Santosh Srinivas wrote:
A fundamental question ...I'm trying to understand the differences between
loop and vectorization ... I understand that it should be a natural choice
to use apply / adply when it is needed to perform the
same function across all rows of a data frame. Any pointers on
Prof. John C Nash wrote:
I spent more time than I should have debugging a script because I wanted
x-seq(0,100)*0.1
but typed
x-seq(O:100)*0.1
seq(0:100) yields 1 to 101,
Which leads us to another rule: never use a variable called O. I remember
this was a no-no even in my
Hi Liviu,
However, I'm still confused on how to compute the scores when rotations
(such as 'varimax' or other methods in GPArotation) are applied.
PCA does an orthogonal rotation of the coordinate system (axes) and further
rotation is not usually done (in contrast to factor analysis).
Hi Yanika,
more information about deSolve (books, papers, tutorials) can be found
on the deSolve homepage:
http://desolve.r-forge.r-project.org
and, of course, in the package documentations. If you need further help
from the list, please provide a short reproducible example.
Thomas
Hello,
I have create my own R package and written the documentation in Rd
format for each of the functions plus the package itself.
However now the functions appear in a random order in the generated PDF
and the package documentation is placed in between the functions, when I
would like it
Can you please show code example, how to draw graph with some nodes and
edges, but with weights. I only found here
http://www.bioconductor.org/packages/release/bioc/vignettes/Rgraphviz/inst/doc/Rgraphviz.pdf-
Using edge weights for labels, but...
Here an example:
library(graph);
Henning Wildhagen wrote:
i want to plot gene regulation data in a lattice barchart. To illustrate
the problem i encounter, the following code uses the barleydataset:
#No, i tried to add error bars using the following code:
..
As Deepayan noted in
#
Dear all,
i have spent a lot of time trying to solve this problem, but I am sure that
there must be a simple solution. So, as a last resort, I am coming back to you
again. I have a dataset with some (almost random) values in many variables.
Lets
say that the dataset represents the scores of
Or is there any kind of File buffer that dossent save a file on the
harddrive?
coz this gives me the thing I want but it still saves the file on the HD
.HTML.file=(temp-file(era.html,w+))
HTML(NANALALA)
HTML(diag(3))
Then I can just use
readLines(temp) to get the result
but as I said I
Hi Joel,
The function hwrite() of the package hwriter does that.
library(hwriter)
hwrite(iris[1:10,])
See examples at http://www.embl.de/~gpau/hwriter/
Cheers,
Greg
---
Gregoire Pau
EMBL Research Officer
http://www.embl.de/~gpau/
On 01/12/10 08:53, Joel wrote:
Hi
Is it possible to
Hello,
I tried to use GEOQuery package of BioC. It does not download GSE.
I investigated problem, understood that the problem was about internal function
download.
Reccomendations about it mostly suggest switching any proxy off in R. I did,
and nothing changed.
I use Ubuntu Lucid 64 bit
Hi,
I don't know much about RODBC, but the package xlsReadWrite works pretty
well for me for reading and writing xls files (and it doesn't need Perl
or anything else to run).
Ivan
Le 12/1/2010 08:56, Stephen Liu a écrit :
Hi folks,
Win 7 64bit
R 2.12.0 32bit
Problem in reading Excel
Hi,
For your second question, take a look at ?clip. The example explains
really well what you can do and how.
HTH,
Ivan
Le 12/1/2010 04:42, Peter Ehlers a écrit :
On 2010-11-30 17:27, Jason Edgecombe wrote:
Hi,
I have the following code:
hist(gps$heartpercent, breaks=5)
rect(90,
This is an interesting discussion on barchart (without error bars)
http://www.decisionsciencenews.com/2010/08/11/which-chart-is-better/
Dieter
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Sent from the R
Hi,
(a) sum() and mean() have a na.rm argument that should be set to TRUE.
(b) let's try with an example:
x - c(1:5, NA, NA, 6:10, NA)
x[is.na(x)] - 0 ## replace NAs by 0
HTH,
Ivan
Le 12/1/2010 10:00, Iasonas Lamprianou a écrit :
Dear all,
i have spent a lot of time trying to solve this
Hi Ivan,
Thanks for your advice.
