Hi everyone,
Suppose I have a list named lst, see below:
lst
$sub1
...
$sub1$x
...
$sub1$y
$sub2
...
$sub2$x
...
$sub2$y
…
$sub3
...
...
...
Now, I want to extract the sub-sublist $y from every sublist(sub1, sub2...)
and then storage them to a new list.
I know how to extract them by
Hello
I am trying to draw a basic black and white map of two European countries.
After searching some key words in google and reading many pages I arrived to
the conclusion that persp() could be used to draw that map.
I have prepared three small example files, which are supposed to be the
I'm fitting a logistic regression model of the form:
outcome ~ covariates + A*B
where A and B are factors -- A has 4 levels, B has 2 levels. The A
and B term each have significant main effects and the interaction term
is significant. I'd like to ask, how does a particular set of A and B
You defined temp as a vector:
temp - vector(mode=numeric, length = vl)
but you try to extract from it as if it was a 2d object:
colA - temp[,compareA]
Maybe you meant to use temp1 instead? More meaningful variable names might
help avoid such mistakes.
On Wed, Aug 3, 2011 at 6:14 PM, Matt
Thank you so much GlenB!
I got it done using your method.
I'm just curious how did you get this idea? Cause for me, this looks so
tricky
Cheers,
Richard
-
I'm a PhD student interested in Remote Sensing and R Programming.
--
View this message in context:
Hi,
I've written a package and converted my Rd files into LaTeX using
Rdconv. When I copy and paste these files in to my Sweave document I
get the error message when compiling the Sweave file:
! Undefined control sequence.
l.32 \inputencoding
{utf8}
I also get the error
Hi C6 (were C1 - 5 already taken in your family?),
I downloaded your data and can replicate your problem. R ceases
responding and terminates. This does not occur with all uses of qr on
a dgCMatrix object. I know nothing about sparse matrices, but if you
believe this should not be occurring,
Dear All,
How would we do this problem looping over seq(1:2) ?
Thank you,
Ashim
On Thu, Aug 4, 2011 at 10:59 AM, Richard Ma xuanlong...@uts.edu.au wrote:
Thank you so much GlenB!
I got it done using your method.
I'm just curious how did you get this idea? Cause for me, this looks so
How would we do this problem looping over seq(1:2) ?
To extend the example in the corresponding nabble post : -
sub1-list(x=a,y=ab)
sub2-list(x=c,y=ad)
lst-list(sub1=sub1,sub2=sub2)
for ( t in seq(1:2) ) print(lst[[t]]$y)
So I can print out the sub1$y/sub2$y but it's not clear how to
On Thu, Aug 4, 2011 at 12:12 AM, Ashim Kapoor ashimkap...@gmail.com wrote:
How would we do this problem looping over seq(1:2) ?
Because this goes to an email list serv, it is good practice to quote
the original problem. I have no idea what this is.
To extend the example in the corresponding
Thank you very much, Josh!
As you suggested, I will contact the developers of Matrix.
PS, C6 are just initial characters of my email account :-)
Best wishes,
C6
2011/8/4 Joshua Wiley jwiley.ps...@gmail.com:
Hi C6 (were C1 - 5 already taken in your family?),
I downloaded your data and can
On Thu, Aug 4, 2011 at 1:02 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
On Thu, Aug 4, 2011 at 12:12 AM, Ashim Kapoor ashimkap...@gmail.com
wrote:
How would we do this problem looping over seq(1:2) ?
Because this goes to an email list serv, it is good practice to quote
the original
On Thu, Aug 4, 2011 at 1:40 AM, Ashim Kapoor ashimkap...@gmail.com wrote:
On Thu, Aug 4, 2011 at 1:02 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
On Thu, Aug 4, 2011 at 12:12 AM, Ashim Kapoor ashimkap...@gmail.com
wrote:
How would we do this problem looping over seq(1:2) ?
