Peter,
Good idea! (why didn't I think of that?)
If it stumped the r-list, I think there is probably a slight bug with the
plot formula.
Problems like this make me realize how amazingly full featured and
relatively bug free R is. A problem like this would never happen in Excel,
because this
Hi,
I was plotting or creating a map for Texas school districts using the shape
file
of Texas. I could not find any other helpful mail in the mailing list.
txshp-read.shape(system.file(S:\\Districts_10_11.shp, package=maptools))
Error- read.shape no found. But read.shape is there in
Hi R list,
I'm new to R software, so I'd like to ask about it is capabilities.
What I'm looking to do is to run some statistical tests on quite big
tables which are aggregated quotes from a market feed.
This is a typical set of data.
Each day contains millions of records (up to 10 non
On 05/24/2011 10:56 PM, jbrezmes wrote:
I would like to be able to call external programs such as Java scripts (*.jar
files) or bring up the browser to a given direction. Can that be done from
R?
I am running R on a mac OS X system.
Thanks again for any suggestions or solutions.
Best
Hi,
I have applied rpart to my data set and for cp=.01, the cross-validation error
(xerr) is less (min 0.05) than for other cp. However, in the final tree, an
important predictor is not retained. Moreover, another predictor contains
missing values in 40% of samples. So I don't know if the
Hi John,
First off, thanks again for your help with this. Much appreciated.
I've attached a file of the original data (yes, as you can see there are
header names). These hour long files are zipped together on a computer
(which is actually an analyzer) and sent each morning to a server. I
then
An alternative approach would be to `split` the data frame by family,
then `lapply` a function selecting random row from each slice, and
then `rbind` it all together.
x = data.frame(family = rep(1:20,sample(2:5,20,replace=TRUE)), xyz=1)
randomrow - function(x) x[sample(1:nrow(x),1),]
# step by
Hi,
I am trying to use tune.svm in e1071 package.
the command i use is
tobj - tune.svm(labels, data= data, cost = 10^(1:2))
Should the last column of the 'data' contain the labels as well? I want to
use the linear kernel. But it gives me the error
Error in model.frame.default(formula, data) :
Forgot to specify that the cross-val error cannot be decreased lower than 0.91.
Note that for smaller values of cp than 0.01, the cross-val error increases.
Is the cross-val error sum of squared error or relative error for
classification
problem (method = class in rpart function) or another
Hi.
Thank you for your help. From your suggestions, I tried the following;
R CMD INSTALL --no-test-load rgl_0.92.798.tar.gz
This seemed to load and install (starting R and issuing library(rgl) did not
flag any problems
But running the sphere example from rgl, it causes big problems :-)
# R
R
On 11-05-25 6:08 AM, john herbert wrote:
Hi.
Thank you for your help. From your suggestions, I tried the following;
R CMD INSTALL --no-test-load rgl_0.92.798.tar.gz
This seemed to load and install (starting R and issuing library(rgl) did not
flag any problems
But running the sphere example
Shant Ch sha1one at yahoo.com writes:
Hi,
I was plotting or creating a map for Texas school districts
using the shape file
of Texas. I could not find any other helpful mail in the mailing list.
txshp-read.shape(system.file(S:\\Districts_10_11.shp, package=maptools))
Error-
federico.eccel federico.eccel at gmail.com writes:
I try to search in the web and in the R forum for any package for computing
The thiessen method but I didn't find anything. I would like to ask if it
exists any package in R that provides the possiblity to compute the Thiessen
method for
In cases where I have to parse through large datasets that will not
fit into R's memory, I will grab relevant data using SQL and then
analyze said data using R. There are several packages designed to do
this, like [1] and [2] below, that allow you to query a database using
SQL and end up with that
Hello,
I want to use the function barplot do display several group of bars.
A standard example is given at this link
http://onertipaday.blogspot.com/2007/05/make-many-barplot-into-one-plot.html
But in their example the 4 groups of bars are all composed of 8 bars.
