Hi,
Suppose i have generated an object using the following :
fit - rpart(Kyphosis ~ Age + Number + Start, data=kyphosis)
And when i print fit, i get the following :
n= 81
node), split, n, loss, yval, (yprob)
* denotes terminal node
1) root 81 17 absent (0.7901235 0.2098765)
2)
On Sun, 12 Dec 2010, jagdeesh_mn wrote:
Hi,
Suppose i have generated an object using the following :
fit - rpart(Kyphosis ~ Age + Number + Start, data=kyphosis)
And when i print fit, i get the following :
n= 81
node), split, n, loss, yval, (yprob)
* denotes terminal node
1) root 81 17
Hi. In a data set I have a variable that takes values from 1 to 14. For each
subgroup of values of this variable, I would like to obtain some descriptive
statistics of other variables present in the data set. I've been trying with
a for loop but I couldn't get nothing. Could you please suggest me
?aggregate
?doBy::summaryBy
Le 12/13/2010 11:04, effeesse a écrit :
Hi. In a data set I have a variable that takes values from 1 to 14. For each
subgroup of values of this variable, I would like to obtain some descriptive
statistics of other variables present in the data set. I've been trying
Which version of R and sampling? Where is the reproducible code?
Uwe Ligges
On 11.12.2010 16:16, andrija djurovic wrote:
Hi R users.
I have a problem with function strata in sampling packages.
st0 = strata(dom, stratanames=stratas, size=sample.size,
method=systematic,pik, FALSE)
Error in
It does for me under R-2.12.0 32-bit on Windows with the windows()
device, so:
Which version of R, which OS, which device do you use?
Uwe Ligges
On 13.12.2010 07:30, Marcin Kozak wrote:
Dear All,
I've been playing with pty, and it seems it does not produce square
plots as it is expected
On 12/13/2010 09:04 PM, effeesse wrote:
Hi. In a data set I have a variable that takes values from 1 to 14. For each
subgroup of values of this variable, I would like to obtain some descriptive
statistics of other variables present in the data set. I've been trying with
a for loop but I
R-11.1 on both 32-bit and 64-bit on Windows with the windows() device.
Best
Marcin
2010/12/13 Uwe Ligges lig...@statistik.tu-dortmund.de:
It does for me under R-2.12.0 32-bit on Windows with the windows() device,
so:
Which version of R, which OS, which device do you use?
Uwe Ligges
A nice way to obtain summary for data is to use summary.formula in Hmisc
package.
Justin BEM
BP 1917 Yaoundé
Tél (237) 76043774
De : Jim Lemon j...@bitwrit.com.au
À : effeesse scarpin...@gmail.com
Cc : r-help@r-project.org
Envoyé le : Lun 13 décembre 2010,
Dear Emmanuel and dear list,
Therefore, I let this problem to sleep. However, I Cc this answer (with
the original question below) to Max Kuhn and Friedrich Leisch, in the
(faint) hope that this feature, which does not seem to have been missed
by anybody in 8 years,
I've been missing it every
Hi,
I have two matrices containing some probabilities score obtained from
two different prediction programs. Now, I want to compare these two matrices
to measure the difference. Could you please suggest some method to do this
in R.
Thanks
Sabari
[[alternative HTML version deleted]]
Another way is the remix function of the remix package.
On Monday, December 13, 2010, justin bem justin_...@yahoo.fr wrote:
A nice way to obtain summary for data is to use summary.formula in Hmisc
package.
Justin BEM
BP 1917 Yaoundé
Tél (237) 76043774
On 13.12.2010 11:29, Marcin Kozak wrote:
R-11.1
This one does not exist.
Please try R-2.12.0 (but it also worked with R-2.11.1 if you meant that).
My guess is that you are confusing plotting region with device region.
In order to get a squared device region, you have to ask the device
Hello,
I'm looking for an easy way to display a data.frame (or other variables)
page by page, similarly to what is possible on a file using the more command
in a standard UNIX shell. Any help would be greatly appreciated.
