Hi, Paul:
Your example is so complicated that I don't want to take the time
to check it. You apply deriv to an exponential divided by a sum of
exponentials, and I'm not convinced that your manual Correct way is
actually correct. It looks like you've followed the examples in the
Hi Mike.
In the plotting you do, there are usually parameters in the function you use
to help you add text to the plot.
for example:
par(mfrow = c(2, 2))
plot(x, sub = text in the bottom, main = text in top, ylab = text to
the side of the axis, xlab = text to the bottom of the axis)
plot(y) # this
Hi,
I have a question about derivatives of functions.
if i have the following function,
f - function(x) x^3-2*x^2+3*x-5
i need a simple function for the derivative of this with respect to 'x', so
that i can then sub in values to the the derivative function, and use Newtons
method of finding
Dear all,
I have some trouble with the number of decimals in R (currently R
2.9.0). For instance:
options()$digits
[1] 3
let me hope that I will get three digits where useful when a number is
printed. BUT:
44.25+31.1+50
[1] 125
No way to get the right result 125.35
Can anybody tell me
Hello all,
I have a large data frame and I want to look at the distribution of each
variable very quickly by plotting an individual histogram for each variable.
I'd like to do so using lattice.
Here is a small example using the iris data set:
Patrick Giraudoux wrote:
I have some trouble with the number of decimals in R (currently R
2.9.0). For instance:
options()$digits
[1] 3
let me hope that I will get three digits where useful when a number is
printed. BUT:
44.25+31.1+50
[1] 125
No way to get the right
Tena koe Patrick
If you want more than three digits, change the options:
options(digits=7)
44.25+31.1+50
[1] 125.35
HTH
Peter Alspach
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Patrick Giraudoux
Sent: Tuesday, 12
Thom_249 wrote:
I have data like this:
[1] 16.800 6.533 5.067 3.933 2.200 1.667
[7] 1.200 1.067 0.733 0.667
And I want that all these data, printed on a 4 rows instead of 8, and it's
be great without the [x]
First look would be
Kon Knafelman wrote:
if i have the following function,
f - function(x) x^3-2*x^2+3*x-5
i need a simple function for the derivative of this with respect to 'x',
so that i can then sub in values to the the derivative function, and use
Newtons method of finding a root for this.
Hi all:
As to hist,the help file says: R's default with equi-spaced breaks (also the
default) is to plot the counts in the cells defined by breaks.
I wanna know how the break is calculated by R?
In other words: break = (max - min)/(number of group) but how the number of
group is calculated
*
*
*
I have to setup a simple classification method (mix of factor and
numeric variables) that can iteratively:
- Use expert opinion prior on item X1
- Classify X1 based on estimated model (training set) and
expert opinion (previous requirement)
-
Hi
This happens because of the way PostScript files are generated, with all
metadata in the head of the file, including font information. So you
need to predeclare any fonts that you are going to use in a PostScript
file. In this case, something like ...
postscript(fonts=Times)
... or if
So, this would allow me to assign a color to each of the 2592 rectangular
grid cells on a map of the world? I guess I am having trouble finding a
suitable method of doing this. Also, to be able to distinguish country
boundaries from the grid lines (which are both black color), could the grid
Hi
I'm sorry for my so basic question, but it's so basic that I can't find
anwser anywhere...
I have data like this:
[1] 16.800 6.533 5.067 3.933 2.200 1.667
[7] 1.200 1.067 0.733 0.667
[1] 35.6113946 6.9576953 4.5271667 2.3744674
Hi All,
Can anybody explain why the following three ways of extracting residuals
from a glm object are giving me different outputs:
idv = runif(1000,0,1)
dv = rbinom(1000,1,0.5)
d = data.frame(idv,dv)
fit = glm(dv~idv, data=d, family=binomial)
head(residuals(fit))
1 2
Hi,
Does anyone know how to code newton's method for finding the roots of
polynomial functions? im not sure whether i need to do this manually, or just
code something with a loop to stop when it gets to the desired result
thanks guys!