I want to be able do display
Dear Victor,
Here is a basic solutions using ggplot2
library(ggplot2)
dataset - data.frame(Main = c(A, A, A, B, B), Detail = c(a, b,
c, 1, 2), value = runif(5, min = 0.5, max = 1))
ggplot(dataset, aes(x = Detail, y = value)) + geom_bar() + facet_grid(.~Main,
scales = free_x)
Best regards,
Hi,
On Wed, May 25, 2011 at 4:54 AM, Salih Tuna saliht...@gmail.com wrote:
Hi,
I am trying to use tune.svm in e1071 package.
the command i use is
tobj - tune.svm(labels, data= data, cost = 10^(1:2))
The first few arguments from the method signature for tune.svm is:
tune.svm(x, y = NULL,
Hi,
On Wed, May 25, 2011 at 12:29 AM, Roman Naumenko ro...@bestroman.com wrote:
Hi R list,
I'm new to R software, so I'd like to ask about it is capabilities.
What I'm looking to do is to run some statistical tests on quite big
tables which are aggregated quotes from a market feed.
This is
Dear All,
Suppose this data.frame
D
V7 V8 V9 V10 V11 V12 V13 V14 V15 V16 V17 V18 V19 V20 V21 V22
C C C C T T G G A A C C G G C C
G G T T A A A A T A T T C C G G
C C C C T T G G A A C C G G C C
I would translate
See ?t
__Scott Chamberlain
Rice University, EEB Dept.
On Wednesday, May 25, 2011 at 9:07 AM, Mohamed Lajnef wrote:
Dear All,
Suppose this data.frame
D
V7 V8 V9 V10 V11 V12 V13 V14 V15 V16 V17 V18 V19 V20 V21 V22
C C C C T T G G A A C C G G C C
G G T T A A A A T A T T
Dear All,
Sorry for the previous mail,suppose this data.frame
D
V7 V8 V9 V10 V11 V12 V13 V14 V15 V16 V17 V18 V19 V20 V21 V22
C C C C T T G G A A C C G G C C
G G T T A A A A T A T T C C G G
C C C C T T G G A A C C G G
Hello,
I am trying to run JRI example from rJava, but I have some issues. I have read
many posts and didn't find any solution to my problem.
I have the following code:
Rengine re = new Rengine(null, false, null);
System.out.println(Rengine created, waiting for R);
if (!re.waitForR())
Hi,
I’m an R beginner and I'd really appreciate an hand…
I'd like to create a new column in a dataframe in wich will be print the
content of several other columns.
For instance :
I’ve got 2 columns : site – sampling number and I would like to create a
third column ID, in wich will appear both
Hi again,
I've got another question...
I often use the symbol == to select some levels of factor variables like :
data[data$var==blabla, [
But this time, I'd like to select all the levels of my variable wich contain
the letter B, is that a way to determine this conditions ?
Thanks a lot !
Zoé
Hi,
I have a data-matrix:
CB
                  Zeit         Low
2Â Â 2011-05-02 08:05:05 7596.0
3Â Â 2011-05-02 08:10:06 7593.5
4Â Â 2011-05-02 08:15:11 7594.5
5Â Â 2011-05-02 08:20:15 7597.5
6Â Â 2011-05-02 08:25:18 7595.0
7Â Â 2011-05-02 08:30:20
Dear all,
I am looking for an R function which does stepwise selection cox model in r
(delta chisq likelihood ratio test) similar to the stepwise, pe (0.05) lr:
stcox in STATA.
I am very thankful for any reply.
Regards,
Linda
[[alternative HTML version deleted]]
Sorry, I have wrote a wrong subject in the first email!
Regards,
Linda
-- Forwarded message --
From: linda Porz linda.p...@gmail.com
Date: 2011/5/25
Subject: combined odds ratio
To: r-help@r-project.org
Cc: r-help-requ...@stat.math.ethz.ch
Dear all,
I am looking for an R
Hi,
I have a problem during choosing a Cran mirror, an error messages comes:
In open.connection (con, r)
connection to 'cran.r-project.org' impossible to prt 80.
I don't know why? can you help me to choose a cran mirror.
thanks for any suggestion.
