Idgarad wrote:
... Very long non-self-contained code removed
Suggestions on how to handle the whole linearModel and the child data?
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PLEASE do read the
R,
I want to get means and confidence limits on the original scale for
the treatment effect after running a mixed model.
The data are:
response-c(16,4,5,8,41,45,10,15,11,3,1,64,41,23,18,16,10,22,2,3)
block-factor(c(A,A,A,A,I,I,I,I,N,N,N,P,P,P,P,P,P,S,S,S))
On 16/07/09 00:13, Chris Anderson wrote:
I'm trying to pull data from multiple MS SQL Sever databse in R. I can access
the databases one at a time, but the tables are to large to pull the entire
tables then join then in R. So I need to do a SQL join that will join the
tables from the each of
Hi All,
I am using the following data for determining level of agreement. I am
fleidd kappam
Following is an example of my data frame
P1 P2 P3
H2 2 2
M2 4 2
L 2 2 2
Looking at the above data the kappa value shoudl be close to 1, but I am
getting negative
Hi,
Does anybody know whether it's possible (and sensible) to calculate R^2 (or
something approximating R^2) on the results of a major axis Model II regression
done by lmodel2?
The function lmodel2 provides an R^2 for the OLS regression only (example below)
Also, is it possible to extract
Hello Steve,
On Thu, Jul 16, 2009 at 2:28 AM, S Ellisons.elli...@lgc.co.uk wrote:
Auto-updating sounds hard in R for a 'regular' data frame. You could
perhaps define an entirely new class of object and define data
entry/indexing methods so that, say, they sought functions in an
attribute
Hi R-users,
I would like to detach and installed the fBasics package but it gives me this
message:
detach(package:fBasics,unload=TRUE)
Error in detach(package:fBasics, unload = TRUE) : invalid name
install.packages(repos=NULL,pkgs=c:\\Tinn-R\\fBasics_2100.77.zip)
package 'fBasics'
I imagine I make a function whose results are a Matrix Z
How cn I save in a txt or excel file the result of apply my function?
something similar to save Z.txt.
Thanks in advance.
[[alternative HTML version deleted]]
__
R-help@r-project.org
Hi
r-help-boun...@r-project.org napsal dne 15.07.2009 17:59:39:
see ?ifelse
you didn't specify what happens if a value is exactly zero in the
dataset
and so i've just bundled it in with the negative case:
x - rnorm(20, 0, 1)
y-ifelse(x=0, 10, 5)
For this simple case you can also use
At 10:37 13/07/2009, anna.bucharova wrote:
Dear all.
I am sort of beginner with R. I do logistic regression with binomial
response variable and several continuous and categorical variables. In one
categorical variable, zero cell occures (2x2 table looks like
7 - 0
23 - 25
This leads to
Hi Jose,
Have you tried:
Z - diag(10)
write.csv(Z, file = mymatrix.csv)
type ?write.csv to see the options to get a better result with excel.
However you can open the file mymatrix.csv with excel
(it is stored in the My Documents folder in windows).
Ok, hope that helps.
Next time you can try
Hi
r-help-boun...@r-project.org napsal dne 16.07.2009 11:31:25:
I imagine I make a function whose results are a Matrix Z
How cn I save in a txt or excel file the result of apply my function?
something similar to save Z.txt.
write.table(tab, clipboard, sep = \t, row.names = F)
to paste to
Have a look at ?write.table
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
and Forest
Cel biometrie, methodologie en kwaliteitszorg / Section biometrics,
methodology and
Hello all
I have been working to fix this for weeks now, It should be simple to fix.
Please help
Let me explain what I am doing, I have a data set for 65 countries over a
period of 9 years (2000-2008). Each country has on an average say 2000
interviews, so that the total set has roughly
bfoubert b.foub...@maastrichtuniversity.nl writes:
I'm running R/snow on a small cluster with opensuse, openmpi, and openshh. I
start up R with mpirun -n 1 R --no-save. That works but it strikes me how
easily I get kicked out of R whenever I run into syntax errors. Is there a
way to avoid
Dear all,
I'm using Roxygen for the first time and I'm getting a rather cryptic
error message. I must be doing something wrong but I have no clue what
is it. Any suggestions?
