Uwe Ligges ligges at statistik.tu-dortmund.de writes:
On 03.11.2010 16:26, Fabon Dzogang wrote:
Hi,
I run R 2.10.1 under ubuntu 10.04 LTS (Lucid Lynx) and klaR version 0.6-4.
I compute a model over a 2 classes dataset (composed of 700 examples).
To that aim, I use the function
Hi,
I'd like to use the reshape2 package for melting datasets.
The problem is that I've also loaded the gglot2 package which
automatically loads the reshape-package. And the reshape is
masking my reshape2.
Thats why I tried
reshape2::melt(df_test,id=c(X1,
Have you tried loading reshape2 after ggplot2 and all it's requirements?
Usually whatever is loaded last masks earlier loaded packages with functions
of the same name so if reshape2 is last then it should mask reshape(1) and
all of it's similarly named functions.
Brandon
Yes, reshape2
Am 10.11.2011 um 09:54 schrieb Brandon Hurr:
Is the value.name ignored as well?
Looks like it might have been left out of the function call?
reshape2::melt
function (data, ..., na.rm = FALSE, value.name = value)
{
UseMethod(melt, data)
}
environment: namespace:reshape2
On 10.11.2011 09:00, Ted Chang wrote:
Uwe Liggesliggesat statistik.tu-dortmund.de writes:
On 03.11.2010 16:26, Fabon Dzogang wrote:
Hi,
I run R 2.10.1 under ubuntu 10.04 LTS (Lucid Lynx) and klaR version 0.6-4.
I compute a model over a 2 classes dataset (composed of 700 examples).
To
Hi hi,
It is much easier to deal with lists than a large number of separate
objects. So the first answer to your question
How can I apply a function to a list of variables.
.. might be to convert your list of variables to a regular list.
Instead of ...
monday - 1:3
tuesday - 4:7
wednesday -
This is plot.xts that generates the error. Argument col seems to be
unsuppotred. Please ask the package maintainer or send patches to
improve the xts package.
Uwe Ligges
On 10.11.2011 04:38, eric wrote:
Recently updated my packages (update.packages() and also updated rstudio to
the latest
On 11-11-09 6:03 PM, Sean Robert McGuffee wrote:
On 11/9/11 7:22 PM, David Winsemiusdwinsem...@comcast.net wrote:
On Nov 9, 2011, at 5:38 PM, Cem Girit wrote:
2. My mailbox do not overflow with emails so that I do not
need to
edit it every day
Yes. You were offered an option to
On 11-11-09 10:34 PM, eric wrote:
I did an update of both rstudio and my packages. I had some trouble but was
able to move a lot of the packages so most troubles seem to be behind me.
But having a problem with code that previously ran fine. See below:
require(quantmod)
Loading required package:
On 11-11-10 12:11 AM, Alex DJ wrote:
Hello,
Beginner, sorry if this is wasting anyone's time, but have been working on
this for a couple of days now, think it should have take a few hours!
The Problem:
Error in Summary.factor(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 4L, :
max not
I want to use function cbind.na at library(qpcR)
I install package qpcR and I can use functions such
m1 - pcrfit(reps, 1, 2, l5)
AICc(m1)
[1] -102.5843
but when i try cbind.na(1, 1:7) i take message
Error: could not find function cbind.na
Thanks
--
View this message in context:
On Nov 9, 2011, at 5:38 PM, Cem Girit wrote:
Hello,
Is there a web version of this R-Help user group
snip
Yes. You were offered an option to get a digest when you signed up.
I'm not sure if this response answers the question. It seems to me
that
there
Did you try
qpcR:::cbind.na(1, 1:7) as specified in the help files?
cbind.na isn't exported in the namespace, but can still be used as
above. The examples in the documentation show this.
Sarah
On Thu, Nov 10, 2011 at 6:38 AM, Evgenia ev...@aueb.gr wrote:
I want to use function cbind.na at
Hi,
I tried that before but then I get:
Error: 'melt.data.frame' is not an exported object from 'namespace:reshape2'
Strange that this is working in your case but not in my case.
