Hi:
Here's one way using package plyr and its ddply() function. ddply()
takes a data frame as input and expects to output either a scalar or a
data frame. In this case, we want the latter.
library(plyr)
f - function(df) {
mn - min(df$result)
tms - df$time[df$result == mn]
subdf -
Hello
With due respect, have a nice time. I would like to ask some command in R.
It is regarding variable selection in linear regression.
In R, there is one rebuild function called step which
selecting variables according to AIC.
let say i have data [y, x1,x2,x3,x4]
we start with y~b0
i
Hi all,
this might be a stupid question, but still.
Everytime i find some new function it's prettty easy to understand how to
use the syntax and to perform a text. Even the general idea of what the
function does is pretty easy to understand, but i can not find an
explanation (detailed
Hello Christian
Thanks for answering. Yes, I have tried dbscan from fpc but I'm still
stuck on the memory problem. Regarding your answer, I'm not sure which
memory parameter should I look at. Following is the code I tried with
dbscan parameters, maybe you can see if there is any mistake.
Hello
With due respect, have a nice time. I would like to ask some command in R.
It is regarding variable selection in linear regression.
In R, there is one rebuild function called step which
selecting variables according to AIC.
let say i have data [y, x1,x2,x3,x4]
we start with y~b0
I am working on my thesis in which i have couple of independent variables
that are categorical in nature and the depndent variable is dichotomus.
Initially I run univariate analysis and added the variables with significant
p-values (p0.25) in my full model.
I have three confusions. Firstly, I am
On 07/06/2011 4:14 AM, mpavlic wrote:
Hi all,
this might be a stupid question, but still.
Everytime i find some new function it's prettty easy to understand how to
use the syntax and to perform a text. Even the general idea of what the
function does is pretty easy to understand, but i can not
Hello,
I'm running R on Linux (Ubantu) and I'm trying to run a script that will read
and plot data on a linux server. I've looked around and haven't been able to
figure out how to do this.
I want to load several files on the server and then be able to manipulate
them.
Any ideas?
Thanks!
On Jun 6, 2011, at 11:22 , Prof Brian Ripley wrote:
As a further example of the trickiness, the function method of plot()
relies on curve(x, ...) being a request to plot the function x(x) against x.
I've added a comment to that effect to the help page.
Ouch. This springs to mind:
Hi
I have data set consisting of my many variables and also in some cases
missing values. I want to probit transformation of my whole data set
using library VGAM or any other possible way. I would appreciat if
some one can help in writing code for probit transformation
V1 V10 V11
Hi, everyone,
I currently run into a problem about DCC-Garch model. I use the package
cc-garch and the function dcc.estimation. One of the output of this function
is DCC matrix, which shows conditional correlation matrix at every time
period you gives. However, I cannot figue out how the
Date: Tue, 7 Jun 2011 01:38:32 -0700
From: farah.farid@student.aku.edu
To: r-help@r-project.org
Subject: [R] Logistic Regression
I am working on my thesis in which i have couple of independent variables
that are categorical in nature and the
Am Dienstag, den 07.06.2011, 11:40 +0200 schrieb Brown, Mathew:
Hello,
I'm running R on Linux (Ubantu) and I'm trying to run a script that will read
and plot data on a linux server. I've looked around and haven't been able to
figure out how to do this.
I want to load several files on the
Hi again,
RCurl is just smarter than me:
getURL(http://my.web.service,.opts=curlOptions(username=:))
does the trick.
Don't know how I missed that yesterday.
Hope nobody wated time on this.
Cheers,
Thomas
-Original Message-
From: TAPO (Thomas Agersten Poulsen)
Sent: 6. juni 2011
can we populate values into an excel sheet from html forms that has to be
used in R for data analysis
Can we directly retireve the values from html forms into R fro analysis
--
View this message in context:
http://r.789695.n4.nabble.com/Populating-values-from-html-tp3579215p3579215.html
Sent
On 06/07/2011 06:20 AM, Sarah Goslee wrote:
Hi all,
I got curious about something, so in proper scientific fashion I
obtained some data and analyzed it.
