I think you should have a look at the 'proto' package on CRAN.
Yvonnick Noel
University of Brittany, Rennes
France
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PLEASE do read the posting guide
Hi all-
this seems to be simple to figure out but since im new to writing functions
I dont know what is happening. Here is my code along with the error I am
receiving:
semivario=function(data,ids,times,resids){
id=unique(data$ids)
index=combinations(length(data$times[data$ids==id[1]]),2)
Hi,
I would like to plot a bunch of tree ring width data (time series)
using ggplots, but I'm having trouble figuring out how to do it.
My data is in a data.frame, with years as rownames and a distinct tree
ring series in each column. So, something like this:
rwl-matrix(rnorm(800), nrow =
Dear R-help-list
I have two character vectors
a - c(A, B, C)
b - c(A, C, B)
Then
sapply(a, function(i) grep(i, b))
computes the permutation of the entries in 'b' needed
to bring 'b' into the same order as 'a'.
I have searched around, but haven't been able to find
any existing function that
On Wed, 2010-09-15 at 08:25 -0700, dadrivr wrote:
Thanks for your help, guys. I'm looking to produce a high-quality plot (no
jagged lines or other distortions) with a filetype that is accepted by
Microsoft Word on a PC and that most journals will accept. That's why I'd
prefer to stick with
Dear Alison,
Creating a dataset in long format instead of wide format makes things
much easier with ggplot2. You also need a variable with Year. Rownames
will not do.
rwl - matrix(rnorm(800, 1, sd =0.5), nrow = 100)
colnames(rwl) - paste('V', 1:8, sep = '')
rwl - as.data.frame(rwl)
rwl$Year -
Here's a way with less code...
# assume original matrix is X
u - unique( sort(X) )
ucdf - cumsum( tabulate(X)[u] )
Xcdf - matrix(ucdf[ match(X, u) ], 8)
Michael
On 16 September 2010 14:58, chuan zun liang chuan...@yahoo.com.my wrote:
Hello Friend:
Thanks a lot. I kindly told that Micheal
The calculation of semivraiogram is allready implemented is many R
packages. So why do it yourself?
library(sos)
findFn(variogram)
Gives you 190 hits!
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team
@Thierry-
I am writing my own semivariogram code since I could not find a pre-made
function that did what I need it do. The code in the function correctly
works but I not sure how to get the function itself to work. In other words
if I fill in the commands (hope,id,sctime,scResid) by hand then
Hi, I was trying to split the following matrix dat:
set.seed(1)
dat - matrix(rnorm(4*16), 4, 16)
dat
[,1] [,2] [,3][,4][,5][,6]
[,7] [,8][,9] [,10] [,11]
[1,] -0.6264538 0.3295078 0.5757814 -0.62124058 -0.01619026
Hi,
I'm trying to read a .mat file into R (2.11.1) with medium success so far. The
file I have is a MATLAB 5.0 MAT-file exported from RiverSurveyor LIVE software
(http://www.sontek.com/software.php). I have R.matlab and Rcompression
installed and readMat() starts reading the file, as can be
Actually I tried in both ways : yum install R and sudo yum install R ,
but the error is same. I have root privilege, means I used the command su -
and enter the password. May be its problem from Fedora. Thanks for your
valuable help. I will post this issue in R-SIG-Fedora list.
Kind
Here is one possibility:
set.seed(1)
dat - matrix(rnorm(4*16), 4, 16)
dim(dat) - c(4,4,4)
dat
, , 1
[,1] [,2] [,3][,4]
[1,] -0.6264538 0.3295078 0.5757814 -0.62124058
[2,] 0.1836433 -0.8204684 -0.3053884 -2.21469989
[3,] -0.8356286 0.4874291 1.5117812
match(b, a) ?
Michael
On 16 September 2010 17:13, Niels Richard Hansen
niels.r.hansen+li...@math.ku.dk wrote:
Dear R-help-list
I have two character vectors
a - c(A, B, C)
b - c(A, C, B)
Then
sapply(a, function(i) grep(i, b))
computes the permutation of the entries in 'b' needed
to
Hi all,
After a bit of offlist correspondence, the problem with feather.plot was
found to be with the input data format (lists) and the particular data
revealed a bug in the function. A fix for the bug and a warning about
lists as input will be in the next version of plotrix (3.0-1).