Some addtional info about my package versions:
R 2.14.0
reshape 0.8.4
reshape 1.1
ggplot2 0.8.9
cheers
/j
Yes, I dit it. I got the same error message
qpcR:::cbind.na(1, 1:7)
Error in get(name, envir = asNamespace(pkg), inherits = FALSE) :
object 'cbind.na' not found
--
View this message in context:
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Sent from the R help
Then we likely need to know the information requested in the posting
guide, including your version of R and OS; the output of sessionInfo()
at the very least.
And please send your replies to the list, not just me.
Sarah
2011/11/10 ev...@aueb.gr:
Yes, I dit it. I got the same error message
Thanks Duncan.
This is a package, SIAR.
fo - ordered(f)
fo
[1] a b c d e
Levels: a b c d e
max(fo)
[1] e
Levels: a b c d e
The data set has 101 values, what can I use instead of letters?
Best wishes,
Alex.
--
View this message in context:
Dear R-project!
How do i create 1 dummy from 2 already existing dummys. To be more precise, I
want to create a dummy from a dummy called sex and another called sex1 when
both thoose dummys are 1 I want my created dummy samesex to take 1.
Thanks for the help!
Paulie
Have you tried loading reshape2 after ggplot2 and all it's requirements?
Usually whatever is loaded last masks earlier loaded packages with
functions of the same name so if reshape2 is last then it should mask
reshape(1) and all of it's similarly named functions.
Brandon
On Thu, Nov 10, 2011 at
Is the value.name ignored as well?
Looks like it might have been left out of the function call?
reshape2::melt
function (data, ..., na.rm = FALSE, value.name = value)
{
UseMethod(melt, data)
}
environment: namespace:reshape2
Brandon
On Thu, Nov 10, 2011 at 08:45, Johannes Radinger
I was thinking of an analytical solution, but using diff() works great as well!
thanks for help,
nico
On Nov 10, 2011, at 2:55 AM, R. Michael Weylandt wrote:
I think this will do it:
sum(sqrt(diff(x.pred)^2 + diff(y.pred)^2))
Michael
On Tue, Nov 8, 2011 at 11:34 AM, Nicolas Schuck
I am using gsub to remove numbers for each element of a list. Code is given
below.
testList - list(this contains a number 1000,this does not contain)
removeNumbers - function(X)
{
gsub(\\d,,X)
}
outputList - lapply(testList,removeNumbers)
However, when I try to find the number of
Hi,
I want to remove the outliers of my database with the following program (an
observation is considered an outlier if it is bigger than second quartile +
1,5* distance interquartiles or less than second quartile - 1,5*distance
interquartiles):
for(i in 1:length(dados)){
q3=quantile(dados[i],
I had the same issue. The problem is that melt will call a method. The
method will dispach melt.data.frame from reshape package, thus
ignoring reshape2. The solution is to call specificly
reshape2::melt.data.frame()
HTH
Luciano
2011/11/10 Johannes Radinger jradin...@gmx.at:
Am 10.11.2011 um
Hello,
Only answer to one but:
1. I can do a search on any topic over thousands of posts on R easily
and effectively
= www.rseek.org
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Sent from the R help mailing list
Sorry, it's reshape2:::melt.data.frame()
Luciano
2011/11/10 Johannes Radinger jradin...@gmx.at:
Hi,
I tried that before but then I get:
Error: 'melt.data.frame' is not an exported object from 'namespace:reshape2'
Strange that this is working in your case but not in my case.
Some
It is hard to tell with reproducible example; e.g., you data is
missing. At least provide 'str(dados)' so we have an idea of what it
looks like. My guess is that you want 'dados[[i]]' instead of
'dados[i]'. Also a stack trace would be useful. There was a
discussion yesterday about trapping
On Nov 10, 2011, at 6:12 AM, Alex DJ wrote:
Thanks Duncan.
This is a package, SIAR.
fo - ordered(f)
fo
[1] a b c d e
Levels: a b c d e
max(fo)
[1] e
Levels: a b c d e
The data set has 101 values, what can I use instead of letters?
Why not as.numeric(fo)?
--
View this
This is probably what you want:
outLength - lapply(outputList, function(x)length(strsplit(x, ' ')[[1]]))
outLength
[[1]]
[1] 4
[[2]]
[1] 4
notice that 'outputList' is a 'list' and not a legal argument to strsplit.