Dieter Menne wrote:
It says digits, not decimals:
(44.25+31.1+50)/100
[1] 1.25
Dieter
(44.25+31.1+50)*10
[1] 1254
Strictly speaking, this should print as 1250 (no flames, please, I can live
with it)
Dieter
--
View this message in context:
I have some trouble with the number of decimals in R (currently R
2.9.0). For instance:
options()$digits
[1] 3
let me hope that I will get three digits where useful when a number is
printed. BUT:
44.25+31.1+50
[1] 125
No way to get the right result 125.35
Can anybody tell
Hi,
Is the variable st character or a factor? What does str(train$st) show?
str(train$st)
Factor w/ 208 levels 0,000,0,0058643,..: 132 134 41 29 42 151 195 195
196 207 ...
Thank you very much Max with your help I found my error, now it works.
Marlene.
if i have the following function,
f - function(x) x^3-2*x^2+3*x-5
i need a simple function for the derivative of this with respect to
'x', so that i can then sub in values to the the derivative
function, and use Newtons method of finding a root for this.
You could take a look at
I have a large data frame and I want to look at the distribution of
each variable very quickly by plotting an individual histogram for
each variable.
I'd like to do so using lattice.
Here is a small example using the iris data set:
Shame on me... I confused digits and decimals
Thanks anyway to make me come to the English basics...
Patrick
Peter Alspach a écrit :
Tena koe Patrick
If you want more than three digits, change the options:
options(digits=7)
44.25+31.1+50
[1] 125.35
HTH
Peter Alspach
As to hist,the help file says: R's default with equi-spaced breaks
(also the default) is to plot the counts in the cells defined by
breaks.
I wanna know how the break is calculated by R?
In other words: break = (max - min)/(number of group) but how the
number of group is calculated by
Kon Knafelman wrote:
Hi,
Does anyone know how to code newton's method for finding the roots of
polynomial functions? im not sure whether i need to do this manually, or just
code something with a loop to stop when it gets to the desired result
See ?optim for optimization methods.
Uwe
Hi,
I am quite new to R and I have two questions regarding ROCR.
1. I have tried to understand how to extract area-under-curve value by looking
at the ROCR document and googling. Still I am not sure if I am doing the right
thing. Here is my code, is auc1 the auc value?
pred1 -
Dear R users,
Does anyone know how to write function for Kumaraswamy distribution in R? Since
I cannot write dkumar, pkumar, etc. in R.
Please help.
Thanks a lot,
Debbie
_
[[elided Hotmail spam]]
[[alternative
I can reproduce it. Can you please send a bug report to R-bugs so that
this won't get lost.
Thank you,
Uwe Ligges
Dan Kelley wrote:
Some time ago, I posted a note about what I considered to be a bug in
axis.POSIXt() for R 2.8.x, relating to whether timezones in the data are
obeyed on the
Dear list members,
I am trying to make a clean up on my computer (windows problems, off course),
and I wanted to remove some libraries that I have installed in R, which have
been hardly used.
Is there any way to see how often each library is used by us?
I have many that I am not sure...
Romain Francois wrote:
Hi,
Something like this perhaps:
files - dir( pattern = \\.csv$ )
for( x in files){
assign( sub( \\.csv$, , x ) , read.csv(x), envir = .GlobalEnv )
}
or maybe
csvs = Map(read.csv, dir(pattern='\\.csv$'))
possibly with a correction of list item names
1. I have tried to understand how to extract area-under-curve value by
looking at the ROCR document and googling. Still I am not sure if I am doing
the right thing. Here is my code, is auc1 the auc value?
pred1 - prediction(resp1,label1)
perf1 - performance(pred1,tpr,fpr)
plot( perf1,
Phillip Porter wrote:
At 9:25 PM +1000 5/11/09, Jim Lemon wrote:
Hi Phillip,
I'm not exactly sure how you are positioning the labels. Is it
possible to give us an example with some data that will produce a
plot to show what you want? It shouldn't be too hard to do.
