Hi , I am trying to do a 3 variable interaction and received this warning
message. Can someone please interpret?
Model31.glm - glm(cbind(Shells, TotalEggs-Shells) ~
Aeventexhumed:HTL:Sector, data=data.to.analyze, family = binomial)
Warning message:
glm.fit: fitted probabilities numerically 0 or
I am doing Principal Component Analysis (PCA) on assets data for household
income prediction. The problem is that the assets data are rank ordered
(usually binary ... possess car/don't possess car), so the normal correlation
is inappropriate for the calculation of the PCA. Instead one has to
Dear All,
I have data set which includes details of locations e.g latitude, longitude
, time.
I would like to compare two different data sets ( sampling in space and
time).
the e.g data sets are as follows
t_lat
[1] -90.00 -86.17 -82.34 -78.51 -74.68 -70.85 -67.02 -63.19 -59.36 -55.53
Dear All
I am trying to include sampling weights in multilavel regression analysis using
packege lme4 using following codes
print(fm1 lt;- lmer(DC~sex+age+smoker+alcohol+fruits(1|setting), dataset,REML
= FALSE), corr = FALSE)
print(fm2 lt;-
sorry there is typing error in codes
the correct ones are
nobs-length(s_lat)
for (i in 1:length(nobs)){lat_match- which(abs(t_lat - s_lat ==
min(abs(t_lat - s_lat)))}
--
View this message in context:
Hi
Dear All,
I have data set which includes details of locations e.g latitude,
longitude
, time.
I would like to compare two different data sets ( sampling in space and
time).
the e.g data sets are as follows
t_lat
[1] -90.00 -86.17 -82.34 -78.51 -74.68 -70.85 -67.02 -63.19
I'm trying to create a data frame in which some of the column names
contain a dash -. A simple example:
d - data.frame(x = c(0, 1))
d - data.frame(d, y = c(0,1))
names(d)[2] - a.-5
d
x a.-5
1 00
2 11
d - data.frame(d, y = c(0,1))
d
x a..5 y
1 00 0
2 11 1
names(d)[2] - a.-5
d
Hi Mark,
I cannot tell you why (maybe someone else can), but the check.names
argument to data.frame() interpret a.-5 as an unvalid name and convert
to to a valid one. What I don't understand is why it isn't valid since
it works anyway.
You can set up the check.names argument to FALSE when
On 01/24/2012 06:23 AM, Debs Majumdar wrote:
Hi All,
I am trying to figure out what package was used to create the following
graph?
http://f.imgtmp.com/MZjwy.png
Why stackpoly in plotrix, of course.
Jim
powerplot.pdf
Description: Adobe PDF document
I am using wireframe function from lattice package, and I would like to use
shade option in a manner that can decide which color palette I want to use.
If I am using drape=TRUE option and I have no shade effect, but if I am
using shade=TRUE than I loose drape palette I wished. For instance, I
J,
For at least one combination of Aeventexhumed:HTL:Sector Shell is either 0 or
equal to TotalEggs.
Best regards,
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie Kwaliteitszorg / team Biometrics Quality Assurance
Or maybe ?filled.contour.
Regards
Petr
On 01/24/2012 06:23 AM, Debs Majumdar wrote:
Hi All,
I am trying to figure out what package was used to create the
following graph?
http://f.imgtmp.com/MZjwy.png
Why stackpoly in plotrix, of course.
Jim
[příloha powerplot.pdf
On 01/24/2012 09:13 PM, Petr PIKAL wrote:
Or maybe ?filled.contour.
Regards
Petr
On 01/24/2012 06:23 AM, Debs Majumdar wrote:
Hi All,
I am trying to figure out what package was used to create the
following graph?
http://f.imgtmp.com/MZjwy.png
Why stackpoly in plotrix, of course.
Hi,
I am a total newbie to R so I apologize if the answer to my question is too
obvious. I a data set of the following form:
Date
V1
V...
VN
Region
Industry
22/03/1995 23:01:12
1
3
2
15
A
Hi Thanks for reply, there was some mistakes in typo. I have already
corrected it.
this function gives us closest point ( R book reference).