On Thu, Nov 10, 2011 at 5:29 AM, vioravis viora...@gmail.com wrote:
I am
Not sure what you mean by 'dummies'; do you mean 'objects'?
samesex - sex == sex1
Examples of the data would help in the formulation of an answer.
On Thu, Nov 10, 2011 at 5:13 AM, David . loove...@hotmail.com wrote:
Dear R-project!
How do i create 1 dummy from 2 already existing dummys. To
Hello,
Can anyone point me to an online tutorial or book containing the easiest way to
do ANOVA over the result data from a 2^k*r experiment. It is not clear to me if
I can pass the raw data corresponding to each experiment or just the summarized
data i.e. mean, sse, std, etc.
I would like to
Without having any actual idea what you mean (sample data!), this might work:
sex - c(1,0,1,0)
sex1 - c(1,1,0,0)
samesex - ifelse(sex == 1 sex1 == 1, 1, 0)
Note that this does NOT return 1 if both initial variables are 0, so
it isn't really a samesex indicator, but it is my best guess as to
Hello -
So I am trying to use ggplot2 to show a linear regression between two
variables, but I want to also show the fit of the line on the graph as well.
I am using ggplot2 for other graphics in what I am working on, so even though
this would be a fairly easy thing to do in Excel, I would
Hi,
Try ifelse function.
samesex - ifelse( sex==1 sex1==1, yes=1, no=0)
Cheers
Philippe Baril Lecavalier
On 2011-11-10 8:03 AM, David . loove...@hotmail.com wrote:
Dear R-project!
How do i create 1 dummy from 2 already existing dummys. To be more
precise, I want to create a dummy from a
The latest version, maps_2.2-2 (appearing soon on CRAN), has been
enhanced with the state.vbm and state.carto databases (thanks to Simon
Urbanek), and the state.fips, county.fips (both thanks to Clint
Cummins), state.vbm.center and state.carto.center datasets.
Enjoy,
Ray Brownrigg
On Nov 9, 2011, at 9:11 PM, Aimee Jones wrote:
Hi all,
I am trying to import some functions into a script and am having
difficulty in doing so. I am able to import a series of functions from
a .tex file into my script, and call on each function by column name,
however R reads them as data
Jim, you can use the function appended below, which is part of package
HandyStuff. If you want an example, see ?lmEqn after installing HandyStuff,
available at github.com/bryanhanson/HandyStuff. Bryan
lmEqn -
function(df = NULL, y = NULL, x = NULL,
method = lm, leg.loc = c(0, 0),
Dear R users,
I read your methods of extracting the variance explained by each
predictor in different places. My question is: using the method you
suggested, the sum of the deviance explained by all terms is not equal to
the deviance explained by the full model. Could you tell me what caused
Hi
Thanks Duncan.
This is a package, SIAR.
fo - ordered(f)
fo
[1] a b c d e
Levels: a b c d e
max(fo)
[1] e
Levels: a b c d e
The data set has 101 values, what can I use instead of letters?
Why do you need to use letters? AFAIK this was only illustration
hi Paulie,
Further to Sarahâs email, this will give the same sex indicator (both 0 or
both 1 then samesex scores 1):
samesex-ifelse(sex==sex1,1,0)
from what you have described this will give you the desired result
hope that helps,
Rob
Robert M Griffin
Department of Evolutionary Biology
On Nov 10, 2011, at 5:29 AM, vioravis wrote:
I am using gsub to remove numbers for each element of a list. Code
is given
below.
testList - list(this contains a number 1000,this does not
contain)
removeNumbers - function(X)
{
gsub(\\d,,X)
}
outputList -
On Nov 10, 2011, at 8:41 AM, Sarah Goslee wrote:
Without having any actual idea what you mean (sample data!), this
might work:
sex - c(1,0,1,0)
sex1 - c(1,1,0,0)
samesex - ifelse(sex == 1 sex1 == 1, 1, 0)
sex sex1
[1] TRUE FALSE FALSE FALSE
0+(sex sex1)
[1] 1 0 0 0
Note that
Going down the text parsing approach, you might want to use something
like this:
fnc - eval(parse(text=function(x) dnorm(x)))
all.equal(1/sqrt(2*pi), fnc(0))
[1] TRUE
On Thu, Nov 10, 2011 at 8:55 AM, David Winsemius dwinsem...@comcast.net wrote:
On Nov 9, 2011, at 9:11 PM, Aimee Jones wrote:
Since apparently there is no one familiar with this error message let me
rephrase the question. Is there a 'manual' process to fully remove a version
of 'R' from my machine? This is a Window PC running Windows 7.
