This certainly involves arranging multiple plots and plotting multiple
variables within the same plot (in the upper graph). The lower plots looks
rather standard and just have to be arranged right. Further, you have to put
the labels (if they are desired). There is a book on R-graphics which may
Thank you Deepayan.
Still on lattice, can the same overlap function be applied to categorical
variable plot such as barchart? I mean, can I create an overlap barchart
plot?
On Tue, Oct 28, 2008 at 5:41 PM, Deepayan Sarkar
[EMAIL PROTECTED]wrote:
On Tue, Oct 28, 2008 at 4:31 PM, Ferry [EMAIL
Alessandro alessandro.montaghi at unifi.it writes:
but I must processing several and several files and I wish to know the
methodology to create a loop formula.
Put your processing in a function, and call it like this
datafiles = dir(../raw)
for(file in datafiles)
{
Thank you Dylan for the hints - I found them very useful, a good
starting point for me to learn about clustering in R.
Best wishes
Viktoras
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
The summary stats for the xin and yin variables below are correct. However,
if I use plot(xin,yin), an exception is thrown saying that object xin is
not found.
Also, it is apparent that I can't successfully replace the x and y vectors
with values from xin and yin.
The four plots on one
Laura Bonnett wrote:
Hi Everyone,
I have data in a long format e.g. there is one row per patient but each
follow-up appointment is included in the row. So, a snippet of the data
looks like this:
TrialNo Drug Sex Rand Adate1 Date1 Dose1 Time1 Adate2 Date2 Dose2
Time2 B1001029 LTG M 15719
Hi Jim,
Thank you very much for your help. It is much appreciated.
Bert, the reason I didn't ask someone at work is because none of us knew.
The person I referred to in my email thought it might be possible but didn't
know how. I can now inform everyone.
Thanks,
Laura
On Wed, Oct 29, 2008
stephen sefick ssefick at gmail.com writes:
I couldn't download this either with install.packages
from two or three mirrors- I haven't tried since thinking that the
binaries were being built for windows and mac ... If this isn't right
I would be interested.
I wondered about this to. If
Dear Thierry,
Thank you very much!
As usual, I should have RTFM :-[
Kind Regards,
Paolo
ONKELINX, Thierry ha scritto:
Paolo,
Try using \nocite{*}. That will cite every entry in your bibliography.
HTH,
Thierry
you 'll may be interested in the drc package (a quick start would be
http://www.bioassay.dk), where you get some nice plots and can fit
appropriate models as well - very handy if you want to estimate
effective doses.
hth.
Laura Bonnett schrieb:
Hi Everyone,
I have data in a long format
I am having difficulty installing the arm package and would be
grateful if anyone could give some advice.
I have updated my computer to a Mac OS X version 10.5.5 ( processor: 2
x 2.8 GHz Quad-Core Intel Xeon) and I have downloaded R version 2.8.0
I have downloaded the package arm, but when i
Well, if you are really serious about this name business, it is much
deeper than just current frequencies of names. Both the popularity of
given personal names and their conjunction with family names varies over
time (see http://www.galbithink.org/names.htm for a good discussion of
the long
Jonathan Greenberg greenberg at ucdavis.edu writes:
..faint internal grid when running the following command to make a
filled contour plot of some data I have (x,y,z being the inputs):
filled.contour(interp(x,y,z,duplicate=strip,
xo=seq(1800,3200,length=57),
yo=seq(120,280,length=65)),
'xin' is an element of a dataframe and you must explicity reference it
as such. See the Intro to R.
plot(mydata$xin, mydata$yin)
On Wed, Oct 29, 2008 at 4:29 AM, Leif Peterson [EMAIL PROTECTED] wrote:
The summary stats for the xin and yin variables below are correct. However,
if I use
Paul,
Look for the An Introduction to R on the CRAN - R web site. The latest
version, as far as I know, is Version 2.7.2 (2008-08-25). You might also
want to examine the R Data Import/Export doc
Both can be found here : http://cran.r-project.org/doc/manuals.html
Steve
Steve Friedman Ph. D.
