I want to sample from the ID. For each ID, i want to have 2 set of data. I
try the sample() function but it didn't work.
x-data.frame(id=c(1,1,1,2,2,2,2,3,3,3,4,4), v1=c(1:12), V2=c(12:23))
x
id v1 V2
1 1 1 12
2 1 2 13
3 1 3 14
4 2 4 15
5 2 5 16
6 2 6 17
7 2 7 18
8 3
Hi thanks ! that works perfectly ! now I am wodering how to create a new
table ,
I run the codes:
x-read.table(C:/R/DATA.txt,colClasses=c(Date,character,integer),
header=T)
DateTime-as.POSIXct(paste(x[,1],x[,2]),format=%Y-%m-%d%H%M%S)
and get :
2004-11-01 23:33:11 GMT
2004-11-01 23:42:27
Hi,
I am using a very simple R function to get each row from the
attached file and run Wilcox.test between columns 1-3 and 4-12. However, I keep
getting an error message. The data files is attached. Any suggestion?
Thank you.
Rong
Error message:
+ return c$p.value
Error: unexpected
thx for your suggestions , i have made it csv file,and it looks:
data‐read.table('E:/my documents/r/1.csv',header=TRUE)
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings,
:
line 1 did not have 2 elements
is there wrong with the data?
--
View this message in
Dear Sir/Madam,
I would like to know what is the maximum number of observations a
single file must have when using R. I am asking this because am trying
to do research on banking transactions and i have around 49million
records. Can R handle this? Advise with regard to this.
Hello Marta,
have you read ?coeftest and ? VAR carefully enough? The function does expect a
lm/glm object for x as argument. Hence, the following does work:
library(vars)
data(Canada)
myvar - VAR(Canada, p = 2, type = const)
lapply(myvar$varresult, coeftest)
Best,
Bernhard
Hi, how could I add a small text note to a vertical or horizontal line?
x - rnorm(50)
y - rnorm(50)
plot(x,y)
abline(h=0)
I would like to add the text cutoff just above it.
Thanks,
D.
[[alternative HTML version deleted]]
On 02/17/2011 10:16 AM, Nasila, Mark wrote:
Dear Sir/Madam,
I would like to know what is the maximum number of observations a
single file must have when using R. I am asking this because am trying
Dear Mark,
to do research on banking transactions and i have around 49million
records. Can
On Thu, 17 Feb 2011, Nasila, Mark wrote:
Dear Sir/Madam,
I would like to know what is the maximum number of observations a
single file must have when using R. I am asking this because am trying
to do research on banking transactions and i have around 49million
records. Can R handle this?
On 2011-02-16 13:29, Sam Steingold wrote:
how do I create a data frame with the given column names
_NOT KNOWN IN ADVANCE_?
i.e., I have a vector of strings for names and I want to get an _EMPTY_
data frame with these column names.
is it at all possible?
It's not really clear to me what you
On 2011-02-17 01:54, David A. wrote:
Hi, how could I add a small text note to a vertical or horizontal line?
x- rnorm(50)
y- rnorm(50)
plot(x,y)
abline(h=0)
I would like to add the text cutoff just above it.
text(-1.5, 0.1, cutoff, col = red)
see ?text.
Peter Ehlers
Thanks,
D.
Hi ,
what about split function ?
?split divided x into 2 data.frame
a-split(x,1:2)
a[[1]] first data frame
a[[2]] second data frame
regrads
M
Le 17/02/11 05:35, yf a écrit :
I want to sample from the ID. For each ID, i want to have 2 set of data. I
try the sample() function but it
On 11-02-16 16:29, Sam Steingold wrote:
how do I create a data frame with the given column names
_NOT KNOWN IN ADVANCE_?
i.e., I have a vector of strings for names and I want to get an _EMPTY_
data frame with these column names.
is it at all possible?