Jim
Data is something
Marta Rufino wrote:
Dear list members,
I am trying to make a clean up on my computer (windows problems, off course), and I wanted to remove some libraries that I have installed in R, which have been hardly used.
Is there any way to see how often each library is used by us?
No, unless you
dxc13 wrote:
Hi useR's
I have created a simple map of the world using the following code:
m - map(xlim=c(-180,180), ylim=c(-90,90))
map.axes()
I then create a grid of dimension 36x72 using the code:
map.grid(m, nx=72, ny=36, labels=FALSE, col=black)
This gives 2592 grid cells. In a separate
Hi list,
I have a function that detects saccadic eye movements in a time series
of eye positions sampled at a rate of 250Hz. This function needs
three vectors: x-coordinate, y-coordinate, trial-id. This information
is usually contained in a data frame that also has some other fields.
The names
On Tue, May 12, 2009 at 12:18:59PM +0200, Titus von der Malsburg wrote:
Is there a canonical way to tell a function which fields in a data
frame are relevant? What other alternatives are possible? What are
the pros and cons of the alternatives?
Why not simply rearrange your data frames to
You could define a generic detect(obj, ...) that dispatches (using S3):
detect.formula(fo, data)
detect.data.frame(data)
detect.default(x, y, trial)
where the first two call the third thereby modeling it on lm,
a common approach, and giving the user choice in interface.
On Tue, May 12, 2009 at
Hi Zeljko,
thanks for your suggestion!
On Tue, May 12, 2009 at 12:26:48PM +0200, Zeljko Vrba wrote:
Why not simply rearrange your data frames to have standardized column names
(see names() function), and write functions that operate on the standardized
format?
Actually that's what I'm
On 12/05/2009 6:18 AM, Titus von der Malsburg wrote:
Hi list,
I have a function that detects saccadic eye movements in a time series
of eye positions sampled at a rate of 250Hz. This function needs
three vectors: x-coordinate, y-coordinate, trial-id. This information
is usually contained in a
Hi,
I would like to have no ticks on a scale that represents a factor. The
tick.number argument from scales does not work in such a situation, as
the help page as well as this simple (fairly stupid) code show:
require(lattice)
fact-gl(4,1,labels=LETTERS[1:4])
y-c(1,4,3,2)
Dear Debbie,
On Tue, May 12, 2009 at 5:37 AM, Debbie Zhang debbie0...@hotmail.com wrote:
Dear R users,
Does anyone know how to write function for Kumaraswamy distribution in R?
Since I cannot write dkumar, pkumar, etc. in R.
Please help.
Thanks a lot,
Debbie
Check the CRAN Task
dkumar = function(x,a,b) a*b*(x^(a-1))*((1-x^a)^(b-1))
pkumar = function(x,a,b) 1-(1-x^a)^b
(I've based this entirely on the wikipedia entry on the Kumaraswamy
distribution [http://en.wikipedia.org/wiki/Kumaraswamy_distribution],
so best to check both my replication of the formula there and the
Dear All,
Perhaps, what I am asking is impossible, but I am asking it anyway.
I have got several pdf files with rows of colored rectangles: red
rectangles should be read as 0; green rectangles as 1. No other color
exists. Is there some way to have R reading the colored rectangles to
a matrix or
You could also use rSymPy to symbolically differentiate it. For example,
based on the semi-automatic differentiation example on the rSymPy home
page:
http://code.google.com/p/rsympy/#Semi-Automatic_Differentiation
just replace the indented lines there with the indented lines here
(I've also
I would like to have no ticks on a scale that represents a factor. The
tick.number argument from scales does not work in such a situation, as
the help page as well as this simple (fairly stupid) code show:
require(lattice)
fact-gl(4,1,labels=LETTERS[1:4])
y-c(1,4,3,2)
On Tue, May 12, 2009 at 12:20:56PM +0100, Paul Smith wrote:
I have got several pdf files with rows of colored rectangles: red
rectangles should be read as 0; green rectangles as 1. No other color
exists. Is there some way to have R reading the colored rectangles to
a matrix or data frame
Thanks Tobias!
