Hello, I'm rather new to R and I want to do some image analysis. Is there a
way to read jpeg files into a matrix like matlab's imread?
--
View this message in context:
http://www.nabble.com/Reading-Image-Files-tp24619129p24619129.html
Sent from the R help mailing list archive at Nabble.com.
On 07/22/2009 06:49 PM, Liviu Andronic wrote:
Hello,
On Wed, Jul 22, 2009 at 6:25 PM, Bert Guntergunter.ber...@gene.com wrote:
You can find a list of IDE's/R code editors for R here:
http://www.sciviews.org/_rgui/projects/Editors.html
However, this is somewhat dated, and you may find others
You may want to use the function corner.label from the plotrix-package.
Frank
Mark Na mtb...@gmail.com 21.07.2009 23:03
Dear R-helpers,
I wish to place some text in a plot, at approx 10% of my upper xlim
and
approx 90% of my upper ylim, i.e.
plot(log(all$SR,10)~log(all$AREA,10))
On Wed, Jul 22, 2009 at 10:18 PM, Josh Rollj_r...@hotmail.com wrote:
In `[-.factor`(`*tmp*`, Props_$pct_vacant == #NULL!, value = 0) :
invalid factor level, NAs generated
Thats what made me wonder if the #NULL! value was being treated
differently than a typical NULL value. Thoughts?
I
Hi all,
After a lot of rewriting, I am happy to say that plotrix_2.6-4 is on
CRAN. The reason I am announcing this is that the newish hierobarp
function has had a complete rewrite. This was the result of my learning
that the old version was horrendously slow on large data sets. Let me
know if
I just have a simple question. I'm using the predict function, and I get
about 1000 values. Now, how would I make it into a data frame or a list so
that I can easily use Excel to graph the data? Right now, it's in horizontal
lines, and it would be a pain to copy and paste and make it into a
Hi,
how to install packages without Tcl/Tk interface?
For instance, if I run install.packages('R.oo'), I need to select Cran
repository via graphic interface. How to avoid this?
bye, Matej
__
R-help@r-project.org mailing list
Dear R-helpers,
does anyone know of some package/function that can build a network from
the functions that are implemented in a package,
i.e. visualize the cross-references from one function to another in the
same or some dependent package?
An example would be a function like 'nls' on top of the
Allan Engelhardt allane at cybaea.com writes:
It is a little stupid, but the length of a vector is limited to 2^31-1
entries on any platform. A matrix is stored as a vector, so the product
of all dimensions is also limited to 2^31-1.
Allan.
Matthew Gwynne wrote:
Hi,
I have been
Hi,
I have two products which are substitudes. I try to fix a system as below to
mydata.
Demand1 = A1 -B1*Price1 + C1*Price2
Demand2 = A2 +B2*Price1 - C2*Price2
I would expect C1 B2 to be symmetric, If they are truly substitude. How
can I enforce this symmetry when creating a system of
On 07/23/2009 08:58 AM, Matej Kovacic wrote:
Hi,
how to install packages without Tcl/Tk interface?
For instance, if I run install.packages('R.oo'), I need to select Cran
repository via graphic interface. How to avoid this?
bye, Matej
Use the repos argument of install.packages:
On Wed, 2009-07-22 at 14:07 -0700, megh wrote:
Thanks for your suggestions. I need one more thing :
x = y = vector(list)
for (i in 1:5) x[[i]] = rnorm(2); y[[i]] = rnorm(2)
Here I want to get t(x[[i]]) %*% y[[i]] for each i. Can anyone please help
me?
