guohao.hu...@gmail.com wrote:
Please check the following pdf file.
http://tw.nextmedia.com/applenews/article/art_id/32119622/IssueID/20091127
Besides a beautiful blond girl, I do not recognize any pdf here...
Could you provide a direct link?
Thanks!
mario
1. First
On Thu, 26-Nov-2009 at 11:03PM -0800, Julia Cains wrote:
| Dear Sir,
|
| Thanks again for your help. Sir, actually I am working on a data containing
84 months and the corresponding savings (core) balances and non-core balances
and I am plotting a stacked bar.
|
| The original code I am using
/20091127
Besides a beautiful blond girl, I do not recognize any pdf here...
Could you provide a direct link?
Thanks!
mario
1. First install.packages(Flury)
2. library(Flury)
3. data(wines)
'wines’ is a data frame with 26 observations, one factor denoting the
country of origin and 15
There are different ways to inspect the conent of a data frame. For example,
View(CO2)
2009/11/27 Brock Tibert btibe...@yahoo.com:
Hi All,
I am making a serious effort to try to learn R, but one hurdle I am facing is
that I need to see the data as I walk through the examples in the
On Fri, 27 Nov 2009 15:19:11 +0800 Saji Ren saji@gmail.com wrote:
I want to get a rolling estimation of the stdev of my data.
There is a 'runsd' in the 'caTools' package which does exactly this.
--
Karl Ove Hufthammer
__
R-help@r-project.org
Brock Tibert wrote:
Hi All,
I am making a serious effort to try to learn R, but one hurdle I am facing is that I need to
see the data as I walk through the examples in the packages. For instance, many
examples on the web start by a command like data(wines). How can I actually view what
the
Hi
There is one issue which I encountered recently with this type of
behaviour,
mat-matrix(NA,5,4)
fix(mat)
put some number in any cell and close fix
mat
col1 col2 col3 col4
[1,] NA NA NA NA
[2,] NA NA NA NA
[3,] NA NA NA NA
[4,] NA NA NA NA
[5,] NA
Hello,
I'm taking several physiological measurements on participants (e.g.,
skin conductivity, heart rate, etc.). I know that those participants
belong to one of three groups (from another measurement), and I'm
looking to find the physiological measurement that best describes
group membership.
Dear All,
At least in three different GNU/Linux systems, the parallel function
from the multicore package leaves defunct (zombie) R processes.
For instance
library(multicore)
parallel(1:5)
collect()
After collect, the child process (with pid as given by collect) is
left defunct. (If we run
I'm curious about why no one has answered my question below. I
can't imagine it would be because no one knows how to answer, it
must be something basic I am ignorant about. But I have never seen
such a pattern, it seems strange to me that a class with an empty
definition is automatically
We will need a minimal reproducible example (as per last line on every
message to r-help) to answer as trying it with made up data seems to
work for me. If c is very long try cutting it down to the smallest
you can get it to and still produce the error, e.g.
cc - c[1:10]
rollapply(cc, ...)
and
Dear users,
I am struggling with this issue. I want to estimate a VAR(1) for three
variables, say beta1 beta2 beta3, using monthly observations from January
1984 to September 2009. In-sample period January 1984 to December 2003,
out-of-sample January 2004 to September 2009. This is what I have
Are you using mgcv:::gam? To get plot data suitable for making plots of smooth
effects, you probably need to use `predict.gam' to evaluate the smooth curves
(and standard errors) at a nice regular set of points for plotting. Also
don't forget that the residuals shown on plot.gam are the
Hello
On Fri, Nov 27, 2009 at 4:46 AM, Brock Tibert btibe...@yahoo.com wrote:
In short, I know that data() lists all of the available datasets,
data(wines) will load the dataset wines, but how can I look at the raw data?
See this [1].
[1]
do you mind me asking what code you used to create that data frame and name
the groups 1 and 2?
David Winsemius wrote:
On Nov 26, 2009, at 10:26 PM, Joe King wrote:
In the filled bands part of xYplot of the Hmisc package, is there
a way to
have multiple bands with multiple lines? or
Try this:
# each of these three show entire data set
wines
dput(wines)
View(wines)
# get help
?wines
# various info on data set
head(wines)
tail(wines)
summary(wines)
str(wines)
class(wines)
dim(wines)
# plotting
plot(wines)
# for a better plot see the example at the bottom of ?wines
On Thu,
Hi all,
I have to ask this and I know that the reason is that I am a newbie with R
programming. So apologize if it is too obvious but I didn't find an answer
after googling and reading An introduction to R. So i have return
data from 30 instruments and I am fitting a mixture of normal
Hi Brock,
Have you tried View() ?
