Hi. Essentially your data is currently in wide format, with repeated
measures in different columns. For most analysis and in particular for
graphing, it is frequently helpful to reshape your data into a long
format, with one row per data value and additional variables to list
experiment or subject
Hi David,
It looks like we will be in minority this time around.
See you there,
Tal
On Wed, Jul 1, 2009 at 8:04 PM, David M Smith
da...@revolution-computing.com wrote:
I'm going to both UseR! (in Rennes) and DSC (in Copenhagen), and will
be blogging about the talks and other interesting
what happened to the xlsReadWrite package?
[snip]
Are there any plans for it be available again?
Yes. (I do have a halfway finished version but then had much work on
my regular job, my 'free-programming-time' got eaten by a e-texteditor
plugin
2009/7/2 Chris Anderson chris6...@netzero.net:
Is there a way to export multiple datasets into multiple excel spreadsheets
using xlsReadWritePro or with xlsReadWrite?
I have answered the question in your other thread. See:
http://thread.gmane.org/gmane.comp.lang.r.general/154614/focus=154752
Ben
that subset(..) works, and it solves all my problems. thnks!
Ben Bolker wrote:
JoK LoQ wrote:
Just a quickly beginner's question.
I wanna find the mean only from the values from a column related to
specific values from another one. Like, theres a 'region' column, i want
I'm dealing with lots of columns and conditions, wats t best way to deal with
that?
How do I work with SQL on R? the manual is quite confuse talking about that.
Do I need a package?
--
View this message in context:
http://www.nabble.com/SQL-on-R-tp24340314p24340314.html
Sent from the R help
On Sat, 2009-07-04 at 22:24 -0700, JoK LoQ wrote:
I'm dealing with lots of columns and conditions, wats t best way to deal with
that?
How do I work with SQL on R? the manual is quite confuse talking about that.
Do I need a package?
I don't understand your question, but
if you think use SQL
Thanks everyone for your help!
Bill
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,
I want a function that takes an input vector, the number of columns
and returns a matrix as follows.
x- 1:5
foo(x, nc=3)
1 5 4
2 1 5
3 2 1
4 3 2
5 4 3
Thanks again for any help.
Bill
__
R-help@r-project.org mailing list
On Jul 4, 2009, at 9:22 PM, nyk wrote:
I have a data matrix containing quite a lot of missing values (NA).
I know
how to remove all column or rows containing NA values, but is there
a some
standard method for removing not all NA containing rows/column, but
only
those which have
On Jul 5, 2009, at 8:54 AM, William Simpson wrote:
I want a function that takes an input vector, the number of columns
and returns a matrix as follows.
x- 1:5
foo(x, nc=3)
1 5 4
2 1 5
3 2 1
4 3 2
5 4 3
See if this gives you any ideas:
sapply(1:3, function(z) { ((x - z) %% 5) +1 } )
On Sat, Jul 4, 2009 at 5:22 PM, jim holtmanjholt...@gmail.com wrote:
See if this example helps; show how to either plot the row or columns
of a data frame:
test - data.frame(C1=runif(10), C2=runif(10), C3=runif(10))
test
C1 C2 C3
1 0.91287592 0.3390729 0.4346595
2
On Sun, Jul 5, 2009 at 12:00 AM, Mark Wardlem...@wardle.org wrote:
Hi. Essentially your data is currently in wide format, with repeated
measures in different columns. For most analysis and in particular for
graphing, it is frequently helpful to reshape your data into a long
format, with one
Try this (ignore the warning):
k - 3
matrix(1:5, 9, k)[1:5, ]
On Sun, Jul 5, 2009 at 8:54 AM, William
Simpsonwilliam.a.simp...@gmail.com wrote:
I want a function that takes an input vector, the number of columns
and returns a matrix as follows.
x- 1:5
foo(x, nc=3)
1 5 4
2 1 5
3 2 1
4
On Jul 5, 2009, at 9:53 AM, Mark Knecht wrote:
On Sat, Jul 4, 2009 at 5:22 PM, jim holtmanjholt...@gmail.com wrote:
See if this example helps; show how to either plot the row or columns
of a data frame:
test - data.frame(C1=runif(10), C2=runif(10), C3=runif(10))
test
C1C2
2) Related to the above, how do I tell what packages are currently
loaded at any given time so that I don't waste time loading things
that are already loaded? search() tells me what's available, but
what's loaded? The best I can find so far goes like this:
Loading something a second time
Try this:
foo - function(x, ncols){
tail(embed(rep(x, ncols), ncols), length(x))
}
foo(x, 3)
On Sun, Jul 5, 2009 at 9:54 AM, William Simpson william.a.simp...@gmail.com
wrote:
I want a function that takes an input vector, the number of columns
and returns a matrix as follows.
x- 1:5
Also make sure to check roxygen (from roxygen.org) - it makes package
documentation much much easier. Ironically, the documentation for
roxygen currently leaves something to be desired but I think Peter and
Manuel are working on it.
