Hi:
Perhaps the OP is referring to Jim Lindsey's event package, which is not on
CRAN but available at
http://www.commanster.eu/rcode.html
HTH,
Dennis
On Wed, Jun 23, 2010 at 3:11 AM, Jim Lemon j...@bitwrit.com.au wrote:
On 06/23/2010 02:10 AM, Pedro Mota Veiga wrote:
Hi people of R forum,
Hi,
The format problem is really annoying. How to get rid of it?
x
[1] 1e+06
And also when I do barplot,
x=rnorm(100,mean=1000)
barplot(table(cut(x,breaks=c(0,50,100,150,200,250,300,350,400,450,500,1000,2000,5000,1
The data will show as scientific format, when it is larger than 999
Hi:
Does this work for you?
xyplot(distance ~ age | Sex, data = Orthodont, groups = Subject,
main = 'Individual linear regressions ~ age', type = c('g', 'r'),
panel = function(x, y, ...) {
panel.xyplot(x, y, ..., col = gray(0.5))
panel.lmline(x,
Hi all,
I understand that gls() uses generalized least squares, but I thought
that maybe optimum weights from gls might be used as weights in lm (as
shown below), but apparently this is not the case. See:
library(nlme)
f1 - gls(Petal.Width ~ Species / Petal.Length, data = iris, weights
=
On Wed, 2010-06-23 at 16:30 -0700, cc super wrote:
What if the size of the newdata is different from the previous one
used to generate the regression model?
Let's say
pdat - data.frame(x1 = rnorm(5, 2), x2 = rnorm(5))
predict(lin, pdat)
It comes up with warning and the result is not
Hi:
Try this:
for (i in 1:2) {
+ x=c(1,2,3,4)
+ y=c(10,20,30,40)
+ G - paste(name, i, sep=)
+ assign(G, data.frame(x,y))
+ }
name1
x y
1 1 10
2 2 20
3 3 30
4 4 40
name2
x y
1 1 10
2 2 20
3 3 30
4 4 40
HTH,
Dennis
On Wed, Jun 23, 2010 at 3:56 PM, Douglas M.
Lorenzo,
This is a bit ugly but should work. Instead of using plotrix's show.values,
use the text() command:
for(i in 1:5) {
for(j in 1:5) {
text(i-0.5,j-0.5,format(A[6-j,i],digits=3),col=white)
}
}
--
View this message in context:
Upload it to GoogleDocs http://docs.google.com or
Dropboxhttp://dropbox.comand give us a public link to the dataset.
HTH,
Brandon
On Wed, Jun 23, 2010 at 21:57, Felipe Carrillo mazatlanmex...@yahoo.comwrote:
For some reason the shapefile can't get attached.
The shapefile is too large to put
PS.
Mayby I can somehow try to transform data and check it, for example, using the
skewness-function of timeDate-package?
Thanks. What I have had to ask is that
how do you test that the data is symmetric enough?
If it is not, is it ok to use some data transformation?
when it is said:
Thank you.
I finally found what was the problem.
By mistake, I compiled with different version of MinGW compiler. I heard
that new MinGw compiler does not support _Unwind_ kinds of functions
anymore.
Thank you again.
Lee.
On Wed, Jun 23, 2010 at 7:30 PM, Geun Seop Lee clarmas...@gmail.com
Thanks. What I have had to ask is that
how do you test that the data is symmetric enough?
If it is not, is it ok to use some data transformation?
when it is said:
The Wilcoxon signed rank test does not assume that the data are sampled from a
Gaussian distribution. However it does assume that
Hi
see
?options and scipen parameter
e.g. options(scipen=9)
Regards
Petr
r-help-boun...@r-project.org napsal dne 24.06.2010 08:39:29:
Hi,
The format problem is really annoying. How to get rid of it?