A new question: if I want to draw an average ROC from cross-validation, how to
make the bar color same as the line color? Here is my code:
plot( perf2,avg=threshold,lty=2,col=2, spread.estimate=stddev,barcol=2)
Even I specify barcol=2, the color of bars are still black, the
Hi All
This is a general stats problem that I am dealing with using R, so any help is
greater appreciated.
I have two lognormal distributions with means M1 and M2.
If we have:
H0: log(M1/M2)=0
H1: log(M1/M2) !=0 equivalent to log(M1/M2)=log(1+P) where P0 or P0.
If we calculate the power for
On May 12, 2009, at 3:50 AM, utkarshsinghal wrote:
Hi All,
Can anybody explain why the following three ways of extracting
residuals from a glm object are giving me different outputs:
idv = runif(1000,0,1)
dv = rbinom(1000,1,0.5)
d = data.frame(idv,dv)
fit = glm(dv~idv, data=d,
To color the error bars in ROCR the same way as the performance curve,
you need to add one more argument (plotCI.col='red') to your plot
call:
plot( perf2,avg=threshold,lty=2,col=2, spread.estimate=stddev, plotCI.col=2)
The use of 'plotCI.col' is an example for the general mechanism of
ROCR to
Depending on the nature of your pdf file, it may be possible to use
the grImport package. I've never used it before, but a quick test
seems promising,
# create a test picture
colorStrip -
function (colors, draw = T)
{
x - seq(0, 1 - 1/ncol(colors), length = ncol(colors))
y -
Hi,
I have the following data and I would like to delete douple names, it is almost
similar to SAS PROC SORT nodupkey! Is there any function in R does this?
x1 - rnorm(11,5,1)
x2 - runif(11,0,1)
nam -paste(A, c(1:4,4,5:9,9), sep=.)
mydata - data.frame(x1,x2)
crownames(mydata) - nam
Many
Thom_249 wrote:
I got them from a Matrix on with I use the applyfunction tu compute the
mean columns by columns
print(apply(matSD,2,mean))
matSD = matrix(round(rnorm(20),2),nrow=4)
cat(matSD)
print(matSD)
dput(matSD) # How to send this matrix to r-help
newMat = apply(matSD,2,mean)
Dear List,
I am trying to plot a similar graph to attached from minitab manual in R.
I have a response Y and three components which systematically vary in their
proportions. I have found in R methods/packages to plot ternary plots (eg.
plotrix) but nothing which can extend it to response
Thanks, Baptiste and Zeljko. I am attaching here an example of the
picture of the rectangles.
Paul
On Tue, May 12, 2009 at 1:23 PM, baptiste auguie ba...@exeter.ac.uk wrote:
Depending on the nature of your pdf file, it may be possible to use
the grImport package. I've never used it before,
Dear List,
I am trying to plot a similar graph to attached from minitab manual in R.
I have a response Y and three components which systematically vary in their
proportions. I have found in R methods/packages to plot ternary plots (eg.
plotrix) but nothing which can extend it to
*I´m writing to ask you how can I do Survivals Curves using Time-dependent
*covariates? Which packages I need to Install?*
This is a very difficult problem statistically. That is, there are not many
good ideas for what SHOULD be done. Hence, there are no packages. Almost
everything you find
Hi,
I was wondering how to specify the line type for line instead of for bar.
