Hi,
A slight modification corrects this:
ttt - data.frame(A = c(Inf, 0, 0), B = c(1, 2, 3))
apply(ttt, 2, function(x) {x[is.infinite(x)] - 0; x})
and please do use spaces in your code. It is much more legible. Most
notably spaces are after commas.
Cheers,
Josh
On Sun, Jul 17, 2011 at 10:01
ttt - data.frame(A = c(Inf, 0, 0), B = c(1, 2, 3))
apply(ttt, 2, function(x) {x[is.infinite(x)] - 0; x})
Ok thank you. That does work. What does
apply(ttt, 1, function(x) x[is.infinite(x)] - 0 )
this return. I get all 0's,but can you explai why ?
Thank you.
Ashim
[[alternative
Hola Mario,
No sé si finalmente pudiste solucionar el problema que planteaste, por si
todavía lo tienes te sugiero que incluyas el correo en la lista de ayuda de
R pero en español R-help-es.
Puedes darte de alta aquí:
https://stat.ethz.ch/mailman/listinfo/r-help-es
Saludos,
Carlos Ortega
On Mon, Jul 18, 2011 at 12:22 AM, Ashim Kapoor ashimkap...@gmail.com wrote:
ttt - data.frame(A = c(Inf, 0, 0), B = c(1, 2, 3))
apply(ttt, 2, function(x) {x[is.infinite(x)] - 0; x})
Ok thank you. That does work. What does
apply(ttt, 1, function(x) x[is.infinite(x)] - 0 )
this return.
On Jul 18, 2011, at 01:11 , Rolf Turner wrote:
This
more sophisticated solution is a pain in the pohutukawa ( :-) ) to calculate
by hand, but if you've
got a computer to do the nasty arithmetic for you, then why not?
Yes. Notice the irony: Textbook authors choose the simplest
I used mgarch and mgarchBEKK packages to esti,ate a BEKK model ,but i
cannot get the P-value of the
coefficient ， how can I get P-value ,anyone can help me ? thanks
--
View this message in context:
http://r.789695.n4.nabble.com/BEKK-help-tp3674545p3674545.html
Sent from the R help
On Jul 18, 2011, at 06:09 , David Winsemius wrote:
PFB
What ever that TLA means
Just google for it: Postcard from Buster ;-)
--
Peter Dalgaard
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Email: pd@cbs.dk
Ok Josh. Many thanks for your effort.
Ashim : )
On Mon, Jul 18, 2011 at 1:34 PM, Joshua Wiley jwiley.ps...@gmail.comwrote:
On Mon, Jul 18, 2011 at 12:22 AM, Ashim Kapoor ashimkap...@gmail.com
wrote:
ttt - data.frame(A = c(Inf, 0, 0), B = c(1, 2, 3))
apply(ttt, 2, function(x)
On 2011-07-17 17:37, Steven Ranney wrote:
All -
I'm having an issue with trying to plot a model derived from nls()
onto a simple plot. I have included a sample data set and the code
that I've been using.
year month day date location mileage cost gallon cpg
mpg x
Peter Dalgaard-2 wrote:
On Jul 18, 2011, at 06:09 , David Winsemius wrote:
PFB
What ever that TLA means
Just google for it: Postcard from Buster ;-)
offtopic
I did and found this gem for PFB
Pseudofolliculitis barbae, a medical term for persistent inflammation caused
by
Hi,
I need to make a cluster classification by the unique values of the data frame.
I explain the problem. I need to classify this table, and assign to
the same cluster each row that has the same combination of value:
data1
layer_1 layer_2 layer_3
[1,] 0.246000 2
Your data1 and your data1_class file differ in the first three
columns. Assuming that's an error, here's one way to do it:
data1 - data.frame(layer1=c(.2, .5, .2, .8, .2, .5, .5, .8, .2,
.8),layer2=c(2,3,2,2,1,2,3,2,2,2), layer3=c(1,1,1,1,1,1,1,1,1,4))
data1 - cbind(data1,
Thank you Jim, Steve and David.
I found findIntervals to work best for my problem.