Dear list,
I have the function (as a simple example, which is actually part of a
larger function)
pres.test-function(N0=N0, N1=N1)
{
dt-5
r-log(N1/N0)/dt
r
}
which calculates the annual growth rates in a population
Where N0 is the population classified into age intervals, say 5
Dear useRs,
I am using the function tune.rpart() implemented in the e1071 package under
R 2.7.1 on Windows XP.
Sometimes, i.e., for some datasets, I get the following error:
tune.rpart(dataset, data = dataset, cp = c(.005,.01,.02))
Error in table(pred, true.y) : all arguments must have
What's wrong with that result?
you should look at the result as: first take the 3th element of a, then the
first one, than the second one and then the fourth.
if you do a[order(a)] then you get 15,20,30,40.
I suppose you expected:
rank(a)
[1] 2 3 1 4
Good luck
Bart
lll73 wrote:
I am
try this:
lapply(split(dat, dat$country), function (x) {
pres.test(x$pop1995, x$pop2000)
})
I hope it helps.
Best,
Dimitris
Corey Sparks wrote:
Dear list,
I have the function (as a simple example, which is actually part of a
larger function)
pres.test-function(N0=N0, N1=N1)
{
Try this:
split(mapply(function(x, y)pres.test(x, y), DF$pop1995, DF$pop2000),
DF$country)
On Wed, Oct 29, 2008 at 10:19 AM, Corey Sparks [EMAIL PROTECTED]wrote:
Dear list,
I have the function (as a simple example, which is actually part of a
larger function)
pres.test-function(N0=N0,
#this is my stab at - I am sure that I am missing something. If this
doesn't make sense then please ask for more details. #This may show
my low level of programing knowledge
hester. - c(1,1,1,1,2,2,2,2,3,3,3,3,4,4,4,4)
value - rnorm(16)
x - data.frame(value, hester.)
z -
For a good, extemely basic, tutorial see
http://www.math.ilstu.edu/dhkim/Rstuff/Rtutor.html
You might also want to have a look at
http://zoonek2.free.fr/UNIX/48_R/all.html
If you are familiar with SPSS or SAS then Bob Muenchen's paper in PDF form
http://oit.utk.edu/scc/RforSASSPSSusers.pdf
[Using R 2.7.2 on Windows XP]
After re-building our heplots package, I've begun to get the following
error from sessionInfo(),
even though it passes R CMD check and builds without errors:
sessionInfo()
Error in x$Priority : $ operator is invalid for atomic vectors
In addition: Warning
Hi,
I would like to know how to get the maximum possible values that can be used
for the dimensions of a device,
For example windows(h=,w=), what are the maximum values that I can pass as
parameters for w and h.
environment info:
platform: Windows XP SP2
R version: 2.7.1
Thanks
Nishan
I know it's easy to write a simple loop to do this, but in the spirit
of lapply, I thought I would ask if there is a builtin to filter or
take a subset of a list based on a predicate in a similar way to the
Erlang lists:filter/2 function:
http://www.erlang.org/doc/man/lists.html#filter-2
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
This is the bit where I get stuck.
Drats!! I almost thought that you had gotten a hold on the elusive
problem of estimating the population of R users
We are legion! :-)
I admit: that doesn't help with calculations ...
Detlef
I am using the order function and the result seems to be incorrect:
a-c(20,30,15,40)
order(a)
[1] 3 1 2 4
Any suggestions?
Thanks,
Laura
--
View this message in context:
http://www.nabble.com/Incorrect-order-tp20224993p20224993.html
Sent from the R help mailing list archive at
I thought R users were measured in fractal dimensions...or is that fractious?
On Wed, Oct 29, 2008 at 4:06 AM, Detlef Steuer
[EMAIL PROTECTED] wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
This is the bit where I get stuck.
Drats!! I almost thought that you had gotten a hold on
Laura,
Order works fine. The output tells you that the third element of a is
the smallest, the first element is a second smallest, ... Try
a[order(a)] that should be equal to sort(a).