Read the posting guide, provide example
I'm trying to work out the simplest way to remove the upper and lower
quantiles, in this case upper and lower 25% from an array. I can do it in two
steps but when I try it in one, it fails. Is there something simple missing
from my syntax or are there other simple elegant way to accomplish
You need two logical test and then combine them with (AND) or | (OR)
i[quantile(i,.25) = i i = quantile(i,.75)]
Best regards,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie
have a look at the help page for ?'', try also this:
i - 1:20
qs - quantile(i, c(.25, 0.75))
i[i qs[1] i qs[2]]
I hope it helps.
Best,
Dimitris
On 2/17/2011 11:08 AM, Maas James Dr (MED) wrote:
I'm trying to work out the simplest way to remove the upper and lower
quantiles, in this
Try this:
i[quantile(i,.25) i i quantile(i,.75)]
Andrija
On Thu, Feb 17, 2011 at 11:08 AM, Maas James Dr (MED) j.m...@uea.ac.ukwrote:
I'm trying to work out the simplest way to remove the upper and lower
quantiles, in this case upper and lower 25% from an array. I can do it in
two steps
On 2011-02-16 09:42, Sam Steingold wrote:
Description:
'lapply' returns a list of the same length as 'X', each element of
which is the result of applying 'FUN' to the corresponding element
of 'X'.
I expect that when I do
lapply(vec,f)
f would be called _once_ for each
Thierry,
you forgot !
i[! quantile(i,.25) = i i = quantile(i,.75)]
Best
M
Le 17/02/11 11:18, ONKELINX, Thierry a écrit :
You need two logical test and then combine them with (AND) or | (OR)
i[quantile(i,.25)= i i= quantile(i,.75)]
Best regards,
Thierry
Thierry,
you forgot !
i[! quantile(i,.25) = i i = quantile(i,.75)]
Best
M
Le 17/02/11 11:18, ONKELINX, Thierry a écrit :
You need two logical test and then combine them with (AND) or | (OR)
i[quantile(i,.25)= i i= quantile(i,.75)]
Best regards,
Thierry
Dear all,
two days ago I was trying to run a bunch of adaptIntegrate() functions (double
integrals) into my 4 core pc.
As I was not satisfied about my pc's performance I tried also to run my code to
another computer that has 8 or 16 cores. Unfortunately I didnt get any really
decent
Here's one more way:
i[ findInterval(i, quantile(i, c(.25, .75))) == 1 ]
Peter Ehlers
On 2011-02-17 02:08, Maas James Dr (MED) wrote:
I'm trying to work out the simplest way to remove the upper and lower
quantiles, in this case upper and lower 25% from an array. I can do it in two
steps
Dear all,
I post again my question with a new title ... please, help me!
I build a customized version of R-2.12.1 from source (under windows XP). I
work as explain in the R Installation and Adminstration manual and all
seems to be good... But When I try to uninstall this version I have the
Hi chen,
avoid naming the function with specific expressions (:,;.) and try
this code as follow
Scripranksum- function(a){
g1- c(1, 2, 3)
g2- c(4, 5, 6, 7, 8, 9, 10, 11, 12)
c- wilcox.test(a[g1], a[g2])
return (c$p.value)
}
Best
Mohamed
Le 17/02/11 08:15, Mr rong chen a écrit :
--- On Thu, 2/17/11, John Kane jrkrid...@yahoo.ca wrote:
From: John Kane jrkrid...@yahoo.ca
Subject: RE: [R] Variable length datafile import problem
To: Ingo Reinhold in...@kth.se
Received: Thursday, February 17, 2011, 5:54 AM
Generally most of the gurus are in
this list. Hopefully
On 11-02-16 10:23 PM, Sébastien Bihorel wrote:
Dear R-users,
I have some questions about the scope of functions, which I would like to
illustrate with the following example:
### First example
require(Hmisc)
combine.levels- function(x,y) browser()
whatever- function(x,y) combine.levels(x,y)
On 11-02-17 5:44 AM, Jeremy MAZET wrote:
Dear all,
I post again my question with a new title ... please, help me!