Thank you.
Kevin
From: Kevin Burton [mailto:rkevinbur...@charter.net]
Dear all. Let say I have a group of codes which will be used in many places
in my overall R-code files. These group of codes will be used within a
for-loop (with a big length, like 1 times) and also many other places
outside of that for loop. As this group of codes are being used in many
Will traceback() work in the error routine specified in tryCatch?
error - function(e)
{
traceback()
}
tryCatch(..., error=error)
-Original Message-
From: William Dunlap [mailto:wdun...@tibco.com]
Sent: Wednesday, November 09, 2011 5:09 PM
To: Thomas Lumley; rkevinbur...@charter.net
Why don't you just download the latest release from CRAN - R. It is the
recommended approach to installing R.
Steve Friedman Ph. D.
Ecologist / Spatial Statistical Analyst
Everglades and Dry Tortugas National Park
950 N Krome Ave (3rd Floor)
Homestead, Florida 33034
steve_fried...@nps.gov
Hi
Since apparently there is no one familiar with this error message let me
rephrase the question. Is there a 'manual' process to fully remove a
version
of 'R' from my machine? This is a Window PC running Windows 7.
Not sure about W7 but I can easily remove R installation by simple
I downloaded and installed the latest (2.14.0). It works just fine. But, I
still have 2.13.2 installed and when I try to uninstall it I get the error
that I showed at the beginning of this thread.
-Original Message-
From: steve_fried...@nps.gov [mailto:steve_fried...@nps.gov]
Sent:
Hi,
On Thu, Nov 10, 2011 at 10:07 AM, Christofer Bogaso
bogaso.christo...@gmail.com wrote:
Dear all. Let say I have a group of codes which will be used in many places
in my overall R-code files. These group of codes will be used within a
for-loop (with a big length, like 1 times) and also
Yes, there will be some reduction in speed:
E.g.,
system.time(replicate(1e5, (function() sum(1:10))()))
user system elapsed
0.696 0.022 0.729
system.time(replicate(1e5, sum(1:10)))
user system elapsed
0.292 0.006 0.306
But it's not much: 3 tenths of a second for 10,000
Hi Christofer,
Any speed reduction should be relatively small, and the advantage in
terms of easily maintainable, clearly understandable code will be
enormous. If the function you make from the code does not have any
methods and you are concerned about a slow down related to your loop
repeatedly
You might want to try Revo Uninstaller. Reportedly it hunts down and kills
just about anything connected to a program that you want to uninstall. I have
only used it once but it seems to work. There is a free and a paid version. I
have the free one.
--- On Thu, 11/10/11, Kevin Burton
You can always runs a quick test. Here a loop is repeated 10M times
and the cost of the function call adds 344 ns; is this significant in
your case? Probably not for the modularity that is gained. For your
10,000 loops, it would add 3.44 ms to the overall run (less than an
blink of the eye).
On 10/11/2011 10:28 AM, R. Michael Weylandt wrote:
Yes, there will be some reduction in speed:
E.g.,
system.time(replicate(1e5, (function() sum(1:10))()))
user system elapsed
0.696 0.022 0.729
system.time(replicate(1e5, sum(1:10)))
user system elapsed
0.292 0.006
Dr Murdoch,
You're absolutely correct -- my apologies.
Michael
On Thu, Nov 10, 2011 at 10:44 AM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
On 10/11/2011 10:28 AM, R. Michael Weylandt wrote:
Yes, there will be some reduction in speed:
E.g.,
system.time(replicate(1e5, (function()
I can get multiple plots on a page like:
op - par(mfcol = c(3, 1))
What I was wondering is if there is a way to have a title for the whole
page? I can specify the title for each individual plot like:
plot(xxx, main=.)