Two ways:
set.seed(123)
x = y =
Hi
Strange. Before starting with R about 10 years ago I used Excel for for
graphing too. As soon as I learned few tricks and read intro documents I
abandoned Excel for graphing almost completely. Now even for simple
visualisations of data I copy them ***from*** spreadsheet to R. But as you
Hi,
This post might get you started:
http://romainfrancois.blog.free.fr/index.php?post/2009/03/07/What-functions-are-called-by-my-function
tail( callees( nls ), 20 )
functions
names new.env nls.control nlsModel
812
Dear Mo
You only need to use the name of a variable in your dataframe. The
example below lets the size of the points depend on the variable carat.
library(ggplot2)
ggplot(diamonds, aes(x = table, y = price, size = carat)) + geom_point()
HTH,
Thierry
Hi,
qseq is a variable from the data.frame mtcars,
that has been used to create the initial plot p.
library(ggplot2)
p - ggplot(mtcars, aes(wt, mpg))
p + geom_point(aes(size = qsec)
Just replace qseq by your variable of interest.
Regards,
Matthieu
Dear R users,
I'm trying to get a good x-scale and labels on a plot like the one below.
library(lattice)
## make almost a year of hourly data:
mydat - data.frame(dates = Sys.time() + 3600 * (1:7000), y = runif(7000))
## plot it
xyplot(y ~ dates, data = mydat, type = l)
Only one x-label is
That problem is that for every y I get a different x and thus cant
create an array as in the help page examples.
I was just wondering, whether there is a possibility to create such a
contour plot easily without having to spend too much time with setting
up a suitable matrix manually.
Armin
Frank Bloos wrote:
You may want to use the function corner.label from the plotrix-package.
Frank
Mark Na mtb...@gmail.com 21.07.2009 23:03
Dear R-helpers,
I wish to place some text in a plot, at approx 10% of my upper xlim
and
approx 90% of my upper ylim, i.e.
Hi
maybe package akima with function interp can help you
Regards
Petr
r-help-boun...@r-project.org napsal dne 23.07.2009 11:04:25:
That problem is that for every y I get a different x and thus cant
create an array as in the help page examples.
I was just wondering, whether there is a
Have a look at the reshape and ggplot2 package.
ds - matrix(rnorm(100), nrow = 10)
library(reshape)
molten - melt(data = ds)
library(ggplot2)
ggplot(molten, aes(x = X1, y = X2, z = value)) + geom_contour()
HTH,
Thierry
David Winsemius wrote:
On Jul 22, 2009, at 3:02 PM, malcolm Crouch wrote:
Hi ,
How can you tell which packages work on windows ?
This is the place to find listing for automated compiler check results:
http://cran.stat.ucla.edu/bin/windows/contrib/checkSummaryWin.html
Yes, and
Hi everyone,
I am trying to analyse my data from a small plant experiment (for a meeting
tomorrow afternoon) and am a beginner to R so I apologise if this is a very
basic question.
I carried out a plant experiment examining plant interactions between two
species (A and B) under different
Hey,
I want to compile R version 2.9.1 on debian stable but the make command
stops with this message:
...
Building/Updating help pages for package 'tcltk'
Formats: text html latex example
make[2]: Leaving directory `/usr/src/R/R-2.9.1/src/library'
make[1]: Leaving directory
Stefan wrote:
Hey,
I want to compile R version 2.9.1 on debian stable but the make command
stops with this message:
...
Building/Updating help pages for package 'tcltk'
Formats: text html latex example
make[2]: Leaving directory `/usr/src/R/R-2.9.1/src/library'
make[1]: Leaving directory
On Thu, Jul 23, 2009 at 12:16:36PM +0200, Stefan wrote:
I want to compile R version 2.9.1 on debian stable but the make command
stops with this message:
...
begin installing recommended package VR
Error in library(Hmisc, verbose = FALSE) :
there is no package called 'Hmisc'
Execution
Hi everyone,
Is there any counter function in R for the following purpose:
x - matrix(c(1,1,0,2,1,0,0,2,0,1,2,1,2,1,0,1),nrow=4)
As I would like to know how many zeros, ones, and twos in each row of x?
Many thank in advance,
Amor
[[alternative HTML version deleted]]
apply(x, 1, table)
Uwe Ligges
amor Gandhi wrote:
Hi everyone,
Is there any counter function in R for the following purpose:
x - matrix(c(1,1,0,2,1,0,0,2,0,1,2,1,2,1,0,1),nrow=4)
As I would like to know how many zeros, ones, and twos in each row of x?
