Hi Every one,
I have been struggling with a problem and need your help. I would like to
automate execution of a .R file. Therefore i thought of creating a batch
file. It reads
@echo off
start /d C:\Program Files\R\R-2.13.1\bin\x64 R BATCH Model.R
No success with running it. The command prompt
Eclipse with the Stat-ET plugin does syntax highlighting for .R, .Rd and .Rnw
files.
Best regards,
Thierry
-Oorspronkelijk bericht-
Van: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
Namens Joshua Wiley
Verzonden: zondag 16 oktober 2011 22:09
Aan: Bogaso
People,
I want to create a multi-page PDF doc and the pdf command works fine if
I only use Portrait OR Landscape but how do I create a document that
contains BOTH sorts of pages? Is it possible? - I couldn't find info
about it.
Thanks,
Phil.
--
Philip Rhoades
GPO Box 3411
Sydney NSW
Hi Sarah,
Thanks for your very lucid explanations.
Thanks also to David and Dennis.
I got it completely. I now have some nice ggplot of a couple ecdf in
my paper :-)
Now on to do some matrix plots of correlation matrices and some lm().
I'm like a child in a candy shop. :-)
I'm learning something
PDF does not know about portrait/landscape: that is really an issue
about whether the MediaBox is taller than it is wide. pdf()'s
arguments only set the MediaBox (and where relative to the origin the
'ink' is placed)
Note that the orientation of the text on the page does not help:
typically
I am trying to create a pie chart using rpy2 of the following data
Pathway Occurrences
A 10%
B50%
C20%
E10%
filename = './testing.png'
grdevices = importr('grDevices')
rdevices.png(file=filename, width=1200, height=800)
dataf =
Hi Listers,
This has a simple answer but it has been eluding me nonetheless.
I have been building a PCA plot from scratch with the ability to plot
predefined groups in different colors. This has worked fine but when I try
to get a polygon drawn around each of the groups it is not recognising my
On Sun, 2011-10-09 at 10:25 -0400, Lei Liu wrote:
Hi there,
I am reading the 2004 paper Smoothing with mixed model software in
Journal of Statistical Software, by Ngo and Wand. I tried to run
their first example in Section 2.1 using R but I had some problems.
Here is the code:
I'm not
On Sun, 2011-10-09 at 10:25 -0400, Lei Liu wrote:
Hi there,
I am reading the 2004 paper Smoothing with mixed model software in
Journal of Statistical Software, by Ngo and Wand. I tried to run
their first example in Section 2.1 using R but I had some problems.
Here is the code:
[whoops -
On Mon, 2011-10-17 at 21:02 +1000, Andrew Halford wrote:
Hi Listers,
This has a simple answer but it has been eluding me nonetheless.
ordiellipse() doesn't work the way you think it does - it can only take
a single colour at a time. Therefore you need to do /n/ calls to
ordiellipse() to draw
Hi Hami
This is what I use when I have run a file using the BATCH command for
windows XP
D:\rw\bin\R CMD BATCH --no-restore --no-save Rfile.R Rfile_log.txt
where
D:\rw\bin\R is your R exe file name and path
Rfile.R is the R file your are sourcing
Rfile_log.txt is the log file - handy if
Hi,
On Sun, Oct 16, 2011 at 6:24 PM, Bob Briggs rbrig...@hotmail.com wrote:
Hello
I'm wanting to understand more about ptrend (a statistical explanation via an
internet website if possible) and also to know what package in R would
produce a ptrend.