So I would like to find all observations on another grid spatially and
temporally.
the function is just for finding all closest observations.
uday
--
This site can help you with SPSS stuff,
http://www.ivoryresearch.com/custom-statistical-services-spss.php its really
good
--
View this message in context:
http://r.789695.n4.nabble.com/read-in-Stata-and-SPSS-with-value-labels-formats-tp4311210p4323359.html
Sent from the R help mailing list
Hi,
I would like to substitute a semicolon with two double quotation marks and
a comma inbetween.
It suppose to look like that:
I have:
FBpp0070086;FBpp0099643;FBpp0112915
I would like to have:
FBpp0070086,FBpp0099643,FBpp0112915
I tried with various numbers of backslashes, but noe have worked.
On Tue, Jan 24, 2012 at 12:20 AM, Ted Byers r.ted.by...@gmail.com wrote:
Here is a relatively simple script (with comments as to the logic
interspersed):
# Some of these libraries are probably not needed here, but leaving them in
place harms nothing:
library(tseries)
library(xts)
Hi all,
Since three month ago I started working with R professionally, I never did
it before, so I am such a newbie.
I am having some problems using the 'debug' package. I love this package,
but most of the times I wanna use it it just fails :P
When typing at prompt 'mtrace(myfunct)' most of
I cannot understand why a function appears to be available to R
(is.loaded('planckwR') returns TRUE) but the call with .C results in an
error message:
C symbol name 'planckwR' not in DLL for package path to DLL file here
This is what I do:
Loading a homebrewed DLL, compiled with MS VS97.
Hi
I need to remove source of the library from sweave. Please help me
cat(\nlibrary(caret),file = abc.Rnw, append = TRUE)
cat(\nlibrary(xtable),file = abc.Rnw, append = TRUE)
i'm getting the source of the library also.
can any one help
-
Thanks in Advance
Arun
--
View this
Hi Assa,
On Tue, Jan 24, 2012 at 6:30 AM, Assa Yeroslaviz fry...@gmail.com wrote:
Hi,
I would like to substitute a semicolon with two double quotation marks and
a comma inbetween.
It suppose to look like that:
I have:
FBpp0070086;FBpp0099643;FBpp0112915
I would like to have:
Hi All,
This is the file which I want to import into R After importing and querying the
data, error is coming as null.
read.csv(Noname3.csv, header=T) - FD
FD$SUBJECT
NULL
Can please help?
Regards
Devarayalu
__
R-help@r-project.org mailing list
On 23.01.2012 19:43, Ben Bolker wrote:
Uwe Liggesliggesat statistik.tu-dortmund.de writes:
On 23.01.2012 15:12, Gilda Mazzarelli wrote:
Hi all!
I'va tried to install the routine FEAR in R, to compute DEA estimates for
an academic work.
I've downloaded and installed R (the last version
On 23.01.2012 20:05, Tom Porteus wrote:
I am running R 2.14.1 on a Windows XP (32 bit) system, and am trying to
install the package 'Rmpi' to allow me to parallel process on all cores of a
quad-core PC (and if that works well, I want to add extra slaves from a
dual-core laptop). Rmpi appears
On Tue, Jan 24, 2012 at 12:07:26PM +, Sri krishna Devarayalu Balanagu wrote:
Hi All,
This is the file which I want to import into R After importing and querying
the data, error is coming as null.
read.csv(Noname3.csv, header=T) - FD
FD$SUBJECT
NULL
Hi.
Names of the columns are
Hi Ista,
This is hat I thought I am doing
I forgot to mention, but I am working with a table which look like that:
head(data)
id protein_ids
45FBpp0070037
46FBpp0070039;FBpp0070040
47FBpp0070041;FBpp0070042;FBpp0070043
48FBpp0070044;FBpp0110571
...