I have problem running xlsReadWrite on 64 bit Win7.
library(xlsReadWrite)
xlsReadWrite version (cran shlib)
Copyright (C) 2010 Hans-Peter Suter, Treetron, Switzerland.
!! Your installation contains the cran placeholder shlib (dll/so).
Please get the regular
And just to add to Ivan's comment, if you are using the rowSums or
colSums functions with a matrix or data.frame they also have the na.rm
argument.
Michael
On 1 December 2010 20:16, Ivan Calandra ivan.calan...@uni-hamburg.de wrote:
Hi,
(a) sum() and mean() have a na.rm argument that should be
On 12/01/2010 12:27 PM, Jason Edgecombe wrote:
Hi,
I have the following code:
hist(gps$heartpercent, breaks=5)
rect(90, par(usr)[3], 100, par(usr)[4], col = red)
How do I get the rectangle to appear behind the histogram. Barring that,
how can I make certain bars of the histogram to be a
coplot() usually puts grid lines in the panels it makes. To see examples,
example(coplot).
How can I remove those grid lines?
Seth Roberts
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
thank you, I'll have a go and let you know if i have problems
Dr. Iasonas Lamprianou
Assistant Professor (Educational Research and Evaluation)
Department of Education Sciences
European University-Cyprus
P.O. Box 22006
1516 Nicosia
Cyprus
Tel.: +357-22-713178
Fax: +357-22-590539
Honorary
Hi Joel,
You can use:
obj=diag(3)
txt=capture.output(HTML(obj,file=))
Then you may manipulate elements, paste with collapse argument, replace
parts with gsub and so on.
HTH,
Eric
2010/12/1 Joel joda2...@student.uu.se
Hi
Is it possible to instead of getting the HTML code written to a
Hello, I tried to use GEOQuery package of BioC. It does not download GSE. I
investigated problem, understood that the problem was about internal function
download. Reccomendations about it mostly suggest switching any proxy off in
R. I did, and nothing changed.
I use Ubuntu Lucid 64 bit
Thanks
this is a clearer (I hope) version of an earlier post -
My problem is formulating the random = argument to give estimates
of all 9 random components for this kind of setup where there are
(I think) 9 variance/covariance components ...
Study.1Study.2 ...
Hi Peter
Many thanks. I will have a go with that and see if I have
any joy.
Your advice is much appreciated.
Sam
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Hi again,
There are also other packages to read and write xls files, including
gdata (read), dataframe2xls and writeXLS (write), which depend on Perl
or Python if I'm not mistaken.
I have no idea whether they work on Windows 64 bits.
Visit Crantastic http://crantastic.org/
Ivan
Le 12/1/2010
Run
update.packages(checkBuilt=TRUE)
to get package binaries that were compield for your version of R.
Uwe Ligges
On 24.11.2010 04:24, john moran wrote:
Apologies for my previous effort in HTML which apparently was scrubbed
Dear R-users
I wonder if I could get advice on the above
Thanks Thierry
Using the position_dodge positioning option ought to work but there is
something wrong with the scaling when the binwidth is not = 1.
You can begin to see this with the example I sent:
If you do
ggplot(data=dafr, aes(x = d1, fill=d2)) + geom_histogram(binwidth = 1, position
=
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,
On 30/11/2010 9:54 PM, randomcz wrote:
Hi guys,
How to pass an operator to a function. For example,
test- function(a, , b)
{
return(ab) #the operator is passed as an argument
}
Thanks,
It's much simpler than the other suggestions. Just pass the operator,
and treat it as a
On 01/12/2010 5:12 AM, Koray Kaya wrote:
Hello, I tried to use GEOQuery package of BioC. It does not download GSE. I investigated
problem, understood that the problem was about internal function download.