Thanks
Alexandre
[[alternative HTML version deleted]]
On Mon, 13 Dec 2010, Uwe Ligges wrote:
It does for me under R-2.12.0 32-bit on Windows with the windows() device,
so:
Which version of R, which OS, which device do you use?
Since (s)he used windows() we know the OS. But I think one possible
explanation is on the help page, arguments
From: fe...@nfrac.org
Date: Sun, 12 Dec 2010 11:47:55 +1100
Subject: Re: [R] overlap different line in a xyplot (lattice)
To: ehl...@ucalgary.ca
CC: nutini.france...@gmail.com; r-help@r-project.org
On 12 December 2010 00:08, Peter Ehlers ehl...@ucalgary.ca wrote:
On 2010-12-11 03:12,
Prof Brian Ripley wrote:
On Sun, 12 Dec 2010, jagdeesh_mn wrote:
Hi,
Suppose i have generated an object using the following :
fit - rpart(Kyphosis ~ Age + Number + Start, data=kyphosis)
And when i print fit, i get the following :
n= 81
node), split, n, loss, yval, (yprob)
*
Goodmorning to everyone,
I'm new so sorry for bad english and formulation.
I go to the point: I am using since months the retrieve.nc function from
clim.pact to extract data from netcdf files. I always had no problem, but
some days ago I updated both R and the package to the latest versione
Dear [R] Users,
I have implemented a linear model with this syntax:
model- lm (var_dependent ~ var_indipendent + factor + var_indipendent :
factor, dataframe)
anova (model)
Response: var_dependent
Df Sum Sq Mean Sq F value
Pr(F)
This message also reports wrong estimates produced by lmRob.fit.compute()
for nested factors when using the correct contrast matrix.
And in these respects, I have found that S-Plus behaves the same way as R.
Using the three available contrast types (sum, treatment, helmert)
with lm() or
to add to Michael's response:
http://www.statmethods.net/advgraphs/parameters.html
On Mon, Dec 13, 2010 at 2:23 AM, Michael Bedward
michael.bedw...@gmail.com wrote:
Hello Erin,
Try this...
plot(x, y, type=b, pch=16)
Michael
On 13 December 2010 18:11, Erin Hodgess
Hello Petr,
don't want to convince you. If you like the following:
x - factor(1:4, labels=c(one, two, three, four))
y - factor(3:5, labels=c(three, four, five))
data.frame(character=c(as.character(x), as.character(y)), numeric=c(x, y))
character numeric
1 one 1
2 two
On 10/12/10 02:56:13, jothy wrote:
Am working on neural network.
Below is the coding and the output [...]
summary (uplift.nn)
a 3-3-1 network with 16 weights
options were -
b-h1 i1-h1 i2-h1 i3-h1
16.646.62 149.932.24
b-h2 i1-h2 i2-h2 i3-h2
-42.79 -17.40 -507.50
On 10/12/10 03:45:46, sadanandan wrote:
I am trying to develop a neural network with single target variable and 5
input variables to predict the importance of input variables using R. I used
the packages nnet and RSNNS. But unfortunately I could not interpret the out
put properly and the
Dear Researchers,
I am looking for to read a SAS macro in R. Although I searched it on web, I
couldnât find anything.
Can you help me or direct me?
Thank you for your interest and patience.
Best.
Ozgur
[[alternative HTML version deleted]]
On 10/12/10 23:26:28, dorina.lazar wrote:
I am looking for a clustering method usefull to classify the countries in
some clusters taking account of: a) the geographical distance (in km)
between countries and b) of some macroeconomic indicators (gdp, life
expectancy...).
Hi Dorina,
before
On 2010-12-13 02:49, Alexandre CESARI wrote:
Hello,
I'm looking for an easy way to display a data.frame (or other variables)
page by page, similarly to what is possible on a file using the more command
in a standard UNIX shell. Any help would be greatly appreciated.
How about View(mydata)?
On 12/13/2010 07:14 AM, Özgür Asar wrote:
Dear Researchers,
I am looking for to read a SAS macro in R. Although I searched it on web, I
couldn’t find anything.
Are you hoping just to read it in, or to actually have it
execute the macro as SAS would?