Because
Dear R-Users,
I want to use mtable from package memisc to produce Latex-style estimation
output. However, mtable() only gives me a p-value and not the corresponding
test-statistic. Does anyone know how to extract it, either from a glm/anova
object or mtable? Here is a short example:
# Run this
Hi Erich,
Thanks for the example. You can access the coefficient table output
by a call to summary:
coef(summary(res1))
so if you want the test statistic (the t value here), just extract the
third column of the matrix:
coef(summary(res1))[, 3]
or to keep in matrixy form
On Thu, Aug 4, 2011 at 2:12 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
On Thu, Aug 4, 2011 at 1:40 AM, Ashim Kapoor ashimkap...@gmail.com
wrote:
On Thu, Aug 4, 2011 at 1:02 PM, Joshua Wiley jwiley.ps...@gmail.com
wrote:
On Thu, Aug 4, 2011 at 12:12 AM, Ashim Kapoor
On Thu, Aug 4, 2011 at 2:08 AM, Ashim Kapoor ashimkap...@gmail.com wrote:
On Thu, Aug 4, 2011 at 2:12 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
On Thu, Aug 4, 2011 at 1:40 AM, Ashim Kapoor ashimkap...@gmail.com
wrote:
On Thu, Aug 4, 2011 at 1:02 PM, Joshua Wiley
Thanks for reporting this. It was a bug, now fixed in gamm4 0.1-3. Simon
On 19/07/11 22:16, Melinda Power wrote:
Hello,
I'm running mixed models in GAMM4 with 2 (non-nested) random intercepts and
I want to include a spline term for one of my exposure variables. However,
when I include a
Thank you Joshua.
Ashim.
On Thu, Aug 4, 2011 at 2:53 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
On Thu, Aug 4, 2011 at 2:08 AM, Ashim Kapoor ashimkap...@gmail.com
wrote:
On Thu, Aug 4, 2011 at 2:12 PM, Joshua Wiley jwiley.ps...@gmail.com
wrote:
On Thu, Aug 4, 2011 at 1:40 AM,
Wir sind bis am 20. August in den Ferien und werden keine e-mails beantworten.
Bei dringenden Fällen melden Sie sich bei Stefanie von Felten
steffi.vonfel...@oikostat.ch
We are on vacation until 20. August. In urgent cases, please contact Stefanie
von Felten steffi.vonfel...@oikostat.ch
On 08/03/2011 11:07 PM, wwreith wrote:
So I take it 3D pie charts are out?
P.S. It is not about hiding anything. It is about consulting and being told
by your client to make 3D pie charts and change this font or that color to
make the graphs more apealing. Given that I am the one trying to open
Hi Richard,
Have you configured Tinn-R to work with R?
Check your Rprofile.site
#quick configuration check in R
grep(.trPaths,readLines(file.path(R.home(component=etc),Rprofile.site)))0
If that fails, Tinn-R helps you to do all the necessary config steps,
just use the menu
R - Configure -
Thanks, Peter and David, for the pointers -and my apologies to the list for
posting to the wrong place; i will in future use the SIG-Mac list for such
things.
To the problem: Yes, i did indeed make that fundamental error of taking the
R.app GUI package to be all i needed to run the program. I
Dear All,
I am using rhierMnlRwMixture in the bayesm package for the analysis of data
from a choice experiment. I am trying to follow the margarine example set
out in the bayesm manual (p.28). However, after several attempts I keep
getting an error message with regards to my Z matrix as below.
## I clicked the send-button too quickly, before changing the title of the
message etc... Sorry.##
I am running following phylogenetic analyses with the caper package:
data=read.table(file=data.txt,header=T,sep=\t)
tree = read.nexus(Tree.nex)
primate = comparative.data(phy=tree, data=data,Â
Â
hi everyone,
i had the same problem, i simply wrote:
*ifelse(is.infinite(AALB),NA,AALB)*
this code replace infinite values by NA's, then you can use na.omit,
replace, or even a zero, which is my case.
goog luck Nigel
--
View this message in context:
Dear List's Members,
I'm trying to implement 1. Roger Klein and Francis Vella, “A semiparametric
model for binary response and continuous outcomes under index
heteroscedasticity,” Journal of Applied Econometrics 24, no. 5 (2009):
735-762.
estimator. I have a technical doubt about the choice of
I have run into a speed issue, and given the size of the problem it feels
like there should be an easy solution. Here is the problem statement with
some arbitrary numbers added.