I build a customized version of R-2.12.1 from source (under windows XP). I
work as explain in the R Installation and Adminstration manual and all
seems to be good... But When I try
Here is a method that works despite generating a warning:
cbind(X, z = ave(X$y, X$x, FUN = seq) - 1)
David Winsemius, MD
West Hartford, CT
I was happy a bit too early. There's still an error:
x-as.factor(c('a','a','a','a','a','b','b','b','c','d','d','d'))
y-c(1,3,6,8,8,3,4,7,5,6,7,10)
Hi RTSlider,
I suspect you rather need to use the lme command (or perhaps glmmPQL or lmer)
because you have a random predictor?
lme(fixed=LeafLength~AirTemp*SnowFreeDate,random=~1|Species)
See
http://socserv.mcmaster.ca/jfox/Books/Companion-1E/appendix-mixed-models.pdf
for a tutorial on
Hello.
I am trying to find probability density distribution that best fits my
data. Therefore, I am trying to fit several models (like gamma,
pareto, log-normal, ...) and then choose the best one using Akaike
Information Criterion (AIC).
In order to find the parameters for the power-law
On Feb 17, 2011, at 11:40 AM, Alaios wrote:
...Is it possible to split work in many cores in R and if yes how is this
library called?
I'd recommend the mclapply function in the multicore package. The only
drawback is that you can't run your code in a GUI any more.
Ben Haller
McGill
Hi R-helpers,
Did any of you get a chance to look into this issue?i am kind of stuck in my
work due to this..Is there any R command/option that can be used to overcome
this?
Regards,
Raji
--
View this message in context:
On Wed, Feb 16, 2011 at 12:36 PM, Hasan Diwan
di...@economicriskmanagement.com wrote:
Rjdbc consistently gives me an execution error with postgresql 9.0s JDBC4
driver. It's probably something trivial so am including my code below:
library(RJDBC)
param - 249
param2 - 188129
postgres -
On Tue, Feb 15, 2011 at 9:44 PM, Lancaster, Vicki
vicki.lancas...@fda.hhs.gov wrote:
First I have read all the previous post on error bars segments as well as
the Lattice book by Sarkar.
I am using xyplot, there are 2 panels, each panel displays the measurements
from 5 matrices over
try this:
x - factor(c('a','a','a','a','a','b','b','b','c','d','d','d'))
y - c(1,3,6,8,8,3,4,7,5,6,7,10)
X - data.frame(x, y)
cbind(X, z = ave(X$y, X$x,
FUN = function (x) match(x, unique(x)) - 1))
I hope it helps.
Best,
Dimitris
On 2/17/2011 11:15 AM, mathijsdevaan wrote:
Here is a
Hi,
I have an assignment in which I am asked to use the Oaxaca decomposition. I have
not been able to find any support for this in R using rseek.
Is anybody aware of an implementations of this in R? I know there is one for
Stata, but I do not have easily access to Stata.
Thanks,
Rasmus
[1]
Thanks! That solved the problem.
Dimitris Rizopoulos-4 wrote:
try this:
x - factor(c('a','a','a','a','a','b','b','b','c','d','d','d'))
y - c(1,3,6,8,8,3,4,7,5,6,7,10)
X - data.frame(x, y)
cbind(X, z = ave(X$y, X$x,
FUN = function (x) match(x, unique(x)) - 1))
I hope it
Hi,
You need to add parentheses around your return argument. (Please, note that
your example is not successfully because of data problem).
ranksum - function(a){
g1 - c(1, 2, 3)
g2 - c(4, 5, 6, 7, 8, 9, 10, 11, 12)
c - wilcox.test(a[g1], a[g2])
return(c$p.value)
}
[[alternative
Hello
I have a number of data files which are outputs for each step of a
simulation. The data is organized like this:
dmindmax coef
5 6 0.490981
3 8 0.098056
5 6 0.425926
6 6 0.517860
2 4 0.527778
I would
On Wed, Feb 16, 2011 at 1:13 PM, RTSlider rob.t.sli...@gmail.com wrote:
Hello all,
I’m running simple linear regressions on multiple species of plants,
comparing abiotic factor X against plant trait Y (e.g. Species1: leaf length
vs air temperature).
Ideally, what I’m looking for is an
On Feb 16, 2011, at 11:35 PM, yf wrote:
I want to sample from the ID. For each ID, i want to have 2 set of
data. I
try the sample() function but it didn't work.
