Hi,
I've solved the problem. This command works
axis(1,at=axTicks(1),label = axTicks(1)/100);
Thanks for your help
~Rajesh
On Mon, May 17, 2010 at 9:55 AM, rajesh j akshay.raj...@gmail.com wrote:
Hi,
I tried using this in my plot and I get an error saying
'at' and 'labels' lengths differ, 8
I tried cbind, it works.
moms-read.delim(females.txt, sep = ,stringsAsFactors=FALSE,header=TRUE)
dads-read.delim(males.txt, sep = ,stringsAsFactors=FALSE,header=TRUE)
output_offspring -
cbind(moms[,c(1,sample((2:5),2))],dads[sample(nrow(dads),nrow(moms),replace=TRUE),c(1,sample((2:5),2))])
Hi Tobias,
Yes, epiR and irr provide respectively CCC and ICC, but I could not find any
implementation of the total deviation index.
I might just implement Lin's code.
Met vriendelijke groeten, Gregoire
From: r-help-boun...@r-project.org
On May 16, 2010, at 1:12 PM, sam.e wrote:
Thank you for the helpful direction to the smoothing splines
function, it was
very helpful and is exactly what i am trying to do. My data however
is 3-D,
i.e. i have x and y values which are coordinates for different field
sites
and z values
HI,
I am trying to create a heatmap with 24 samples with 15672 varibles, I read
in the table in R, and then made it as a matrix, then try to create the
heatmap using heatmap(x,...)
However, I received the error message as:
heatmap(t(x))
Error: cannot allocate vector of size 936.8 Mb
Dear, I want to make an application to calculate quantile within a For()
I tried the following without success:
ej.
date
p_val - matrix(sample(10, 1000, replace=TRUE), 200,5)
test 1
rr - paste(p_val$,names(p_val[1]), sep=)
quant - quantile(rr, probs = c(0, 10, 20, 30, 40, 50, 60, 70, 80,
Hi,
Thanks! :)
I'll install the newer version of R. However do I have to recompile all the
modules that I did for my previous version of R?
Regards,
Padma Tan
Genome Institute of Singapore
60 Biopolis Street, Genome
#02-01 Singapore 138672
DID : 6478 8671
Fax : 6478 9058
email:
Hello,
I'm fairly new to R and am running version 2.11.0 with Windows 7. I need to
run the package gplots. The package installs fine, but when I try to load
it I receive the message:
Loading required package: gtools
Error: package 'gtools' could not be loaded
In addition: Warning message:
I've examining a number of linear regression models on a large dataset
following the basic ideas presented here
http://www.r-bloggers.com/r-calculating-all-possible-linear-regression-models-for-a-given-set-of-predictors/
Calculating all possible linear regressions . I run into a problem with
Dear everyone,
I try to regress a dynamic panel model with pgmm function in the plm
package, but it doesn't work. The error report is Error in names(coefficients)
- c(namesX, namest) :
'names' attribute [13] must be the same length as the vector [5].
My command is:
Hi,
When I check the beadarray in R, I found the following information:
package.version(beadarray)
[1] 1.16.0
library(beadarray)
Error in library.dynam(lib, package, package.lib) : Cannot find sharing library
(beadarray)
Does anybody know what I can do for this problem?
Thanks a lot!
Amit amitkumartiwary at gmail.com writes:
Hi! All,
To find co-expressed genes from a expression matrix of dimension (9275
X 569), I used rcorr function from library(Hmisc) to calculate pearson
The code itself is correct. I have tried it on my computer.
About the Pvalue, FDR may be
Hi r-users,
I have a matrix B and a list of 3x3 matrices (mylist). I want to
calculate the quantiles in the list using each of the value of B as
probabilities.
The codes I wrote are:
B - matrix (runif(12, 0, 1), 3, 4)
mylist - lapply(mylist, function(x) {matrix (rnorm(9), 3, 3)})
for
I won't have an answer but it will help others to help you if you also
report what the following gives:
library(gtools);
print(sessionInfo());
and
print(packageDescription(gtools));
My $.02
Henrik
On Mon, May 17, 2010 at 4:01 AM, agusdon agus...@gmail.com wrote:
Hello,
I'm fairly new to
Additionally, please give the full output that let you assume
The package installs fine...
