Dear Jia-Chiun Pan,
First of all, why install an older version of R? In my experience the
backward compatibility of R is quite good. So using R 2.10.0 should be
ok. But if you really want this you can build R from source. The source
can be downloaded from CRAN:
I have quite a complicated problem that's hard to describe.
Suppose I have a dataframe d. I want to access the vector d$var, where
var is one of the variables in d. Just take for granted that there's a
good reason I want to do this as follows.
var-DeOxyA
xx-paste(d$,var, sep=)
mean(xx)
[1] NA
Hello,
I was following an example on The ROCR Package pdf, learning to overlay ROC
curves on the same plot using the add = TRUE statement. I used this one:
data(ROCR.hiv)
attach(ROCR.hiv)
pred.svm - prediction(hiv.svm$predictions, hiv.svm$labels)
perf.svm - performance(pred.svm, 'tpr',
On Thu, 19 Nov 2009 00:13:27 +0100 Duncan Murdoch
murd...@stats.uwo.ca wrote:
hunsynte...@hush.com wrote:
Dear R-ers,
While browsing the R sources, I found the following piece of
code
in src\main\memory.c:
static void reset_pp_stack(void *data)
{
R_size_t *poldpps = data;
Hi all,
I've tried to make a 3D plot, but have run into some problems.
I'd like to have a plot that I can rotate interactively using the mouse, which
is possible using the plots3d {R.basic}. However, I would like to change the
symbols used as the points, but there's no pch in plot3d().
Hi,
Try this,
d - data.frame(a=1:4, b=3:6)
var - a
mean(d[var])
## or, if you are not aware of
## fortune(parse)
xx - paste(d$,var, sep=)
mean(eval(parse(text=xx)))
HTH,
baptiste
2009/11/19 William Simpson william.a.simp...@gmail.com:
I have quite a complicated problem that's hard to
On 11/19/2009 03:13 AM, Sunita Patil wrote:
Hello Sir
I have got 150 observations, got 10 posts/ 6 departments/ tasks vary from 5
to 10,
A few of the variables are crossed specially in case of Office boy, where
the tasks are like open the door, put on the lights,
Yes time variable I have used
Thanks very much Phil and Baptiste!
d[[var]]
is exactly what I wanted.
Sorry for being so inarticulate. I still couldn't describe my problem
if I wanted to! Anyway, now I have the solution.
Cheers
Bill
On Thu, Nov 19, 2009 at 9:39 AM, baptiste auguie
baptiste.aug...@googlemail.com wrote:
Hi,
Greetings All.
According to the PLoS (Public Library of Science) Guidelines
for Figure preparation, if a figure is submitted as EPS rather
than TIFF then Figure text must be in Arial font -- see:
[1]
http://www.plosntds.org/static/figureGuidelines.action#text
and also other sections in that
Try the rgl package.
r
-
Remko Duursma
Post-Doctoral Fellow
Centre for Plants and the Environment
University of Western Sydney
Hawkesbury Campus
Richmond NSW 2753
Dept of Biological Science
Macquarie University
North Ryde NSW 2109
Australia
The NEWS of the randomForest R library mention that version 4.5-13 fixed a
bug in predict.randomForest() when newdata is a matrix with no rownames.
I think it corresponds to the difference in files
predict.randomForest.R
which is the new line
if (is.null(rn)) rn - keep
As I've been using version
Hello all,
I happen to get a (legitimate) hold of a city budget for the (4) years:
2006,2007,2008,2009
The budget holds over 12,000 rows of budget sections with numbers being
Zero's positive and negatives.
I would like to find something interesting in this dataset.
I don't have a clear
On 19/11/2009 4:23 AM, Hun S. Tesatte wrote:
On Thu, 19 Nov 2009 00:13:27 +0100 Duncan Murdoch
murd...@stats.uwo.ca wrote:
hunsynte...@hush.com wrote:
Dear R-ers,
While browsing the R sources, I found the following piece of
code
in src\main\memory.c:
static void reset_pp_stack(void
Hello
On Thu, Nov 19, 2009 at 11:00 AM, Ted Harding
ted.hard...@manchester.ac.uk wrote:
While there is a section (Enable the use of Arial in R) in the
Guidelines (URL [2]), the instructions assume the presence of
Arial .ttf files, not usually the case with Linux.
