Hi David,
Thank you very much. Problem solved.
sapply() and lapply() are so powerful that even I have read their documents
several times, still lots of tricky stuff to learn and try.
Thank you again!
Richard
David Winsemius wrote:
sapply(c(hsp, dal), function(x) locpoly(x=ts,
Hi Remko,
How about ?try
Hope it helps,
Tsjerk
Not quite, because then the code chunk in the final doc. will have this
try() around it as well - not too pretty for a user manual.
remko
On Aug 9, 2011 5:30 AM, Remko Duursma remkoduur...@gmail.com wrote:
Dear R-helpers,
sorry if
I am trying to convert a matlab code to R.
Most of the conversion statements are simple, but problem is with return.
Since it's a recursive function it's a bit complicated. Anyway in matlab
we can have return statment like
[price, notional] = functionname()
and also for the same function...
Hello,
I can't seem to add transparency to any color ramp I create using
colorRampPalette(). Can someone tell me if it is possible to create transparent
colour ramps?
I am attempting to map shaded relief under elevation data. I know I can use the
terrain.colors() with the alpha option, but
Hi Remko
After thinking about try and tryCatch the problem was catching the error
what about ?captureOutput
Regards
Duncan
At 14:28 09/08/2011, you wrote:
Hi Remko,
How about ?try
Hope it helps,
Tsjerk
Not quite, because then the code chunk in the final doc. will have this
try()
On Aug 9, 2011, at 02:38 , Kathie wrote:
Thanks a lot all of you
Yes, you're right.
However, as i know, do.call calls its function once, but apply(or sapply
etc) not. So, I think do.call is faster than apply. That's why i am trying
to use do.call.
Am I right??
You're not getting the
Hi Remko,
You can modify the behaviour upon errors by setting the error option. Check
?option and ?stop
Cheers,
Tsjerk
On Aug 9, 2011 8:35 AM, Duncan Mackay mac...@northnet.com.au wrote:
Hi Remko
After thinking about try and tryCatch the problem was catching the error
what about
On 08/09/2011 04:39 AM, Annabel wrote:
I am trying to convert a matlab code to R.
Most of the conversion statements are simple, but problem is with return.
Since it's a recursive function it's a bit complicated. Anyway in matlab
we can have return statment like
[price, notional] =
I understood that the function has to be vectorized.
I was just wondering which one is faster.
Thanks
--
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You can modify the behaviour upon errors by setting the error option. Check
?option and ?stop
I looked at the 'error' settings in ?options, but I am not sure how that
would be helpful, since I am trying to avoid Sweave from halting after an
error occurs. I still want the error to be printed,
Hi
Hi R help,
I am trying to determine how nls() generates a function based on the
self-starting SSlogis and what the formula for the function would be.
I've scoured the help site, and other literature to try and figure
this out but I still am unsure if I am correct in what I am coming up
On 09.08.2011 02:32, Michael Sumner wrote:
Is it this?
https://stat.ethz.ch/pipermail/r-devel/2011-July/061540.html
Try a recent version of R 2.13.1 patched
Where it has been fixed by Duncan Murdoch.
Uwe
On Tue, Aug 9, 2011 at 1:53 AM, Colin Fordcol_f...@yahoo.com wrote:
Hi Pete,
I
Hi Remko,
The default behaviour of R upon encountering an error is to stop
execution of whatever is happening. To circumvent that, you have to
catch the error, using try, or you have to change the reaction of R to
errors, using 'options'. The help page for ?stop gives an explicit
example of the
On 11-08-08 9:48 PM, Remko Duursma wrote:
Dear R-helpers,
sorry if this is obvious, but I can't find this in the documentation.
I am using Sweave, and have some code that does not actually work - but I
want to include it anyway, including the error message that R produces.
But on running
Dear List,
I'm trying to draw vector in XYZ with rgl under use of a cylinder3d.
Therefore I scale and rotate a basis-cylinder).