Appreciate any help I can get on this
I have a dataframe in the general format:
chr1 0.5
chr1 0
chr1 0.75
chr2 0
chr2 0
chr3 1
chr3 1
chr3 0.5
chr7 0.75
chr9 1
chr9 1
chr22 0.5
chr22 0.5
where the first column is the chromosome location and the second column is
some value. What I'd like to do is have a histogram created for each chr
On Sat, 2011-10-15 at 09:11 -0700, lincoln wrote:
#Uwe:
snip /
#Gavin:
I have read carefully your thread but I am not sure to understand what you
are suggesting (my gaps in statistics!). You say that it should be due to
the /Hauck Donner/ effect and that it is not a quasi separation or
Hi,
On Mon, Oct 17, 2011 at 8:07 AM, a217 aj...@case.edu wrote:
I have a dataframe in the general format:
chr1 0.5
chr1 0
chr1 0.75
chr2 0
chr2 0
chr3 1
chr3 1
chr3 0.5
chr7 0.75
chr9 1
chr9 1
chr22 0.5
chr22 0.5
Using dput to give us some reproducible data would be even better.
Hello,
I have the following problem:
I successfully installed R (Version 2.1.3.0 for Windows) on my Notebook
(Windows 7) in June. Now I used the same setup file for a PC (Windows XP)
and got a message from the anti virus software (Avira), that the setup file
contains the Trojan
how can i set the position of the first and last tick to the
borderline of a plot?
The plot should look like this one made in Gnuplot [1].
Gnu-R adds some space between the ticks and the end of plot.
do you mean like this?
plot(rnorm(25),rnorm(25), xaxs =i, yaxs=i, xlim=c(-2,2),
Dear R users,
I work with Matlab R simultaneously. Usually I used to read successfully
mat files (cell, structure, etc.) into R, till Matlab 2011b release.
For reading mat files (or maybe I should say, converting it into R variable
or structure) Im using *readMat* (from R.matlab
Couldn't you also just count the number of characters with nchar()?
Michael Weylandt
On Oct 17, 2011, at 1:57 AM, Henri-Paul Indiogine hindiog...@gmail.com wrote:
I think I have it and my apologies for spamming the list. I should
not work this late on Sunday :-)
I think that it should be
Hi,
When using ggplot, take a look at facet_wrap and geom_histogram.
regards,
Paul
On 10/17/2011 12:14 PM, Sarah Goslee wrote:
Hi,
On Mon, Oct 17, 2011 at 8:07 AM, a217 aj...@case.edu wrote:
I have a dataframe in the general format:
chr1 0.5
chr1 0
chr1 0.75
chr2 0
chr2 0
chr3 1
On Mon, 17 Oct 2011, Annette Prochnow wrote:
Hello,
I have the following problem:
I successfully installed R (Version 2.1.3.0 for Windows) on my Notebook
(Windows 7) in June. Now I used the same setup file for a PC (Windows XP)
and got a message from the anti virus software (Avira), that the
Adam Zeilinger zeil0006 at umn.edu writes:
I have a log likelihood function that I was able to optimize using
mle2. I have two years of the data used to fit the function and I would
like to fit both years simultaneously to test if the model parameter
estimates differ between years, using
Hi,
i am unable to install the rugarch package.
More than that i do not even find this package in my list of possible
packages.
Its possible than the name has changed, or the package is not longer
availiable?
Is there a similar package avaliable for garch modelling except the fGarch
what i am
Tinn-R also highlights .rd files and is free.
Me, I use TextPad with a latex syntax file.
S Ellison
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Bogaso Christofer
Sent: 16 October 2011 13:57
To: r-help@r-project.org
Thank you very much for your answer.
It works just as I want!.
Kenneth
El sáb, 15-10-2011 a las 20:39 +0530, Deepayan Sarkar escribió:
On Fri, Oct 14, 2011 at 10:02 AM, David Winsemius
dwinsem...@comcast.net wrote:
Legends are built in columns. You need to find a graphics symbol to put in
Hi,
I had a large file for which I require a subset of rows. Instead of reading
it all into memory, I use the awk command to get the relevant rows. However,
I'm doing it pretty inefficiently as I write the subset to disk, before
reading it into R. Is there a way that I can read it into an R
On Mon, 17 Oct 2011, user84 wrote:
Hi,
i am unable to install the rugarch package.
More than that i do not even find this package in my list of possible
packages.
