Hi,
I am trying to assemble a three-way contingency table examining the
presence/absence of mussels, water depth (Depth1 and Depth 2) and water
velocity (Flow vs. No Flow). I have written the following code listed below;
however, when run the glm I get the following message, Error in
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
https://stat.ethz.ch/mailman/listinfo/r-help
At the bottom of the webpage.
-c
On 08/29/2010 03:58 AM, Kaigang Li wrote:
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
pbrbrbr/p
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented,
Hi,
I have a data.frame with factors in columns like
startdate enddate
27SEP2005 01JAN2006
How can I calculate the duration between those two dates and move this in a
extra column in the data.frame.
Thanks,
André
[[alternative HTML version deleted]]
Try this:
x
startdate enddate
1 27SEP2005 01JAN2006
x$start - as.Date(x$startdate, format=%d%b%Y)
x$end - as.Date(x$enddate, format=%d%b%Y)
x
startdate enddate startend
1 27SEP2005 01JAN2006 2005-09-27 2006-01-01
x$duration - x$end - x$start
x
startdate enddate
Hi Greg,
Thanks for your advice.
data(women)
women
height weight
1 58115
2 59117
3 60120
4 61123
5 62126
6 63129
7 64132
8 65135
9 66139
10 67142
11 68146
12 69150
13 70154
14
Hi David,
Thanks for your advice.
B.R.
Stephen L
- Original Message
From: David Winsemius dwinsem...@comcast.net
To: Stephen Liu sati...@yahoo.com
Cc: r-help@r-project.org r-help@r-project.org
Sent: Sun, August 29, 2010 1:52:50 AM
Subject: Re: [R] About plot graphs
On Aug 28, 2010,
Hi,
Your example works fine for me. My guess is that you have one of wd,
wv, MP, or Count defined as a global variable. This is the main reason
the use of attach() is discouraged by many people on this list. The
safer thing to do is
model1 - glm(Count~MP+wd+wv,poisson. data = frame)
-Ista
On
Hi,
Sorry for this simple question but I searched the internet and can't find
the answer.
From a date I want the year extracted:
data$start[1
[1] 2006-11-01
Thanks for the answer,
Andre
[[alternative HTML version deleted]]
__
Try this:
format(data$start, %Y)
On Sun, Aug 29, 2010 at 11:32 AM, André de Boer rnie...@gmail.com wrote:
Hi,
Sorry for this simple question but I searched the internet and can't find
the answer.
From a date I want the year extracted:
data$start[1
[1] 2006-11-01
Thanks for the
The likelihood ratio test is more reliable when one model is nested in the
other. This true for your case.
AIC/SBC are usually used when two models are in a hiearchical structure.
Please also note that any decision made made based on AIC/SBC scores are
very subjective since no sampling
The likelihood ratio test is more reliable when one model is nested in the
other. This true for your case.
AIC/SBC are usually used when two models are in a hiearchical structure.
Please also note that any decision made
made based on AIC/SBC scores are very subjective since no sampling
I didn't see any error when I ran your code in my computer:
numbers - c(1134,956,328,529,435,599,27,99)
dim(numbers) - c(2,2,2)
numbers
, , 1
[,1] [,2]
[1,] 1134 328
[2,] 956 529
, , 2
[,1] [,2]
[1,] 435 27
[2,] 599 99
dimnames(numbers)[[3]] -list(Mussels, No
My suggestion:
If compare model 1 and model 2 with model 0 respectively, the (penalized)
likelihood ratio test is valid.
IF you compare model 2 with model 3, the (penalized) likelihood ratio test
is invalid. You may want to use AIC/SBC to make a subjective decision.
--
View this message in
My suggestion for Teresa:
If compare model 1 and model 2 with model 0 respectively, the (penalized)
likelihood ratio test is valid.
IF you compare model 2 with model 3, the (penalized) likelihood ratio test
is invalid. You may want to use AIC/SBC to make a subjective decision.
--
View this
Hi, all
I made a simple R script to take the basename of a file without directory
names.
path.splitted - strsplit('/path/to/a_basename', '/')
path.length - length(path.splitted[[1]])
basename - path.splitted[[1]][path.length] # basename - 'a_basename'
Is there a simple function for this?