Many thank in advance,
Amor
On Thu, Jul 23, 2009 at 10:44:16AM +, amor Gandhi wrote:
Hi everyone,
Is there any counter function in R for the following purpose:
x - matrix(c(1,1,0,2,1,0,0,2,0,1,2,1,2,1,0,1),nrow=4)
As I would like to know how many zeros, ones, and twos in each row of x?
Yes there is:
As you are
Hi all,
I have a system of 3 equations with many defined parameters and 3 variables
I need to find solutions to. I actually know the solutions I'm aiming for
(.0061,0.287,0.070) but R tends to give me (0,0,0).
I tried the BB package but don't really follow how to refine my solutions
from that;
Dear list:
Being a bit unsatisfied with global optimization approaches in R such as SANN
(in 'optim') or DEoptim, I looked for alternatives on the Web, such as PSwarm
http://www.norg.uminho.pt/aivaz/pswarm/ or PIKAIA.
There is an R interface to PSwarm (version 1.4) on its home page which I was
cotixan wrote:
Hello, I'm rather new to R and I want to do some image analysis. Is there a
way to read jpeg files into a matrix like matlab's imread?
http://cran.r-project.org/web/packages/rimage/index.html
--
Drs. Paul Hiemstra
Department of Physical Geography
Faculty of Geosciences
I am getting following strange error :
library(sn)
library(ggplot2)
dat1 - as.matrix(rsn(1000, 0, 1, 0))[,1]
ggplot() + geom_histogram(aes(x = dat1, y = ..density.., fill = ..count..))
+
xlab(Distribution) + scale_y_continuous()
Error: No data for layer
Can anyone please tell
Hi
I hope this is the right mailing list - if not, could you please refer
me to a mora appropriate?
My question:
I am using sweave (in LyX with beamer) for a lecture and I would like
to evaluate the R code chunks for the handout, but not for the
presentation.
I thought that I can use
Well, you did not specify the dataset. You want:
ds - data.frame(dat1 = rsn(1000, 0, 1, 0))
ggplot(ds, aes(x = dat1)) + geom_histogram(aes(y = ..density.., fill =
..count..)) + xlab(Distribution) + scale_y_continuous()
HTH,
Thierry
On 23/07/2009 8:58 AM, Rainer M Krug wrote:
Hi
I hope this is the right mailing list - if not, could you please refer
me to a mora appropriate?
My question:
I am using sweave (in LyX with beamer) for a lecture and I would like
to evaluate the R code chunks for the handout, but not for the
On Thu, Jul 23, 2009 at 3:04 PM, Duncan Murdochmurd...@stats.uwo.ca wrote:
On 23/07/2009 8:58 AM, Rainer M Krug wrote:
Hi
I hope this is the right mailing list - if not, could you please refer
me to a mora appropriate?
My question:
I am using sweave (in LyX with beamer) for a lecture and
Hi Everyone,
I am relatively new to R, but I want to try to learn how to use it and
potentially replace the other commercial packages I have learned to use over
the years. That said, I need to get at data in databases, more
specifically, MySQL.
I installed the RMySQL package without error, but
Hi Matej,
You can also try:
sapply(ls(), function(x) object.size(get(x)))
or
eapply(.GlobalEnv, object.size)
which list all objects - as with ls() - but giving their sizes.
I'm also quite new to R so am not sure which other properties you could hope
to get out of it, but by substituting
Make a copy of the libmySQL.dll and put it in your R_HOME\bin directory and
try again..
Just to be on the safe side, I created an env variable called R_HOME and
added R_HOME\bin to my path.
HTH
-c
Brock Tibert wrote:
Hi Everyone,
I am relatively new to R, but I want to try
Sarah B wrote:
Hi everyone,
I am trying to analyse my data from a small plant experiment (for a
meeting tomorrow afternoon) and am a beginner to R so I apologise if this
is a very basic question.
I carried out a plant experiment examining plant interactions between two
species (A
Try also:
t( apply(x, 1, function(x) table( factor(x, levels = 0:2) ) ) )
# 0 1 2
# [1,] 1 2 1
# [2,] 1 3 0
# [3,] 3 0 1
# [4,] 0 2 2
See ?apply, ?table and ?factor for more details, examples and information.