Its possible than the name has changed, or the package is not longer
availiable?
No: see
On Mon, Oct 17, 2011 at 9:23 AM, Brian Smith bsmith030...@gmail.com wrote:
Hi,
I had a large file for which I require a subset of rows. Instead of reading
it all into memory, I use the awk command to get the relevant rows. However,
I'm doing it pretty inefficiently as I write the subset to
On Mon, 17 Oct 2011, Brian Smith wrote:
Hi,
I had a large file for which I require a subset of rows. Instead of reading
it all into memory, I use the awk command to get the relevant rows. However,
I'm doing it pretty inefficiently as I write the subset to disk, before
reading it into R. Is
rugarch installs and works fine for me under windows 7 64-bit and R 2.13.1
64 bit.
On Mon, Oct 17, 2011 at 7:49 AM, user84 roland.ta...@gmx.at wrote:
Hi,
i am unable to install the rugarch package.
More than that i do not even find this package in my list of possible
packages.
Its possible
On Sun, 2011-10-16 at 19:36 -0500, Yihui Xie wrote:
Hi,
I have spent a few hours on the R-exts manual and the documentation of
parse_Rd() (as well as the PDF document in the references), but I
still have not figured out what results=rd means. I thought I could
use an R code fragment to
Search: mcmcglmm heritability to see some discussions using the
mcmcglmm package. This package is discussed often
on the mixed model list. You can also use the kinship package. It will
take some time to get familiar with R. Work through
a few of the examples for variance component models, and then
Thanks a lot! Sorry for cross-posting, but I did it intentially
because I tend to believe Barry Rowlingson (Why R-help Must Die!), and
I will summarize the answers here later to StackOverflow.
Another user also told me this worked for 2.13.1, but not later versions.
Regards,
Yihui
--
Yihui Xie
Paul Hiemstra paul.hiemstra at knmi.nl writes:
Hi,
When using ggplot, take a look at facet_wrap and geom_histogram.
regards,
More specifically, try something along the lines of
d - data.frame(f=factor(paste(chr,rep(c(1,2,3,7,9,22),each=50),sep=)),
v=runif(300))
library(ggplot2)
Hello Fellow R
Users,I have
spent the last week trying to find a work around to this problem and I can't
seem to solve it. I simply want to plot my GEE model result with 95% confidence
bands.
I am using the geepack package to run a basic GEE model involving
nestling weights, to a Gaussian
Got it. Thanks!
On Mon, Oct 17, 2011 at 9:40 AM, Prof Brian Ripley rip...@stats.ox.ac.ukwrote:
On Mon, 17 Oct 2011, Brian Smith wrote:
Hi,
I had a large file for which I require a subset of rows. Instead of
reading
it all into memory, I use the awk command to get the relevant rows.
Like others have suggested, I think ggplot2 is probably the best way
to go about this, but if you'd rather use base graphics (and you never
indicated how you felt about ggplot2), you could do something like
this with tapply:
fcts - letters[sample(9,1500,T)]
vals - rnorm(1500)
df -
Hello,
I have simulation results in the form of
Time V I
0.e+000 7.218354344368e-001 5.224478627497e-006
1.e-009 7.218354344368e-001 5.224477718002e-006
2.e-009 7.218354344368e-001
On Oct 17, 2011, at 8:04 AM, Sarah Goslee wrote:
Hi,
On Sun, Oct 16, 2011 at 6:24 PM, Bob Briggs rbrig...@hotmail.com
wrote:
Hello
I'm wanting to understand more about ptrend (a statistical
explanation via an internet website if possible) and also to know
what package in R would
I would like to build a forest of regression trees to see how well some
covariates predict a response variable and to examine the importance of
the
covariates. I have a small number of covariates (8) and large number of
records (27368). The response and all of the covariates are continuous
Hi Jason,
I would go for Zelig package to get simulated values and confidence
intervals. It can handle gee model.
