On Sat, Feb 04, 2012 at 08:45:20AM +0100, Marc Girondot wrote:
Hi the list !
I would like to create a dataframe that answer to : all the
combinations of the different way to distribute n indistinguishable
balls into k distinguishable boxes. Let take an example: 2 balls in 3
boxes:
Box1
Hi the list,
I am writing a function in which I need to affect a variable on a higher
level. My fnction could be:
++
fooBis - function(x){
nameObject - deparse(substitute(x))
print(nameObject)
assign(nameObject,4,envir=parent.frame())
}
fooBis(e)
[1] e
e
[1] 4
Hi,
i have used the code below to come out with censored data with real values
but if i want to generate data from
q-rweibull(25,2,4) that involves percent eg 5% or 10% censored i do not
know how to do it.
Can somebody show me how to do it.
Thank you in advance
d -
Le vendredi 03 février 2012 à 18:51 +, William Dunlap a écrit :
Instead of colSums(t(aMatrix)), why not the more
direct rowSums(aMatrix)?
Because I felt it was more didactic. The question was about counting
occurrences per column, so using rowSums() could be a little confusing
without an
Hi David and Rui,
Sorry to be so slow in replying. Thank you both for pointing out that the
problem with my code was that I was using comparison operators on mixed data
types. This is something I'll have to be more careful about in the future.
In an earlier email, David talked about how R can
Dear Eileen,
You apparently misunderstand what the effect() function does; it computes
fitted values and their standard errors under the model (by default in a GLM
on the scale of the response) at specific combinations of values of the
predictors (e.g., letting two interacting predictors range
Hello,
i have used the code below to estimate the parameters of weibull distribution
and i want to obtain the fisher information
by providing the the next code but i receive errors anytime i try to, what do i
do?
by the way is my replication correct and is it placed at the right position for
I think this should be easy to write a function doing this.
Assume that Y is matrix normal with mean matrix mu and row and column
dispersion matrices Sigma and Gamma, respectively.
Isn't Y = AZB + mu, where Z is a matrix of independent N(0, 1)'s, A is
the square root matrix of Sigma (the
is have vector from table stored in s variable
s
[1] R P Y A C P V E S C D R R F S R S A D L T R H I R I
Levels: A C D E F G H I K L M N P Q R S T V Y
--
View this message in context:
Dear list!
I have a problem with eliminate rows with all NA values in matrix of special
class (my.class). Belowe is a example:
#class definition
setClass(my.class, representation(ID=character, years=integer,Â
my.mat=matrix))
data.1 - new(my.class, ID = c(tA, tB, tC), years =
On Sat, Feb 04, 2012 at 06:07:01AM -0800, sagarnikam123 wrote:
is have vector from table stored in s variable
s
[1] R P Y A C P V E S C D R R F S R S A D L T R H I R I
Levels: A C D E F G H I K L M N P Q R S T V Y
Hi.
Is as.character(), what you are looking for?
as.character(s)
[1]
Dear all,
I would like to create a k,n matrix which that will include
- k random elements with value 1
-all rest zeros
-one single 1 in each row
- each column will have maximum one 1
so far I have a so stupid function that with nested while tries to fit k
numbers randomly in a row by row
Hi.
If I understood you correctly here is one approach to your solution:
k - 5
mat - diag(1,nrow=k,ncol=k)
set.seed(10)
samp - mat[sample(1:k,3,rep=FALSE),]
samp
[,1] [,2] [,3] [,4] [,5]
[1,]00100
[2,]01000
[3,]00010
#check
You do not have the path to the R binary set in your operating systems
(obviously Windows, although unstated) PATH environment variable. This
is explained in so many places, including the R Installation and
Administration manual ...