What gives you the idea the latter is
On Dec 13, 2010, at 8:14 AM, Özgür Asar wrote:
Dear Researchers,
I am looking for to read a SAS macro in R. Although I searched it on
web, I couldn’t find anything.
Can you help me or direct me?
fortune(SAS)
For almost 40 years SAS has been the primary tool for statisticians
On 2010-12-13 03:13, Francesco Nutini wrote:
From: fe...@nfrac.org
[...snip...]
xyplot(y1 + y2 ~ x | sites, DF, type = b)
Great Felix! this is what I was looking for!
But if y1 and y2 have a different scales? Can I plot, for example y2, on
secondary axis?
There are probably good
I am sorry, but I cannot understand how to use the summary function. Maybe,
if I describe my needs, you could sketch a line that could work.
In the data set variable V can take values 1 to 14. For the subgroup of
individuals where V takes value =1 I want the mean and variance of a
certain set of
Consider the following missing data problem:
y = c(1, 2, 2, 2, 3)
a = factor(c(1, 1, 1, 2, 2))
b = factor(c(1, 2, 3, 1, 2))
fit = lm(y ~ a + b)
anova(fit)
Analysis of Variance Table
Response: y
Df Sum Sq Mean SqF valuePr(F)
a 1 0.8 0.8 1.3637e+33 2.2e-16
I would suggest what we already suggested to you:
?aggregate
?by
?doBy::summaryBy
We could help you more precisely if you could provide a reproducible
example, as explained in the posting guide (see link at the end of every
email from this list)
Ivan
Le 12/13/2010 15:14, effeesse a écrit :
Dear Sabari, if you need a single number for comparison then there could be
many options. You can calculate smallest absolute eigen value, or may be the
determinant (i.e. a measure of volumn of matrices) or may be the smallest
element in absolute term, depending on your research need.
Thanks,
--
hi
thanks for your suggestion and reply. let me try it out.
With Warm Wishes and Regards
A. Abdul Rasheed, M.C.A., M.E., Ph.D.,
Assistant Professor,
Department of Computer Applications,
Valliammai Engineering College,
SRM Nagar,
With summary do this
my.summary-function(x) c(mean(x),var(x))
summary(v1~V, fun=my.summary,data=df)
summary(v2~V, fun=my.summary,data=df)
summary(v3~V, fun=my.summary,data=df)
summary(v4~V, fun=my.summary,data=df)
summary(v5~V, fun=my.summary,data=df)
If you want you get the mean of all
Dear R users,
Suppose I have an vector like this:
animal - c(Tiger,Panda)
I would like to know is there any function that check for the
existence of certain item in a vector.
e.g.
func(Tiger,animal) # check for the existence of Tiger
TRUE
func(Acacia,animal) #Acacia is not an item of the
Hi,
See ?%in% or ?match
animal - c(Tiger,Panda)
Tiger %in% animal
[1] TRUE
Acacia %in% animal
[1] FALSE
Panda %in% animal
[1] TRUE
HTH,
Ivan
Le 12/13/2010 15:48, C.H. a écrit :
Dear R users,
Suppose I have an vector like this:
animal- c(Tiger,Panda)
I would like to know is there any
Hi,
I am using k means algorithm for clustering.My data contains a few null/NA
values.kmeans doesnt cluster with those values.Are there any option like
na.omit which can avoid these null values and cluster the remaining values?
Thanks,
Raji
--
View this message in context:
Hi CH,
Check
?is.element
?%in%
HTH,
Jorge
On Mon, Dec 13, 2010 at 9:48 AM, C.H. wrote:
Dear R users,
Suppose I have an vector like this:
animal - c(Tiger,Panda)
I would like to know is there any function that check for the
existence of certain item in a vector.
e.g.
CH,
How about any:
any(Tiger == animal)
The function which will tell you the index if any match
which(Tiger == animal.
You should also look at the match funciton.