Regards.
On Fri, Nov 27, 2009 at 7:46 AM, Brock Tibert btibe...@yahoo.com wrote:
Hi All,
I am making a serious effort to try to learn R, but one hurdle I am facing
is that I need to see the data as I walk through the examples in the
packages. For
Hi,
I'm quite new using R and have got no one to help me get through it.
Hopefully someone can help me with one problem I've been struggling with
for the last hours!!
(Sorry if I'm using the wrong terminology as well!)
I have a data matrix in which SIE is one of my variables. What I need to
Hi JorisMeys and thanks!
JorisMeys wrote:
On Thu, Nov 26, 2009 at 1:04 AM, Tyler82 procaccianti.clau...@gmail.com
wrote:
Hi all!
I am working with R package cluster and I have a little problem:
let's say I have two datasets...first one (A) is divided into 4
clusters
by means of Pam
hello,I would like to ask a question,Is there any way to pass arguments to a
script?I have this code:
Invernadero-read.table(file.choose(),header=T,sep=,)
attach(Invernadero)
names(Invernadero)
Invernadero-ts(Invernadero-argument) //Here introduce the argument
See ?commandArgs
Also the getopt and optparse CRAN packages.
On Fri, Nov 27, 2009 at 4:20 AM, yonosoyelmejor
yonosoyelme...@hotmail.com wrote:
hello,I would like to ask a question,Is there any way to pass arguments to a
script?I have this code:
On Fri, Nov 27, 2009 at 1:13 AM, Kjetil Halvorsen
kjetilbrinchmannhalvor...@gmail.com wrote:
I think the subject says it all. I want to make a simple lattice plot,
using xyplot with the
argument type=c(l,a).
The problem then is that in the resulting plot it is
difficult/impossible to see
On Thu, Nov 26, 2009 at 12:09 AM, Titus Malsburg malsb...@gmail.com wrote:
The documentation of xyplot could be improved here. It says:
If 'index.cond' is a list, it has to be as long as the number of
conditioning
variables, and the 'i'-th component has to be a valid indexing vector for
Thanks for the interesting reference to alphahull. It might be a good
starting point for placing e.g. a legend in a plot (I think the usual
techniques for this (gregmisc?) are a bit more brute-force.)
baptiste
2009/11/27 Kjetil Halvorsen kjetilbrinchmannhalvor...@gmail.com:
There is a package
On Thu, Nov 26, 2009 at 6:22 AM, ychu066 ychu...@aucklanduni.ac.nz wrote:
i was trying to do a for loop for plotting the histograms , but it doesnt
work properly
library(lattice)
columns - 8:153
plots - vector(list, length(columns))
j - 0
for (i in columns)
+ {
+ plots[[ j - j+1 ]] -
On Fri, Nov 27, 2009 at 9:21 AM, Peng Cai pengcaimaill...@gmail.com wrote:
@ Peter: I got it, thanks a lot for all your help! And yes, as you said the
title option in auto.key is redundant.
@ All, Hi: I need to add percentage sign to y-axis labels (like 0%, 20%,
..., 100%). How can I get it.
Hi,
I have recently begun using the lattice package, and have been using
the wireframe command to visualise matrices which are model outputs. I
have been trying to plot two surfaces (from two matrices)
simultaneously in one panel, to visualise intersections etc., but
neither my attempts or
Vitória Magalhães Piai wrote:
Hi,
I'm quite new using R and have got no one to help me get through it.
Hopefully someone can help me with one problem I've been struggling with
for the last hours!!
(Sorry if I'm using the wrong terminology as well!)
I have a data matrix in which SIE is one
Peter Ehlers wrote:
Vitória Magalhães Piai wrote:
Hi,
I'm quite new using R and have got no one to help me get through it.
Hopefully someone can help me with one problem I've been struggling
with for the last hours!!
(Sorry if I'm using the wrong terminology as well!)