Hadley
On Sat, Jul 4, 2009 at 3:59 PM, Jason
David Winsemius wrote:
On Jul 5, 2009, at 9:53 AM, Mark Knecht wrote:
On Sat, Jul 4, 2009 at 5:22 PM, jim holtmanjholt...@gmail.com wrote:
See if this example helps; show how to either plot the row or columns
of a data frame:
test - data.frame(C1=runif(10), C2=runif(10), C3=runif(10))
On Sun, Jul 5, 2009 at 7:35 AM, David Winsemiusdwinsem...@comcast.net wrote:
On Jul 5, 2009, at 9:53 AM, Mark Knecht wrote:
On Sat, Jul 4, 2009 at 5:22 PM, jim holtmanjholt...@gmail.com wrote:
See if this example helps; show how to either plot the row or columns
of a data frame:
test -
On Jul 5, 2009, at 10:50 AM, Uwe Ligges wrote:
David Winsemius wrote:
So if your values are calculated from other values then consider
using all.equal()
And repeated applications of the testing criteria process are
effective:
test[3,][which(names(test)==C1):(which(test[3,] == 0.0)-1)]
In terms of x this is:
k - 3
x - 1:5
n - length(x)
matrix(x, 2*n-1, k)[1:n, ]
On Sun, Jul 5, 2009 at 10:01 AM, Gabor
Grothendieckggrothendi...@gmail.com wrote:
Try this (ignore the warning):
k - 3
matrix(1:5, 9, k)[1:5, ]
On Sun, Jul 5, 2009 at 8:54 AM, William
Thanks very much Gabor
Bill
On Sun, Jul 5, 2009 at 4:44 PM, Gabor
Grothendieckggrothendi...@gmail.com wrote:
In terms of x this is:
k - 3
x - 1:5
n - length(x)
matrix(x, 2*n-1, k)[1:n, ]
On Sun, Jul 5, 2009 at 10:01 AM, Gabor
Grothendieckggrothendi...@gmail.com wrote:
Try this (ignore
On Sun, Jul 5, 2009 at 3:40 PM, hadley wickhamh.wick...@gmail.com wrote:
2) Related to the above, how do I tell what packages are currently
loaded at any given time so that I don't waste time loading things
that are already loaded? search() tells me what's available, but
what's loaded? The
On Sun, Jul 5, 2009 at 8:18 AM, David Winsemiusdwinsem...@comcast.net wrote:
On Jul 5, 2009, at 10:50 AM, Uwe Ligges wrote:
David Winsemius wrote:
So if your values are calculated from other values then consider using
all.equal()
And repeated applications of the testing criteria process
On Jul 5, 2009, at 12:19 PM, Mark Knecht wrote:
On Sun, Jul 5, 2009 at 8:18 AM, David
Winsemiusdwinsem...@comcast.net wrote:
On Jul 5, 2009, at 10:50 AM, Uwe Ligges wrote:
David Winsemius wrote:
So if your values are calculated from other values then consider
using
all.equal()
And
David Winsemius wrote:
On Jul 5, 2009, at 12:19 PM, Mark Knecht wrote:
On Sun, Jul 5, 2009 at 8:18 AM, David
Winsemiusdwinsem...@comcast.net wrote:
On Jul 5, 2009, at 10:50 AM, Uwe Ligges wrote:
David Winsemius wrote:
So if your values are calculated from other values then consider
2009/7/5 Uwe Ligges lig...@statistik.tu-dortmund.de:
David Winsemius wrote:
On Jul 5, 2009, at 12:19 PM, Mark Knecht wrote:
On Sun, Jul 5, 2009 at 8:18 AM, David Winsemiusdwinsem...@comcast.net
wrote:
On Jul 5, 2009, at 10:50 AM, Uwe Ligges wrote:
David Winsemius wrote:
So if your
Dear list,
I have a question regarding how to allocate or initialize the proper type of
the arrays or lists.
I have a for loop, each iteration, I want it to assign a subset of a data
frame to an element of an array or list.
