Douglas Bates wrote:
The first VAX at our university, a VAX-11/780, was allegedly a 1
MIPS machine but it was pretty difficult to get it to do a million of
any instruction in one second. I eventually succeeded because it had
a special instruction for decrement and branch on zero so if you
Hi Felipe,
Make sure predictors data.frame has the EXACT same column names as the
data.frame you used for creating ModeloLineal.
Cheers,
Tal
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me:
hi,
maybe you should see:
http://cc.oulu.fi/~jarioksa/softhelp/FAQ-vegan.html#How-to-use-different-plotting-symbols-in-ordination-graphics_003f
greetings,
kay
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Kay Cichini wrote:
i need to calculate ci's for each of 4 groups within a dataset, to be able
to infere about differences in the variable similarity. the problem is
that data within groups is dependent, as assigned by the blocking-factor
site. my guess was to use a block bootstrap but
not yet,
but it would either not solve the non iid problem, or would it?
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Dear All
I am doing one distributed data mining program. So I selected GridR
package for the distributed programming.
*grid.init(service=local,debug=FALSE, localTmpDir=GridRTmp/)
grid.apply(x,UCS, wait=TRUE )*
UCS is a function.
When I execute this statement, I have some errors like :
*cannot
Hi all,
I am modifying a program I wrote before to perform smallest canonical
(SCAN) correlation method for identification of ARMA(p,q) orders in Time
Series, but when I compared the output with SAS, there are some differences.
My SCAN R code can be downloaded in the following URL:
On 04/04/2010 06:21, Deepayan Sarkar wrote:
On Thu, Apr 1, 2010 at 4:10 AM, Luigi Ponti lpo...@inbox.com wrote:
Hello,
I am trying to give different colors to boxes in a violin plot obtained via
bwplot from lattice package using a color palette from RColorBrewer:
[...]
However, when I
*Always* report sessionInfo() and traceback() when reporting problems. /Henrik
On Tue, Apr 6, 2010 at 11:11 AM, wesley mathew wesleycmat...@gmail.com wrote:
Dear All
I am doing one distributed data mining program. So I selected GridR
package for the distributed programming.
1. Are you able to determine if its the filtering step that is the
problem? Also is it the size of the file or is it a particular record
that is causing the problem? If you read it in in two pieces do both
pieces work or just one piece? It might be a problem in the
filtering step (in which
Hi Bert,
Thanks for your reply.
I AM making an assumption of MAR data, because
informative missingness (I assume you mean NMAR) is too hard to deal with
I have quite a few covariates (so the observed is likely to predict
the missing and mitigate against informative missingness)
the
Dear Thomas,
Thanks for your reply.
Yes you are quite right (your example) complete case does not require
MCAR, however as well as being a bit less robust than ML it is throwing
away data.
Missing Data in Clinical Studies, Geert Molenberghs, Michael Kenward,
have a nice section in chapter 3
Dear All,
I seem entirely unable to solve what should be a very simple problem. I
have imported a SPSS dataset into R using spss.get from Frank Harrell's
Hmisc library. The variables are imported classed as 'labelled': missing
values are coded as either the SPSS missing value code, 8 or 88.
Hi All,
I'm hoping someone else can help me out with this. I am doing some
matrix algebra using sub-parts of matrices, and sometimes I need only
a single row/column of the original matrix. However, whenever I pull
out only a single row/column, R returns a row vector, but often this
will break my
a - c(1, 8, 9, 10, 8)
a[which(a==8)] - NA
Nikhil
On Apr 6, 2010, at 7:31 AM, David Foreman wrote:
Dear All,
I seem entirely unable to solve what should be a very simple
problem. I
have imported a SPSS dataset into R using spss.get from Frank
Harrell's
Hmisc library. The variables are
On Apr 6, 2010, at 6:31 AM, David Foreman wrote:
Dear All,
I seem entirely unable to solve what should be a very simple problem. I
have imported a SPSS dataset into R using spss.get from Frank Harrell's
Hmisc library. The variables are imported classed as 'labelled': missing
values are
On Apr 6, 2010, at 6:39 AM, Robert M. Flight wrote:
Hi All,
I'm hoping someone else can help me out with this. I am doing some
matrix algebra using sub-parts of matrices, and sometimes I need only
a single row/column of the original matrix. However, whenever I pull
out only a single
x - iris$Sepal.Length[1:50]/iris$Sepal.Width[1:50]
y - iris$Petal.Length[1:50]/iris$Petal.Width[1:50]
I want to check whether (x,y) follows a bivariate normal distribution or
not, using density plot or scatter plot. Is it possible to plot a bivariate
density in R. I cant find any.