Manuel
--
View this message in context:
http://r.789695.n4.nabble.com/Number-in-interval-tp3673537p3674969.html
Sent from the R help mailing list archive at Nabble.com.
Dear all,
I merged 2 data frames using the merged command and the resulting data frame
looks perfect into R.
However, I have serious problems when I try to write this new data frame
into a file using the write.table command.
Basically I get parts of the second file that I merged into the file.
Also read FAQ 7.31 before using 'numerics' as grouping factors.
On Mon, Jul 18, 2011 at 6:36 AM, Sarah Goslee sarah.gos...@gmail.com wrote:
Your data1 and your data1_class file differ in the first three
columns. Assuming that's an error, here's one way to do it:
data1 -
On Sat, Jul 16, 2011 at 11:50 PM, Eduardo M. A. M. Mendes
emammen...@gmail.com wrote:
Hello
I am new to R and I need to convert some dates (numeric format by matlab) to
actual dates in R.
For instance,
Matlab - 730456 - datestr(730456)
ans =
02-Dec-1999
Set the origin to Matlab's
it's not possible to look for a local statistical consultatnt. I was just
hoping
for help. Thanks anyway.
From: Uwe Ligges lig...@statistik.tu-dortmund.de
Cc: r-help@r-project.org
Sent: Sun, July 17, 2011 9:27:22 AM
Subject: Re: [R] Out of Sample Prediction
1st Data Analysis Contest Using R
Nestoria is a specialized web search engine platform in house prices.
Nestoria y Lokku Labs aim to improve the understanding of the public of
the value of its databases. The company aims to engage a few brilliant
statisticians in the expectation that their
Hi Andrea,
On Mon, Jul 18, 2011 at 6:07 AM, Andrea Franceschini ata...@gmail.com wrote:
Dear all,
I merged 2 data frames using the merged command and the resulting data frame
looks perfect into R.
However, I have serious problems when I try to write this new data frame
into a file using
On Jul 18, 2011, at 14:08 , Gabor Grothendieck wrote:
On Sat, Jul 16, 2011 at 11:50 PM, Eduardo M. A. M. Mendes
emammen...@gmail.com wrote:
Hello
I am new to R and I need to convert some dates (numeric format by matlab) to
actual dates in R.
For instance,
Matlab - 730456 -
Ted, Rolf Peter,
Thanks for a truly educational (at least for me) thread.
I did indeed look up the article /Interval Estimation for the
Difference Between Independent Proportions: Comparison of Eleven
Methods. /which I found here.
Dear R users,
Any idea of how to calculate an area of an overlap between two functions? The
only R build in function that I found is I Similarity Statistic for Quantifying
Niche Overlap and I am really not sure if this function is producing exactly
what I am interested in since I was plotting
On Jul 18, 2011, at 9:40 AM, Ana Kolar wrote:
Dear R users,
Any idea of how to calculate an area of an overlap between two
functions? The only R build in function that I found is I Similarity
Statistic for Quantifying Niche Overlap and I am really not sure if
this function is producing
On Mon, Jul 18, 2011 at 8:56 AM, peter dalgaard pda...@gmail.com wrote:
On Jul 18, 2011, at 14:08 , Gabor Grothendieck wrote:
On Sat, Jul 16, 2011 at 11:50 PM, Eduardo M. A. M. Mendes
emammen...@gmail.com wrote:
Hello
I am new to R and I need to convert some dates (numeric format by
I have a data set that looks like this:
dene - data.frame(length =
c(35,32,33,34,41,40,46,35,41,40,45,36,38,37,39,40,42,42,42,43,44),
sex=c(1,1,1,1,2,2,2,1,2,2,2,1,2,2,2,2,2,2,2,2,2))
I would like to plot the density (frequency of occurrence) of each length
class but I want to have different
On 2011-07-18 06:38, Steven Ranney wrote:
Provided, of course, that I alter the lines for different data sets
and data frames, the code to plot a line derived from nls() onto a
plot works with no problems.
Here's an example:
Year NOP
2002 6
2003 8
2004 11
2005 19
2006 26
2007 25
mod1-
You might also enjoy the binconf() function in the Hmisc pkg.