However, I am wondering how I should initialize or allocate the empty
Try
mylist - NULL
and then just assign the subsets to each element of the list
mylist[[1]] - data1[,1]
as an example
--- On Sun, 7/5/09, zrl zrl1...@gmail.com wrote:
From: zrl zrl1...@gmail.com
Subject: [R] allocation/initialization of arrays/lists
To: r-h...@stat.math.ethz.ch
Received:
On Jul 5, 2009, at 1:19 PM, Uwe Ligges wrote:
snippedpreample
test - data.frame(A=1:10, B=100, C1=runif(10), C2=runif(10),
C3=runif(10), C4=runif(10), C5=runif(10), C6=runif(10))
test-round(test,2)
#Make array ragged
test$C3[2]-0;test$C4[2]-0;test$C5[2]-0;test$C6[2]-0
Hi ZRL,
zrl wrote:
Dear list,
I have a question regarding how to allocate or initialize the proper type of
the arrays or lists.
I have a for loop, each iteration, I want it to assign a subset of a data
frame to an element of an array or list.
However, I am wondering how I should
David Winsemius wrote:
On Jul 5, 2009, at 1:19 PM, Uwe Ligges wrote:
snippedpreample
test - data.frame(A=1:10, B=100, C1=runif(10), C2=runif(10),
C3=runif(10), C4=runif(10), C5=runif(10), C6=runif(10))
test-round(test,2)
#Make array ragged
On Jul 5, 2009, at 2:43 PM, Martin Morgan wrote:
Hi ZRL,
zrl wrote:
Dear list,
I have a question regarding how to allocate or initialize the
proper type of
the arrays or lists.
I have a for loop, each iteration, I want it to assign a subset of
a data
frame to an element of an array
Hi all,
say, I have following vector :
x - c(rep(5, 5), rep(3,4), rep(5,10))
Now I want to get the index numbers where elements of that vector changes
i.e. in above example I want to get a vector with elements : 6, 10. Because
at that indices, element of original vector changes value.
Is there
Suppose, I have following
vec - vector(list, length=3)
for (i in 1:3) vec[[i]] - matrix(rnorm((i+3)*2), (i+3))
vec
Now I want to change the type of vec from list to a matrix with (4+5+6)
rows and 2 columns. How can I do that?
Thanks and regards,
--
View this message in context:
I tried to apply the scheme you suggested to open the web page on
http://mirecords.umn.edu/miRecords/index.php; and got the followiing:
result - postForm(http://mirecords.umn.edu/miRecords/index.php;,
+ searchType=miRNA, species=Homo sapiens,
+ searchBox=hsa-let-7a, submitButton=Search)
html
Try:
do.call(rbind, vec)
On Sun, Jul 5, 2009 at 4:10 PM, megh megh700...@yahoo.com wrote:
Suppose, I have following
vec - vector(list, length=3)
for (i in 1:3) vec[[i]] - matrix(rnorm((i+3)*2), (i+3))
vec
Now I want to change the type of vec from list to a matrix with (4+5+6)
rows and
Try this:
which(c(0, diff(x)) != 0)
On Sun, Jul 5, 2009 at 4:03 PM, Arun Kumar Saha
arun.kumar.s...@gmail.comwrote:
Hi all,
say, I have following vector :
x - c(rep(5, 5), rep(3,4), rep(5,10))
Now I want to get the index numbers where elements of that vector changes
i.e. in above
Try this:
subset(test[3,], select=C1:C6)[,subset(test[3,], select = C1:C6) 0]
subset(test[6,], select=C1:C6)[,subset(test[6,], select = C1:C6) 0]
On Sun, Jul 5, 2009 at 1:19 PM, Mark Knecht markkne...@gmail.com wrote:
On Sun, Jul 5, 2009 at 8:18 AM, David Winsemiusdwinsem...@comcast.net
mau...@alice.it wrote:
I tried to apply the scheme you suggested to open the web page on
http://mirecords.umn.edu/miRecords/index.php; and got the followiing:
result - postForm(http://mirecords.umn.edu/miRecords/index.php;,
+ searchType=miRNA, species=Homo sapiens,
+ searchBox=hsa-let-7a,
On Sun, Jul 5, 2009 at 12:30 PM, Henrique Dallazuannawww...@gmail.com wrote:
Try this:
subset(test[3,], select=C1:C6)[,subset(test[3,], select = C1:C6) 0]
subset(test[6,], select=C1:C6)[,subset(test[6,], select = C1:C6) 0]
I must admit I like this one. Pleasing to look at. It seems
Yes,
First, select only columns C1 to C6, then look for values greater than 0,
after use this to select the columns in original subset.
