Wonderful, David! Thank you much for your help on this.
AC
On Fri, Jul 9, 2010 at 6:49 PM, David Winsemius dwinsem...@comcast.netwrote:
On Jul 9, 2010, at 7:19 PM, Erik Iverson wrote:
AC Del Re wrote:
Hi David,
I don't have the function in order yet but the names will be going into
the
On 07/09/2010 11:29 PM, Mao Jianfeng wrote:
Dear R-help listers,
I am new. I just want to get helps on how to plot two histograms
overlapped in the same plane coordinate. What I did is very ugly.
Could you please help me to improve it? I want to got a plot with semi-
transparent overlapping
These packages were not available. Are these the only places to go for
backtesting technical trading systems other than ttrTests pls?
install.packages(quantstrat, repos=http://R-Forge.R-project.org;)
Warning in install.packages(quantstrat, repos =
http://R-Forge.R-project.org;) :
argument
Ravi Varadhan wrote:
Hi,
The absolute function stopping criterion is not meant for any positive
objective function. It is meant for functions whose minimum is 0. Here is
what David Gay's documentation from PORT says:
6 - absolute function convergence: |f (x)| V(AFCTOL) = V(31). This test
Now that I have installed R outside Program files to get past the
permissions problem, there are packages I can only access from certain
working directories:
setwd(U:/Calc/zTemp) # U: points to a USB hard drive
library(splines) # ok
library(locfdr)
Error in library(locfdr) : there is no
David Bickel wrote:
Now that I have installed R outside Program files to get past the
permissions problem, there are packages I can only access from certain
working directories:
setwd(U:/Calc/zTemp) # U: points to a USB hard drive
library(splines) # ok
library(locfdr)
Error in
Hi,
I'm trying to check a column of dates and creating indicator variables showing
different time periods.
For example, if I were to do this in Excel I would have something like:
Year to Dec 2004=IF(AND(referral dateDATE(2005,1,1), OR($closure
dateDATE(2003,12,31), LEN($closure date) = 0)),
Dear Kevin,
Assuming that closure and referral are two columns in your df and you have
already converted them to date columns.
The following should work:
df$Dec04- ifelse(df$referral 2005-01-01 df$closure 2003-12-31 |
df$closure== , Yes, No)
if you are trying to account for the column
On 09/07/10 21:19, Duncan Murdoch wrote:
On 09/07/2010 4:11 PM, Gene Leynes wrote:
I thought the apply functions are faster than for loops, but my most
recent test shows that apply actually takes a significantly longer
than a
for loop. Am I missing something?
Probably not. apply() needs
I won't add to the quite long discussion about the vagaries of nlminb, but will note that
over a long period of software work in this optimization area I've found a number of
programs and packages that do strange things when the objective is a function of a single
parameter. Some methods quite
On Jul 10, 2010, at 3:32 AM, Raghu wrote:
These packages were not available. Are these the only places to go for
backtesting technical trading systems other than ttrTests pls?
Is it possible that your install packages default for your unnamed OS
is binary or win-binary and that these
On Jul 10, 2010, at 9:29 AM, Wang, Kevin (SYD) wrote:
Hi,
I'm trying to check a column of dates and creating indicator
variables showing different time periods.
For example, if I were to do this in Excel I would have something
like:
Year to Dec 2004=IF(AND(referral dateDATE(2005,1,1),
I'd really love to do this
\setkeys{Gin}{width=\columnwidth}
label=something,fig=TRUE,echo=FALSE,width=\columnwidth,height=0.3\columnwidth=
plot(y~x)
@
The \columnwidth macro does not work, of course, in the second line.
What can I do instead?
__
Thank you, Prof. Murdoch. I have this:
.libPaths()
[1] \\Users\\dbickel/R/win-library/2.11 C:/R/R-2.11.1/library
Since the following naive line in the profile failed, I just moved the
new packages to the same directory as the default packages.
On Jul 10, 2010, at 9:42 AM, nvanzuy...@gmail.com wrote:
Dear Kevin,
Assuming that closure and referral are two columns in your df and
you have
already converted them to date columns.
The following should work:
df$Dec04- ifelse(df$referral 2005-01-01 df$closure
2003-12-31 |
On 10.07.2010 15:59, David Winsemius wrote:
On Jul 10, 2010, at 3:32 AM, Raghu wrote:
These packages were not available. Are these the only places to go for
backtesting technical trading systems other than ttrTests pls?
Is it possible that your install packages default for your unnamed OS
Hi all,
Thanks for the really great help I've received on this board in the past.