Reccomendations about it mostly suggest switching any proxy off in R. I did, and nothing
Dear,
I have a dataset with 4 subjects (see ID in example), and 4 treatment (see
TRT in example) which are tested on 2 locations and in 3 blocs. By using
Lattice dotplot, I made a graph that shows the raw data per location and
per bloc. In that graph, I would like to have a reference line per
The following works nicely. Thank you.
plot(z, sf[[s]], type=l) #where the dataframe name in my case is sf
Sorry - I meant to say there were 24 rows in each column, so z=1:24
Gregory A. Graves, Lead Scientist
Everglades REstoration COoordination and VERification (RECOVER)
Restoration
On Wed, Dec 1, 2010 at 2:56 AM, Stephen Liu sati...@yahoo.com wrote:
Hi folks,
Win 7 64bit
R 2.12.0 32bit
Problem in reading Excel spreadsheets
There are quite a few alternatives for reading Excel spreadsheets.
They are listed here:
On Sun, Nov 28, 2010 at 6:44 AM, Stephen Liu sati...@yahoo.com wrote:
Hi folks,
Win 7 64 bit
R 32 bit
install.packages(gregmisc)
Installing package(s) into
‘C:\Users\satimiswin764\Documents/R/win-library/2.12’
(as ‘lib’ is unspecified)
--- Please select a CRAN mirror for use in this
Hi Bill,
Please keep the R list copied.
I don't think you've given enough information to pin down your
problem. This works:
dat - read.table(textConnection(dates returns
2000-1-4 -0.038344718
2000-1-50.00195
2000-1-60.000955702
2000-1-70.027090384
2000-1-100.011189966
Hi,
I am also doing PCA.
Is the following right for extracting the scores?
library(psych)
pca-principal(data,nfactors=,rotate=varimax,scores=T)
pca$loadings
pca$score
Best regards,
He
On Tue, Nov 30, 2010 at 10:22 AM, Liviu Andronic landronim...@gmail.com wrote:
Dear all
I'm unable to find
Peter Langfelder wrote:
On Fri, Nov 26, 2010 at 6:55 AM, Derik Burgert derik2...@yahoo.de wrote:
Dear list,
running a hierachical cluster analysis I want to define a number of
objects that build a cluster already. In other words: I want to force
some of the cases to be in the same
Hi Sandy,
I don't have an answer to your question, but wanted to share another
possibility:
ggplot(data=dafr, aes(x = d1, fill=d2)) + geom_histogram(binwidth = 1,
position = position_identity(), alpha=.5)
Best,
Ista
On Wed, Dec 1, 2010 at 6:09 AM, Small Sandy (NHS Greater Glasgow
Clyde)
On 2010-12-01 01:51, Seth Roberts wrote:
coplot() usually puts grid lines in the panels it makes. To see examples,
example(coplot).
How can I remove those grid lines?
Seth Roberts
That's hard-coded in coplot. But you can easily make a
modified copy of coplot. Here are the steps:
1. make a
Hi,
I have the following matrix (named m):
key
sensor_date Laser_1 Laser_2
Laser_3
2010-09-30T15:00:12+020063
1
2010-10-31T15:05:07+0100
Dear everyone,
I am doing some work about species richness estimation. Nonparametric
estimation (such as Chao1, Jacknife1) can be done just using function
specpool() and estimateR() in package vegan. The problem is that I can
not found any functions for parametric estimation (such as MMMeans,
David Winsemius dwinsem...@comcast.net
on Mon, 29 Nov 2010 09:46:08 -0500 writes:
On Nov 29, 2010, at 9:00 AM, pilchat wrote:
Hi guys,
to make it easier, here is a simple case with the same issues. I use
the short function below to make the attached PS file.
Just for fun
This small program gives negative Sum of Sq in anova (with R versions
2.9.2 and 2.10.0) (linux 32 kernel 2.6.29.6-smp slackware 13.0) :
y = c(3.6, 5.0, 5.0, 4.6, 4.5, 4.3, 4.5, 5.1, 4.5, 4.3)
trans = as.factor(c(NT,NT,NT,NT,NT,T,T,T,T,T))
lc = lm(y ~ trans)
l1 = lm(y ~ 1)
Hi everybody,
I am a beginner in the steps of pre-processing and data analysis of
non-targeted metabolomic profiling experiments.
Anyone knows if there exists some tool for normalizing this type of data (raw
data or XCMS matrix data)
in R repositories? Many thanks in advance.