I have a data matrix
On Nov 26, 2009, at 3:23 PM, Jonhnny Weslley wrote:
I have a file in the following format:
Scenario1 Scenario1CIL Scenario1CIU Scenario2 Scenario2CIL
Scenario2CIU
60 57 62 45 48 50
110 101 111 51 50 52
120 117 122 64 62 66
192 190 194 79 75 79
where:
First column = Scenario1 mean value
Dear all,
A friend of mine requested me to analyze some data she has generated. I
am hoping for some advice on best way of properly analyzing the data as
I have never worked with such complicated or nested designs.
Here is the setup. She has taken material from 5 animals and each
material
I took the OP's variables, reversed the direction of the second y,
bundled them up in a dataframe and then assigned the grp. So starting
with the OP's code:
x-seq(1,10,1)
y-seq(1,10,1)
ci-y*.10
ciupper-y+ci
cilower-y-ci
x2-seq(1,5,.5)
y2-seq(5, 1, -.5) #reverse second variable
ci2-y2*.10
On Nov 27, 2009, at 5:34 AM, Vitória Magalhães Piai wrote:
Hi,
I'm quite new using R and have got no one to help me get through it.
Hopefully someone can help me with one problem I've been struggling
with for the last hours!!
(Sorry if I'm using the wrong terminology as well!)
I have a
Dear all,
I have the following problem which I cannot solve:
data - numeric (100)
for (i in 1:100){
p - runif(1,min=0,max=1)
data[i] - rnorm(1,mean=2,sd=1)
}
ke - density(data,bw=sj,n=61)
How can I now find the value of this density function for example ke(0),
ke(2) etc.
Maybe this is an
Hi All,
I'm trying to analyze some time series data and I have run into difficulty. I
have decadal sun spot data and I want to separate the very regular periodic
function from the trend and noise. I looked into using stl(), but the frequency
of the time series data must be greater than 1 for
Hi R-ers,
I am struggling with my x-axis in a association plot. What I would like is
to place the labels of the x-axis between the tick markers and normally the
labels are printed at the place where the tick marker is placed. I donât
want to move the tick marker (it gives the
Anastasia wrote:
Dear all,
I have the following problem which I cannot solve:
data - numeric (100)
for (i in 1:100){
p - runif(1,min=0,max=1)
data[i] - rnorm(1,mean=2,sd=1)
}
Er what is p doing in there. As far as I can see, you might as well do
data - rnorm(200, 2, 1)
ke -
Hello list,
I'm following the paper (http://www.jstatsoft.org/v27/i02/paper) on how to
use plm to run panel regressions, and am having trouble with what I
believe should be something very basic.
When I run the command (p.9 in the paper):
R
On Nov 27, 2009, at 9:55 AM, chris carleton wrote:
Hi All,
I'm trying to analyze some time series data and I have run into
difficulty. I have decadal sun spot data and I want to separate the
very regular periodic function from the trend and noise. I looked
into using stl(), but the
Hello list,
I'm following the paper (http://www.jstatsoft.org/v27/i02/paper) on
how to use plm to run panel regressions, and am having trouble with
what I believe should be something very basic.
When I run the command (p.9 in the paper):
R
On Nov 27, 2009, at 10:25 AM, Owen Powell wrote:
Hello list,
I'm following the paper (http://www.jstatsoft.org/v27/i02/paper) on
how to use plm to run panel regressions, and am having trouble with
what I believe should be something very basic.
When I run the command (p.9 in the paper):
R
Dear all,
I have querry on how to extract the data by matching between two data set where
one has the same elements multiple times?
For example, I have two matrix X and Y.
X
[,1] [,2] [,3]
1 A 5 P
2 B 6 P
3 C 7 P
4 D 5 Q
5 E
On 11/27/2009 10:25 AM, ram basnet wrote:
Dear all,
I have querry on how to extract the data by matching between two data set
where one has the same elements multiple times?
For example, I have two matrix X and Y.
X
[,1][,2] [,3]
1 A 5 P
2 B 6 P
Hello,
I am new to R program, therefore, I am sorry if this is a really stupid
question.
I wrote a simple function and for some reason it doesn't work
ReturnsGrid = function(x,y,m){
for (i in 1:m){
grid[i] - x + (i-1)*(y-x)/m
}
grid
}
xx=ReturnsGrid(0,9,3)
Thanks a lot!
On Nov 27, 2009, at 10:25 AM, ram basnet wrote:
Dear all,
I have querry on how to extract the data by matching between two
data set where one has the same elements multiple times?