For one line your solution
Hello everyone,
I am writing my own function to return the column index of all variables
(these are currently character vectors) in a data frame that contain a
dollar sign($). A small piece of the data look like this:
can_sta can_zip ind_ite_con ind_uni_con AL 36106 $251,895.80 $22,874.43
AL
Dear R-helpers,
I am trying to add an information about the mean value for each variable
within each plot by adding text to the multiple plots in this way:
par(mfrow=c(2,2))
df$Date - as.Date(df$Date, format=%d/%m/%Y)
for (i in 2:5){
plot(df$Date, df[[i]])
Mean -
Either
any(grepl($,x, fixed = TRUE)) # You probably want grepl not grep
any(grepl(\\$,x) )
? regexpr # $ has a special value
Michael
PS -- Stop with HTML postings (seriously, it actually does mess up
what the rest of us see and I think it causes trouble for the archives
as well)
On Tue, Jan
On 01/24/2012 03:49 PM, Dan Abner wrote:
Hello everyone,
I am writing my own function to return the column index of all variables
(these are currently character vectors) in a data frame that contain a
dollar sign($). A small piece of the data look like this:
can_sta can_zip
Dear R-helpers,
I have a bivariate phenotype to be compared between several groups.
Using 'manova' function I can get point estimates of group means. I
would like to plot these estimates together with their confidence
ellipses, but I do not know, how to get interval estimates of group
means as
On Jan 24, 2012, at 4:44 AM, Ivan Calandra wrote:
Hi Mark,
I cannot tell you why (maybe someone else can), but the check.names
argument to data.frame() interpret a.-5 as an unvalid name and
convert to to a valid one. What I don't understand is why it isn't
valid since it works anyway.
Yuanyuan Tang vas escriure el dia dl, 23 gen 2012:
Hi, all:
I met Non-conforming parameters for function %*% problem, when I run the
Jags model in R.
Please, try the JAGS forum:
http://sourceforge.net/projects/mcmc-jags/forums/forum/610037
And start trying to find the problem as is
It seems that using Beta=NULL causes the routine to function the way
beta=TRUE used to function, i.e., the value is computed and reported. I
think, IMHO, that this new functionality should this be documented on the
help page.
I did not test out how the gamma parameter behaves.
Thanks.
--
View
All,
I currently have a dataset with a variety of different columns, let's say,
A,B,C, and D. I'd like to run an R script that graphs only certain rows of
the dataset based on what's in column A. In awk, it'd be something like:
awk ' { if(A==5 B ==6) print $0 } ' datafile | command or file
By it works anyway, I mean that you can have a dash in a column name,
there is no error or even warning.
I guess that some functions would throw an error or warning, depending
on the requirements, but data.frame() doesn't.
Ivan
Le 24/01/12 15:35, David Winsemius a écrit :
On Jan 24, 2012,
Hi everybody,
I know that a similiar topic has been posted, but as my question differs I
am opening a new topic. I am trying to follow how the godness of fit test
for copulas in the copula package works. Therefore I wrote a function to
caculate the empirical copula, whose results are necessary to
Hi,
I have a series of MS word files and each file contains plain text. From
these texts I would like to extract only those elements (read: words) that
are between square brackets. Example of a text:
Most fundamentally, it has led to an effort to clarify the organizational
form concept.
On 24/01/2012 6:49 AM, Alex van der Spek wrote:
I cannot understand why a function appears to be available to R
(is.loaded('planckwR') returns TRUE) but the call with .C results in an
error message:
C symbol name 'planckwR' not in DLL for packagepath to DLL file here
You posted this question
how bout using read.table(... , sep= ).
That would give you a vector of single words. then
grepl(\\[[9-z]+\\],x)
will return a boolean vector
x-c('test','[bracket]','hi]','[blah','foo','[bar]')
grepl('\\[[9-z]+\\]',x)
[1] FALSE TRUE FALSE FALSE FALSE TRUE
x[grepl('\\[[9-z]+\\]',x)]
[1]
On Jan 24, 2012, at 8:12 AM, ksaw wrote:
Dear R-helpers,
I am trying to add an information about the mean value for each
variable
within each plot by adding text to the multiple plots in this way:
par(mfrow=c(2,2))
df$Date - as.Date(df$Date, format=%d/%m/%Y)
for (i in 2:5){
I am using the wireframe function from lattice package. The problem that I
have is very interesting. Namely, this is my code:
x= seq(-pi, pi, len = 20)
y=seq(-pi, pi, len = 20)
xyz= expand.grid(x = x, y = y)
xyz$z=sin(sqrt(xyz$x^2 +xyz$y^2))
I wish to perform moving tiles bootstrap resampling on some gridded data
meteorological data. I've many years experience with S-Plus, but it has
no way to perform a moving-tiles bootstrap. Within R I've learned how to
use quadratresample() with the spatstats package and would be happy to
Ivan:
On Tue, Jan 24, 2012 at 6:47 AM, Ivan Calandra
ivan.calan...@u-bourgogne.fr wrote:
By it works anyway, I mean that you can have a dash in a column name,
there is no error or even warning.