#p,q: vector with length(q)==length(p)==1 and length(levels(p))==3000
#y,z: vectors with
Hi, have you considered using array,
for example
example-array(1,dim=c(2,2,3))
dimnames(example)-list(c(x1,x2),c(y1,y2))
then if you want to extract the component x1,y1 from every member of the
list of matrices you have to
example[x1,y1,]
leaving blank in the last position.
hope it helps.
Thanks, Michael. I was, however, after a function I coul use for both
extracting and replacing subarrays. In case anybody else stumbles over
this problem, here is my solution. Its programming is most probably
horribly clumsy:
ind.datacube = function(
##title create logical index matrices for
Use extractAIC in frailty cox model (estimated with coxph function, gaussian
random effect) i obtaided
extractAIC(fit.cox.f)
[1] 11.84563 8649.11736
but I don't know why I can't use the classic formulation of the AIC where
the degree of freedom are the number of the parameter (in my case 3).
Many thanks, Greg. It works like a dream.
Best wishes,
Pete
From: Greg Snow greg.s...@imail.org
To: Peter Morgan morga...@cardiff.ac.uk, r-help@r-project.org
r-help@r-project.org
Date: 03/08/2011 19:06
Subject:Re: [R] Coefficient names when using lm() with contrasts
Sent by:
Hi Joshua,
Really helpful that you posted so many useful solutions for my problem.
I can understand all your codes except these:
*[code]
lapply(lst, `[[`, y)
## or if you are only retrieving a single value
sapply(lst, `[[`, y)
[/code]*
Can you explain these a little bit? What does '[[' means?
The Centre for Multilevel Modelling is very pleased to announce the
addition of R practicals to our free on-line multilevel modelling course.
These give detailed instructions of how to carry out a range of analyses
in R, starting from multiple regression and progressing through to
multilevel
Dear R-Users,
I am using R for years now but recently I encounter a problem with the
pdf-size of graphics generated with sweave. However, I am new in this forum.
Hence, please don't hesitate if I am wrong here.
I use a script which runs perfectly in R 2.11.1 and the pdf-size of the
graphs is
A subset of actual data and what you would expect as a result would be
very helpful. All you say is that p.q are vectors, but it would
appear that they are character vectors, but the content is unknown.
Also will the expression q[i==p]-z[i==y] have the same length on
each side; the vectors
Duncan Murdoch murdoch.dun...@gmail.com
on Tue, 2 Aug 2011 16:51:38 -0400 writes:
On 11-08-02 2:39 PM, wwreith wrote:
Does anyone know how to create a 3D Bargraph using
ggplot2/qplot. I don't mean 3D as in x,y,z coordinates. Just a
2D bar graph with a 3D shaped bard.
Hi Rosario,
you might have a look at the maps and maptools (for reading
shape-files) packages.
#e.g.
library(maps)
map(world,c(sweden,germany))
Cheers
Am 04.08.2011 02:58, schrieb Rosario Garcia Gil:
Hello
I am trying to draw a basic black and white map of two European countries.
After
Rosario,
I don't think persp() is the function you need.
You may find that the maps in R's historical world map would work for you.
In that case you can try something like this (an example mapping France
and Germany):
require(maps)
map(world, c(France, Germany), xlim=c(-6.61, 17.21),
On 11-08-04 1:42 AM, Michael O'Keeffe wrote:
Hi,
I've written a package and converted my Rd files into LaTeX using
Rdconv. When I copy and paste these files in to my Sweave document I
get the error message when compiling the Sweave file:
! Undefined control sequence.
l.32 \inputencoding
Try this:
q - z[match(p, y)]
Jean
`·.,, (((º `·.,, (((º `·.,, (((º
Jean V. Adams
Statistician
U.S. Geological Survey
Great Lakes Science Center
223 East Steinfest Road
Antigo, WI 54409 USA
715-627-4317, ext. 3125 (Office)
715-216-8014 (Cell)
715-623-6773 (FAX)
On 11-08-04 8:20 AM, Martin Maechler wrote:
Duncan Murdochmurdoch.dun...@gmail.com
on Tue, 2 Aug 2011 16:51:38 -0400 writes:
On 11-08-02 2:39 PM, wwreith wrote:
Does anyone know how to create a 3D Bargraph using
ggplot2/qplot. I don't mean 3D as in x,y,z coordinates.