Take a look on ?basename help page.
On Sun, Aug 29, 2010 at 12:07 PM, Hyunchul Kim
hyunchul.kim@gmail.comwrote:
Hi, all
I made a simple R script to take the basename of a file without directory
names.
path.splitted - strsplit('/path/to/a_basename', '/')
path.length -
Hi, all
I want to take a vector of component names of a list.
list.a - list('x'=1, 'y'=2)
how to get a c('x','y') from list.a?
Thanks in advance,
Hyunchul
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Try this:
names(list.a)
On Sun, Aug 29, 2010 at 12:51 PM, Hyunchul Kim
hyunchul.kim@gmail.comwrote:
Hi, all
I want to take a vector of component names of a list.
list.a - list('x'=1, 'y'=2)
how to get a c('x','y') from list.a?
Thanks in advance,
Hyunchul
[[alternative
Hy,
I had a mistake on a function of a package i have created!
I have solved it and then i repackaged and installed the modified package.
I use to launch R from Excel!
And so when i launch R, and next call my function from the workspace, i
still find the problem on my function.
And when i read on
check at the online help file of function ?names(), and then try this:
names(list.a)
I hope it helps.
Best,
Dimitris
On 8/29/2010 5:51 PM, Hyunchul Kim wrote:
Hi, all
I want to take a vector of component names of a list.
list.a- list('x'=1, 'y'=2)
how to get a c('x','y') from list.a?
On Aug 28, 2010, at 10:58 PM, Randklev, Charles wrote:
Hi,
I am trying to assemble a three-way contingency table examining the
presence/absence of mussels, water depth (Depth1 and Depth 2) and
water velocity (Flow vs. No Flow). I have written the following code
listed below; however,
Hello all.
A Journal we are sending an article to is asking for the following:
To ensure the best reproduction quality of your figures we would appreciate
high resolution files. All figures should preferably be in TIFF or EPS
format... and should have the following resolution: Graph: 800 - 1200
Hey!
Just a quick question:
How do you interpret cross-validation error?
For my model the function cv.glm returns a cross validation error of 0.31
does this mean to say that model has an accuracy of 0.69
(69 Percent of points are correctly classified)?
Thanks,
Mark
--
View this message
Hi there,
Ive tried trawling the lists for a solution but I could not find any
matches. I am typing up all my code on a Linux machine and I call this
other script file from my script file using source(foo.r). Now sometimes
i access my folder from my Windows machine at work (the files are on
On Sun, Aug 29, 2010 at 5:46 PM, Tal Galili tal.gal...@gmail.com wrote:
Hello all.
A Journal we are sending an article to is asking for the following:
To ensure the best reproduction quality of your figures we would appreciate
high resolution files. All figures should preferably be in TIFF
Hello everyone,
I have been trying to figure out away to integrate under a spline produced
by the package tps(fields). As the package does not output functions I am
trying to do something similar to the trapezium rule. My data are 3D (x, y
z). I have extracted from the surface output by Tps the
Hi Tal,
You have set the resolution, but you have not set the width/height.
The res argument generally controls how many pixels per inch (PPI
which is often used similarly to DPI). So if you want 800 DPI and you
want it to be a 4 x 4 inch graph something like:
tiff(file = temp.tiff, width =
glm(A~B+C+D+E+F,family = binomial(link = logit),data=tre,na.action=na.omit)
Error in `contrasts-`(`*tmp*`, value = contr.treatment) :
contrasts can be applied only to factors with 2 or more levels
however,
glm(A~B+C+D+E,family = binomial(link = logit),data=tre,na.action=na.omit)
runs fine
On Aug 29, 2010, at 12:46 PM, Tal Galili wrote:
Hello all.
