2008/9/7 asdfjkl; [EMAIL PROTECTED]:
Yes, I don't know how to copy the plot on Mac and paste on to Word because
you can't right click on the graph and say copy as metafile.
I'm so surprised I can't find any information about this anywhere on the
Internet...
The obvious way would be to save
How are you executing the script? Quite possibly FAQ Q7.22 applies (it
will it you use source(), for example).
On Sat, 6 Sep 2008, Nathan Teuscher wrote:
I have the following code that when executed from the command line
works properly and produces a proper PDF. When the script is executed,
Hi there,
I try to rewrite some Java-code with R. It deals with reading XML files. I
started with the XML package. In Java, I had a very useful method which gave me
a node by using:
name of the node
index of appearance
start point: global (false) / local (true)
So, I could do something like
Thank you very much, Adam.
I have to get a bit more familiar with the model you propose in order to
understand if it applies to my problem as well.
My question is not really does time show a different effect but which one
of two measures is more reliable: My respondents have completed exactly
It's exactely what I was looking for.
Thanks a lot
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Carlos Morales wrote:
Hello everyone,
I would like to know if there is any function to calculate the mode value, or I
have to build one to do it.
Hi Carlos,
If you mean the mode of a sample from a discrete distribution, try Mode
in the prettyR package.
Jim
Hello
I am a newbie. I had my R upgraded from 2.7.1 to 2.7.2 and in doing so I
decided to install all 2.7 versions under c:\program files\R\2.7 from now on
(2.7.1 is located under .\2.7.1)
Although I don't like the idea (I am running Vista), I have edited
etc\Renviron.site to contain:
Dear all,
I encountered a problem on starting and using the R v 2.7.2 installation on
my PC running Windows Vista and would appreciate your help.
When R was first started, the Rgui returned several error messages:
Error in structure(.Internal(Sys.getenv(as.character(x),
as.character(unset)$
here is a simple approach to, for instance, plot scores for PC1 and
PC2 using diff colors:
scores - prcomp(yourdata)$x
plot(scores[1:100,1], scores[1:100,2], pch = 20, col = blue)
points(scores[101:200,1], scores[101:200,2], pch = 20, col = red)
PM
On Sat, Sep 6, 2008 at 11:44 PM, pgseye [EMAIL
Dear all,
I have a question on Cohen's kappa:
Assume I have two datasets, one has 500 objects, 10 methods and the other,
1000 different objects, 20 different methods. Could I compare between the
two datasets to conclude the 10 methods are more concordant than the 20
ones by looking at some
I think you need to save the plot and import it into Word. AFAIK you can only
copy and paste a plot in Windows.
Have a look at ?png (There are other formats available)
--- On Sun, 9/7/08, asdfjkl; [EMAIL PROTECTED] wrote:
From: asdfjkl; [EMAIL PROTECTED]
Subject: [R] ON MAC, how to copy
well not sure how its done in R , but heres a way to do it in simple Excel.
http://decisionstats.com/2008/parsing-xml-files-easily/
Parsing XML files easily
To parse a XML (or KML or PMML) file easily without using any
complicated softwares, here is a piece of code that fits right in your
excel
On 7 September 2008 at 10:22, Antje wrote:
| I try to rewrite some Java-code with R. It deals with reading XML files. I
[...]
| Now, I'd like to do something like this in R. Most important would be to
| retrieve a node just by its name, not by the whole path. How is it possible?
|
| Can
-- Forwarded message --
From: jim holtman [EMAIL PROTECTED]
Date: Sun, Sep 7, 2008 at 11:42 AM
Subject: Re: [R] request: most repeated sequnce
To: Muhammad Azam [EMAIL PROTECTED]
This should do it for you:
In particular try this:
Lines - '
+ root
+ data loc=1
+val i=t1 22 /val
+val i=t2 45 /val
+ /data
+ data loc=2
+val i=t1 44 /val
+val i=t2 11 /val
+ /data
+ /root
+ '
library(XML)
doc - xmlTreeParse(Lines, asText = TRUE, trim = TRUE, useInternalNodes =
TRUE)
root -
I just CMD-C'd it and pasted it into OpenOffice with CMD-V.
el
On 07 Sep 2008, at 16:57 , John Kane wrote:
I think you need to save the plot and import it into Word. AFAIK
you can only copy and paste a plot in Windows.
Have a look at ?png (There are other formats available)
Hi Kurt,
Please tell me how to format data in a data frame so when currency amount is
displayed in a chart the axis tick labels contain leading $ signs.
The easiest way is add a custom scale:
vals - seq(0, 100, by = 10)
qplot(...) + scale_x_continuous(breaks = vals, labels = paste($,
vals,
Thanks Ben!