If you have a Windows
On Thu, Nov 19, 2009 at 4:30 PM, Ted Harding
ted.hard...@manchester.ac.uk wrote:
Greetings All.
According to the PLoS (Public Library of Science) Guidelines
for Figure preparation, if a figure is submitted as EPS rather
than TIFF then Figure text must be in Arial font -- see:
[1]
Hello, the sqlSave function is used in order to write a dataframe on excel.
This function creates worksheets using the attribute tablename and writes
the data.frame in it. What I want to do is to create this data.frame but
being able in case this worksheet already exists to delete the former
On 19-Nov-09 11:52:57, Deepayan Sarkar wrote:
On Thu, Nov 19, 2009 at 4:30 PM, Ted Harding
ted.hard...@manchester.ac.uk wrote:
Greetings All.
According to the PLoS (Public Library of Science) Guidelines
for Figure preparation, if a figure is submitted as EPS rather
than TIFF then Figure text
See Addendum at end.
On 19-Nov-09 12:17:54, Ted Harding wrote:
On 19-Nov-09 11:52:57, Deepayan Sarkar wrote:
On Thu, Nov 19, 2009 at 4:30 PM, Ted Harding
ted.hard...@manchester.ac.uk wrote:
Greetings All.
According to the PLoS (Public Library of Science) Guidelines
for Figure preparation,
Hi,
When using lapply (or sapply) to loop over a list, can I somehow access the
index of the list from inside the function?
A trivial example:
df1 - split(
x=rnorm(n=100, sd=seq(from=1, to=10, each=10)),
f=letters[seq(from=1, to=10, each=10)]
)
str(df1)
#List of 10
# $ a: num [1:10]
lapply over the list names rather than the list itself:
junk - lapply(names(df1), function(nm) plot(df1[[nm]], ylab = nm))
On Thu, Nov 19, 2009 at 7:27 AM, Bjarke Christensen
bjarke.christen...@sydbank.dk wrote:
Hi,
When using lapply (or sapply) to loop over a list, can I somehow access the
On 19/11/2009 7:27 AM, Bjarke Christensen wrote:
Hi,
When using lapply (or sapply) to loop over a list, can I somehow access the
index of the list from inside the function?
No, but you can loop over the indices in lapply, not just in a for
loop. For example,
lapply(names(df1),
On 19 November 2009 at 13:00, (Ted Harding) wrote:
| However,
| (a) I do not have the 'ttf2afm' program;
| (b) Synaptic cannot find it in the repositories.
|
| So, I'm off on another hunt!
i) You should try to get over the 'Synaptic is the only interface to
package' syndrome. It limits
On 11/19/09, Ted Harding ted.hard...@manchester.ac.uk wrote:
However,
(a) I do not have the 'ttf2afm' program;
(b) Synaptic cannot find it in the repositories.
http://packages.debian.org/search?searchon=contentskeywords=ttf2afmmode=exactfilenamesuite=testingarch=any
Liviu
Dear all,
is there any functions which allow to calculate Student t-criterion using
means, their SE and sample size? I've seek for, but bulit-in t-criterion works
only with initial sample...
Best regards,
A.Morkovin
__
R-help@r-project.org mailing
Maybe this : http://tolstoy.newcastle.edu.au/R/e4/help/08/04/8720.html
Romain
On 11/19/2009 01:27 PM, Bjarke Christensen wrote:
Hi,
When using lapply (or sapply) to loop over a list, can I somehow access the
index of the list from inside the function?
A trivial example:
df1- split(
You can try this:
par(mfcol=c(5,2))
lapply(df1, function(x){
nm -
names(eval(as.list(sys.call(-1))[[2]]))[as.numeric(gsub([^0-9],
, deparse(substitute(x]
plot(x, main = nm)
})
On Thu, Nov 19, 2009 at 10:27 AM, Bjarke
On Nov 18, 2009, at 11:00 PM, ychu066 wrote:
hey Jim ,
I have solve the column name problems now. But i am still unable to
read
the date in R ...
toms_dat- replace(toms_dat, toms_dat ==2009-08-24, 6)
replace needs its first argument to be a vector, while you have given
it a
Hi
I'm trying to learn how to use R when it comes to acceptance sampling.