I have a very particular graph that I'm trying to plot, and I'm not really
sure how to do it. I think I should be able to use ggplot for this, but I'm
not really sure how.
I have a data.frame which contains fifty
*Hi,
I want to know how can I configure R in a Ubuntu to be a server.
I am planning to use R in a Windows machine with Tinn-R, but I want R
running at an Ubuntu Lucid machine.
How can i do this?
*Atenciosamente,
Leandro Marino
http://est.leandromarino.com.br/Blog (Estatístico)
Cel.: + 55 21
Hi,
I have a question relating to R package
If i have the frequencies of data as following
1 2 3 4 data
2 3 3 1 frequency
Which command i can use to get the data set in the above example should be
1 2 3 4
Thanks
Nada
[[alternative HTML version deleted]]
Raghu
Those packages are still not on CRAN. You can download the current
version from R-forge:
*|install.packages(blotter, repos=http://R-Forge.R-project.org;)
Mat
|*
Le 10. 07. 10 12:00, r-help-requ...@r-project.org a écrit :
Message: 137
Date: Sat, 10 Jul 2010 08:32:38 +0100
From:
Hi,
I have a question relating to R package
If i have the frequencies of data how i can get the data as following :
1 2 3 4 data
2 3 3 1 frequency
Which command i can use to get the data set in the above example should be
1 1 2 2 2 3 3 3 4
Thanks
Nada
Hi all, please see my code:
library(zoo)
a - as.yearmon(March-2010, %B-%Y)
b - as.yearmon(May-2010, %B-%Y)
nn - (b-a)*12 # number of months in between them
nn
[1] 2
as.integer(nn)
[1] 1
What is the correct way to find the number of months between a and b,
still retaining
Is this what you want:
x - c(1,2,2,2,3,3,3,4,4,5)
z - table(x)
z
x
1 2 3 4 5
1 3 3 2 1
as.integer(rep(names(z), z))
[1] 1 2 2 2 3 3 3 4 4 5
On Sat, Jul 10, 2010 at 10:55 AM, nn roh nn.r...@gmail.com wrote:
Hi,
I have a question relating to R package
If i have the frequencies of data
Do you mean just installing R on a server? I have R installed onto a
server. I ssh -X ... and everything works just fine.
On Sat, Jul 10, 2010 at 1:46 PM, Leandro Marino
leandromar...@leandromarino.com.br wrote:
*Hi,
I want to know how can I configure R in a Ubuntu to be a server.
I am
On Sat, Jul 10, 2010 at 3:17 PM, Bogaso Christofer
bogaso.christo...@gmail.com wrote:
Hi all, please see my code:
library(zoo)
a - as.yearmon(March-2010, %B-%Y)
b - as.yearmon(May-2010, %B-%Y)
nn - (b-a)*12 # number of months in between them
nn
[1] 2
as.integer(nn)
[1] 1
On Sat, Jul 10, 2010 at 3:07 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Sat, Jul 10, 2010 at 3:17 PM, Bogaso Christofer
bogaso.christo...@gmail.com wrote:
Hi all, please see my code:
library(zoo)
a - as.yearmon(March-2010, %B-%Y)
b - as.yearmon(May-2010, %B-%Y)
nn -
Thanks Gabor for your input. However my question is, is your solution
general for any value of a and b?
-Original Message-
From: Gabor Grothendieck [mailto:ggrothendi...@gmail.com]
Sent: 11 July 2010 00:42
To: Bogaso Christofer
Cc: r-help@r-project.org
Subject: Re: [R] Need help on date
On Jul 10, 2010, at 3:17 PM, Bogaso Christofer wrote:
Hi all, please see my code:
library(zoo)
a - as.yearmon(March-2010, %B-%Y)
b - as.yearmon(May-2010, %B-%Y)
nn - (b-a)*12 # number of months in between them
nn
[1] 2
as.integer(nn)
[1] 1
What is the correct way to find the
d - 1:4
f - c(2,3,3,1)
rep(d,f)
[1] 1 1 2 2 2 3 3 3 4
On Sat, Jul 10, 2010 at 10:55 PM, nn roh nn.r...@gmail.com wrote:
Hi,
I have a question relating to R package
If i have the frequencies of data how i can get the data as following :
1 2 3 4 data
2 3 3 1 frequency
On Sat, Jul 10, 2010 at 3:34 PM, Bogaso Christofer
bogaso.christo...@gmail.com wrote:
Thanks Gabor for your input. However my question is, is your solution
general for any value of a and b?
#1 and #2 are general.
For #3 I think there is a possibility you might in general have to do
the same
Hi
Dne Sat 10. of July 2010 20:46:33 Leandro Marino napsal(a):
*Hi,
I want to know how can I configure R in a Ubuntu to be a server.