Jim
match(b, a) ?
Michael
Right! Thanks, Michael.
On 16 September 2010 17:13, Niels Richard Hansen
niels.r.hansen+li...@math.ku.dk wrote:
Dear R-help-list
I have two character vectors
a - c(A, B, C)
b - c(A, C, B)
Then
sapply(a, function(i) grep(i, b))
computes the permutation of
On 09/16/2010 12:05 PM, rusers.sh wrote:
Hi all,
I want to put several figures in a one figure for easy comparison, so i
need to use the same methods to plot these figures. The following is an
example. I also list my method, but it does not work.
#Example data
x- 1:10; y- 1:10; z- outer(
Dear fellows,
I am a novice in R. I would like to combine a matrix and a vector. Assume
that we have the matrix a and the vector b with same length of column.
a-matrix(seq(1:10),nrow=2,ncol=5,byrow=TRUE)
a=
12345
6789 10
b-t(c(11,12,13,14,15))
b=
11 12 13 14
Hi!
Take a look at rbind()
Btw, I don't think you have to transpose b.
HTH,
Ivan
Le 9/16/2010 11:09, Wonsang You a écrit :
Dear fellows,
I am a novice in R. I would like to combine a matrix and a vector. Assume
that we have the matrix a and the vector b with same length of column.
Dear Henrik and Steven,
Thank you for your kind help and guidance even though it is a basic
question. I misunderstood that gunzip is a part of not R.utils but
utils. I could find out the function in R.utils. Then, it was successful
to decompress any gz file as follows.
library(R.utils)
Dear Tony,
A mixed models is not a good idea if you have only two levels for sites and two
times two for phase.
The first problem is a mathematical problems. You are estimating variances
based on only two and four values. Which is very small, hence you will not get
reliable estimates of the
you are welcome. Henrik's package is an great piece of work. It is worth
the time to read through the whole thing and see how you can improve your
programs by using other features as well.
On Thu, Sep 16, 2010 at 2:16 AM, Wonsang You y...@ifn-magdeburg.de wrote:
Dear Henrik and Steven,
Thank
Hello,
why you don't use the last 3 arguments?
semivario=function(data,ids,times,resids){
id=unique(data$ids)
...
It seems data be a list. In that case the last 3 arguments are useless.
Could you please send us a runable code example. That means some example data
and your all neede functions
Hello,
I am also facing exactly same problem like Mike while compiling R on AIX 5.3
Error in read.dcf(file = descfile) :
Line starting 'Package: tools ...' is malformed!
Calls: makeLazyLoading ... code2LazyLoadDB - loadNamespace -
parseNamespaceFile - read.dcf
Execution halted
My Environment
On 15.09.2010 17:40, Gregory Ryslik wrote:
Hi,
That seems to be the case. Is there a way that I can put an object in some
global place where all the workers can access it?
Doing the following at the start (before I make multiple workers) does not work:
Assign('global.control', control,
stephen sefick wrote:
I will get R-dev tomorrow, and give it a try. Where do I check out the svn?
https://svn.r-project.org/R/trunk
The fixed files are in .../src/library/stats/R and are approx.R,
spline.R and splinefun.R. The only one that affects your report is
approx.R.
Duncan
Hello I have some strange output from R and I try to understand how R works.
Could you please help me with that?
temp - rbind (c(10,1),c(99,98))
temp
[,1] [,2]
[1,] 101
[2,] 99 98
dist(temp)
1
2 131.6435
sqrt(dist(temp))
1
2 11.47360
so far so good.