Question: what is the female participation in the R-help email list?
Data: the most recent list postings, obtained from the website. I took
The 10% change idea was never a good one and has not been backed up by
simulations. It is quite arbitrary and results in optimistic standard
errors of remaining variables. In fact a paper presented at the Joint
Statistical Meetings about 3 years ago (I'm sorry I've forgotten the names
of the
Hi all,
I have build the following data frame
head(href)
chr tx_start tx_end g_id strand cds_start cds_end exon_count
1 chr1 8384389 8404227 NM_001080397 + 8384389 8404073 8
2 chr1 16767166 16786584 NM_001145277 + 16767256 16785491 7
3 chr1 16767166
Dear Prof. Ripley,
Am Montag, den 21.02.2011, 11:40 + schrieb Prof Brian Ripley:
So there is very likely a bug in your system software or compiler.
There is no such problem on other x86_64 systems (including
Fedora 14 and 12, FreeBSD, Solaris and Windows).
You can debug segfaults for
Two questions related to creating animated movies with rgl:
1. I've created an rgl scene with 5 different views I want to display in
a movie, but I'd like to insert pauses (say, 5 seconds)
at each view. How can I do this?
I first created 5 userMatrix's, then
play3d( par3dinterp(
I'm analysing some ID50 data for 2 different groups and had already
calculated this by hand using Reed-Muench formula, when I came across the
dose.p function in R.
I have 2 queries:
1) dose.p gives me a different answer to Reed-Muench, and actually I suspect
wrong answer, given that the dose.p
Date: Tue, 7 Jun 2011 03:35:46 -0700
From: ammasamri...@gmail.com
To: r-help@r-project.org
Subject: [R] Populating values from html
can we populate values into an excel sheet from html forms that has to be
used in R for data analysis
Can we
Hello,
i'm a research student working on everyday sounds classification.
i need to draw a dendrogram to show how the classification is done, but
while i never used R before, i guess that a help from someone would be
great :)
does any one of you did something like that before?
Thank you
--
Dear Windseav, I found that it is quite subjective because the effect of
initial value will dilute after couple of time periods, hence whatever value
you put there never matters. However I found that common practice is to put
the unconditional variance/covariance/correlation for the first period.
Hi Ayoub,
You'd be best served by learning how to search and to get help.
Within R,
??dendrogram
will give you a list of all the functions mentioning dendrogram, while
?dendrogram
will give you the help page for the function specifically named dendrogram().
While it can be a bit difficult to
Hi all,
I am attempting to run a script in which I permute my data and run a
Wilcoxon rank sum test on the data 1000 times and compare my original test
statistic to the permuted test statistics to more accurately estimate a
significance level for the trends I am observing.
In the process of
Hi,
It looks to me that your data frame is being sorted as text.
What does
str(W_table)
show?
How was W_table created? Your W column appears to not be numeric.
Sarah
On Tue, Jun 7, 2011 at 9:51 AM, William Armstrong
william.armstr...@noaa.gov wrote:
Hi all,
I am attempting to run a script
Hi Sarah,
str(W_table) gives me:
str(W_table)
'data.frame': 11 obs. of 3 variables:
$ pds_gagehandles.i.: Factor w/ 1 level mibe: 1 1 1 1 1 1 1 1 1 1 ...
$ p : chr 1 2 3 4 ...
$ W : chr 746 870.5 767 1066 ...
here is the script I am using, with the lines
Hi Blaz,
What do you do if the number of values sampled to be set missing
(e.g., 4) is greater than the number of values for a given case that
are less than your 3 threshold? If no special considerations are
needed for that, I do not see why you cannot apply the same technique
you did below
Also, I tried changing a line to store W as numeric:
sample_info-c(pds_gagehandles[i],p,as.numeric(sample_W))
But it is still sorting incorrectly:
W_table[order(W_table$as.numeric.W.),]
pds_gagehandles.i. p as.numeric.W.
