The current population survey march supplements contain records on
households, families and individuals, each with distinct record types all in
the same file. I'm trying to efficiently read these files,
the following function reads the data file indata, the records are
described in lists
Hi
I am calling R from Perl. I have read the file into an array but I am
stuck on passing that array to RSPerl dataframe. I thought the steps
would be :
1.Read file into array
2.Pass array into RSPerl environment convert to data structure e.g data
frame
3.Call randomForest functions on
Thanks a lot! I have one other question,however. If I want to have two
garchFits, garchFit(~aparch(1,1), data = sunspot.year) and
garchFit(~arma(2,1)+apaarch(1,1), data = sunspot.year), how do I automate
the creation of these models?
for(k in 1:2)
{
garchFit~...,data = sunspot.year),
}
I
I'm not sure if you want general literature or R-specific answers.
In any case, check either source below and you may have better
luck contacting authors as many may use R but not be on this list.
Date: Wed, 6 Oct 2010 06:28:02 -0700
From:
On Wed, Oct 6, 2010 at 9:32 AM, Ralf B ralf.bie...@gmail.com wrote:
Can one create a variable through a function by name
createVariable - function(name) {
outputVariable = name
name - NULL
}
after calling
createVariable(myVar)
I would like to have a variable myVar
Dear all,
I have the following data, which is the output from ms hudson software.
segsites: 6
positions: 0.1256 0.3122 0.3218 0.4970 0.5951 0.7943
001010
110101
010100
001010
010100
I want to make R function to calculate the R-Square across pairs separated
by 10% (the difference between
Look at the shadowtext function in the TeachingDemos package and the
boxed.labels function in the plotrix package.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org
Suppose I have implemented my own R function. How do I call this function in
Eclipse using JRI?
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-run-own-R-functions-in-JRI-tp2965288p2965288.html
Sent from the R help mailing list archive at Nabble.com.
The k-means/Ward criterion can be written down in terms of squared
Euclidean distances in a way that doesn't involve means. It is half the
sum (over all clusters) of the sum (over all observations in a
cluster) of all within-cluster squared dissimilarities, the inner sum
divided by the cluster
On Wed, Oct 6, 2010 at 9:32 AM, Ralf B ralf.bie...@gmail.com wrote:
Can one create a variable through a function by name
createVariable - function(name) {
outputVariable = name
name - NULL
}
after calling
createVariable(myVar)
I would like to have a variable myVar
Dear all,
I have the following data, which is the output from ms hudson software.
segsites: 6
positions: 0.1256 0.3122 0.3218 0.4970 0.5951 0.7943
001010
110101
010100
001010
010100
I want to make R function to calculate the R-Square across pairs separated
by 10% (the difference
An alternative to Peter's solution:
createVariable - function(name) {assign(name, NULL, envir=.GlobalEnv)}
Jeff.
On Wed, Oct 6, 2010 at 12:32 PM, Ralf B ralf.bie...@gmail.com wrote:
Can one create a variable through a function by name
createVariable - function(name) {
outputVariable
On Oct 6, 2010, at 12:32 PM, Ralf B wrote:
Can one create a variable through a function by name
Isn't that what - does?
createVariable - function(name) {
outputVariable = name
name - NULL
}
after calling
createVariable(myVar)
?assign # and isn't this covered in
Does anyone know why a data frame created with empty character columns
converts them to integer columns?
df-data.frame(a=character(0),b=character(0))
df-rbind(df,c(a,a))
typeof(df[1,1])
[1] integer
AsIs doesn't help:
df-data.frame(a=I(character(0)),b=I(character(0)))
df-rbind(df,I(c(a,a)))
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of peter dalgaard
Sent: Wednesday, October 06, 2010 7:22 AM
To: Henrique Dallazuanna
Cc: r-help@r-project.org; Andre Easom
Subject: Re: [R] Adding a time variable prior to using
On Oct 6, 2010, at 12:58 PM, David Winsemius wrote:
On Oct 6, 2010, at 12:32 PM, Ralf B wrote:
Can one create a variable through a function by name
Isn't that what - does?
createVariable - function(name) {
outputVariable = name
name - NULL
}
after calling
Here's a simple example that might be instructive:
x = 9.790001
y = 9.79
x
[1] 9.79
y
[1] 9.79
x == y
[1] FALSE
abs(x - y) 1e-8
[1] TRUE
all.equal(x,y)
[1] TRUE
And as others have said, FAQ 7.31 .