Arindam
yes, there is -- have a look at the online help file ?[, especially
argument 'drop'. Try also this:
crud - matrix(c(1,2,3,4,5,6,7,8,9,10,11,12),nrow=3,ncol=4)
crud[, 1, drop = FALSE]
I hope it helps.
Best,
Dimitris
On 4/6/2010 1:39 PM, Robert M. Flight wrote:
Hi All,
I'm hoping someone
Many others have made good comments regarding your questions, my
suggestion would be this: You may or may not know that R is freely
available and that you can install more than one version of R on the
same PC, so I would suggest installing both R 2.6 and the latest version
of R (2.10.x) and try
I am attempting to extract the derivative/ gradient from this expression
df1p - deriv(f1, P)
df1p
expression({
.value - s - c - a * P
.grad - array(0, c(length(.value), 1L), list(NULL, c(P)))
.grad[, P] - -a
attr(.value, gradient) - .grad
.value
})
So in this case I want
jda wrote:
I have imported data from an Excel spreadsheet. Columns in that
spreadsheet are named name, x, and y, and several sets of those
columns appear in the worksheet. For example:
name x y name x y
test1 1 3 test2 4 4
test1 2 2 test2 5 5
test1 3 1 test2 6 6
When I
Hello List,
I am having a great trouble using svm function in e1071 package. I have 4gb of
data that i want to use to train svm. I am using Amazon cloud, my Amazon
Machine Image(AMI) has 34.2 GB of memory. my R process was killed several times
when i tried to use 4GB of data for svm. Now I am
Dear all,
What is the right test to test whether the median of two groups are
statistically significant? Is it the wilcox.test, mood.test or the ks.test?
In the text book I have got there is explanation for the Wilcoxon (Mann
Whitney) test which tests ob the two variable are from the same
Try this:
attributes(eval(df1p))$gradient[,'P']
On Tue, Apr 6, 2010 at 9:09 AM, nickymcp nickymcpher...@gmail.com wrote:
I am attempting to extract the derivative/ gradient from this expression
df1p - deriv(f1, P)
df1p
expression({
.value - s - c - a * P
.grad - array(0,
attributes(eval(df1p))$gradient[,'P']
Error in eval(expr, envir, enclos) : object 's' not found
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Post your f1 function to us
On Tue, Apr 6, 2010 at 10:23 AM, nickymcp nickymcpher...@gmail.com wrote:
attributes(eval(df1p))$gradient[,'P']
Error in eval(expr, envir, enclos) : object 's' not found
--
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First, apologies for no example data but I don't think it's needed in
this case,
Q: Can (and if so how ) the line end style be changed for 'cloud' plots?
I've tried par(lend=2), trellis.par.set(add.line = list(lend=2)) and
much googling but to no avail
Thanks in advance
Dan
P.S. the reason
f1
~s - c - a * P
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R-help@r-project.org mailing list
Try fixing the constants
s - 2
c - 3
a - 2
P - 1
attributes(eval(df1p))$gradient[,'P']
On Tue, Apr 6, 2010 at 10:30 AM, nickymcp nickymcpher...@gmail.com wrote:
f1
~s - c - a * P
--
View this message in context:
OK... next question.. Which is still a data manipulation problem so I
believe the heading is still OK.
##So now I read my population data from excel.
pop-read.csv(pop.csv)
typeof(pop) ## yields a list where I have age-specific population rows
and a yearly column population, where the years are
Thanks for your help - this works and I get
s - 2
c - 3
a - 2
P - 1
attributes(eval(df1p))$gradient[,'P']
P
-2
What I really wanted was an expression that I can use later - do you think
there's any way to do this?