What I want to do is to type in a lot size, an AQL level and a LQ level and get
the required sample size in accordance with inspection level II (ISO 2859-2).
I have tried find.plan (c(0.01,0.95), c(0.07,0.05),
Add col=i in the histogram call.
--
View this message in context:
http://old.nabble.com/How-do-I-change-the-colour-and-format-for-the-trelli-plot---tp26418382p26421302.html
Sent from the R help mailing list archive at Nabble.com.
__
Also see of the journal will let you use NimbusSan:
pdf('my.pdf', onefile=FALSE, pointsize=18,
family=NimbusSan,height=6,width=8,paper=special)
...
dev.off()
embedFonts('my.pdf')
Frank
Dirk Eddelbuettel wrote:
On 19 November 2009 at 13:00, (Ted Harding) wrote:
| However,
| (a) I do not
On Nov 19, 2009, at 4:39 AM, baptiste auguie wrote:
Hi,
Try this,
d - data.frame(a=1:4, b=3:6)
var - a
mean(d[var])
I tried get() on Simpson's pasted argument without success. Assuming
the OP still wanted to use only text arguments, then this approach works
dfn - d
get(dfn)[var]
While putting my R code into functions, I've encountered a ddply function
nesting issue and need a bit of advice on the proper way to fix it. I've tried
several approahces, but neither worked and I need to have the ability to
include the cut, range, and fullseq methods within ddply. (For a
Dear all,
I need to create n*n table with sums of all possible pair combinations of
numbers from n-row column. What function allows it?
Best regards,
A.Morkovin
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Hello Sir
Thanx even I will try to work out on your suggestions, will keep you updated
on the progress. Thanx a lot
Regards
Our Thoughts have the Power to Change our Destiny.
Sunita
On Thu, Nov 19, 2009 at 3:50 PM, Jim Lemon j...@bitwrit.com.au wrote:
On 11/19/2009 03:13 AM, Sunita Patil
Hello Sir
Thanx a lot, will try Pareto chart for my data
Regards
Our Thoughts have the Power to Change our Destiny.
Sunita
On Thu, Nov 19, 2009 at 12:29 PM, Petr PIKAL petr.pi...@precheza.cz wrote:
Well, from what you say it seems to me that you could also use Pareto
charts together with
Thanks to everybody who replied - I got three distinct, very useful
suggestions.
Bjarke Christensen
Romain Francois
romain.francois@
On Nov 19, 2009, at 9:40 AM, Антон Морковин wrote:
Dear all,
I need to create n*n table with sums of all possible pair
combinations of numbers from n-row column. What function allows it?
?expand.grid
Best regards,
A.Morkovin
__
Look at the ggobi program and the rggobi package for interactions between R and
ggobi.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
Hi,
I think your ddply call with a calculation inside .( ) is the
problem. Are you sure you need to do this? Performing the cut outside
ddply seems to work fine,
determine_counts-function()
{
min_range-1
max_range-30
bin_range_size-5
Me_df-data.frame(Data =
Dear All,
I appreciate any advice or hints you could provide about the following.
We are running R code in a server (running Windows XP and QuadCore Xeon
processors, see details below) and we would like to use the server
efficiently. Our code takes a bit more than 6 seconds per 25 iterations in
Hi!
I have a data.frame data and splitted it.
data - split(data, data[,1])
This is a quite slow procedure; and I do not want to do it again. So,
any unsplit and resplit is no option for me.
But: I have to cbind variables to the splitted data from another list,
that contains of vectors with
Dear Stephan,
Here is a suggestion using do.call():
res - do.call(cbind, yourlist)
res
HTH,
Jorge
On Thu, Nov 19, 2009 at 10:03 AM, Stephan Dlugosz wrote:
Hi!