Shige
On Mon, Oct 17, 2011 at 9:38 AM, JASON M. HILL jmh...@psu.edu wrote:
Hello Fellow R
Users,I have
spent the last week trying to find a work around to this problem and I
thanks guys!! your great
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__
R-help@r-project.org mailing list
Hello all,
Has anyone tried to create an R mlogit model object from a text file? If yes,
what would be the best way to do it? I already have models that have been
estimated using other software and would like to use R to help me make
predictions for new data.
Thank you!
Bhargava Sana
Hello,
I am having hard time obtaining a value from a function. fit is a survival
function that produces some results, such as median, confidence
intervals etc. But str() function does not list these values. How can I
extract these to be able use them? For example, I need median value for
the
You're going to have to say more about your text file if you want
meaningful help: specifically, what is in the file: data, output from
other software, etc?
There are probably two questions to deal with here: reading in
whatever is in the text file and mapping it to the correct R object
and
Assuming I'm reading your post correctly -- fit is the output object
and the lines following fit are the console output, which implicitly
calls print -- it looks like the median isn't stored in fit but is
calculated on the fly in the print call. But this doesn't seem
consistent with your claim
Bonjour
I have this data frame and I am newbie in R.
I want to ask if it is possible to draw 10 lines in a plot such that: a line
for every colomn, the x - axis is the second column and the y-axis is the
third one.
Thank you for any input
1 0 1094442
1 0.2 1163576.2
1 0.4 1238539.6
1
Michael,
Thanks for the quick response. I currently have a few models that have been
estimated using Biogeme. I have attached a sample output file from the
estimation.
I am more concerned about creating a model object from scratch rather than the
reading part. Let us just say if we have a
There are indeed many, many ways in R to do something like you've
described. If you are just a beginner, I'd recommend something simple:
suppose your data is called df and the columns named are id, x'',
and y respectively.
with(df, plot(x[id == 1], y[id==1], ylim = range(y), type=l)
# Call plot
Often the summary() methods for the modelling functions
contain the kinds of details you are looking for. Sometimes
there are special extractor functions but often not.
You have to study the help file for summary.objectClass
and the vignettes for the package, and perhaps do a little
On Oct 17, 2011, at 11:13 AM, Cem Girit wrote:
Hello,
I am having hard time obtaining a value from a function. fit is a
survival
function that produces some results, such as median, confidence
intervals etc. But str() function does not list these values. How
can I
extract these to be
I am trying to run an rlq analysis on some pretty cool data.
The error message I am getting states Error in rlq(dudiR, dudiL, dudiQ,
scannf = TRUE, nf = 2) : Non equal row weights
Problem for me is that the row weights are equal; that is if the set-up is
correct.
The contingency tables column
Hi Everyone,
I am new to R Language and was wondering if someone could help me convert my
latitude-longitude coordinates to cartesian coordiantes using geoXY() from SoDA
package? I have been uploading my coordinates from a text file into R (they
originate as a dataframe) and them
Greetings
I have been experimenting with sampling from posterior distributions using
R. Assume that I have the following observations from a normal distribution,
with an unscaled joint likelihood function:
normsamples = rnorm(1000,8,3)
joint_likelihood = function(observations, mean, sigma){
Hi!
I have fitted a Negative Binomial model (glm.nb) and a Poisson model (glm
family=poisson) to some count data. Both have the same explanatory variables
dataset
When I call sum(fitted(model.poisson)) for my GLM-Poisson model, I obtain
exactly the same number of counts as my data.
However,
Hello R-community,
I am trying to populate a column (doy) in a large dataset with the first
column number that exceeds the value in another column (thold) using the
'apply' function.
Sample data:
pt D1 D17 D33 D49 D65 D81 D97 D113 D129 D145 D161 D177
D193 D209 D225 D241
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Seref Arikan
Sent: Monday, October 17, 2011 9:11 AM
To: r-help@r-project.org
Subject: [R] Best practices for handling very small numbers?