Here is my code:
plotCI(x=mcra1avg, uiw=stdev1, type=l,col=2,lty=2)
This way, I will have the bar line as dashed lty=2 and red col=2, and
the line connecting the centers of the bars is also red col=2 but solid
lty=1.
On 5/12/2009 8:29 AM, amor Gandhi wrote:
Hi,
I have the following data and I would like to delete douple names, it is
almost similar to SAS PROC SORT nodupkey! Is there any function in R does
this?
x1 - rnorm(11,5,1)
x2 - runif(11,0,1)
nam -paste(A, c(1:4,4,5:9,9), sep=.)
mydata -
Finding polynomial roots is not a problem where one wants a quick and dirty
code. There are a lot of pitfalls, especially if there are roots that are
multiples, and there has been a lot of work on this problem. See
http://en.wikipedia.org/wiki/Category:Root-finding_algorithms .
And Uwe may
John,
Nothing about the data set you posted should give issues in any version of
the
package. The points =0 usually arises when the survival curve drops to
zero,
and so log(-log(0)) is being trimmed off the graph by the plot command. This
is
what should happen. As Thomas pointed out to
Amor,
You have the possibility to use the duplicated() function.
A[!duplicated(A[,var]),]
Atenciosamente,
Leandro Lins Marino
Centro de Avaliação
Fundação CESGRANRIO
Rua Santa Alexandrina, 1011 - 2º andar
Rio de Janeiro, RJ - CEP: 20261-903
R (21) 2103-9600 R.:236
( (21) 8777-7907
(
On 12-May-09 12:00:50, Steve Candy wrote:
Hi All
This is a general stats problem that I am dealing with using R,
so any help is greater appreciated.
I have two lognormal distributions with means M1 and M2.
If we have:
H0: log(M1/M2)=0
H1: log(M1/M2) !=0 equivalent to
John C Nash wrote:
Finding polynomial roots is not a problem where one wants a quick and
dirty code. There are a lot of pitfalls, especially if there are roots
that are multiples, and there has been a lot of work on this problem.
See
Hi,
Â
I'm actually Iâm performing a TSLS linear multiple regression on annually
data which go from 1971 to 1997. After performing the TSLS regression, I tried
to extract the R squared value using âoutput$r.squaredâ function and to
perform autocorrelation (Durbin Watson and
Hello,
I was wondering if there is a function in R that imports tables directly
from a HTML document. I know there are functions (say, getURL() from {RCurl}
) that download the entire page source, but here I refer to something like
google document's function importHTML() (if you don't know this
I am exploring neural networks (adding non-linearities) to see if I can
get more predictive power than a linear regression model I built. I am
using the function nnet and following the example of Venables and
Ripley, in Modern Applied Statistics with S, on pages 246 to 249. I have
standardized
Greetings:
There is a LinkedIn R Group. There are job postings, news, as well as
other discussions.
http://www.linkedin.com/groups?about=gid=77616trk=anet_ug_grppro
Regards,
Ajit
--
_
Ajit Gemunu de Silva
Oakland CA 94619
skype: ajit_de_silva
On 5/12/2009 8:43 AM, Tim Carnus wrote:
Dear List,
I am trying to plot a similar graph to attached from minitab manual in R.
I have a response Y and three components which systematically vary in their
proportions. I have found in R methods/packages to plot ternary plots (eg.
Greetings:
There is a LinkedIn R Group. There are job postings, news, as well
as other discussions.
http://www.linkedin.com/groups?about=gid=77616trk=anet_ug_grppro
Regards,
Ajit
http://www.linkedin.com/groups?about=gid=77616trk=anet_ug_grppro
Hi,
I'm having trouble understanding how to construct a random number generator
for a parametric bootstrap. My aim is to bootstrap a Likelihood Ratio
statistic (under the null) for a linear model. The function at this point
is given by
boot.test.n01 - function(data, indeces, maxit=20) {
y1 -
Dear R-community,
Dear Prof. Therneau,
I would like to fit an AFT-model with time-dependent covariates and
right-censored data.