I am trying to correct for the effect of 2 covariates in a gene expression data
set.
design-model.matrix(~0 + Factor + cov1 + cov2)
QUESTION:
How to set up the contrast matrix?
The usual commands
fit - lmFit(selDataMatrix, design)
cont.matrix - makeContrasts(FacCont=Group1-Group2,
Hello,
I have an input file that contains multiple columns, but the column I'm
concerned about looks like:
TR
5
0
4
1
0
2
0
To count all of the rows in the column I know how to do NROW(x$TR) which
gives 7.
However, I would also like to count only the number of rows with values =1
(i.e. not 0).
C6H5NO2 c6h5...@gmail.com
on Thu, 4 Aug 2011 16:03:54 +0800 writes:
Thank you very much, Josh!
As you suggested, I will contact the developers of Matrix.
PS, C6 are just initial characters of my email account :-)
Best wishes,
C6
well, as the posting guide
Hi
r-help-boun...@r-project.org napsal dne 04.08.2011 14:56:09:
a217 aj...@case.edu
Odeslal: r-help-boun...@r-project.org
04.08.2011 14:56
Komu
r-help@r-project.org
Kopie
Předmět
[R] Counting rows given conditional
Hello,
I have an input file that contains multiple
Sorry for renewing the topoic. I thought it worked but now I've run
into a little problem:
# My data frame with dates for week starts (Mondays)
y-data.frame(week=seq(as.Date(2009-12-28),
as.Date(2011-12-26),by=week) )
# I have a vector of super bowl dates (including the future one for 2012):
Hi John,
The limma package is part of Bioconductor, so you should be asking this
question on the BioC listserv bioconduc...@r-project.org rather than
R-help.
In addition, please see the posting guide. The example you give is not
self-contained, and the term 'does not work' is so unspecific
I'm not Josh Wiley, but I think I can answer this:
When dealing with lists, its often more convenient to use [[ instead of
[ because [ returns a single element list while [[ returns the list
element itself. (i.e., if I set x = list(Q = rnorm(64), V =
matrix(rnorm(64),8)) then x[Q] is a list that
Hi,
I am using ggplot2 to with the following code:
gmathk2 -
qplot(time,math,colour=Kids,data=kids.ach.lm.k5,geom=smooth,method=lm,formula=y~ns(x,1))
+ opts(title=Smoother Plot: Math K-5) + xlab(Time) + ylab(Math) +
scale_colour_brewer(pal=Set1); gmathk2
This plots all the smoother for all the x
Worked like a charm!
Thanks a lot Jean V Adams
--
View this message in context:
http://r.789695.n4.nabble.com/R-loop-problem-tp3718449p3718670.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Dear list,
I would like to plot several age distributions that are influenced by a factor
(called group in the data example below). I would like to use historam() in the
lattice package, but I can't figure out how to set up the data. Could someone
give me a hint how to do it for the example
Best I know, they are effectively the same** within R but I prefer [ for a
couple of reasons.
1) [ works for all data types, while $ is sometimes picky: e.g.,
x = matrix(rnorm(9),3); colnames(x) - c(a,b,c)
x.df = as.data.frame(x)
x$a gives Error in x$a : $ operator is invalid for atomic vectors
Hi all,
After reading this interesting discussion I delved a bit deeper into the
subject matter. The following snippet of code (see the end of my mail)
compares three ways of performing this task, using ddply, ave and one
yet unmentioned option: data.table (a package). The piece of code
Thanks!
I found (by properly reading docs) to use the inputenc package. The Rd
package solve most problems except for where I has a multiple line
code element in my Rd file. I tried to convert it to a LaTeX Rd 'code'
element and use an 'alltt' environment to hold the multi-line text. I
worked
On 08/04/2011 08:53 AM, Belmont, John W wrote:
I am trying to correct for the effect of 2 covariates in a gene
expression data set.
design-model.matrix(~0 + Factor + cov1 + cov2)
QUESTION: How to set up the contrast matrix?