x
[1] 1e+06
And also when I do barplot,
x=rnorm(100,mean=1000)
Hi ,
i am trying to install tseries packages from local drive.i am getting
.Please advise
I am getting this errror
Please advise
utils:::menuInstallLocal()
Error in gzfile(file, r) : cannot open the connection
In addition: Warning message:
In gzfile(file, r) :
cannot open compressed file
I wanted to know if there is a way to perform a two sample binomial test in
R. I know you can use the proportion test i.e.:
prop.test(c(19,5),c(53,39),p=NULL,alternative=two.sided). But I was
looking to use the exact binomial test, binom.test, however when I have
tried replacing prop.test with
Hello Nabble users,
A question about having two y axes on a chart. I'm trying to show on the
left (first) y axis a measure used in an experiment; the x axis shows the
experiment number, that has been sorted in a specific manner -- i.e. not
Experiments 1,2,3,n, but could be Experiment 6,1,18,n;
Dear all, is there any R implementation on the Multivariate binomial
distribution like calculate the value of p.m.f., drawing random sample from
it etc.
Thanks,
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi
r-help-boun...@r-project.org napsal dne 24.06.2010 09:44:49:
Hello Nabble users,
A question about having two y axes on a chart. I'm trying to show on the
left (first) y axis a measure used in an experiment; the x axis shows
the
experiment number, that has been sorted in a specific
see ?levels eg:
x - rnorm(10)
y - cut(x,c(-10,0,10))
levels(y)-c(-10-0,0-10)
cheers
Joris
On Thu, Jun 24, 2010 at 4:14 AM, Yi liuyi.fe...@gmail.com wrote:
Yeap. It works. Just to make the result more beautiful.
One more question.
The interval is showns as (0,10].
Is there a way to change
On Wed, Jun 23, 2010 at 11:35 PM, Michael Friendly frien...@yorku.ca wrote:
Thanks, Deepayan
I read your presentation and understand how this works for the case you
presented, but I can't
get it to work for my case, where I want to superimpose model fitted lines
over individual
subject
Dear R-listers,
I have been using Snowfall (version 1.84) for parallel computing on a quad-PC
running Windows 7 for a month or so without much problem. I started having
problems runnnig R with Snowfall over our network when a new Novell client was
installed for Windows 7. I experinenced
On 24-Jun-10 06:36:39, associatedboy wrote:
I wanted to know if there is a way to perform a two sample binomial
test in R. I know you can use the proportion test i.e.:
prop.test(c(19,5),c(53,39),p=NULL,alternative=two.sided). But I was
looking to use the exact binomial test, binom.test,
Lorenzo,
You can also use a custom colorscale using color.scale and the
cellcolors option of color2D.matplot:
pdf(test_color_scale_logcolor.pdf)
oldpar-par( mar = c(4.5,5, 2, 1) + 0.1,
cex.axis=1.4,cex.lab=1.6,cex.main=1.6)
cellcolors - color.scale(log(A),c(0.2,1),c(0.2,0.5),c(0,0))
Dear R-community,
I am just conducting various mediation analyses with data from individual
participants who are nested in teams. I found the “sobel.lme” function to be
pretty helpful when doing so. (A big thank you to Paul Bliese for his
multilevel-package and the awesome manual!)
Here’s the
Isn't that exactly what you would expect when using a _generalized_
least squares compared to a normal least squares? GLS is not the same
as WLS.
http://www.aiaccess.net/English/Glossaries/GlosMod/e_gm_least_squares_generalized.htm
Cheers
Joris
On Thu, Jun 24, 2010 at 9:16 AM, Stats Wolf
Thanks for reply.
Yes, they do differ, but does not gls() with the weights argument
(correlation being unchanged) make the special version of GLS, as this
sentence from the page you provided says: The method leading to this
result is called Generalized Least Squares estimation (GLS), of which
WLS
Apologies for posting my question in HTML earlier. Reposted in plain text
now.
Dear R-listers,
I have been using Snowfall (version 1.84) for parallel computing on a quad-PC
running Windows 7 for a month or so without much problem. I started having
problems runnnig R with Snowfall over our
One way of looking at it is doing a sign test after substraction of
the mean. For symmetrical data sets, E[X-mean(X)] = 0, so you expect
to have about as many values above as below zero. There is a sign test
somewhere in one of the packages, but it's easily done using the
binom.test as well :
Dear useRs,
Thanks for any advices
# I do not know where are the examples how to mark groups
# based on signal occurence in the additional variable: cf. variable c2,
# How to calculate different calculations for groups defined by (split by
occurence of c2 characteristic data)
#First
On 06/23/2010 11:30 PM, Bill Harris wrote:
Let's say you have a dataframe of car trade-ins. For example, each row
contains
oldcar newcar qty
and a typical entry could be
lexus bmw1
I put the qty column to allow for fleet purchases, where one purchase
may convert multiple cars at
You are probably under Windows. The Menu to install from local zip files
implies you specify a precompiled binary package.