--
View this message in context:
What's the logic behind the following, and where can I find any
documentation about it? In particular, why are 2:9 - as characters - not
regarded as being smaller than 10?
# R-Code:
a - as.character(1:12)
a 10
# [1] TRUE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE
FALSE
Ok, I found how to do,
with the function paste()
--
View this message in context:
http://r.789695.n4.nabble.com/Print-the-content-of-several-columns-in-only-one-tp3549114p3549514.html
Sent from the R help mailing list archive at Nabble.com.
__
Thanks a lot for both replies.
If I setup the option as proposed everything works as I wanted it to.
I guess as.character would work as well. Only then I guess I would need
to loop through the data frame.
Lutz
On 24/05/11 22:42, Ista Zahn wrote:
This is a FAQ:
On May 24, 2011; 11:06pm Belle wrote:
Does anyone know how to run Multinomial logistical Model in R in order to
get predicted probability?
Yes. I could stop there but you shouldn't. The author of the package
provides plenty of examples (and two good vignettes) showing you how to do
this.
I am trying to calculate Poisson regression based adjusted rate ratios in R,
but R's default in glm does not code the intercept as the global rate. In
SAS I use cell means coding so that the intercept is the global rate, but
I do not know how to do this in R. If anyone knows a way to make glm
Yes I had included the library(maptools) in my code, it is already installed in
my computer. but still it is showing the same error.
From: Ben Bolker bbol...@gmail.com
To: r-h...@stat.math.ethz.ch
Sent: Wed, May 25, 2011 8:06:19 AM
Subject: Re: [R] plotting
Thanks Jonathan.
I'm already using RMySQL to load data for couple of days.
I wanted to know what are the relevant R capabilities if I want to process much
bigger tables.
R always reads the whole set into memory and this might be a limitation in case
of big tables, correct?
Doesn't it use
Hi,
On Wed, May 25, 2011 at 12:29 AM, Roman Naumenko
ro...@bestroman.com wrote:
Hi R list,
I'm new to R software, so I'd like to ask about it is capabilities.
What I'm looking to do is to run some statistical tests on quite
big
tables which are aggregated quotes from a market feed.
Then use as.matrix. Transpose is not a well-defined operation for data frames.
---
Jeff Newmiller The . . Go Live...
DCN:jdnew...@dcn.davis.ca.us Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research
On May 24, 2011, at 11:42 PM, Gene Leynes wrote:
Peter,
Good idea! (why didn't I think of that?)
If it stumped the r-list, I think there is probably a slight bug
with the
plot formula.
Problems like this make me realize how amazingly full featured and
relatively bug free R is. A
On 25/05/2011 6:06 AM, Niklaus Kuehnis wrote:
What's the logic behind the following, and where can I find any
documentation about it? In particular, why are 2:9 - as characters - not
regarded as being smaller than 10?
# R-Code:
a- as.character(1:12)
a 10
# [1] TRUE FALSE FALSE FALSE FALSE
Take a look at the High-Performance and Parallel Computing with R CRAN Task
View:
http://cran.us.r-project.org/web/views/HighPerformanceComputing.html
specifically at the section labeled Large memory and out-of-memory data.
There are some specific R features that have been implemented in a
On May 25, 2011, at 4:46 AM, zoe.cryocla wrote:
Hi again,
I've got another question...
I often use the symbol == to select some levels of factor variables
like :
data[data$var==blabla, [
But this time, I'd like to select all the levels of my variable wich
contain
the letter B, is that
Hi,
On Wed, May 25, 2011 at 10:18 AM, Roman Naumenko ro...@bestroman.com wrote:
[snip]
I don't think data.table is fundamentally different from data.frame type, but
thanks for the suggestion.
http://cran.r-project.org/web/packages/data.table/vignettes/datatable-intro.pdf
Just like
Date: Wed, 25 May 2011 09:49:00 -0400
From: ro...@bestroman.com
To: biomathjda...@gmail.com
CC: r-help@r-project.org
Subject: Re: [R] Processing large datasets
Thanks Jonathan.
I'm already using RMySQL to load data for couple of days.