Peter Ehlers
On 2011-07-18 06:17, Jack Sofsky wrote:
Ted, Rolf Peter,
Thanks for a truly educational (at least for me) thread.
I did indeed look up the article /Interval Estimation for the
Difference Between Independent
Dear all, Sarah,
ok, I start to give some details.
I use version 13 of R in OSX (downloaded and installed less than 1 year ago).
I pasted below the results of the str() command.
The data frame looks perfect for me.
I generated the dataframe using the following commands:
On Jul 18, 2011, at 15:48 , Gabor Grothendieck wrote:
On Mon, Jul 18, 2011 at 8:56 AM, peter dalgaard pda...@gmail.com wrote:
On Jul 18, 2011, at 14:08 , Gabor Grothendieck wrote:
On Sat, Jul 16, 2011 at 11:50 PM, Eduardo M. A. M. Mendes
emammen...@gmail.com wrote:
Hello
I am new to
Yes, indeed! I believe I should integrate differences of min of both functions,
no? I'm not quite sure how this should be done in R therefore I was wondering
if there are some build in functions that do this job already. If not I would
appreciate any help of how should it be done otherwise.
On Jul 18, 2011, at 10:10 AM, Kishor Tappita wrote:
Dear David,
Thank you for your reply. I realized that the summary function can
help me in finding the the order of the curves.
The 0.95UCL (95% upper confidence level) column in particular seems
to follow the same pattern as the
Dear David,
Thank you for your reply. I realized that the summary function can help me
in finding the the order of the curves.
The 0.95UCL (95% upper confidence level) column in particular seems to
follow the same pattern as the curves on the plot.
I am new to survival analysis, so please
Provided, of course, that I alter the lines for different data sets
and data frames, the code to plot a line derived from nls() onto a
plot works with no problems.
Here's an example:
Year NOP
2002 6
2003 8
2004 11
2005 19
2006 26
2007 25
mod1 - nls(NOP~alpha*exp(beta*Year), data=aic,
Unfortunately, the transposition of lines and list was a typo on my
part. Now that I look like a fool and have corrected the issue, I'm
still faced with the same dilemma. With the original data set I
posted in this thread,
plot(mpg~x, data=mileage[year==2009,], ylab=Miles per gallon,
xlab=2009,
On Mon, Jul 18, 2011 at 04:00:29PM +0200, Andrea Franceschini wrote:
I use version 13 of R in OSX (downloaded and installed less than 1 year ago).
Probably 2.13 ...
[...] code omitted
The first lines are OK (i.e. 14 columns, like the dataframe), while at
a certain point I get lines with
On Mon, Jul 18, 2011 at 10:08 AM, peter dalgaard pda...@gmail.com wrote:
On Jul 18, 2011, at 15:48 , Gabor Grothendieck wrote:
On Mon, Jul 18, 2011 at 8:56 AM, peter dalgaard pda...@gmail.com wrote:
On Jul 18, 2011, at 14:08 , Gabor Grothendieck wrote:
On Sat, Jul 16, 2011 at 11:50 PM,
On Jul 18, 2011, at 10:11 AM, Ana Kolar wrote:
Yes, indeed! I believe I should integrate differences of min of both
functions, no? I'm not quite sure how this should be done in R
therefore I was wondering if there are some build in functions that
do this job already. If not I would
On Jul 18, 2011, at 10:42 AM, Kishor Tappita wrote:
Ok David, Thanks for clearing my misconception. Then could you
please suggest me how I could get the KM estimate for a time point.
I remember reading the formula
for calculating the KM. Do, I have to write a method to compute the
KM
Dear David,
The toy example doesn't represent functions as such, but represents type of
data that I'm operating with. These data are product of an analysis. If I
understand you correctly, I would need to approximate distribution functions of
these data first and then integrate. This makes
Dear Philipp,
You were right,
thankyou very much.
Effectively the second read.table didn't work (probably because of the
strange characters).
From my point of view this is a very bad R bug.