Uwe Ligges
On 17.05.2010 10:18, Henrik Bengtsson wrote:
I won't have an answer but it will help others to help you if you also
report what the following gives:
library(gtools);
print(sessionInfo());
On 17.05.2010 05:22, Padma TAN wrote:
Hi,
Thanks! :)
I'll install the newer version of R. However do I have to recompile all the
modules that I did for my previous version of R?
If you use the same library (or a copy of it) you used for packages
under the old R version, then
I'm trying to dynamically build variable names to use on a list. Let's say I
have a list like this one:
l - list(V1_1=c(1,2,3), V1_2=c('One','Two','Three'))
And I succesfully build my variable name like this:
paste('l$', 'V1_1', sep='')
Why can't I just run a mean call with the pasted
Hi,
I wonder why my attempt to extend an existing loess fit to a new data set is
producing error. I was trying the following:
dat = read.csv(choose.files())
x = dat[,2]; y = dat[,1]
x.sort = sort(x)
y.loess = loess(y~x, span=0.75)
# For testing the above fit with a new dataset:
test =
I'm trying to dynamically build variable names to use on a list. Let's say I
have a list like this one:
l - list(V1_1=c(1,2,3), V1_2=c('One','Two','Three'))
And I succesfully build my variable name like this:
paste('l$', 'V1_1', sep='')
Why can't I just run a mean call with the
library(fortunes)
fortune('parse')
If the answer is parse() you should usually rethink the question.
-- Thomas Lumley
R-help (February 2005)
On Mon, May 17, 2010 at 5:08 AM, Stefan Petersson
stefan.peters...@inizio.se wrote:
I'm trying to dynamically build variable names to
?'[['
What I think you want is:
x - V1_1
mean(l[[x]])
Also you need to look at 'get'.
On Mon, May 17, 2010 at 4:41 AM, Stefan Petersson
stefan.peters...@inizio.se wrote:
I'm trying to dynamically build variable names to use on a list. Let's say
I have a list like this one:
l -
On Mon, May 17, 2010 at 11:12 AM, jim holtman jholt...@gmail.com wrote:
?'[['
What I think you want is:
x - V1_1
mean(l[[x]])
Also you need to look at 'get'.
...and if the answer is get() or assign() you should usually consider
library(fortunes); fortune(rethink the question);
/Henrik
Dear Limin,
might be just about anything. Could you please provide a reproducible
example?
Best,
Giovanni
- Original message --
Message: 51
Date: Mon, 17 May 2010 10:36:03 +0800 (CST)
From: ??? dlm...@163.com
To: r-help@r-project.org
Subject: [R] pgmm
On 05/17/2010 06:01 PM, Lorenzo Cattarino wrote:
Hi r-users,
I have a matrix B and a list of 3x3 matrices (mylist). I want to
calculate the quantiles in the list using each of the value of B as
probabilities.
The codes I wrote are:
B- matrix (runif(12, 0, 1), 3, 4)
mylist- lapply(mylist,
There's a note on this issue at
http://www.nag.co.uk/numeric/RunderWindows.asp
which claims it can 'safely be ignored'.
Your mileage may vary, I presume.
I had the same error message under a previous version (but with a
different library and during installation, not loading, some packages)
Hi R Forum
I am a newbie to R and I have been amazed by what
I can get my team to accomplish just by
implementing Scripting routines of R in all my
team's areas of interest..
Recently i have been trying to adopt R scripting
routine for some analysis with longitudanal data..
I am presenting my R
On 05/16/2010 11:20 PM, shizhu zang wrote:
Hi,
When I check the beadarray in R, I found the following information:
package.version(beadarray)
[1] 1.16.0
library(beadarray)
Error in library.dynam(lib, package, package.lib) : Cannot find sharing
library (beadarray)
Does anybody
Dear users,
I've noticed some time ago that some of the packages I use (especially
doBy) could not run (yet) on R 2.11. So I kept on using R 2.10.
But I think it should be fine by now.
