On 1/12/09, Ptit_Bleu ptit_b...@yahoo.fr wrote:
Hello and Happy New Year to all R-Users !!!
I would like to plot a lattice graph with a logarthmic y axis and add two
reference lines that is :
ref-c(0.0070, 0.0096)
graph1-xyplot(data$y1 ~ as.numeric(strptime(data$x1, format=%Y-%m-%d
Hello R List,
I seem to have a peculiar problem. When using time series data, I get
the following error when running the acf and pacf function.
Using the function acf(dtxts,plot= TRUE,xaxt = n,col=red,na.action
= na.omit) (where dtxts is a time series object created with package
xts ) results in
when reading R's fullrefman.pdf (available from
http://cran.r-project.org/doc/manuals/fullrefman.pdf) in Mac OS X's
preview.app (version 4.1, on Mac OS 10.5.x), if i try to do a keyword
search within the document, the indexing step freezes about 2/3 the
way through the progress bar. this
G'Day R users!
Following an ordination using prcomp, I'd like to test which variables
singnificantly contribute to a principal component. There is a method
suggested by Peres-Neto and al. 2003. Ecology 84:2347-2363 called
bootstrapped eigenvector. It was asked for that in this forum in
Dear R experts,
I'm trying to call 'pchisq' from within a C subroutine. The following
error is returned:
** NON-convergence in pgamma()'s pd_lower_cf() f= nan.
This error message is not printed the first time I call 'pchisq' from
the C subroutine, but the second time or the next time I call
Rolf Turner wrote:
On 19/01/2009, at 10:44 AM, Gabor Grothendieck wrote:
Well, that's why it was only provided when you insisted. This is
not what regexp's are good at.
On Sun, Jan 18, 2009 at 4:35 PM, Rau, Roland r...@demogr.mpg.de wrote:
Thanks! (I have to admit, though, that I expected
Axel Strauß schrieb:
G'Day R users!
Following an ordination using prcomp,
Sorry, correction. I mean using princomp.
I'd like to test which variables singnificantly contribute to a
principal component. There is a method suggested by Peres-Neto and al.
2003. Ecology 84:2347-2363 called
Hi,
I installed JRI in my 64bit linux.
And when i run the test case in JRI, it turns out such Exception:
JNI_GetCreatedJavaVMs said there's no JVM running!
Exception in thread Thread-1 java.lang.NullPointerException
at org.rosuda.JRI.Rengine.setupR(Rengine.java:131)
at
Stavros Macrakis wrote:
On Sun, Jan 18, 2009 at 2:22 PM, Wacek Kusnierczyk
waclaw.marcin.kusnierc...@idi.ntnu.no wrote:
x[-grep(abc, x)]
which unfortunately fails if none of the strings in x matches the pattern,
i.e., grep returns integer(0);
Yes.
arguably, x[integer(0)]
I don't get the error, but I assume it's because your C function returns a
double and .C() assumes it is a void function.
-thomas
On Mon, 19 Jan 2009, Jeremy Silver wrote:
Dear R experts,
I'm trying to call 'pchisq' from within a C subroutine. The following
error is returned:
**
Hi Alex,
I presume you've asked Jari what the bug is? He obviously knows and you
are asking a lot for the rest of us to i) know the method you speak of
and ii) debug the code of another.
As an alternative, try function testdim() in the ade4 package. This
implements the method of Dray:
Dray, S
On Mon, 2009-01-19 at 09:54 +0100, Jeremy Silver wrote:
Dear R experts,
(...)
pchisq(5.464342,1,lower.tail = FALSE)
[1] 0.01940836
reproduceError(5.464342)
stat = 5.464342, p = 0.019408
pchisq(5.464342,1,lower.tail = FALSE)
[1] NaN
Warning messages:
1: In pchisq(5.464342,
oops. . . . Turning it into a void function fixed the problem!
Thanks.
Jeremy
Thomas Lumley wrote:
I don't get the error, but I assume it's because your C function
returns a double and .C() assumes it is a void function.
-thomas
On Mon, 19 Jan 2009, Jeremy Silver wrote:
Dear R
On Mon, 19 Jan 2009, Rolf Turner wrote:
On 19/01/2009, at 10:44 AM, Gabor Grothendieck wrote:
Well, that's why it was only provided when you insisted. This is
not what regexp's are good at.