HTH,
Thierry
ir. Thierry
Hi,
I believe Bart answered to your question. What is the solution you are
expecting? If you don't give us more explanations we cannot understand
what is wrong for you.
help(sort)
|order| returns a permutation which rearranges its first argument into
ascending or descending order, breaking
Dear Duncan, Ben and Megha
Thank you for your help! I tried
sudo apt-get build-dep r-cran-rgl
And so all necessitated package were installed and I could install rgl..
nice!
Mat
I believe the correct incantation is:
sudo apt-get build-dep r-cran-rgl
If that doesn't work, get back to us
Dear all,
This is my first time using this listserv and I am seeking help from the
expert. OK, here is my question, I am trying to use impute.knn function
in impute library and when I tested the sample code, I got the error as
followingt:
Here is the sample code:
library(impute)
The variable iter from read.table takes on values of 0,5,10,15, and 20. I
am trying to pick off values of iter by assigning it to grp, and e.g.
iter-5, then fill the x and y vectors and make plots of x,y for each value
of iter (0)
For some reason all of the plots are the same, so I am not
Dear all,
I'm trying to estimate some parameters with the optim() function but I
need to restrict one parameter and I have not found how to do it.
Could you help me please?
my program is basically
fn-function(s)
initial-function(r)
{
cst-r[1]
cst1-r[2]
beta-r[3]
rho-r[4]
p1-r[5]
Try:
?Filter
e.g.
Filter(function(x) x 0, x1)
or using gsubfn's fn
library(gsubfn)
fn$Filter(~ x 0, x1)
On Wed, Oct 29, 2008 at 9:06 AM, Whit Armstrong
[EMAIL PROTECTED] wrote:
I know it's easy to write a simple loop to do this, but in the spirit
of lapply, I thought I would ask if
Peter Dalgaard wrote:
Drats!! I almost thought that you had gotten a hold on the elusive
problem of estimating the population of R users
I suspect that the Higgs Boson will be observed well before we get
reasonable estimates on that figure...just need to get the LHC back
online...
;-)
Dear all,
How can I get the duplicated elements from a vector? For example,
x - c(yes, no, yes, yes, no, not sure), how can I filter
out all the elements which occured =2 times?
Thanks for any help!
Regards,
Leon
__
R-help@r-project.org
Dear Leon,
Perhaps:
x - c(yes, no, yes, yes, no, not sure)
names(table(x))[table(x)=2]
HTH,
Jorge
On Wed, Oct 29, 2008 at 9:47 AM, Leon Yee [EMAIL PROTECTED] wrote:
Dear all,
How can I get the duplicated elements from a vector? For example,
x - c(yes, no, yes, yes, no, not sure),
?Filter ...
how did I miss that one?
Thanks, Gabor.
-Whit
On Wed, Oct 29, 2008 at 9:37 AM, Gabor Grothendieck
[EMAIL PROTECTED] wrote:
Try:
?Filter
e.g.
Filter(function(x) x 0, x1)
or using gsubfn's fn
library(gsubfn)
fn$Filter(~ x 0, x1)
On Wed, Oct 29, 2008 at 9:06 AM,
check duplicated(), e.g.,
x - c(yes, no, yes, yes, no, not sure)
x[duplicated(x)]
I hope it helps.
Best,
Dimitris
Leon Yee wrote:
Dear all,
How can I get the duplicated elements from a vector? For example,
x - c(yes, no, yes, yes, no, not sure), how can I filter
out all the elements
On Wed, Oct 29, 2008 at 2:47 PM, Leon Yee [EMAIL PROTECTED] wrote:
Dear all,
How can I get the duplicated elements from a vector? For example,
x - c(yes, no, yes, yes, no, not sure), how can I filter out
all the elements which occured =2 times?
Thanks for any help!
Regards,
Leon
Gustaf Rydevik wrote:
Hi Leon,
unique(x)
or
duplicated(x)
should work, depending on what you want.
Best,
Gustaf
Hi,
Thank you all. Actually, I have a data frame or matrix, whose first
column is numerical values, and whose 2nd column is names. I need those
whose names repeated 3
Dear Leon,
It's not the most efficient way but it works. Hopefully someone else will
come up with another approach. Here a toy example: 1. calculate the mean for
each name in your second column by using tapply or others, 2. determinate
which names are repeated = 2 times, 3. match the names of the
Leon Yee wrote:
Gustaf Rydevik wrote:
Hi Leon,
unique(x)
or
duplicated(x)
should work, depending on what you want.