I
On May 25, 2011, at 7:56 AM, Victor Gabillon wrote:
Hello,
I want to use the function barplot do display several group of bars.
A standard example is given at this link
http://onertipaday.blogspot.com/2007/05/make-many-barplot-into-one-plot.html
But in their example the 4 groups of bars
Shant Ch sha1one at yahoo.com writes:
Yes I had included the library(maptools) in my code, it is already
installed in
my computer. but still it is showing the same error.
In that case you should (1) read the posting guide, (2) copy and
paste the code you ran, and the precise error you
I suggest a couple of courses before proceeding. Multinomial logistic models
have special challenges. And note that you have two nomenclature errors in
your note, which is usually a sign of not having taken the relevant
coursework.
Frank
Belle wrote:
Does anyone know how to run Multinomial
Hi.
I have been trying to load the mgcv package but I always get the error
message:
there is no package called 'nlme'
Error: package/namespace load failed for 'mgcv'
I load the package nlme and still I get the same message. I have noticed
that there are some problems in using nlme in recent
On May 25, 2011, at 5:28 AM, linda Porz wrote:
Sorry, I have wrote a wrong subject in the first email!
Regards,
Linda
-- Forwarded message --
From: linda Porz linda.p...@gmail.com
Date: 2011/5/25
Subject: combined odds ratio
To: r-help@r-project.org
Cc:
On May 25, 2011, at 7:25 AM, Lutz Fischer wrote:
Thanks a lot for both replies.
If I setup the option as proposed everything works as I wanted it to.
I guess as.character would work as well. Only then I guess I would
need
to loop through the data frame.
as.character is vectorized. You
We really need some more information to be able to help you (as
requested in the posting guide):
What OS?
What version of R?
How did you install nlme? Were there any messages?
What happens when you type library(nlme) at the R prompt?
How did you install mgcv? Were there any messages?
On Wed,
Or use melt in the reshape2 package to melt all columns to one with an indexing
column to boot...
__Scott Chamberlain
Rice University, EEB Dept.
On Wednesday, May 25, 2011 at 7:06 AM, zoe.cryocla wrote:
Ok, I found how to do,
with the function paste()
--
View this
Date: Wed, 25 May 2011 10:18:48 -0400
From: ro...@bestroman.com
To: mailinglist.honey...@gmail.com
CC: r-help@r-project.org
Subject: Re: [R] Processing large datasets
Hi,
If your datasets are *really* huge, check out some packages listed
Hi,
You are unlikely to find one, as fundamentally, stepwise procedures are a bad
way to engage in covariate selection. Search the list archives at rseek.org
using 'stepwise' as the keyword to see a plethora of discussion on this point.
This is not a new issue BTW, as I happened to stumble
I have a data set where the lines look like:
2011-05-13 00:00:00 EONAAL330 dfa13002516PSCNONA
2011-05-13 00:00:01 EONAAL223 laa13044510AS.NONM
Some lines are missing the field before and after the NON:
2011-05-13 00:00:05 EONBHS229 mia13001621NON
I read them into R using
df = read.fwf(file,
Everything looks OK. Does this help?
test -
data.frame(alpha=as.factor(c(A,A,B,B,C)),number=c(1,2,3,4,5))
mode(test)
[1] list
class(test)
[1] data.frame
sapply(test, mode)
alphanumber
numeric numeric
sapply(test, class)
alphanumber
factor numeric
On 5/25/11 10:42 AM,
See the Vignette in the glmnet package for one alternative approach to
variable selection. Of course, you need to gain some background to
know what you're doing here.
-- Bert
On Wed, May 25, 2011 at 8:38 AM, Marc Schwartz marc_schwa...@me.com wrote:
Hi,
You are unlikely to find one, as
With PostgreSQL at least, R can also be used as implementation
language for stored procedures. Hence data transfers between
processes can be avoided alltogether.
http://www.joeconway.com/plr/
Implemention of such a procedure in R appears to be straighforward:
CREATE OR REPLACE FUNCTION
Dear R Helpers,
I am having trouble combining some pieces of programming that work fine
individually, but fall down when I try to get them to work together.