On Sun, Jan 18, 2009 at 4:35 PM, Rau, Roland r...@demogr.mpg.de wrote:
Thanks! (I have to admit,
you could take a look at this:
http://www.omegahat.org/RSPerl/
but I'm not sure how well maintained it is currently.
adam
On 19 Jan 2009, at 02:00, ANJAN PURKAYASTHA wrote:
Hi,
I'm planning to access R from my perl scripts.
The only noteworthy bridge seems to be
Gabriel Margarido gramarga at gmail.com writes:
... I looked for a way to return the values
without copying (even tried Rmemprof), but without success. Any ideas?
...
I solved similar problems using the R.oo package, which emulates
pass-by-reference semantics in 'R'.
HTH
Keith
Please consider the following toy data matrix example, called x
for simplicity. There are 20 different individuals (ID), with
information about the alleles (A,T, G, C) at six different loci
(Locus1 - Locus6) for each of these 20 individuals. At any
single locus (e.g., Locus1 or Locus2,
Hi All
How can you associate names with a list when names have not been
assigned? For example if you have a list like this:
list2-list(1,2,3)
list2
[[1]]
[1] 1
[[2]]
[1] 2
[[3]]
[1] 3
How do you make it look like this with names? :
f1-1
f2-2
f3-3
list1-list(name1=f1, name2=f2, name3=f3)
If I understand correctly:
names(list2) - paste(name, 1:3, sep = )
On Mon, Jan 19, 2009 at 10:23 AM, john seers (IFR)
john.se...@bbsrc.ac.ukwrote:
Hi All
How can you associate names with a list when names have not been
assigned? For example if you have a list like this:
I have used glm and stepAIC to choose a best model. I can use termplot to
assess the contribution of each explanatory variable in the glm. However
the final model after running stepAIC includes interaction terms, and when I
do termplot I get Error in `[.data.frame`(mf, , i) : undefined columns
Thanks Henrique and Nathalie for your answers.
Very strange - I thought I had tried that and it had not worked so I came to
the conclusion that names did not work on lists. Now it does work, so I must
have had some finger trouble.
Regards
John
---
From: Henrique
On Thu, Jan 8, 2009 at 11:25 AM, René J.V. Bertin rjvber...@gmail.com wrote:
Hello - and happy newyear to all of you!
I've got some data that I'm plotting with bwplot, a 3x2x3 design where
the observable decreases with the principle independent factor, but at
different rates.
I'd like to
You might want to look at the 'quantreg' package, written by Roger Koenker,
in CRAN. The associated vignette has many examples.
Abuzer Bakis wrote:
Dear All,
I am economist and working on poverty / income inequality. I need
descriptive
statitics like the ratio of education
Hi all,
I am struggling with a strange issue in R that I have not encountered
before and I am not sure how to resolve this.
The model looks like this, with all irrelevant variables left out:
LABOUR - a dummy variable
NONLABOUR = 1 - LABOUR
AGE - a categorical variable / factor
VOTE - a dummy
It would be helpful to have a reproducible dataset to track down what
is happening.
On Mon, Jan 19, 2009 at 3:45 AM, Harsh singhal...@gmail.com wrote:
Hello R List,
I seem to have a peculiar problem. When using time series data, I get
the following error when running the acf and pacf
Very Sorry for the oversight.
The dataset that I have used is:
Sunspots,Datefield
9.5,1/1/1900
2.7,1/1/1901
5,1/1/1902
24.4,1/1/1903
42,1/1/1904
63.5,1/1/1905
53.8,1/1/1906
62,1/1/1907
48.5,1/1/1908
43.9,1/1/1909
18.6,1/1/1910
5.7,1/1/1911
3.6,1/1/1912
1.4,1/1/1913
9.6,1/1/1914
47.4,1/1/1915
power.law.fit simply ML fits the 'prob(d) = d^\alpha' model to the
input, where d is positive integer. It seems to work for me:
data - sample(1:1, prob=(1:1)^-3, rep=TRUE)
power.law.fit(data)
Call:
mle(minuslogl = mlogl, start = list(alpha = start))
Coefficients:
alpha
3.017056
Dear Jos,
In R you don't need to create you own dummy variables. Just create a
factor variable LABOUR (with two levels) and rerun your model. Then you
should be able to calculate all coefficients.