For example, I have two matrix X and Y.
X
[,1][,2] [,3]
1 A 5 P
2 B 6
Hello,
I have a function that creates an expression object with some variables
substituted e.g
foo - function(s){
expression({
v - s
print(v)
})
}
Thus foo returns an expression, however the expression has the symbol 's'
contained within it and thus returns an error when eval'd e.g
Hi,
You need to create the grid object before you can assign values to it. Try
ReturnsGrid = function(x,y,m){
grid - numeric()
for (i in 1:m){
grid[i] - x + (i-1)*(y-x)/m
}
grid
}
On Fri, Nov 27, 2009 at 11:00 AM, Anastasia nast...@gmail.com wrote:
Hello,
I am new to R program, therefore,
Duijvesteijn, Naomi wrote:
Hi R-ers,
I am struggling with my x-axis in a association plot. What I would like is
to place the labels of the x-axis between the tick markers and normally the
labels are printed at the place where the tick marker is placed. I don’t
want to move the
Hi,
The error message,
Error in grid[i] - x + (i - 1) * (y - x)/m :
object of type 'closure' is not subsettable
indicates that grid is actually known to R as a function (type grid
to see its definition). You can define your own variable with the same
name, but that needs to be done before the
On 27/11/2009 11:04 AM, Saptarshi Guha wrote:
Hello,
I have a function that creates an expression object with some variables
substituted e.g
foo - function(s){
expression({
v - s
print(v)
})
}
Thus foo returns an expression, however the expression has the symbol 's'
contained
Hi,
If you execute the following code it works but I wouldn't use grid if I
were you as a vector as this name is already used by R (check
help(grid)) and it explains why you have to define it in the function.
ReturnsGrid = function(x,y,m){
grid - numeric(m)
for (i in 1:m){
grid[i] - x +
Thanx.
I'll just post in here the way I solved it in case someone happens to
need something similar in the future. It may not be the most elegant
way, but it worked!
yes = small
no = large
data3$group = ifelse(data3$SIE 50.64593,yes,no)
Peter Ehlers wrote:
Peter Ehlers wrote:
Vitória
I'm not sure what you mean by 'multiplying by 10 and rounding'. I've tried to
re-organize the data and then create a ts object that is analogous to the
various sunspot datasets provided in the data package with R, but the matrix I
generate by binning the data into centuries (which would make
Hi all,
I'm trying my best in changing the names of my experiments in the spectral
map.
My experiments are from six different time points, two as control and two
treated experiments.
I set have for each time point a different color .
Now I want to change the symbols so that I have for the
The substitute() function can do it, but the bquote() function is the most
convenient:
foo - function(s) {
+ bquote(expression({
+ v - .(s)
+ print(v)
+ }))
+ }
foo(10)
expression({
v - 10
print(v)
})
Duncan Murdoch
Thanks, after sending this email, i used
My script generates a mixture of normal and ff objects.
Very often I would like to save the workspace for
each parameter setting, so that I can get back to it later on.
Is there an easy way to do this,
instead of needing to save individual ff objects separately?
With one save() you can
I wonder how efficiently it is to do the following command on a frequent
basis.
nrow(matFF) - nrow(matFF)+1
Obviously there is overhead (closing file, enlarging file, openeing file).
I recommend you measure yourself whether this is acceptable for you.
no large file copying is needed each
Hi,
You would also make your code more efficient and possible more readable
by doing
ReturnsGrid -
function(x, y, m)
{
x + (seq.int(m) - 1) * (y - x) / m
}
(xx - ReturnsGrid(0, 9, 3))
#[1] 0 3 6
And if you want to supply vector x and y you could do something like
(there are probably better
Erm... Maybe the sequence bit wont work ... A bit hasty there
And also the length check should be
if (length(x) != length(y) !(length(x) == 1 | length(y) == 1)) stop
(inputs not compatible) # or something
I missed out the not!
-Original Message-
From: r-help-boun...@r-project.org
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Rob Steele
Sent: Thursday, November 26, 2009 8:03 AM
To: r-h...@stat.math.ethz.ch
Subject: [R] Best way to preallocate numeric NA array?
These are the ways that occur to me.
Morning folks (at least here on the western side of the U.S.)...
This morning I constructed a contour plot of some bivariate
distributions I'm working with. When I attempted to add a second
contour to the plot using a dashed line (lty=2), R immediately went
off to la-la land, requiring a
Great! That did the trick, thanks David.