I precisely inserted the \t separator in the read table command,
hence I would expect that everything is
On Jul 18, 2011, at 11:07 AM, Ana Kolar wrote:
Dear David,
The toy example doesn't represent functions as such, but represents
type of data that I'm operating with. These data are product of an
analysis. If I understand you correctly, I would need to approximate
distribution functions
This is just a gentle reminder of the final registration deadline for
this year's useR! conference (University of Warwick, 16-18 August;
tutorials 15 August).
No further registrations will be accepted after this Friday (22 July).
Contributions to the conference programme can still be offered as
Hello,
I am facing problems with plotting graphs in R. It was working well since
today, but I cannot get some graphs for unknown reasons. Initially it gave
me diagonal straight lines. Now it is giving me very strange curves. I have
tried to re-install the softwear. It still did not help.
Please,
Dear all
I am struggling with how to deal with missing values using geeglm. I know
that geeglm only works with complete datasets, but I cannot seem to get the
na.omit function to work. For example
assuming DataMiss contains 3 columns, each of which has missing
observations, and an id column
Ok David, Thanks for clearing my misconception. Then could you please
suggest me how I could get the KM estimate for a time point. I remember
reading the formula
for calculating the KM. Do, I have to write a method to compute the KM
estimate or will the survival package provide it for me?
Thank
Thanks a lot. I used survfit to generate KM plots but I will try to figure
out to find the corresponding returned value for KM estimate. Thank you for
your invaluable help.
On Mon, Jul 18, 2011 at 8:28 PM, David Winsemius dwinsem...@comcast.netwrote:
On Jul 18, 2011, at 10:42 AM, Kishor
Many thanks for this, David. It is applicable, indeed! Thank you for sharing
the search function as well.
Have a good day!
Ana
From: David Winsemius dwinsem...@comcast.net
To: Ana Kolar annako...@yahoo.com
Cc: R r-help@r-project.org
Sent: Monday, 18 July
Dear R-experts!
I am working on some meta-analysis using the metafor package. I would like
to extract values of the confidence intervals of the effect sizes of the
single studies from an rma object. Those values are printed out when
plotting a forest plot using the forest function on the rma
Hi,
May I ask a question about a thread
https://stat.ethz.ch/pipermail/r-help/2005-March/068365.html?
I understand I need to use prcomp instead of princomp when i have less
units than variables.
However, when I use prcomp the scores is NULL. How can I overcome this?
Regards,
Armin
--
Kind
I have done ?barplot. I have not problems making barplots in R except for
this where there are actually two stacked columns for each fish.
I have also searched the internet to look for examples like what I would
like to plot, but have not found any which is why I thought putting a post
would
On Jul 18, 2011, at 10:13 AM, Steven Ranney wrote:
Unfortunately, the transposition of lines and list was a typo on my
part. Now that I look like a fool and have corrected the issue, I'm
still faced with the same dilemma. With the original data set I
posted in this thread,
No. You did not
Hi Sally,
I'm not sure what your question actually is. How to make a stacked bar
plot, perhaps?
If so, do any of the examples at these two sites help?
http://www.harding.edu/fmccown/R/#barcharts
http://addictedtor.free.fr/graphiques/search.php?engine=RGGq=barplot
If not, can you explain what
Hi,
You need to explain what you want to do. This is not a software
issue, you simply cannot create more uncorrelated variables than you
have observations.
Josh
On Mon, Jul 18, 2011 at 8:53 AM, a.me...@yahoo.co.uk
a.me...@yahoo.co.uk wrote:
Hi,
May I ask a question about a thread
On Jul 18, 2011, at 11:10 AM, Andrea Franceschini wrote:
Dear Philipp,
You were right,
thankyou very much.
Effectively the second read.table didn't work (probably because of the
strange characters).
From my point of view this is a very bad R bug.