Best
On 12/01/2010 02:43 PM, alcesgabbo wrote:
I plot the first column with the following function:
plot(m[,1],type=o, xaxt=n,ylim=c(min(m[,1:length(colnames(m))])-1,
max(m[,1:length(colnames(m))])+1))
for the other columns I use there functions:
lines(m[,2],type=\o\)
lines(m[,3],type=\o\)
ok,
On 2010-12-01 04:02, barbara.cha...@bayer.com wrote:
Dear,
I have a dataset with 4 subjects (see ID in example), and 4 treatment (see
TRT in example) which are tested on 2 locations and in 3 blocs. By using
Lattice dotplot, I made a graph that shows the raw data per location and
per bloc. In
It might be a good idea not to use an outdated version of R.
I don't see your problem in R 2.12.0.
Peter Ehlers
On 2010-12-01 05:44, jean.cour...@math.u-psud.fr wrote:
Just for fun
This small program gives negative Sum of Sq in anova (with R versions
2.9.2 and 2.10.0) (linux 32 kernel
Hi He Zhang,
Is the following right for extracting the scores?
...
pca$loadings
pca$score
Yes.
But you should be aware that the function principal() in package psych is
standardizing your data internally, which you might not want. That is, the
analysis is being based on the correlation
barbara.chaves wrote:
I have a dataset with 4 subjects (see ID in example), and 4 treatment (see
TRT in example) which are tested on 2 locations and in 3 blocs. By using
Lattice dotplot, I made a graph that shows the raw data per location and
per bloc. In that graph, I would like to
On 12/01/2010 05:57 AM, nquer...@clinic.ub.es wrote:
Hi everybody,
I am a beginner in the steps of pre-processing and data analysis of
non-targeted metabolomic profiling experiments.
Anyone knows if there exists some tool for normalizing this type of data (raw
data or XCMS matrix
On Wed, 2010-12-01 at 07:32 -0500, Gabor Grothendieck wrote:
On Sun, Nov 28, 2010 at 6:44 AM, Stephen Liu sati...@yahoo.com wrote:
snip /
In the end it appears that there was no problem in accessing the gdata
package or any of its components and that the poster's problem stemmed
from issuing
However if you do:
ggplot(data=dafr, aes(x = d1, fill=d2)) + geom_histogram(binwidth = 1,
position = position_dodge(width=0.99))
The position of first bin which goes from 0-2 appears to start at about 0.2
(I accept that there is some white space to the left of this) while the
position of
Hi Dimtris and esteemed useRs,
I don't understand why i get this error message when attempting to use
merge() -
temp - merge(x, y[,17, drop=FALSE], by=rownames, sort=FALSE)
Error in as.vector(x, mode) :
cannot coerce type 'closure' to vector of type 'any'
It should work because:
Hi,
A new package Rd2roxygen has been released on CRAN:
http://cran.r-project.org/package=Rd2roxygen (source package
available; binaries to come)
This package can be useful for developers who used to document their
functions in the raw Rd files but want to switch to roxygen now using
inline
I am having problems trying to get R to graph data input that is log-normal
on the horizontal (x) axis.
The data is log (base 10), and I am more interested in viewing the tails of
the distribution. The closest I can get with this is log on the vertical
(y) axis and linear on the horizontal axis.
Hello dudes.
I'm developing VAR analysis based on suggestions made by Horváth in its
paper Canonical Correlation Analysis and Wiener-Granger Causality Tests.
That's the reason I'm looking for if there's any R package to develop Wiener
- Granger Causality Test.
Thanks a lot for your unvaluable
On Dec 1, 2010, at 9:18 AM, Peter Ehlers wrote:
It might be a good idea not to use an outdated version of R.
I don't see your problem in R 2.12.0.
Furthermore isn't it a bit something to be asking why the sign on a
number that is effectively zero happens to be negative? I would think
Hello fellows,
I would like to create a sequence for repeated numbers in a dataset. For
example:
ID - c(1:20)
grade - c(4,4,4,5,5,7,7,7,7,8,8,8,9,9,9,9,9,10,10,10)
Data:
ID Grade
1 4
2 4
3 4
4 5
5 5
6 7
7 7
8 7
9 7
(...)
I would like to create a variable sequence:
Data:
ID
Sorry this should have ben to the whole list:
Hadley
I think I've sorted it out in my head but for the record, and just to be sure...