- Phil Spector
Try this:
df - data.frame(a=character(0),b=character(0), stringsAsFactors = FALSE)
df[1,] - c('a', 'a')
On Wed, Oct 6, 2010 at 2:00 PM, N David Brown hubd...@gmail.com wrote:
Does anyone know why a data frame created with empty character columns
converts them to integer columns?
Patrick Burns has been my great source of resources in my R learnings. Most
of the answers you would find from his stuffs only, see
http://www.burns-stat.com/;. However for functions and their
executions/debugging related quires we might find John Chambers
This should do it:
df - data.frame(a=character(0), b=character(0), stringsAsFactors=F)
because:
typeof(factor(0))
is integer
while:
typeof(character(0))
is character.
Cheers,
Jeff.
On Wed, Oct 6, 2010 at 1:00 PM, N David Brown hubd...@gmail.com wrote:
Does anyone know why a data frame
Try this:
ab - array(rnorm(3*3), dim = c(3,3,3))
ab[,,-1] - NA
ab[ , ,tail(seq(dim(ab)[3]), 2)] - ab[, , 1]
On Wed, Oct 6, 2010 at 12:49 PM, Farida Mostajabi farida...@gmail.comwrote:
Dear list,
Does anyone know if there is a function that replaces a matrix of NAs in
an array with the
Possible? Yes (as others have shown), advisable? No, see fortune(106),
fortune(236), and possibly fortune(181).
What is your ultimate goal? Maybe we can help you find a better way.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
On Oct 6, 2010, at 1:00 PM, N David Brown wrote:
Does anyone know why a data frame created with empty character columns
converts them to integer columns?
Quick answer: it's the strngsAsFactors demon but you have invoked that
demon twice, Once with data.frame and the second rime with rbind.
Start with Writing R Extensions, part of the free documents that come with R.
Much of what you ask is covered in there. After reading that, then you can
look for the other resources.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
Large coefficients and large standard errors in logistic regression models can
be indicative of the Hauk-Donner phenomenon. This is where the coefficient is
highly significant, but the Wald Statistic is misleading because the likelihood
curve is relatively flat in the area of the estimate
I think what you are looking for is
?table
and/or
?prop.table
So, let's say you have two matrices: ACTUAL and CLASS, you can ...
table(ACTUAL, CLASS)
Or, diag(1-prop.table(table(ACTUAL, CLASS), 1)) to get row percentages
and take the diagonal.
So, using your example:
# table() as above
Hi:
Another approach is:
v1 = c(1.2, 1.4, 0.9, 1.0, 1.1, 1.0)
v2 = c(aa, cc, bb, bb, cc, bb)
v3 = c(8, 10, 11, 9, 9, 10)
df = data.frame(v1=v1, v2=v2, v3=v3)
ggplot(df) + geom_bar(aes(x = reorder(v2, desc(v3
HTH,
Dennis
On Wed, Oct 6, 2010 at 2:09 AM, Morten morten.lindb...@siv.no wrote:
Dear R users,
I have huge dataset like the bellow (prepared in notepad in txt format:
31;39;00N+65;40;00E T
36;31;42N+69;04;21E T
34;10;00N+69;41;00E T
34;34;00N+69;06;00E T
31;40;00N+65;44;00E T
35;00;00N+69;07;00E T
34;00;00N+69;53;00E T
These are geographical coordinates, degree minute,
I think the basic answer here is package it, which I did a couple of times
but found inconvenient if I was going to change the function fairly often,
i've taken a different tact, just including custom functions when R starts,
i wrote a function that runs when I start the R session, loading the
Hi all,
I am having trouble assigning a value within a vector using a variable
defined within a function. I suspect this has something to do with
namespaces but I cannot figure it out. Please reply directly to me if you
can help.