When I read this I thought it was an
Am Sonntag, den 03.07.2011, 18:19 +0200 schrieb r...@rz.uni-potsdam.de:
Quoting r...@rz.uni-potsdam.de:
Quoting Juergen Rose r...@rz.uni-potsdam.de:
Hi,
I was just able to install the patched Rmpi on the second system with
openmpi-1.5.3. What can we that Rmpi_0.5-9a.tar.gz becomes a
Dear Jokel,
Right now, none of the functions return that information. But it's easy to
calculate those CIs by hand (simply take yi +- 1.96 sqrt(vi) and apply, if
needed, some appropriate transformation). For example:
data(dat.bcg)
dat - escalc(measure=RR, ai=tpos, bi=tneg, ci=cpos, di=cneg,
On Mon, Jul 18, 2011 at 5:04 PM, UnitRoot akhussa...@gmail.com wrote:
Hello,
I am facing problems with plotting graphs in R. It was working well since
today, but I cannot get some graphs for unknown reasons. Initially it gave
me diagonal straight lines. Now it is giving me very strange curves.
On Jul 18, 2011, at 16:36 , Gabor Grothendieck wrote:
.
However, this was after reinstalling and reloading zoo. Restarting R and
retrying did indeed make things work.
Does the fact that it worked if R was restarted, but not without,
imply that there is something in R that needs
Note:
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Also, your question may be more appropriate for the R mixed-models mailing
list.
Kevin
On Sun, Jul
Hi all, I am trying to understand the R's environment concept
however the underlying help files look quite technical to me. Can
experts here provide me some more intuitive ideas behind this concept
like, why it is there, what exactly it is doing in R's architecture
etc.?
I mainly need some
On Mon, Jul 18, 2011 at 1:59 PM, peter dalgaard pda...@gmail.com wrote:
On Jul 18, 2011, at 16:36 , Gabor Grothendieck wrote:
.
However, this was after reinstalling and reloading zoo. Restarting R and
retrying did indeed make things work.
Does the fact that it worked if R was
This **is** an inherently technical topic. Did you try the R Language
Manual section on environments (wasn't clear from your message)?
You might try posting on R-devel. Folks there may know of
tutorials/books that might be useful to you.
-- Bert
On Mon, Jul 18, 2011 at 11:16 AM, Nipesh Bajaj
On Jul 18, 2011, at 20:19 , Gabor Grothendieck wrote:
On Mon, Jul 18, 2011 at 1:59 PM, peter dalgaard pda...@gmail.com wrote:
On Jul 18, 2011, at 16:36 , Gabor Grothendieck wrote:
.
However, this was after reinstalling and reloading zoo. Restarting R and
retrying did indeed make
I would like to make stacked barplots, but with two stacked columns per x
value. For cod - I have kept and discard values for 2 nets. I would like
to have one stacked column for the control net with the kept and discard
value and then another column with the kept and discard values for the
Hi,
I'm very new to R. I am most interested in the variable importance measures
that result from randomForest, but many of my predictors are highly
correlated. My first question is:
1. do highly correlated variables render variable importance measures in
randomForest invalid?
and 2. I know that
I know there are several threads about IDEs for R.
I've tried Tinn-R, but I am looking for an IDE (win) with a preview function
that shows me the variables and the table/matrix etc. when klicking.
(comparable to Matlab). Does an IDE like this exist or can't IDEs give this
functionality in R?
Hello,
In order to reduce the width of my legend in a plot I introduced line jumps in
the title. Here's the problem; the legend box hasn't adapted accordingly and
part of the title is printed out of the frame.
See the example below:
plot(1:10)
legend(bottomright, bg=white,
Hi, R users,
I have a question about using ClassStat in SDMtools. I want to calculate
total edge of patch; however, according to FRAGSTAT, the total.edge value
of ClassStat means that total length (m) of edge in landscape involving
patch type (class) i; includes landscape boundary and background
Thanks, Dennis, for your suggestions. I was thinking about the package
'sqldf', but I guess that I must have a data frame to plot a
histogram.
Paul
On Fri, Jul 15, 2011 at 4:15 PM, Dennis Murphy djmu...@gmail.com wrote:
I would suggest that you avoid the histogram and make a density plot
On Mon, Jul 18, 2011 at 7:16 PM, Nipesh Bajaj bajaj141...@gmail.com wrote:
Hi all, I am trying to understand the R's environment concept
however the underlying help files look quite technical to me. Can
experts here provide me some more intuitive ideas behind this concept
like, why it is
On Mon, Jul 18, 2011 at 2:57 PM, peter dalgaard pda...@gmail.com wrote:
On Jul 18, 2011, at 20:19 , Gabor Grothendieck wrote:
On Mon, Jul 18, 2011 at 1:59 PM, peter dalgaard pda...@gmail.com wrote:
On Jul 18, 2011, at 16:36 , Gabor Grothendieck wrote:
.