So my question is how do I check whether a package is compatible with
the last version of R? How can I
Dear R Family,
I have an error message. I would like to learn how to deal with that.
The orginal series is as follows: I just pick up the first 10 observations.
dif_transaud[1:10]
[1] 0.0065880493 -0.0065880490 -0.0131743570 0.0197745715 0.0065889175
[6] 0.0131813110 0.0065923924
On May 16, 2010, at 6:16 PM, Agustín Muñoz M. (AMFOR) wrote:
Dear, I want to make an application to calculate quantile within a
For()
I tried the following without success:
ej.
date
p_val - matrix(sample(10, 1000, replace=TRUE), 200,5)
test 1
rr - paste(p_val$,names(p_val[1]), sep=)
On 17/05/2010 6:58 AM, S Ellison wrote:
There's a note on this issue at
http://www.nag.co.uk/numeric/RunderWindows.asp
which claims it can 'safely be ignored'.
That's very specific to NAG. The quote continues: Only one of the NAG
routines uses a different FPU control word and this
I'm an R noob and have a (maybe) stupid question...
I have a table where I have the weekdays and a number for each weekday of
entries:
Thats what the table looks like...
Now I want to have an pie3D plot of this, but obviously the order of the
weekdays are not as one would expect...
Friday
The probem is that in the case of model 2 the standard error terms
reduce to a vector of length one. Since subsetting with '[' drops
unneeded dimensions by default, this vector loses it's name. The
solution is to add 'drop = FALSE' to your subset call, like this
ldply(fits, function(x)
On May 17, 2010, at 4:47 AM, Chintanu wrote:
Hi,
I wonder why my attempt to extend an existing loess fit to a new
data set is
producing error. I was trying the following:
dat = read.csv(choose.files())
x = dat[,2]; y = dat[,1]
x.sort = sort(x)
That is not needed, furthermore, you don't
On May 17, 2010, at 8:07 AM, Ivan Calandra wrote:
Dear users,
I've noticed some time ago that some of the packages I use
(especially doBy) could not run (yet) on R 2.11. So I kept on using
R 2.10.
But I think it should be fine by now.
So my question is how do I check whether a package
Dear Sir or Madam:Hi,sorry for disturbing you. Currently, I'm a master
student, and my lecturer didn't teach us anything about how to use R. But the
assignment is all about R. So even a very stupid error,I still can't tell. So
please forgive my innocence.
The following is the
Hello.
I ran a simulation that took a few days to complete, and want to analyze the
results, but have just realized that I (idiotically) did not assign the
output to a variable when I intitiated the simulation. Is there any way to
retrieve the last output produced by R so that these last few
We still have a long way to go with the data we were given by some drug
discovery scientists.
The problem is to select the few variables (Collective Variables), from a set
of variables sampled during a
Molecular Dynamics simulation, which exhibit a consistent and coherent
relationship with
On May 17, 2010, at 8:22 AM, Moohwan Kim wrote:
Dear R Family,
I have an error message. I would like to learn how to deal with that.
The orginal series is as follows: I just pick up the first 10
observations.
[1:10]
[1] 0.0065880493 -0.0065880490 -0.0131743570 0.0197745715
See
.Last.value
On Mon, May 17, 2010 at 10:07 AM, math_daddy math_da...@hotmail.com wrote:
Hello.
I ran a simulation that took a few days to complete, and want to analyze
the
results, but have just realized that I (idiotically) did not assign the
output to a variable when I intitiated
Hi,
Try this,
saveMyWork - .Last.value
HTH,
baptiste
On 17 May 2010 15:07, math_daddy math_da...@hotmail.com wrote:
Hello.
I ran a simulation that took a few days to complete, and want to analyze the
results, but have just realized that I (idiotically) did not assign the
output to a
I'm working with the randomForest package and have successfully build a
model. I'd like to go one step further however, and use the output from
the model to construct a map using the output. My input data are spatial,
and I have an independent set of rasterize maps for each of the predictor
Thank you David!
Le 5/17/2010 15:10, David Winsemius a écrit :
On May 17, 2010, at 8:07 AM, Ivan Calandra wrote:
Dear users,
I've noticed some time ago that some of the packages I use
(especially doBy) could not run (yet) on R 2.11. So I kept on using R
2.10.