I guess what I was expecting was that the width parameter would be independent
of binwidth. Thus a width parameter of 0.5 would always indicate an overlap of
Hi all,
I have the output of summary() of an lme object called lme.exp1, for
example
#
summary(lme.exp1)
Linear mixed-effects model fit by REML
Data: DATA
Log-restricted-likelihood: -430.8981
Fixed: fixed.exp1
Random effects:
On Wed, Dec 1, 2010 at 9:02 AM, Ben Bolker bbol...@gmail.com wrote:
Peter Ehlers ehlers at ucalgary.ca writes:
It might be a good idea not to use an outdated version of R.
I don't see your problem in R 2.12.0.
Peter Ehlers
On 2010-12-01 05:44, Jean.Coursol at math.u-psud.fr wrote:
Hi everyone.
I have a quick question regarding the look of my legend in my plot. As you
can see in the next figure, I have 3 series.
http://r.789695.n4.nabble.com/file/n3067466/legend.png
However, I find rather difficult to differentiate the series 1 and 3
according to their line type (lty).
Here are two options that might work for you given the little bit you've said:
## If its the same parameter all 30 times
## say, for example, base = 4.5 to log
for(i in 1:30) {
print(log(1:10, base = 4.5))
}
## if they are different parameters, you could try
lapply(X = c(1.3, 3, 2.2, 4, 5),
Try this:
ord - order(grade)
ID - Id[ord]
grade - grade[ord]
sequence - unlist(sapply(table(grade), FUN = function(x) 1:x),
use.names = F)
And as a general tip, it is much easier to work with related values like
ID and grade if they are in a data frame. Such as:
dat - data.frame(ID,
You can also explore the classical() function in the MiscPsycho package that
does item analysis.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Iasonas Lamprianou
Sent: Wednesday, December 01, 2010 4:52 AM
To: Michael
Hi Luana,
Try this:
ID - 1:20
grade - c(4, 4, 4, 5, 5, 7, 7, 7, 7, 8, 8, 8, 9, 9, 9, 9, 9, 10, 10, 10)
d - data.frame(ID, grade)
d$Sequence - do.call(c, sapply(rle(grade)$lengths, seq))
d
HTH,
Jorge
On Wed, Dec 1, 2010 at 11:08 AM, Luana Marotta wrote:
Hello fellows,
I would like to
Luana -
It's probably not the most efficient way, but here's
a solution that's not dependent on the grades being sorted:
grade - c(4,4,4,5,5,7,7,7,7,8,8,8,9,9,9,9,9,10,10,10)
unlist(sapply(rle(grade)$lengths,function(x)seq(1,x)))
[1] 1 2 3 1 2 1 2 3 4 1 2 3 1 2 3 4 5 1 2 3
On Wed, 2010-12-01 at 21:23 +0800, yangwenjing wrote:
Dear everyone,
I am doing some work about species richness estimation. Nonparametric
estimation (such as Chao1, Jacknife1) can be done just using function
specpool() and estimateR() in package vegan. The problem is that
I can not found
On Dec 1, 2010, at 10:13 AM, Filoche wrote:
Hi everyone.
I have a quick question regarding the look of my legend in my plot.
As you
can see in the next figure, I have 3 series.
http://r.789695.n4.nabble.com/file/n3067466/legend.png
However, I find rather difficult to differentiate the
On Dec 1, 2010, at 11:51 AM, David Winsemius wrote:
On Dec 1, 2010, at 10:13 AM, Filoche wrote:
Hi everyone.
I have a quick question regarding the look of my legend in my plot.
As you
can see in the next figure, I have 3 series.
http://r.789695.n4.nabble.com/file/n3067466/legend.png
Hello
Anyone know how can I calculate the value of the beta parameter when I know
the number of cointegrating relationships between two variables.