Checking on the function 'combinations' in gplot i find this:
if (mode(n) != numeric || length(n) != 1 || n 1 || (n%%1) !=
0)
stop(bad value of n)
So essentially, the argument 'length(data$times[data$ids == id[1]])' in the
line
'combinations(length(data$times[data$ids ==
Hi,
This is a bug of tre-regex(AIX 64bit only).
following patches help you.
https://r-forge.r-project.org/scm/viewvc.php/patches/aix_R210_tre.patch?view=markuproot=aix
2010/9/16 Balkrishna Ketkar bket...@gmail.com:
Hello,
I am also facing exactly same problem like Mike while compiling R on
Hello Alex,
Look at the help page for the dist function. You'll see it doesn't
return a simple vector or matrix, rather a dist class object which
is why you got a surprise when you tried to treat it like a simple
value. The function is not really intended for spatial point distance
calculations,
Hi Alex,
What is happening is that the ´dist´function calculates a distance matrix,
and returns an object of the ´dist´ class.
temp - rbind (c(10,1),c(99,98))
x=dist(temp)
x
1
2 131.6435
class(x)
[1] dist
You can see a description of the ´dist´class at the end of the function´s
I fixed by adding this:
k - sqrt(dist(temp))
k returns sort of a list. So I need to select the first item which is the
result.
a - k[1]
Can someone explain me why k[1] is needed for that?
Best Regards
Alex
From: Mario Valle mva...@cscs.ch
Sent: Thu,
The question is wehter cat() can print out a matrix as it is. For example,
Let's assume that we have matrices A, B, D(= A+B), if it is possible that
cat(\n, A, +,B,=, D, some control arguments , \n)
prints out
matrix A + matrix B = matrix D
where matrices A, B, D (= A+B) should be in the
print(k) and you see a lower triangular distance matrix.
k[1] selects distances between 1 and 2
k[2] selects distances between 1 and 3 and so on.
you have a distance matrix, not a single distance value, so you have to
select which distance you need.
Ciao!
mario
On
Hello together,
I am an absolute noob in R and therefore I need help urgently. I have
received a script from my tutor with plot functions in it. However, I can'
manage to adapt these plots.
The hole script is as follows:
setwd(E:/)
# (1) Read data ###
dat -
On Sep 16, 2010, at 4:23 AM, Michael Bedward wrote:
match(b, a) ?
Or just order(.) :
b[order(a)]
[1] A C B
--
David
Michael
On 16 September 2010 17:13, Niels Richard Hansen
niels.r.hansen+li...@math.ku.dk wrote:
Dear R-help-list
I have two character vectors
a - c(A, B, C)
b - c(A,
Dear readers,
The problem is simple: I have weekly time series data with a maximum
week number of (52,53,52,52) in (2008,2009,2010,2011) respectively. That
means I have a dataset looking like this:
2008-01 value
2008-02 value
.
.
2011-52 value
And I would like to turn that data into a plotable
Hi,
Take a look at ?par, all the arguments for the plot() function are
described there. Check in particular ylim, xlab and ylab
HTH,
Ivan
Le 9/16/2010 14:45, strampe a écrit :
Hello together,
I am an absolute noob in R and therefore I need help urgently. I have
received a script from my
Thanks for the help
I have tried the one that uses xtab() and the answer is correct because when I
was using the rbind() still getting the same error messageâ¦
Now I have some more questions â¦
I am trying to be able to adapt this for any kind of data of the same structure
so now im
A few days ago Tal Galili posted a message about some controversies
concerning the future of R. Having read the discussions, especially those
following Ross Ihaka's post, I have come to the conclusion, that, as usual,
the problem is money. I doubt there would be discussions about dropping R in
Dear readers,
The problem is simple: I have weekly time series data with a maximum
week number of (52,53,52,52) in (2008,2009,2010,2011) respectively. That
means I have a dataset looking like this:
2008-01 value
2008-02 value
.
.
2011-52 value
And I would like to turn that data into a plotable
Hello Petr,
If you want to get results of your function for a vector of reynolds and
dk you can use function outer and probably get rid of for cycle in the
function.
outer(c(100, 530,2410), c(10, 150,200),lambda_wall)
[,1] [,2] [,3]
[1,] 0.640 0.6400
On 15.09.2010 17:06, Tao wrote:
Thanks. It seems that both Rtools210.exe and Rtools211.exe support R 1.10.x,
which one is better for R 2.10.1.
You can use both, but you may want to choose the newer one.