However, somehow the rotation is wrong as
verified by overplotting arrow3d().
Where is my mistake?
library(heplots)
library(rgl)
# ... 2 vectors
On Aug 9, 2011, at 09:44 , Kathie wrote:
I understood that the function has to be vectorized.
I was just wondering which one is faster.
do.call is as fast as just calling the function. If you need to Vectorize() the
function first, then that in itself inserts a mapply() call, so you're
Dear Remko,
Here is a working example on what Duncan suggested.
Best regards,
Thierry
echo = TRUE, eval = TRUE=
TheObject - Something
ls()
rm(TheObject)
@
%outputs the R code but does not execute it. So no error
echo=TRUE, eval=FALSE=
TheObject
@
% executes the code but displays only the
On 11-08-09 5:22 AM, René Mayer wrote:
Dear List,
I'm trying to draw vector in XYZ with rgl under use of a cylinder3d.
Therefore I scale and rotate a basis-cylinder).
However, somehow the rotation is wrong as
verified by overplotting arrow3d().
Where is my mistake?
I would guess it is in
Yes that sounds very much like it. I'm using R 13.1 on Windows 7 32 bit. I did
do a search but didn't find anything - probably not using the correct search
terms. Glad its not just me.
Thank you,
Col.
From: Michael Sumner mdsum...@gmail.com
Cc: Peter Morgan
Thanks Duncan.
I ended up resorting to lt;eval=FALSEgt;, and just adding the error
message 'manually', which is what the Schunk approach does as well.
Unfortunately, the highlight package does not work with that Schunk -
because it replace the Sweave driver, but anyway, this is close enough.
Dear List,
I like to assign names to vectors in a loop.
Here is a short example:
DMUs -
as.data.frame(matrix(c(b,c,d,a,e,h,i,f,g,j,k,l),ncol
=7, nrow=10))
colnames(DMUs) - v_DMUs - c(a,b,c,d,e,f,g)
for (i in v_DMUs)
assign(paste(eff_val,i,sep=.),abs(rnorm(10)))
Now I like to
On 08/09/2011 03:10 AM, az...@illinois.edu wrote:
Original message
Date: Wed, 3 Aug 2011 16:06:33 -0500 (CDT)
From:az...@illinois.edu
Subject: Need help with xyplot
To: r-help@r-project.org
Consider I have the following data:
AgeRangeAgeOfPerson PersonNo
Hi
Dear List,
I like to assign names to vectors in a loop.
Here is a short example:
DMUs -
as.data.frame(matrix(c(b,c,d,a,e,h,i,f,g,j,k,l),ncol
=7, nrow=10))
colnames(DMUs) - v_DMUs - c(a,b,c,d,e,f,g)
for (i in v_DMUs)
assign(paste(eff_val,i,sep=.),abs(rnorm(10)))
Now I like to
Thanks Duncan!
yes! this works;
I paste the code in case someone wants to draw
3d-vectors with cylinders and cones.
René
vector3D=function(start=c(0,0,0), end, mycol='green', cone.length=0.1, ... ){
# ... cylinder as basis-vector
c=cylinder3d(rbind( c(start), # start
Hi r-help,
I use lavaan:sem() for structural equation modelling with latent
variables. Below is a reproducible example (the code requires a
working installation of lavaan) where the latent variable criminality
is in focus. Besides criminality in general, I am specifically
interested one of the
My question is: how can I analyse the part of the variation in
fire.setting that is not included in the latent variable criminality?
Ideally I would want a new variable that captures just this. Then I
could model regressions with this variable as the dependent variable.
You can add a
Dear Sir/Madam
Hi. I am a general paediatrician, and I have read *some* chapters of the
following books(1-3). I think SPSS lacks some features that may be important
in data analysis (for example: interval of correlation coefficient in
bivariate normal distribution, PRESS, and MSPR in
On Tue, Aug 09, 2011 at 02:28:22AM -0700, Mehrshad Koleini wrote:
Dear Sir/Madam
Hi. I am a general paediatrician, and I have read *some* chapters of the
following books(1-3). I think SPSS lacks some features that may be important
in data analysis (for example: interval of correlation
Wow that worked! Thank you very much.