###begin code
#simple vector
test-c(4,5,6)
#simple function to
Hello R-users,
I'm currently facing a pretty hard problem which I'm hopping you'll be able to
help me with. I'm using R to create images. That alone is not the problem,
the problem is that I'm using R to create 168 000 images... My code (which is
given below) use different package (raster
#another simple function to update the value in a vector
update-function(index){
test[index]- 20
}
update(2)
test
#The update() function silently fails to accomplish the update
Replace the '-' by '-' and you'll be good to go if you call the
function from a global environment. More
Have you looked to see how fast your memory might be growing? Are you
leaving around any large objects that should be removed? Have you
looked to see if you are paging? Is it your CPU time that is
increasing, or your wall clock time? You may need to run perfmon to
see what is happening. It
Hi all,
I have scripts that have one variable called 'output', the script
creates a data frame and stores this data frame in 'output'. Then
the data frame is written to disk. This is simple when working with a
single script. However, as soon as one script calls other, variables
overwrite each
See the replace function:
index - 3
test - replace(test, index, 20)
On Wed, Oct 6, 2010 at 2:31 PM, Andrew Barr wab...@gmail.com wrote:
Hi all,
I am having trouble assigning a value within a vector using a variable
defined within a function. I suspect this has something to do with
try this:
input - read.table(textConnection(31;39;00N+65;40;00E T
+ 36;31;42N+69;04;21E T
+ 34;10;00N+69;41;00E T
+ 34;34;00N+69;06;00E T
+ 31;40;00N+65;44;00E T
+ 35;00;00N+69;07;00E T
+ 34;00;00N+69;53;00E T), sep = +, as.is = TRUE)
closeAllConnections()
result - NULL
for (i in 1:2){
+
On Oct 6, 2010, at 1:31 PM, Andrew Barr wrote:
Hi all,
I am having trouble assigning a value within a vector using a variable
defined within a function. I suspect this has something to do with
namespaces but I cannot figure it out. Please reply directly to me
if you
can help.
###begin
I wasn't sure about the subject so I am sorry about the vagueness, but if I
have a vector of values, how do I get a certain type of vectors to be bold
or italics?
So let x be a vector from -10 to 10, how would I tell it to bold the x
values that are greater than 0? Or like absolute value of 5?
Hello,
I am working on a variable selection problem and would like to have some
suggestions. Thank you.
In my data, the number of observations/samples is much less than the number
of variables. And I am not interested in generating only a few models,
instead I will need a couple of hundred
Thanks a lot for your quick answer. Here is my answer to your questions:
Have you looked to see how fast your memory might be growing?
BFR- Yes I did, it's not to bad, it's starts around 60 000ko, rise up to 120
000 at the most, so not too scary.
Are you leaving around any large objects that
What output medium? On a graphic? In LaTeX ouput?
Or do you mean in the R console?
Joe P King wrote:
I wasn't sure about the subject so I am sorry about the vagueness, but if I
have a vector of values, how do I get a certain type of vectors to be bold
or italics?
So let x be a vector from
oh sorry for not specifying, I want it returned in the console, another
vector I can call.
Joe King
206-913-2912
j...@joepking.com
Never throughout history has a man who lived a life of ease left a name
worth remembering. --Theodore Roosevelt
-Original Message-
From: Erik Iverson
Hello, I am having trouble getting the output from the tapply function
formatted so that it can be made into a nice table. Below is my question
written in R code. Does anyone have any suggestions? Thank you. Geoff
#Input the data;
name - c('Tom', 'Tom', 'Jane', 'Jane', 'Enzo', 'Enzo', 'Mary',
Try this:
aggregate(height ~ class + group + name, data = myData, FUN = mean)
On Wed, Oct 6, 2010 at 4:13 PM, Geoffrey Smith g...@asu.edu wrote:
Hello, I am having trouble getting the output from the tapply function
formatted so that it can be made into a nice table. Below is my question
Hello,
You can use ddply from the very useful plyr package to do this.