Switching over to the gamma pdf and using the algorithm=plinear did the
trick.
jpl
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Hash: SHA1
Hi Antje
Well, the XML package gives you a variety of ways to parse
an XML document and manipulate it in R.
Perhaps the approach that best matches the Java-style you
outline is to use XPath to access nodes.
To do this, you use
doc =
Dear List:
I found an error when I called the 'gee' function. I cannot solve and explain
it. There are no errors when I used the 'geeglm' function. Both functions fit
the gee model. The project supervisor recommends me to use the 'gee' function.
But I cannot explain to him why this error
Thanks very much. This is what I implemented. I found a similar example
elsewhere too.
It works fine now.
jholtman wrote:
I would suggest that you use a list to store the values since it is
easier to create and reference:
output - list()
for (i in 1:10) output[[i]] - seq(i)
output
Hi,
y is nominal (3 categories), x1 to 3 is scale. What I want is a
regression, showing the probability to fall in one of the three
categories of y according to the x. How can I perform such a
regression in R?
Thanks for your help
Sören
__
check:
help(multinom, package = nnet)
I hope it helps.
Best,
Dimitris
[EMAIL PROTECTED] wrote:
Hi,
y is nominal (3 categories), x1 to 3 is scale. What I want is a
regression, showing the probability to fall in one of the three
categories of y according to the x. How can I perform such a
On Sun, Sep 7, 2008 at 12:10 PM, Gabor Grothendieck
[EMAIL PROTECTED] wrote:
In particular try this:
Lines - '
+ root
+ data loc=1
+val i=t1 22 /val
+val i=t2 45 /val
+ /data
+ data loc=2
+val i=t1 44 /val
+val i=t2 11 /val
+ /data
+ /root
+ '
library(XML)
doc
Thanks a lot to Gabor and Duncan!
I didn't know that XPath is a standard. I'll give it a deeper look to better
understand it.
Oh, I guess I understand a bit more
xpathApply(doc, //val, function(n) xmlValue(n))
would search globally for all nodes named val and return its values :-)
So that's
Dear all,
I have a large dataset which I hope to reduce in size, to make it more useable.
I hope to do this by taking an average of each 60 x 60 blockof values and
forming a new data frame out of the averaged values.
How would I go about taking averages of 60 x 60 'blocks' in R, and cycling
On Sun, Sep 7, 2008 at 2:56 PM, Antje [EMAIL PROTECTED] wrote:
Thanks a lot to Gabor and Duncan!
I didn't know that XPath is a standard. I'll give it a deeper look to better
understand it.
Oh, I guess I understand a bit more
xpathApply(doc, //val, function(n) xmlValue(n))
or just
This was answered last month:
http://tolstoy.newcastle.edu.au/R/e4/help/08/08/19091.html
On Sun, Sep 7, 2008 at 3:32 PM, Steve Murray [EMAIL PROTECTED] wrote:
Dear all,
I have a large dataset which I hope to reduce in size, to make it more
useable. I hope to do this by taking an average
On Sun, Sep 7, 2008 at 12:32 PM, Steve Murray [EMAIL PROTECTED] wrote:
Dear all,
I have a large dataset which I hope to reduce in size, to make it more
useable. I hope to do this by taking an average of each 60 x 60 blockof
values and forming a new data frame out of the averaged values.
Gabor - thanks for your suggestion... I had checked the previous post, but I
found (as a new user of R) this approach to be too complicated and I had
problems gaining the correct output values. If there is a simpler way of doing
this, then please feel free to let me know.
Dylan - thanks, your
Gabor - thanks for your suggestion... I had checked the previous post, but I
found (as a new user of R) this approach to be too complicated and I had
problems gaining the correct output values. If there is a simpler way of doing
this, then please feel free to let me know.
Dylan - thanks, your
Hello,
I want to know how to draw a line connecting each point to the x-axis
perpendicularly (i.e. a vertical line).
abline(v=...) seems not to work for my purpose, because it runs over the
data point. Can anyone help? Thanks.
Anny
[[alternative HTML version deleted]]
Dear R Gurus:
How would I create a vignette, please?
Why would a vignette be better than examples, please?
Thanks,
Edna Bell
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
This should do it for you:
CODE NAME
13 aaa
23 aab
33 aac
44 bba
54 bbb
64 bbc
74 bbd
85 cca
95 ccb
x.s - split(x$NAME, x$CODE)
maxLine - max(table(x$CODE))
# pad out the lines
x.pad - lapply(x.s, function(line){
+ # convert to character
+
Anny
Here's one way:
plot(0:10, 0:10, pch=16)
lines(rep(0:10, each=3), t(matrix(c(0:10, rep(c(0,NA), each=11)),
ncol=3)))
HTH
Peter Alspach
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Anny Huang
Sent: Monday, 8 September 2008 8:49 a.m.