Next time I will try this number generator thing. Thanks for the hint. I had
no idea, that this might have caused the silence. Thomas.
--
View this message in context:
On Aug 9, 2011, at 2:10 AM, Richard Ma wrote:
Hi David,
Thank you very much. Problem solved.
sapply() and lapply() are so powerful that even I have read their
documents
several times, still lots of tricky stuff to learn and try.
The basic difference between my approach and yours was
Hello all,
I've run a Spearman's Rank test to discern relationships between landscape
characteristics and a specific aspect of river behaviour.
I've executed a correlation matrix between the one dependent variable and
all of the predictors, which gives me a nice output of Spearman's Rho
values.
?cor.test
cor.test(x, y, method = spearman)$p.value
HTH,
Jorge
On Tue, Aug 9, 2011 at 8:44 AM, ScottM wrote:
Hello all,
I've run a Spearman's Rank test to discern relationships between landscape
characteristics and a specific aspect of river behaviour.
I've executed a correlation matrix
Hi Listers,
I am trying to reflect a PCA biplot in the x-axis (i.e. PC1) but am not
having much success. In theory I believe all I need to do is multiply the
site and species scores for the PC1 by -1, which would effectively flip the
biplot.
I am creating a blank plot using the plot command and
Cheers Jorge,
I've tried this, but keep getting error messages, relating to either:
Error: unexpected '$' in $
or
Error in cor(data, method = spearman)$p.value :
$ operator is invalid for atomic vectors
Very annoying!
S
Scott McGrane MA (Hons), MRes
SAGES Theme 1 PhD Student
Northern
Just pointing out that Jorge wrote
cor.test
not cor.
Don't know if you saw that but it should help.
Michael Weylandt
On Aug 9, 2011, at 8:58 AM, ScottM scott.mcgr...@abdn.ac.uk wrote:
Cheers Jorge,
I've tried this, but keep getting error messages, relating to either:
Error:
On Tue, Aug 09, 2011 at 01:49:13PM +0200, yrosseel wrote:
My question is: how can I analyse the part of the variation in
fire.setting that is not included in the latent variable criminality?
Ideally I would want a new variable that captures just this. Then I
could model regressions with this
Hello
I need to use R together with a system I´m developing.
I need to call the U.S. by passing a command line script to run.
The result of this script (data or graph) should be written to a text file or
image.
This call will be made through a system made ââin PHP.
It has to do it? I´m not
Works like a charm, thanks!
remko
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Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Hello R users,
My problem is that the data I've got is in the minimum number of columns
with each ward (geographic area) appearing multiple times. The first 30
terms look like this
HHum02
CASW Btype Yr CO2Group NumVeh
170597 00CCFA CARS 2002C 2
170598 00CCFA CARS
Dear friends,
I would like to know how to use Greek (and plotmath characters) in
lattice plots. Here is an example which works: but I would like to
replace s_v with expression(hat(sigma))_v.
Finally, is there a way to get the BIC, ICL, etc in the same panel such
that we can have this text on
Sorry. I forgot to paste 3 lines over: here is the corrected
reproducible code.
Apologies again, and many thanks,
Ranjan
Dear friends,
I would like to know how to use Greek (and plotmath characters) in
lattice plots. Here is an example which works: but I would like to
replace s_v with
Can I include criminality among those and thereby get the common part
of criminality and fire.setting out of the way?
No. You already regress fire.setting on criminality since it is an
indicator in the measurement model of criminality. In other words, the
'criminality' part is already
Works for me:
x - rnorm(10)
y - rnorm(10)
cor.test(x, y, method = 'spearman')$p.value
[1] 0.166058
What are the classes of your inputs? A reproducible example would be
helpful. From the help page of cor.test():
x, y numeric vectors of data values. x and y must have the same length.