--
View this message in context:
On Apr 6, 2010, at 7:48 AM, arindam fadikar wrote:
x - iris$Sepal.Length[1:50]/iris$Sepal.Width[1:50]
y - iris$Petal.Length[1:50]/iris$Petal.Width[1:50]
I want to check whether (x,y) follows a bivariate normal
distribution or
not, using density plot or scatter plot. Is it possible to plot
df1p is a expression, and you can use later.
On Tue, Apr 6, 2010 at 11:00 AM, nickymcp nickymcpher...@gmail.com wrote:
Thanks for your help - this works and I get
s - 2
c - 3
a - 2
P - 1
attributes(eval(df1p))$gradient[,'P']
P
-2
What I really wanted was an expression that I can use
Roger DeAngelis(xlr82sas) wrote:
Hi,
About the forest plot.
Some Phrarma companies demand the report and graphics follow very
restrictive layouts.
Thank goodness that the FDA does not require that.
Frank
SAS allows uses to use one template for graphs and tables.
Margins have
Dear useRs,
version 2.2-2 of the betareg package has just been released on CRAN
http://CRAN.R-project.org/package=betareg
accompanied by an article in the Journal of Statistical Software
http://www.jstatsoft.org/v34/i02/
The package provides beta regression for data in the unit interval
Dear useRs,
version 1.0-0 of the Formula package has just been released on CRAN
http://CRAN.R-project.org/package=Formula
accompanied by an article in the Journal of Statistical Software
http://www.jstatsoft.org/v34/i01/
It provides simple infrastructre for processing formulas like
y
Also I have seen 5,000 page listings in SAS.
Is this a pro or a con?
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
Department of Statistics / Rice University
http://had.co.nz/
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Dear R-list members,
I am calculating the linear extrapolation for a data set, using the function
found in Hmisc.
x=c(0.0265,-0.0003,0.0142,0.0263,0.0634,0.1145,0.2504)
y=c(58,107,152,239,362,512,724)
x1=0.0393216
approxExtrap(x,y,x1, method=linear)
approx(x,y,x1)
#to see what is happening:
On Thu, 2010-03-25 at 11:54 -0800, Jeff Brown wrote:
Wow, you guys are awesome. Thanks!
Thanks for the cat() question Jeff and to all guRus out there for the
replies. This is something I was looking for the last hour.
Nikos
__
R-help@r-project.org
On Tue, Apr 6, 2010 at 9:09 AM, nickymcp nickymcpherson at gmail.com
https://stat.ethz.ch/mailman/listinfo/r-help wrote:
*
** I am attempting to extract the derivative/ gradient from this expression
**
** df1p - deriv(f1, P)
** df1p
** expression({
**.value - s - c - a * P
**.grad -
On Apr 6, 2010, at 10:42 AM, marta rufino wrote:
Dear R-list members,
I am calculating the linear extrapolation for a data set, using the
function
found in Hmisc.
x=c(0.0265,-0.0003,0.0142,0.0263,0.0634,0.1145,0.2504)
y=c(58,107,152,239,362,512,724)
x1=0.0393216
approxExtrap(x,y,x1,
Hi Claire,
I'm replying and CC-ing to the R-help list to get more eyes on your
question since others will likely have more/better advice, and perhaps
someone else in the future will have a similar question, and might
find this thread handy.
I've removed your specific research aim since that
someone else on this list may be able to give you a ballpark estimate
of how much RAM this merge would require.
I don't have an absolute estimate, but try data.table::merge, as it needs
less
working memory than base::merge.
20 million rows of 5 columns isn't beyond 32bit :
(1*4 +
Dear all,
I have used following code but everytime I encounter a problem of not having
coefficients for all the variables in the predictor set.