Searching the mailing list for information on the subject, I found some old
posts which said it didn't work back then.
My questions:
(1) Has this kind of fitting
Uwe,
John's comment about the difficulties with finding polynomial roots is even
more forceful for a system of polynomials. There are likely numerous roots,
some possibly real, and some possibly multiple. Homotopy methods are
currrently the state-of-art for finding all the roots, but beware
I am analyzing the voice telephone traffic of some operators. In this type of
phenomenon is useful to consider the anomalies in the duration in minutes of
conversation but it is very important to take account of another variable:
average time of conversation, the relationship between the duration
I am a PhD Student at the University of
Agriculture,Abeokuta Nigeria.Also a Statistician at
National
Horticultural Research institites ibadan Nigeria.
I currently working on Discriniant analysis and i need
a
help on hoe to solve Lanche Bruch's hold out
Procedure
using R .
Hello,
I'm trying to do a comparsion on a large scale say 10L bottle of liquid and a
small scale bottle of liquid 0.5L, I have 5 different samples from each and
they are measured over the space of 8 days as % viability and the % viability
decreases over time. However not all 10 samples got
Hi
I have a dataset of orientation and elevation in a dataframe which I am
plotting in circular. Orientation is on the range 0-360, however I need to
reduce this to 0-180 as the values over 180 are not necessarily correct. I
can do
striae$orientation[striae$orientation180]-180)
to extract
Totally awsom!
Thank you very much
Thom
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View this message in context:
http://www.nabble.com/How-to-display-data-content-on-a-only-row--tp23497437p23502952.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org
Thanks for showing me how to use genD correctly and that it matches deriv
here. Like you say, there must be a problem with the manual way of doing
it, and I will look at it closely. Thanks again.
spencerg wrote:
Hi, Paul:
Your example is so complicated that I don't want to take
Hi
I've been playing with a 3x2 graphics device using the default size as it
appears on screen. This has given me tall thin plots which I can resize by
dragging the window and increasing the window width. However I was wondering
if I can force R to produce square plots or set the actual aspect
Greetings,
I am using rpart for classification with class method. The test data is
the Indian diabetes data from package mlbench.
I fitted a classification tree firstly using the original data, and then
exchanged the order of Body mass and Plasma glucose which are the
strongest/important
Dear:
I am trying to merge two tables by a common variable. However, there are a
few same variables which are in both of two tables. How can I take them away
when I merge the two tables?
Thanks!
Xin
__
R-help@r-project.org mailing
Hello Dieter
I got them from a Matrix on with I use the applyfunction tu compute the mean
columns by columns
print(apply(matSD,2,mean))
So it's a kind of vector.
I'll check with the cat function
Thank you, have a nice day
Thomas
--
View this message in context:
Hello,
I am using triangle.class in ade4 package and a factor. I would like to use
this graphic parameter (pch) to set a different kind of point for each group
in my factor (lakes). I have tried pch=1:4, I guess it does what it is
supposed to do but not what I want. I can't use colors.
Thank
Hello,
I have a data set with many variables, and often I want to run a given
function, like summary() or cor() or lmer() etc. on many combinations of one
or more than one of these variables. For every combination of variables I
want to analyze I have been writing out the code by hand, but
Hi Mike,
MikSmith wrote:
Hi
I have a dataset of orientation and elevation in a dataframe which I am
plotting in circular. Orientation is on the range 0-360, however I need to
reduce this to 0-180 as the values over 180 are not necessarily correct. I
can do
Given two numeric vectors of possibly unequal length, I'd like to pair
each element of the shorter vector with an element of the longer
vector such that the sum of squared differences between the pairs is
minimized. Can someone point me to an R function or an algorithm for
accomplishing
Hello
I'm plotting 6 graphs using mfrow = c(2, 3). In these plots, only
graphs in the first column have titles for the y axis, and only the ones
in the last row have titles for the x axis.