The usual commands
fit - lmFit(selDataMatrix, design)
cont.matrix -
It's not immediately obvious
You need to look at coord_cartesian() and its ylim argument.
Best, t
Sent from my iPhone
On 4 Aug 2011, at 02:38 PM, Christopher Desjardins cddesjard...@gmail.com
wrote:
Hi,
I am using ggplot2 to with the following code:
gmathk2 -
Thank you, Martin.
Yes, on my computer (48Gb memory) it also gives a message caught
segfault as you got. So it is because the matrix size is too large.
I apologize for the offence I've caused.
2011/8/4 Martin Maechler maech...@stat.math.ethz.ch:
C6H5NO2 c6h5...@gmail.com
on Thu, 4 Aug
Dear all,
I used modFit of the package FME to fit a set of ODE to a ste of eperiemntal
data.
The summary of this fit give me the following error
summary(Fit)
Residual standard error: 984.1 on 452 degrees of freedom
Error in cov2cor(x$cov.unscaled) : 'V' is not a square numeric matrix
In
Hello!
I have a data set:
set.seed(123)
y-data.frame(week=seq(as.Date(2010-01-03), as.Date(2011-01-31),by=week))
y$var1-c(1,2,3,round(rnorm(54),1))
y$var2-c(10,20,30,round(rnorm(54),1))
# All I need is to create lagged variables for var1 and var2. I looked
around a bit and found several ways of
Hi, all,
I'm trying to modify the code to a log scale for y-axis from the post
http://tolstoy.newcastle.edu.au/R/help/06/06/28612.html
However, the error bar did not change accordingly. The following is the code I
used based on the singer.ucl data.
Thanks in advance!
prepanel.ci - function(x,
If you start looking at the time series classes (xts, zoo, etc) they have
very quick and flexible lag functions built in.
Might this be a slightly more efficient solution for the homebrew
implementation?
OurLag - function(y, k=1) {
t = y[,1,drop=F]; d = y[,-1,drop=F];
if (is.matrix(y))
Dear all,
I used modFit of the package FME to fit a set of ODE to a ste of
experimental data.
The summary of this fit give me the following error
summary(Fit)
Residual standard error: 984.1 on 452 degrees of freedom
Error in cov2cor(x$cov.unscaled) : 'V' is not a square numeric matrix
In
More than happy to help.
I think the term is sparse matrix.
I haven't totally wrapped my mind around why your version seems to work (and
testing it, it does seem to work for non-sparse matrices as well), but
still, if it makes sense to you, why bother with adding one to the sum and
the if
You are getting 105 because the default behavior of findInterval is such
that v[N+1] := + Inf (as noted in ? findInterval); that is, the last
interval is actually taken to stretch from the final element of sbwl.dates
unto eternity. It shouldn't be hard to write a catch line to set that to
Michael, thanks a lot!
Really appreciate it - what wasn't hard for you would be for me!
Dimitri
On Thu, Aug 4, 2011 at 2:20 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
You are getting 105 because the default behavior of findInterval is such
that v[N+1] := + Inf (as noted in ?
Hi, I was reading a paper published in JCO Prediction of risk of distant
recurrence using 21-gene recurrence score in node-negative and node-positive
postmenopausal patients with breast cancer treated with anastrozole or
tamoxifen: a TransATAC study (ICO 2010 28: 1829). The author uses a method
Thanks a lot, guys!
It's really helpful. But - to be objective- it's still quite a few
lines longer than in SPSS.
Dimitri
On Thu, Aug 4, 2011 at 2:36 PM, Daniel Nordlund djnordl...@frontier.com wrote:
-Original Message-
From: r-help-boun...@r-project.org
But quite a few thousand dollars cheaper - seems a fair trade to me!
Seriously though: your last few requests have been focused on time objects,
so I strongly suggest you take a look at xts/zoo (
http://cran.r-project.org/web/packages/xts/index.html) -- it will make time
objects much easier for
Hello everyone,
I need to do a sample size calculation. The study two arms and two endpoints.
The two arms are two different cancer drugs and the two endpoints reflect
efficacy (based on progression free survival) and toxicity.
