata: 0 and 1, and it is labeled M and F
respectively, analogous to an R factor. Thus, read.dta reads it in as a
factor.
Now, I wanted to see what this
On Thu, Jul 31, 2008 at 12:54 PM, GOUACHE David
[EMAIL PROTECTED] wrote:
Hello R-helpers,
I would like to produce a boxplot for dates, using lattice.
Here is a dummy example :
dates-as.Date(32768:32895,origin=1900-01-01)
plouf-data.frame(days=dates,group=factor(rep(1:2,times=128/2)))
below is another way ( maybe the same ? )but with an extra line to make
roworder. i'm also not clear on why I have to take the transpose of
the result that
comes back form the apply call. in ?apply, it says that the function
tries to convert the result back to a matrix. that's fine but why
Dear all,
I was trying to understand how multcomp package works by running the
examples given in the documentation.
However I still don't understand when it comes to multiple comparison set by
user (please refer to Ksub in the code). Therefore I run 2 other cases
along with the original example
I am getting an error allocMatrix: too many elements specified when
I am trying to create large matrix or vector (about 1 billion elements).
How can I find out limits on allocMatrix? Can I increase them?
?Memory-limits, and you cannot increase them unless you have a
system which has larger
Hi all,
I am doing some experiment studies...
It seems to me that with different combination of 5 parameters, the end
results ultimately converged to two scalars. That's to say, some
combinations of the 5 parameters lead to one end result and some other
combinations of the 5 parameters lead to
I am trying to write a function for P-I curve meansurament of Platt (1980). I
used the exemple of nonlinear least squares in R-intro.pdf but I can't finish
the analysis. Could you help me? Is there another way to do this analysis?
Thanks.
I- c(0,0,100,100,200,200,500,500)
P-
I came up with the same solution as Mark Leeds.
a1roworders - t(apply(a1, 1, order))
a2ord - t(sapply(seq(nrow(a1)), function(x) a2[x, a1roworders[x,]] ))
a2ord
[,1] [,2] [,3]
[1,] 102 101 103
[2,] 102 101 103
[3,] 103 101 102
[4,] 101 102 103
Mark's question about the
Hi,
say I have a loop that cannot complete. how do I abort within JGR?
I use unbuntu linux.
Thanks.
--
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Hi,
Suppose I have these two matrices (could be more).
What I need to do is to store these matrices into a hash.
So that I can call back any of the matrix back later.
Is there a way to do it?
mat_1
[,1][,2]
[1,] 9.327924e-01 0.067207616
[2,] 9.869321e-01 0.013067929
I think a named list is probably the easiest way to start off, something
like:
all_mat - list(mat1 = mat1, mat2 = mat2)
all_mat$mat2
Gundala Viswanath wrote:
Hi,
Suppose I have these two matrices (could be more).
What I need to do is to store these matrices into a hash.
So that I can
Thanks so much Eric,
But how do you include that in a loop.
I tried this, doesn't seem to work. Please advice:
__BEGIN__
all_mat - NULL
for (matno in 1:10) {
mat - process_to_create_matrix(da[matno])
all_mat - list(all_post, matno = mat)
}
print(all_mat) # it gives funny structure.
In the first case, 'crops' is an object that is 142MB in size, and
that alone will take up almost 50% of your memory. You are also
probably generating another object of like size in doing the
operation. Can you cut down the size of the objects that you need.
What operating system do you have and
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