To summarize for the list, to get dynformula to work (example):
R a =
dynformula(emp~wage+capital,log.form=list(capital=FALSE,TRUE),lag.form=list(emp=2,c(2,3)),diff.form=list(FALSE,capital=TRUE))
it might be necessary to use:
R plm(formula =
You might also note that the authors hint on the help page that one
might want to use the formula() operation on the result of dynformula.
Following that path would have gotten us to a more successful
conclusion.
grun.fe - plm(formula = formula(a),data=EmplUK)
grun.fe
Model Formula:
I want to find the inverse of an integer k mod p (prime.) Is there a
function that can do this for me? I know i could simply write (k^(p-2)) %%
p, but i need to do this for large primes (above 100) and this gives the
warning message:
Warning message:
probable complete loss of accuracy in modulus
On Nov 27, 2009, at 12:04 PM, Owen Powell wrote:
Hi David,
Thank you for the response.
I forgot to mention that I'd already tried what (I think) you propose
(adding .form to the end of the lag, log and diff) and I still
see the same results (posted below). Specifically, I still see no
lags,
Hi David,
Thank you for the response.
I forgot to mention that I'd already tried what (I think) you propose
(adding .form to the end of the lag, log and diff) and I still
see the same results (posted below). Specifically, I still see no
lags, logs or diffs in my model.
Any other ideas?
~Owen
Hello,
how to replace the NA by number zero?
matrizt
[,1] [,2] [,3][,4]
[1,] 1.000NA NA NA
[2,] 0.6717685 0.1453253 NA NA
[3,] 0.3971276 0.1493241 0.14532526 NA
[4,] 0.1493241
Hi,
Try this,
matrizt[is.na(matrizt)] - 0
HTH,
baptiste
2009/11/27 Romildo Martins romildo.mart...@gmail.com:
Hello,
how to replace the NA by number zero?
matrizt
[,1] [,2] [,3] [,4]
[1,] 1.000 NA NA NA
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of SJ Robson-Davis
Sent: Friday, November 27, 2009 8:52 AM
To: r-help@r-project.org
Subject: [R] Modular inverses
I want to find the inverse of an integer k mod p (prime.) Is
Hi,
I just started with R and I found that there are many options to rearrange
the data to do mixed models.
I want to use the reshape function. I have 2 between subject variables and
one within.
I was able to change the data structure but still - the result of the aov
functions are calculating
matritz[is.na(matritz)] - 0
On Fri, Nov 27, 2009 at 04:15:45PM -0200, Romildo Martins wrote:
Hello,
how to replace the NA by number zero?
matrizt
[,1] [,2] [,3][,4]
[1,] 1.000NA NA NA
[2,] 0.6717685
Hello,
After some research, I didn't resolve my doubt yet...
Maybe I didn't explain very well my question... So, I have a bootstrap
simulation, but suppose just a simple part of my function:
teste -function(x){
rw_mean_app-rnorm(x, mean = 10, sd = 2)
rwy_mean_app-rnorm(x, mean = 10, sd = 2)
Hi list,
It may be a FAQ, but I searched the web and Uni of Newcastle Maths and Stats and
R mailing list archive on this issue but was unable to find a solution. I would
appreciate any pointer to help me solving this.
I am using R version 2.10.0 (2009-10-26) on linux mandriva 2010.0
I tried to
Or Duek wrote:
Hi,
I just started with R and I found that there are many options to rearrange
the data to do mixed models.
I want to use the reshape function. I have 2 between subject variables and
one within.
I was able to change the data structure but still - the result of the aov
functions
Hi all,
I'm new to R. Having a functional background, I was wondering what's
the idiomatic way to iterate. It seems that for loops are the default
given there's no tail-call optimization.
I'm curious to know whether there is a way to transform the following
toy snippet into something that
Hi Luis.
You can change the two lines
PROBLEM buf
WARN;
to the one line
warning(buf);
That should compile.
If not, please show us the compilation command for DocParse.c, i.e. all the
arguments
to the compiler, just above the error messages.
D.