Uwe Ligges
On 24.06.2010 06:12, vijaysheegi wrote:
Hi ,
i am trying to install tseries packages from local drive.i am getting
.Please advise
I am getting this errror
--- On Thu, 6/24/10, Jim Lemon j...@bitwrit.com.au wrote:
From: Jim Lemon j...@bitwrit.com.au
Subject: Re: [R] Analyzing large transition matrix
To: Bill Harris bill_har...@facilitatedsystems.com
Cc: r-help r-help@r-project.org
Received: Thursday, June 24, 2010, 7:44 AM
On 06/23/2010
Hi,
1) There is no feature in geeglm for that sort of truncation of the outcome.
2) It is generally fragile - and not recommendable - to use
corstr=unstructured in geeglm.
Regards
Søren
Fra: r-help-boun...@r-project.org [r-help-boun...@r-project.org]
Hi,
perhaps you can send X.csv in a private message. It is easier to have a
reproducible example than reading the code line by line.
Best,
Uwe Ligges
On 24.06.2010 00:27, Dennis wrote:
Dear R users:
I was trying to fit a HMM with mixture of Gaussian into the dataset, and I
tried to
Indeed, WLS is a special case of GLS, where the error covariance
matrix is a diagonal matrix. OLS is a special case of GLS, where the
error is considered homoscedastic and all weights are equal to 1. And
I now realized that the varIdent() indeed makes a diagonal covariance
matrix, so the results
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org]
On Behalf Of Dr. David Kirkby
Sent: Tuesday, June 22, 2010 7:49 PM
To: r-help@r-project.org
Subject: Re: [R] Popularity of R, SAS, SPSS, Stata...
...
I don't know how practical it is with R, but
Indeed, they should give the same results, and hence I was worried to
see that the results were not that same. Suffice it to look at
standard errors and p-values: they do differ, and the differences are
not really that small.
Thanks,
Stats Wolf
On Thu, Jun 24, 2010 at 2:39 PM, Joris Meys
Hi everyone,
I made this set of boxplots that would show me the widths of some sites
broken up by some chromosome, but I don't know how to make it indicate the
number of data points that created the boxplot.
How do I do that?
boxplot(data$site~data$chr,varwidth='TRUE')
--
View this message
Hi all,
I have some time-series data in half hourly time steps and I want to be
able to either average or sum the two half hours together into hours.
Any help greatly appreciated.
Thanks,
Jenny
--
The University of Edinburgh is a charitable body, registered in
Scotland, with registration
(I've just realised that the example above might not be clear when
viewed in a browser)
So just to clarify, I would like to convert HTML entities into the
ASCII equivalent using R, saving the results to a plain text file.
For example:
x - paste(i, s, n, , a, p, o, s, ;, t, sep = )
would become
Hi - I am looping over a structural equation model for a variety of datasets.
Occasionally, the model returns an error and the loop then breaks. I'd like
to set a condition which says something like if error, then print NAs
rather than the loop breaking, but I don't know how to say if error.
I'm sorry, I don't understand your problem to the detail so my suggestion
may be waaay off, but how's this? You can see in vector vec - all ok values
except where there's an error.
n - 10
vec - rep(NA, n)
for (j in 1:n)
{tryCatch(ifelse(j==5, vec[j] - j, j), finally=print(oh dear))}
vec
I am studying on statistical shape analysis, I wonder is there any way or
package available that I can perform Euclidean Distance Matrix Analysis
(EDMA I or EDMA II) in R...
thanks
Gokhan
--
View this message in context:
Does ?tryCatch do what you want?