Until now, I have been trying to understand this in terms of a
I'm just wondering
When I use your function on your data I get a result that is not very
intuitive. Is this what you were trying to do?
(I took the liberty of setting dims to 3 since 'auto', 1, and 2 didn't
work.
data- array(rnorm(64),dim=c(4,4,4))
indices-
-Original Message-
From: Dimitri Liakhovitski [mailto:dimitri.liakhovit...@gmail.com]
Sent: Thursday, August 04, 2011 11:47 AM
To: Daniel Nordlund; r-help
Subject: Re: [R] Efficient way of creating a shifted (lagged) variable?
Thanks a lot, guys!
It's really helpful. But - to be
Dear All,
Suppose that you are trying to create a binary logistic model by
trying different combinations of predictors. Has R got an automatic
way of doing this, i.e., is there some way of automatically generating
different tentative models and checking their corresponding AIC value?
If so, could
Marc,
Try this one
barchart(data=dta, ~x, group=y,
stack=T,col=sort(brewer.pal(7,Purples)), xlab=Percent,
box.width=.5, scales=list(tick.number=10),
panel=function(x,y,...){
panel.barchart(x,y,...)
panel.text(cumsum(x)-dta$x/2,y,labels=dta$x)
Sounds like you want a best subsets regression, the bestglm() function,
found in the bestglm() package will do the trick.
Jeremy
On 4 August 2011 12:23, Paul Smith phh...@gmail.com wrote:
Dear All,
Suppose that you are trying to create a binary logistic model by
trying different
Dear R-users
I am trying to understand how Sweave works by running some simple examples. In
the example I am working with there is a chunk where the R-commands related to
plotting a figure are placed. When running R CMD Sweave … , pdflatex the
output is a portrait figure. I wonder whether
Hi Jannis,
Like Gene, I'm not entirely sure what your code is intended to do, but it
wasn't hard to adapt mine to at least print out the desired slice through
the higher-dimensional array:
cubeValues - function(Insert, Destination, Location) {
Location = as.matrix(Location)
Location =
On Aug 4, 2011, at 11:46, Dimitri Liakhovitski dimitri.liakhovit...@gmail.com
wrote:
Thanks a lot, guys!
It's really helpful. But - to be objective- it's still quite a few
lines longer than in SPSS.
Not once you've sources the function! For the simple case of a vector, try:
X - 1:10
On 04/08/2011 3:40 PM, Eduardo M. A. M. Mendes wrote:
Dear R-users
I am trying to understand how Sweave works by running some simple examples. In
the example I am working with there is a chunk where the R-commands related to
plotting a figure are placed. When running R CMD Sweave … ,
Hi,
I am looking for the equivalent of capture.output for stdin. Imagine I am
writing a test for a function that reads from stdin, say scan.
1: foobar
2: Read 1 item
[1] foobar
(please don't reply that scan can also read from a file, that's not what I
am trying to test; let's say I found a bug
Dear John
I am not aware of an R package that does this, but I believe that Patrick
Royston's -stpm- function for Stata does. Here's two references found in
http://www.stata-journal.com/sjpdf.html?articlenum=st0001_2:
Royston, P. 2001. Flexible parametric alternatives to the Cox model. Stata
David and Josh,
Thank you for the suggestions. I have attached a file ('q_values.txt') that
contains the values of the 'Q' variable.
David -- I am attempting an 'S' mode PCA, where the columns are actually the
cases (different stream gaging stations) and the rows are the variables (the
maximum
On Aug 4, 2011, at 2:40 PM, Eduardo M. A. M. Mendes wrote:
Dear R-users
I am trying to understand how Sweave works by running some simple examples.
In the example I am working with there is a chunk where the R-commands
related to plotting a figure are placed. When running R CMD Sweave
I did save workspace and when I load it, I can see the variables,
using ls().
But I cannot see the commands from the program I saved. How to do
that?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
I am using SRC function in the sensitivity library. The independent
variables (X) are a few dummy variables and the dependent variable (y)
is numeric, ranged from 0,18 to 0.84. Example of independent variables
are red coded as [0,0,0,1], green [0,0,1,0], blue [0,1,0,0], and
yellow [1,0,0,0]. Error
Wonderful! Thanks, Jeremy.