Greetings
I have been experimenting
I think something like this should do it at a huge speed up, though
I'd advise you check it to make sure it does exactly what you want:
there's also nothing to guarantee that something beats the threshold,
so that might make the whole thing fall apart (though I don't think it
will)
# Sample data
Try vectorizing it a bit by looping over the columns.
E.g.,
f1 - function (df)
{
# loop (backwards) over all columns in df whose
# names start with D to find the earliest one
# that is bigger than column thold. I tested with
# df being a data.frame but a matrix should
Hello,
I'm almost positive R can do the following, I just haven't hit upon the
right package or search terms, however. Here's what I'm after: I've got
concentration output from two different models that I want to qualitatively
compare in a contour plot (or some variant of a contour plot). The
Hi All,
I have some data from which I set four points to be breaks. Based on these
points, I cut the dataset into four groups and assign a number to it:
=331.04 assign 0
331.04 =476.07 assign data-331.04/(476.07-331.04)
476.07=608.66 assign 1
608.66 =791.5 assign 791.5- data/(791.5-608.66)
On Sun, 16-Oct-2011 at 03:05PM -0700, Benjamin Cheah wrote:
| Hi all,
[...]
| It is particularly frustrating when you need to adjust axis title
| positions separately for x and y axes - i.e. specify mgp twice -
| once for each axis within the axis function. But this doesn't seem
| to work - is
so here is the code I need help to fix the line for 'st' when it reaches
maximum, that's where i am getting stuck.
thanks
Sharad
set.seed(100)
d=data.frame(x=rnorm(20)+5,
x1=rnorm(20)+5,
x2=rnorm(20)+5,
x3=rnorm(20)+5,
x4=rnorm(20)+5,
x5=rnorm(20)+5,
x6=rnorm(20)+5,
x7=rnorm(20)+5,
Thanks. bb=replicate(2, rnorm(20)) was very useful for me.
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__
Hello,
I need some help getting started with data analysis. Iâm having trouble
getting R to read my data file. Iâve referred to various R help
documentation, the website, and FAQs, but I donât see my situation listed.
I saved an Excel file (post-2007 Excel version) of data as a
where the first column is the chromosome location and the second column is
some value. What I'd like to do is have a histogram created for each chr
location (i.e. a separate histogram for chr1, chr2, chr3, chr7, chr9, and
chr22). I am just having a hard time getting everything to work out
Thanks, I consider all of those options and tried some, but the
z=color gradient seems the best option for my data.
kb
On Oct 2, 10:42 pm, Ben Bolker bbol...@gmail.com wrote:
Duncan Murdoch murdoch.duncan at gmail.com writes:
On 11-10-02 1:11 PM, Kerry wrote:
I have 3 columns of
Oh, I just saw your ggplot example, that works well too. However, it
seems much of the options are hidden for changing the range of colors
or the color types altogether. I'm currently looking through the
ggplot ref manuals.
Thanks,
kb
On Oct 2, 10:42 pm, Ben Bolker bbol...@gmail.com wrote:
I would assume that you would use 'read.csv'. I don't know where you
got the syntax for summary;
x - read.csv((C:\\Documents\\R_dfiles\\H_N_T.csv,as.is=TRUE)
summary(x)
On Mon, Oct 17, 2011 at 2:56 PM, Sally Ann Sims sallys...@earthlink.net wrote:
Hello,
I need some help getting started with
Thanks for the info. I am working with Recombinant Inbred Lines(RILs), not
pedigree, so most of what I could find does not apply to my work. I've found
a couple of tutorials explaining how to use analysis of variance components
with lme4, but I don't have multiple measurements per individual per
You aren't reading the file in at all: notice that,
summary(MooGoesTheCow,header=TRUE,as.is=TRUE)
Length Class Mode
1 character character
This is because you are asking for a summary of the string containing
the file name, not the file itself.