You don't say _how_ you used the sample function. You should show what
code you used when stating the _something_ doesn't
He said 'pc' in the part you excised, but failed to follow the posting
guide and tell us his OS. I am guessing this means Windows, on which
multicore does not run.
There are several other solutions on CRAN: I'd suggest 'snow' which
can run over sockets on a single Windows machine, and also
Dear All,
Please consider a dataframe like the one below (I am showing only a few
rows).
role degree strength weight count disparity intermittency
P 10 82 18017 2 2.317073 5.550314e-05
P 7 529 434560 5.178466 6.904488e-03
In building a package, is it possible to make the package depend upon another
package that is only available on R-Forge (not CRAN). For example, by doing
something in the DESCRIPTION file
I'd like to add a dependency to my package such that when the user install my
package it will automatically
On 16.02.2011 22:38, poisontonic wrote:
Uwe Ligges-3 wrote:
If the available space got too fragmented, there is not single 3.8 block
of memory available any more
Is there anything I can do to prevent this?
If you did it after a fresh reboot: I don't see a way to prevent it.
I'm using the range command to get the minimum and maximum values of an array
as in
x - range(array_y)
which gives me two values such as
[1] -2 9
I need to be able to test if this range of values includes a third value. For
example I'd like to query
1) does the range of -2 to 9 include
Dear Bill,
Thank you very much for your careful discussion of the issue.
It is not surprising that the deviance is the same whether you fit the
model using a factor response with weights or individual 0/1 responses.
I think this happens because the fitted probabilities in the saturated
models
On 17.02.2011 15:29, Damian Betebenner wrote:
In building a package, is it possible to make the package depend upon another
package that is only available on R-Forge (not CRAN). For example, by doing
something in the DESCRIPTION file
I'd like to add a dependency to my package such that when
I'm using the range command to get the minimum and maximum values of an array
as in
x - range(array_y)
which gives me two values such as
[1] -2 9
I need to be able to test if this range of values includes a third value. For
example I'd like to query
1) does the range of -2 to 9 include 3,
On 2011-02-17 07:36, Maas James Dr (MED) wrote:
I'm using the range command to get the minimum and maximum values of an array
as in
x- range(array_y)
which gives me two values such as
[1] -2 9
I need to be able to test if this range of values includes a third value. For
example I'd like
On Feb 17, 2011, at 10:36 AM, Maas James Dr (MED) wrote:
I'm using the range command to get the minimum and maximum values of
an array as in
x - range(array_y)
which gives me two values such as
[1] -2 9
I need to be able to test if this range of values includes a third
value. For
Dear all
I have six variables of the average metal concentrations
Var1 4.77
Var2 23.5
Var3 5.2
Var4 12.3
Var5 42.1
Var6 121.2
I want to plot them as a barplot with error bars. Could you help me?
Cheers
Maria
[[alternative HTML version deleted]]
Hi Maria,
Look at barplot function
? barplot for help
Regards
M
Le 17/02/11 17:00, Lathouri, Maria a écrit :
Dear all
I have six variables of the average metal concentrations
Var1 4.77
Var2 23.5
Var3 5.2
Var4 12.3
Var5 42.1
Var6 121.2
I want to plot them as a barplot with error
Hello Marta,
arrg, sorry, I have not carefully enough read your message. Well, if you follow
the cited thread further down, you will find:
(and hereby directly quoting from:
https://stat.ethz.ch/pipermail/r-sig-finance/2009q2/004274.html)
snip
On Tue, 9 Jun 2009, Matthieu Stigler wrote:
Motivation: during each iteration, my code needs to collect tabular data (and
use it only during that iteration), but the rows of data may vary. I thought I
would speed it up by preinitializing the matrix that collects the data with
zeros to what I know to be the maximum number of rows. I was
Try the function ctree() in the package party or earth() in earth. You can
use factor variable as is, or you can transform the factor to binary variables
(i.e., is_P is 0 or 1, is_D is 0 or 1). In the second case, you can use any
algorithm, and earth() automatically transforms factors to
Im am curerntly trying to use R software to extract uncompressed waveform
values with I have acquired from IDLreadGLAS tool.