8mibe 81004.5
1mibe 1
Hi Nanami,
you do not use the same file in export, href or new_CTTS ?
Regards
M
Le 07/06/11 14:42, ads pit a écrit :
Hi all,
I have build the following data frame
head(href)
chr tx_start tx_end g_id strand cds_start cds_end exon_count
1 chr1 8384389 8404227
On 07.06.2011 11:57, peter dalgaard wrote:
On Jun 6, 2011, at 11:22 , Prof Brian Ripley wrote:
As a further example of the trickiness, the function method of plot() relies
on curve(x, ...) being a request to plot the function x(x) against x. I've added a
comment to that effect to the
Hi,
On Tue, Jun 7, 2011 at 10:01 AM, William Armstrong
william.armstr...@noaa.gov wrote:
Hi Sarah,
str(W_table) gives me:
str(W_table)
'data.frame': 11 obs. of 3 variables:
$ pds_gagehandles.i.: Factor w/ 1 level mibe: 1 1 1 1 1 1 1 1 1 1 ...
$ p : chr 1 2 3 4 ...
I want to plot 6 line graphs. I have 10 points 0.1, 0.2, 0.3, 0.4, 0.5,
0.6,
0.7, 0.8, 0.9 and 1.0.
At each point say 0.1, I have 6 variables A, B, C, D, E and F. The
variables
all have values between 0 and 1 (and including 0 and 1). I also want to
label the x axis from 0.1 to 1.0 and the y
IMHO, you evidence considerable confusion and misunderstanding of
statistical methods. I would say that most of what you describe is
nonsense. Of course, maybe I'm just the one who's confused, but I
would strongly suggest you consult with a local statistician. This
list is unlikely to be able to
On Tue, 2011-06-07 at 16:17 +0200, Uwe Ligges wrote:
On 07.06.2011 11:57, peter dalgaard wrote:
On Jun 6, 2011, at 11:22 , Prof Brian Ripley wrote:
As a further example of the trickiness, the function method of plot()
relies on curve(x, ...) being a request to plot the function x(x)
On 07/06/2011 9:24 AM, Michael Friendly wrote:
Two questions related to creating animated movies with rgl:
1. I've created an rgl scene with 5 different views I want to display in
a movie, but I'd like to insert pauses (say, 5 seconds)
at each view. How can I do this?
I first created 5
On 06.06.2011 20:14, MARYAM ZOLGHADR wrote:
Dear All, Hello!
I have some questoins in R programming as follows:
Question 1- How to take the integral of this function with respect to y, such
that x would appear in the output after taking integral.
Thanks for catching that, Sarah.
It seems like the problem was that I was using the c() function to combine
terms (including W) that I was adding to a data frame.
This caused R to convert the numeric W to a character string.
I fixed this by using data.frame() and then rbind() instead of c() and
Hi! I'm learning mgcv, and reading Simon Wood's book on GAMs, as recommended
to me earlier by some folks on this list. I've run into a question to which I
can't find the answer in his book, so I'm hoping somebody here knows.
My outcome variable is binary, so I'm doing a binomial fit with
On 6/7/2011 10:52 AM, Duncan Murdoch wrote:
Something like this works:
play3d(par3dinterp(times=c(0,5,6,11,12,17),
userMatrix=list(m1,m1,m2,m2,m3,m3),
method=linear))
The linear says to use linear interpolation between time points, so
it will stay exactly constant
On 07/06/2011 12:22 PM, Michael Friendly wrote:
On 6/7/2011 10:52 AM, Duncan Murdoch wrote:
Something like this works:
play3d(par3dinterp(times=c(0,5,6,11,12,17),
userMatrix=list(m1,m1,m2,m2,m3,m3),
method=linear))
The linear says to use linear
Hi,
My project is set up the following way:
root directory contains the following folders:
folders: Breast_Cancer AND Colorectal_Cancer AND Lung_Cancer AND
Prostate_Cancer
I want to create a file, call it: repeating_functions.R and place it in
the root directory such that I can call these
On 07/06/2011 12:41 PM, Ben Ganzfried wrote:
Hi,
My project is set up the following way:
root directory contains the following folders:
folders: Breast_Cancer AND Colorectal_Cancer AND Lung_Cancer AND
Prostate_Cancer
I want to create a file, call it: repeating_functions.R and place it in
On 6/7/2011 12:36 PM, Duncan Murdoch wrote:
On 07/06/2011 12:22 PM, Michael Friendly wrote:
On 6/7/2011 10:52 AM, Duncan Murdoch wrote:
Something like this works:
play3d(par3dinterp(times=c(0,5,6,11,12,17),
userMatrix=list(m1,m1,m2,m2,m3,m3),
method=linear))
Hi,
I'm using the package gnm to perform non-linear models and I cannot
find how to write the formula for a power function model. I found out
that there was a function Raise() to do this but it no longer exists
in the package. I guess I need to use the nonlin function Mult(), but
I
Dear All, Hello!