# code
rm(list=ls())
library(caret)
# generating response and design matrix
X-matrix(rnorm(50*100),nrow=50)
y-rnorm(50*1)
# Applying caret package
Hi,
On Tue, Apr 6, 2010 at 8:07 AM, Shyamasree Saha [shs] s...@aber.ac.uk wrote:
Hello List,
I am having a great trouble using svm function in e1071 package. I have 4gb
of data that i want to use to train svm. I am using Amazon cloud, my Amazon
Machine Image(AMI) has 34.2 GB of memory. my
Thank David,
That is completely correct! I have no ideia how come matlab and Octave do
not do this... maybe the interp1 function has some kind of trick. .. maybe
the algorythm looks for the closest ranked values and not by its true value.
What ever...
Just sort it out in a not prety-but
ok, not really sorted :-(does not work in other values,...and I am not
really sure how to come over it
x=c(0.0191,0.0088,0.0150,0.0105,0.0430,0.0697,0.1999)
y=c(58,107,152,239,362,512,724)
x1=0.02220172
kk=y[x==min(x)]
approxExtrap(x[ykk],y[ykk],x1, method=linear)
approx(x[ykk],y[ykk],x1)
plot(x,
On Apr 6, 2010, at 12:13 PM, marta rufino wrote:
ok, not really sorted :-(does not work in other values,...and I am
not really sure how to come over it
x=c(0.0191,0.0088,0.0150,0.0105,0.0430,0.0697,0.1999)
y=c(58,107,152,239,362,512,724)
x1=0.02220172
kk=y[x==min(x)]
Hello I am trying to use predict, but I am having trouble getting out of
sample predictions. I am getting the same output if I use the following
three commands:
predict(ModeloLineal,predictors[721:768,])
predict(ModeloLineal,predictors[1:768,])
predict(ModeloLineal)
where ModeloLineal is the
Dear Whom it may concern,
I need help to figure the macro function in R: I need to plot the
different data sets by a plotxyf function, I want the title to be different
for different data set.
# get the data set
final.xyf- xyf(data=as.matrix(my.final),
Y=classvec2classmat(final$outcome),
On Apr 6, 2010, at 12:25 PM, Luis Felipe Parra wrote:
Hello I am trying to use predict, but I am having trouble getting
out of
sample predictions. I am getting the same output if I use the
following
three commands:
predict(ModeloLineal,predictors[721:768,])
On Tue, 2010-04-06 at 09:33 -0700, Changbin Du wrote:
#plot function
plotxyf-function (data) {
plot(data, type=mapping, labels=final$target, col=final$outcome+1,,
main=Supervised: Mapping plot for data)
Change this to: main=paste(Supervised: Mapping plot for, data)
Steve Lianoglou mailinglist.honeypot at gmail.com writes:
Hi Claire,
I'm replying and CC-ing to the R-help list to get more eyes on your
question since others will likely have more/better advice, and perhaps
someone else in the future will have a similar question, and might
find this
None of them.
- mood.test() looks promising until you read the help page and see that it
does not do Mood's test for equality of quantiles, it does Mood's test for
equality of scale parameters.
- wilcox.test() is not a test for equal medians
- ks.test() is not a test for equal medians.
A small correction.
On Tue, Apr 6, 2010 at 9:43 AM, Stuart Luppescu s...@ccsr.uchicago.eduwrote:
On Tue, 2010-04-06 at 09:33 -0700, Changbin Du wrote:
#plot function
plotxyf-function (data) {
plot(data, type=mapping, labels=final$target, col=final$outcome+1,,
main=Supervised: Mapping
On Tue, 6 Apr 2010, Stuart Luppescu wrote:
On Tue, 2010-04-06 at 09:33 -0700, Changbin Du wrote:
#plot function
plotxyf-function (data) {
plot(data, type=mapping, labels=final$target, col=final$outcome+1,,
main=Supervised: Mapping plot for data)
Change this to: main=paste(Supervised:
Hi,
First a quick note about FDA and Style Guides.
Frank is correct the FDA does not require strict formatting. I once worked
for small startup and they sent EXCEL sheets to the FDA. However big pharma
usually has very strict formatting requirements. I once produced a table
where one of the
Jeff Brown wrote:
Wow, you guys are awesome. Thanks!