Rather, use
X =
Your original code works far faster when the input
is a matrix that when it is a data.frame. Selecting
a row from a data.frame is a very slow operation,
selecting a row from a matrix is quick. Modifying
a row or a single element in a data.frame is even
worse compared to do it on a matrix. I
On Sun, Oct 16, 2011 at 7:20 PM, David Winsemius dwinsem...@comcast.net wrote:
On Oct 16, 2011, at 1:17 AM, Richard M. Heiberger wrote:
How can I right justify the right-axis tick values? They appear in the
example below as left-justified.
I have tried several different ways and all fail
data.frames are quite efficient when you use
a column at a time, but not when used a row
at a time.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: Nathan Piekielek [mailto:npiekie...@gmail.com]
Sent: Monday, October 17, 2011 12:37 PM
To: William
I'm running the following ANCOVA model in R: X=a*b*d + d where d is the
covariate. I want to produce adjusted means for X for all possible
treatment combinations. a has 6 levels, b has 2 levels, c has 2 levels, so
this is a 6x2x2 = 24 possible treatment combinations. When I run:
effect(d,
Here's my loadable data in case it helps. It creates 2 separate plots
which I'd like to be in the same graph with 2 separate legends.
library(ggplot2)
#Here's the 1st plot
x-rnorm(100)
y-rnorm(100)
z-rnorm(100)
d - data.frame(x,y,z)
dg-qplot(x,y,colour=z,data=d)
dg +
Hello,
I am trying to run a small example with foreach, but I am having some
problems. Here is the code:
*library(doMC)
registerDoMC()
zappa = list()
frank = list()
foreach (i = 1:4) %dopar% {
zappa[[i]] = kmeans (iris[-5],4)
frank[[i]] = warnings()
}*
The code runs without error. However
Hi,
Looking at the fastICA library. I want to test separating out different sounds
from a recorded wav file.
But, I only have a SINGLE stream of data (one channel wav.) It appears as if
the fastICA won't let me separate more sounds than I have columns in my data
matrix. is this correct?
Yes, the qplot works great, but do you know how to allow for multiple
plots? I want one variable to be plotted say from blue to red and
another say from yellow to green but in the same graph, each having
there own separate legends. I've tried print() and arrange() but no
luck.
Thanks again,
kb
Hello All,
Has anyone had success building 64-bit R on Solaris 10 Sparc with the Oracle
Studio Compiler suite? Could anyone start give me a clue. I have tried to no
avail.
Thanks,
Nynese
Nynese Tinsley, BSEE, MSCIS
UNIX Systems Analyst
Harvard School of Public Health
Center for
Dear Mattune,
I guess that you're using the effect() function in the effects package.
You've requested the effect for the covariate fixing the values of the
factors, rather than vice-versa. Try effect(a*b*c, Anocova.Model) or, for
more detail in the output, summary(effect(a*b*c, Anocova.Model)).
On Mon, Oct 17, 2011 at 4:31 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
I have no idea what's going on in the code you provided, particularly
why there are no ratios given your subject line or why you are looping
over an unused variable, but how about this:
n - colnames(d)
n -
I'm not at all familiar with mlogit or Biogene so I can't really give
a definitive answer, but it seems that this would be a very dangerous
thing to try.
Looking at the mlogit manual, I see that, like most model objects in
R, mlogit has a variety of elements including many of those you
The instructions *are* in the manual, and they do work: I checked for
R 2.14.0 beta only this morning.
On Mon, 17 Oct 2011, Nynese Tinsley wrote:
Hello All,
Has anyone had success building 64-bit R on Solaris 10 Sparc with the Oracle
Studio Compiler suite? Could anyone start give me a
Hello
Trying to apply a model to each level of a factor
For example, i have three levels of a variable I call 'Code'...I want to
model the data under each level of code differently...I've attached a sample
data set... http://r.789695.n4.nabble.com/file/n3913431/data.txt data.txt
I.E for
Hi,
I have a list of lists that I would like to convert into a dataframe such
that the name(?) of the individual lists is replicated as rows with each
item in the list listed in another column.