There must be a way using base R functions, but plyr is
worth looking into in my opinion.
install.packages(plyr)
library(plyr)
ddply(myData, .(class, group, name), function(x) mean(x$height))
class group name V1
1
Hello Jim,
Thanks. It works. Great.
By the way, I am beginner in R.
All the best,
Mehdi
--- On Wed, 10/6/10, jim holtman jholt...@gmail.com wrote:
From: jim holtman jholt...@gmail.com
Subject: Re: [R] Help to trafnsform data!
To: Mehdi Zarrei gagzar...@yahoo.com
Cc: r-help@r-project.org
Geoffrey -
The output you want is exactly what the aggregate() function
provides:
aggregate(myData$height, myData[c('class','group','name')],mean)
class group namex
1 1 A Enzo 66.5
2 0 B Jane 58.5
3 1 B Mary 70.5
4 0 A Tom 62.5
It should be mentioned
Another way:
library(gsubfn)
sapply(lapply(lapply(input, strapply, pattern = \\d{2}, ~as.numeric(x),
simplify = rbind),
sweep, MARGIN = 2, STATS = c(1, 60, 3600), '/'),
rowSums)
On Wed, Oct 6, 2010 at 2:51 PM, Mehdi Zarrei gagzar...@yahoo.com wrote:
Dear R users,
I have
I know its no consolation, but I have a similar issue with R on a MAC, also
ploting
out large numbers of raster layers. sometimes the problem lingers even
after I clear the workspace, do gc() etc. Almost as if R wont ask for
processor resources.
weird.
On Wed, Oct 6, 2010 at 12:06 PM, Bastien
Hello,
I am working on a variable selection problem and I wonder whether there is
some function or package in R works similar to the 'PROC REG' in SAS? Thank
you.
Some facts about 'PROC REG':
PROC REG in SAS first composes a crossproducts matrix. The matrix can be
calculated from input data,
I am still a little unsure of how I would do this. I do not want to install
GEdit. Is there anyway in the retest in the included example that you can
show me how I would do this? My function is:
lol = function(x,y)
{
sum = x+y
mod = sum %5
return mod
}
--
View this message in
Hi Simon,
You'll notice the test data.frame has a whole mix of characters in
the columns you're interested, including a - for missing values, and
that the columns you're interested in are in fact factors.
as.numeric(factor) returns the level of the factor, not the value of
the level. (See
Hi,
Thanks for the help! The prop.table definitely will save some time but my
question is how would you actually build the mat matrix.
What I have now is 1000 matrices that are nx1 which have a predicted value for
each of the n observations. I want to count then how many elements are really
Chris,
Here is an example. Please ignore the particulars of the models - they were
built only to demonstrate sapply():
library(lme4)
statedata - data.frame(state.x77, state.region)
#create empty list object
mods - list()
#run the models, adding each one to the list
mods$m1 - glm(Income ~
On 10/6/2010 8:52 AM, Simon Kiss wrote:
Dear Colleagues,
I used this code to scrape data from the URL conatined within. This code
should be reproducible.
require(XML)
library(XML)
theurl - http://www.queensu.ca/cora/_trends/mip_2006.htm;
tables - readHTMLTable(theurl)
n.rows -
Thanks to all three of you for responding. Brilliant answer there,
David - using the options() function as exemplified to set
stringsAsFactors=FALSE universally solved the issue.
Much appreciated, guys.
On 6 October 2010 18:27, David Winsemius dwinsem...@comcast.net wrote:
On Oct 6, 2010, at
dear list,
is there any function in R with which i can compute subject-wise means for a
single factor level? for instance, i wanna have the mean for each subject
for the first level of factor A, how can i get that? is there a
straightforward way to solve this problem?
kind regards
jake
Hi CZ,
The methods may not be the same, but you can use lm() for basic linear
regression, and glm() for general linear models. Do you have a
particular goal or statistical analysis in mind?