The end goal is to take a data frame, and if any of the variables has more
than 10 values, then use cut2 to reduce the number of
Well, that answered some of my questions, though you forgot to send
your answer to the r-help list rather than just to me. I don't use
windows, so someone else may have better advice.
On Wed, May 25, 2011 at 12:02 PM, gbre...@ssc.wisc.edu wrote:
Sorry, I forgot to be more specific.
I am using
Hi John,
The issue is that:
infert$age != infert$age
One is a text string, the other references the information stored in
the age variable of the infert object. If you need to pass the names
as a string, use [ instead:
## for a data frame
infert[, age]
## for a list
infert[[age]]
It looks
You need to use get() so that you are acting on the dataframe,
and not the string that names the dataframe.
Sarah
On Wed, May 25, 2011 at 12:02 PM, Sparks, John James jspa...@uic.edu wrote:
Dear R Helpers,
I am having trouble combining some pieces of programming that work fine
individually,
Victor,
I agree with Marc's point of view. So, if you can use another representation
of you data, like points, considering looking at
http://lmdvr.r-forge.r-project.org/figures/figures.html figures 10.20 and
10.21 for a start point.
Walmes.
Sorry, I forgot to be more specific.
I am using Windows XP.
I am using R.12.2
I installed both packages from the install packages menu.
I always write library(name.of.library), and it is enough.
But when I write library(nlme), R does not find nlme right away
I load nlme first and it says
John -
Try
infert[,toolong] = sapply(infert[,toolong],cut2,g=10,levels.mean=TRUE)
- Phil Spector
Statistical Computing Facility
Department of Statistics
Hi,
On Wed, May 25, 2011 at 11:00 AM, Mike Marchywka marchy...@hotmail.com wrote:
[snip]
If your datasets are *really* huge, check out some packages listed
under the Large memory and out-of-memory data section of the
HighPerformanceComputing task view at CRAN:
Matthew,
You can change the matrix (restriction) involved. Start from
help(contr.sum)
to know how specify this.
Walmes.
==
Walmes Marques Zeviani
LEG (Laboratório de Estatística e Geoinformação, 25.450418 S, 49.231759 W)
On May 25, 2011, at 12:11 PM, linda Porz wrote:
Many thanks for your reply. I have run a stepwise selection in Stata
and R using the function fastbw (rule=p) from Design package. Both
functions give the same results. Is this because both functions do
the same job or can it be that for
Thankyou very much, I managed to count he numbr of Markers 2 linked to
Markers 3. And Markers 1 to Markers 3 with the aggregate function:
with(data,aggregate(Marker1,list(Marker2=Marker2),length))
data2-with(data,aggregate(Marker1,list(Marker2=Marker2,Marker3=Merker3),length))
So, now is easy I
Hi Josh,
You are definitely right. And were all time.
Yes, the problem was always with the write.csv(). I though it was with the ds.
Thank you very much.
Cheers,
Rui
Date: Tue, 24 May 2011 14:30:56 -0700
Subject: Re: [R] How to intantiate a list of data.frames?
From: jwiley.ps...@gmail.com
Many thanks for your reply. I have run a stepwise selection in Stata and R
using the function fastbw (rule=p) from Design package. Both functions
give the same results. Is this because both functions do the same job or can
it be that for different data one will have different results?
Many
Dear R users,
I have two datasets:
id1 - c(rep(1,10), rep(2,10), rep(3,10))
value1 - sample(1:100, 30, replace=TRUE)
dataset1 - cbind(id1,value1)
id2 - c(1,2,3)
subtract.value - c(1,3,5)
dataset2 - cbind(id2, subtract.value)
I want to subtract the number of rows in the subtract.value that
You can produce a graph similar to the ggplot with lattice::barchart,
require(lattice)
dataset - data.frame(Main=c(A,A,A,B,B),
Detail=c(a,b,c,1,2),
value=runif(5, min= 0.5, max=1))
barchart(value~Detail|Main, data=dataset,
On May 25, 2011, at 1:16 PM, Scott Hatcher wrote:
Hello Dr. Winsemius,
First of all, thank you for your prompt and helpful reply. Also, for
providing something I hoped would be produced from joining this
mailing list: a means of discovering incredibly useful packages such
as the
Hi:
Does this work?