I am very lost with this know I have to assess the GLA01 product data,
however, any advice on the matter atall would be brilliant, particularly on
define thresholds and
Hi everybody,
I tried to analyze a custom Affymetrix 3'-biased Array. So I wanted to make
a cdf package. (My CDF file size is 1.12Go).
I tried several methods but the same error occured
Method 1
#Set the working directory
setwd(D:/Analyse R/Cel files)
#library to create cdf env
Try putting d,e,f in a list:
Xxx = list(d,e,f)
For (I in 1:length(xxx))
For (j in 1:length(xxx))
If (i!=j) bigfunction(xxx[[i]],xxx[[j]])
(bad indentation, caps thanks to outlook)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of
Dear R-list
I'm working with with geom_errorbar; specifically I'm trying to
reproduce the example Hadley Wickham have on
http://had.co.nz/ggplot2/geom_errorbar.html (all in the button of the
page) where he makes an nice plot with errorbars and then draw lines
between the points.
What confuses me
I am using VGAM package to model a multinormial outcome with spline
function. But from the following result, I only can get p-value for variable
with spline function, such as s(As). However, there is no p-value available
for variable with linear function, such as SEX, Parity. Does anybody know
Dear all,
Does anyone have any idea on how to speed up the for() loop below.
Currently it takes approximately 2 minutes and 30 seconds.
Because of the size of Nsim and N, simulating a multivariate normal
(instead of simulating Nsim times a vector of N normal distributions)
would require too
Dear MCMCglmm users,
I am currently struggling with the specification of a proper prior and model
formula for a multi-response MCMCglmm with two of the three response variables
being Gaussian and the third being za-poisson. The model includes several fixed
effects and three nested random
Thank you for your hint!
I see that there was a thread discussing implementation of what I
wanted to do (Newey-West standard errors in a VAR context), but that
there is a conflict due to how the type = const is defined in the VAR
command:
On Thu, 17 Feb 2011, Uwe Ligges wrote:
On 17.02.2011 15:29, Damian Betebenner wrote:
In building a package, is it possible to make the package depend upon
another package that is only available on R-Forge (not CRAN). For example,
by doing something in the DESCRIPTION file
I'd like to add a
If you google barplot with error bars you immediately find
http://svitsrv25.epfl.ch/R-doc/library/prada/html/barploterrbar.html .
Toby.
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf Of
Lathouri, Maria
Thanks for helping me out so generously. After reading the vignettes and the
other info I still have a question (sorry I am a R novice):
I am not so much trying to construct time series (although it comes very
close). Rather for each pair (Bi,Bj) in project (An) I am trying to sum up
the values
I hate to sound like David Have You Read The Posting Guide? Winsemius, but
there's no way for anyone to know what you are trying to accomplish here
without a lot more information. You don't show us the output you expect and
the output you got. I would expected relatedness to be on a scale
Hi all,
I'm having a problem once again, trying to do something very simple. Consider
the following data frame:
x - read.table(textConnection(locus1 locus2 locus3
A T C
A T NA
T C C
A T G), header = TRUE)
closeAllConnections()
I am trying to make a new data frame, replacing A with A/A, T with
Josh, you've made it far too complicated. Here's one simpler way (note
that I changed your read.table statement to make the values NOT factors,
since I wouldn't think you want that).
x - read.table(textConnection(locus1 locus2 locus3
+ A T C
+ A T NA
+ T C C
+ A T G), header = TRUE, as.is=TRUE)
Try this:
xNew - as.data.frame(mapply(paste, x, x, sep = /))
xNew[is.na(x)] - NA
xNew
On Thu, Feb 17, 2011 at 2:54 PM, Josh B josh...@yahoo.com wrote:
Hi all,
I'm having a problem once again, trying to do something very simple.