However, this was after
Hi,
I am trying to install the package rblas which is an R interface to the BLAS
and LAPACK libraries. I have downloaded the rblas.tar from
Dear all,
I would like to estimate the standard errors of Klein and Spady's estimator
for that I am using:
library(np)
N-100
X-matrix(c(rnorm(N,1,1), rnorm(N,0,1)), ncol=2)
BETA -matrix(1,2,1)
Z-X%*%BETA
L-rlogis(N,location=0, scale=1)
Y -as.vector(X%*%BETA+L=0)*1
KS - npindexbw (xdat=X,
Hi all,
new to this forum
I'm try to using R to draw a heatmap of my RNA-seq data
before doing that I did a log2 transformation of my data and produce a lot
-inf in the matrix
when I try to use the heatmap function, it seems can not deal with the -inf
so I was wondering how to deal with these
On Jul 18, 2011, at 1:14 PM, Dutrieux, Loïc wrote:
Hello,
In order to reduce the width of my legend in a plot I introduced
line jumps in the title. Here's the problem; the legend box hasn't
adapted accordingly and part of the title is printed out of the frame.
See the example below:
I'm building R 2.13.1 on i686-pc-linux-gnu, using gcc 4.6.1
and with glibc 2.14.
I get this error:
In file included from xdr.c:61:0:
./rpc/types.h:63:14: error: conflicting types for 'malloc'
make[4]: *** [xdr.o] Error 1
I can make the build proceed some by commenting out the
declaration
On Jul 18, 2011, at 3:34 PM, rebioman wrote:
Hi all,
new to this forum
I'm try to using R to draw a heatmap of my RNA-seq data
before doing that I did a log2 transformation of my data and produce
a lot
-inf in the matrix
when I try to use the heatmap function, it seems can not deal with
On Mon, Jul 18, 2011 at 10:57 AM, Paul Smith phh...@gmail.com wrote:
[snip] I guess that I must have a data frame to plot a histogram.
Not at all!
## a *vector* of 100 million observation
x - rnorm(10^8)
## a histogram for it (see attached for the result from my system)
hist(x)
No data frame
I remember seeing an example using the EM algorithm where one of the variables
was age of child and they assumed that an age like 16 months was accurate to
the month, but ages like 18 months may have been off by as much as 2 months and
ages like 3 years could be off by 6 months (or more), so
There is one problem. No matter what I do, I can't recover the correct
runway in the final list.
You had rw = as.numeric(df$lrw) # index into 'levels'
I have tried
df$lrw = factor(df$lrw, ordered=TRUE)
rwys = factor(unique(df$lrw), ordered=TRUE)# Get the names of
the runways
rwys
A small modification of this would be:
library(TeachingDemos)
-3 %=% z %=% 3
Whether that is prettier or uglier than Jim's answer is in the eye of the
beholder (for longer variable names this version could save a few key strokes).
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Others have explained why R gives a different answer based on a different
approximation, but if you want to get the same answer as the book/minitab/...
for your own understanding (or so the grader doesn't get confused by superior
answers, or other reasons) here is one way to do it:
x - c(
Try RStudio. It is the best IDE for R I've seen.
On Tue, Jul 19, 2011 at 3:31 AM, Michael Bernsteiner
dethl...@hotmail.com wrote:
I know there are several threads about IDEs for R.
I've tried Tinn-R, but I am looking for an IDE (win) with a preview function
that shows me the variables and
There are several options depending on what exactly you want to do.
If you use code like:
write.table(x, 'clipboard', sep='\t')
In R, then go to excel and choose a cell and paste to it, the matrix or data
frame 'x' will be pasted into excel at that point (topleft corner of data goes
in
On Mon, Jul 18, 2011 at 9:11 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
[snip] I guess that I must have a data frame to plot a histogram.
Not at all!