Dave
From:
C.H. chainsawti...@gmail.com
To:
R-help r-help@r-project.org
Date:
12/13/2010 08:50 AM
Subject:
[R] check for
Dear all,
I've written a small booklet on using R for biomedical statistics
(mostly focussed on cohort and case-control studies), available here
under a Creative Commons Attribution 3.0 License :
A Little Book of R for Biomedical Statistics
batchfiles is a set of batch, javascript and HTML
Application files that are useful for running R and
associated programs on Windows.
Version 0.6-0 updates them for the new architecture
specific directory structure in R 2.12.0 .
A few of the lesser used utilities have been dropped.
Each
Dear R-Users,
I am currently trying to fit a tensorial function in its principal
coorinate system. The function is given by:
1~(x1^2 + x2^2 + x3^2 - chi0*(x1*x2 + x1*x3 + x2*x3))/eps0^2 + (x1 + x2
+ x3)/xi0
Where eps0 = 0.0066, chi0 = -0.66 and xi0 = 0.011 are obtained from
experimental data
I asked Jeff Horner that question a while back and he said it was Linux
only. He doesn't have time to create a windows version.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Santosh Srinivas
Sent: Saturday, December 11, 2010
On 13/12/2010 10:13 AM, Uwe Wolfram wrote:
Dear R-Users,
I am currently trying to fit a tensorial function in its principal
coorinate system. The function is given by:
1~(x1^2 + x2^2 + x3^2 - chi0*(x1*x2 + x1*x3 + x2*x3))/eps0^2 + (x1 + x2
+ x3)/xi0
Where eps0 = 0.0066, chi0 = -0.66 and xi0 =
TukeyHSD(fit)
Error in TukeyHSD(fit) : object 'fit' not found
TukeyHSD(anova)
Error in UseMethod(TukeyHSD) :
no applicable method for 'TukeyHSD' applied to an object of class
function
TukeyHSD(group)
Error in UseMethod(TukeyHSD) :
no applicable method for 'TukeyHSD' applied to an object
Hello,
Are there any packages which allow for a good integration between R and
LaTex / LyX? I'm interested mainly in automatic (automagic?) imports of
plots/graphics.
Thanks in advance and best regards,
Eduardo de Oliveira Horta
[[alternative HTML version deleted]]
TukeyHSD(fit)
Error in UseMethod(TukeyHSD) :
no applicable method for 'TukeyHSD' applied to an object of class lm
TukeyHSD(anova)
Error in UseMethod(TukeyHSD) :
no applicable method for 'TukeyHSD' applied to an object of class
function
TukeyHSD(group)
Error in UseMethod(TukeyHSD) :
no
Hi Sandy,
The way I'd describe it is that you expected the width parameter of
the position adjustment to be relative to the binwidth of the
histogram - but it's actually absolute, and it has to be this way
because there's currently no way for the position adjustment to know
about the parameters
Dear list
I have quite a small data set in which I need to have the following
values ignored - not used when performing an analysis but they need to
be included later in the report that I write.
Can anyone help with a suggestion as to how this can be accomplished
Values to be ignored
0 -
Hi,
I was hoping to get some advice regarding the testing of interactions, when one
factor is modelled as a random effect...
I have a model with binomial error structure where the response variable is the
proportion of time spent at the main sett (animals were tracked for 28
consecutive days
?Sweave
LyX is a bit harder, although you can probably export LyX docs to a *.tex
and Sweave those fairly painlessly.
--
Jonathan P. Daily
Technician - USGS Leetown Science Center
11649 Leetown Road
Kearneysville WV, 25430
(304) 724-4480
Is the room still a
Dear R users,
do you know how to print the latex \odot symbol subscripted to axes
labels?
Thank you in advance
Gaetano
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
what am I supposed to put into function(x)? The indicator for extracting the
subgroups?
data is the df. cluster={1,...,14}.
This is how I was compiling:
for (i in 1:14) {
my.summary-data$cluster==i c(mean(?),var(?))
summary(var_A~cluster, fun=my.summary,data=data)
summary(var_B~cluster,
On Mon, Dec 13, 2010 at 4:55 PM, Jonathan P Daily jda...@usgs.gov wrote:
?Sweave
LyX is a bit harder, although you can probably export LyX docs to a *.tex
and Sweave those fairly painlessly.