Cheers,
Josh
On Wed, Oct 6, 2010 at 12:50 PM, CZ cxzh...@ualr.edu wrote:
Hello,
I am working on a
Dear Jake,
An easy way to find the value of one variable by different levels of
another is using by(). For example, turning to the good old mtcars
data again:
by(mtcars$mpg, factor(mtcars$cyl), mean)
factor(mtcars$cyl): 4
[1] 26.66364
steven mosher moshersteven at gmail.com writes:
I know its no consolation, but I have a similar issue with R on a MAC, also
ploting
out large numbers of raster layers. sometimes the problem lingers even
after I clear the workspace, do gc() etc. Almost as if R wont ask for
processor
I'm giving a talk about some aspects of language and conceptual tools
for thinking about how
to solve problems in several programming languages for statistical
computing and graphics. I'm particularly
interested in language features that relate to:
o expressive power: ease of translating what
Hi all
I have a large dataframe with (among others) a categorical variable of 52
levels and would like to create a barplot with the bars ordered in
decreasing frequency of the levels. I belive it is referred to as a pareto
plot.
Consider a subset where I keep only the categorical variable in
Thats certainly more succinct than what I had!
-Don
On 10/5/10 10:35 PM, bill.venab...@csiro.au bill.venab...@csiro.au wrote:
PS ... actually, now I think about it...
as.polylist(apply(m, 1, polynom))
List of polynomials:
[[1]]
1 + 5*x + 9*x^2 + 13*x^3
[[2]]
2 + 6*x + 10*x^2 + 14*x^3
Thanks,
haven't used valgrind in years, this should be fun.
Steve
On Wed, Oct 6, 2010 at 1:55 PM, Ben Bolker bbol...@gmail.com wrote:
steven mosher moshersteven at gmail.com writes:
I know its no consolation, but I have a similar issue with R on a MAC,
also
ploting
out large
Hi All,
I am running a scatter plot and trying to add a best fit line. I use an abline
function, but get no line drawn over the points. I also get no error. I arm
using V 2.10.0 on Windows 7.
Here is my code, including the SAS transport file import:
require (foreign)
require (chron)
Thanks for the leads. I had been looking at CrossTables for awhile, but they
only seem to have one variable on each axis for each example I read.
The Hmisc summary.formula looks very promising, so I will investigate it
now. I think that might be the winner from looking at the examples you
On Oct 6, 2010, at 5:19 PM, Morten wrote:
Hi all
I have a large dataframe with (among others) a categorical variable
of 52
levels and would like to create a barplot with the bars ordered in
decreasing frequency of the levels. I belive it is referred to as a
pareto
plot.
Consider a
Sure, so, all I was saying about gedit is that it handles the R session for
me, which is a neat feature but not mandatory to get the expected result,
there's an rprofile.site file which describes your (user specific)
preferences,
you can manually edit this file to add functions at start up by
Hi,
I am interested in running multivariate contrasts from manova. Here is the code
I have currently for a one-way Manova. I would like to run multivariate
contrasts for the Year factor.
Thanks!
#Reduced model
t14m1-manova(as.matrix(t14c[,4:10])~t14c$Year)
#get multivariate results
Thanks a lot!!
Any integer is single element, whereas any number with decimal point is
double element ? Is that right ?
below is what I tried
so, basically, simply force it to be integer would save some space ?
P=1
a=rnorm(P*P)*1000
a=as.integer(a)
D1=matrix(a, nrow=P)
object.size(D1)
On Oct 6, 2010, at 5:56 PM, Gerard Smits wrote:
Hi All,
I am running a scatter plot and trying to add a best fit line. I
use an abline function, but get no line drawn over the points.
xyplot is Lattice
abline is base graphics
I also get no error. I arm using V 2.10.0 on Windows 7.