But I think it should be
On 17/05/2010 9:07 AM, APOLLOCHEROKEE wrote:
Dear Sir or Madam:Hi,sorry for disturbing you. Currently, I'm a
master student, and my lecturer didn't teach us anything about how to use R.
But the assignment is all about R. So even a very stupid error,I still can't
tell. So please
Please read the Posting Guide. Several of your questions will get
answered, including why the attachment did not arrive at any of out
mail clients.
We are having some difficulty understanding why you say your lecturer
didn't teach us anything about how to use R. It appears from the
For example if nombreC - nombreC - c(Juan, Carlos, Ana, María,Mario)
I do not want as a result:
name index
1 Juan 1
2 Juan 5
3 Carlos 2
4Ana 3
5 María 4
6 Mario 0
I want:
name index
1 Juan 1
2 Juan 5
3 Carlos 2
4Ana 3
5 María
Steve,
It sounds to me like you want to use the model to predict data in other
maps. If so, you should be using predict(), not getTree(). getTree()
shows the classification rules in _one_ of the trees in the forest
(default the first tree), which is rarely of interest if you've grown
hundreds
I'm just guessing (since as David pointed out, no reproducible example
were given), but this perhaps could be the problem:
R x - 1:10
R y - rnorm(x)
R fm - loess(y ~ x)
R predict(fm, data.frame(x=5:15))
[1] 0.1830450 0.2145826 -0.2158466 -0.3051978 -0.2635318 -0.1013985
[7] NA
Dear R-help,
just for the record a summary of responses to my problem:
On 04/05/2010 9:41 AM, Rainer Scheuchenpflug wrote:
a student of mine tries to use the Windows-Rconsole with screen
reading software (she is blind), and cannot access the command line (Menus
are ok).
- Duncan Murdoch
7 data points? What's wrong with with doing it manually?
x-c(173,193,194,167,119,80,96)
labs-c(Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday)
pie3D(x,labels=labs)
-tgs
On Mon, May 17, 2010 at 8:46 AM, someone vonhof...@t-online.de wrote:
I'm an R noob and have a (maybe) stupid
Hello,
the positioning of text elements in a graphics is nortmally
done via x/y coordin ates of the displayed data.
most of the time this is very helpful (and missing in other
programs).
But when I want to set some text into a graphics always at the same position,
this will not be easy...
I
well, actually the script is run by crone job once in a while and id hate to
do things manually...
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On May 17, 2010, at 10:31 AM, someone wrote:
well, actually the script is run by crone job once in a while and id
hate to
do things manually...
The order of levels of a factor variable variable can be changed with
a call along the lines of
fac - factor(fac, levels=c(Monday, Tuesday,
On 13 May 2010 00:41, RATIARISON Eric eratiari...@monceauassurances.com wrote:
Hi, here my new version:
I submit you my case:
( Pseudo likehood for exponential family with offset )
loglik - function(param) {
b-param
m=as.vector(of+z%*%b)
ll - sum(v*m-exp(m)) }
gradlik -
Hello,
What about something like this?
week.table - data.frame(Friday=119, Monday=173, Saturday=80,
Sunday=96, Thursday=167, Tuesday=193, Wednesday=194)
ordered -
c(Monday,Tuesday,Wednesday,Thursday,Friday,Saturday,Sunday)
week.table - week.table[,ordered]
library(plotrix)
Hello Giovanni
I made a minor modification to your function, which now allows to
compute the within R-sq in Twoways Within models (see below).
However I ran into an issue that I have already encountered before:
whenever I try to fit Twoways Within models on my unbalanced data, the
process is
= Summary =
Version 0.8.0 of the Rcpp package was released to CRAN today. This release
marks another milestone in the ongoing redesign of the package, and
underlying C++ library.