I am planning to use R in a Windows machine with Tinn-R, but I want R
running at an Ubuntu Lucid machine.
How can i do this?
Install Ubuntu and set
You can do that, as well as install RKWard if you want a gui front end
and use ssh/x11 forwarding. If I think what you want to do is control a
remote ubuntu instance via windows using Tinn, I don't think that is
possible. You could look into Rserve/etc and possibly try to go that
route as
Thanks!
-N
On 7/9/10 2:20 AM, Noah Silverman wrote:
Hi,
I am trying to figure out a short way to access two values output from
the sort function.
x - c(3,4,3,6,78,3,1,2)
sort(x, index.return=T)
$x
[1] 1 2 3 3 3 4 6 78
$ix
[1] 7 8 1 3 6 2 4 5
It would be great to
On Sat, Jul 10, 2010 at 3:17 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Sat, Jul 10, 2010 at 3:34 PM, Bogaso Christofer
bogaso.christo...@gmail.com wrote:
Thanks Gabor for your input. However my question is, is your solution
general for any value of a and b?
#1 and #2 are
Hi,
I want to use singular value decompositions (SVD) to remove some artifacts
in my microarray data.
what i do is replacing the first eigenvalue to zero:
library(MASS)
data - as.matrix(read.table(data.txt, header=TRUE,row.names=1, sep =
\t, as.is = TRUE))
a.svd - svd(data)
length(a.svd$d)
186
Thomas Levine wrote:
I'd really love to do this
\setkeys{Gin}{width=\columnwidth}
label=something,fig=TRUE,echo=FALSE,width=\columnwidth,height=0.3\columnwidth=
plot(y~x)
@
The \columnwidth macro does not work, of course, in the second line.
What can I do instead?
This may be
Hello,
well, if You wish, You can always write scripts in R and then send it to
Ubuntu server, but it is too complicated. Tinn-R is Windows only, but Rkward
is IMHO much more better. You can not work in Windows in Tinn-R and send it
directly to R running on remote Linux server.
Best regards,
Yes, that's actually quite helpful.
I think this gets to the point that Patrick Burns was making in Ch. 4 of the
Inferno book. I think the sapply is breaking the problem into chunks that
make it more efficient.
This is a prototype of a function that I will probably use quite often, so
it's
What I was trying to say is that TINNR has a possibility to connect to R on
a server. I want to know if its possible to have the r in a server with
ubuntu and use it from the TINNR software.
Sent from my mobile.
Att,
Leandro Marino
http://www.leandromarino.com.br (Fotógrafo)
I don't have tinnR to test - I would suspect that this is possible,
but I may be naive.
2010/7/10 Leandro Marino leandromar...@leandromarino.com.br:
What I was trying to say is that TINNR has a possibility to connect to R on
a server. I want to know if its possible to have the r in a server
Hi all,
I have a large data set and want to immediately build a 'blind' model
without first examining the data. Now it appears in the data there are a lot
of fields that are constant or all missing values - which prevents the model
from being built.
Can someone point me the right direction as
Hi - I have a dataframe with 4 variables - long, lat, temp and year. I would
like to plot temperature by lat and long in contour plots by year. There
are 391 data points. When I try
contourplot(temp~long*lat|year,data=hake,cuts=10,labels = TRUE,contour =
TRUE,pretty = TRUE,region=TRUE)
I
You can remove NAs with:
train - subset(train, !is.na(TargetVariable))
I am not sure what you mean by constant values. You could use 'table'
to determine which values appear the most and then remove them:
x - table(train$TargetVariable)
train - subset(train, !(TargetVariable %in% names(x)[x
Hi,
The best solution would be to identify where the problem is in the FORTRAN code
and correct it. However, this problem of premature termination due to absolute
function convergence is highly unlikely to occur in practice. As John Nash
noted, this is going to be highly unlikely for
Hi Jim,
Thanks for your response, although I was probably not clear about exactly
what I want to achieve, please let me see if I can explain a little
better...
There are certain (unknown) columns in my data that contain either NULL in
every row, or the same value in every row (eg '1'). These
Is this what you want:
test - data.frame(a=runif(10), b=rep(NA, 10), c=rep(3,10), d=runif(10))
test
a b c d
1 0.3390729 NA 3 0.4346595
2 0.8394404 NA 3 0.7125147
3 0.3466835 NA 3 0.344
4 0.3337749 NA 3 0.3253522
5 0.4763512 NA 3 0.7570871
6 0.8921983 NA 3 0.2026923
Yep - that is what I want.