HTH,
Thierry
ir.
On Mon, 19 Jan 2009, stephen sefick wrote:
It would be helpful to have a reproducible dataset to track down what
is happening.
True.
Although in this case it's relatively easy to guess what went wrong.
The user probably has some irregular series, for example daily with
missing days:
x
The statement to read in the data is missing from your post but
I suspect that you are representing the data as daily data so its filling
in 364 or 365 NA's between points. Represent it as the annual data
that it is. Try this:
Lines - Sunspots,Datefield
9.5,1/1/1900
2.7,1/1/1901
5,1/1/1902
On 1/19/2009 8:51 AM, hadley wickham wrote:
On Thu, Jan 8, 2009 at 11:25 AM, René J.V. Bertin rjvber...@gmail.com wrote:
Hello - and happy newyear to all of you!
I've got some data that I'm plotting with bwplot, a 3x2x3 design where
the observable decreases with the principle independent
On Mon, 19 Jan 2009, Gabor Grothendieck wrote:
The statement to read in the data is missing from your post but
I suspect that you are representing the data as daily data so its filling
in 364 or 365 NA's between points. Represent it as the annual data
that it is.
One further pointer: Also
Dear Bob,
Take a look at the effects package, described in
http://www.jstatsoft.org/v08/i15/paper.
I hope this helps,
John
--
John Fox, Professor
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
web: socserv.mcmaster.ca/jfox
-Original
Hello,
Sweave seems to have trouble processing german letters in R.
For example, my noweb R-input looks like this.
=
Oberflächenfehler = c(4, 11, 6, 2, 7, 9)
@
If I send it through Sweave, I get the following error message.
error: chunk 1
Error in parse(text = chunk) : unexpected input in
Hi Jim,
This is clearly the function I need to use. However, I am new to Rplot
and coding. I know that my output image is not what the data
indicate. My input file is a matrix, where the first row is the
residue number (10 values), and the second row is the hydrophathy
values (10 corresponding
Hi Thierry,
Thanks for your quick answer. The problem is not so much the LABOUR
variable, however, but the AGE variable, which consists of about 5
categories for which I do indeed not create separate dummy variables.
But R does not behave as expected when deciding on which dummy to use
as
mmuurr[AT]gmail.com wrote:
.
has anyone else experienced this? i sent in a bug report to Apple,
but i doubt i'll see any change in preview.app prior to the next OS
release. fullrefman.pdf is also the only document that i've ever
observed this behavior with, and since i can now
Hi Gerrit,
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Gerrit Voigt
Sent: Monday, January 19, 2009 4:48 PM
To: r-help@r-project.org
Subject: [R] Sweave encoding problem
Hello,
Sweave seems to have trouble processing
Dear UseRs,
I am having some problems using R with WinBUGS using the R2WinBUGS
package. Specifically, when I try to run bugs() I get the following
message.
Error in FUN(X[[1L]], ...) :
.C(..): 'type' must be real for this format
To give a little more context, my bugs() command (for a
G'day Jos,
On Mon, 19 Jan 2009 15:52:00 +
Jos Elkink jos.elk...@ucd.ie wrote:
Thanks for your quick answer. The problem is not so much the LABOUR
variable, however, but the AGE variable, which consists of about 5
categories for which I do indeed not create separate dummy variables.
But R
Hi Jos,
you can force R to set contrasts for factors the way you like them with
contrasts(). You seem to be thinking of treatment contrasts, which are
most easily interpreted, but there are also others.
However: are you sure you want to bin an age variable into categories?
You will lose
I don't know if there are bugs in the code, but the step 4) does not
compute significance... at least the way statisticians know it. The
fractions above or below 0 are not significance. I don't even know how
to call those... probably cdf of the bootstrap distribution evaluated
at zero.
Let's put
Jos,
See ?relevel for information on how to reorder the levels of a factor,
while being able to specify the reference level.