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-say-if-error-tp2266619p2266749.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
I've had a look at the conditions in base and I can't get the ones to work
I've looked at but it is all new to me.
For example, I can work the examples for tryCatch, but it won't print a
finally message for me when I apply it to my model. Even if I could get
this to work, I think it would
Does:
boxplot(data$site~data$chr, varwidth=TRUE)
(notice I removed the ' ' from the 'TRUE')
Work ?
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) |
Isn't this what
?dist
Does ?
Tal
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
Thanks Roman - you're right it can do more than I thought. We're close now
to solving it I feel. Essentially I'm trying to get the code below to work.
If the condition is satisfied, it prints 2, but it doesn't save it in z. I
want it to save it even though there's an error. Perhaps you can
Carrie,
According to the help file for the function integrate, the integrand 'f':
must accept a vector of inputs and produce a vector of
function evaluations at those points. The ‘Vectorize’ function
may be helpful to convert ‘f’ to this form.
The integrate function wraps
The weights in 'aa' are the inverse standard deviations. But you want to use
the inverse variances as the weights:
aa - (attributes(summary(f1)$modelStruct$varStruct)$weights)^2
And then the results are essentially identical.
Best,
--
Wolfgang Viechtbauer
__ Information from ESET NOD32 Antivirus, version of virus signature
database 5224 (20100624) __
The message was checked by ESET NOD32 Antivirus.
http://www.eset.com
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Thanks, John and Jim. In general, the problem is the large number of
entries, as you said (I could use up a lot of ink in a large-format
plotter, I guess).
Someone has suggested a pivot table in Excel :-) which makes me realize
that I need to learn the reshape and plyr packages immediately. The
On Thu, Jun 24, 2010 at 1:18 PM, Eugeniusz Kaluza
eugeniusz.kal...@polsl.pl wrote:
Dear useRs,
Thanks for any advices
# I do not know where are the examples how to mark groups
# based on signal occurence in the additional variable: cf. variable c2,
# How to calculate different
it works with the 'TRUE' as well but this only shows me the boxplots width;
it doesn't show me the number of data points used though.. This is what I
can't figure out
--
View this message in context:
http://r.789695.n4.nabble.com/boxplot-width-tp2266805p2266932.html
Sent from the R help mailing
On 24/06/2010 7:06 AM, Paul Chatfield wrote:
I've had a look at the conditions in base and I can't get the ones to work
I've looked at but it is all new to me.
For example, I can work the examples for tryCatch, but it won't print a
finally message for me when I apply it to my model. Even if
Thanks! I was getting confused as wel, Wolf really had a point.
I have to admit that this is all a bit counterintuitive. I would
expect those weights to be the inverse of the variances, as GLS uses
the inverse of the variance-covariance matrix. I finally found in the
help files ?nlme::varWeights
On Jun 24, 2010, at 7:45 AM, nana wrote:
Hi everyone,
I made this set of boxplots that would show me the widths of some
sites
broken up by some chromosome, but I don't know how to make it
indicate the
number of data points that created the boxplot.
How do I do that?
An old-fashioned and I guess also advised-against method would be to
use try() itself, eg :
set.seed(1)
x - rnorm(1:10)
y - letters[1:10]
z - rnorm(1:10)
for (i in list(x,y,z)){
cc - try(sum(i), silent=T)
if(is(cc,try-error)) {next}
print(cc)
}
Put silent=F if you want to see the error
nana,
If you save the boxplot as an R object, you can access various parameters of
the resulting plot. Since we don't have your data, I'll give you an example
with the preloaded ToothGrowth dataset:
ToothGrowth-y
b-boxplot(y$len~y$dose,xaxt=n)
Now, if you type b at the R prompt, you will see
Hi
r-help-boun...@r-project.org napsal dne 24.06.2010 15:18:39:
it works with the 'TRUE' as well but this only shows me the boxplots
width;
it doesn't show me the number of data points used though.. This is what
I
can't figure out
Save your boxplot call to same object
bbb -
Try this:
library(XML)
xmlValue(getNodeSet(htmlParse(x, asText = TRUE), //p)[[1]])
On Thu, Jun 24, 2010 at 6:53 AM, Tony Breyal tony.bre...@googlemail.comwrote:
(I've just realised that the example above might not be clear when
viewed in a browser)
So just to clarify, I would like to
In VBA there is a syntax if error resume next which sometimes acts as very
beneficial on ignoring error. Is there any similar kind of function/syntax
here in R as well?