Here is a way to do it by reading in 60 lines at a time and computing the means:
# create some test data
n - 360
x - matrix(runif(360*16800), nrow=16800)
cat(x, file=/tempxx.txt)
# now process the data 60 lines at a time, averaging each 60x60 block
result - matrix(0, nrow=6, ncol=280)
nextLine
Hello
I am a newbie. I had my R upgraded from 2.7.1 to 2.7.2 and in doing so I
decided to install all 2.7 versions under c:\program files\R\2.7 from now
on (2.7.1 is located under .\2.7.1)
Although I don't like the idea (I am running Vista), I have edited
etc\Renviron.site to contain:
2008/9/7 Anny Huang [EMAIL PROTECTED]:
Hello,
I want to know how to draw a line connecting each point to the x-axis
perpendicularly (i.e. a vertical line).
abline(v=...) seems not to work for my purpose, because it runs over the
data point. Can anyone help? Thanks.
If your x-axis is at
Try this:
# read in data ensuring NAME is character, not factor
Lines - CODE NAME
+ 13 aaa
+ 23 aab
+ 33 aac
+ 44 bba
+ 54 bbb
+ 64 bbc
+ 74 bbd
+ 85 cca
+ 95 ccb
+
DF - read.table(textConnection(Lines), header = TRUE, as.is = TRUE)
DF$seq =
Hi,
I am at the end of my wit to figure out how to run the optim function on
a list.
Basically, I have a data set of three columns as Site, Pool and
Positivity ( the full data set is copied at the end). I want to run
the maximal likelihood estimation separately on subsets split by Site
Dear list,
I have to read a not-so-small bunch of not-so-small Excel files, which
seem to have traversed Window 3.1, Windows95 and Windows NT versions of
the thing (with maybe a Mac or two thrown in for good measure...).
The problem is that 1) I need to read strings, and 2) those
From the gee() help page:
Data are assumed to be sorted so that observations
on a cluster are contiguous rows for all entities in the formula.
-thomas
On Sun, 7 Sep 2008, Qinglin Wu wrote:
Dear List:
I found an error when I called the 'gee' function. I cannot solve and explain
On 07/09/2008 4:51 PM, Edna Bell wrote:
Dear R Gurus:
How would I create a vignette, please?
Why would a vignette be better than examples, please?
You can create a vignette any way you like, but the most common way is
with Sweave: write a document that is mainly LaTeX, but with R code
Hi R users
Is there any example for nonlinear parametric boot? I google it but I
can't find it. I am interested in the parameter estimators of a
nonlinear model. But I really don't know how to code it in the
ran.gen statement (data set from ?nls)
fm1 - nls(weight ~
Dear Thomas Lumley:
According to your suggestion I have sorted the 'newdata' by id. When I print
the results the error was still there. So I tried to sort the 'newdata' by y,
x although I don't think it make sense. The error was still there. Here it
was the part of the code:
Dear Srini,
Here is one way:
# Data set
x=read.table(textConnection(fruit weight
1 apple1.3
2 apple1.5
3 apple1.6
4 orange1.4
5 orange1.6),header=TRUE)
x[tapply(x$weight,x$fruit,which.max),]
apple orange
1.61.6
or
Try also
I'm not sure I exactly understand your problem, but if you are
looking for a recursive algorithm for calculating the average by
addition of one record only at a time, consider:
y[k] = y[k-1] + (x[k] - y[k-1])/k, where y(0) = 0, k = 1, 2, ...
At each stage, y[k] = (x[1]+...+x[k])/k.
At
one more question,
The third value (kappa (2*PA-1)) is adjusted for prevalence using the
method proposed by Byrt, Bishop and Carlin (1993) --- from ?cohen.kappa
What does the prevalence refer to?
On Sun, Sep 7, 2008 at 10:43 PM, Weiwei Shi [EMAIL PROTECTED] wrote:
Dear all,
I have a
Soren,
It sounds like you are new to R so I will refer you to some packages that I
think some people would find more user friendly as beginners.
Zelig is excellent. You could run a series of logistic regressions coding your
dependent variables as follows (a versus b, a versus c, b versus c)
Dear R-help,
Â
Chi Square Test for Goodness of Fit
Â
Â
Problem Faced :
Â
I have got a discrete data
as given below (R script)
Â
No_of_Frauds -c
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