= Overview =
Rcpp is an R package and C++ library that facilitates integration of C++
code in R
Assuming you really do have a table,
tab - as.table(c(Friday=119, Monday=173, Saturday=80,
+ Sunday=96, Thursday=167, Tuesday=193, Wednesday=194))
tab
FridayMonday SaturdaySunday Thursday Tuesday Wednesday
119 1738096 167 193 194
we
Hello to the list
I'm using a Rscript launched via the linux terminal as the title of this
mail explains. The following is the code of the Rscript :
myRscript.r
1 #!/usr/bin/Rscript
2
3 #Read data
4
I have a large data frame 48:2185 with different numbers.
I would like to add only one row at the very top of my data frame with
0's or NA's.
I don't know which approach to use. Should i create 2 different data
frames and merge them? Ive also tried the rbind command with no luck.
I would
Hi Holger,
I would also highly recommend you look at the ?boxcox and ?logtrans
functions in the MASS package. There is also a very illuminating,
concise discussion about their use on Pages 170 - 172 of
Venables, W. N. and Ripley, B. D. (2002) Modern Applied Statistics
with S. Fourth edition.
Version 2.2.0 of package bcp is now available. It replaces the
suggests of NetWorkSpaces (previously used for optional parallel MCMC)
with the dependency on package foreach, giving greater flexibility and
supporting a wider range of parallel backends (see doSNOW, doMC,
etc...).
For those
The long-promised revision to bigmemory has arrived, with package
4.2.3 now on CRAN. The mutexes (locks) have been extracted and will
be available through package synchronicity (on R-Forge, soon to appear
on CRAN). Initial versions of packages biganalytics and bigtabulate
are on CRAN, and new
Hello.
In this post:
http://finzi.psych.upenn.edu/Rhelp10/2010-March/233815.html
Uwe Ligges suggests using BRugs rather than R2WinBUGS under windows. He
also notes that it is not in the main CRAN repository, but it is in
extras which is a default repository under windows.
I have OpenBUGS
Try this:
x - data.frame(a=1:10, b=1:10)
x
a b
1 1 1
2 2 2
3 3 3
4 4 4
5 5 5
6 6 6
7 7 7
8 8 8
9 9 9
10 10 10
# add a row at the top
x - x[c(1,seq(nrow(x))),]
x
a b
11 1
1.1 1 1
22 2
33 3
44 4
55 5
66 6
77 7
88 8
Lot of examples for one way pipes, but I need to create some named
pipes from R to another process, especially SQLite. I am look at the
R/SQLite packages for help. ANy pointers?
___
R-packages mailing list
r-packa...@r-project.org
Dear all,
I have a function f(x).
ptm - proc.time()
y=f(x)
proc.time() - ptm
works fine for me.
However it is not possible to write
system.time(y=f(x))
and
system.time(f(x))
does not store the value of f(x).
Should I prefer the 3 lines with proc.time ?
Thank you very much,
Gustave
Dear All,
I am executing my R script from PHP using the shell_exec.
$return = shell_exec(/usr/bin/R --slave --args .$Domain.,.$Gender.
/var/www/html/trends/newTrend.R);
In newTrend.R, I am plotting graph and save in pdf file using the below
code. It will create a pdf file with two line.
Does this work?
data(cars)
cars2 - cars
cars2[2:nrow(cars)+1,] - cars2[1:nrow(cars),]
cars2[1,] - NA
Nikhil Kaza
Asst. Professor,
City and Regional Planning
University of North Carolina
nikhil.l...@gmail.com
On May 17, 2010, at 11:28 AM, ecvet...@uwaterloo.ca wrote:
I have a large data
On 2010-05-17 9:28, ecvet...@uwaterloo.ca wrote:
I have a large data frame 48:2185 with different numbers.
I would like to add only one row at the very top of my data frame with
0's or NA's.
I don't know which approach to use. Should i create 2 different data
frames and merge them? Ive also
Thank-you for the replies. I believe I figured out what the problem was.
When I installed the package on linux it ran smoothly, but I just need to
install a lot of accessory packages to make gplots work with Windows.
Thanks again,
Aaron
2010/5/17 Uwe Ligges lig...@statistik.tu-dortmund.de
Hi, Everyone,
I am trying to fit a ring specific gravity dataset using the linear
mixed-effects model (lme function) in R. However, the AIC value is extrememly
low (such as -8000) and the loglikehihhod value is extremely big (such as
4000), which seems not correct to me. What could the result
On 2010-05-17 11:14, Nikhil Kaza wrote:
Does this work?
data(cars)
cars2 - cars
cars2[2:nrow(cars)+1,] - cars2[1:nrow(cars),]
cars2[1,] - NA
Not for me. Did you try it?