I have a data.frame data and splitted it.
data - split(data, data[,1])
This is a quite slow procedure; and I do not want to
On Nov 19, 2009, at 9:25 AM, Carlos Hernandez wrote:
Dear All,
I appreciate any advice or hints you could provide about the
following.
We are running R code in a server (running Windows XP and QuadCore
Xeon
processors, see details below) and we would like to use the server
efficiently.
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Stephan Dlugosz
Sent: Thursday, November 19, 2009 7:03 AM
To: r-help@r-project.org
Subject: [R] Efficient cbind of elements from two lists
Hi!
I have a data.frame data and
Hello everybody, I started to use Rexcel and I am getting an error with the
following code:
Sub AutoForma1_Clique()
Call RInterface.StartRServer
Call RInterface.RRun(setwd(C:/Program Files/R/R-2.10.0/Working
Directory))
Call RInterface.RRun(getwd())
End Sub
The error is the following
Dear List,
I am trying to run a mixed model which, on the R console, prints output as
follows:
[1] Marker
[1] perm no.
[1] NA
Linear mixed model fit by REML
Formula: peg.no.prm ~ 1 + (1 | family/f)
Data: modeldf
AIC BIC logLik deviance REMLdev
3119 3134 -1555 31123111
Random
Dear List,
I thought it would be much easier to put a second query into a second mail.
I need to print 426*1 blocks of variance components data, where 426 is
the number of columns of data that have 1 permutations of variance
generated for each of them.
I have tried printing out a
Hi,
I'm trying to plot the forecasts I generated using the Plot.Fore function of
the BootPR package.
But I got an error from zoo:
My data:
Time Series:
Start = 1
End = 18
Frequency = 1
[1] 38731 38628 39117 92809 71984 31226 58613 72360 107956 92066
[11] 95208 99098 95848
Dear R experts,
I have a so-called person-level data frame that I need to transform
into a person-period data frame.
If the lingo is unclear, the data have one row for each subject, with
repeated measures data each in a separate column.
I need to transform these data so that each subject has
Contact the BootPR maintainer regarding a bug in this line of Plot.Fore:
y1 - zooreg(x, start, end, frequency)
where x is a ts object but that may not be used in that context.
as.zooreg is available for converting ts series (and certain other
objects) to zooreg objects.
2009/11/19 Ricardo
Thanks for your reply! I just added some more details below.
Our code needs around 1GB of RAM and all machines and R configurations have
its default maximum above this number.
Our suspicion is that the windows server could run the code in half of its
current time (given the apparent factor of 2
On Thu, 19 Nov 2009, Ricardo Gonçalves Silva wrote:
Hi,
I'm trying to plot the forecasts I generated using the Plot.Fore function of
the BootPR package.
But I got an error from zoo:
My data:
Time Series:
Start = 1
End = 18
Frequency = 1
[1] 38731 38628 39117 92809 71984 31226 58613
Ok,
Thanks all.
Rick.
--
From: Achim Zeileis achim.zeil...@wu-wien.ac.at
Sent: Thursday, November 19, 2009 3:06 PM
To: Ricardo Gonçalves Silva ricard...@terra.com.br
Cc: R-Help r-help@r-project.org; j@latrobe.edu.au
Subject: Re: [R] Problem
Robert Terwilliger wrote:
Dear R experts,
I have a so-called person-level data frame that I need to transform
into a person-period data frame.
If the lingo is unclear, the data have one row for each subject, with
repeated measures data each in a separate column.
I need to transform these data
Dear all,
As a newbie in R I would like to do the following (simple?) thing:
to plot a filled.contour plot over a map showing country boundaries (e.g. for
Europe)
What i do is:
map('worldHires',xlim=c(-10,40),ylim=c(35,70),boundary = TRUE,border=0.1)
map.axes()
filled.contour(mslp,
Alla Bulashevska wrote:
Dear R users,
i try to use function dmvnorm(x, mean, sigma, log=FALSE)
from R package mvtnorm to calculate the probability of x
under the multivariate normal distribution with mean equal
to mean and covariance matrix sigma.