Best,
Gustaf
Hi,
Thank you all. Actually, I have a data frame or matrix, whose first
column is numerical values, and whose 2nd column is names.
Then you
ear all,
This is my first time using this listserv and I am seeking help from the
expert. OK, here is my question, I am trying to use impute.knn function
in impute library and when I tested the sample code, I got the error as
followingt:
Here is the sample code:
library(impute)
On Wed, Oct 29, 2008 at 3:45 PM, Erik Iverson [EMAIL PROTECTED] wrote:
Leon Yee wrote:
Gustaf Rydevik wrote:
Hi Leon,
unique(x)
or
duplicated(x)
should work, depending on what you want.
Best,
Gustaf
Hi,
Thank you all. Actually, I have a data frame or matrix, whose first
Dear all,
Yes, indeed my knowledge in statistics is rather limited, but let me
reformulate my question. I have two samples (V1 and V2) of measurements of
observed physical values( v1_i and v2_i). Each value in the samples is
measured with an error (err_i), so it is in interval (v1_i-err_i,
Dear R experts..
I am trying to understand what exactly strptime and strftime do...
Where can I look for the detailed notes on these two functions? In addition,
how POSIX functions like POSIXct and POSIXlt are used in these functions?
Regards,
Santosh
[[alternative HTML version
?strptime gives the percent codes and R News 4/1 has an article
on dates with a table at its end containing many examples.
On Wed, Oct 29, 2008 at 11:03 AM, Santosh [EMAIL PROTECTED] wrote:
Dear R experts..
I am trying to understand what exactly strptime and strftime do...
Where can I look
Hello,
I've got a function that takes a numeric vector (x), computes a
transformation value (myAttr) for x, transforms x according to myAttr
and then sets myAttr as an attribute of x before returning x, so I can
easily know what myAttr was used (basically it's a power transformation
and myAttr is
Hello all
I am working with the package multcomp but I have problems with the function
simtest; the program say that can not find this function, nevertheless I
doesn't have any problem with the function glht that it is in the same package.
Someone knows what could be the problem?
Thank you
Hello,
I am having problems in reading appropriately a huge .prn file of almost
450.000 rows and 29 columns.
The variables are consisted of characters, dates, time, numeric values.
I use read.table(file.prn, header=F, sep=\t, na.strings=*), where the
missing values are declared as *.
The R
Hello,
is there a R function or package containing a similar functionality then
the SAS PROC SURVEYSELECT?
Thanks
Markus
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
I would guess that your separator is not really a tab like you think
it is. Take a small subset of the data, bring it up in a text editor,
check the contents and then try to read it. Always start small to see
if it is working the way you think it should. Also it seem to have a
header, so why
On Wed, Oct 29, 2008 at 06:19:51PM +0200, [EMAIL PROTECTED] wrote:
I am having problems in reading appropriately a huge .prn file of almost
450.000 rows and 29 columns. The variables are consisted of characters,
dates, time, numeric values. I use read.table(file.prn, header=F,
sep=\t,
jim holtman wrote:
I would guess that your separator is not really a tab like you think
it is. Take a small subset of the data, bring it up in a text editor,
check the contents and then try to read it. Always start small to see
if it is working the way you think it should. Also it seem to
Dear R-users,
Using Maximum-likelihood Fitting (fitdistr function) I've got the next
error:
fitdistr(datos,weibull,lower=0)
Error in optim(x = c(1.4625e-06, 0.257854, 0.0001217545, 0.11421005,
0.028721576, :
L-BFGS-B *needs finite values of 'fn' *
where datos is a vector of length=1000
Hi Markus,
is there a R function or package containing a similar functionality then
the SAS PROC SURVEYSELECT?
I think you need the sampling package
http://cran.r-project.org/web/packages/sampling/index.html
It is a package accompanying the book
Tillé, Y. (2006). Sampling Algorithms, New
Again thanks for the input. I've been a recipient of this list for
quite a few years although I don't post often. It is an invaluable
resource and I appreciate the effort of all the contributors. I support
a lot of software so I know how much work it can be.