I guess that some functions would throw an error or warning, depending on
the requirements, but
Hi Deivit,
Can you offer a self contained example of r code when the function fails
for you?
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il
Hi andreas,
Please give a sample of your data, and how you want it to be after the
manipulation.
Consider using
?dput
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) |
Hi everyone,
I am using Michael's approach (grepl()) to identify which columns
containing $ signs. I was hoping to incorporate this into a line of
code that would automatically 1) find which columns contain $ signs,
2) strip the $ and commas, and 3) convert the result to a numeric
vector.
I have
For quantile normalization check out
normalize.quantiles in the Biocondcutor preProcess package. Also,
there is a Bioconductor mailing list for future where these topics
are discussed.
http://svitsrv25.epfl.ch/R-doc/library/preprocessCore/html/normalize.quantiles.html
On Sat, Jan 21, 2012 at
Hi, Michael,
Got it, thank you so much!
Chee
From: R. Michael Weylandt
Sent: Monday, January 23, 2012 11:33 PM
To: r-help ; Chee Chen
Subject: Re: [R] Help: read a proportion of high through-put data
Ok, it seems to have worked on my machine as well, but for some levels
you didn't mention
Hello,
I would like to reshape a dataframe into an array. This is kind a similar task
as Excel performs with a Pivot table. To illustrate it:
LOC - factor(c(1,2,2,3,1,1))
SPEC1 - c(0,0,23,0,12,11)
SPEC2 - c(1,2,0,0,0,4)
df - data.frame(LOC,SPEC1,SPEC2) # original dataframe
a -
Dear R users,
I'm a new user to R and have a data set consisting of a number of variables (in
a data frame). I wish to carry out a regression analysis of the first variable
against all the rest in turn. I have used the following code to do this
dd-read.table(for loop.txt,header=T)
for (j in
I'll try,
Here is a piece of code it fails for me, the error I get is always the same,
and it happens in most of my functions. The problem is always the same
trying to execute 'mtrace'.
Thanks!
--- execution --
mtrace(index_remap)
Error in x[[i]] : subscript out of
Hello,
I have a dataset with 40 variables, some of them are always 0 (each
row). I would like to make a subset containing only the columns which
values are not all 0, but I don't know how to do it.
I tried:
for(cut_column in 1:40) {
if(sum(dataset[,cut_column])!=0) {
Bert,
Thank you for correcting my inaccuracy. A quick look at the original
question might help you understand what I meant:
d- data.frame(x = c(0, 1))
d- data.frame(d, y = c(0,1))
names(d)[2]- a.-5
d
x a.-5
1 00
2 11
d1- data.frame(d, y = c(0,1))
d1
x a..5 y
1 00 0
2 11 1
On Jan 24, 2012, at 11:07 AM, Dan Abner wrote:
Hi everyone,
I am using Michael's approach (grepl()) to identify which columns
containing $ signs. I was hoping to incorporate this into a line of
code that would automatically 1) find which columns contain $ signs,
2) strip the $ and commas, and
Dear David,
Thanks for your reply. However, I can't see how this is a case. The table is
read into R from .csv file. The column Date has a factor format then. If I
don't change it to as.Date format and use the same code, the 'text' function
print the mean by the maximum on y ax regardless to
I've usually understand the restrictions on syntactic names as being
tied to the parser.
E.g., how could R tell the difference between
d - data.frame(a = 3, `a-2` = 3, check.names = TRUE)
d$a-2 ## Equal to 1 or 3 ?