LyX can play very nicely with Sweave and R.
For the 1.6.x series, you could get started here [1]. If
On 2010-12-13 07:29, PGZC wrote:
TukeyHSD(fit)
Error in UseMethod(TukeyHSD) :
no applicable method for 'TukeyHSD' applied to an object of class lm
TukeyHSD(anova)
Error in UseMethod(TukeyHSD) :
no applicable method for 'TukeyHSD' applied to an object of class
function
TukeyHSD(group)
On Mon, Dec 13, 2010 at 8:20 AM, Ethan Arenson
ethan.a.aren...@gmail.com wrote:
Consider the following missing data problem:
y = c(1, 2, 2, 2, 3)
a = factor(c(1, 1, 1, 2, 2))
b = factor(c(1, 2, 3, 1, 2))
fit = lm(y ~ a + b)
anova(fit)
Analysis of Variance Table
Response: y
Steve Sidney sbsidney at mweb.co.za writes:
Dear list
I have quite a small data set in which I need to have the following
values ignored - not used when performing an analysis but they need to
be included later in the report that I write.
Can anyone help with a suggestion as to how
Hello R User,
I am new in R and trying to migrate from SAS. I have to convert a table that
look like this
YEARFIRMID_NAME VALUE
1994Microsoft John Doe5
1994Microsoft Mark Smith 3
1994Microsoft David Ring
Can anybody tell me why this is happening?
library( Defaults)
ls()
[1] class foomlct
[4] mlctTheme overlayFunctionpct
[7] priprimaryFractionreclassFractions
[10] reclassMatrix reclassNames
An alternative way of getting summary statistics by a grouping
variable is to use describe.by in the psych package:
using Jim Lemon's example:
library(psych)
testmat-data.frame(sample(1:14,50,TRUE),rnorm(50),runif(50)) #make
up the data
describe.by(test.mat,testmat[1]#get descriptive
Do it with aggregate(), something like this should do:
aggregate(.~cluster, FUN=summary, data=data)
Now if you don't want to run summary(), replace it with the function
you'd like.
HTH,
Ivan
Le 12/13/2010 17:17, effeesse a écrit :
what am I supposed to put into function(x)? The indicator
Hi everyone,
I am new to R and I have a beginner's question on Time Series: I have an
irregular time series that goes like this:
TIMESTAMP PRICE
2010-11-29 12:29:28 25.255
2010-11-29 12:30:47 25.255
2010-11-29 12:36:58 25.230
2010-11-29 12:43:14 25.235
Values to be ignored
0 - zero and 1 this is in addition to NA (null)
The reason is that I need to use the log10 of the values when performing
the calculation.
Currently I hand massage the data set, about a 100 values, of which less
than 5 to 10 are in this category.
This is probably a
On Mon, Dec 13, 2010 at 11:37 AM, matteop mpr...@iese.edu wrote:
Hello R User,
I am new in R and trying to migrate from SAS. I have to convert a table that
look like this
YEAR FIRM ID_NAME VALUE
1994 Microsoft John Doe 5
1994 Microsoft
Hi! I'm just getting started with R (and with the analysis of large
datasets in general). I have several beginner-level questions whose
answers I have not been able to find, and was hoping one of you would
be kind enough to throw me a cluebrick or two.
I have a 6-dimensional numeric array
Thanks to R ... I just got myself a new ubuntu setup just an hour back! It
feels good! :-)
On Mon, Dec 13, 2010 at 8:46 PM, Bos, Roger roger@rothschild.comwrote:
I asked Jeff Horner that question a while back and he said it was Linux
only. He doesn't have time to create a windows version.
Thanks for the questions.
1) The data represents micro-organism counts and a count of zero in
this case is highly unlikely given the info we have; including the other
participants.
2) The data is submitted in duplicate and then a standardised sum and
difference is established and is used to
Hi Patrick,
Thanks! That worked perfectly!
M
--
View this message in context:
http://r.789695.n4.nabble.com/Projecting-data-on-a-world-map-using-long-lat-tp3081298p3085834.html
Sent from the R help mailing list archive at Nabble.com.