Cheers Jim you Legend.
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__
R-help@r-project.org
On Sat, Jul 10, 2010 at 6:28 PM, pdb ph...@philbrierley.com wrote:
Hi all,
I have a large data set and want to immediately build a 'blind' model
without first examining the data. Now it appears in the data there are a lot
of fields that are constant or all missing values - which prevents the
On 10/07/2010 10:37 AM, David Bickel wrote:
Thank you, Prof. Murdoch. I have this:
.libPaths()
[1] \\Users\\dbickel/R/win-library/2.11 C:/R/R-2.11.1/library
That first path doesn't look like it would work in Windows: it has no
drive letter, so its meaning will depend on the driver
On 10/07/2010 7:32 PM, Ravi Varadhan wrote:
Hi,
The best solution would be to identify where the problem is in the FORTRAN code
and correct it. However, this problem of premature termination due to absolute
function convergence is highly unlikely to occur in practice. As John Nash noted,
On 10/07/2010 10:35 AM, Thomas Levine wrote:
I'd really love to do this
\setkeys{Gin}{width=\columnwidth}
label=something,fig=TRUE,echo=FALSE,width=\columnwidth,height=0.3\columnwidth=
plot(y~x)
@
The \columnwidth macro does not work, of course, in the second line.
What can I do instead?
hi, i'm trying to prepend some plain (i.e. unevalutated) text to a
typographically evaluated R expression in a legend(...) call.
here's a working legend(...) call that is close to what i'd like
(where x and y are returned from an lm(...) call):
legend(topleft, legend = c(bquote(R^2 ==
On Jul 10, 2010, at 5:58 PM, Sally_roman wrote:
Hi - I have a dataframe with 4 variables - long, lat, temp and
year. I would
like to plot temperature by lat and long in contour plots by year.
There
are 391 data points. When I try
On Jul 10, 2010, at 8:58 PM, Murat Tasan wrote:
hi, i'm trying to prepend some plain (i.e. unevalutated) text to a
typographically evaluated R expression in a legend(...) call.
here's a working legend(...) call that is close to what i'd like
(where x and y are returned from an lm(...) call):
On Jul 10, 2010, at 10:45 PM, David Winsemius wrote:
On Jul 10, 2010, at 8:58 PM, Murat Tasan wrote:
hi, i'm trying to prepend some plain (i.e. unevalutated) text to a
typographically evaluated R expression in a legend(...) call.
here's a working legend(...) call that is close to what i'd
Awsome!
It made sense once I realised SD=standard deviation !
pdb
--
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http://r.789695.n4.nabble.com/eliminating-constant-variables-tp2284831p2284915.html
Sent from the R help mailing list archive at Nabble.com.
__
ok, here's a self-contained example.
topleft legend will plot 1 example of exactly what i want, but only 1
line.
bottomleft legend will plot what i had hoped would work... as it's the
logical extension of the topleft example to two cases.
dev.new()
plot.new()
plot.window(xlim = c(0, 1), ylim =
Hi, everyone,
I wrote a function, which includes an nlme estimation. The problem is
sometimes nlme may not converge due to too many random effects.
Say a, b are two parameters. if I specify random effects by:
random = a+b~1,
nlme fails to converge.
Then I have to constrain the random effects
Darn. Well here's what I'll do
%Preamble
lengths=
columnwidth=whatever the \columnwidth is
@
%Figures
\setkeys{Gin}{width=\columnwidth}
label=something,fig=TRUE,echo=FALSE,width=columnwidth,height=0.3*columnwidth=
plot(y~x)
@
It needs to be exact so that the line weight and point size are
On Jul 10, 2010, at 11:22 PM, David Winsemius wrote:
On Jul 10, 2010, at 10:45 PM, David Winsemius wrote:
On Jul 10, 2010, at 8:58 PM, Murat Tasan wrote:
hi, i'm trying to prepend some plain (i.e. unevalutated) text to a
typographically evaluated R expression in a legend(...) call.
On Jul 10, 2010, at 11:39 PM, Jun Shen wrote:
Hi, everyone,
I wrote a function, which includes an nlme estimation. The problem is
sometimes nlme may not converge due to too many random effects.
Say a, b are two parameters. if I specify random effects by:
random = a+b~1,
nlme fails to
well, figured it out, apparently placing the bquote results in a
vector doesn't result in a vector of expressions, so you have to
coerce it like so:
dev.new()
plot.new()
plot.window(xlim = c(0, 1), ylim = c(0, 1))
legend(topleft, legend = bquote(paste(foo bar , R^2 == .(2^2))),
fill = red)
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