Do
On Aug 9, 2011, at 8:36 AM, RobinLovelace wrote:
Hello R users,
My problem is that the data I've got is in the minimum number of
columns
with each ward (geographic area) appearing multiple times. The first
30
terms look like this
HHum02
CASW Btype Yr CO2Group NumVeh
170597
I'm trying to make a monthly boxplot using this:
boxplot(varmeasure ~ vardates)
vardates = [1] 10/1/2010 10/1/2010 10/1/2010 10/1/2010 10/1/2010 10/1/2010
10/1/2010
[8] 10/1/2010 10/1/2010 11/1/2010 11/1/2010 11/1/2010 11/1/2010 11/1/2010
varmeasure = [1] 0.0 26.0 0.2 -0.2 -1.2
On Aug 9, 2011, at 9:29 AM, Ranjan Maitra wrote:
Sorry. I forgot to paste 3 lines over: here is the corrected
reproducible code.
Apologies again, and many thanks,
Ranjan
Dear friends,
I would like to know how to use Greek (and plotmath characters) in
lattice plots. Here is an example which
On Mon, Aug 8, 2011 at 6:44 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Mon, Aug 8, 2011 at 9:16 AM, Johannes Egner johannes.eg...@gmail.com
wrote:
Hi,
I'm removing non-unique time indices in a zoo time series by means of
aggregate. The time series is bivariate, and the row to
On Aug 9, 2011, at 9:46 AM, Fernando Andreacci wrote:
I'm trying to make a monthly boxplot using this:
boxplot(varmeasure ~ vardates)
vardates = [1] 10/1/2010 10/1/2010 10/1/2010 10/1/2010 10/1/2010
10/1/2010
10/1/2010
[8] 10/1/2010 10/1/2010 11/1/2010 11/1/2010 11/1/2010 11/1/2010
On Tue, Aug 9, 2011 at 9:57 AM, Johannes Egner johannes.eg...@gmail.com wrote:
On Mon, Aug 8, 2011 at 6:44 PM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Mon, Aug 8, 2011 at 9:16 AM, Johannes Egner johannes.eg...@gmail.com
wrote:
Hi,
I'm removing non-unique time indices in a zoo
It worked, thanks.
Is there a way to put a trend line through the boxplots?
On Tue, Aug 9, 2011 at 10:58 AM, David Winsemius dwinsem...@comcast.netwrote:
On Aug 9, 2011, at 9:46 AM, Fernando Andreacci wrote:
I'm trying to make a monthly boxplot using this:
boxplot(varmeasure ~ vardates)
I have two column of points y and x. I want to use finite differences to
find the largest gradient to the 'smoothed' fitted curve for x and y. Can R
do this?
--
Thanks,
Jim.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing
Hi,
Yes. Use lines()
Regards,
Carlos Ortega
www.qualityexcellence.es
On Tue, Aug 9, 2011 at 4:17 PM, Fernando Andreacci fandrea...@gmail.comwrote:
It worked, thanks.
Is there a way to put a trend line through the boxplots?
On Tue, Aug 9, 2011 at 10:58 AM, David Winsemius
See if the following is close to what you're looking for. If not, please give
more detail on what you want to do.
data(airquality)
airquality - na.omit(airquality)
set.seed(131)
ozone.rf - randomForest(Ozone ~ ., airquality, importance=TRUE)
imp - importance(ozone.rf) # get the importance
On Aug 9, 2011, at 10:17 AM, Fernando Andreacci wrote:
It worked, thanks.
Is there a way to put a trend line through the boxplots?
You have not shown us how you set the data up or made the boxplots. A
trend line through boxplots seems be a bit ambiguous, since the x-
variable needs to be
Hi David Winsemius, thanks for the input but your reply seems to omit any
answer!
Anyway, I've figured this out for myself, with some help from the reshape
package.