I've seen the reproducible code
I have tried installing R on a web server on which I have a user
account but not root access.
I checked and the PERL, Fortran, etc. prerequisites all seem in order.
The compiling of R with:
% ./configure --with-x=no
This works fine without errors.
I try a make check, however, and soon get an
Hi,
I have a question about how I should report the results for a linear
mixed effects model where the model includes as predictors three
factors (facA, facB and facC), one of which (facA) interacts with the
other two. facA and facB have two levels and facC has 3 levels. There
are also several
Hi,
I would like to impose an inequality constraint on one of the regression
parameters of a panel linear model. How can I do that?
Thanks for your help,
Sara
_
[[elided Hotmail spam]]
[[alternative HTML version deleted]]
Dear friends
I am analysing the leaf expansion of a grass species and am interested in
the speed of expansion. I produced exponential models for each of the
treatments and got the equation for leaf size in function of time. I want to
compare the coeficients that gives the initial inclination of
Ok, I've placed the input files and the PDF on a website (I apologize
for attaching the PDF -- the readme guide for this listserv indicated
that PDFs were fine):
http://www.cstars.ucdavis.edu/~jongreen/temp/
The full suite of commands I used are:
Dear List,
I need a barplot with vertical bars. Each bar should have a label.
The problem is, that the labels are too long, so they overlap, or
only every seccond label is displayed in the output.
Here is a little syntax:
dd - c(100,110,90,105,95)
barplot(dd,names.arg=c('Conduct
Try this:
nm - c('Conduct Disorders','Attention Deficit', 'Eating
Disorders','Substance Abuse','Developmental Disorders')
barplot(dd, names.arg = gsub( , \n, nm))
On Wed, Oct 29, 2008 at 4:43 PM, Udo [EMAIL PROTECTED] wrote:
Dear List,
I need a barplot with vertical bars. Each bar should have
Hi there,
I am trying to have a connectivity graph (two plots at once) in R:
this is an example:
x1=sin((0:100)*2*pi/100)
y1=cos((0:100)*2*pi/100)
plot(x1,y1)
will draw a circle and
x2=c(1,9,3,4,8,4,2,0)
y2=c(3,6,8,2,4,1,9,6)
plot(x2,y2,type=b)
will draw a graph with corresponding x's and
Udo,
You can try inserting a newline where you need the break in your labels:
dd.names - c('Conduct Disorders','Attention Deficit', 'Eating Disorders',
'Substance Abuse','Developmental Disorders')
dd.names.2 - sapply(dd.names, function(x) gsub(\\s, \\\n, x))
barplot(dd, names.arg=dd.names.2)
Thanks a lot, Henrique and Christos!
It works fine
Quoting Christos Hatzis [EMAIL PROTECTED]:
Udo,
You can try inserting a newline where you need the break in your labels:
dd.names - c('Conduct Disorders','Attention Deficit', 'Eating Disorders',
'Substance Abuse','Developmental
On Wed, 29 Oct 2008 10:49:03 -0700,
Jeff Laake [EMAIL PROTECTED] wrote:
Again thanks for the input. I've been a recipient of this list for
quite a few years although I don't post often. It is an invaluable
resource and I appreciate the effort of all the contributors. I
support a lot of
#How about this?
x1=6*(sin((0:100)*2*pi/100))+4
y1=6*(cos((0:100)*2*pi/100))+4
plot(x1,y1)
x2=c(1,9,3,4,8,4,2,0)
y2=c(3,6,8,2,4,1,9,6)
lines(x2,y2,type=b)
On Wed, Oct 29, 2008 at 2:48 PM, Alex99 [EMAIL PROTECTED] wrote:
Hi there,
I am trying to have a connectivity graph (two plots at once) in
I have included data at the bottom of this email. It can be read in by
highlighting the data and then using this command: dat -
read.table(clipboard, header = TRUE,sep=\t)
I can obtain solutions with both of these:
library(gee)
fit.gee-gee(score ~ chem + time, id=id,
I need some help with sub-setting my data. I am trying to divide a data frame
into multiple data frames based on the year collected, and stored in a list
with each new data frame labeled with year X where X is the year the data was
collected. When I run my current code I get nine error
?split.