Nikos Alexandris wrote:
Thanks for the cat() question Jeff and to all guRus out there for the
replies. This is something I was looking for the last hour.
I can't seem to make this run:
I have a function ( Column.of.Matrix.1 ,
I think the problem is that you have R configured as 32-bits. If that
is the case, then you will only have access to 4 gigs of RAM (see
http://www.brianmadden.com/blogs/brianmadden/archive/2004/02/19/the-4gb-windows-memory-limit-what-does-it-really-mean.aspx).
Try booting up an ubuntu instance in
Hi Peter,
This looks like another one: gset_is_equal(X,X) and X == X evaluate to
FALSE ?
uv - c('a', 'b', 'c'); s - gset(uv, runif(length(uv)))
s
{a [0.0811552], b [0.3552998], c [0.996772]}
gset_is_equal(s, s)
[1] FALSE
s == s
[1] FALSE
class(s)
[1] gset cset
Best regards,
Ryszard
I've shared a document with you:
plot.png
http://docs.google.com/leaf?id=0B_J5_yv8GrERYWRhZjU4NDItMmMyOS00ZGIxLWE2ZDUtMDFiYTY3MzliMzhkhl=eninvite=CI2a3aYC
It's not an attachment -- it's stored online at Google Docs. To open this
document, just click the link above.
[[alternative HTML
On Tue, 2010-04-06 at 19:29 +0200, Nikos Alexandris wrote:
Jeff Brown wrote:
Wow, you guys are awesome. Thanks!
Nikos Alexandris wrote:
Thanks for the cat() question Jeff and to all guRus out there for the
replies. This is something I was looking for the last hour.
I can't seem to
On Tue, Apr 6, 2010 at 6:27 PM, Roger DeAngelis(xlr82sas)
rdean...@amgen.com wrote:
Hi,
First a quick note about FDA and Style Guides.
Frank is correct the FDA does not require strict formatting. I once worked
for small startup and they sent EXCEL sheets to the FDA. However big pharma
Hi,
Just a couple of notes to reply to others questions.
1. unx is a file handle that points to my UNIX SAS work directory(like an
R workspace). This directory is not mounted under windows. most of the SAS
objects, ie SAS datasets in the 64bit Unix directory are available to my
windows SAS
I've shared a document with you:
plot.png
http://docs.google.com/leaf?id=0B_J5_yv8GrERYWRhZjU4NDItMmMyOS00ZGIxLWE2ZDUtMDFiYTY3MzliMzhkhl=eninvite=CIa4nqkK
It's not an attachment -- it's stored online at Google Docs. To open this
document, just click the link above.
Hi there,
Using the code
Hi,
I agree with Barry, but there are some of us out there that are trying to
change the image of big Pharma.
R helps statisticians do real science.
I have complained for about 10 years about EXCEL and WORD driving the
delivery of inputs and outputs. Years ago, I did a short gig with
Hi,
I have a data set of a number of compounds and their C13 chemical
shifts data. The classes of the compounds are either strong or weak. There
are 100 feature variables which are different C13 bins. In each C13 bin the
values are counts (number of times a chemical shift is present in
Thanks, Bill! That was deep, and took me a long time to work through, but I
get it now.
And Gabor -- r-proto is great!
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Hello,
I would like to place region names (or abbreviations if space is too
limited) on a map. I have tried the following, copying and adapting
various examples I have seen but without success. The first example
is self-contained, but the second one requires the .shp file, which
can retrieved
On Apr 6, 2010, at 9:56 AM, moleps islon wrote:
OK... next question.. Which is still a data manipulation problem so I
believe the heading is still OK.
##So now I read my population data from excel.
No, you read it from a text file and providing the first ten lines of
that text file should
On Apr 6, 2010, at 3:30 PM, David Winsemius wrote:
On Apr 6, 2010, at 9:56 AM, moleps islon wrote:
OK... next question.. Which is still a data manipulation problem so I
believe the heading is still OK.
##So now I read my population data from excel.