One of those strange eval things that makes alot of sense for an
interactive
Sorry, I meant check.names = FALSE (d'oh!)
Michael
On Tue, Jan 24, 2012 at 11:33 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
I've usually understand the restrictions on syntactic names as being
tied to the parser.
E.g., how could R tell the difference between
d - data.frame(a
dataset-data.frame(a=1:10,b=c(0,0,0,1,0,0,0,0,1,0),c=rep(0,10))
apply(dataset,2,function(x) all(x==0))
a b c
FALSE FALSE TRUE
dataset[,!apply(dataset,2,function(x) all(x==0))]
a b
1 1 0
2 2 0
3 3 0
4 4 1
5 5 0
6 6 0
7 7 0
8 8 0
9 9 1
10 10 0
On Tue, Jan
On Jan 24, 2012, at 11:20 AM, Katarzyna Sawicka wrote:
Dear David,
Thanks for your reply. However, I can't see how this is a case. The
table is read into R from .csv file. The column Date has a factor
format then. If I don't change it to as.Date format and use the same
code, the 'text'
Try also
dataset[, colSums(dataset == 0) != nrow(dataset)]
HTH,
Jorge.-
On Tue, Jan 24, 2012 at 11:14 AM, Francisco wrote:
Hello,
I have a dataset with 40 variables, some of them are always 0 (each row).
I would like to make a subset containing only the columns which values are
not all
Ivan:
AFAICS you did not read my post carefully enough. Unquoted improper
identifiers trigger an error because the input cannot be parsed. It
has nothing to do with data.frame() .(**R EXPERTS, PLEASE CORRECT IF
WRONG**). Unquoted LEGAL names are accepted because that's how R works
-- they can be
Hello Everyone,
Still new to R. Wrote some code that finds and prints invalid dates (see
below). This code works but I suspect it's not very good. If someone could show
me a better way, I'd greatly appreciate it.
Here is some information about what I'm trying to accomplish. My sense is that
Hi Tal,
thank you very much for your reply. The xts-dataframe I am using is like:
example - as.data.frame(structure(c( 1, 2, 1, 2, 1, 1,
2, 1, 2,
1, 2, 3, 1, 1, 2, 2, 3, 1, 2, 2,
1, 2, 1, 1, 2, NA, 2, NA, NA, 1, 3, 1,
3, 3, 2, 3, 3, 3, 2, 2, 2, 3, 3,
Uploaded the DLL here:
http://www.filefactory.com/file/c2c56ad/n/Planck.dll
Appreciate if you can check to see if anything is wrong with this DLL. I
use dumpbin to look at what is in the exports table of the DLL. No reason
for concerns there. I can work with this DLL from both VBA and Python.
Dear All,
I'm wondering if there is a R function could give me all the
combinations of the grouping/cluster result, given the number of the groups.
e.g.
3 objects: x1 x2 x3, number of groups is 2
so the result will be
group1:x1,x2; group2: x3
group1: x1;group2: x2,x3
group1: x1,x3;group2: x2
A) Reposting the same message as a separate thread is bad netiquette.
B) Posting HTML email on this list is strongly discouraged.
C) You probably ought to read the posting guide.
D) This is a list about using R. Posting theoretical questions without
corresponding R code that illustrates what
I wish to proffer my sincere apologies to both you and the list. I had
not seen my posting appear -- it was initially held for moderator
approval, but I never saw that it was released. During the subscription
process, I had used an incorrect e-mail address and so withdrew the
post. Within my
I just watched
http://www.youtube.com/watch?v=iSXNfZESR5I
and there is a section where Hadley Wickham showed demonstrated a county map
of the US that was interactive. This is exactly what I would like. I have
downloaded ggplot2 but still failed to find out how to even read in and plot
On 24/01/2012 11:55 AM, Alex van der Spek wrote:
Uploaded the DLL here:
http://www.filefactory.com/file/c2c56ad/n/Planck.dll
I get:
403 Forbidden
Request forbidden by administrative rules.