A Journal we are sending an article to is asking for the following:
To ensure the best reproduction quality of your figures we would
appreciate
high resolution files. All figures should preferably be in TIFF or EPS
format... and
On Aug 29, 2010, at 3:13 PM, moleps wrote:
glm(A~B+C+D+E+F,family = binomial(link =
logit),data=tre,na.action=na.omit)
Error in `contrasts-`(`*tmp*`, value = contr.treatment) :
contrasts can be applied only to factors with 2 or more levels
however,
glm(A~B+C+D+E,family = binomial(link =
On Sun, Aug 29, 2010 at 1:13 PM, Abhisek shi...@gmail.com wrote:
Hi there,
Ive tried trawling the lists for a solution but I could not find any
matches. I am typing up all my code on a Linux machine and I call this
other script file from my script file using source(foo.r). Now sometimes
i
On Aug 29, 2010, at 3:42 PM, sam.e wrote:
Hello everyone,
I have been trying to figure out away to integrate under a spline
produced
by the package tps(fields). As the package does not output functions
I am
trying to do something similar to the trapezium rule. My data are 3D
(x, y
Using a p-value to make any kind of decision is questionable to begin
with, and especially unreliable in choosing covariates in regression.
Old studies, e.g. by Walls and Weeks and by Bendel and Afifi, have shown
that if predictive ability is the criterion of interest and one wishes
to use
Hi
the two models are identical because of having the same independent
variable and dependent variable.they produce different termplot()s because
of they base on different variables,one is x,the other is logx.see the
lateral axis.
Sure; this is all obvious from the code and the plots.
CRAN (and crantastic) updates this week
New packages
* ProjectTemplate (0.1-2)
Maintainer: John Myles White
Author(s): John Myles White
http://crantastic.org/packages/ProjectTemplate
The ProjectTemplate package provides a function, create.project(),
that automatically
Is there a simple way to put a legend outside the plot area for a simple
plot?
I found... (at http://www.harding.edu/fmccown/R/)
# Expand right side of clipping rect to make room for the legend
*par(xpd=T, mar=par()$mar+c(0,0,0,4))*
# Graph autos (transposing the matrix) using heat colors,
#
I'm trying to run an epsilon regression model, and am comparing the results
between e1071 and kernlab. I believe that I'm calling the ksvm and svm
functions the same way but I'm getting different results:
library(e1071); library(kernlab)
ksvm(x=1:100, y=(1:100)/5, type=eps-svr,
Hi,
On Aug 29, 2010, at 8:00 PM, Worik R wrote:
Is there a simple way to put a legend outside the plot area for a
simple
plot?
I found... (at http://www.harding.edu/fmccown/R/)
# Expand right side of clipping rect to make room for the legend
*par(xpd=T, mar=par()$mar+c(0,0,0,4))*
#
On Aug 26, 2010, at 7:10 PM, Peter Dunn wrote:
Hi all
I was playing with termplot(), and came across what appears to be an
inconsistency.
It would appreciate if someone could enlighten me:
# First, generate some data:
y - rnorm(100)
x - runif(length(y),1,2)
# Now find the log of x:
All,
I have been trying to get calls to hist(...) to be plotted
with the y-axis having a log scale.
I have tried: par(ylog=TRUE)
I have also looked at the histogram package.
Suggestions welcome.
--
Derek M. Jones tel: +44 (0) 1252 520 667
Knowledge Software Ltd
How about computing the log of you variable and calling hist() on the log data.
logy - log(y)
Hhist(logy)
John
John Sorkin
Chief Biostatistics and Informatics
Univ. of Maryland School of Medicine
Division of Gerontology and Geriatric Medicine
jsor...@grecc.umaryland.edu
-Original
Hello
all,
Is
there a complete list of Sweave tags (control sequences) and their usage? For
instance,
I know a few blow. But I donât really know how to use them. It seems to me
that
there is nowhere to find further information. I would really appreciate any
input. Thanks!