Regards,
Thierry
roxygenize(AFLP, roxygen.dir = AFLP, copy.package = FALSE,
unlink.target = FALSE)
Writing AFLP.outlier
Dear Saurav,
I get the feeling that you are looking for mixed models. Try something
like.
library(lme4)
glmer(s ~ age + gender + gemedu + gemhinc + es_gdppc + imf_pop +
estbbo_m + (1|yearctry), family = binomial(link = probit), data =
adpopdata)
HTH,
Thierry
At 10:37 13/07/2009, anna.bucharova wrote:
Dear all.
I am sort of beginner with R. I do logistic regression with binomial
response variable and several continuous and categorical variables. In one
categorical variable, zero cell occures (2x2 table looks like
7 - 0
23 - 25
This leads to
On 7/15/2009 9:56 PM, Carl Witthoft wrote:
If you want to take the second approach, it can be relatively easily
generalized by calculating the cex values based on the count of ordered
pairs in the original dataset.
Here's a data set:
xy
x y
[1,] 1 4
[2,] 1 5
[3,] 2 3
[4,] 3 3
Gates, Michael wrote:
...
Members,
I recently submitted my first package to the submissions ftp site on CRAN
(7.3.09). The package has remained on the server since with no action? Do
package review/updates occur monthly? When I submitted, I sent an email to CRAN
to let them know about the
NDC/jshipman wrote:
Hi,
I am new to R plot. I am trying to increase the data point
observation when duplicate data points exist
xy
110
110
23
45
9 8
in the about example 1, 10 would be displayed larger than the other
data points. Could someone give me some
Marlin Keith Cox wrote:
I have re-labeled tick marks on the x axis. The problem is that by using
axes=FALSE, the axes disappears and when they are called back using
axis(side=1)..etc. the axis on sides 1 and 2 do not meet at the bottom left
corner of the graph. I would also like to have the
Hi all,
I want to change the order of the panels in a Coplot (2x2 panels).
Instead of the default order of the panels from bottom left to top right, I
would like to display them from top left to bottom right.
Is there any way I can do this?
thanks,
David
--
View this message in context:
Hi. I tried the following:
F-function(x,y,b1,b2,b3) b1/(1+b2*(x+b3*y));
t-data.frame(ExM=c(T$ExM,F(T$S1,T$S2,0.2,0.2,51.28205)),S1=rep(T$S1,2),S2=rep(T$S2,2),gr=c(rep(1,length(T$ExM)),rep(2,length(T$ExM;
library(lattice);
wireframe(ExM ~ S1 * S2, data = t, groups=gr);
where T
You need to use %Y (upper case) for
z=strptime( 07/14/2009 13:41:00,%m/%d/%Y %H:%M)
z
[1] 2009-07-14 13:41:00
On Wed, Jul 15, 2009 at 11:45 PM, Alon Ben-Arialon.ben...@gmail.com wrote:
Hello
I am trying to read a date and time from a file and convert them to POSIXct
using strptime()
Gates, Michael wrote:
Members,
I recently submitted my first package to the submissions ftp site on CRAN
(7.3.09). The package has remained on the server since with no action? Do
package review/updates occur monthly? When I submitted, I sent an email to
CRAN to let them know about the
Hello,
Please forgive me that this question is so basic, but i have not been able
to find a solution in any of the basic R introductions, in the R wiki, or in
the stats textbook i'm using to learn R. I run R on a macintosh, and i have
not been able to load any data files yet. For instance, if I
On Jul 16, 2009, at 6:08 AM, stvienna wiener wrote:
Have you tried:
Z - diag(10)
write.csv(Z, file = mymatrix.csv)
type ?write.csv to see the options to get a better result with
excel.
However you can open the file mymatrix.csv with excel
(it is stored in the My Documents folder in
On Thu, Jul 16, 2009 at 1:32 PM, caballojamespi...@hotmail.com wrote:
Error in file(file, r) : cannot open the connection
In addition: Warning message:
In file(file, r) :
cannot open file 'c:\harddrivename\users\username\desktop\schools.txt':
No such file or directory.