I mean, I using the procedure: ca.jo I do the following:
summary (ca.jo (UR [, c (2.52)], type = trace ECDET = trend, K = 2, spec
= longrun))
dear M.,
I do not know how to get the SE for the joinpoint (or breakpoint) from
your ljr fit. However you can find useful the segmented package which
works for any GLM (including the logistic one) and it returns
(approximate) StErr (and Conf Int) also for the joinpoint (breakpoint in
the
Try this:
id - 1:20
grade - c(4,4,4,5,5,7,7,7,7,8,8,8,9,9,9,9,9,10,10,10)
sequence - ave( id, grade, FUN=seq )
# if grade is not sorted
grade2 - sample(grade)
sequence2 - ave( id, grade2, FUN=seq )
cbind( grade2, sequence2 )
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
On Wed, 1 Dec 2010, Anna Berthinussen wrote:
Hi,
I receive the following warning message when I run a poisson GLM in R:
glm.fit: fitted rates numerically 0 occurred
The model summary is shown below. The variable 'Species' consists of
counts of different species ranging from 0 to 4. I suspect
On 01/12/2010 10:13 AM, Filoche wrote:
Hi everyone.
I have a quick question regarding the look of my legend in my plot. As you
can see in the next figure, I have 3 series.
http://r.789695.n4.nabble.com/file/n3067466/legend.png
However, I find rather difficult to differentiate the series 1
Hi,
Suppose I have the following data
name score
Abel 88
Baker 54
Charlie 77
stored a table called myData.
I want to write a function that will create a table which is a subset of myData
containing those have a score 75.
I know I can do this with the following command:
On Wed, 1 Dec 2010, cmccar...@bmcc.cuny.edu wrote:
Hi,
Suppose I have the following data
name score
Abel??? 88
Baker? 54
Charlie??? 77
stored a? table called myData.
I want to write a function that will create a table which is a subset of myData
containing those have a score
Try this:
newTable - function(data, criteria) {
do.call(subset, list(data, substitute(criteria)))
}
On Wed, Dec 1, 2010 at 3:56 PM, cmccar...@bmcc.cuny.edu wrote:
Hi,
Suppose I have the following data
name score
Abel88
Baker 54
Charlie77
stored a table called
Hi Arthur,
I was asking the same thing and came across the following (your need the sna
library).
http://students.washington.edu/mclarkso/documents/gplot%20Ver2.pdf
Take a look at the edge.lwd and vertex.cex examples of the function gplot. You
can use vectors for the different nodes.
Kind
Thank you all for your very fast replies.
I tried Henrique's method (see one of the above posts) , and it works
perfectly!
Thanks again!
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Sent from the R help
On Dec 1, 2010, at 1:12 PM, Charles C. Berry wrote:
On Wed, 1 Dec 2010, cmccar...@bmcc.cuny.edu wrote:
Hi,
Suppose I have the following data
name score
Abel88
Baker 54
Charlie77
stored a table called myData.
I want to write a function that will create a table which
David Winsemius wrote:
...BUT NOT SHOWN US CODE
OR SAMPLE DATA.
Hi and thank you for your help.
For instance, here's my code:
legend(topleft, inset = .05, title=Water masses, pch = c(22,25,21), lty
= c(4,1,2), lwd = 1, c(North,Central,South), horiz = F, pt.bg
Thank you sir for your answer. I'll take a look at the original legend
function and modify it for my own purpose.
With regards,
Phil
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Dear R-users,
I'm trying to work out a way to set default values for arguments in a function
which includes the optional argument '...'.
In practice, I have a 'plot' method for a function which specifies different
types of plots. Every different plot should have different default arguments
Hi
On 2/12/2010 4:55 a.m., Mark Ebbert wrote:
Dear R Gurus,
I have a fairly simple problem, but I haven't been able to find the
answer on 'the google' or in the r-help archives.
I am generating plots on both Windows and OS X where I need to
guarantee that the font used is Arial. In my plot
Hi:
On Wed, Dec 1, 2010 at 7:49 AM, CALEF ALEJANDRO RODRIGUEZ CUEVAS
alejandro.rodriguez.cue...@gmail.com wrote:
Hello dudes.
I'm developing VAR analysis based on suggestions made by Horváth in its
paper Canonical Correlation Analysis and Wiener-Granger Causality Tests.
Poor Horvath has
I think both responses so far have missed the point, (assuming the O was a typo
for zero).
That is:
seq(0:1)
[1] 1 2
when
seq(0,1)
[1] 0 1
was intended.