Thanks for your attention
[[alternative HTML version deleted]]
__
Hi Ralf,
Ralf B wrote:
Sorry for the lack of details. Since I run the same SQL first directly
on MySQL (using the MySQL Query Browser) and then again using R
through the RJDBC interface, I assume that I won't simply have a badly
constructed SQL query. However, just to clear possible objection,
On 6/24/2010 10:30 AM, Christofer Bogaso wrote:
In VBA there is a syntax if error resume next which sometimes acts as very
beneficial on ignoring error. Is there any similar kind of function/syntax
here in R as well?
?try
Thanks for your attention
[[alternative HTML version
That's great. That solves it. I can work on eloquence later :) I just to
sort out that model problem:
dof-numeric(10)
for (i in 1:10){
x-rnorm(i-1);y-rnorm(i-1)
cc - try(lm(y~x), silent=T)
if(is(cc,try-error)) {dof[i]-NA}
else
Thank you. It worked.
Regards
--
View this message in context:
http://r.789695.n4.nabble.com/boxplot-width-tp2266805p2267050.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
http://r.789695.n4.nabble.com/How-to-say-if-error-td2266619.html#a2266619
Cheers
On Thu, Jun 24, 2010 at 4:30 PM, Christofer Bogaso
bogaso.christo...@gmail.com wrote:
In VBA there is a syntax if error resume next which sometimes acts as very
beneficial on ignoring error. Is there any similar
See ?aggregate
Cheers
J
On Thu, Jun 24, 2010 at 10:45 AM, Jennifer Wright
j.wright...@sms.ed.ac.uk wrote:
Hi all,
I have some time-series data in half hourly time steps and I want to be able
to either average or sum the two half hours together into hours. Any help
greatly appreciated.
Thank you kindly Henrique, that works perfectly for me.
On 24 June 2010 15:25, Henrique Dallazuanna www...@gmail.com wrote:
Try this:
library(XML)
xmlValue(getNodeSet(htmlParse(x, asText = TRUE), //p)[[1]])
On Thu, Jun 24, 2010 at 6:53 AM, Tony Breyal tony.bre...@googlemail.com
wrote:
Dear useRs,
Thanks for advice from Joris Meys,
Now will try to think how to make it working for less specyfic case,
to make the problem more general.
Then the result should be displayed for every group between non empty string in
c2
i.e. not only result for:
#mean:
c1 c3c4
Unfortunately, I have a lot of errors with RMySQL -- but that is
another thread...
Ralf
On Thu, Jun 24, 2010 at 10:31 AM, James W. MacDonald
jmac...@med.umich.edu wrote:
Hi Ralf,
Ralf B wrote:
Sorry for the lack of details. Since I run the same SQL first directly
on MySQL (using the MySQL
On a similar issue, how can you detect a warning in a loop - e.g. the
following gives a warning, so I'd like to set up code to recognise that and
then carry on in a loop
x-rnorm(2);y-c(1,0)
ff-glm(y/23~x, family=binomial)
so this would be incorporated into a loop that might be
You could do that using the options, eg :
set.seed(1)
x - rnorm(1:10)
y - letters[1:10]
z - rnorm(1:10)
warn -getOption(warn)
options(warn=2)
for (i in list(x,y,z)){
cc - try(mean(i), silent=T)
if(is(cc,try-error)) {next}
print(cc)
}
options(warn=warn)
see ?options under warn
Cheers
Dear Hrishi,
I am almost there, thanks. The only small problem left is to convince
also the colorbar to plot the values I want.