Uwe Ligges
On 03.02.2012 18:25, ql16717 wrote:
Hi,
I
Thanks for the reply. Two things - I must have something missing because
copying and pasting your example gave me an error
... your definitions of nn
Output = do.call(as.data.frame(rbind),nn)
Error in as.data.frame.default(rbind) :
cannot coerce class 'function' into a data.frame
The
On Fri, Feb 3, 2012 at 12:25 PM, ql16717 ql16...@gmail.com wrote:
Hi,
I never acutally made a package before. I have a folder, say called
john that has everything it needs to be in a R package. Some
instruction says I need Rtools from R mirror site. I installed the
Rtools, but under DOS, the
I want to run the glm () function for my data but instead of using the
family distributions in R, I need the 4P Burr distribution.
Can some please explain how can I go about doing that. Or please provide
me with an example.
Im new to R.
Eg.
Model1 - glm(Postwt ~ Prewt + Treat +
On 04.02.2012 15:36, Christopher Kelvin wrote:
Hello,
i have used the code below to estimate the parameters of weibull distribution
and i want to obtain the fisher information
by providing the the next code but i receive errors anytime i try to, what do i
do?
by the way is my replication
On 03.02.2012 13:34, Thomas Mang wrote:
Hi,
Moving to a new computer (Windows 7) but for reasons of reproduceability
I would seriously like to also install my present R 2.8.1 along with all
extension packages on that machine as well (that is besides R 2.14.1).
What's the best way of doing
Hi Group,
I have been working with the code below. Everything seems to work
okay, except that the discrete values on the x-axis are far from each
end of the graph. I've tried several things including changing the
discrete values and playing with the limits, but can't get it to work.
I tested this
Dear all,
I'd like to introduce the paramlink package, offering parametric
linkage analysis in R, as well as other likelihood-based pedigree
analyses.
While a rudimentary version of the package has existed for a while, it
was never properly introduced to this forum. The present version is a
Thomas,
It is a limitation of the function you are using. The method vode is an
implicit method, meaning that it has to create and invert a matrix of the size
= number of variables ^2. In your case, this is a full matrix of 33000 rows and
columns.
If your ODE is easy to solve, you might try to
Hello,
I use the R command
unlink(file, recursive = TRUE, force = TRUE)
to delete folders, subfolders and files on Mac OS X.
When I was running my script on a Windows computer I realised that for
unlink there is no option/parameter force. I do not know why but without
that force option R
Using substitute() and assign(..., envir=parent.frame()) in
fooBis will lead you into a lot of trouble. It is nicer to
use a 'replacement function', whose name ends with '-',
whose last argument is named 'value', and which returns
the modified first argument. They are usually paired with
The Journal of Statistical Software published eight volumes in 2011, five of
them as special volumes.
V38: Special Volume: Competing Risks and Multi-State Models
V39: Regular Volume
V40: Regular Volume
V41: Special Volume: Statistical Software for State Space Methods
V42: Special Volume:
On 04.02.2012 18:13, mails wrote:
Hello,
I use the R command
unlink(file, recursive = TRUE, force = TRUE)
to delete folders, subfolders and files on Mac OS X.
When I was running my script on a Windows computer I realised that for
unlink there is no option/parameter force. I do not know
Okay, so I have a homework projecr for R, and we had to input the following
link as some sort of data:
nb10 - read.table(http://www.adjoint-functors.net/su/web/314/R/NB10;).
Afterwards, we have to use
fivenum(nb10) to find max, min, quantiles, and sd, but I'm okay with this.
The next question
I found something a little different:
median(nb10[,1])
[1] 404
mean(nb10[,1])
[1] 404.59
compare them
They are different. Your sample is not perfectly symmetrical (50% above,
50% below) about the mean (ie. the third standardized moment (skewness) is
not zero). This is really not a
Dear all
I am having a linear system of the form
A*X=B and I want to find the X by using least squares.
For example my A is of dimension [205,3] and my B is of dimension[205,1]
I am looking for the X matrix which is of the size [3,1]. In the matlab I was
doing that by the function
X =
On Feb 4, 2012, at 9:07 AM, sagarnikam123 wrote:
is have vector from table stored in s variable
s
[1] R P Y A C P V E S C D R R F S R S A D L T R H I R I
Levels: A C D E F G H I K L M N P Q R S T V Y
If you want to join two factor vectors you need first coerce to
character vectors, use
On 04-02-2012, at 19:14, Alaios wrote:
Dear all
I am having a linear system of the form
A*X=B and I want to find the X by using least squares.