But I would like a 'title' for the group of plots. Is this
?mtext
(Note the outer argument)
-- Bert
On Thu, Nov 10, 2011 at 8:07 AM, Kevin Burton rkevinbur...@charter.netwrote:
I can get multiple plots on a page like:
op - par(mfcol = c(3, 1))
What I was wondering is if there is a way to have a title for the whole
page? I can specify the
Try ?mtext for information on how to plot into the outer margin of a group of
plots.
Sarah
On Thu, Nov 10, 2011 at 11:07 AM, Kevin Burton rkevinbur...@charter.net wrote:
I can get multiple plots on a page like:
op - par(mfcol = c(3, 1))
What I was wondering is if there is a way to have
Hi,Don't know if this will help you but...In my short experience and following
the guidelines you should first uninstall R.
http://cran.r-project.org/doc/manuals/R-admin.html#Installing-R-under-Windows
Unistall it from the Windows control panel. The old R version libraries file
will be kept on
Perhaps something like this?
par(oma=c(0,0,2,0))
par(mar=c(1,1,1,1))
par(mfcol=c(3,1))
plot(rnorm(10))
mtext(title)
plot(rnorm(10))
plot(rnorm(10))
--
Muhammad Rahiz
On Thu, 10 Nov 2011, Kevin Burton wrote:
I can get multiple plots on a page like:
op - par(mfcol = c(3, 1))
What I was
The advice below is wholly unnecessary, and, in fact, various versions of R
can coexist without problems (and are designed to do so).
I just upgraded to 2.14.0 on Windows via the simple binary install process,
copied old libraries over (unnecessary if you do not wish to keep old
versions around
I have windows 7
and below is information about R and loading library(qpcR)
R version 2.9.1 (2009-06-26)
Copyright (C) 2009 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
R is free software and comes with ABSOLUTELY NO WARRANTY.
You are welcome to redistribute it under certain
Sounds like you are hypotesis testing. you can try an R companion to applied
regression 2nd edition 2011 by john fox and sanford weisberg.
effects package does interactions quite well.
- Original Message -
From: Giovanni Azua brave...@gmail.com
To: r-help@r-project.org
Sent: Thursday,
I know they can coexist. It all works fine with both versions installed. But
with limited resources I would like to uninstall the previous version (for
me it is 2.13.1). Choosing uninstall from the 'Control Panel' results in the
error listed at the beginning of this thread.
From: Bert Gunter
Well, that's your problem.
You need to upgrade to the latest version of R, and the latest version of qpcR.
It's no wonder things found in the current version don't work
correctly in software that's over two years old.
Sarah
On Thu, Nov 10, 2011 at 11:43 AM, Evgenia ev...@aueb.gr wrote:
I have
The problem with this documentation is two-fold. One it seems to concentrate
on building from source which I don't need. Two it doesn't address the
upgade. I have a number of packages and so I need to do what has been
suggested and install the latest version *first*. Then copy the libraries
The error seems clear enough to me... sqlSave is trying to create the table but
it already exists.
Some possible directions you could take:
1) Do your work on a particular instance of the table within a single
transaction and rollback at the end.
2) Delete the table before you run sqlSave.
3)
From: Uwe Ligges ligges_at_statistik.tu-dortmund.de
mailto:ligges_at_statistik.tu-dortmund.de?Subject=Re:%20[R]%20Help%20with%2
0gam
Date: Wed, 11 May 2011 19:08:38 +0200
On 11.05.2011 17:22, Zsolt Macskasi wrote:
Hi,
http://tolstoy.newcastle.edu.au/R/e14/help/11/05/1036.html#1040qlink1
Thanks for the answer, but I already fixed the problem. The problem was in
selecting the row and column of the matrix. The program fixed is:
for(i in 1:length(dados)){
q3=quantile(dados*[,i]*, probs=.75)
q2=quantile(dados*[,i]*, probs=.50)
q1=quantile(dados*[,i]*, probs=.25)
d=q3-q1
for(i2 in
Hi everybody,
I started to receive a weird message in R that I have never seen
before...also I haven't found anything on google or on this forum about it.