Consider
the following data frame:
x -
Hi,
You could use car::recode to change the levels of the factors,
library(car)
transform(x, locus1 = recode(locus1, 'A' = 'A/A' ; else = 'T/T'),
locus2 = recode(locus2, 'T'='T/T' ; 'C' = 'C/C'),
locus3 = recode(locus3, 'C'='C/C' ; 'G' = 'G/G'))
HTH,
Dear all
when I call color.scale like this:
require('plotrix')
colcolor-color.scale(c(range_sr,sr),extremes=c(red,blue))
Error in if (min(reds) 0 || max(reds) 1) reds - rescale(reds, c(0, :
missing value where TRUE/FALSE needed
range_sr
[1] -10.00 44.02977813958366
In addition to the other answers that you received you can also do:
library(TeachingDemos)
i[ quantile(i,.25) %% i %% quantile(i,.75) ]
This may or may not be more readable than the others. Also note that
precomputing both quantiles in one step may be faster than calling quantile
twice.
You
You may write as this:
for (i in 1:nrow(x)){
for (j in 1:ncol(x)){
if (!is.na(x[i, j])) {
if(x[i, j] == 'A') {x2[i, j] - 'A/A'} else{
if(x[i, j] == 'T') {x2[i, j] - 'T/T'} else{
if(x[i, j] == 'G') {x2[i, j] - 'G/G'} else{
Simona -
I don't think preallocating your random variables would make
the code run any faster.
A very simple change that would speed things up a little would
be to replace
simPD.vec[i]=length(R.vec[R.veccutoff.])
with
simPD.vec[i] = sum(R.vec cutoff.)
Since you're using a different set
But i need for each id have two data.
Like...
x
id v1 V2
1 1 1 12
2 1 2 13
4 2 4 15
5 2 5 16
8 3 8 19
9 3 9 20
11 4 11 22
12 4 12 23
So should write sample( if sample id 2 ,2). I don't know how to write (if
sample id 2). Thanks.
--
View this message in context:
I believe that this code will work (...for very small) samples, but let some
correct me if there is something wrong.
require(logistf);require(combinat)
permY-permn(data$y)
ntimes-length(permY)
results-matrix(nrows=ntimes,ncols=number_of_coefficients)
for(i in 1:ntimes){
On Thu, Feb 17, 2011 at 12:35 AM, mipplor wang-p...@hotmail.com wrote:
thx for your suggestions , i have made it csv file,and it looks:
data‐read.table('E:/my documents/r/1.csv',header=TRUE)
It looks like you could benefit from (re)reading my previous email.
You either need to specify the
Dear Colleagues,
Hope you will be fine. I am student of Ph.D and doing some work on
distribution.
I developed a new distribution and having some problems in estimating their
parameters by MLE. I used R-program and used maxLik function (maxLik: A
Package for Maximum Likelihood Estimation in R)
Hi, when ploting Kaplan-Meier estimate curves as below, the censoring symbols
(crosses) to not change thickness along the lines
plot(survfit(surv ~ I(x=cut.off) ),lty=c(1,2), lwd=2)
is there any strightforward way to make it happen? thanks
robert
--
View this message in context:
On Thu, Feb 17, 2011 at 10:02 AM, Alex F. Bokov
ahupxo...@sneakemail.com wrote:
Motivation: during each iteration, my code needs to collect tabular data (and
use it only during that iteration), but the rows of data may vary. I thought
I would speed it up by preinitializing the matrix that
This is, maybe, not the best solution but I hope it will help you:
x-data.frame(id=c(1,1,1,2,2,2,2,3,3,3,4,4), v1=c(1:12), V2=c(12:23))
do.call(rbind,by(x,x$id,function(x) x[c(sample(nrow(x),2)),]))
Andrija
On Thu, Feb 17, 2011 at 6:39 PM, yf chang...@umn.edu wrote:
But i need for each id
On 17/02/2011 11:02 AM, Alex F. Bokov wrote:
Motivation: during each iteration, my code needs to collect tabular data (and
use it only during that iteration), but the rows of data may vary. I thought I
would speed it up by preinitializing the matrix that collects the data with
zeros to what I
This is a presenation from the R Users Group (Bay Area)
Covers building predictive analytic models in R, exporting in PMML and
using ADAPA for model deployment and execution. Introduction to the
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*Dear All,*
*I'm trying to do Multivariate BLUP in R. I'd highly appreciate if someone
can share R code and data for Multivariate BLUP. Thanks*
*
*
*Regards!