Uwe
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R-help@r-project.org mailing list
I am a poor student, and would gladly donate 20ish bucks if it would
help. R continues to make me more productive. Thanks for all of the
good work!
On Thu, Sep 16, 2010 at 5:49 AM, jaropis jaro...@zg.home.pl wrote:
A few days ago Tal Galili posted a message about some controversies
concerning
On 16/09/2010 6:49 AM, jaropis wrote:
A few days ago Tal Galili posted a message about some controversies
concerning the future of R. Having read the discussions, especially those
following Ross Ihaka's post, I have come to the conclusion, that, as usual,
the problem is money. I doubt there
Hi,
We have some tight controls in our systems and I am having difficulty
downloading/upgrading R packages. The IT department will configure our
system to let me download packages from two or three R depositories.
How do I find out what the IP address of the R depositories are so that
I can
I mailed a check for an R Foundation membership almost a year ago, along
with the form. In US dollars, corrected by the then-current Euro
exchange rate. It has never been cashed.
Christopher W. Ryan, MD
SUNY Upstate Medical University Clinical Campus at Binghamton
425 Robinson Street,
Hello,
I've been unsuccessfully trying to reproduce a sem from Grace et al.
(2010) published in Ecological Monographs:
http://www.esajournals.org/doi/pdf/10.1890/09-0464.1
The model in question is presented in Figure 8, page 81. The errors
that I've been getting are:
1. Using a correlation
Hi all,
Please consider the following code:
require(plotrix)
l - list(rnorm(50),rnorm(50,sd=2),rnorm(50,mean=3))
multhist(l)
I have two things I need help with:
(1) In the output, there are empty spaces on the x-axis. How would I eliminate
these spaces? I want a nice, smooth,
I cannot speak for the R Foundation, but you know, getting a US check
into money is roughly 20$ fees (at least in Germany, don't know the
typical Austrian conditions).
I know from organizing a conference in Germany that the only really good
way was and is ordinary money transfer via BIC and
I hope to revive this topic. I have the same error message when I try to
install any package.
Many thanks upfront!
--
View this message in context:
http://r.789695.n4.nabble.com/error-in-2-10-R-include-directory-is-empty-prevents-package-installation-tp907110p2542306.html
Sent from the R help
Dear all,
I've discovered the possibility to do the Nemenyi-Damico-Wolfe-Dunn test in the
library(coin); oneway_test()
With the given example I am unfortunately not able to reproduce the test. What
does trafo and contrMat mean?
I have a dataframe with 176 elements in 7 classes. It may be a
Josh-
The link you included with your post provides the code for the example plot.
Simply click on the icon in the Download Source Code section.
I think you'll be able to learn a lot by playing with that source code.
-tgs
On Thu, Sep 16, 2010 at 9:40 AM, Josh B josh...@yahoo.com wrote:
Hi
Jorge Nieves jorge.nieves at moorecap.com writes:
Hi,
We have some tight controls in our systems and I am having difficulty
downloading/upgrading R packages. The IT department will configure our
system to let me download packages from two or three R depositories.
How do I find out
Hi Josh,
You can go to http://addictedtor.free.fr/graphiques/sources/source_55.R and
see the source code there. Now, if you want to run the example directly from
the R console, something along the lines of
source('http://addictedtor.free.fr/graphiques/sources/source_55.R')
might work.
HTH,
Hi,
I have problems downloading complete folders via ftp with R. Single files
work fine.
I tried Rcurl, but it does not work.
This is my code:
url =
ftp://disc2.nascom.nasa.gov/data/TRMM/Gridded/Derived_Products/3B42_V6/Daily/2009/;
filenames = getURL(url, ftp.use.epsv = FALSE, ftplistonly =
Thank you so much for your help. It was successful to combine matrix and
vector by using rbind as follows.
a-matrix(seq(1:10),nrow=2,ncol=5,byrow=TRUE)
a
[,1] [,2] [,3] [,4] [,5]
[1,]12345
[2,]6789 10
b-t(c(11,12,13,14,15))
b
[,1] [,2] [,3]
Try this:
mapply(download.file, filenames, basename(filenames))
On Thu, Sep 16, 2010 at 11:56 AM, Martin mar...@bier-mail.de wrote:
Hi,
I have problems downloading complete folders via ftp with R. Single files
work fine.