No, you read it from a text file and
Hi Guys
I have two data frames which I would like to merge on two conditions.
I am doing the following (abstract form)
new.data.frame - merge(df1,df2, by=c(Col1,Col2))
It is giving me a null result.
Basically I need to apply two conditions.
I also tried sqldf but it is running forever. Will
Hi there,
Using the code below I generated the plot attached. The error bars at day =
-3, 2 and 4 appear are larger. I was thinking if there is a way I could make
all the error bars to be of the same size. I don't know if that makes sense.
If not, then, is there a way I can plot only these 3
Hi Trey,
On Mon, Apr 5, 2010 at 1:58 PM, Trey trey3...@hotmail.com wrote:
Dr. Stevens,
Hi, my name is Trey Scott, and I'm a grad student of Brian McCarthy's. He
referred me to you because of your expertise in handling complex R problems.
We were hoping you could help us solve a nagging
I have uploaded the property data from Lee County Property Appraiser into R,
but my problem is that I am unable manipulate and use many of the columns
because they are classified as factors. I think this is because the values
represent selling prices and therefore have $ in front of them. I
On Apr 6, 2010, at 3:54 PM, Abhishek Pratap wrote:
Hi Guys
I have two data frames which I would like to merge on two conditions.
I am doing the following (abstract form)
new.data.frame - merge(df1,df2, by=c(Col1,Col2))
What does
str(df1) ; str(df2)
... show?
It is giving me a null
Hi David
Here it is. You can ignore the bio jargon if it sounds confusing. The
corresponding data type of column (SNP, chr) on which I am applying merge is
same.
merge(data_lane6_snps, data_lane6_snps_rsid , by = c(SNP,chr))
str(data_lane6_snps)
'data.frame': 7724462 obs. of 10 variables:
And I should also add that if I merge only on one column it works fine but
the result is not what I want.
merge(data_lane6_snps, data_lane6_snps_rsid , by = c(SNP) : works as
expected.
Is the chr column being a factor creating probs here ?
-A
On Tue, Apr 6, 2010 at 4:03 PM, Abhishek Pratap
possible hint:
as.numeric(gsub(\\$, , c($1.23, $1.32)))
cavalier33901 wrote:
I have uploaded the property data from Lee County Property Appraiser into R,
but my problem is that I am unable manipulate and use many of the columns
because they are classified as factors. I think this is because
On 06/04/2010 3:40 PM, cavalier33901 wrote:
I have uploaded the property data from Lee County Property Appraiser into R,
but my problem is that I am unable manipulate and use many of the columns
because they are classified as factors. I think this is because the values
represent selling prices
Erik Iverson wrote:
possible hint:
as.numeric(gsub(\\$, , c($1.23, $1.32)))
and convert to character first before as.numeric if they were factors to
begin with...
cavalier33901 wrote:
I have uploaded the property data from Lee County Property Appraiser
into R,
but my problem is that
Hi Shyama,
Don't forget to CC the r-help list in your discussions so that there
are more eyes on this problem, and others might potentially benefit
from discussion.
Comments in line.
On Tue, Apr 6, 2010 at 4:06 PM, Shyamasree Saha [shs] s...@aber.ac.uk wrote:
Dear Steve,
Thanks a lot for
On Apr 6, 2010, at 4:03 PM, Abhishek Pratap wrote:
Hi David
Here it is. You can ignore the bio jargon if it sounds confusing.
Sometimes it is essential to have domain details.
The corresponding data type of column (SNP, chr) on which I am
applying merge is same.
merge(data_lane6_snps,
Hi David
I can understand looking the SNP data values it can be felt that they are
different values and hence no result in merge. However the columns still
have ~700K SNPs common. What I am looking for is a merge where the SNP and
Chr matches. If I match only the SNP column I get partially
Just so you know
length(intersect(data_lane6_snps$SNP, data_lane6_snps_rsid$SNP))
796120
I just need to include the chr condition now where I am stuck.