Hadley
On Wed, Oct 29, 2008 at 3:22 PM, t c [EMAIL PROTECTED] wrote:
I need some help with sub-setting my data. I am trying to divide a data
frame into multiple data frames based on the year collected, and stored in a
list with each new data frame labeled with year X where X is the
Sorry. I did not output the NAs correctly.
dat - read.table(clipboard, header = TRUE)
id treat time1 time2 time3 time4 chem1 chem2 chem3 chem4 time score chem
1 1 20 18 15 15 1000 1100 1200 1300 0 20 1000
1 1 20 18 15 15 1000 1100 1200 1300 2 18 1100
1 1 20 18 15 15 1000 1100 1200 1300 3 15 1200
I found there's a very good functional set of operations in R, such as
apply family, Hadley Wickham's lovely plyr, etc. There's even a
Reduce (a.k.a. fold). Now I wonder how can we do pattern-matching?
E.g., now I split dimensions like this:
m - dim(V)[1] # R
n - dim(V)[2]
Dear R People:
Here is a toy example:
x - c(2E,5W,12H)
substr(x,2,2)
[1] E W 2
Sometimes x has 3 elements, sometimes 2. I want to extract the last
element, and then extract the other 1 or 2 elements.
How can I do this, please?
TIA,
Sincerely,
Erin
--
Erin Hodgess
Associate Professor
## untested
last - tail(x, n = 1)
first - head(x, n = length(x) - 1)
Erin Hodgess wrote:
Dear R People:
Here is a toy example:
x - c(2E,5W,12H)
substr(x,2,2)
[1] E W 2
Sometimes x has 3 elements, sometimes 2. I want to extract the last
element, and then extract the other 1 or 2 elements.
Try this:
library(gsubfn)
## The last character
strapply(x, (.)$, simplify = TRUE)
## The last two character
strapply(x, (..)$, simplify = TRUE)
On Wed, Oct 29, 2008 at 6:57 PM, Erin Hodgess [EMAIL PROTECTED]wrote:
Dear R People:
Here is a toy example:
x - c(2E,5W,12H)
substr(x,2,2)
How about
x - c(2E,5W,12H)
substr(x, nchar(x), nchar(x))
[1] E W H
substr(x, 1, nchar(x)-1)
[1] 2 5 12
-- David
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Erin Hodgess
Sent: Wednesday, October 29, 2008 3:58 PM
To: [EMAIL PROTECTED]
Subject:
on 10/29/2008 03:57 PM Erin Hodgess wrote:
Dear R People:
Here is a toy example:
x - c(2E,5W,12H)
substr(x,2,2)
[1] E W 2
Sometimes x has 3 elements, sometimes 2. I want to extract the last
element, and then extract the other 1 or 2 elements.
How can I do this, please?
TIA,
On 30/10/2008, at 9:08 AM, Juliet Hannah wrote:
I have included data at the bottom of this email. It can be read in by
highlighting the data and then using this command: dat -
read.table(clipboard, header = TRUE,sep=\t)
I can obtain solutions with both of these:
library(gee)
Title says it all remember cast() with sum as the aggregation function
--
Stephen Sefick
Research Scientist
Southeastern Natural Sciences Academy
Let's not spend our time and resources thinking about things that are
so little or so large that all they really do for us is puff us up and
make us
On 30/10/2008, at 10:46 AM, [EMAIL PROTECTED] wrote:
I usually just run my R programs at the R command prompt but for my
latest one I want to save any output that gets written to the
screen so
I am
trying to use R CMD BATCH and send the output to an output file. I
realize I could use sink
Susana Zuloaga wrote:
Hello all
I am working with the package multcomp but I have problems with the function
simtest; the program say that can not find this function, nevertheless I doesn't have any problem with the function glht that it is in the same package.
Someone knows what could be
Luis SAGAON TEYSSIER luis.sagaon_teyssier at etumel.univmed.fr writes:
Dear all,
I'm trying to estimate some parameters with the optim() function but I
need to restrict one parameter and I have not found how to do it.