I have some questoins in R programming as follows:
Question 1- How to take the integral of this function with respect to y,
such that x would appear in the output after taking integral.
f(x,y)=(0.1766*exp(-exp(y+lnx))*-exp(y+lnx))/(1-exp(-exp(y+lnx))) y in
(-6.907,-1.246)
It
I have a data frame (attached) that has interpolated EOT errors for
each minute before flight landing. It also has the runway and an index
for the flight:
times[1:4,]
time error runway flight
10 -0.0220623504R 1
21 -0.0796163104R 1
32 -0.1379538004R
Le 07/06/2011 15:43, Sarah Goslee a écrit :
Hi Ayoub,
You'd be best served by learning how to search and to get help.
Within R,
??dendrogram
will give you a list of all the functions mentioning dendrogram, while
?dendrogram
will give you the help page for the function specifically named
Hi,
I have two matrices of the following form:
cluster (n=18):
12062 1
12063 2
12064 2
12065 3
12066 5
KreisSA (n=2304)
12062
12062
12067
12065
12063
12067
I try to assign the cluster[,2] to KreisSAa by the follwoing loop:
n - nrow(cluster)
KreisSAa - numeric()
for(i in 1:n){
Hi
Don't use t as var names, because t is also a function (transpose).
This code should work...
set.seed(1)
T - rnorm(500)
qplot(T, geom = blank) +
geom_histogram(aes(y = ..density..), colour = black, fill = blue) +
stat_density(geom = line, colour = red)
--
View this message in context:
I am performing a precipitation analysis. data is in the form of daily
precipitation amounts, e.g.
x- c(4,5,3,0,0,0,2,4,6,4,0,0,0,2,2,0,3,4,1,0,...)
I would like to find the length of the storm, length of storm would be
defined as the number of days with continues precipitation. in this case the
Hi
I have a problem for which I would like to know a solution. I have a gene
expression data and I would like to choose only lets say top 200 genes that had
the highest expression variance across patients.
How do i do this in R?
I tried x=apply(leukemiadata,1,var)
x1=x[order(-1*x)]
but the
Hi to all, I'm new to this forum and new to R. I have to build a tree
classifier that has boolean values as response.
When I build the tree with:
echoknn.tree - tree(class ~ ., data=echoknn.train)
where class is a coloumn of my dataset (echoknn.train) of boolean values,
the result is a tree
R Help,
I posted a question on StackOverflow yesterday regarding an issue I've been
having with the RgoogleMaps packages' displaying of axes. Here is the text of
that submission:
http://stackoverflow.com/questions/6258408/rgooglemaps-axes
I can't find any documentation of the following
Hi Arun, thank you so much for your reply.
I have tried to use cor() function in R to calculate the unconditional
correlation matrix of my time series, but it is not the same as the
calculated first period Dynamic Conditional Correlation matrix by the
function dcc.estimation...I don't know
Dears
I would like to know the command line to:
1. plot the periodogram of a time series
2. To calculate a sazonal difference of the 7th order
3. Put the AR or MA term of the 9th order sazonal (or not-sazonal) part.
4. The significance level (P-value) for the estimated parameters of the
ARMA(1,1),
I am a new user, and i am trying to sort out a data frame.