## a *vector* of 100 million observation
x - rnorm(10^8)
## a histogram for it (see attached for the result from my system)
hist(x)
No
Note that the precendence of %=% is not the
same as that of =, so you can be surprised by its
behavior in slightly more complex expressions:
z - seq(1.2, len=5, by=.7)
which( 2 %=% z %=% 3 ) # same as which(2=z z=3)
[1] 3
which( 2 %=% z %=% 1.5*2 )
Error in which(2 %=% z %=% 1.5 *
Dear All,
I've tried install Rwinedt using my Winedt 6.
I cannot see R tab in Rwinedt even though I followed the instruction.
(Installed RWinEdt and called the library)
Version 6 doesn't work? If not, if would you recommend an R editor for
window user?(Except for Emacs)
Thanks,
Good point, I have added a note and example to the documentation to this effect.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: William Dunlap [mailto:wdun...@tibco.com]
Sent: Monday, July
Hey there,
I've got a for loop in my code which I'm having difficulty seeing how to
avoid.
Here's the code, with some sample data. You can safely copy and paste into
the interpreter if you want.
#I have some data frames.
a - as.data.frame(matrix(runif(50), nrow = 10, ncol = 5))
b -
We are trying to fit a multi-level logistic regression and we work with
public opinion data. Our dependent variable is interest in politics, a
dummy variable. We have individual and group-level (country) covariates.
Hence, we work with group level predictors. Actually, our theory argues
that, the
That what I did, I replaced the -infinite with lowest number I got from my
data set.
I'm not sure this kind of data manipulation is allowed in a publication
--
View this message in context:
http://r.789695.n4.nabble.com/heatmap-with-RNA-Seq-data-tp3676207p3676280.html
Sent from the R help
Good Evening,
my aim is to perform a multiple correspondence analysis on a textual matrix
by using the ‘ca’ package, which performs a 3d visualization of the results.
Specifically, the frequency matrix contains words (rows) and variables
(columns), and the contempt of each cell is the occurrence
Thanks, I just upgraded to 1.7.1
Also thanks for adding the t() function.
On Mon, Jul 18, 2011 at 12:38 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Mon, Jul 18, 2011 at 2:57 PM, peter dalgaard pda...@gmail.com wrote:
On Jul 18, 2011, at 20:19 , Gabor Grothendieck wrote:
Hi All:
Along with Applied Sciences Associates we have been working on a GUI add-on for
R that allows easy access to literally pterabytes of remote oceanographic and
meteorological data that can be subsetted in time and space, and then will be
brought directly into R using web services. The
Clarification question: does one need Mplus installed in order to use
Mplus Automation package?
--
Dimitri Liakhovitski
www.ninah.com
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
On Mon, Jul 18, 2011 at 06:36:13AM -0400, Sarah Goslee wrote:
Your data1 and your data1_class file differ in the first three
columns. Assuming that's an error, here's one way to do it:
data1 - data.frame(layer1=c(.2, .5, .2, .8, .2, .5, .5, .8, .2,
.8),layer2=c(2,3,2,2,1,2,3,2,2,2),
To recover the runways, try:
levels(df$lrw)[times[, 'runway']]
The 'runway' column has the index into 'levels(df$lrw)'
On Mon, Jul 18, 2011 at 4:35 PM, James Rome jamesr...@gmail.com wrote:
There is one problem. No matter what I do, I can't recover the correct
runway in the final list.
You
Apologies for a naive question: Can R be installed and run on a server
(operating system Windows Server 2008)?
Thank you!
--
Dimitri Liakhovitski
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
On Mon, Jul 18, 2011 at 2:08 PM, Paul Smith phh...@gmail.com wrote:
On Mon, Jul 18, 2011 at 9:11 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
[snip] I guess that I must have a data frame to plot a histogram.
Not at all!
## a *vector* of 100 million observation
x - rnorm(10^8)
## a
Ok, I think I had a good idea to solve my problem and need someone who second
me on that or tell me what a fool I am :-) .
My problem: I went for curve-fitting with nls() and took knot()-ecdf() for
collecting data for nls-basis-dataframe. I came into trouble, because my
x-y-data of the
1 - 100 of 109 matches
Mail list logo
