I couldn't download this either with install.packages
from two or three mirrors- I haven't tried since thinking that the
binaries were being built for windows and mac ... If this isn't right
I would be interested.
On Tue, Oct 28, 2008 at 6:10 PM, David Huffer [EMAIL PROTECTED] wrote:
I'm
Hi,
On Tue, Oct 28, 2008 at 2:25 PM, Minho Chae [EMAIL PROTECTED] wrote:
Dear R users,
I am tryting to save an 3d array to a matlab file like the following.
A - array(1:24, c(2,3,4))
writeMat(filename, A=A)
But if I load the mat file from Matlab, it is not 3d matrix anymore.
Does anyone
Igor Telezhinsky wrote:
Dear all,
I have recently found out about the R project. Could anyone tell me if it is
possible to make the comparison of two distributions using R packages? The
problem is TRICKY because I have the distributions of measurements and each
measurement in the given
Zitat von David Scott [EMAIL PROTECTED]:
On Tue, 28 Oct 2008, Oliver Bandel wrote:
Hello,
what are they meaning? It could be something that
would show a threshhold above which the result is
indicating different meanings then just random noise.
But there is no description on the
Dear R users,
Is it possible to have an overlap histogram plot? For example:
stuff - data.frame(Mode = c(Land, Air), AgeGroup = c(Young, Adult,
Old), Value = sample(1:300))
histogram( ~Value | AgeGroup * Mode, data = stuff, auto.key = TRUE)
Instead of having 2 * 3 panel, I want to have just 3
On Tue, 28 Oct 2008, Oliver Bandel wrote:
Zitat von David Scott [EMAIL PROTECTED]:
On Tue, 28 Oct 2008, Oliver Bandel wrote:
Hello,
what are they meaning? It could be something that
would show a threshhold above which the result is
indicating different meanings then just random noise.
But
Zitat von David Scott [EMAIL PROTECTED]:
On Tue, 28 Oct 2008, Oliver Bandel wrote:
Zitat von David Scott [EMAIL PROTECTED]:
On Tue, 28 Oct 2008, Oliver Bandel wrote:
Hello,
what are they meaning? It could be something that
would show a threshhold above which the result is
Try this:
do.call(rbind.data.frame,
lapply(p1, function(i)power.prop.test(p1=i,p2=0.5*i,power=0.8,
sig.level=0.05)))
On Tue, Oct 28, 2008 at 7:16 PM, Farrel Buchinsky [EMAIL PROTECTED] wrote:
I have solved this problem once before but don't recall exactly how.
Is there a url that
On Tue, Oct 28, 2008 at 4:31 PM, Ferry [EMAIL PROTECTED] wrote:
Dear R users,
Is it possible to have an overlap histogram plot? For example:
stuff - data.frame(Mode = c(Land, Air), AgeGroup = c(Young, Adult,
Old), Value = sample(1:300))
histogram( ~Value | AgeGroup * Mode, data = stuff,
JohnLi sent the following at 28/10/2008 19:56:
Thanks a lot ! I learn a lot about R while I solve my problem according to
those provided informatin.
Me too: thanks all.
This particular question has suddenly become relevant to me as I'm
trying to do a bit of simulating to model power for a
Hi,
I have a question of aov. e.g.
aov.ex = aov(x~y)
summary(aov.ex)
The aov summary will print to the screen. How can I extract the aov
result, in particular the values of Pr(F) and F value into a vector
so that I can use them for other use?
Thanks.
--
Waverley @ Palo Alto
Dear Waverley,
Try
# Data
x=rnorm(10)
y=rep(1:2,5)
aov.ex = aov(x~y)
tail(unlist(summary(aov.ex)),2)
# or
anova(lm(x~y))$Pr(F)
HTH,
Jorge
On Tue, Oct 28, 2008 at 8:48 PM, Waverley [EMAIL PROTECTED]wrote:
Hi,
I have a question of aov. e.g.
aov.ex = aov(x~y)
summary(aov.ex)
The
Any insight into the behavior of by in the following case would be
appreciated. There is a note in the help details for by about
documenting behavior since v2.7 but I don't entirely understand what it
is saying. I'm using R2.7.2 Windows. I'm interested if the following
behavior was a change
On 29/10/2008, at 2:04 PM, Jeff Laake wrote:
Any insight into the behavior of by in the following case would be
appreciated. There is a note in the help details for by about
documenting behavior since v2.7 but I don't entirely understand
what it
is saying. I'm using R2.7.2 Windows. I'm
On Tue, 28 Oct 2008 18:04:57 -0700,
Jeff Laake [EMAIL PROTECTED] wrote:
Any insight into the behavior of by in the following case would be
appreciated. There is a note in the help details for by about
documenting behavior since v2.7 but I don't entirely understand what
it is saying. I'm
#this is my stab at - I am sure that I am missing something. If this
doesn't make sense then please ask for more details. #This may show
my low level of programing knowledge
hester. - c(1,1,1,1,2,2,2,2,3,3,3,3,4,4,4,4)
value - rnorm(16)
x - data.frame(value, hester.)
z -
(if(x[,hester.]==1){
On 29/10/2008, at 2:41 PM, stephen sefick wrote:
#this is my stab at - I am sure that I am missing something. If this
doesn't make sense then please ask for more details. #This may show
my low level of programing knowledge
hester. - c(1,1,1,1,2,2,2,2,3,3,3,3,4,4,4,4)
value - rnorm(16)
x -
Thanks to those that replied. It was reproducible on my system but it
was nested within other code which would have been obvious had I left
the browse portions in it. The reason for the behavior was obvious
when I used str(samples). Even though Effort looked like a vector in
samples, it was
Hello. I am relatively new to R and trying to figure out how go about
graphing something like this: http://www.math.yorku.ca/SCS/Gallery/images/NYweather.jpg
Specifically, I am having a hard time graphing the mean, min, and max
temperatures as they are depicted on that graph. When I plot
Hello, R subscribers.
I would like to define a function like this one:
Fun - function(x)sin(x)/x
with value 1 at x=0. How can I do that?
Is there a way to plot it symbolically, without using x as a vector?
e.g.
x - seq(from=-10, to=10, length=100)
plot(x, Fun(x))
Thank you in advance.
Dear George,
Perhaps redefining Fn as
Fun2 - function(x) ifelse(x==0,1,sin(x)/x)
could help. Now, for the symbolic part (I'm not sure if understood
correctly), try ?curve as follows:
curve(Fun2(x),-10,10)
HTH,
Jorge
On Wed, Oct 29, 2008 at 12:21 AM, KARAVASILIS GEORGE [EMAIL
G'day George,
On Wed, 29 Oct 2008 06:21:37 +0200
KARAVASILIS GEORGE [EMAIL PROTECTED] wrote:
Hello, R subscribers.
I would like to define a function like this one:
Fun - function(x)sin(x)/x
with value 1 at x=0. How can I do that?
Fun - function(x) ifelse(x==0, 1, sin(x)/x)
Is there a
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