Consider the small snippet at the end of the email: colors and numbers
inside the cells are OK, but the legend shows the extremes of the log
transformed data instead of
Same trick :
c0-rbind( 1, 2 , 3, 4, 5, 6, 7, 8, 9,10,11,
12,13,14,15,16,17 )
c0
c1-rbind(10, 20 ,30,40, 50,10,60,20,30,40,50, 30,10,
0,NA,20,10.3444)
c1
c2-rbind(NA,A,NA,NA,B,NA,NA,NA,NA,NA,NA,C,NA,NA,NA,NA,D)
c2
C.df-data.frame(c0,c1,c2)
C.df
pos -
If you want a more objective eye-ball test, look at:
Buja, A., Cook, D. Hofmann, H., Lawrence, M. Lee, E.-K., Swayne,
D.F and Wickham, H. (2009) Statistical Inference for exploratory
data analysis and model diagnostics Phil. Trans. R. Soc. A 2009
367, 4361-4383 doi:
On Jun 24, 2010, at 11:38 AM, Lorenzo Isella wrote:
Dear Hrishi,
I am almost there, thanks. The only small problem left is to convince
also the colorbar to plot the values I want.
Consider the small snippet at the end of the email: colors and numbers
inside the cells are OK, but the legend
Lorenzo,
I think your question was already answered by Jan van der Laan -
http://r.789695.n4.nabble.com/Plotrix-Trick-tp2265893p2266722.html
--
View this message in context:
http://r.789695.n4.nabble.com/Plotrix-Trick-tp2267177p2267225.html
Sent from the R help mailing list archive at
Using par(new=T) is dangerous and tricky for those people who understand what
it does and how to use it. Trying to use it without fully understanding it
will be much worse.
I would use the updateusr function from the TeachingDemos package instead. The
first example on the help page may give
On 24/06/2010 11:12 AM, Paul Chatfield wrote:
On a similar issue, how can you detect a warning in a loop - e.g. the
following gives a warning, so I'd like to set up code to recognise that and
then carry on in a loop
x-rnorm(2);y-c(1,0)
ff-glm(y/23~x, family=binomial)
so this would be
I try to load a file
myData - read.csv(file=C:\\myfolder\\mysubfolder\\mydata.csv,
head=TRUE, sep=;)
and get this error:
Error in file(file, rt) : cannot open the connection
In addition: Warning message:
In file(file, rt) :
cannot open file 'C:\myfolder\mysubfolder\mydata.csv: No such file
or
Hey everyone,
I've been using 'R' long enough that I should have some idea of what the
heck either expression() or eval() are really ever useful for. I come
across another instance where I WISH they would be useful, but I cannot get
them to work.
Here is the crux of what I would
HI, GUYS,
I used the following codes to run SVM and get prediction on new data set hh.
dim(all_h)
[1] 2034 24
dim(hh)# it contains all the variables besides the variables in all_h
data set.
[1] 640 415
require(e1071)
svm.tune-tune(svm, as.factor(out) ~ ., data=all_h,
On 24.06.2010 19:02, Ralf B wrote:
I try to load a file
myData- read.csv(file=C:\\myfolder\\mysubfolder\\mydata.csv,
head=TRUE, sep=;)
and get this error:
Error in file(file, rt) : cannot open the connection
In addition: Warning message:
In file(file, rt) :
cannot open file
On Thu, Jun 24, 2010 at 10:16 AM, Mike Williamson this.is@gmail.com wrote:
Hey everyone,
I've been using 'R' long enough that I should have some idea of what the
heck either expression() or eval() are really ever useful for. I come
across another instance where I WISH they would
Thank you, Peter!
I sure love this help group!! :)
Telescopes and bathyscaphes and sonar probes of Scottish lakes,
Tacoma Narrows bridge collapse explained with abstract phase-space maps,
Some x-ray slides, a music score, Minard's Napoleanic war:
The most exciting frontier is charting
jep! I forgot to use sep= for paste and introducted a space in front
of the filename... damn, 1 hour of my life!
Ralf
2010/6/24 Uwe Ligges lig...@statistik.tu-dortmund.de:
On 24.06.2010 19:02, Ralf B wrote:
I try to load a file
myData- read.csv(file=C:\\myfolder\\mysubfolder\\mydata.csv,
On Jun 23, 2010, at 9:58 PM, Atte Tenkanen wrote:
Thanks. What I have had to ask is that
how do you test that the data is symmetric enough?