Dear R-help,
I have a matrix of data values specified in polar coordinates, i.e. (r,theta).
I know that I can transform this image to Cartesian coordinates and then use
image to display the results, however, I want to display the image as is,
without any coordinate transformations. This would
On Oct 6, 2010, at 6:08 PM, Carrie Li wrote:
Thanks a lot!!
Any integer is single element,
Not the way I would have expressed it. An integer is a 4 byte number
(range 2^31 + sign) and a double has a 8 byte floating point
representation (probably specified by some IEEE designation that
On Oct 6, 2010, at 6:30 PM, Justin Peter wrote:
Dear R-help,
I have a matrix of data values specified in polar coordinates, i.e.
(r,theta).
I know that I can transform this image to Cartesian coordinates and
then use image to display the results, however, I want to display
the image
On Oct 6, 2010, at 7:08 PM, David Winsemius wrote:
On Oct 6, 2010, at 6:30 PM, Justin Peter wrote:
Dear R-help,
I have a matrix of data values specified in polar coordinates, i.e.
(r,theta).
I know that I can transform this image to Cartesian coordinates and
then use image to display
Hi David,
Just changed to the standard plot from xyplot and it worked fine. I'll check
out panel.lmline.
Thanks for your help.
Gerard
On Oct 6, 2010, at 3:27 PM, David Winsemius wrote:
On Oct 6, 2010, at 5:56 PM, Gerard Smits wrote:
Hi All,
I am running a scatter plot and trying
Hi,
On Wed, Oct 6, 2010 at 5:05 PM, Michael Friendly frien...@yorku.ca wrote:
I'm giving a talk about some aspects of language and conceptual tools for
thinking about how
to solve problems in several programming languages for statistical computing
and graphics.
For graphics, I'm guessing
On Oct 6, 2010, at 7:38 PM, Abey George wrote:
I am trying to only fit this distribution to the data to see how
well it fits it. Getting the parameters is secondary. Did correct
the square brackets in the exponential equation but still get the
same result. There is only 1 variable to
6000 pages/sec sounds very high, but if your CPU utilization is
decreasing over time, this is one of the causes. The system is paging
memory out and having to wait for I/O to complete and therefore is not
using the CPU. What other I/O is your system doing? When you are
partitioning the image,
On 10/6/2010 6:14 PM, David Winsemius wrote:
Graphics: I realize you were focusing on language but the graphical
tools are extremely important if one is describing how data
exploration and summarization is done effectively.
Well, I'm focusing on the language features that make it easy or
On 10/6/2010 6:07 PM, Ali S wrote:
Hi,
I am interested in running multivariate contrasts from manova. Here is the code
I have currently for a one-way Manova. I would like to run multivariate
contrasts for the Year factor.
Thanks!
#Reduced model
t14m1-manova(as.matrix(t14c[,4:10])~t14c$Year)
Dear List
I am running a loop downloading web pages and save the html to a
temporary file (use download.file() )
then read (using readLines) it in for processing;
finally write useful info from each processed page to a unique file
the problem is once the loop runs up to somewhere near 5000,
I am trying to only fit this distribution to the data to see how well it
fits it. Getting the parameters is secondary. Did correct the square
brackets in the exponential equation but still get the same result. There is
only 1 variable to data2 and that is points. I am trying to fit this
Good day,
I need to subset a data by removing several rows. I know the %in% operator,
i.e.
sub - mydata[group %in% c(A,B,E,G), ]
What I need is the opposite, that is remove rows and/or columns. What is the
operator for NOT IN? I tried (i)! %in% and (ii) ^%in% and both resulted in
a could
On Wed, Oct 6, 2010 at 10:16 AM, lord12 trexi...@yahoo.com wrote:
Thanks a lot! I have one other question,however. If I want to have two
garchFits, garchFit(~aparch(1,1), data = sunspot.year) and
garchFit(~arma(2,1)+apaarch(1,1), data = sunspot.year), how do I automate
the creation of these
Put the ! in front of the whole expression, not just the %in%
function. I.e.
sub - mydata[!(mydata$group %in% c(A, B, E, G)),]
Christian
On Thu, 2010-10-07 at 09:17 +1000, Emily Deomano wrote:
Good day,
I need to subset a data by removing several rows. I know the %in% operator,
i.e.
sub
I am wondering, if I want the output in bold in the console, to hold in an
object, can I use the expression() command?