I have for example bins of data. Within each bin i have multiple counts of
animals and the depths at which these count were taken. How would I summarise
this to being only the maximum count per bin alongisde the corresponding height
Using RStudio 0.93.89 on Windows 7. When I do Run Lines on a segment of
code in the Workspace and get an error message displayed in the Console, I
want to know what line number the error is on.
Is this possible in RStudio or can you suggest another workflow where I can
actually know what line my
SamiC wrote:
I am a new user, and i am trying to sort out a data frame.
I have for example bins of data. Within each bin i have multiple counts
of animals and the depths at which these count were taken. How would I
summarise this to being only the maximum count per bin alongisde the
William,
I think to convert to numeric, you might need to do something like:
as.numeric(as.character()) ## and not just as.numeric()
As it stands, it would appear that it is still being read as a character string.
From: William Armstrong
Dear R-users,
having a bit of experience with R under windows, I recently switched to
linux (ubuntu 10.4, 64-bit).
I'm using gedit 2.30.3 and GNOME Terminal 2.30.2
Everything works fine, except that occasionally gedit and/or the terminal
seem to behave strangely.
For example:
Thr_min - 0
I am learning ggplot2 commands and I have figured out how to create
histograms and density curves but I am not sure how to add a density curve
on top of a histogram.
Here are the two graphs that I created.
## Histogram
t-rnorm(500)
w-qplot(t, main=Normal Random Sample, fill=I(blue),
Hi,
I've been driving myself insane with this problem. I have a trellis plot of
contours, and I want each level to have something like z=value for each
one. I can get each one to say z, or each one to say the value (by using
as.factor) but not both. Heres an artificial example to show what I mean
I am a new user, and i am trying to sort out a data frame.
I have for example bins of data. Within each bin i have multiple counts of
animals and the depths at which these count were taken. How would I
summarise this to being only the maximum count per bin alongisde the
corresponding height
This question pertains to setting up a model in the package dlm
(dynamic linear models,
http://cran.r-project.org/web/packages/dlm/index.html
I have read both the vignette and An R Package for Dynamic Linear
Models (http://www.jstatsoft.org/v36/i12/paper), both of which are
very helpful. There
I am learning ggplot2 commands specifically qplot for the time being and I
have figured out how to create histograms and normal density curves but I am
not sure how to add a normal bell curve or other dist. as well on top of a
histogram.
Here are the two graphs that I created.
## Histogram
It's likely that class is numeric and you actually want factor
(regression tree vs classification tree).
str(echoknn.train) will show you.
By saying, I have to build a tree classifier you make me think that
this is a course assignment. If it is, you should perhaps talk to your
instructor. If
Hello forum,
I am interested in investigating non-linear relationships between variables
using something akin to Multivariate Adaptive Regression Splines. The
problem is that my data have sample weights and stratification variables,
and I don't think earth and similar packages support these.
Hi James,
Specify data = times in the qplot call and get rid of times$
everywhere. For example, do
pp2 = qplot(time, error, data = times)
pp2 + facet_wrap(~ runway)
Best,
Ista
On Tue, Jun 7, 2011 at 4:01 PM, James Rome jamesr...@gmail.com wrote:
I have a data frame (attached) that has
Hello forum,
I am interested in investigating non-linear relationships between variables
using something akin to Multivariate Adaptive Regression Splines. The
problem is that my data have sample weights and stratification variables,
and I don't think earth and similar packages support these.
Hi All,
I'm using WinBUGS on a very simple survival model (log-normal with one
covariate Treat), but I cannot understand the way it handles censored
data. I'm posting the R file which generates the data from pre-specified
parameters, as well as the .bug file.
The question is, if I use NA to
On Jun 7, 2011, at 9:25 AM, davetracz wrote:
I am performing a precipitation analysis. data is in the form of daily
precipitation amounts, e.g.
x- c(4,5,3,0,0,0,2,4,6,4,0,0,0,2,2,0,3,4,1,0,...)