Luis Tito de Morais wrote:
Hi list,
On Thu, Nov 26, 2009 at 6:56 PM, David Winsemius dwinsem...@comcast.net
wrote:
The situation that I see (after looking at the documentation for adehabit)
is that for some as yet unarticulated reason, you have decided that the
methods used in prior publications in your domain are not the best and
I'm not entirely sure I understand the problem, but one possible solution
would be to use some device like postscript that saves the graphics to a
file. (Or some other device appropriate for your intended use and OS.)
You could still save the data to a list if you wanted - just make it part
of
The following I do not understand, but then I did'nt really use
S4 methods ...
showMethods(plot)
Function: plot (package graphics)
x=ANY
x=lmList.confint
x=merMCMC
(inherited from: x=ANY)
plot(x=moda0MCMC)
Error in as.double(y) :
cannot coerce type 'S4' to vector of type 'double'
Dear R-Users!
The most recent entries on orthogonal regression that I have found on
this list date back to 2005.
Is there, by now, any package available that allows for a multivariate
orthogonal regression in R?
Thanks and best regards.
Georg
georg.blind at gmx.net
Dear All,
I am looking at discriminating among several individuals based on a few
variable sets (I think some variables do not make sense unless they are
entered together, so I force them into the models together, hence
datasets). I have done so with linear discriminant analysis (LDA) using
I posted the full extent of this question to Nabble, but essentially I'm having
difficulty determining the route cause of the unexpected string constant
error in the zp2ssg2.R (which I'm trying to port over from Octave).
Here is my current Nabble posting:
I want an 'apply' function that can give me results by bind the result
from each function call of g. Could somebody let me know how to do it?
g-function(x){
if(x==1){
rbind(c(1,3,8))
} else if(x==2) {
rbind(c(4,7,2), c(3,7,3)) #if I use line, sapply() below gives me a list
Buenas noches César,
Tal y como se estipula en la sección 8.1 de [1], la R 32-bits funciona en
Windows 64-bits aunque con las limitaciones de RAM que todos conocemos (solo
puedes usar hasta 4 GB de RAM en el mejor de los casos). Para instalarlo
sólo descarga el ejecutable usual de CRAN, haz doble
I'm not a programmer either, if by programmer you mean one who took
a computer science degree and is employed with some title that implies
a creator of code. I am a user of software toward particular purposes.
The purposes need to be defined in sufficiently specific manner to
guide that
Peng Yu pengyu.ut at gmail.com writes:
I want an 'apply' function that can give me results by bind the result
from each function call of g. Could somebody let me know how to do it?
g-function(x){
[snip]
}
x=1:3
sapply(x,g)
do.call(rbind,sapply(x,g))?
I get a different result, undoubtedly because I have different
packages loaded:
showMethods(plot)
Function plot:
not a generic function
sessionInfo()
R version 2.10.0 Patched (2009-10-29 r50258)
x86_64-apple-darwin9.8.0
locale:
[1] en_US.UTF-8/en_US.UTF-8/C/C/en_US.UTF-8/en_US.UTF-8
On Nov 27, 2009, at 9:39 PM, David Winsemius wrote:
I get a different result, undoubtedly because I have different
packages loaded:
showMethods(plot)
Function plot:
not a generic function
sessionInfo()
R version 2.10.0 Patched (2009-10-29 r50258)
x86_64-apple-darwin9.8.0
locale:
[1]
yeah, my mistake is that i did not make the data c into a zoo class.
now the problem solved.
thank you everybody
2009/11/27 Gabor Grothendieck ggrothendi...@gmail.com
We will need a minimal reproducible example (as per last line on every
message to r-help) to answer as trying it with made up
My apologies to all of you. I sent this email to the wrong email list :)
Best,
Jorge
2009/11/27 Jorge Ivan Velez
Buenas noches César,
Tal y como se estipula en la sección 8.1 de [1], la R 32-bits funciona en
Windows 64-bits aunque con las limitaciones de RAM que todos conocemos (solo
Evidently it just needed a little more tweaking...
http://n2.nabble.com/Need-help-solving-the-unexpected-string-constant-error-td4077984.html#a4078425
Hopefully all this will work out...
- Original Message
From: Jason Rupert jasonkrup...@yahoo.com
To: R-help@r-project.org
Sent:
i had some great success with mosiacplots...
http://stat.ethz.ch/R-manual/R-patched/library/graphics/html/mosaicplot.html
http://stat.ethz.ch/R-manual/R-patched/library/graphics/html/mosaicplot.html
...does anyone know of any other hidden gems out there that allow you to
examine the
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