HTH,
Jorge
On Thu, Jul 23, 2009 at 6:44 AM, amor Gandhi amorigan...@yahoo.de
Dear List,
I am new to ROC analysis and the package ROCR. I want to compute the confidence
intervals of sensitivity and specificity for a given cutoff value. I have used
the following to calculate sensitivity and specificity:
data(ROCR.simple)
pred - prediction(ROCR.simple$predictions,
Hi R user,
I need some help about how to calculate w in a SVR in package e1071.
I have a regression y_i=f(x_i)+e
where f(*x*)=(w,phi(x))+b
then go on with the SVR calculation I know that w*=Sum_i=1^n [(á_i -
á*_i)K(x,x_i) ] where á_i and á*_i are the lagrangian multipliers of the
dual form.
Doing the computations in R then the graphs in Excel reminds me of the maxim:
Measure with a micrometer
Mark with chalk
Cut with an ax
Before continuing you should really read:
http://www.burns-stat.com/pages/Tutor/spreadsheet_addiction.html
and look at the final graphic in:
I'd like to plot n (say n = 10) semi-transparent lines in such a way that if
all n happen to exactly overlay each other, the resulting line is completely
opaque. In principle, I believe that this is what setting alpha = 1/n should
accomplish.
In practice, different values of n produce
Hi there,
I'm trying to remove multiple columns by name from a data.frame. As a
result I need to get back the modified data.frame without the removed
columns. My columns I want to delete are listed in a vector called
delete.
data - read.csv2(data.csv)
delete - c(col1, col2, col3)
newData
Dear all,
When I loaded a dataset (a txt file), which is structured in a tabular
format, to R by using read.delim, I found some rows were missing. The column
number was correct. These missing rows are no apparently different from the
other rows, and for some unknown reasons these missing rows
Hello,
i have a short question concerning constrained OLS regressions using ?lm
. i would like the value of my only independent variable to be
constrained to 1.
## data
capg - rnorm(100)
invest - rnorm(100)
## regression
reg- lm(capg ~ invest)
how do i use ?offset in that regard?
Dear Anne,
Check out
http://www.nabble.com/correct-way-to-subset-a-vector-to24412577.html#a24412577
for alternatives.
HTH,
Jorge
On Thu, Jul 23, 2009 at 9:49 AM, Anne Skoeries h...@anne-skoeries.dewrote:
Hi there,
I'm trying to remove multiple columns by name from a data.frame. As a
There are several ways to do it. Here's one:
fakedata - data.frame(col1 = runif(10), col2 = runif(10), col3 = runif(10))
delete - c(col1, col3)
fakedata2 - fakedata[, !(colnames(fakedata) %in% delete), drop=FALSE]
Sarah
On Thu, Jul 23, 2009 at 9:49 AM, Anne Skoeriesh...@anne-skoeries.de wrote:
try this:
data - data[, !(names(data) %in% delete)]
On Thu, Jul 23, 2009 at 9:49 AM, Anne Skoeriesh...@anne-skoeries.de wrote:
Hi there,
I'm trying to remove multiple columns by name from a data.frame. As a
result I need to get back the modified data.frame without the removed
columns. My
try using the options:
quote='', comment.char=''
You might have a comment character (#) or unbalanced quote marks.
Look closely at the rows that your missing, especially several rows
prior to them.
On Thu, Jul 23, 2009 at 9:35 AM, Rnewbiexua...@yahoo.com wrote:
Dear all,
When I loaded a
I have troubles understanding how goodfit() function in the vcd package
computes the Pearson coefficient. Can anybody provide more information
on the computation?
In particular, for HorseKicks data in vcd package, goodfit() yields
oo - goodfit(HorseKicks,type=poisson,method=MinChisq)
Gabor G. wrote
R does not currently have AD (except for the Ryacas package
which can do true AD for certain simple one line functions, i..e.
input the function and output a function representing its
derivative); however, for specific problems one can get close
using deriv and
This should work
which((x==2)|(x==3))
--Quotable Quotes-
A Smile costs Nothing But Rewards Everything
- Anonymous
Happiness is not perfected until it is shared
That works perfekt! Thanks so much!