Basically, the first level of the factor is taken as the reference. If
you want to utilize a different ordering, as an alternative to the
above, simply use:
AGE -
I am having a hard time understanding what is happening with ifelse.
Let me illustrate:
h - numeric(5)
p - 1:5
j - floor(j)
x - 1:1000
ifelse(h == 0, x[j+2], 1:5)
[1] 2 3 4 5 6
My question is, shouldn't this be retruning 25 numbers? It seems that the
ifelse should check 5 values of h for
Dear all,
I have a simple question which I unfortunately do not seem to be able
to solve myself. I have a (NxK) matrix and want to generate a new
matrix by multiplying each row with itself such that the new matrix
has dimension ((N*K)xK) (or better, generate an array with dimension
(K,K,N)). I
Gabor Grothendieck wrote:
Note that
rm(i)
for(j in 1:4) F(j)
raises an error due to scoping issues.
Yes. This has nothing to do with lazy evaluation, and everything to do
with scoping: f is not defined in the scope of F, so does not know about
its variables (nor those in the implicit loop
On Mon, Jan 19, 2009 at 12:40 PM, Peter Dalgaard
p.dalga...@biostat.ku.dk wrote:
Gabor Grothendieck wrote:
Note that
rm(i)
for(j in 1:4) F(j)
raises an error due to scoping issues.
Yes. This has nothing to do with lazy evaluation, and everything to do with
scoping: f is not defined in
Try this:
matrix(apply(u, 1, tcrossprod), nr = nrow(u)*ncol(u), byrow = T)
On Mon, Jan 19, 2009 at 3:39 PM, Stephan Lindner lindn...@umich.edu wrote:
Dear all,
I have a simple question which I unfortunately do not seem to be able
to solve myself. I have a (NxK) matrix and want to generate
Dear Stephan,
Try this:
do.call(rbind,lapply(1:2,function(x) matrix(u[x,]%*%t(u[x,]),ncol=ncol(u
HTH,
Jorge
On Mon, Jan 19, 2009 at 12:39 PM, Stephan Lindner lindn...@umich.eduwrote:
Dear all,
I have a simple question which I unfortunately do not seem to be able
to solve myself. I
Dear list,
I'm trying to download a text file directly from the internet using the RCurl
package and the command getURL. Duncan Lang graciously helped me solve the
first step in this problem using the following command:
#
txtfile -
On Mon, 19 Jan 2009, rkevinbur...@charter.net wrote:
I am having a hard time understanding what is happening with ifelse.
Let me illustrate:
h - numeric(5)
p - 1:5
j - floor(j)
And j is 0:4 + epsilon , where 0 = epsilon 1, evidently.
x - 1:1000
ifelse(h == 0, x[j+2], 1:5)
[1] 2 3 4 5 6
If you are having problems with the default download.file method you
can try method = wget:
f -
ftp://ftp.wcc.nrcs.usda.gov/data/snow/snow_course/table/history/idaho/13e19.txt;
download.file(f, basename(f), method = wget)
On Mon, Jan 19, 2009 at 1:26 PM, zack holden zack_hol...@hotmail.com
Hello,
I am trying to access several netCDF files that are also zipped (via
gzip I guess) (and stored in a directory that I only have reading
permit)
I tried to unzip them using gzfile, gzcon, etc, and then open them
with open.ncdf (from ncdf package). Everything was unsuccesful.
I had no
Peter Dalgaard wrote:
snip
Notice also that in
lapply(1:4,function(i) F(i))
it would be pretty weird if lapply would behave differently depending
on the name of formal arguments of the function, i.e. if
lapply(1:4,function(meep) F(meep))
gave a different result. And f() depends on
Hello,
I have a question regarding the candisc package. My data are:
speciesthreefive
12.956.63
12.537.79
13.575.65
13.165.47
22.584.46
22.166.22
23.273.52
I put these in a table and then a linear model
newdata - lm(cbind(three,
Dear All:
Greetings!
I am able to produce an xyplot in R; But I am not able to put multiple
legends on it! So for that matter, I have saved the xyplot and reproduced
the same using the simple plot option. Then using the legend option I
successfully placed the require text and its
you could take a look at this:
http://www.omegahat.org/RSPerl/
but I'm not sure how well maintained it is currently.
adam
On 19 Jan 2009, at 02:00, ANJAN PURKAYASTHA wrote:
Hi,
I'm planning to access R from my perl scripts.