Joe King
206-913-2912
j...@joepking.com
Never throughout history has a man who lived a life of ease left a name
worth remembering. --Theodore Roosevelt
-Original
Thanks, Christian. This is really helpful.
I was not aware of that equality, but now I can see it. I think you mean the
inner sum over all distances in the distance matrix (for that cluster),
which means that each distance is counted twice (which is why we divide by
2).
Peter
Christian Hennig
you should close files that you do not use anymore. the maximum number
of open files is likely 4000 or so. Use close(file) before you open
the next one.
Peter
On Wed, Oct 6, 2010 at 4:55 PM, Yong Wang wangyo...@gmail.com wrote:
Dear List
I am running a loop downloading web pages and save the
On Oct 6, 2010, at 9:03 PM, Christian Raschke wrote:
Put the ! in front of the whole expression, not just the %in%
function. I.e.
sub - mydata[!(mydata$group %in% c(A, B, E, G)),]
You can also look at the match help page where %in% and its negation,
%w/o% , are illustrated.
--
David.
On Wed, Oct 6, 2010 at 4:05 PM, Michael Friendly frien...@yorku.ca wrote:
I'm giving a talk about some aspects of language and conceptual tools for
thinking about how
to solve problems in several programming languages for statistical computing
and graphics. I'm particularly
interested in
Dear List,
I have a column of dates say:
test$date1 - seq(19900511, to = 19900521)
I want the next column to have the number of days between each subsequent
date i.e days between r(i+1) and r(i)
Any easy way to do this? (I've done it in a roundabout way but just
wondering if there is any way
Hi Alex,
In the picture are depicted the areas that I need to calculate somehow. Of
course the easiest way would be to use some already implemented function
which does not seem to exist.
That was why I posted a function to calculate polygon area in my
previous reply :) Have you tried that
Hello Alex,
I recently published a post titled:
Managing a statistical analysis project guidelines and best
practiceshttp://www.r-statistics.com/2010/09/managing-a-statistical-analysis-project-guidelines-and-best-practices/
This post might prove useful to you:
Dear R users,
Anyone can tell me how to change the font size of X and Y axis labels in
plot function? Thanks.
Gary
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
Hi:
# Generate a factor and a random set of counts/frequencies
df - data.frame(gp = LETTERS[1:20], frq = rpois(20, 30))
# bar plot in lexicographic order of factor levels
ggplot(df, aes(x = gp)) + geom_bar(aes(y = frq), stat = 'identity')
# bar plot in increasing order of frequency
ggplot(df,
Hi:
See below.
On Wed, Oct 6, 2010 at 2:56 PM, Gerard Smits g_sm...@verizon.net wrote:
Hi All,
I am running a scatter plot and trying to add a best fit line. I use an
abline function, but get no line drawn over the points. I also get no
error. I arm using V 2.10.0 on Windows 7.
Here
On Oct 6, 2010, at 11:07 PM, Santosh Srinivas wrote:
Dear List,
I have a column of dates say:
test$date1 - seq(19900511, to = 19900521)
Those aren't dates. (but if they were the methods should be the same)
I want the next column to have the number of days between each
subsequent
date
On Oct 6, 2010, at 11:40 PM, Hongwei Dong wrote:
Dear R users,
Anyone can tell me how to change the font size of X and Y axis
labels in
plot function? Thanks.
?par # cex.lab
--
David.
Gary
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Hi, Michael,
When I teach/preach on R, I emphasize the language's focus on data,
both in its objects and operations. It might seems basic, but it's
fundamental to most of the features you and others have mentioned. As
a statistical programming language, what we intend to do with R is
often very
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