I'm guessing that
On Jul 16, 2009, at 6:32 AM, caballo wrote:
Hello,
Please forgive me that this question is so basic, but i have not
been able
to find a solution in any of the basic R introductions, in the R
wiki, or in
the stats textbook i'm using to learn R. I run R on a macintosh, and
i have
not been
Thanks Gabor,
I tried a little bit, and your example works. However, it seems that
the read.zoo has a limitation of records up to around 300 !? I took
your suggestion and modified a little bit in order to read from the
file which contains about 9000 records:
dataTs - read.zoo(filename.csv,
On Jul 16, 2009, at 7:40 AM, Michael Knudsen wrote:
On Thu, Jul 16, 2009 at 1:32 PM, caballojamespi...@hotmail.com
wrote:
Error in file(file, r) : cannot open the connection
In addition: Warning message:
In file(file, r) :
cannot open file 'c:\harddrivename\users\username\desktop
There is a worked example of exactly what you are trying to do on the
wireframe/cloud help page. Thinking incorrectly (and foolishly as it
turned out) that this was a reproducible example. I tried your code.
I then tried the help page code. If reviewing the help page is
ineffective, then
On Thu, Jul 16, 2009 at 3:04 PM, Marc Schwartzmarc_schwa...@me.com wrote:
Actually, by default, the OSX HFS+ file system is not case sensitive:
Sorry. I just took that for granted, as Mac (at least in a terminal)
is very similar to Linux.
--
Michael Knudsen
micknud...@gmail.com
Hi, All,
I passed an array reference to the R script and do not know how to do
dereferencing in the R script. Anybody has some suggestion?
Many thanks
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PLEASE do read
On Jul 16, 2009, at 8:44 AM, Marc Schwartz wrote:
On Jul 16, 2009, at 6:32 AM, caballo wrote:
Hello,
Please forgive me that this question is so basic, but i have not
been able
to find a solution in any of the basic R introductions, in the R
wiki, or in
the stats textbook i'm using to
Hi Karsten,
as you will know, SweaveListingUtils is a contributed package,
so it is a good habit to address the package maintainer (which
is me in this case) directly.
I clearly do not mind discussing this on r-help, but maybe
this already quite busy mailing list should not be bothered
too much
xin liu wrote:
Hi, All,
I passed an array reference to the R script and do not know how to do
dereferencing in the R script. Anybody has some suggestion?
R doesn't have references, so it doesn't do dereferencing.
Duncan Murdoch
Many thanks
__
On Thu, Jul 16, 2009 at 2:44 PM, Marc Schwartzmarc_schwa...@me.com wrote:
If you are using the OSX GUI (R.app) you may also want to review the OSX
FAQ:
If you use the GUI, you may also just want to hit cmd+d and browse to
your preferred working directory. If you set the working directory to
It looks like Biostrings function writeFASTA overwrites the output file at
each run.
It seems it does not support the append parameter.
I have to generate one big file gathering a miRNA identifier and relative
sequence followd by a variable number of dara records pertaining such a miRNA
On Jul 16, 2009, at 8:15 AM, Michael Knudsen wrote:
On Thu, Jul 16, 2009 at 3:04 PM, Marc Schwartzmarc_schwa...@me.com
wrote:
Actually, by default, the OSX HFS+ file system is not case sensitive:
Sorry. I just took that for granted, as Mac (at least in a terminal)
is very similar to
Hi Peter,
- Forwarded message --
From: Peter Schmidtke pschmid...@mmb.pcb.ub.es
To: r-help@r-project.org
Date: Wed, 15 Jul 2009 12:27:17 +0200
Subject: [R] interacting variables in a formulae in R
Dear R Mailing Subscribers,
I just have a question of how R handles
Hi,
I was wondering what would be the best way to check if the three dots
argument contains any arguments (i.e. does ... contain any arguments or
not? )
#Example
test = function(x,y, ...)
{
#Wanted R-Code
# if(empty(...))
#do some calculation
plot(x,y,...)
}
Thanks
Try
dots - list(...)
if (length(dots) == 0) {
## do something
}
On Thu, Jul 16, 2009 at 6:46 AM, Thomas Roth (geb.