On Sun, Jul 5, 2009 at 4:48 PM, Mark Knecht markkne...@gmail.com wrote:
On Sun, Jul 5, 2009 at 12:30 PM, Henrique Dallazuannawww...@gmail.com
wrote:
Try
On Sun, 05-Jul-2009 at 12:10PM -0700, megh wrote:
|
| Suppose, I have following
|
| vec - vector(list, length=3)
| for (i in 1:3) vec[[i]] - matrix(rnorm((i+3)*2), (i+3))
| vec
|
do.call(rbind, vec)
|
| Now I want to change the type of vec from list to a matrix with (4+5+6)
| rows and 2
Fala ai cara!
Era o RMySQL mesmo q eu precisava, vlw
Bernardo Rangel tura wrote:
On Sat, 2009-07-04 at 22:24 -0700, JoK LoQ wrote:
I'm dealing with lots of columns and conditions, wats t best way to deal
with
that?
How do I work with SQL on R? the manual is quite confuse talking about
On Sun, Jul 5, 2009 at 1:00 PM, Henrique Dallazuannawww...@gmail.com wrote:
Yes,
First, select only columns C1 to C6, then look for values greater than 0,
after use this to select the columns in original subset.
On Sun, Jul 5, 2009 at 4:48 PM, Mark Knecht markkne...@gmail.com wrote:
On
We’re very pleased to announce another update to
http://crantastic.org/, the community site for R packages. Notable new
features include:
* More package relationships. We now have enhances, imports, and
reverse relationships.
* Easier rating: just log-in, and click the number of stars you
I think the root cause of a number of my coding problems in R right
now is my lack of skills in reading and grabbing portions of the data
out of arrays. I'm new at this. (And not a programmer) I need to find
some good examples to read and test on that subject. If I could locate
which column
Try,
library(fGarch)
fitmodel = garchFit(formula=~ar(1)+~garch(1,1), data=garat)
fitmo...@fit$ics #is a vector with Information Criterion Statistics
fitmo...@fit$ics[1] #is the AIC
Ben Bolker wrote:
Vasileios Ismyrlis vasismir at gmail.com writes:
library(fGarch)
fit =
Try,
library(fGarch)
fitmodel = garchFit(formula=~ar(1)+~garch(1,1), data=garat)
fitmo...@fit$ics #is a vector with Information Criterion Statistics
fitmo...@fit$ics[1] #is the AIC
Murilo Eiji Doi
Ben Bolker wrote:
Vasileios Ismyrlis vasismir at gmail.com writes:
On Sun, Jul 5, 2009 at 1:44 PM, hadley wickhamh.wick...@gmail.com wrote:
I think the root cause of a number of my coding problems in R right
now is my lack of skills in reading and grabbing portions of the data
out of arrays. I'm new at this. (And not a programmer) I need to find
some good
Hi,
Thank you for using Rdonlp2.
2009/7/4 Lars Bishop lars...@gmail.com:
Error in tryCatchList(expr, classes, parentenv, handlers) :
SET_VECTOR_ELT() can only be applied to a 'list', not a 'character'
I guess you are using an older version of Rdonlp2 that is incompatible
to R-2.9.0. I have
At 10:42 AM -0700 7/5/09, Mark Knecht wrote:
2009/7/5 Uwe Ligges lig...@statistik.tu-dortmund.de:
- a lot of other conversation omitted, to focus on the following
Currently my data is one experiment per row, but that's wasting space
as most experiments only take 20% of the row and 80% of
You can also derive what you need using the rle()
function, though the which() solution may be
easier.
-Don
At 4:20 PM -0300 7/5/09, Henrique Dallazuanna wrote:
Content-Type: text/plain
Content-Disposition: inline
Content-length: 944
Try this:
which(c(0, diff(x)) != 0)
On Sun, Jul 5,
Is there anyway in ggplot2 to set the aesthetics for a geom_boxplot
directly, rather than having them computed by an implicit stat_boxplot?
If I try:
ggplot(data = t, aes(x = factor(x))) + geom_boxplot(coef=NULL,
aes(lower=y_q1, upper=y_q3, middle=y_med, ymin=y_min, ymax=y_max))
I get the
Hi Malcolm,
You need to tell geom_boxplot not to use stat_boxplot:
geom_boxplot(aes(lower=y_q1, upper=y_q3, middle=y_med, ymin=y_min,
ymax=y_max), stat = identity)
Hadley
On Mon, Jul 6, 2009 at 6:55 AM, Malcolm Ryanmalco...@cse.unsw.edu.au wrote:
Is there anyway in ggplot2 to set the
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