Is bestglm() also able of trying nonlinear transformations of the
variables, say log(X1) for instance?
Paul
On Thu, Aug 4, 2011 at 8:28 PM, Jeremy Miles jeremy.mi...@gmail.com wrote:
Sounds like you want a best subsets regression, the bestglm() function,
found in
Hi
I am looking at generating a random dataset of say 100 values fitting in a
normal distribution of a given mean and SD, I am aware of rnorm
function. However i am trying to build into this function one added
constraint that all the random value generated should also obey the
constraint that they
Thanks a lot for the recommendations - some of them I am implementing already.
Just a clarification:
the only reason I try to compare things to SPSS is that I am the only
person in my office using R. Whenever I work on an R code my goal is
not just to make it work, but also to boast to the SPSS
On 04/08/2011 12:03 PM, Vijayan Padmanabhan wrote:
Hi
I am looking at generating a random dataset of say 100 values fitting in a
normal distribution of a given mean and SD, I am aware of rnorm
function. However i am trying to build into this function one added
constraint that all the random
On Aug 4, 2011, at 2:23 PM, Paul Smith wrote:
Dear All,
Suppose that you are trying to create a binary logistic model by
trying different combinations of predictors. Has R got an automatic
way of doing this, i.e., is there some way of automatically generating
different tentative models and
Thanks, Gene, for your hint! I indeed did not check any possible
situation and my function was not returning what I intened it to return.
This updated version, however, should. I am sure there are much easier
ways (or ready made functions) to do the same.
ind.datacube = function(
##title
Dear All,
I am trying to add some text annotation to a graph using matplot() as
follows:
vars - c(v1, v2, v3, v4, v5, v6, v7, v8, v8, v10)
id - seq(5.000, 0.001, by = -0.001)
sid - c(4.997, 3.901, 2.339, 0.176, 0.151, 0.101, 0.076, 0.051, 0.026,
0.001)
rn - sample(seq(0, 0.6, by =
Hello,
I am running randomForest models on a number of species. I would like to be
able to automate the printing of dependence plots for the most important
variables in each model, but I am unable to figure out how to enter the
variable names into my code. I had originally thought to extract
(I was just about to send this before your last reply)
As a more general tip, I find that using %in% is easier to understand than
is.element and setdiff because it can be more universal, especially when
combined with all and the !.
To me the functions like setdiff are easier to read, but harder
Check out ?savehistory in utils.
Also, I think most GUI's do this - I can certainly attest that RStudio does
Michael Weylandt
On Thu, Aug 4, 2011 at 11:55 AM, Bogdan Lataianu bodins...@gmail.comwrote:
I did save workspace and when I load it, I can see the variables,
using ls().
But I cannot
On Aug 4, 2011, at 2:03 PM, Paul Miller wrote:
Hello everyone,
I need to do a sample size calculation. The study two arms and two endpoints.
The two arms are two different cancer drugs and the two endpoints reflect
efficacy (based on progression free survival) and toxicity.
Until
Hi,
Does anyone know of a package that implements Multi-task SVM in R? I found
one in Matlab :
http://www.ece.umn.edu/users/cherkass/predictive_learning/Resources/MTL_Software_Description.pdf
I was wondering if there is something similar in R?
Thank you for your help.
Sincerely,
Vishal
This function you wrote is interesting, but I almost missed it since I
didn't see a direct example!
cubeValues(NULL, data, indices)
cubeValues(1, data, indices)
cubeValues(c(1,2), data, indices)
(sorry if I'm beating a dead horse here)
On Thu, Aug 4, 2011 at 2:58 PM, R. Michael Weylandt
I realize this should be simple, but even after reading over the several
help pages several times, I still cannot decide between the myriad apply
functions to address it. I simply want to apply a function to all the rows
(or columns) of the same index from two (or more) identically sized arrays
Hi all, the reference for this method was:
“Flexible parametric proportional-hazards and proportional-odds models for
censored survival data, with application to prognostic modeling and estimation
of treatment effects” published in Stat Med (2002) 21: 2175
The abstract is:
Modelling of
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