I become the following
Error in
Can't be too hard to convert it in pixmap representation, but you need
to tell us hoe the representation looks like, probbaly with a short code
that makes it reproducible (e.g. generate some data that we can use in R).
Uwe Ligges
Rajarshi Guha wrote:
Hi, I have some code that uses rJava.
Awesome!
Thanks a ton!
I guess I had overlooked how it was really working.
I will still have to reflect on why it was working running it straight through,
but not being nested.
That is kind of a mystery. Oh well...
Thanks again.
- Original Message
From: baptiste auguie
On Nov 19, 2009, at 12:23 PM, Richard M. Heiberger wrote:
Robert Terwilliger wrote:
Dear R experts,
I have a so-called person-level data frame that I need to transform
into a person-period data frame.
If the lingo is unclear, the data have one row for each subject, with
repeated measures
Actually it may be that the documentation is at fault more than the
code. The help page for Plot.Fore says that the first argument is a
time series data set and although that seems to suggest that it should
be a ts object the code seems to be written assuming a plain numeric
vector; therefore,
Hello,
I just started using R to do epidemiologic simulation research using the Cox
proportional hazard model. I have 2 covariates X1 and X2 which I want to
model as h(t,X)=h0(t)*exp(b1*X1+b2*X2). I assume independence of X from t.
After I simulate Time and Censor data vectors denoting the
Dear R Users,
I am trying to read in a series of csv files which vary by the letter on the
end of he file name. When I input what seems to be a logical for loop I get an
error message that doesn't make sense to me.
for(i in 1:12){ paste(GP, LETTERS[i],sep='')
Dear Paul,
Thank you for your response. I am investigating a differentially expressed
gene detected method that cannot be applied on R 2.9.1 that currently I
used. The reason about why it cannot work due to the changes of new version
of R. And, recently, I study a lots of methods that developed
Hi Thomas,
Here are two suggestions which storage all the files in a list:
# Parameters
route - /Users/thomasjackson/Data/GEPCO/GEPCO
lts - LETTERS[1:12]
toread - paste(route,lts,/HPLC_,lts,12.csv,sep='')
# Reading in the data -- option 1
myfiles - list()
for(i in 1:12) myfiles[i] -
Try something like:
gp - lapply(
paste((/Users/thomasjackson/Data/GEPCO/GEPCO,LETTERS[1:12],/HPLC_,LETTERS[1:12],12.csv,sep=''),
read.csv, header=TRUE, sep=',' )
names(gp) - paste(GandP, LETTERS[1:12], sep='')
Now gp (or whatever you want to call it) will be a list with your 12
On Fri, 20 Nov 2009, Matthias Demuzere wrote:
Dear all,
As a newbie in R I would like to do the following (simple?) thing:
to plot a filled.contour plot over a map showing country boundaries (e.g.
for Europe) What i do is:
map('worldHires',xlim=c(-10,40),ylim=c(35,70),boundary =
You need to look at the assign function:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-turn-a-string-into-a-variable_003f
(... and in addition to R FAQ 7.21 also perhaps read the rest of the R
FAQ.)
There are a ton of very similar questions in the r-help archives, so
you could
You probably want to put the map boundaries on top of the contour plot rather
than the other way around. Here is one example of doing that (find the correct
asp may be the hardest part):
library(maps)
x - seq( -124.7, -67, length.out=25 )
y - seq( 25, 49, length.out=25 )
z - outer(x,y,'+')
Hi
In my experiment I have 2 Groups (control patient) and 4 blocks of trials
per subject, n=12 for Control and n=11 for patient
The variances of the patients is very much higher than that of the Control.
1- I tried an ANOVA with Groups as between factor and Blocks as within
factor (repeated
Hello,
I am currently working on a modeling project using Fortran to run
large repetitive loops (many DO loops). As part of this process I
would like to use a model fit in R and currently stored as an R
object. This is a rather complex model, a GAMM, and I am curious
whether
I'm currently using the mvtnorm package to model unobserved
heterogeneity in a structural model and using optim to estimate the
model. I have got good clues that convergence is not really a problem
but the hessian matrix estimate is very bad. To overcome this problem,
I'm constructing an
On Thu, Nov 19, 2009 at 12:14 PM, Paul Warren Simonin
paul.simo...@uvm.edu wrote:
Hello,
I am currently working on a modeling project using Fortran to run
large repetitive loops (many DO loops). As part of this process I
would like to use a model fit in R and currently stored as an R
Why I don't see 'par(ask=T)' in /usr/lib/R/library/graphics/R-ex/barplot.R?
