Tdf
bin TCC_TCA TCA_CR TCC_CR Timesn.rnc
117 117 258 27314 (08/28/08 00:09:42) 50.21
118 118 251 30291 (08/28/08 00:09:47) 50.21
119 119 247 28289 (08/28/08 00:09:52) 50.21
120 120 251 29282 (08/28/08 00:09:57) 50.21
Hi
Dbfile contains
bin TCC_TCA TCA_CRTCC_CRTime sn.rnc
1 301 38 365 (08/28/08 00:00:02) 50.20
2 302 39 358 (08/28/08 00:00:07) 50.20
3 319 43 377 (08/28/08 00:00:12) 50.20
4 312
I am calling fft and getting a non-numeric error:
+ fit - lm(Quantity ~ DayOfYear, .sublist)
+ # Make the time series
+ x - as.numeric(rep(0,512))
+ x - merge(residuals(fit), x)
+ # Transform range to -pi - pi
+ x - x - pi
+ x - x * (2 *
If you do
?read.table
you would most likely find the answer on your own.
Have a look at the description of the as.is and colClasses argument.
The column sn.rnc has been automatically recognised as being numeric.
After
Df1-read.table(Dbfile,colClasses=character,header=TRUE)
you will see
Hi
str-50.20
as.numeric(str)
[1] 50.2
But I want 50.20 as o/p
How can I get
Thanks
K.Ravichandra
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
Yuan Jian jayuan2008 at yahoo.com writes:
[...snip...]
I want to remove level b because level b has less than 2.
f
[1] a a
Levels: a
f[which(f %in% names(table(f))[table(f) = 2]), drop=TRUE]
[1] a a
Levels: a
HTH,
Adrian
__
Adrian Dusa wrote:
Adrian Dusa dusa.adrian at gmail.com writes:
[...snip...]
f[which(f %in% names(table(f))[table(f) = 2]), drop=TRUE]
[1] a a
Levels: a
Or, more simple:
f[f %in% names(table(f))[table(f) = 2], drop=TRUE]
[1] a a
Levels: a
Adrian
Also see the combine.levels function in
Original Message
Subject: ***HTML***R help
Date: Sat, 30 Aug 2008 14:30:48 +0530
From: sayeed hussain [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Hello there
I am stuck with a problem and I need help
---
R has a defined function sum()
I by chance defined a
Brian Lunergan ff809 at ncf.ca writes:
I am stuck with a problem and I need help
---
R has a defined function sum()
I by chance defined a function with same name
sum-function(type='public')
{
...
}
and now I m not able to get rid of my sum() fuction.
Estaré ausente de la oficina desde el 29/08/2008 y no volveré hasta el
07/09/2008.
Responderé a su mensaje cuando regrese.
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
[EMAIL PROTECTED] wrote:
I am calling fft and getting a non-numeric error:
+ fit - lm(Quantity ~ DayOfYear, .sublist)
+ # Make the time series
+ x - as.numeric(rep(0,512))
+ x - merge(residuals(fit), x)
+ # Transform range to -pi - pi
+ x - x -
Kurapati, Ravichandra (Ravichandra) wrote:
Hi
str-50.20
as.numeric(str)
[1] 50.2
But I want 50.20 as o/p
For output formatting, see ?formatC, for example.
Uwe Ligges
How can I get
Thanks
K.Ravichandra
[[alternative HTML version
Brian Lunergan wrote:
Evening all:
Stepping away from the stats methodology questions for a moment, I have
a housekeeping question for when it comes time to make the jump to v2.7.2.
I'm running v2.7.1 on an XP system. I have a suspicion that, by way of
experimentation with a couple of
On Fri, Aug 29, 2008 at 6:46 PM, David Huffer [EMAIL PROTECTED] wrote:
I'm looking for something along the lines of
which ( table ( x ) == max ( table ( x ) ) )
to find the most common level of one factor
by several other factors. For instance, I've got
X - data.frame (
+ x = factor
Dear list,
I am trying to split a string using regexp:
x - 2 Value 34 a-c 45 t
strsplit(x, [0-9])
[[1]]
[1]Value a-c t
But I don't want to lose the digits (pattern), the result
should be:
[[1]]
[1] 2 Value 34 a-c 45 t
Thanks for any tipp
Patrick
Try this:
library(gsubfn)
strapply(x, [0-9]+| +[^ ]+ *)[[1]]
[1] 2Value 34 a-c45 t
which keeps the spaces around the non-numeric entries as in
your example; however, if keeping the spaces is not important
then its even easier:
strsplit(x, )[[1]]
[1] 2 Value 34
I am using the RGL library in scripted (non-interactive) mode, but wish to
give the data analyst an opportunity to exam the 3D plots. The data
analysts understand the data, but not R. My intent is to provide simple
Windows (XP) batch files that call R and automatically pass scripts to it,
and thus
If this is the case then how to I take a list of numbers (residuals in this
case) and create anothe list that is longer and padded by zeros? Maybe fft
already does this for me but as I understood it I need to pass an vector to the
fft that is of a power of 2 length. If I still need to do this
Dear List,
I am trying to draw a rectangular plane using the persp function, however I
can't seem to get it to work. I want the length along x1 axis to be between
1 and 3 and the length along the x2 axis to be between 1 and 4. All z
values for x1 should be equal (say, z=1) because this is a
Hi,
I want a function to write some of its output into a text file with
the following format:
'some text'
output matrix A
'some more text'
output matrix B
'some other text still'
output matrix C
...
The dimensions of matrices A, B, ... are different and the total
number of matrices
that I
I have been trying to specify a different color palette to the image
method in plot.Design. My model has crossed two rcs() arguments and
one two-level gender argument. The goal which appears to have been
mostly achieved is to produce separate bivariate plots for men and women
The call to
you can combine write and write.table, using append=TRUE.
e.g.,
write1 - function(txt, mat, filename) {
for(i in 1:length(txt)) {
write(txt[i], file=filename, append=i!=1)
write.table(mat[[i]], file=filename, append=TRUE,sep =\t)
}
}
t - c(text1, text2, text3)
m -
On 30/08/2008 10:10 AM, Steven Shafer wrote:
I am using the RGL library in scripted (non-interactive) mode, but wish to
give the data analyst an opportunity to exam the 3D plots. The data
analysts understand the data, but not R. My intent is to provide simple
Windows (XP) batch files that call R
Is this what you want to do:
x - seq(from=1,to=3,by=.1)
y - seq(1,4,by=.1)
z - matrix(1, length(x), length(y))
persp(x=x,y=y,z,zlim=c(0,2))
On Sat, Aug 30, 2008 at 2:08 PM, dxc13 [EMAIL PROTECTED] wrote:
Dear List,
I am trying to draw a rectangular plane using the persp function, however I
Hello ALL,
I'm unsure how to interpret partial dependence plots and had 2 questions:
Does the randomForest library scale partial dependence plots such that zero
on the y axis is mean(y)? I am also unclear as to why the range of y on
these plots is smaller than what is in the dataset.
Also I
Yes, this works nicely. Thank you!
jholtman wrote:
Is this what you want to do:
x - seq(from=1,to=3,by=.1)
y - seq(1,4,by=.1)
z - matrix(1, length(x), length(y))
persp(x=x,y=y,z,zlim=c(0,2))
On Sat, Aug 30, 2008 at 2:08 PM, dxc13 [EMAIL PROTECTED] wrote:
Dear List,
I am trying
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