Whenever I use the command source(...) to point to one of my scripts, I get
the following message:
Error in source(myfunctions.R) :
Hello,
to understand better how efpFunctional works, I'm trying to construct my own
functionals. But concerning already existing functionals I have some
questions. With maxBB it is clear:
functional = list(comp = function(x) max(abs(x)), time = max),
with rangeBB:
functional = list(time =
Hi everybody,
I started to receive a weird message in R that I have never seen
before...also I haven't found anything on google or on this forum about it.
Whenever I use the command source(...) to point to one of my scripts, I get
the following message:
Error in source(myfunctions.R) :
Hi,
I am a little new in R but I'm finding it extremely useful :)
Here's my tiny question:
I've got a table with a lot of columns. What I am interested now is to
evaluate how many of 4 columns have a value greater than 1.
I think it can be done with subset() but it will take a very long
Hello,
Sorry in advance for adding a silly question on this forum but I haven't
found the right keywords to find a solution to this basic problem.
I'm just looking a way to have a white background behind the legend to hide
the grid.
Thanks in advance.
The silly example for my silly question:
Hi:
Here's an example of how one might do this in a specific example using
geom_text().
# Some fake data:
df - data.frame(x = 1:10, y = 0.5 + (1:10) + rnorm(10))
# Fit a linear model to the data and save the model object:
mod - lm(y ~ x, data = df)
# Create a list of character strings - the
Hello R friends,
I get quite confused in using the grid graphic function grid.pack( )
and grid.frame ( ). Here is a simple example:
library(grid)
grid.frame(name=frame1)
grid.pack(frame1,rectGrob(width=unit(0.5,npc),
height=unit(0.5,npc), gp=gpar(col=red)))
what I expect is a rectangle with
please post my query in your mailing list
--
LAXMI KANT TIWARI
Andaman and Nicobar Space Application Cell
PCCF'S Office, Van Sadan, Haddo - 744102
Port Blair, Andaman and Nicobar Islands, India
Ph:+913192234430
Mobile:+919531839311
Alternate email: tiwari21...@itc.nl
When you put (fo) what do you mean?
With ordered variable am now getting this error message:
model1 - siarmcmcdirichletv4(data, source, tef, concdep=0, 50, 5)
Error in matrix(1, ncol = (numsources + numiso) * numgroups, nrow =
(siardata$iterations - :
invalid 'ncol' value (too
The data set has 101 values, what can I use instead of letters?
Why do you need to use letters? AFAIK this was only illustration what
could be root of the error message. If the function requires ordered
factor you can use
your.ordered.factor - ordered(your.unordered.factor)
I do not
You have a syntax error in your script. Take a look around line 884
On Thu, Nov 10, 2011 at 9:27 AM, ftonini f_ton...@hotmail.com wrote:
Hi everybody,
I started to receive a weird message in R that I have never seen
before...also I haven't found anything on google or on this forum about it.
try this:
x
Col1 Col2 Col3 Col4
11111
22111
34141
43333
apply(x, 1, function(a) sum(a 1))
[1] 0 1 2 4
x$count - apply(x, 1, function(a) sum(a 1))
x
Col1 Col2 Col3 Col4 count
11111 0
22111
Hi JL,
How about the following?
rowSums(d 1) # d is your data
Best,
Jorge.-
On Thu, Nov 10, 2011 at 10:24 AM, JL Villanueva wrote:
Hi,
I am a little new in R but I'm finding it extremely useful :)
Here's my tiny question:
I've got a table with a lot of columns. What I am interested
I have the following code,
gibbs -function(m,theta = 0.25, lambda =0.55, n =1){
alpha - 1.5
beta - 1.5
gamma - 1.5
x- array(0,c(m+1, 3))
x[1,1] - theta
x[1,2] - lambda
x[1,3]- n
for(t in 2:(m+1)){
x[t,1] - rbinom(1, x[t-1,3], x[t-1,1])
On Thu, 10 Nov 2011, bonda wrote:
Hello,
to understand better how efpFunctional works, I'm trying to construct my own
functionals. But concerning already existing functionals I have some
questions. With maxBB it is clear:
functional = list(comp = function(x) max(abs(x)), time = max),
with
Hello everyone,
Can anyone suggest a decently documented (with good examples in the
documentation) R package/function that performs segmentation (cluster,
mixture modeling) of a population using both continuous and categorical
input variables?