-Peter Ehlers
Nikhil Kaza
Asst. Professor,
City and Regional Planning
University of North Carolina
Subsequently saw this in FAQs
See FAQ:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-do-lattice_002ftrellis-graphics-not-work_003f
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On May 17, 2010, at 1:36 PM, GL wrote:
I have the two loops listed below. The first executes perfectly and
creates a
series of density plots. The second does not produce any output,
however, if
I enter the exact bwplot command after the loop executes, I get
output for
the last value in
Works with warnings for me. but your method is better.
Nikhil
On May 17, 2010, at 1:35 PM, Peter Ehlers wrote:
data(cars)
cars2 - cars
cars2[2:nrow(cars)+1,] - cars2[1:nrow(cars),]
cars2[1,] - NA
__
R-help@r-project.org mailing list
I am trying to perform quantile regression (using quantreg package) and
I am particularly interested to know whether the technique requires
independence of observations.
I am an ecologist and, in particular, I collected data of abundance of a
species in 15 location around an island. In each
This is not an R question, though you may receive help from this list. But
you would probably do better posting on a statistical list, especially one
focused on ecology.
Bert Gunter
Genentech Nonclinical Biostatistics
-Original Message-
From: r-help-boun...@r-project.org
I am recoding some data. Many values that should be 1.5 are recorded
as 1-2. Some example data and my solution is below. I am curious about
better approaches or any other suggestions. Thanks!
# example input data
myData - read.table(textConnection(id, v1, v2, v3
a,1,2,3
b,1-2,,3-4
I have a matrix that is 2400x2000 and I would like to display it as an image,
I have tried image(), but due to the size of the matrix the drawing of the
plot is extremely slow. Does anybody know of any fast ways to visualize such
a large matrix. Thanks
--
View this message in context:
Try this:
newData - sapply(numdat, function(x)lapply(strsplit(as.character(x), '-'),
function(.x)mean(as.numeric(.x
On Mon, May 17, 2010 at 3:29 PM, Juliet Hannah juliet.han...@gmail.comwrote:
I am recoding some data. Many values that should be 1.5 are recorded
as 1-2. Some example data
On Mon, May 17, 2010 at 6:24 PM, Peter Ehlers ehl...@ucalgary.ca wrote:
Try
system.time(y - f(x))
and see ?=.
-Peter Ehlers
Ah ha. That explains the curly brackets I saw in a posting with
system.time on stack overflow just now:
system.time({y=f(x)})
works as expected since the {}
Hi,
try this,
m = matrix(runif(2000*2400), nrow=2000)
library(grid)
grid.raster(m)
HTH,
baptiste
On 17 May 2010 20:35, tetonedge de...@tetonedge.net wrote:
I have a matrix that is 2400x2000 and I would like to display it as an image,
I have tried image(), but due to the size of the matrix
My mistake.
cars2 should be initalized to have all the extra rows.
cars2 - data.frame(matrix(rep(NA, prod(dim(cars)) + ncol(cars)),
nrow(cars)+1))
cars2[2:nrow(cars2),] - cars
In this way, insertion at any row is possible.
Nikhil
On May 17, 2010, at 2:46 PM, Peter Ehlers wrote:
data(cars)
That works great, thanks
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__
R-help@r-project.org mailing list
I have created separate plots in multiple graphics windows using the
windows() function in R.
How do I save all the plots in one PDF file?
I tried savePlot(C:/rplot.pdf, type = pdf). However, it only saved the
plot in the current graphics window.
Thank you!
[[alternative HTML version
1.Open pdf device
pdf()
2.Do your plotting as many as you want, you won't see the plots on the
screen because they go directly to the pdf() device.
3.Turn off the pdf()
dev.off()
Then you can review your plots in the pdf file. For more details see ?pdf
Jun
On Mon, May 17, 2010 at 2:41 PM,
Thanks!