Solution:
mdata - melt(Humn02)
Denormal - cast(mdata, CASW~CO2Group~variable, sum)
Check out the power of the reshape package
Hi David Winsemius, thanks a lot for the answer that I finally spotted
amongst my verbose message.
Many thanks, and I see that it does work now: I had to change the variable
names of the subset HHum02
because all the rows from main dataset were still there invisibly (after I
used subset to remove
Something like
opar- par(mfcol = c(1, 2))
z- prcomp(USArrests, scale = TRUE)
biplot(z, cex = 0.5)
z$x[,1]- -z$x[,1]
z$rotation[,1]- -z$rotation[,1]
biplot(z, cex = 0.5, xlab = -PC1)
par(opar)
perhaps?
Allan
On 09/08/11 13:57, Andrew Halford wrote:
Hi Listers,
I am trying to reflect a PCA
Thanks Duncan, Martin,
You both provided exactly what I needed!
Regards,
Mike
---
XKCD http://www.xkcd.com
On Mon, Aug 8, 2011 at 5:21 PM, Duncan Murdoch murdoch.dun...@gmail.comwrote:
On 08/08/2011 8:04 PM, Mike Williamson wrote:
Hi
Your assertion that xtabs did not work on subsetted data seems suspect. Please
provide an example so we can show you what you did wrong or R can be fixed.
I suspect that you need to learn more about how and when to use factors, since
removing all instances of a particular level doesn't
If you know how to generate random data that represents your null hypothesis
(chance, auc=0.5) and how to do your analysis, then you can do this by
simulation, simulate a dataset at a given sample size, analyze it, repeat a
bunch of times and see if that sample size is about the right size. If
Hi, I got what I want using
lines(varmeasure ~ vardates)
but, as I'm using as.Date(vardates) in my boxplot code
boxplot(varmeasure ~ as.Date(vardate))
I want to change how vardate is displayed
I used strftime(as.Date(vardate), format=%m/%Y) and it worked well,
However it mixed the inital and
Hi:
You could always try cut() to discretize a continuous variable and
then apply your vector of set colors to the discretized variable in
ggplot2's scale_*_manual().
HTH,
Dennis
On Tue, Aug 9, 2011 at 9:26 AM, Adrienne Wootten amwoo...@ncsu.edu wrote:
All,
I'm working with ggplot2 to
Hi,
How do I stop Tinn-R from starting automatically when I start R or R studio,
without uninstalling it.
I just started using R studio and might want to switch back to Tinn-R so I
don't want to uninstall it.
Thanks,
D
[[alternative HTML version deleted]]
Lolz, My bad in assigning 13, 14 to age ranges 15-18. I have corrected that to
16 and 17. Thanks for pointing out.
Your R code works great. I shall try it with my real data. I shall get back
with more questions after I give a shot to understand your code myself.
Best,
Fayez
Original
On Tue, Aug 09, 2011 at 03:30:17PM +0200, yrosseel wrote:
Can I include criminality among those and thereby get the common part
of criminality and fire.setting out of the way?
No. You already regress fire.setting on criminality since it is an
indicator in the measurement model of
Very interesting. I can track every person along the lines too. It would be
useful to have a grouping on Age-range as my actual data has above six thousand
nodes and thus the spaghetti can get really messy. I shall get back with more
questions after some trials with your code.
Best,
Fayez
You really need to follow the suggestions in the posting guide to get the best
help from this list.
Which versions of randomForest are you using in S-PLUS and R? Which version of
R are you using? When you restore the object into R, what does str(object)
say? Have you also tried
On 8/9/2011 10:32 AM, Fernando Andreacci wrote:
Hi, I got what I want using
lines(varmeasure ~ vardates)
but, as I'm using as.Date(vardates) in my boxplot code
boxplot(varmeasure ~ as.Date(vardate))
I want to change how vardate is displayed
I used strftime(as.Date(vardate), format=%m/%Y)
Hi Devon,
check your rprofile.site file and comment the following lines
options(IDE='C:/Tinn-R/bin/Tinn-R.exe')
trStartIDE()
hth.