Heyi
Â
The
Hi Derek,
Here is an option using the package ggplot2:
library(ggplot2)
x - sample(x = 10:50, size = 50, replace = TRUE)
qplot(x = x, geom = histogram) + scale_y_log()
However, the log scale is often inappropriate for histograms, because
the y-axis represents counts, which could potentially be
I'm a newbie to R and I was hoping someone could answer a simple question. I
want to read in an ASCII file with 3 columns - x,y,z. Let's say there is a lot
of data - 100,000 entries. I then want to histogram x values that pass
arbitrary (and complicated) cuts on y and/or z. Likewise, I
Hi Guys,
stumped by a simple problem. I would like to take a file of the form
Pair group param1
1 D 10
1 D 10
1 R 10
1 D 10
2 D 10
2 D 10
2 D 10
2
Eh?
## First calculate the means:
mns - with(alldata, tapply(param1, list(Pair, group), mean))
## now put the results into a data frame
res - data.frame(mns, dif = mns[, D] - mns[, R])
## Then write it out if that's your thing.
-Original Message-
From: r-help-boun...@r-project.org
Hi Marcel,
Not quite sure what you want the while loop for. Does this do what you want?
mydat - read.table(textConnection(
Pair group param1
1 D 10
1 D 10
1 R 10
1 D 10
2 D 10
2
On Aug 29, 2010, at 10:50 PM, Erik Ramberg wrote:
I'm a newbie to R and I was hoping someone could answer a simple
question. I want to read in an ASCII file with 3 columns - x,y,z.
Let's say there is a lot of data - 100,000 entries. I then want to
histogram x values that pass
Hi all, I am working on exporting Johansen test statistics (Johansen test:
ca.jo in package urca)to Excel. The problem is that the function output
is not a number, but like this:
#
# Johansen-Procedure Unit Root / Cointegration Test #
Hi,
I have the following matrix
cc - matrix (1:21, 3)
cc[,3:4]- 0
cc
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[1,]1400 13 16 19
[2,]2500 14 17 20
[3,]3600 15 18 21
and I would like to sum just the values in columns
On Aug 30, 2010, at 12:57 AM, David Winsemius wrote:
On Aug 29, 2010, at 10:50 PM, Erik Ramberg wrote:
I'm a newbie to R and I was hoping someone could answer a simple
question. I want to read in an ASCII file with 3 columns - x,y,z.
Let's say there is a lot of data - 100,000 entries.
What statistical measure(s) tend to be answering ALL(?) question of practical
interest?
--
View this message in context:
http://r.789695.n4.nabble.com/Re-Question-regarding-significance-of-a-covariate-in-a-coxme-survival-tp2399386p2399524.html
Sent from the R help mailing list archive at
Dear list
I used to use python or awk do preliminary process and then feed into
R. In some circumstances, the data transmission becomes quite a pain.
I am wondering if there is a convenient way to read in R text file
(not data, text file in common sense) and specify field separator and
records
Hi,
I believe what you are looking for is in the teststat slot
sjd.v...@teststat
sjd.v...@teststat[1] # first one
etc.
HTH,
Josh
On Sun, Aug 29, 2010 at 9:12 PM, aurumor aurum_g...@yahoo.com.hk wrote:
Hi all, I am working on exporting Johansen test statistics (Johansen test:
ca.jo in
Dear Guys,
I do converting codes from Fortran into R and got stuck in solving LOOPING
procedure with R. In FORTRAN, it is (DO and END DO) for looping in the net.
In R, it is (FOR with { }).
I believe there is something wrong with my coding in R, do hope that you can
help me solving following
On Sun, Aug 29, 2010 at 9:18 PM, Yong Wang wangyo...@gmail.com wrote:
Dear list
I used to use python or awk do preliminary process and then feed into
R. In some circumstances, the data transmission becomes quite a pain.
I am wondering if there is a convenient way to read in R text file
(not
On Aug 30, 2010, at 12:18 AM, Yong Wang wrote:
Dear list
I used to use python or awk do preliminary process and then feed into
R. In some circumstances, the data transmission becomes quite a pain.
I am wondering if there is a convenient way to read in R text file
(not data, text file in
On Aug 29, 2010, at 8:47 PM, Lorenzo Cattarino wrote:
Hi,
I have the following matrix
cc - matrix (1:21, 3)
cc[,3:4]- 0
cc
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[1,]1400 13 16 19
[2,]2500 14 17 20
[3,]3600 15 18 21
60 matches
Mail list logo