*
--
*
Muhammad Yaseen
*
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Dear R users,
I would like to know how to indentify the polygons that are located on the
border of a map (i.e.shapefile).
Do you have any suggestion on how to do it?
Thank you very much,
Leo Monasterio.
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Hi All
I have data like this
tom randy mike dan doug
height 150 152 155 134 141
I am trying to create a line plot, with names on X-axis and height measure
on Y. how can i get it through R.
I could get several versions which are close (dotchart, bargraph), but not
Hi all,
i'm sure there is an easy way to do this, but i'm stumped, so any help would
be appreciated.
i have a single column of data for precipitation every 15 minutes over a
year. i want to sum the precip to daily data.
so the first 96 records = the first day, the second 96 records = the second
Hi Janet,
One relatively simple way would be to transofrm the data into a 96 x
Ndays matrix and use colSums(). Of course, lets say on one day, the
measurement tool had technical difficulties and missed two
observations, then you only have 94 observations for that day, you
will need a fancier
After ctree builds a tree, how would I determine the direction missing values
follow by examining the BinaryTree-class object? For instance in the example
below Bare.nuclei has 16 missing values and is used for the first split, but
the missing values are not listed in either set of factors.
muhammad mohsin mohsinshahid at yahoo.com writes:
Hope you will be fine. I am student of Ph.D and doing '
some work on distribution.
I developed a new distribution and having some problems in estimating their
parameters by MLE. I used R-program and used maxLik function (maxLik: A
Package
Janet:
The zoo package and aggregate.zoo should do the trick. I have done this
many times with these tools.
HTH,
Stephen
On Thu, 2011-02-17 at 11:56 -0800, Janet Choate wrote:
Hi all,
i'm sure there is an easy way to do this, but i'm stumped, so any help would
be appreciated.
i have a
On Feb 17, 2011, at 1:33 PM, andrija djurovic wrote:
This is, maybe, not the best solution but I hope it will help you:
x-data.frame(id=c(1,1,1,2,2,2,2,3,3,3,4,4), v1=c(1:12), V2=c(12:23))
do.call(rbind,by(x,x$id,function(x) x[c(sample(nrow(x),2)),]))
Andrija
Another way (and note that
dat-c(150,152,155,134,141)
plot(dat,type=o,ylim=c(100,160),xlab=Names,ylab=Height)
On Thu, Feb 17, 2011 at 7:45 PM, world peace buysellrentof...@gmail.com wrote:
Hi All
I have data like this
tom randy mike dan doug
height 150 152 155 134 141
I am trying to
Hi Toby and Maria,
I did a check on Toby's suggestion and it is not there:
R version 2.12.1 (2010-12-16)
??barploterrbar
No help files found with alias or concept or title matching
'barploterrbar' using fuzzy matching.
Also I went to the following location which does not exist.
The reason that it's easy to produce dotcharts or barplots in R with
data like yours, and difficult to produce a line plot, is because
dotcharts and barplots are appropriate for your data, whereas a line
plot is not. Since the values on the x-axis represent names,
and those names are not
A new version of rms is now available on CRAN for Linux/UNIX. I expect
Mac and Windows versions to be available in a day or so. This version
works with and requires the newest version of Therneau's survival package.
More information is at http://biostat.mc.vanderbilt.edu/Rrms
Changes in
R users,
I have been trying to write a program in R that will extract rows from a data
frame and combine the rows
into a new smaller data frame while meeting several criteria. I would greatly
appreciate any advice
that could help me get started down the right path. What I want to do is to
Hi all,
I have some some problem with regard to finding the integral of a
function containing an indicator function.
please see the code below:
func1 - function(x, mu){
(mu^2)*dnorm(x, mean = mu, sd = 1)*dgamma(x, shape=2)}
m1star - function(x){
integrate(func1, lower = 0, upper =
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