I tried Rcurl, but it does not work.
This is my code:
url =
works, thanks a lot!
--
View this message in context:
http://r.789695.n4.nabble.com/FTP-Download-tp2542359p2542380.html
Sent from the R help mailing list archive at Nabble.com.
__
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On 2010-09-16 8:31, Anne-Christine Mupepele wrote:
Dear all,
I've discovered the possibility to do the Nemenyi-Damico-Wolfe-Dunn test in the
library(coin); oneway_test()
With the given example I am unfortunately not able to reproduce the test. What
does trafo and contrMat mean?
I have a
Hello everybody,
I am using plot.fmri function to plot some stats on a functional image, but
for some reasons the only collor I get on the image is gray.
Here is the function I am
using:plot.fmridata(t1,type=slice,col.o=heat.colors(256))
It is the first time I am using this package, so I
Hi all,
I'm having trouble saving graphics output from within a loop, and I
can't figure out a solution. I'd like to produce and save lots of
individual plots for inspection, so I set up the following script:
library( lattice )
wd = ~/Documents/PPM/
ppm = read.table( paste( wd,
Hello David and Greg,
Thank you for your suggestions. These really help me.
I'm curious about txtStart function of TeachingDemos library. It looks
exactly what I need.
So I installed TeachingDemos library and tried following.
-
library(TeachingDemos)
setwd(/Users/NOBU/Documents/R_data/)
First I have a matrix called stocks1:
class(stocks1)
[1] matrix
Here are the first 5 rows of the last 4 columns:
stocks1[1:5,2:5]
[,1] [,2] [,3] [,4]
[1,] 80.73 31.95 25.4 25.69
[2,] 83.66 31.95 27.12 25.2
[3,] 83.27 32.93 28.74 26.29
[4,] 83.9 34.07 29.77 26.6
[5,]
See the FAQ 7.22 Why do lattice/trellis graphics not work?
The most likely reason is that you forgot to tell R to display the graph.
Lattice functions such as xyplot() create a graph object, but do not display
it (the same is true of
*ggplot2*http://cran.r-project.org/package=ggplot2graphics, and
Hi,
I was trying to install R in my home directory on a Mac OS X Server running
Darwin. How do I go about installing it? How can I install from the binary
provided (R-2.11.1.pkg) from command line?
Is there any other information that I can provide?
thanks
[[alternative HTML
Use as.data.frame instead. It does what you want it to do.
newdata.df-as.data.frame(stocks1[1:5,2:5])
Cheers,
Michael
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Leigh E. Lommen
Sent: 16. september 2010 17:18
To:
Hi,
Well, it works for me:
x - matrix(1:20, nrow=5, ncol=4)
data.frame(x[1:5,2:4])
X1 X2 X3
1 6 11 16
2 7 12 17
3 8 13 18
4 9 14 19
5 10 15 20
Maybe with as.data.frame(), or set the drop argument to FALSE:
data.frame(x[1:5,2:4,drop=FALSE])
Not sure why it doesn't work for you. Check
Got it, thanks!
On Thu, Sep 16, 2010 at 10:22 AM, RICHARD M. HEIBERGER r...@temple.eduwrote:
See the FAQ 7.22 Why do lattice/trellis graphics not work?
The most likely reason is that you forgot to tell R to display the graph.
Lattice functions such as xyplot() create a graph object, but do
Dear All,
I have a function:
gen - function(m){for(i in 1:m){assign(paste(x,i, sep=),
(7*get(paste(x,i-1,sep=)))%%13); print(get(paste(x, i, sep=)))}}
my question is, I do gen(20), then the function prints out 20 values,
however when I do objects(), I can't see x1,x2,x3,,x20 as objects.
Hi, is there an R function like sql's TOP key word?
I have a dataframe that has 3 columns: company, person, salary
How do I get top 5 highest paid person for each company, and if I have
fewer than 5 people for a company, just return all of them?