__
I want to change leaf color by group in hclust plot.
I've seen several answers about A2R package but I cannot install A2R
and Rtools in windows.
Do you know how to install A2R package in windows or how to change
leaf color by group in hclust plot?
Thank you in advance,
Soyeon
I'm attempting to calculate a regression in R that I normally use Prism for,
because the formula isn't pretty by any means.
Prism presents the formula (which is in the Prism equation library as
Heterologous competition with depletion, if anyone is curious) in these
segments:
KdCPM =
Thanks for the comments
Please see my reply to Stavros - the counts represent organisms and btw
both mean and the median are virtually unaffected by the removal of
these valuse.
Furthermore, experience rather than statistics indicates that these
values are in fact gross errors and as you of
What error do you get when using:
install.packages(A2R)
?
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com
One possibility, though not as simple as what you ask for, is to use etxtStart
and friends from the TeachingDemos package.
Other possibilities include using gui interfaces to R, possibilities (though
they may do more than you ask, and color might be different) include emacs/ess;
vim; jgr; and
Dear all,
In a function I paste a string and convert it to a formula which I pass
to lm[e]. The idea is to write a function which takes the name of the
response variable and the explanatory variable and the data frame as an
argument and calculates an lm[e]. (see example below)
This works fine,
Inline below. -- Bert
On Mon, Dec 13, 2010 at 9:42 AM, Steve Sidney sbsid...@mweb.co.za wrote:
Thanks for the questions.
1) The data represents micro-organism counts and a count of zero in this
case is highly unlikely given the info we have; including the other
participants.
?? Censoring
An example is described here that you can adapt:
http://r.789695.n4.nabble.com/coloring-leaves-in-a-hclust-or-dendrogram-plot
-tt795496.html#a795497
HTH. Bryan
*
Bryan Hanson
Professor of Chemistry Biochemistry
DePauw University, Greencastle IN USA
On 12/13/10 12:54 PM, Soyeon
On Dec 13, 2010, at 12:20 PM, Roy Shimizu wrote:
Hi! I'm just getting started with R (and with the analysis of large
datasets in general). I have several beginner-level questions whose
answers I have not been able to find, and was hoping one of you would
be kind enough to throw me a
Hi All,
I generated 5000 samples using the following script
test- rnorm(5000,1000,100)
test1 - subset(test, subset=(test 1100))
d - density(test)
plot(d, main=Density of production)
abline(v=mean(test1)
I wanted to do the following but faced
For data frames the best is probably the View function (note capitol V) which
opens the data frame in a spreadsheet like window that you can scroll through.
For more complicated, list or list-like objects, look at TkListView in the
TeachingDemos package.
For more general investigation of data
- --- included message
i try to calculate the probabilty to survive a given time by using the
estimated survival curve by kaplan meier.
What is the right way to do that? as far as is see i cannot use the
predict-methods from the survival package?
end inclusion
The
Here's one way to do what I think you want:
test- rnorm(5000,1000,100)
test1 - subset(test, subset=(test 1100))
d - density(test)
plot(d, main=Density of production, xlab=)
lines(d$x[d$x 1100], d$y[d$x 1100], col=blue, lwd=2)
curveheight - d$y[abs((d$x -
Thorn,
Here's how I do it:
retval - list(as.name('lm'),
formula=as.formula(paste(Response, ~, Explan,
sep='')),
data=as.name(Data))
#... optionally add other arguments
retval - eval(as.call(retval))
Dave
From:
Thaler, Thorn, LAUSANNE, Applied
Thanks Sarah,
1. to shade or color (blue) the curve using the criterion that any values
greater than 11,000
I think I was not clear in the above point. I want shade not the line but
the area under the curve,
and
Your last line of code,
segments(x0=mean(test1), y0=0, y1=curveheight)
gave me
You could also use aggstat() of package tdisplay (available at
http://forums.cirad.fr/logiciel-R/viewtopic.php?t=3367). See the help
page.
mydata - data.frame(
+ y1 = c(NA, rnorm(n = 8, mean = 10, sd = 5), NA),
+ y2 = c(rep(NA, 2), rnorm(n = 6, mean = 10, sd = 5), rep(NA, 2)),
+ y3 =
Googles Huge Change and How it affects you.