I have provided a partial from my list: (let's say the list is called
help.me)
[[2]]
[1] 18 27 11
Yes, there seem to be a lot of elements in the mlogit model object and I don't
have some of that information now since the models have been estimated in
Biogeme. I had been trying some of the steps that you suggested (after I posted
my question) and as you mentioned, realized that this is
In the absence of a reproducible example (your example is not
reproducible as is), try this:
names(help.me) - as.character(2:4)
library('plyr')
newDF - ldply(help.me, rbind)
newDF[['.id']] - as.numeric(newDF[['.id']])
ldply will create a new column named .id that contains the name of the
list
Hi, all,
I'm running a monte carlo simulation with missing data. The data are arranged
such that there are k columns and n rows over a set number of simulations (set
to 10 right now so it runs fast while I set everything up). The data are
integers, numbers 1-7 only (normal distribution). The
Hi,
Please check if this representation helps you.
library(lattice)
library(latticeExtra)
p1.gr - cloud( ts181 ~ x * z, data=FD, panel.3d.cloud = panel.3dbars,
scales = list(arrows = FALSE, just = right))
p2.gr - cloud( ts1825 ~ x * z, data=FD, panel.3d.cloud = panel.3dbars,
scales = list(arrows
On Oct 17, 2011, at 5:11 PM, xhan wrote:
Hi,
I have a list of lists that I would like to convert into a dataframe
such
that the name(?) of the individual lists is replicated as rows with
each
item in the list listed in another column.
I have provided a partial from my list: (let's say
Hello,
One alternative is to create some kind of contourplot/levelplot which will
enhance and show clearly the spikes and will smooth the rest of the
information. That perhaps will be slow in generating the plot but not with
the postscript file.
Regards,
Carlos Ortega
www.qualityexcellence.es
Hi Carlos,
Thanks for the response. The plot you suggested was not in line with what
I'm trying to produce in R. The last plot found at:
http://www.advsofteng.com/gallery_contour.html
is more along the lines of what I'm looking for. Notice the scatter points
(shown by x) are not laid
On Oct 17, 2011, at 5:59 PM, emorway wrote:
Hi Carlos,
Thanks for the response. The plot you suggested was not in line
with what
I'm trying to produce in R. The last plot found at:
http://www.advsofteng.com/gallery_contour.html
is more along the lines of what I'm looking for. Notice
Dear R helpers,
I am a beginner at R so please be gentle :)
I have already read manuals and FAQs, with no help.
I have a monthly time series data on public debt with 40 variables, it starts
on January 1994 and ends on June 2011.
I am loading the data into R using read.csv and the data looks ok
Dear List Members,
I am working on a below piece of code: Initially have created pie
charts with Enlish labels to present the data for Czech Republic, now
however I need to print the label with original Czech fonts.
When I copy paste from Word, certain fonts get 'simplified' distorting
original
On 18/10/11 10:35, Michael Parent wrote:
Hi, all,
I'm running a monte carlo simulation with missing data. The data are arranged
such that there are k columns and n rows over a set number of simulations (set
to 10 right now so it runs fast while I set everything up). The data are
integers,
Thank you David, I'm moving forward again. I was not aware of that website,
I was recently at
http://www.r-project.org/
and clicked on the 'mailing list' link and didn't see it there...with 8k+
posts, maybe its worth adding?
--
View this message in context:
I'm not a huge fan of using R's ts class directly, much preferring to
use zoo or xts (both of which are packages) to enhance. That said, I
think your problem comes from identifying the data/variable name
incorrectly. You've only tsed dados, but you try to plot divliq.pib;
try
That worked perfectly, thanks!!
I'd assumed that it wasn't necessary for me to type out ...based on a MV
normal distribution that I made into 1-7 integers by blah blah blah; the
distribution is normal-ish after I transform it around for the purposes I need
for the simulations. I'll be sure to
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