Kaliwe)hamstersqu...@web.de wrote:
Hi,
I was wondering what would be the best way to check if the three dots
argument contains any arguments (i.e. does ... contain any
one way is:
test - function(x, y, ...) {
dots - list(...)
if (length(dots)) cat(\nnon-empty\n) else cat(\nempty\n)
}
test(1, 1)
test(1, 1, 1)
I hope it helps.
Best,
Dimitris
Thomas Roth (geb. Kaliwe) wrote:
Hi,
I was wondering what would be the best way to check if the three dots
Thank you both.
Thomas
Dimitris Rizopoulos schrieb:
one way is:
test - function(x, y, ...) {
dots - list(...)
if (length(dots)) cat(\nnon-empty\n) else cat(\nempty\n)
}
test(1, 1)
test(1, 1, 1)
I hope it helps.
Best,
Dimitris
Thomas Roth (geb. Kaliwe) wrote:
Hi,
I was
So then I am to assume that the output of 'cat' can be truncated by passing it
bad arrays. That is the only difference between the reproducible code you
show and mine. It is just a theory but say that the components array is not
dimmensioned for 4 elements. It seems a little strange if that is
djacinto wrote:
I want to change the order of the panels in a Coplot (2x2 panels).
Instead of the default order of the panels from bottom left to top right,
I would like to display them from top left to bottom right.
coplot is a bit a dinosaur from times when there was no lattice in R.
On 7/16/2009 10:21 AM, rkevinbur...@charter.net wrote:
So then I am to assume that the output of 'cat' can be truncated by passing it bad arrays.
I certainly wouldn't draw that conclusion. Without a reproducible
example, my assumption would be that it is unrelated to cat().
Duncan Murdoch
What do you mean by 'passing an array reference' and 'dereferencing' and
what do you mean by an 'R script'? What language(s) are you accustomed to?
If you mean 'passing an array value' to an 'R function', you just use the
argument name. Since R uses call-by-value (modulo the substitute
There is no such limitation. There is likely a data problem with
one or more records past the 280th one.
Suggest you remove the first 280 and then divide the remaining
in half and try each half and keep dividing that way until you have
located the offending record or records.
On Thu, Jul 16,
Kevin,
The habitués of this mailing list get irritated when users mail in
problem reports which don't include enough information to reproduce
the problem, as requested in the standard footer of r-help mail
(PLEASE ... provide commented, minimal, self-contained, reproducible
code.) This irritation
Thxs to all of you
Alberto
On Thu, Jul 16, 2009 at 7:03 AM, Gabor Grothendieck ggrothendi...@gmail.com
wrote:
Here is a variation on the solution below (first line
is the same but second differs):
ind - which(a == 0, arr = TRUE)
mapply([, dimnames(a), as.data.frame(ind))
[,1] [,2]
Hi,
The following works fine:
f
[1] 0.08 0.03 0.04
A2
[,1] [,2] [,3]
[1,] 0.00e+00 0.00 0.00e+00
[2,] 0.00e+00 0.00 0.00e+00
[3,] 2.999651e-03 0.0009094342 1.945708e-03
[4,] 4.124431e-05 0.0001360390 1.203345e-05
[5,] 3.027932e-04
By the way, note that read.zoo passes the ... arguments to read.table
and so can use the same skip= and nrows= arguments that read.table
uses. These can be used to read in a subset of the rows.
On Thu, Jul 16, 2009 at 10:35 AM, Gabor
Grothendieckggrothendi...@gmail.com wrote:
There is no such
Hello,
I have been attempting to write a script that automatically calculates time
intervals from a list of hh.mm.ss.ms timestamps. Should be easy, but I keep
running into problems. Any help would be greatly appreciated!!
Problems:
1. If I parse the timestamp, it doesn't always return the digits
Try this:
Lines - 19:21:59.855
+ 19:21:59.905
+ 19:21:59.955
+ 19:22:0.5
+ 19:22:0.55
+ 19:22:0.105
+ 19:22:0.155
+ 19:22:0.205
+ 19:22:0.255
+ 19:22:0.305
+ 19:22:0.355
+ 19:22:0.405
DF - read.table(textConnection(Lines))
library(chron)
tt - times(DF[[1]])
diff(tt)
[1]
Hi,
Is there a function in R to do a-b where a and b are two non-numeric sets
(or intersection complement of these two sets).