I would like to find the length of the storm, length of storm would be
defined as the number
Thank you very much. This is incredibly helpful, I just added an R package
and put a bunch of code in it which works very well. I just had a quick
follow-up question.
Suppose across the uncurated data-sets, stage of cancer progression is
entered in the following way, where the column headers
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of dicko ahmadou
Sent: Tuesday, June 07, 2011 11:41 AM
To: r-help@r-project.org
Subject: Re: [R] ggplot 2: Histogram with bell curve?
Hi
Don't use t as var names, because t is
On 07.06.2011 16:24, Dominik P.H. Kalisch wrote:
Hi,
I have two matrices of the following form:
cluster (n=18):
12062 1
12063 2
12064 2
12065 3
12066 5
KreisSA (n=2304)
12062
12062
12067
12065
12063
12067
I try to assign the cluster[,2] to KreisSAa by the follwoing loop:
n - nrow(cluster)
Well:
I programmed an script in R using caret package and the results are very
interesting ...
I have two datasets the first dataset have a linear distribution
experimentaly:
values are: 4.3 , 5.3, 6.3.. 10.3...
the svmRadial kernel work perfectly and I can obtain an R2 = 0.98 between
the
Hi
fn - dir(pattern=txt,full.name=T)
fn
[1] ./GSM696980_US81503234_252741110209_S01_CGH_107_Sep09_1_1_32914.txt
[2] ./GSM696981_US81503234_252741110209_S01_CGH_107_Sep09_1_2_32916.txt
[3] ./GSM696982_US81503234_252741110209_S01_CGH_107_Sep09_1_3_33021.txt
[4]
I'm running R 2.13 on Ubuntu 10.10
I have a data set which is comprised of character strings.
site = readLines('http://www.census.gov/tiger/tms/gazetteer/zips.txt')
dat - c(01, 35004, AL, ACMAR, 86.51557, 33.584132, 6055, 0.001499)
dat
I want to loop through the data and construct a data frame
Hi all,
In follow up to my reply regarding splitting/grouping a vector:
https://stat.ethz.ch/pipermail/r-help/2011-June/280361.html
it seems logical that a generic approach might be useful. So here is one
possibility, which I present for use and improvement as may be appropriate.
x : a
Times is extracted from a larger data frame with the city in it also, so
the variables are not unique. But I tried what you suggested, and get
pp2 = qplot(time, error, times)
pp2 = pp2 + facet_wrap(~ runway)
print(pp2)
Error in eval(expr, envir, enclos) : object 'error' not found
On Jun 7, 2011, at 3:55 PM, Abraham Mathew wrote:
I'm running R 2.13 on Ubuntu 10.10
I have a data set which is comprised of character strings.
site = readLines('http://www.census.gov/tiger/tms/gazetteer/zips.txt')
dat - c(01, 35004, AL, ACMAR, 86.51557, 33.584132, 6055, 0.001499)
dat
Something is very strange:
pp2 = qplot(time, error, times)
plot(pp2)
Error in xy.coords(x, y, xlabel, ylabel, log) :
'x' is a list, but does not have components 'x' and 'y'
On 6/7/2011 4:12 PM, Ista Zahn wrote:
Hi James,
Specify data = times in the qplot call and get rid of times$
everywhere.
Hi James,
On Tue, Jun 7, 2011 at 5:12 PM, James Rome jamesr...@gmail.com wrote:
Times is extracted from a larger data frame with the city in it also, so
the variables are not unique. But I tried what you suggested, and get
pp2 = qplot(time, error, times)
pp2 = pp2 + facet_wrap(~
On 06/07/2011 01:38 PM, Parida, Mrutyunjaya wrote:
Hi
fn- dir(pattern=txt,full.name=T)
fn
[1] ./GSM696980_US81503234_252741110209_S01_CGH_107_Sep09_1_1_32914.txt
[2] ./GSM696981_US81503234_252741110209_S01_CGH_107_Sep09_1_2_32916.txt
[3]
So I have figured out how to do it via a series of loops and conditions, but
i am thinking there must be a quicker way to do it.
an example.