Anyone can now post bad reviews and kill your rank.
We post good reviews and improve your rank.
We post good reviews to keep others from killing your rank.
Google: Judge, Jury and Online Shopping Executioner
Google rank is based on
Hi,
stepAIC generic plot function creates useful graphics for the diagnosis of
multiple regressions. To create predicted versus observed plots, I use to
look for the coefficients, copy them by hand, calculate R², then plot. Is
there a more automated way to plot predicted versus observed with its
Oh dear oh dear!!! another arrogant statistician/scientist
One asks for help and instead one gets an ear full!!!
So much for the much vaunted helpful R community.
But thanks anyway, I guess you were trying
Steve
On 2010/12/13 08:17 PM, Bert Gunter wrote:
Inline below. -- Bert
On
On Mon, Dec 13, 2010 at 2:12 PM, Ashta sewa...@gmail.com wrote:
Thanks Sarah,
1. to shade or color (blue) the curve using the criterion that any values
greater than 11,000
I think I was not clear in the above point. I want shade not the line but
the area under the curve,
Here's an example
Steve Sidney sbsidney at mweb.co.za writes:
Oh dear oh dear!!! another arrogant statistician/scientist
One asks for help and instead one gets an ear full!!!
So much for the much vaunted helpful R community.
But thanks anyway, I guess you were trying
Steve
I know I
On Mon, Dec 13, 2010 at 7:36 PM, Steve Sidney sbsid...@mweb.co.za wrote:
Oh dear oh dear!!! another arrogant statistician/scientist
One asks for help and instead one gets an ear full!!!
So much for the much vaunted helpful R community.
But thanks anyway, I guess you were trying
Hello,
Does anyone know of a function that will determine whether
or not a formula object has a left hand side?
I.e., can differentiate between
y ~ x + z
and
~ x + z
Perhaps I'm overlooking the obvious...
Thanks!
__
R-help@r-project.org mailing
attr(terms(formula), response) is 1 if
the formula has a left hand side and 0
otherwise.
At a lower level, you can look at
length(formula): 2 means there is no LHS,
3 means there is (any other value indicates
that someone made a call object that the
parser would not make).
Bill Dunlap
Spotfire,
Erik -
Perhaps the response attribute of the terms() function?
formula1 = formula(y ~ x + z)
formula2 = formula(~x + z)
attr(terms(formula1),'response')
[1] 1
attr(terms(formula2),'response')
[1] 0
Although there may be more direct ways.
- Phil
On 2010-12-13 11:36, Steve Sidney wrote:
Oh dear oh dear!!! another arrogant statistician/scientist
One asks for help and instead one gets an ear full!!!
So much for the much vaunted helpful R community.
But thanks anyway, I guess you were trying
Steve
Ouch!!
I didn't offer advice
Excellent, thank you all!
William Dunlap wrote:
attr(terms(formula), response) is 1 if
the formula has a left hand side and 0
otherwise.
At a lower level, you can look at
length(formula): 2 means there is no LHS,
3 means there is (any other value indicates
that someone made a call object that
I tried hard to write an automagic script to configure LyX so that you
don't need to go to the instructions on CRAN
(http://cran.r-project.org/contrib/extra/lyx/):
http://yihui.name/en/2010/10/how-to-start-using-pgfsweave-in-lyx-in-one-minute/
This works for LyX 1.6.x and major OS'es with
Greetings
In attempting to create a date variable based on month (e.g.,
February, April, etc.) and year (e.g., 2006) data, wherein I converted
Month to a factor with Jan=1...Dec=12, I used the following command:
data$Date-mdy.date(month=data$Month,day=15,year=data$Year)
however, I get a
Folks:
This is off topic, but I believe many R-Help participants would be
interested in this. My apologies to my British colleagues, who
probably already know about this, and to others for whom this is a
waste of their time.
Dr. Ben Goldacre, a British Physician and science columnist, has
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