Duncan Murdoch
Appreciate if you can check to see if anything is wrong with this DLL. I
use
Hi,
I wouldn't know how to fill the data into the array form you want, but
you can get the aggregated data with
dfm - melt( df )
dfc - cast( dfm, LOC ~ variable, sum )
dfc
LOC SPEC1 SPEC2
1 123 5
2 223 2
3 3 0 0
Hope this helps as a first step!
Rgds,
Rainer
On Tue, Jan 24, 2012 at 05:19:42PM +, yan jiao wrote:
Dear All,
I'm wondering if there is a R function could give me all the
combinations of the grouping/cluster result, given the number of the groups.
e.g.
3 objects: x1 x2 x3, number of groups is 2
so the result will be
On Jan 24, 2012, at 1:15 PM, Kevin Burton wrote:
I just watched
http://www.youtube.com/watch?v=iSXNfZESR5I
and there is a section where Hadley Wickham showed demonstrated a
county map
of the US that was interactive. This is exactly what I would like.
I have
downloaded ggplot2 but
Hi Kevin,
I haven't watched through the video yet, but I guess It's not ggplot2, just
like David pointed out, it's actually using a different graphic engine,
implemented in packages qtbase/qtpaint, which are hosted on Biocondcutor,
to install them, please run
Hello,
Point 3 is very simple, instead of 'print' use 'cat'.
Unlike 'print' it allows for several arguments and (very) simple formating.
{ cat(Error: Invalid date values in, DateNames[[i]], \n,
TestDates[DateNames][[i]][TestDates$Invalid==1], \n) }
Rui Barradas
--
View this
I think you can do this in hexadecimal. To see this, compare the HEX output
from rgb(1,0,0) and rgb(1,0,0,0.5):
#FF
#FF80
They differ only by the addition of the alpha digits hex 80 which are
(almost) half way between 00 and FF. Making a non-transparent scale
transparent is thus just a
We were looking at conducting a pilot program with Dell to virtualize our lab
environments. We are specifically looking at Dell/Citrix provisioning servers.
The OS in this setup is streamed from the server on every boot. I was curious
if the R Project had any licensing stipulations in this
On Tue, Jan 24, 2012 at 6:19 PM, Mohd masood masood0...@rediffmail.com wrote:
Dear All
I am trying to include sampling weights in multilavel regression analysis
using packege lme4 using following codes
print(fm1 lt;- lmer(DC~sex+age+smoker+alcohol+fruits(1|setting),
dataset,REML = FALSE),
On Tue, Jan 24, 2012 at 9:36 AM, Bert Gunter gunter.ber...@gene.com wrote:
1. It's an interaction in a formula not a multiplication.
2. Read the Help file. It says to use ltsreg not lmsreg.
3. But no P values will be given anyway. The reason is that exact
distributions and therefore
On Jan 24, 2012, at 11:17 AM, Taylor, Brian wrote:
We were looking at conducting a pilot program with Dell to virtualize our lab
environments. We are specifically looking at Dell/Citrix provisioning
servers. The OS in this setup is streamed from the server on every boot. I
was curious
Dear all,
I just try to run the example in R brugs packages, but not only once. Loop is
added in this example. After several times (7, 11, or other random number),
there is an error message r for windows gui front-end has stopped working.
This happened in two laptops with windows 7 and vista.
On Tue, Jan 24, 2012 at 07:05:37PM +0100, Petr Savicky wrote:
On Tue, Jan 24, 2012 at 05:19:42PM +, yan jiao wrote:
Dear All,
I'm wondering if there is a R function could give me all the
combinations of the grouping/cluster result, given the number of the groups.
e.g.
3 objects:
I get this error from read.table():
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
line 234 did not have 8 elements
The error is genuine (an extra field separator between 1st and 2nd element).
1. is there a way to see this bad line 234 from R without diving into
dataset.1 - dataset[, apply(dataset, 2, sum)0]
Gregorio R. Serrano
2012/1/24 Francisco franciscororol...@google.com
Hello,
I have a dataset with 40 variables, some of them are always 0 (each row).
I would like to make a subset containing only the columns which values are
not all 0, but I
On 24/01/2012 3:45 PM, Sam Steingold wrote:
I get this error from read.table():
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
line 234 did not have 8 elements
The error is genuine (an extra field separator between 1st and 2nd element).