Bin Depth Fish to: Bin DepthMaxFish
1 4 2 1 8 24
1 8
Thanks Rob, but the legend is not appearing in the plot. I think the best
place for it is on the top left.
Is there anyway I can also get it broken down in tenths instead of fifths?
The legend is easy; just specify where you want it. The first 2 parameters
specify the x, y of the top left
Here's one way:
# Here I read in your data to a variable 'x'
x = read.delim(textConnection(
Bin Depth Fish
1 4 2
1 8 24
1 12 4
2 4 3
2 8 21
2 12 2
3 4 12
3 8 2
3 12 33), sep = , header = TRUE)
do.call(rbind, lapply(split(x, x$Bin), function(grp)
grp[which.max(grp$Fish),]))
--
View this
Hi,
I thought that a common practice is just to ommit the first period data
since it does not have much influence on further results / calculations.
Cheers
Marcin
2011/6/7 windseav winds...@gmail.com
Hi, everyone,
I currently run into a problem about DCC-Garch model. I use the package
my badyou are right
I always use TRUE instead of T, so i forgot that by default T = TRUE in R.
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Let's say that I'm trying to write a functions that will allow me to
automate a process
where I examine all possible combinations of various string groupings. Each
time I run
the one function, I want to include the new values to the end of a data
frame. The data
frame will basically be one column
Hi,
I found an architecture-specific segfault problem with the XML package. I
originally found the problem using the parseKGML2Graph function in the
Bioconductor KEGGgraph package, but as far as I can tell the underlying issue
seems to be with the xmlTreeParse which is called by
I would rather use cleveland dot plots than bar charts to display my study
results. I have not been able to find (or figure out) an R package that is
capable of producing the publication quality dot charts Im looking for. I
have either not been able to get error bars (lattice), cannot order the
Dear R-help,
In the rms package, I have fitted an ols model with a variable
represented as a restricted cubic spline, with the knot locations
specified as a previously defined vector. When I save the model object
and open it in another workspace which does not contain the vector of
knot
Hello Samantha, I'm having some trouble understanding your question in
terms of what's happening in R. Are these bins columns of a
data.frame? Rows?
It's helpful for us to have a small example to look at--for instance,
you could create a small subset of your data called x, then type the
command
Hi:
Here's another approach using the plyr package:
# Write a function that takes a data frame as input and outputs a data frame
f - function(df) df[which.max(df$Fish), ]
ddply(x, 'Bin', f)
Bin Depth Fish
1 1 8 24
2 2 8 21
3 312 33
HTH,
Dennis
On Tue, Jun 7, 2011 at
Alas, you don't have a suffix2 object defined, but try this:
d1 - one(prefix, roots)
d2 - one(roots, suffix)
rbind(d1, d2)
To see a potential flaw in your function (as least as far as console
output is concerned), try
rbind(d1, one(roots, suffix))
HTH,
Dennis
On Tue, Jun 7, 2011 at 3:30 PM,
As suggested above, specifying useful starting points definitely helps in the
case of:
x - seq(0,2*pi, length=1000)
x - cbind(x/(2*pi), sin(x))
fit1 - principal.curve(x, plot = TRUE, trace = TRUE, maxit = 100, start =
cbind(sort(x[,1]), rep(1, nrow(x
Interestingly, I find that if you
guy33 wrote:
As suggested above, specifying useful starting points definitely helps in
the case of:
x - seq(0,2*pi, length=1000)
x - cbind(x/(2*pi), sin(x))
fit1 - principal.curve(x, plot = TRUE, trace = TRUE, maxit = 100, start =
cbind(sort(x[,1]), rep(1, nrow(x
Kia ora Colin
I don't know if there is a package that does what you want, but they are easy
enough to create using plot(). Error bars can be added with arrows().
HTH ...
Peter Alspach
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