If it is not, is it ok to use some data transformation?
when it is said:
The Wilcoxon signed rank test does not assume that the data are
sampled from
Sorry to spam the list again, but I was wondering if anyone has a solution
to this. It seems that writing nulls to sockets is a pretty common use case,
so I would hope there is a way to do this.
Thanks.
On Wed, Jun 16, 2010 at 12:52 PM, Dan Tenenbaum
dtenenb...@systemsbiology.org wrote:
Hello,
Hi,
On Thu, Jun 24, 2010 at 1:22 PM, Changbin Du changb...@gmail.com wrote:
HI, GUYS,
I used the following codes to run SVM and get prediction on new data set hh.
dim(all_h)
[1] 2034 24
dim(hh) # it contains all the variables besides the variables in all_h
data set.
[1] 640 415
Hi,
I am running the following code:
mfg0 - ggplot(aes(x=Grade,y=Math,colour=RiskStatic45678),data=math.f)
mfg1 - mfg0 + geom_smooth(method=lm, formula=y ~ ns(x,2),size=1) +
geom_smooth(aes(y=nalt.math,color=NALT),size=1,data=nalt) +
scale_colour_brewer(Risk Status, pal=Set1) +
On 06/24/2010 12:40 PM, David Winsemius wrote:
On Jun 23, 2010, at 9:58 PM, Atte Tenkanen wrote:
Thanks. What I have had to ask is that
how do you test that the data is symmetric enough?
If it is not, is it ok to use some data transformation?
when it is said:
The Wilcoxon signed rank test
In the example below (or for a censored data) using survfit.coxph, can
anyone point me to a link or a pdf as to how the probabilities
appearing in
bold under summary(pred$surv) are calculated?
These are predicted probabilities that a subject who is age 60 will
still be alive. How this is
Dennis Murphy wrote:
Hi:
Does this work for you?
xyplot(distance ~ age | Sex, data = Orthodont, groups = Subject,
main = 'Individual linear regressions ~ age', type = c('g', 'r'),
panel = function(x, y, ...) {
panel.xyplot(x, y, ..., col = gray(0.5))
To whom it may concern:
I compared several R package results,
and manual checked two generalized chain block
design experiments. The correct adjusted
treatment means can be computed
by using the effects library as follows:
library(effects)
aov1 = aov(y~blocks+rows+trt)
means.aov =
Thanks again Joris - you've been very helpful J
From: Joris FA Meys [via R]
[mailto:ml-node+2267176-1824205151-120...@n4.nabble.com]
Sent: 24 June 2010 16:40
To: Paul Chatfield
Subject: Re: How to say if error
You could do that using the options, eg :
set.seed(1)
x - rnorm(1:10)
y -
¿Is'nt this just another name for multidimensional scaling?
Kjetil
On Thu, Jun 24, 2010 at 9:15 AM, Tal Galili tal.gal...@gmail.com wrote:
Isn't this what
?dist
Does ?
Tal
Contact
Details:---
Contact me:
Hello all -
This code will run, but it bogs down my computer when I run it for finer and
finer time increments and more generations. I was wondering if there is a
better way to write my loops so that this wouldn't happen. Thanks!
-Tyler
#
# Bifurcation diagram
# Using
Hello,
I'm new to R and Sweave and I was wondering whether you can just include all
your R code in external files and then call them from within the code chunks.
I've read the Sweave User Manual but I couldn't find any specific information
about this. Is this not customarily done?
Thanks,
On Thu, Jun 24, 2010 at 9:20 AM, Viechtbauer Wolfgang (STAT)
wolfgang.viechtba...@stat.unimaas.nl wrote:
The weights in 'aa' are the inverse standard deviations. But you want to use
the inverse variances as the weights:
aa - (attributes(summary(f1)$modelStruct$varStruct)$weights)^2
And then
On 24/06/2010 3:00 PM, Gaston Fiore wrote:
Hello,
I'm new to R and Sweave and I was wondering whether you can just include all
your R code in external files and then call them from within the code chunks.
I've read the Sweave User Manual but I couldn't find any specific information
about
1 - 100 of 168 matches
Mail list logo