-Abhi
On Tue, Apr 6, 2010 at 4:51 PM, Abhishek Pratap abhishek@gmail.comwrote:
Hi David
I can understand looking the SNP data values
On 2010-04-06 7:28, Daniel Alcock wrote:
First, apologies for no example data but I don't think it's needed in
this case,
Q: Can (and if so how ) the line end style be changed for 'cloud' plots?
I've tried par(lend=2), trellis.par.set(add.line = list(lend=2)) and
much googling but to no avail
OK, not the SNP's. So look at the chr's. I will bet that you get 0
when you try :
length(intersect(data_lane6_snps$chr, data_lane6_snps_rsid$chr))
... since one is using a format of chrNN and the other is using just
NN. You need to get the chromosome naming convention straightened out.
On Tue, Apr 6, 2010 at 12:48 PM, arindam fadikar
arindam.fadi...@gmail.com wrote:
x - iris$Sepal.Length[1:50]/iris$Sepal.Width[1:50]
y - iris$Petal.Length[1:50]/iris$Petal.Width[1:50]
I want to check whether (x,y) follows a bivariate normal distribution or
not, using density plot or scatter
You got the error. It is different naming convention of chr. I should be
able to fix that pretty easily.
In case the problem persists, I will contact the list.
Thanks!
-Abhi
On Tue, Apr 6, 2010 at 5:01 PM, David Winsemius dwinsem...@comcast.netwrote:
OK, not the SNP's. So look at the chr's. I
Below. -- Bert
Bert Gunter
Genentech Nonclinical Statistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Liviu Andronic
Sent: Tuesday, April 06, 2010 2:06 PM
To: arindam fadikar
Cc: r-help@r-project.org
Subject: Re: [R]
Hello All,
I am very new to the R and i want to know how to connect to the teradata in
R and import data from there.
Currently I am using SAS to import data and i use the following syntax to
connect to teradata.
*Proc Sql;
connect to odbc (dsn=teradata username = '**' password =
How do I append an R-object to a list?
I want to start with an empty list, and append R-objects one by one.
Does this start with a command like
mylist - NULL
??
I have read a few answers on R-help to questions like this, but they all
seem to be well off the point. Sometimes it's assumed that the
All-
I am interested in estimating a parameter that is the starting value for an ODE
model.
That is, in the typical combined fitting procedure using nls and lsoda
(alternatively rk4), I first defined the ODE model:
minmod - function(t, y, parms) {
G - y[1]
X - y[2]
Nice, thanks A lot. I got it figured out
--
View this message in context:
http://n4.nabble.com/Need-Help-with-Manipulating-Columns-tp1753364p1753471.html
Sent from the R help mailing list archive at Nabble.com.
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R-help@r-project.org mailing list
Thanks I tried it with your values and it works, but when I try it with my
values, plugging in just (not sure if i'm doing it right):
as.numeric(gsub(\\$, , (just)))
This is what I get:
[1] NA
Warning message:
NAs introduced by coercion
Btw here are the values im wokring with under
On Tue, Apr 6, 2010 at 10:28 PM, David.Epstein
david.epst...@warwick.ac.uk wrote:
How do I append an R-object to a list?
I want to start with an empty list, and append R-objects one by one.
Does this start with a command like
mylist - NULL
??
I have read a few answers on R-help to
Thanks for the response. I read through the Inferno and there's a lot of
useful stuff in there. However I think you may have missed something.
Having some experience with other languages, I know that floating point
numbers aren't represented exactly, the issue is that R is off by much more
than
On Apr 6, 2010, at 4:26 PM, sumit gupta wrote:
Hello All,
I am very new to the R and i want to know how to connect to the teradata in
R and import data from there.
Currently I am using SAS to import data and i use the following syntax to
connect to teradata.
*Proc Sql;
connect to
Ummm... I think the problem is with _your_ inadequate understanding.
Consider: identical( (4.1 * 100 ) %/% 1 , 409 )
4.1*100 410
[1] TRUE
So, due to finite precision, 4.1*100 is slightly less than 410.
Whence the largest integer 1 can be divided into it is 409. i.e.
(4.1*100) %/% 1
[1] 409
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