Am 09.08.2011 19:51, schrieb devon woodcomb:
Hi,
How do I stop Tinn-R from starting automatically when I start R or R studio,
without uninstalling it.
I
Hi Petr, thanks for your help on this. I will most definitely get this
book as it appears to be a good one.
I am happy with how nls() and the self starting function appears to be
fitting the data set.
What I am wondering about is how to write out this function outside of R.
For example, if I sat
Hi,
please excuse the most likely very trivial question, but I'm having no idea
where to find related information:
I try to recapitulate very simple plotting behavior of Excel within R but
have no clue how to get where I want.
I have tab delimited data like
cell treatment value
line a treat1 4
Dear helpers,
I'm trying out the embedFonts() to embed fonts into my pdf files.
However, when I inspect the new pdf with a program designed to look
for embedded fonts, I see that the fonts have in fact not been
embedded. Below are my calls.
R version 2.13.1 (2011-07-08)
Copyright (C) 2011 The R
I am not familiar with wiki (wich one?) but here is the code without
line-break
--- 8 --
%\usepackage{Sweave}
\RequirePackage[T1]{fontenc}
\RequirePackage{graphicx,ae,fancyvrb}
\IfFileExists{upquote.sty}{\RequirePackage{upquote}}{}
\setkeys{Gin}{width=0.8\textwidth}
In Splus the randomForest package version is 4.5-18; in R randomForest
version is 4.6-2. I'm using R version 2.13.1.
After restore the randomForest object into R using data.restore(), below
are str(cost.rf) outputs,
List of 17
$ call : language randomForest(x =
It worked, thanks.
On Tue, Aug 9, 2011 at 4:15 PM, Brian Diggs dig...@ohsu.edu wrote:
On 8/9/2011 10:32 AM, Fernando Andreacci wrote:
Hi, I got what I want using
lines(varmeasure ~ vardates)
but, as I'm using as.Date(vardates) in my boxplot code
boxplot(varmeasure ~ as.Date(vardate))
Some of you might see that there's a tiny mistake in the embedFonts()
call. fontpaths = C/Windows/Fonts should of course be fontpaths =
C:/Windows/Fonts. I fixed this, but it didn't change the fact that
the new .pdf does not have its fonts embedded.
Sverre
On Tue, Aug 9, 2011 at 4:48 PM, Sverre
For a variety of reasons, there is no easy way to transfer
many kinds of complicated objects (and some simple ones)
from S+ to R (or vice versa). If you want to compare
predictions made by randomForest in S+ and R, I would
recommend transferring the data.frames used to create the
model and to
I have the same problem. Either using install.packages() in R or using R CMD
INSTALL. See below
-
/usr/local/cuda/bin/nvcc -gencode arch=compute_10,code=sm_10 -gencode
arch=compute_11,code=sm_11 -gencode arch=compute_12,code=sm_12 -gencode
David, as always this is a terrific roundup. I note in passing that the big
data logistic function rxLogit used on the 1B observation dataset
(impressive run time!) inappropriately used the t distribution for testing
the coefficients in the logistic model [at least if the notation used is any
Hi Maxim,
I notice no one has replied to you (on list at least) so I'll take a stab at
answering your question and giving some productive advice.
I believe the axis command will do what you want with a little tweaking: It
certainly lines things up for me.
x -
Thanks, Frank! I'm actually not sure what distribution it's using
there, but I'll pass this along to Sue Ranney who created the video.
Kind regards,
# David
On Tue, Aug 9, 2011 at 4:25 PM, Frank Harrell f.harr...@vanderbilt.edu wrote:
David, as always this is a terrific roundup. I note in
Hi all,
I have a zoo time series object, see below code:
---
# This is a pasteable example
library(zoo)
x - c(1, 2, 3, 4, 5)
dt - c(2011-01-01, 2011-01-02, 2011-01-03, 2011-01-04, 201-01-05)
ts - zoo(x, ts)
I'd suggest you look into the xts class and write
require(xts)
xts = as.xts(1:5,Sys.Date()+1:5)
time(xts)[xts==3]
By the way, your code isn't pastable for me: not sure why.