Kind Regards,
Praveen.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Is there a function in R to do a-b where a and b are two non-numeric
sets
(or intersection complement of these two sets).
I think you're looking for setdiff
-steve
--
Steve Lianoglou
Graduate Student: Physiology, Biophysics and Systems Biology
Weill Medical College of Cornell University
Leave the mgp setting alone and use xlab='' when you create the original plot.
This will put the y-label in the usual place and not create the x-label. Then
use the title or mtext function to place the x label where you want it.
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical
Or...
X = c (red, blue, green, black ) ; Y = c(red, blue,
green, magenta, cyan)
unique ( c ( X [X %in% Y] , Y [Y %in% X] ) )
[1] red blue green
David
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Praveen Surendran
It has to be related to 'cat' because the output of 'cat' is truncated. I am
just tyring to find out some possible reasons as to why it is truncated. I have
been unable to form an array like is in the test program. Do you think there is
something else that is gobbling up the output from cat
All,
I've been using AQUAMACS Emacs to develop R code and run/test the code
by clicking eval line and step from within the editor which opens R
in a new tab and displays the output. This calls X11 when a display
window opens up. This was all working fine weeks ago but now when I
try to get a
Hi listers,
I am
--
View this message in context:
http://www.nabble.com/Sample-Function-tp24519071p24519071.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Hi there,
I'm trying to find out the command to stop clipping to plot region in
ggplot.
I have a bar chart (axis flipped) with labels on the bars, but the
labels are clipped at the plot region box.
I know it's possible to turn this off for base and lattice, but how
about ggplot?
Hi All,
This week SPSS Inc. announced version 18, which has some very
interesting enhancements regarding R. It will now ship with R on the
DVD, along with the PASW Statistics-R Integration Package. Previously
this required a download of R, and of the Integration Package. This
may be the first
Hi listers,
Suppose I have a dataset with n=10 observations and I want to sample with
replacement.
My new sample is of size m=9.
So, I am using the following code...
newsample-dataset[sample(m,replace=T),]
The problem is that generates the new sample and the last observation of my
data set is
a
[[1]]
[1] 1 2 3
[[2]]
[1] 4 5 6
[[3]]
[1] 7 8 9
I need to access individual elements, such as the 5 or the 9. Can anyone
please tell me the syntax to do this?
tia
--
View this message in context:
http://www.nabble.com/Problems-with-lists...-tp24519517p24519517.html
Sent from the R help
Like,
a = list (1:3,4:6,7:9)
a
[[1]]
[1] 1 2 3
[[2]]
[1] 4 5 6
[[3]]
[1] 7 8 9
a [[2]] [2]
[1] 5
a [[3]] [3]
[1] 9
HTH
--
David
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of voidobscura
Sent: Thursday, July 16, 2009
have a look at the help page for ?[; try also this
a[[2]]
a[[2]][2]
a[[3]][3]
Best,
Dimitris
voidobscura wrote:
a
[[1]]
[1] 1 2 3
[[2]]
[1] 4 5 6
[[3]]
[1] 7 8 9
I need to access individual elements, such as the 5 or the 9. Can anyone
please tell me the syntax to do this?
tia
--
Hi,
I am trying to do run the following model saved in C:/bugs/sus.bug
model {
for (i in 1:n){
y[i] ~ dpois(lamdba[i])
log(lambda[i]) - mu+bmale[male[i]]+bschn[schn[i]]+epsilon[i] #
epsilon[i] ~ dnorm(0,tau.epsilon)
}
mu ~ dnorm(0,.0001)
bmale ~ dnorm(0,.0001)
tau.epsilon -
Kurt Hornik is currently out of office and will be back soon.
Moreover, CRAN was also unmanned in repspect to all other issues since
all other CRAN maintainers have been attending useR! and/or DSC conferences.
Just a bit more patience, CRAN will be in regular duty soon.