--
Anne Skoeries
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
On Jul 23, 2009, at 8:59 AM, Greg Snow wrote:
Doing the computations in R then the graphs in Excel reminds me of
the maxim:
Measure with a micrometer
Mark with chalk
Cut with an ax
Definitely a fortunes candidate...
Marc Schwartz
__
R 2.8.1
Windows XP
I am trying to analyze repeated measures data (the data are listed at the end
of this Email message) and I need help to make sure that I have properly
specified my model, and would like to know why lmer does not return a p value
for Group, my fixed effect.
My subjects are
Dear R-people,
I hope asking this is not too cheeky, but I do have a R Problem. I hope
that some of you like to play around with R and can help me.
Its like this. I have several plant species (A,B,C) and 10 replicates
per species. 5 plants per species are damaged, 5 not. I let a
caterpillar
Try
which(x %in% y)
HTH
KJ
Philip Twumasi-Ankrah nana_kwadwo_der...@yahoo.com wrote in message
news:519822.56196...@web39502.mail.mud.yahoo.com...
This should work
which((x==2)|(x==3))
--Quotable Quotes-
A Smile costs Nothing But Rewards Everything
- Anonymous
nashjc wrote:
Gabor G. wrote
R does not currently have AD (except for the Ryacas package
which can do true AD for certain simple one line functions, i..e.
input the function and output a function representing its
derivative); however, for specific problems one can get close
Hi,
I found at least 2 typos in your function. Can you check your equations
carefully to make sure that they are correct and then send me a reproducible
version of the code that I can cut and paste into my R session?
Ravi.
Thanks Mark and Richard for your propositions on how to extract residuals.
However, I've tried both solutions on my model, and I got different
residuals :
If we consider the within residuals :
Mark's solution gave me a vector of 24 residuals :
Hi Ravi, apologies for the typos. I believe these have been corrected, please
see the new version of the question on the forum page
Ravi Varadhan wrote:
Hi,
I found at least 2 typos in your function. Can you check your equations
carefully to make sure that they are correct and then send
On Thu, Jul 23, 2009 at 11:07 AM, Ben Bolkerbol...@ufl.edu wrote:
nashjc wrote:
Gabor G. wrote
R does not currently have AD (except for the Ryacas package
which can do true AD for certain simple one line functions, i..e.
input the function and output a function representing its
I'm trying to run this simple random sample procedure and keep getting the
error message shown. I don't understand this; I've designated x as a
numeric vector, so what is going on here? Thanks.
x = as.vector(c(1:12));x
[1] 1 2 3 4 5 6 7 8 9 10 11 12
mode(x)
[1] numeric
sample(x, 3)
Hi all,
I've this ggplot2 graph
(http://www.4shared.com/file/120101043/f3e9350/isotherm.html).
I'd like to tweak the legend for the adsorbent part. I'd like to have full
square of the colors instead of the full circles.
I guess that I've to work on the scale_color_hue or fill somewhere but I
Dear R users,
I really like how R works :)
I would like to know if there is a way to work with the Allan Variance in R.
http://en.wikipedia.org/wiki/Allan_variance
In general, if there is a package for working in Signal Analysis.
Thank you,
Javier.
Dear R users,
I really like how R works :)
I would like to know if there is a way to work with the Allan Variance in R.
http://en.wikipedia.org/wiki/Allan_variance
In general, if there is a package for working in Signal Analysis.
Thank you,
Javier.
Jim Bouldin wrote:
I'm trying to run this simple random sample procedure and keep getting the
error message shown. I don't understand this; I've designated x as a
numeric vector, so what is going on here? Thanks.
x = as.vector(c(1:12));x
[1] 1 2 3 4 5 6 7 8 9 10 11 12
mode(x)
Dear all,
Ive just started with R and I have question:
how can you change a time from a ts object .i.e 2009.004 to 2009-01-01? Is
there any function for this? I tried around with as.Date... but it hasnt
worked.