dd - read.table(textConnection(
C C C C T T G G A A C C G G C C
G G T T A A A A T A T T C C G G
C C C C T T G G A A C C G G C C
), stringsAsFactors = FALSE)
# Convert the data frame to a
Hi:
Here are two alternatives that do work as you expect; sprintf() is your friend:
sprintf(%2d, 1:12)
[1] 1 2 3 4 5 6 7 8 9 10 11 12
sprintf(%02d, 1:12)
[1] 01 02 03 04 05 06 07 08 09 10 11 12
sprintf(%2d, 1:12) 10
[1] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE FALSE
try this using strsplit:
x - round(runif(10)*10, digits=0)
y - as.Date(x, origin=1970-01-01)
str(y)
Class 'Date' num [1:10] 26551 37212 57285 90821 20168 ...
y1 - as.character(y)
str(y1)
chr [1:10] 2042-09-11 2071-11-19 2126-11-04 2218-08-30
2025-03-21 2215-12-22 ...
x - strsplit(y1,
Hello everyone,
I have a 2 x 5 matrix: say
0.2 0.3 1 -1 3
0.2. 0.4 5 0.5 -1
I want to replace all the values greater than or equal to 1 with 1 and those
less than or equal to 0 with 0. So I should end up with a mtrix looking
like:
0.2 0.3 1 0 1
0.2. 0.4 1 0.5 0
It's very easy to do in two steps:
testmat - matrix(c(.2, .3, 1, -1, 3, .2, .4, 5, .5, -1), byrow=TRUE, nrow=2)
testmat
[,1] [,2] [,3] [,4] [,5]
[1,] 0.2 0.31 -1.03
[2,] 0.2 0.45 0.5 -1
testmat[testmat = 1] - 1
testmat[testmat 0] - 0
testmat
[,1] [,2] [,3] [,4]
I get a data frame on my end:
lines - 2011-05-13 00:00:00 EONAAL330 dfa13002516PSCNONA
2011-05-13 00:00:01 EONAAL223 laa13044510AS.NONM
2011-05-13 00:00:05 EONBHS229 mia13001621NON
df = read.fwf(textConnection(lines), widths=c(19,-4,7,3,8,2,1,3,1),
Dear Colleagues,
I'd like to draw your attention to the following job available at the Harvard
Business School. We are looking for a candidate with strong
statistical/econometrical background, with strong programming skills in R or
Stata. Please apply through the following link. If you know
At 00:41 25/05/2011, Greg Snow wrote:
The only statistical method that I know of that can be applied to
any dataset without further definition of the nature of the data or
the question being asked is
SnowsCorrectlySizedButOtherwiseUselessTestOfAnything which is found
in the TeachingDemos
I have a list that is made of lists of varying length. I wish to create a
new vector that contains the last element of each list. So far I have used
sapply to determine the length of each list, but I'm stymied at the part
where I index the list to make a new vector containing only the last item
On May 25, 2011, at 3:25 PM, Seth W Bigelow wrote:
I have a list that is made of lists of varying length. I wish to
create a
new vector that contains the last element of each list. So far I
have used
sapply to determine the length of each list, but I'm stymied at the
part
where I index
On May 25, 2011, at 2:25 PM, Seth W Bigelow wrote:
I have a list that is made of lists of varying length. I wish to create a
new vector that contains the last element of each list. So far I have used
sapply to determine the length of each list, but I'm stymied at the part
where I index the
On May 25, 2011, at 3:25 PM, Seth W Bigelow wrote:
I have a list that is made of lists of varying length. I wish to
create a
new vector that contains the last element of each list. So far I
have used
sapply to determine the length of each list, but I'm stymied at the
part
where I index
Hi:
Interesting problem. Here's one approach:
library(plyr)
# Read in your datasets as data frames rather than matrices
dataset1 - data.frame(id1 = rep(1:3, each = 10),
value1 = sample(seq_len(100), 30, replace = TRUE))
dataset2 - data.frame(id2 = 1:3, subtract.value =
[See in-line below]
On 25-May-11 19:14:11, Michael Dewey wrote:
At 00:41 25/05/2011, Greg Snow wrote:
The only statistical method that I know of that can be
applied to any dataset without further definition of the
nature of the data or the question being asked is
Date: Wed, 25 May 2011 12:32:37 -0400
Subject: Re: [R] Processing large datasets
From: mailinglist.honey...@gmail.com
To: marchy...@hotmail.com
CC: ro...@bestroman.com; r-help@r-project.org
Hi,
On Wed, May 25, 2011 at 11:00 AM, Mike
Hello Dr. Winsemius,
First of all, thank you for your prompt and helpful reply. Also, for
providing something I hoped would be produced from joining this mailing
list: a means of discovering incredibly useful packages such as the
reshape2 one you have introduced me too.