The only noteworthy bridge seems to be
Dear Brian,
I looked on the internet for this warning message Warning message:
'newdata' had X rows but variable(s) found have Y rows that happens
when using some kind of fitting and prediting. I still can't figure out
what is going wrong by reading the documentation or the posts in de
forum.
hello dieter,
sorry for the late reply...
yes my homework needs to be done in R and thats y i have these questions
posted in this forum...hope u reply me the solutions and also thank you for
spending ur precious time in my problem...
BR
sankar.
Dieter Menne wrote:
sankar82
Thanks for all the answers. I'll have a look at ggplot2. I'd seen the
possibility to set panel-specific limits via ylim, but I was in fact
looking for a switch to achieve non-global automatic scaling.
Given the fact that there is no built in provision for that, I take it
it's a functionality that
It's a fixed width format, with irregular entries, perhaps something
along the lines of:
read.fwf(textConnection(txtfile), skip = 8, # skips the header
widths = column widths vector,
colnames= colnames ,
nrows=48 )#drops the trailing summary text
perhaps :
Thanks for all the answers. I'll have a look at ggplot2. I'd seen the
possibility to set panel-specific limits via ylim, but I was in fact
looking for a switch to achieve non-global automatic scaling.
Given the fact that there is no built in provision for that, I take it
it's a functionality that
I am having difficulty getting the trend.spatial function in geoR to
work properly. After creating a trend.spatial object with a covariate,
I try to add the command into my likfit() function as follows:
trend1.trend.spatial - trend.spatial(1st, trend1.geodata)
trend1.spatial.EC0.1.reml -
Sorry I didn't give the proper initialization of j. But you are right j should
also be an array of 5. So x[j + 5] would return 5 values.
So if the array returned from 'ifelse' is the same dimention as test (h), then
are all the values of h being tested? So since h as you say has no dimensions
Dear list,
I would like to plot arrows with different colors according to arrow length,
and also (if
possible) with head size proportional to arrow length. The idea is to make a
quiver-like plot of
matlab with wind speed data.
So far, I´ve been able to use different colors, but I need to find
Hi all,
Thanks for the advice.
See ?relevel for information on how to reorder the levels of a factor,
while being able to specify the reference level.
Basically, the first level of the factor is taken as the reference.
Yes, that is how I always used it. But the problem is, in this
particular
Dear all,
Suppose that I have a matrix A
A - matrix(c(3,3,3,3,3,3,3,3,3),3,3)
and a logical matrix B
B - matrix(c(T,T,T,F,T,T,F,T,F),3,3)
The result matrix should be
C - matrix(c(3,3,3,NA,3,3,NA,3,NA),3,3)
Is there any simple tip or trick to perform this without looping?
Thanks
try this:
A - matrix(c(3,3,3,3,3,3,3,3,3),3,3)
B - matrix(c(T,T,T,F,T,T,F,T,F),3,3)
C - A
C[!B] - NA
C
I hope it helps.
Best,
Dimitris
Andrej Kastrin wrote:
Dear all,
Suppose that I have a matrix A
A - matrix(c(3,3,3,3,3,3,3,3,3),3,3)
and a logical matrix B
B -
Hi Jos,
does explicitly recoding AGE help?
AGE - factor(c(65+,18-24,18-24,25-34))
str(AGE)
AGE -
factor(c(65+,18-24,18-24,25-34),levels=c(65+,18-24,25-34))
str(AGE)
Best,
Stephan
Jos Elkink schrieb:
Hi all,
Thanks for the advice.