Is 'par(ask=T)' implicitly called by example()?
On Mon, Sep 7, 2009 at 10:55 AM, RIOS,ALFREDO ARTURO ar...@ufl.edu wrote:
Hi Peng
I think this is what you are looking for
par(ask=T)
Alfredo
On Sun Sep 06
I've only recently started using R. One of the problems I come up
against is after having extracted a large dataset (5M rows) out of
database, I realize I need another variable. In this case I have data
frame with dates. I want to find the minimum date for each value of x1
and add that minimum
There are a few version of apply() (e.g., lapply(), sapply()). I'm
wondering if there is one that does not return anything but just
silently apply a function to the list argument.
For example, the plot function is applied to each element in 'alist'.
It is redundant to return anything from apply.
On Nov 20, 2009, at 10:21 AM, Peng Yu wrote:
There are a few version of apply() (e.g., lapply(), sapply()). I'm
wondering if there is one that does not return anything but just
silently apply a function to the list argument.
For example, the plot function is applied to each element in 'alist'.
On Thu, Nov 19, 2009 at 2:21 PM, Peng Yu pengyu...@gmail.com wrote:
There are a few version of apply() (e.g., lapply(), sapply()). I'm
wondering if there is one that does not return anything but just
silently apply a function to the list argument.
For example, the plot function is applied to
invisible(apply(...))
On Thu, Nov 19, 2009 at 5:21 PM, Peng Yu pengyu...@gmail.com wrote:
There are a few version of apply() (e.g., lapply(), sapply()). I'm
wondering if there is one that does not return anything but just
silently apply a function to the list argument.
For example, the plot
On Thu, Nov 19, 2009 at 4:27 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Nov 20, 2009, at 10:21 AM, Peng Yu wrote:
There are a few version of apply() (e.g., lapply(), sapply()). I'm
wondering if there is one that does not return anything but just
silently apply a function to the list
I want to use both the name and the content. Although, I could do the
following thing.
for(x in names(List)) {
do some thing with x
do some thing with List[[x]]
}
However, I'd prefer something like the following if R offers such
functionality. But it seems not.
for(x in List) {
do
On Thu, Nov 19, 2009 at 5:31 PM, Peng Yu pengyu...@gmail.com wrote:
Is there a way to get the name of the list in the loop body?
This was just discussed! See this thread:
https://stat.ethz.ch/pipermail/r-help/2009-November/218919.html
__
Hi there,
I have created a single page, multi-panel, xyplot using lattice. Each panel
is a trial (total of 8) from an experiment with 3 variables on the x axis
and the observed value on the y axis. I have added the mean of all trials
so the entire plot looks like this (where M=mean panel and
On Nov 19, 2009, at 4:31 PM, Peng Yu wrote:
On Thu, Nov 19, 2009 at 4:27 PM, Marc Schwartz
marc_schwa...@me.com wrote:
On Nov 20, 2009, at 10:21 AM, Peng Yu wrote:
There are a few version of apply() (e.g., lapply(), sapply()). I'm
wondering if there is one that does not return anything but
You could try
?example
and see what the help page says.
-Peter Ehlers
Peng Yu wrote:
Why I don't see 'par(ask=T)' in /usr/lib/R/library/graphics/R-ex/barplot.R?
Is 'par(ask=T)' implicitly called by example()?
On Mon, Sep 7, 2009 at 10:55 AM, RIOS,ALFREDO ARTURO ar...@ufl.edu wrote:
Hi
Hello,
In reading the loess description I see:
span: the parameter alpha which controls the degree of smoothing.
The default seems to be 0.75. Would it be possible to expand on this decription
so I can avoid trail and error? Can I increase this pass 'span' 1?