Best,
Uwe Ligges
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of MarcioRibeiro
Sent: Thursday, July 16, 2009 8:56 AM
To: r-help@r-project.org
Subject: [R] Sample Function
Hi listers,
Suppose I have a dataset with n=10 observations and I
Hi there!
S provide some functions, such as qq.weibull, to produce various qqplot
for model checking. But I can't find the corresponding version in R. Does
any R package available to produce these qqplots?
Many thanks in advance!!
Cheers~~~
Popo
[[alternative HTML version
Hi,
On Jul 16, 2009, at 2:03 PM, popo UBC wrote:
Hi there!
S provide some functions, such as qq.weibull, to produce various
qqplot
for model checking. But I can't find the corresponding version in R.
Does
any R package available to produce these qqplots?
Many thanks in advance!!
Hi,
I'll try to keep my question brief and to the point, to anyone who helps 'THANK
YOU!'
I want to get a circle/ring/buffer or some other form of drawn line around
certain points on a x,y plot, the points usually don't form a circle, often
they form a 'wobbly' shape, so ideally I'd like
This is just a variation of David's solution below:
intersect(X,Y)
# [1] red blue green
HTH,
Jorge
On Thu, Jul 16, 2009 at 12:07 PM, David Huffer david.huf...@csosa.govwrote:
Or...
X = c (red, blue, green, black ) ; Y = c(red, blue,
green, magenta, cyan)
unique ( c ( X [X %in% Y] ,
Look at the chull function and its examples.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Ahmed, Sadia
It sounds like you might want to draw the convex hull for each group
of points. There is a package called chplot which appears to
do this, though I haven't used it...
albyn
On Thu, Jul 16, 2009 at 06:23:54PM +0100, Ahmed, Sadia wrote:
Hi,
I'll try to keep my question brief and to the
Alright, so I am trying to write my own function to calculate column sums in
a matrix. I want the result as a single list with the values.
So far I have:
csum-function(m)
{
a = data.frame(m)
s = lapply(a,sum)
return(s)
}
What is the easiest way to have it return in a
The easiest way is to just do something like this:
mdat - matrix(c(4,2,3, 11,12,13), nrow = 2, ncol=3)
mdat
[,1] [,2] [,3]
[1,]43 12
[2,]2 11 13
as.vector ( colSums ( mdat ) )
[1] 6 14 25
HTH
--
David
-Original Message-
From: r-help-boun...@r-project.org
Dear voidobscura,
Try either:
colSums(mdat)
# or
apply(mdat, 2, sum)
See ?colSums and ?apply for more details.
HTH,
Jorge
On Thu, Jul 16, 2009 at 2:25 PM, voidobscura nshah...@gmail.com wrote:
Alright, so I am trying to write my own function to calculate column sums
in
a matrix. I
What is dataset?
What is this supposed to be doing?
newsample-dataset[sample(m,replace=T),]
--- On Thu, 7/16/09, MarcioRibeiro mes...@pop.com.br wrote:
From: MarcioRibeiro mes...@pop.com.br
Subject: [R] Sample Function
To: r-help@r-project.org
Received: Thursday, July 16, 2009, 11:55 AM
Not sure if there is an R way to do this or a regular express way, but here is
what I am trying to do.
I've got lots of data where the format is HH:MM:SS, but I need to format it
like HH:MM:00, i.e. round the second down to zero.
What is the best way to do this?
Thanks again.
Jason
I am having trouble setting up a nested anova model. Here is a
truncated version of my data:
data
Ind Treatment PC1
1 PER14SC 1.14105282
2 PER14SH 1.45348615
3 PER14AC 2.45096904
4 PER25SC 1.23687887
5 PER25SH 4.54797450
6
Hello,
I'm brand new to using R. (I've been using Rapid Miner, but would like
to move over to R since it gives me much more functionality.)
I'm trying to learn how to do a conditional logit model.
My data has one dependent variable, 2 independent variables and a
group variable.
example:
On 16-Jul-09 19:40:20, Noah Silverman wrote:
Hello,
I'm brand new to using R. (I've been using Rapid Miner, but would
like to move over to R since it gives me much more functionality.)