See ?relevel for information on how to reorder the
On 20/01/2009, at 9:48 AM, Andrej Kastrin wrote:
Dear all,
Suppose that I have a matrix A
A - matrix(c(3,3,3,3,3,3,3,3,3),3,3)
and a logical matrix B
B - matrix(c(T,T,T,F,T,T,F,T,F),3,3)
The result matrix should be
C - matrix(c(3,3,3,NA,3,3,NA,3,NA),3,3)
Is there any simple
Use the is.na() function to assign
NA values:
is.na(A) - !B
A
[,1] [,2] [,3]
[1,]3 NA NA
[2,]333
[3,]33 NA
C - matrix(c(3,3,3,NA,3,3,NA,3,NA),3,3)
all.equal(A, C)
[1] TRUE
Steven McKinney
Statistician
Molecular Oncology and Breast Cancer Program
On Jan 19, 2009, at 3:54 PM, Dimitris Rizopoulos wrote:
try this:
A - matrix(c(3,3,3,3,3,3,3,3,3),3,3)
B - matrix(c(T,T,T,F,T,T,F,T,F),3,3)
C - A
C[!B] - NA
C
Very elegant. Another, perhaps less elegant, effort:
B[which(B == FALSE)] - NA
B
[,1] [,2] [,3]
[1,] TRUE NA NA
[2,]
Thank you very much, Göran!
I had to install R 2.8.1 since it did not work with 2.4.1.
This is exactly what I wanted, now I can move on with my analysis! (And
learn more about cencoring...)
Best regards,
Mattias
__
R-help@r-project.org mailing list
Hi ...
I wonder if anyone can provide some insight into why the first three
examples using the sunriset function (appended below, with results) give
the correct answer, but the fourth generates and error.
The first two use ISOdatetime with and without a time zone attribute,
and the sunriset
On 20/01/2009, at 10:05 AM, David Winsemius (who should know better)
wrote:
snip
B[which(B == FALSE)] - NA
snip
This sort of syntax drives me, and all right-thinking people,
subclinically neurotic
(or as a psychiatrist would say, stark staring bonkers).
Admittedly
Look at the my.symbols function in the TeachingDemos package (along with the
ms.arrows function in the same package), that may do what you want.
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original
Thanks for your help David. I managed to track down this solution in regard
to the second question:
http://www.nabble.com/lattice-xyplot-with-bty%3D%22l%22-tt12486052.html#a12489170
Regards,
James
David Winsemius wrote:
On Jan 15, 2009, at 9:27 PM, jimdare wrote:
Dear R-Users
I don't know if it is the same algorithm or not, but there is the function
chull that finds the convex hull.
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From:
I think the fact that the grid package does not support cross-hatching is a
feature not a bug (or deficiency), and I hope that this is not fixed.
Tufte's book (The Visual Display of Quantitative Information) has a section on
why cross-hatching should be avoided (unless of course your goal is
Well spotted, the b is a muck up (what happens when you are basing stuff on
someone else's code). The bit you though might be a dimension mismatch seems
to work ok, but the bit that I was worried about from the start doesn't; the
reason I have sqrt of var y/ var x is because my posterior is for a
@ Stas
Thanks for the extensive answer! I squeezed my data in your function but
still need to mull over it and your comments for some time.
спасибо,
Axel
Stas Kolenikov schrieb:
I don't know if there are bugs in the code, but the step 4) does not
compute significance... at least the way
Hi All,
I have a small dataframe [dates, values) I am plotting with
plot(df,type=²l²)
And the date date covers a year. The graph only have marks at 2008¹ and
2009¹.
How do I get the months labeled at the bottom please
Thanks as always
Glenn
[[alternative HTML version deleted]]
?axis
On Mon, Jan 19, 2009 at 6:39 PM, glenn g1enn.robe...@btinternet.com wrote:
Hi All,
I have a small dataframe [dates, values) I am plotting with
plot(df,type=²l²)
And the date date covers a year. The graph only have marks at Œ2008¹ and
Œ2009¹.
How do I get the months labeled at the
Hi,
I am currently writing some own functions that I frequently need.
So, it would be perfect if I could load these functions at the
beginning of each R-session with a small command.
I tried to generate a R-package and install it that way.
But it seems that it is not so easy to add new
On 19/01/2009 7:13 PM, Jörg Groß wrote:
Hi,
I am currently writing some own functions that I frequently need.
So, it would be perfect if I could load these functions at the
beginning of each R-session with a small command.
I tried to generate a R-package and install it that way.
But it
what is your suggestion for distinguishing between many bars without
color? I have grown up in the time of standarized tests - good or bad
I never felt nauseous.