Could you help me please?
Thought someone else would answer by
On 29/10/2008 4:39 PM, Alexy Khrabrov wrote:
I found there's a very good functional set of operations in R, such as
apply family, Hadley Wickham's lovely plyr, etc. There's even a
Reduce (a.k.a. fold). Now I wonder how can we do pattern-matching?
E.g., now I split dimensions like this:
Hi Phil: That's EXACTLY what it is. Thanks so much. It's nice to know
that the R Gods don't hate me. I hope it's okay that I'm going to cc
r-help
in case this thread comes up in the future and also so that other people
who might want to help know that it's solved. Thanks again.
On Wed,
thanks Rolf. Yes, I meant temp.R. I was going to use test.R but then
I realized that I already had a program named that. I think the R gods
are
really hating me !!! it's a very odd thing. I'll grep the file
because maybe the output is in there somewhere and i'm missing it ?
On Wed,
sorry guys. I have a cold and I am not thinking very clearly
On Wed, Oct 29, 2008 at 5:50 PM, stephen sefick [EMAIL PROTECTED] wrote:
Title says it all remember cast() with sum as the aggregation function
--
Stephen Sefick
Research Scientist
Southeastern Natural Sciences Academy
Let's
Here is an example given from
?yags
library(methods)
data(stackloss)
Y1 - yags(stack.loss~Air.Flow,id=1:21, data=stackloss)
How can I access parts of the output.
I tried:
str(Y1)
Formal class 'yagsResult' [package yags] with 25 slots
..@ coefficients : num [1:2] -44.13 1.02
..@
Hi,
I have several time series that I need to plot on the same plot.
There are 3 problems with these series:
1. they do not start or end at the same times
2. they have different time intervals (seconds, minutes or hours)
3. they all have random missing time steps of a few step to longer
periods
why not look at the zoo package it can deal with time irregular time
series. I have used it and I have been very happy.
On Wed, Oct 29, 2008 at 5:52 PM, Levy,Ilan [Ontario] [EMAIL PROTECTED] wrote:
Hi,
I have several time series that I need to plot on the same plot.
There are 3 problems with
Hi,
I am dealing with the following problem. There are two biochemical assays,
say A and B, available for analyzing blood samples. Half the samples have
been analyzed with A. Now, for some insurmountable logistic reasons, we
have to use B to analyze the remaining samples. However, we can do
On 30/10/2008, at 11:48 AM, Juliet Hannah wrote:
Here is an example given from
?yags
library(methods)
data(stackloss)
Y1 - yags(stack.loss~Air.Flow,id=1:21, data=stackloss)
How can I access parts of the output.
I tried:
str(Y1)
Formal class 'yagsResult' [package yags] with 25 slots
Just remember that the Linux kernel is also licensed under GPL v2.
I am not sure if you pay for your Linux distribution. But for many gov
sites and for my copy of Linux, they just use Linux as a completely
free product -- in the sense that no money needs to be paid to a
company or anyone.
Assuming that by elements you mean characters (2E is the first
element of x but E is the last character in x[1]) then this will
create a character matrix of dimensions: length(x) by 2
such that each row corresponds to one component of x
and the second column in that row holds its last character
Using the list function defined here:
http://tolstoy.newcastle.edu.au/R/help/04/06/1430.html
list[m, n] - as.list(dim(iris))
mylist - as.list(1:5)
list[Head, Tail] - list(mylist[[1]], mylist[-1])
On Wed, Oct 29, 2008 at 4:39 PM, Alexy Khrabrov [EMAIL PROTECTED] wrote:
I found there's a very
I have a large matrix which is divided into several pieces, manipulated
individually, and saved into RData in disc. After each pieces are done with
operation, I load them into memory and use rbind to stack them back into
matrix. however, the rbind is only give me the last two pieces. The
Hi,
I'm posting yet another question about tcltk since I'm still struggling
with the package. I'm trying to create a tklistbox and a ttkcombobox on
the same parent and am having a problem. Here's an example:
library(tcltk)
tt - tktoplevel()
tcl1 - tclVar()
tcl2 - tclVar()
tclObj(tcl1) -
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