I'm trying to learn how to do a conditional logit model.
My data has one dependent variable, 2
Have you looked at the chron package? It has a trunc.times function:
??times# would have shown this to you
And the help page appears to provide exactly what was requested.
-puzzlement follows
I did get somewhat unexpected results when I applied what seems to be
the
Hi,
Not sure if there is an R way to do this or a regular express way,
but here is what I am trying to do.
I've got lots of data where the format is HH:MM:SS, but I need to
format it like HH:MM:00, i.e. round the second down to zero.
What is the best way to do this?
Probably not the
It your times are chron objects then
trunc(tt, minutes)
where tt are your times may do what you want. It truncated but that seems to
be what you want.
--- On Thu, 7/16/09, Jason Rupert jasonkrup...@yahoo.com wrote:
From: Jason Rupert jasonkrup...@yahoo.com
Subject: [R] Best way to
Hint: You have 27 observations fit by 27 fixed effects (including the mean).
You need to consult a statistician, as you seem not to have the basic
statistical understanding required. Person should be a random effect. Was
this a homework problem, perchance?
Bert Gunter
Genentech Nonclinical
Dear R-Users,
i want to use the function mice of the mice package with data, that
contains dates, but this gives an error
x - Sys.time()
dat - data.frame(dates=(1:10)*60*60*24+x, size=rnorm(10))
dat$dates[c(3,7)]-NA
mice(dat)
Fehler in check.imputationMethod(imputationMethod,
It is because the nesting structure perfectly explains the data (i.e., there
is only one observation and, therefore, no variation for each Ind in each
Treatment).
e=rnorm(90,0,1)
x=rep(1:3,30)
y=rep(1:30,each=3)
z=x+y+e
ano=aov(z~factor(y)/factor(x))
ano
residuals(ano)
Best,
Daniel
probably :
a - rep(HH:MM:SS, 5)
substring(a, 7) = 00
a
Not sure if there is an R way to do this or a regular express way, but here
is what I am trying to do.
I've got lots of data where the format is HH:MM:SS, but I need to format it
like HH:MM:00, i.e. round the second down to zero.
What is
Dang it. I forgot to mention the actual format of the time is the following:
HH:MM:SS AM or HH:MM:SS PM
And I would still hope for them to end up with the following format:
HH:MM:00 AM or HH:MM:00 PM
How would you propose handling that condition?
I tried to use strsplit with items to split
You can still use my suggestion (sent offline)
if you have a vector of strings, or just one
my.str - HH:MM:SS AM
substr(my.str,7,8) - 00
my.str
[1] HH:MM:00 AM
Doesn't matter if it's AM or PM because the function is just acting
on the 7th and 8th characters.
On Jul 16, 2009, at 1:20
Dear sir,
I have 2 questions:
Question 1:
suppose that we have the following:
a-matrix(c(0,2,0,4,0,6,5,8,0),nrow=3)
colnames(a)-c(F1,F2,F3)
rownames(a)-c(A1,A2,A3)
a
ind - which(a == 0, arr = TRUE)
mapply([, dimnames(a), as.data.frame(ind))
I want to add a column to the result. This Column
Hi Colleagues,
Could you please help?
I get as the output of my calculations following
[1] 0.00e+00 1.89e-04 3.933000e-05 1.701501e-04 2.040456e-04
[6] 3.119242e-04 2.545665e-04 1.893930e-03 1.303112e-03 9.880183e-04
[11] 1.504378e-03 1.549246e-03 5.877690e-04
On Thu, Jul 16, 2009 at 10:09 PM, Andriy Fetsun fet...@googlemail.com wrote:
[1] 0.00e+00 1.89e-04 3.933000e-05 1.701501e-04 2.040456e-04
[6] 3.119242e-04 2.545665e-04 1.893930e-03 1.303112e-03 9.880183e-04
[11] 1.504378e-03 1.549246e-03 5.877690e-04 4.771359e-04
Dear R-help,
I am having quite a difficult time coming up with what I want to do involving
named lists.
I have a list of logical expressions, and I would really like it if the names
of the components of the list were identical to the corresponding logical
expression.
So, as an example:
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