Thank you beforehand.
Chuse.
[[alternative HTML version deleted]]
Thank you. However, when I tried that, I got this message:
Warning message:
In rm(.Random.seed) : variable .Random.seed was not found
Jim Bouldin wrote:
I'm trying to run this simple random sample procedure and keep getting
the
error message shown. I don't understand this; I've
Jim Bouldin wrote:
Thank you. However, when I tried that, I got this message:
Warning message:
In rm(.Random.seed) : variable .Random.seed was not found
In that case, have you attached some package that has its own .Random.seed?
Try to find where the current .random.seed comes from R
Hi,
I am trying to build a VERY basic neural network as a practice before
hopefully increasing my scope. To do so, I have been using package neural
and the MLP related functions (mlp and mlptrain) within that package.
So far, I have created a basic network, but I have been unable to change the
You may need to modify this slightly depending on the specifics
of the fraction calculation but try this to get started:
x - 2009.004
dt - as.Date(paste(floor(x) + 0:1, 1, 1, sep = -))
dt[1] + as.numeric(diff(dt)) * (x %% 1) - 1 # 2009-01-01
On Thu, Jul 23, 2009 at 11:48 AM, Chuse
Salford Data Mining Conference
August 23rd - 25th, 2009
San Diego, California
Early-Bird Registration Deadline: July 24th, 2009
http://SalfordDataMining.com/agenda.php
Post-Conference Training
August 26th - 28th, 2009
Our conference will offer prominent keynote speakers and informative real
Rasanga Ruwanthi wrote:
Dear List,
I am new to ROC analysis and the package ROCR. I want to compute the confidence intervals of sensitivity and specificity for a given cutoff value. I have used the following to calculate sensitivity and specificity:
data(ROCR.simple)
pred -
Jim Bouldin wrote:
Thank you. However, when I tried that, I got this message:
Warning message:
In rm(.Random.seed) : variable .Random.seed was not found
In that case, have you attached some package that has its own
.Random.seed?
Try to find where the current .random.seed
On 23-Jul-09 15:30:05, Jim Bouldin wrote:
I'm trying to run this simple random sample procedure and keep
getting the error message shown. I don't understand this; I've
Thanks.
x = as.vector(c(1:12));x
[1] 1 2 3 4 5 6 7 8 9 10 11 12
mode(x)
[1] numeric
sample(x, 3)
Error in
On 23-Jul-09 16:08:17, Jim Bouldin wrote:
Jim Bouldin wrote:
Thank you. However, when I tried that, I got this message:
Warning message:
In rm(.Random.seed) : variable .Random.seed was not found
In that case, have you attached some package that has its own
.Random.seed?
Try to find
I have a csv file that I am trying to read in and know that values 0
are erroneous - is there a way to read only value grater than 0.
thanks,
--
Stephen Sefick
Let's not spend our time and resources thinking about things that are
so little or so large that all they really do for us is puff us
here is the solution
x - subset(read.csv(foo.csv), VALUE0)
On Thu, Jul 23, 2009 at 11:28 AM, stephen sefickssef...@gmail.com wrote:
I have a csv file that I am trying to read in and know that values 0
are erroneous - is there a way to read only value grater than 0.
thanks,
--
Stephen
Hello,
I am trying to create a heatmap that clusters based on a k-means scheme
rather than a hierarchical clustering scheme.
Suppose I have the following input data, located in sample.table:
x1 x2 x3 x4
x1 17.198 16.306 16.806 16.374
x2 14.554 10.866 15.780 14.596
x3 14.374 14.118 14.569 17.352
I am not sure that I fully understand what all you want to do (and I don't
understand why you need the correlation and if a correlation based on 3 pairs
is even meaningful), but here is a first stab at what you are trying to do:
tmp - Species Control_CR Damage_DR
A 10 2
A 9 3
A 7 4
A 9 2
A 8 3
Thanks much Ted. I actually had just tried what you suggest here before
you posted, and resolved the problem. Thanks also for the other tips. I
wrote x = as.vector(c(1:12)) because I thought that the mode of x might be
the problem, the error message pointing to .Random.seed notwithstanding.