Ray Brownrigg
On Wed, 01 Dec 2010, Ista Zahn wrote:
So you are warning us that you must type zero instead of the letter O
when we want to
Tingting Zhan tingting.zhan at jefferson.edu writes:
Hi all,
I have the output of summary() of an lme object called lme.exp1, for
example
#
summary(lme.exp1)
[snip]
for the common variance parameter sigma. But if I need the
I have a matrix with 3 years of data (2006, 2009, 2010). I am trying to split
this matrix by year so that I have 3 separate matrices. My matrix looks like
this:
Q16.1 Year Gender Grade1 3 2006 1 52 2 2006 0
53 3 2006 0 54 3 2006 0
Hi,
Can someone tell me how to draw a histogram for the following summary?
Richard Minnie Albert Helen Joe Kingston
1233 56 6715 66
The summary tell that Richard has occurrence 12, Minnie has occurrence 33,
and so on. I would like to view this
Try:
plot (myCatVariable)
Andrew Miles
Department of Sociology
Duke University
On Dec 1, 2010, at 2:51 PM, phoebe kong wrote:
Hi,
Can someone tell me how to draw a histogram for the following summary?
Richard Minnie Albert Helen Joe Kingston
1233 56 67
Hi Ali,
Check
?split
HTH,
Jorge
On Wed, Dec 1, 2010 at 2:50 PM, Ali S wrote:
I have a matrix with 3 years of data (2006, 2009, 2010). I am trying to
split this matrix by year so that I have 3 separate matrices. My matrix
looks like this:
Q16.1 Year Gender Grade1 3 2006 1
Dear All,
I am using a Procrustes analysis to compare two NMDS ordinations for the
same set of sites. One ordination is based on fish data, the other is based
on invertebrate data. Ordinations were derived using metaMDS() from the
{vegan} library as follows:
fish.mds-metaMDS(fish.data,
That did it. Thanks!
On Dec 1, 2010, at 12:38 PM, Paul Murrell wrote:
Hi
On 2/12/2010 4:55 a.m., Mark Ebbert wrote:
Dear R Gurus,
I have a fairly simple problem, but I haven't been able to find the
answer on 'the google' or in the r-help archives.
I am generating plots on both
Hi:
When the question is: 'Are there any functions in R for pick your topic?',
package sos is a good place to start:
library(sos) # install if necessary
findFn('MMeans')
Well actually, MMMeans and MMruns came up dry, but Michaelis-Menten is a
commonly occurring model in the biosciences:
This would not draw a histogram.
On Wed, Dec 1, 2010 at 11:54 AM, Andrew Miles rstuff.mi...@gmail.comwrote:
Try:
plot (myCatVariable)
Andrew Miles
Department of Sociology
Duke University
On Dec 1, 2010, at 2:51 PM, phoebe kong wrote:
Hi,
Can someone tell me how to draw a histogram
Antonio,
You need to compare the names of list(...) with the arguments you wish to
check. Here's one way to do so (note that I replaced c with d, because c
is a function):
f - function(a, ...) {
argnames - names(list(...))
# check whether b is an argument
if(!(b %in%
Hi Phoebe,
Try
x - c(12, 33, 56, 67, 15, 66)
names(x) - c('Richard','Minnie','Albert','Helen','Joe','Kingston')
barplot(x, las = 1, space = 0)
HTH,
Jorge
On Wed, Dec 1, 2010 at 2:51 PM, phoebe kong wrote:
Hi,
Can someone tell me how to draw a histogram for the following summary?
thank you, I'll have a good look and come back to you if necessary
Dr. Iasonas Lamprianou
Assistant Professor (Educational Research and Evaluation)
Department of Education Sciences
European University-Cyprus
P.O. Box 22006
1516 Nicosia
Cyprus
Tel.: +357-22-713178
Fax: +357-22-590539
Hi
On 1/12/2010 4:44 a.m., Peter Ehlers wrote:
On 2010-11-30 04:56, Ben Tupper wrote:
Hi,
I thought it might help if I posted the resulting images.
This is the pdf file where the map polygons are not clipped to the
plotting boundary.
http://dl.dropbox.com/u/8433654/test-map.pdf
And this is
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