Stephen
On Mon, Jan 19, 2009 at 5:20 PM, Greg Snow greg.s...@imail.org wrote:
I think the fact that the grid package does not
On 19/01/2009 7:36 PM, stephen sefick wrote:
what is your suggestion for distinguishing between many bars without
color? I have grown up in the time of standarized tests - good or bad
I never felt nauseous.
Use gray levels or labels. If many is bigger than 5, it's not going
to be easy,
On 20/01/2009, at 1:36 PM, stephen sefick wrote:
what is your suggestion for distinguishing between many bars without
color?
Exactly. Sometimes colour printing can be expensive.
I have grown up in the time of standarized tests - good or bad
I never felt nauseous.
Ni moi
If classic graphics is ok try this which uses hatches and different
shades of grey:
barplot(lizards, names.arg = color, col = grey(c(.2, .5, 1)), density = 20,
angle = c(45, -45, 0), legend = color)
On Wed, Jan 14, 2009 at 10:18 PM, stephen sefick ssef...@gmail.com wrote:
#I am putting a
On 20/01/2009, at 1:46 PM, Duncan Murdoch wrote:
On 19/01/2009 7:36 PM, stephen sefick wrote:
what is your suggestion for distinguishing between many bars without
color? I have grown up in the time of standarized tests - good or
bad
I never felt nauseous.
Use gray levels or labels. If
Is there a way to execute this command on every R-start?
I tried to add something in the Startup.h file - but that didn't work.
(working on a mac)
Thanks!
Am 20.01.2009 um 01:25 schrieb Duncan Murdoch:
On 19/01/2009 7:13 PM, Jörg Groß wrote:
Hi,
I am currently writing some own
?.Rprofile
On Mon, Jan 19, 2009 at 8:03 PM, Jörg Groß jo...@licht-malerei.de wrote:
Is there a way to execute this command on every R-start?
I tried to add something in the Startup.h file - but that didn't work.
(working on a mac)
Thanks!
Am 20.01.2009 um 01:25 schrieb Duncan
The zoo faq has an example:
library(zoo)
vignette(zoo-faq) # see question 8
On Mon, Jan 19, 2009 at 6:39 PM, glenn g1enn.robe...@btinternet.com wrote:
Hi All,
I have a small dataframe [dates, values) I am plotting with
plot(df,type=²l²)
And the date date covers a year. The graph only have
Hi,
I tried to generate a .Rprofile file.
But R does not load it automatically.
Is there a tutorial on the web on generating such a file?
(haven't found anything that helped me)
And where do I have to put this .Rprofile-file?
In the working directory?
Does R generate a .Rprofile file when R
On Tue, 2009-01-20 at 01:13 +0100, Jörg Groß wrote:
Hi,
I am currently writing some own functions that I frequently need.
So, it would be perfect if I could load these functions at the
beginning of each R-session with a small command.
I tried to generate a R-package and install it
If you get a program called smultron (or other program that can open
hidden files), go to your working directory, and then open hidden
file and find your .Rprofile file. I set mine up by searching
through the archive and borrowing little bits of code for setting up a
self-compiled version on os x
On 19-Jan-09, at 4:59 PM, Rolf Turner wrote:
On 20/01/2009, at 1:46 PM, Duncan Murdoch wrote:
On 19/01/2009 7:36 PM, stephen sefick wrote:
what is your suggestion for distinguishing between many bars without
color? I have grown up in the time of standarized tests - good
or bad
I never
It does look like Gentleman and Ihaka not only lied to the New York
Times, but also to the New Zealand Herald and who knows who else. This
is disgusting. The R programming language is the S programming
language, and Gentleman and Ihaka are not the ones who designed it.
Hi: I think I saw a link where the author clarified the original article
and explained more clearly that the design of R had it roots in S/S+. I
don't
remember where I saw it but it's somewhere. Also, I think it's jumping
the gun to claim that anyone lied to anyone before doing the research
Mark,
don't feed the troll
Cheers,
Berwin
On Mon, 19 Jan 2009 22:38:24 -0600 (CST)
markle...@verizon.net wrote:
Hi: I think I saw a link where the author clarified the original article
and explained more clearly that the design of R had it roots in S/S+. I
don't
remember where I
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