I got an error message when opening the pdf file: There was an error
opening this document. This file cannot be opened because it has no pages.
Here is what I did in plotting and saving the file:
pdf(file=C:/figure.pdf)
for (j in 1:numColumns)
{
windows(width=5, height=5)
plot(xj,y)
}
If you do plotting in a loop, then you need to print it to the device.
print(plot(xj,y))
On Mon, May 17, 2010 at 3:02 PM, Shirley Bao baoxi...@gmail.com wrote:
Thanks!
I got an error message when opening the pdf file: There was an error
opening this document. This file cannot be opened
No, that's only true for lattice and ggplot2 graphics. The problem
here is with this line,
windows(width=5, height=5)
which shouldn't be there.
HTH,
baptiste
On 17 May 2010 22:23, Jun Shen jun.shen...@gmail.com wrote:
If you do plotting in a loop, then you need to print it to the device.
On 2010-05-17 12:54, Henrique Dallazuanna wrote:
Try this:
newData- sapply(numdat, function(x)lapply(strsplit(as.character(x), '-'),
function(.x)mean(as.numeric(.x
There's a potential problem if numdat contains negative numbers.
It would be better to restrict the recoding to character or
library(xts)
library(TTR)
ndx = getYahooData(^NDX)
aa = ndx$Close
bb = aggregate(aa, as.yearweek, tail, 1)
The last operation takes forever, and then the bb dates are messed up. The
following produces the desired result:
time(aa) = as.Date(time(aa))
bb = aggregate(aa, as.yearweek, tail, 1)
Hi All,
Just thought I'd bring attention to the fact that lme4 is failing cran
checks on the mac platform, and I can't seem to install it from source on
10.5 or 10.6, either (ld: library not found for -lgfortran
) . Any help getting this working?
Thanks!
[[alternative HTML version
Hi All,
Just thought I'd bring attention to the fact that lme4 is failing cran
checks on the mac platform, and I can't seem to install it from source
on 10.5 or 10.6, either (ld: library not found for -lgfortran ) .
Any help getting this working?
Thanks!
(sorry for the non-plain-text...)
On May 17, 2010, at 4:44 PM, Adam November wrote:
Hi All,
Just thought I'd bring attention to the fact that lme4 is failing cran
checks on the mac platform, and I can't seem to install it from source
on 10.5 or 10.6, either (ld: library not found for -lgfortran ) .
Any help getting this
I fit a GAM to turtle growth data using mgcv:
m1 - gam(growth~s(mean.size,
bs=cr)+s(year,bs=cr,k=7)+s(cohort,bs=cr)+s(age,bs=cr), data=grow,
family=quasi(link=identity))
The errors are skewed (and seem to be correlated with age) (code and plots
here:
I believe I'm working with the newest version of R (2.11.0) and I've
tried a few of the most recent versions... No luck yet.
Thanks,
-Adam
On Mon, May 17, 2010 at 1:51 PM, David Winsemius dwinsem...@comcast.net wrote:
On May 17, 2010, at 4:44 PM, Adam November wrote:
Hi All,
Just thought I'd
Thank you Bill, Peter and Barry.
2010/5/17 Barry Rowlingson b.rowling...@lancaster.ac.uk
On Mon, May 17, 2010 at 6:24 PM, Peter Ehlers ehl...@ucalgary.ca wrote:
Try
system.time(y - f(x))
and see ?=.
-Peter Ehlers
Ah ha. That explains the curly brackets I saw in a posting
one way:
x - rnorm(100)
y - x+rnorm(100)
par(mfrow=c(2,2)) # this sets up the graphics window to expect a 2x2 layout
plot(x,y)
boxplot(x,y,names=c(var1,var2))
hist(x)
hist(y)
mtext(fourplots on same page,side=3,outer=T,line=-1.5)
and you can adjust as needed to put more or less plots on the
Thanks Cedric. I did take a look at RServe, but that doesn't seem to support
concurrency in windows environment. As ours is primarily a windows
environment, we are looking for some other ways. Is there any way in
rJava/JRI to call commands directly from java code?
Thank you.
On Sat, May 15,
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