Thank you,
Dan
[[alternative HTML version
Hi:
Add a background = 'color' argument to key():
library('lattice')
xyplot(1~1,
panel = function(x,y, ...) {
panel.xyplot(x,y)
panel.abline(v=seq(0,1.4,by=0.1))
panel.abline(h=seq(0,1.4,by=0.1))
}
,key = list (x=0.2,
It's usually encouraged to reply to the list as well for
threading/archive reasons. (And because occasionally your first
respondent will say something wrong and require correction -- I was
called out just this morning...oops)
Yes, you seem to be using it right to add a title to the plot but you
Hello!
I am trying to create an R optimization routine for a task that's
currently being done using Excel (lots of tables, formulas, and
Solver).
However, otpim seems to be finding a local minimum.
Example data, functions, and comparison with the solution found in
Excel are below.
I am not
Hi:
Here's a toy example:
# Default var names are V1-V20:
u - as.data.frame(matrix(rpois(100, 3), ncol = 20))
u - transform(u,
ngt1 = apply(u[, c('V1', 'V4', 'V9', 'V15')], 1, function(x) sum(x 1)) )
u
HTH,
Dennis
On Thu, Nov 10, 2011 at 7:24 AM, JL Villanueva jlpost...@gmail.com wrote:
I'm studying lists and I came to an example where
L
$name
[1] Fred
$wife
[1] Mary
$no.children
[1] 4
$child.ages
[1] 4 7 9
then following the instructions to extend the list with a new component, I
executed:
L[5] -list(NewName=something)
and the new list I got was:
L
$name
[1] Fred
Hi,
On Thu, Nov 10, 2011 at 1:55 PM, JulioSergio julioser...@gmail.com wrote:
I'm studying lists and I came to an example where
L
$name
[1] Fred
$wife
[1] Mary
$no.children
[1] 4
$child.ages
[1] 4 7 9
then following the instructions to extend the list with a new component, I
Just to add:
I also experimented with the starting parameters (par) under optim,
especially with the second one. I tried 1, 10, 100, 1000, etc.
When I tried 100,000,000 then I got a somewhat better solution (but
still not as good as in Excel). However, under message it said:
ERROR:
On my MacBook Pro (OS 10.6.8), after updating to R version 2.14.0 (2011-10-31)
and reinstalling the Hmisc package, I am unable to load the Hmisc library.
Hmisc was working *before* I updated R.
Any idea what's wrong?
Details below.
install.packages(Hmisc, dependencies=TRUE)
trying URL
Refer to the CRAN Optimization task view, please. That is a much more
appropriate place to begin than posting a query here.
All numerical optimizers only produce local optima.
-- Bert
On Thu, Nov 10, 2011 at 11:24 AM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Just to add:
I think you are off in the order of calls: you need to open the pdf
and then do all the plots so that they get pushed to the pdf. The
blank plot call won't do anything particularly helpful. If you use
pdf() after most of the plot commands they go to your default device
which is usually printing to
Sarah Goslee sarah.goslee at gmail.com writes:
Hi,
You probably want:
L[NewName] - something
or one of the many potential variants.
Thanks, Sara,
That works!
However, following the idea that the syntactic notation L[i] means
a sublist of L, again the syntactic notation
L[i] -
Help!
model1 - siarmcmcdirichletv4(data, source, tef, concdep=0, 50, 5)
Error in matrix(1, ncol = (numsources + numiso) * numgroups, nrow =
(siardata$iterations - :
invalid 'ncol' value (too large or NA)
In addition: Warning message:
In Ops.ordered((numsources + numiso), numgroups) :
Bert,
that's exactly where I started. I found optim in the first paragraph
under General Purpose Continuous Solvers and used bounded BFGS for a
constrained optimization for a situation with more than 1 parameters.
Again, not being an engineer / mathematician - would greatly
appreciate any
Hi All,
I have a scatter plot produced using ggplot2 and I want to add the
regression line to this scatter plot. I suppose I can use
geom_smooth() to do this, but for the sake of learning ( I am new both
to R and ggplot2), I want to try and add it as a function (something
that curve() does in the
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