I have a follow up
Hi,
can anyone help me to figure out how to compute the percentile of an
individual observation with respect to a reference distribution.
What I mean is. Let's assume I have a vector consisting of 10 numbers
{3,5,8,1,9,5,4,3,5.5,7} and I want figure out what percentile the
number 4.9 corresponds
On May 25, 2011, at 3:42 PM, rudi wrote:
Hi,
can anyone help me to figure out how to compute the percentile of an
individual observation with respect to a reference distribution.
What I mean is. Let's assume I have a vector consisting of 10 numbers
{3,5,8,1,9,5,4,3,5.5,7} and I want figure
Hi Rudi,
Take a look at ?ecdf
HTH,
Jorge
On Wed, May 25, 2011 at 3:42 PM, rudi wrote:
Hi,
can anyone help me to figure out how to compute the percentile of an
individual observation with respect to a reference distribution.
What I mean is. Let's assume I have a vector consisting of 10
How can anyone overlook the intra-ocular trauma test (or sometimes called the
inter-ocular concussion test). But the i-o trauma test needs either a small
data set or an appropriate graph of the data (or can you look at a dataset of a
hundred columns and a million rows and do an intra-ocular
I have no problems configuring .r files to start in Emacs or RStudio
and then use Emacs or RStudio to call the required version of R.
You might check when you open with other from Windows Explorer that
the check box Always open with this program is ticked.
If you are using Windows 7 you can set
Dear all,
may I suggest the acronym IOTT for the inter-ocular trauma test?
Now we just need someone to implement iot.test(). I assume it will
appear on CRAN within the next 24 hours.
Looking forward to yet another base package,
Stephan
Am 25.05.2011 23:36, schrieb Greg Snow:
How can
Hi:
On Wed, May 25, 2011 at 12:42 PM, rudi rudi.stras...@gmail.com wrote:
Hi,
can anyone help me to figure out how to compute the percentile of an
individual observation with respect to a reference distribution.
What I mean is. Let's assume I have a vector consisting of 10 numbers
On 25/05/2011 5:43 PM, John C Frain wrote:
I have no problems configuring .r files to start in Emacs or RStudio
and then use Emacs or RStudio to call the required version of R.
You might check when you open with other from Windows Explorer that
the check box Always open with this program is
On May 25, 2011, at 5:50 PM, Dennis Murphy wrote:
Hi:
On Wed, May 25, 2011 at 12:42 PM, rudi rudi.stras...@gmail.com
wrote:
Hi,
can anyone help me to figure out how to compute the percentile of an
individual observation with respect to a reference distribution.
What I mean is. Let's
That worked perfectly. Thank you Dennis - I very much appreciate the
help!
Sara Maxwell, PhD, Postdoctoral Fellow
Marine Conservation Institute
University of California Santa Cruz
Long Marine Laboratory
100 Shaffer Road
Santa Cruz CA 95060 USA
+1 206 355 3249
On May 25, 2011, at 5:56 PM, Gene Leynes wrote:
David, Peter (and others),
If you're interested, I submitted this as a bug, and was informed of
the error of my ways by Professor Ripley
* His informative reply is copied below. *
The short answer is that panel.first is not a documented
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