Michael Weylandt
On Tue, Aug 9, 2011 at 10:39 PM, Richard Ma xuanlong...@uts.edu.au wrote:
Hi all,
I have a zoo time
D'Oh -- just spotted it (don't know what was wrong with me):
in your code: 2011-01-05 and ts = zoo(x dt) need to be changed.
If you do that, the same trick
time(ts)[ts==3]
will work. Still, I'm a big xts fan.
Michael
On Tue, Aug 9, 2011 at 10:45 PM, R. Michael Weylandt
Hello, R-Help -
I am trying to plot the results of an ordination from package vegan. The
tricky part for me right now is getting the colors of the ellipses denoting
the 95% confidence intervals of the group centroids to match the colors of
the points for those same groups.
From and earlier post,
Hi,
I’m trying to do a hierarchical cluster analysis in R with a Big Data set.
I’m running into problems using the dist() function.
I’ve been looking at a few threads about R’s memory and have read the
memory limits section in R help. However I’m no computer expert so I’m
hoping I’ve
On Aug 9, 2011, at 11:38 PM, Chris Howden wrote:
Hi,
I’m trying to do a hierarchical cluster analysis in R with a Big
Data set.
I’m running into problems using the dist() function.
I’ve been looking at a few threads about R’s memory and have read the
memory limits section in R help.
Hello,
I have an R script that I use as a template to perform a task for multiple
files (in this case, multiple chromosomes).
What I would like to do is to utilize a simple loop to parse through each
chromosome number so that I don't have to type the same code over and over
again in the R
Tena koe
Try something along the following lines:
chrData - vector('list', 22)
names(chrData) - paste('chr', 1:22, sep='')
for (i in 1:length(chrData))
{
chrData[[i]] - read.table(file=paste('chr', i, '.out.txt', sep=''), header=F)
...
}
HTH
Peter Alspach
-Original Message-
On Wed, 10 Aug 2011, David Winsemius wrote:
On Aug 9, 2011, at 11:38 PM, Chris Howden wrote:
Hi,
I’m trying to do a hierarchical cluster analysis in R with a Big Data set.
I’m running into problems using the dist() function.
I’ve been looking at a few threads about R’s memory and have read
Sorry if this is a duplicate... my email is giving me trouble this evening...
On Tue, Aug 9, 2011 at 8:38 PM, Chris Howden
ch...@trickysolutions.com.au wrote:
Hi,
I’m trying to do a hierarchical cluster analysis in R with a Big Data set.
I’m running into problems using the dist() function.
Assuming you need the full distance matrix at one time (which you do not for
hierarchical clustering, itself a highly dubious method for more than a few
hundred points).
Apologies if this hijacks the thread, but why is hierarchical
clustering highly dubious for more than a few
hundred points?
Hello,
This is my first project in R, so I'm trying to work 'the R way', but it
still feels awkward sometimes.
The problem that I'm facing right now is that I need to convert a data.frame
into a structure of lists. The data.frame has columns in the order of tens
(I need to focus on only three of
Hi All,
I have been trying to use glmnet package to do LASSO linear regression. my x
data is a matrix n_row by n_col and y is a vector of size n_row corresponding
to the vector data. The number of n_col is much more larger than the number of
n_row. I do the following:
fits = glmnet(x, y,
Hi Michael,
Thanks for your kindly help. Problem solved!
Just curious why you prefer xts rather than zoo? Is xts more powerful?
BTW, It's my mistake that incorrectly type the code. ;-)
Cheers,
Richard
R. Michael Weylandt lt;michael.weyla...@gmail.comgt; wrote:
I'd suggest you look into
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