Thanks,
Richard
dear list,
i am using a multifactorial design with two treatments (factor A: drugs,
three levels; factor B: theraphy, two levels) and a time factor (three
levels, different timepoint). hypothetically, i measured the same subjects
for all treatements and timepoints, so its a repeated measurement
Leaving aside the question of whether this is a good thing to do, you
can accomplish what you want by changing the pos argument, which
by default does not save the variable to the global environment.
Reading the details section of ?assign and also ?environment may help.
I'd offer an example, but
Simple one here ... but can't get it to work ...
for (i in 1:4){
paste(stuff,[i]),sep=) - 3 + i
}
ls()
rm(list=ls())
I just want it to create 4 new variables called stuff1, stuff2, stuff3, stuff4
with the corresponding assignments. I realise that there are more elegant
functions but
Sarah Goslee wrote:
Leaving aside the question of whether this is a good thing to do,
Let's not leave that aside. Surely there is a much more
straight-forward way to accomplish what you want. Why not store
all the X's in a vector, and then you can avoid this for/assign/get
hack.
you
can
On Thu, Sep 16, 2010 at 3:49 AM, jaropis jaro...@zg.home.pl wrote:
A few days ago Tal Galili posted a message about some controversies
concerning the future of R. Having read the discussions, especially those
following Ross Ihaka's post, I have come to the conclusion, that, as usual,
the
Dear All,
I was using rk4 and lsoda to solve a ODE system. However, both of them gave
bad accurate solutions, especially compared with Matlab solver ODE45. For
example, ODE45 gave solutions that can go to a stable level (about 1.6) when
time goes to infinity, however, the solutions from lsoda are
Thanks everyone for the responses. They were all helpful!
On Sep 15, 2010, at 5:22 PM, Abhijit Dasgupta, PhD wrote:
I would approach this slightly differently. I would make func a
function of x and y.
func - function(x,y){
m - median(x)
return(m 2 m y)
}
Now generate tmp
tmp - data.frame(matrix(rnorm(30), 10, 3,
dimnames=list(letters[1:10],
c(company, person, salary
tmp
company person salary
a -1.04590176 -0.7841855 1.07150503
b -1.06643101 0.6545647 0.43920454
c
Hi everyone.
I would like to make a graphic with 2 subplots (lets say A and B). For
instance, I use :
par(mfcol = c(2,1));
The 2 subplots use the same X axis. So I provide no tics labels and no xlab
for the top plot. I would like the second plot to be right bellow the first
one (small
Hi R,
Is there a package in R to perform KMedian clustering?
Thanks.
Shubha
This e-mail may contain confidential and/or privileged i...{{dropped:10}}
__
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PLEASE do read the
Dear All,
I was using rk4 and lsoda to solve a ODE system. However, both of them gave
bad accurate solutions, especially compared with Matlab solver ODE45. For
example, ODE45 gave solutions that can go to a stable level (about 1.6) when
time goes to infinity, however, the solutions from lsoda are
On Sep 16, 2010, at 11:25 AM, James Nead wrote:
Hi,
I was trying to install R in my home directory on a Mac OS X Server
running
Darwin. How do I go about installing it? How can I install from the
binary
provided (R-2.11.1.pkg) from command line?
It's not really an rhelp question, is
Jake,
You can easily use glht for that.
See ?MMC in the HH package for examples.
You may need
install.packages(HH) ## if you don't already have HH.
Specifically, look at the examples showing the use of focus.lmat
On Thu, Sep 16, 2010 at 11:43 AM, Jake Kami jakejk...@gmail.com wrote:
dear
pam/clara in package cluster are probably as close to it as you can be.
There is no unique definition of a multivariate median and therefore there
is no unique definition of k-medians, but pam/clara is one possible
version of it. (Of course if you think of k-medians as defined in a
specific
Hi!
assign() should do the job.
But using a list, and filling each element iteratively (with a for loop
or with *apply() ) might be better, up to you.
Btw, why do you remove your objects?