1. is there a way to see
On 25/01/12 05:14, Francisco wrote:
Hello,
I have a dataset with 40 variables, some of them are always 0 (each
row). I would like to make a subset containing only the columns which
values are not all 0, but I don't know how to do it.
I tried:
for(cut_column in 1:40) {
Like the t-shirt says, There's no place like 127.0.0.1
quote
Though I wasn't familiar with this I check the repositories list and
CRAN (extras) is selected in my installation (R-2.14.1). By the way,
when trying Ryacas after what seemed to be a successful install, for a
simple example of
On Jan 24, 2012, at 20:41 , Thomas Lumley wrote:
It's not meant for sampling weights. It's meant for precision
weights. How best to include sampling weights in mixed models is a
research problem at the moment, but you can rely on getting the wrong
answer if you just use the weights=
On Tue, Jan 24, 2012 at 4:07 PM, Carl Witthoft c...@witthoft.com wrote:
Like the t-shirt says, There's no place like 127.0.0.1
quote
Though I wasn't familiar with this I check the repositories list and CRAN
(extras) is selected in my installation (R-2.14.1). By the way, when trying
Yes, you're right about this being a floating point issue. I guess I
wasn't clear enough that this was already understood. I'd have responded
earlier the response somehow missed my mailbox.
My question is rather whether there is a work around for correctly
displaying POSIXct values as
Given your domain name, you might also get some use out of the
system() and system2() commands which allow the passing of strings to
the OS command line (and thus the use of tools like grep/sed/awk
within R)
E.g., an idiom I use pretty frequently for interactive data analysis:
(not really
Gordon, Alan wrote on 01/24/2012 09:15:31 AM:
Dear R users,
I'm a new user to R and have a data set consisting of a number of
variables (in a data frame). I wish to carry out a regression
analysis of the first variable against all the rest in turn. I have
used the following code to do
On 25/01/12 09:45, Sam Steingold wrote:
I get this error from read.table():
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
line 234 did not have 8 elements
The error is genuine (an extra field separator between 1st and 2nd element).
1. is there a way to see
* Duncan Murdoch zheqbpu.qha...@tznvy.pbz [2012-01-24 16:00:14 -0500]:
On 24/01/2012 3:45 PM, Sam Steingold wrote:
I get this error from read.table():
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
line 234 did not have 8 elements
The error is genuine (an
Oh, yeah, a reproducible example:
read.csv from
=
a,b
1,2
3,4
5,,6
7,8
=
I want to be able to extract the data frame
a b
1 1 1
The previous line should be '1 1 2', right?
2 3 4
3 7 8
Have you tried using count.fields to remove the lines
in the file with
It was supposed to be a joke :-(
On 1/24/12 4:15 PM, Gabor Grothendieck wrote:
On Tue, Jan 24, 2012 at 4:07 PM, Carl Witthoftc...@witthoft.com wrote:
Like the t-shirt says, There's no place like 127.0.0.1
quote
Though I wasn't familiar with this I check the repositories list and CRAN
Johannes Radinger wrote on 01/24/2012 10:15:29 AM:
Hello,
I would like to reshape a dataframe into an array. This is kind a
similar task as Excel performs with a Pivot table. To illustrate it:
LOC - factor(c(1,2,2,3,1,1))
SPEC1 - c(0,0,23,0,12,11)
SPEC2 - c(1,2,0,0,0,4)
df -
* William Dunlap jqha...@gvopb.pbz [2012-01-24 21:47:39 +]:
Oh, yeah, a reproducible example:
read.csv from
=
a,b
1,2
3,4
5,,6
7,8
=
I want to be able to extract the data frame
a b
1 1 1
The previous line should be '1 1 2', right?
of course, thanks!
Sorry, this works
www.zdoor.home.xs4all.nl
Thank you,
Alex van der Spek
On 01/24/2012 07:21 PM, Duncan Murdoch wrote:
On 24/01/2012 11:55 AM, Alex van der Spek wrote:
Uploaded the DLL here:
http://www.filefactory.com/file/c2c56ad/n/Planck.dll
I get:
403 Forbidden
Request forbidden by
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