Hi all,
I need some help about how to calculate w in a SVR in package e1071.
I have a regression y_i=f(x_i)+e
where f(*x*)=(w,phi(x))+b
then go on with the SVR calculation I know that w*=Sum_i=1^n [(á_i -
á*_i)K(x,x_i) ] where á_i and á*_i are the lagrangian multipliers of the
dual
Hi, Gabor and Other R users,
I'm re-posting my script and the results I got.
here is the dynamic model I used to estimate in-sample model (1996-2006)
and it works:
fit-dyn$lm(Y~lag(Y,-1)+z+x+lag(x,-1)+lag(x,-2)+lag(x,-3)+lag(x,-4))
Then I used this model to do out sample forecast with
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Jim Bouldin
Sent: Thursday, July 23, 2009 9:49 AM
To: ted.hard...@manchester.ac.uk; ted.hard...@manchester.ac.uk; r-h...@r-
project.org
Subject: Re: [R] error message:
I vote for it.
--- On Thu, 7/23/09, Marc Schwartz marc_schwa...@me.com wrote:
From: Marc Schwartz marc_schwa...@me.com
On Jul 23, 2009, at 8:59 AM, Greg Snow wrote:
Doing the computations in R then the graphs in Excel
reminds me of the maxim:
Measure with a micrometer
Mark with
Hi all
Can anybody help me with this? I am trying to include in an automatic way
the argument in arg.names in a barplot. I generate the labels I want to
appear below the bars with a for loop, and they contain subscripts, so I
need to use expression
anch-0.05
esp-4
for (i in
Please provide your code in a reproducible form (as requested previously).
Here we fit with first 9 points and then add a point for prediction. (Of
course your model can only predict the current value of Y so you may
have to rethink your model even aside from the implementation if you
really
Dan Nordlund wrote:
It would be necessary to see the code for your 'brief test' before anyone
could meaningfully comment on your results. But your results for a single
test could have been a valid random result.
I've re-created what I did below. The problem appears to be with the
weighting
Hi,
I'm having trouble within my function CalcPos to get it to call
CalcHorz with values from each row. I *think* it's calling CalcHorz
with the final values of the inputs and not the values from each row.
How can I do this properly in R?
The values aa,bb,cc,dd are inputs. CalcPos first
Hi R-helpers,
I have a list containing 10 elements, each of which is a dataframe. I wish
to add a new column to each list element (dataframe) containing the product
of the last two columns of each dataframe.
I'd appreciate any pointers, thanks!
Mark Na
[[alternative HTML version
Dear R People:
I'm having trouble with something that should be very simple.
I'm setting up a matrix outside of a loop and writing items into it
during the loop.
Here is the output:
glob3b(sites.info)
dim 27 3
[1] /raid1/osg-app
Error in xy[i, ] : incorrect number of dimensions
Here is the
Dear Mark,
Try this:
lapply(yourlistofdataframes, function(d){
k - ncol(d)
d$product - d[,k-1] * d[,k]
d
}
)
HTH,
Jorge
On Thu, Jul 23, 2009 at 2:05 PM, Mark Na mtb...@gmail.com wrote:
Hi R-helpers,
I
Hi Mark, study the following example. The two simulated dataframes are put
in a list called listdata. The loop iterates throught the elements in the
list and multiplies the last column listdata[[i]][,length(listdata[[i]])]
by the column before the last listdata[[i]][,length(listdata[[i]])-1].
This
Hi Erin,
On Jul 23, 2009, at 2:12 PM, Erin Hodgess wrote:
Dear R People:
I'm having trouble with something that should be very simple.
I'm setting up a matrix outside of a loop and writing items into it
during the loop.
Here is the output:
glob3b(sites.info)
dim 27 3
[1] /raid1/osg-app
Try adding replace=TRUE to your call to sample, then you will get numbers
closer to what you are expecting.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
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From: r-help-boun...@r-project.org
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