HTH,
Ivan
Le 9/16/2010 17:44, Maas James Dr (MED) a écrit :
Simple one here ... but can't get it to
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Peng, C
Sent: Thursday, September 16, 2010 5:39 AM
To: r-help@r-project.org
Subject: Re: [R] Problem with cat() == A related question
The question is wehter cat() can print
On Sep 16, 2010, at 11:44 AM, Maas James Dr (MED) wrote:
Simple one here ... but can't get it to work ...
for (i in 1:4){
paste(stuff,[i]),sep=) - 3 + i
}
ls()
rm(list=ls())
for (i in 1:4){
+paste(stuff,[i]),sep=) - 3 + i
Error: unexpected '[' in:
for (i in 1:4){
paste(stuff,[
Help!
I am unsure if I can analyze data from the following experiment.
Fish were placed in a tank at (t=0)
Measurements of Carbon Dioxide were taken each day for 120 days (t=0,...120)
A few fish were then randomly pulled out of the tank at different days,
killed and examined for the presence of
Hi:
Could you please devise a reproducible example that illustrates the problem?
As far as points (1) and (2) are concerned, if you lack row or column names,
they can always be defined and added to the object.
Dennis
On Thu, Sep 16, 2010 at 4:26 AM, Natasha Asar natasha.asa...@yahoo.comwrote:
Apologies, but after a fair amount of digging, I still only have a foggy
understanding of the cause of this problem, due to my own ignorance.
I hope to use RODBC package to connect to an Access DB when running 64 bit
Win7 (R version 2.11.1, 64 bit). I have successfully done this before on a
Hi all,
We know old.packages() can check for updates of add-on packages, but
is there a way to check updates of R itself? go to R homepage is a
way, of course, but I hope this can be done by R.
I'm not sure about the reliable place to check; here is a simple
example to check from one of the CRAN
Hello, I am trying to create a panel with the attached data frame. using the
following code:
PanelRio = DataRiopaila[which(duplicated(DataRiopaila$SEC_STE)==T),]
PanelRio=plm.data(PanelRio,index=c(SEC_STE,FechaSiembra))
series
Thanks for all the suggestions, guys. It looks like TIFF may be the easiest
solution, as I wouldn't have to worry about printing to a postscript printer
or converting to PDF (when using EPS). That way, I could send the Word file
as is to all coauthors (important for collaboration - i.e., track
Hi,
I have been trying to use the new .parallel argument with the most recent
version of plyr [1] to speed up some tasks. I can run the example in the NEWS
file [1], and it seems to be working correctly. However, R will only use a
single core when I try to apply this same approach with
I have a file that reads like this:
Species,Year,Julian_day
Alnus_glutinosa, 1873, 123
Sorbus_aucuparia, 1873, 122
(more species...)
Alnus_glutinosa, 1874, 134
Sorbus_aucuparia, 1874, 143
(more species and years)
Is there a way to plot this as julian day over years so that each species
Something like this?
library(ggplot2)
qplot(Year, Julian_day, data=a, colour=Species)
On Thu, Sep 16, 2010 at 12:14 PM, fugelpitch jo...@runtimerecords.net wrote:
I have a file that reads like this:
Species,Year,Julian_day
Alnus_glutinosa, 1873, 123
Sorbus_aucuparia, 1873, 122
(more
Hi Richard
Thanks for the suggestion, but I want top 5 salary for each company, not
the whole list. I don't see how your way can work?
Thanks,
Richard
From: RICHARD M. HEIBERGER [mailto:r...@temple.edu]
Sent: Thursday, September 16, 2010 11:53 AM
To: Tan, Richard
Cc:
On Sep 16, 2010, at 1:14 PM, fugelpitch wrote:
I have a file that reads like this:
How much R do you know? Are you still at the stage where you need
basic help reading a file into a session?
Species,Year,Julian_day
Alnus_glutinosa, 1873, 123
Sorbus_aucuparia, 1873, 122
(more
On 09/15/2010 12:03 PM, darckeen wrote:
Class(person,representation(age=numeric,weight=numeric))
[1] person
bob - new(person,age=30)
is.null(b...@weight)
[1] FALSE
b...@weight
numeric(0)
b...@weight == numeric(0)
logical(0)
Hi darckeen -- use the prototype argument to setClass to
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