I'd like all plots to be of the same size, and I'm trying to keep them
as near each other as possible, but
I don't think get(factor[i]) will work. The problem is get only sees a
character string data$focus instead of doing extracting focus from data.
In your case isn't lapply (or sapply) good enough?
sapply (data, summary)
try ?lapply for details
Jun
On Tue, May 12, 2009 at 10:55 AM, rapton
Forgot one thing, make sure your data is a list or data frame.
On Tue, May 12, 2009 at 12:19 PM, Jun Shen jun.shen...@gmail.com wrote:
I don't think get(factor[i]) will work. The problem is get only sees a
character string data$focus instead of doing extracting focus from data.
In your case
As a follow-up to my email below:
The input data frame to nnet() has dimensions:
dim(coreaff.trn.nn)
[1] 50888
And the predictions from the neural network (35 records are dropped -
see email below for more details) has dimensions:
pred - predict(coreaff.nn1)
dim(pred)
[1]
jim holtman schrieb:
Try this:
key - rownames(a)
key[key == AT] - TA
do.call(rbind, by(a, key, colSums))
something like
paste(sort(strsplit(key, split=)[[1]]), )
might be more general.
__
R-help@r-project.org mailing list
Using traditional ANOVA, you'd have to drop either cases or time
points with missing data. Using linear mixed effects analysis, you'd
be able to use all the data. LME also has the benefit of *not*
assuming sphericity, which is good for data like yours (many measures
across few cases) where the
If the matching need not be one-to-one, then you can just compute the
Euclidean distances between the two vectors, then in each row (or
column, which ever corresponds to the shorter vector) and find the
smallest. This should be fairly easy to do.
Andy
From: Thomas S. Dye
Given two numeric
On Tue, May 12, 2009 at 2:35 PM, Zeljko Vrba zv...@ifi.uio.no wrote:
Aha, so you DON'T have only red and green rectangles in the picture, there is
also white in between, and some pale delimiter lines. Nevertheless, both
things ease the job slightly, and the approach I described should work.
Jun,
sapply() does the trick! Thank you Jun! I really appreciate your help.
-Matt
On Tue, May 12, 2009 at 1:20 PM, Jun Shen jun.shen...@gmail.com wrote:
Forgot one thing, make sure your data is a list or data frame.
On Tue, May 12, 2009 at 12:19 PM, Jun Shen jun.shen...@gmail.com wrote:
Hello Everyone,
I am new to R and need some help.
I have a matrix of x,y,z coordinates that I would like to
interactively plot in 3D and then using the cursor select points on
the plot and have the coordinates sent to a matrix. I am using the rgl
package to plot the data at the moment because it
Thank you, Baptiste and Charlie.
I found some examples wich look great on:
http://www.texample.net/tikz/examples/
Perhaps try the pgfSweave package on r-forge?
http://r-forge.r-project.org/projects/pgfsweave/
[..]
accomplished using the java utility eps2pgf and requires the PGF/TiKZ
On 5/12/2009 3:08 PM, Abby Drake wrote:
Hello Everyone,
I am new to R and need some help.
I have a matrix of x,y,z coordinates that I would like to
interactively plot in 3D and then using the cursor select points on
the plot and have the coordinates sent to a matrix. I am using the rgl
package
Sorry for these multiple postings.
I solved the problem using na.omit() to drop records with missing values
for the time being. I will worry about imputation, etc. later.
I calculated the sum of squared errors for 3 models, linear regression,
neural networks, and support vector machines. This
Hi,
I cannot compile R with shared library.
I am using Redhad Linux on Dell hardware.
Here''s what I am doing:
I set ?PICFLAGS in config.site file:
CPICFLAGS=-fPIC
FPICFLAGS=-fPIC
and issue:
./configure --enable-R-shlib --prefix=$HOME/newR
make
configure finishes with no complaints, the
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