Qualitatively to what degree
I have a problem using optim, so I am hoping someone can help me out with it:
Suppose I have the list:
list(D,R,P)
[[1]]
V1 V2 V3 V4
1 0 1 0 1
2 1 1 0 0
3 1 0 1 0
4 0 0 1 1
5 0 1 0 1
6 1 1 0 0
7 1 0 1 0
8 0 0 1 1
9 1 0 1 0
10 0 0 1 1
[[2]]
This was just answered by Deepayan earlier today:
This code did not produce the plot you have linked to. The answer to
your question depends on how you created the plot, so you have to tell
us that. Changing the color in all panels is easy:
histogram(rnorm(100), col = goldenrod)
Different
Hi all,
I've finally started to use Rscript for my statistical scripting
needs, and find I'm being blocked by what must be a very simple
problem. Specifically, the command lines for my scripts usually
contain: (1) the script name, (2) one or more options and their
arguments, and finally, (3)
what is that ?
Hrishi Mittal wrote:
Add col=i in the histogram call.
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Hello,
I would like some help with sqldf syntax.
Suppose I have table 1 and table 2.
What do I have to do to generate a table with columns 2,5,6 from table 1
(for example), and columns 3,4,5,9 from table 2, but only when values in
column 2 from table 1 are equal to values in column
To have a different colour for each histogram. Wasn't that your question?
Sorry if I misunderstood.
Did you try it?
ychu066 wrote:
what is that ?
Hrishi Mittal wrote:
Add col=i in the histogram call.
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As of last night I have this exact same problem, Enter, Backspace and the
arrow keys do not work for me in TinnR! I am using windows vista prof on a
64bit laptop. I have uninstalled, re-installed many times and even cleaned
the registry etc. Does anyone know of a reason and a fix for this
Fore example my code is
histogram(~data[,8]|data[,2], ylab = Frequency, xlab = Score, xlim =
c(1,5), ylim = c(0,100),layout = c(3,1),col=data[,2] )
and i want the colour to be depended on the level of the factor in data[,2].
how do i do that ?
ychu066 wrote:
what is that ?
I want to change the colour of the histogram in each panel by the levels of
the conoditonal factor.
I have 3 levels in the factor
levels(data[,2])[1]
levels(data[,2])[2]
levels(data[,2])[3]
what can i do , in order to chnage the colour ??
ychu066 wrote:
Fore example my code is
I am doing a project which involve reshaping a large dataset, can any of you
please sugguest me some good reading/websites/ examples can be in R and
SAS
Thanks everyone !!!
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Google for sql join and see the examples in Example 4 on the sqldf home page:
http://code.google.com/p/sqldf/#Example_4._Join
On Thu, Nov 19, 2009 at 2:30 PM, JoK LoQ jok...@gmail.com wrote:
Hello,
I would like some help with sqldf syntax.
Suppose I have table 1 and table 2.
What do
On Nov 19, 2009, at 3:10 PM, ychu066 wrote:
I want to change the colour of the histogram in each panel by the
levels of
the conoditonal factor.
I have 3 levels in the factor
levels(data[,2])[1]
levels(data[,2])[2]
levels(data[,2])[3]
what can i do , in order to chnage the colour ??
Hi,
I am trying to plot a set of means+/-SD calculated by an external
program (an RDBMS) since the data set is too large to happily fit in R
(740M x 100 values - which are summarised to 100 means/SD by the DB). I
want to have a mean with whiskers at +/-1SD.
Can anyone suggest a way to do this?
On Nov 19, 2009, at 6:33 PM, Dan Kortschak wrote:
Hi,
I am trying to plot a set of means+/-SD calculated by an external
program (an RDBMS) since the data set is too large to happily fit in R
(740M x 100 values - which are summarised to 100 means/SD by the
DB). I
want to have a mean with
Hi guys,
Are there any feasible methods in searching finding non-ASCII characters
in R?
For example, from the following object,
x - mia. SzaÌmitaÌó
The desired output is,
x.out - mia. SzaImitaIA
Your help in resolving this would be greatly appreciated.
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