For example my A is of dimension [205,3] and my B is of dimension[205,1]
I am looking for the X matrix which is of the size [3,1]. In the matlab
Hi Charles,
Thanks for your answer! I am still struggling with two problems with
respect to the example I gave in my message. I have 2 approaches, but each
of them has its limitations, and there are things I cannot do so far with
each of them
1.If I use the following stable command:
Hi,
On Fri, Feb 3, 2012 at 1:12 PM, HC hca...@yahoo.co.in wrote:
Thank you.
The readLines command is working fine and I am able to read 10^6 lines in
one go and write them using the write.table command.
Does this readLines command using a block concept to optimize or goes line
by line?
Hi Aurelien,
You just need to put the \caption outside the scalebox command, like this:
\documentclass[11pt]{report}
\usepackage{rotating}
%\usepackage[counterclockwise]{rotating}
\usepackage{graphics}
\usepackage{float}
\pagestyle{empty}
\begin{document}
\begin{sidewaystable}[ht]
Sorry group didn't realize this got cross-posted on R-help . . .
thought it didn't make it through. Thanks to Justin Haynes for the
solution below and wanted to pass it along.
With a factor you can add:
scale_x_discrete(expand=c(0, 0))
to plot all the way to the edges:
df -
Partha Sinha pnsinh...@gmail.com
Wed Feb 1 07:31:08 CET 2012
Can optimisation (simplex etc) be done through R?
The GLPK mixed-integer library has R language bindings.
I am not sure how up-to-date it is though. Information
is available here:
http://en.wikibooks.org/wiki/GLPK/R
best
Hello,
I am not exactly sure but I think the version which is installed on that
windows computer is 2.13.x
So it looks like that the people who developed that function recently
updated it.
I need to check that on Monday.
Thanks for you answer.
--
View this message in context:
This is reallly not a list for homework help. However I'd guess that you are
supposed to discuss the mean and median, not assault them with R :)
I probably shouldn't do this. :(
Plot the data and then discuss the mean median
John Kane
Kingston ON Canada
-Original Message-
From:
Thank you Jim for your reply.
I could figure out that readLines works fine until 35,841,335 lines
(records).
When the next line is read to be read, a window with R for Windows GUI
front-end has stopped working message comes, with an option to close
program or checking online for a solution.
Hi there!
I have following problem: I created some graphics with win.metafile, which
I wanted to use in a Powerpoint presentation, but when I paste them into
Powerpoint the graphics are missing the axes. It looks like the axes are cut
off and I was wondering, if somebody know this problem and how
I get the same result.
I suspect it has something to do with the fact that month is
is a factor. You would probably be okay if you converted month to a date
format but I don't have time, at the moment, to test it as I always muck up
date conversions and take forever to get them right.
I did
I think you are using the wrong function. See ?strftime
Try
dataset=c(1/2/1978)
strptime(dataset,%d/%m/%Y)
John Kane
Kingston ON Canada
-Original Message-
From: rrast...@gmail.com
Sent: Fri, 3 Feb 2012 14:34:09 +0100
To: r-help@r-project.org
Subject: [R] strftime - Dates from
On Feb 4, 2012, at 5:18 PM, R.newbie wrote:
Hi there!
I have following problem: I created some graphics with
win.metafile, which
I wanted to use in a Powerpoint presentation, but when I paste them
into
Powerpoint the graphics are missing the axes. It looks like the axes
are cut
off and
THANK YOU ! Actually, the key is to disable AWT before loading the R
packages.
At last, it works with just a few warnings.
Julien
On Feb 2, 2012, at 4:36 PM, Zhou Zhou wrote:
The Sys.setenv(NOAWT=TRUE) code indeed solved my problem which was
excatly
what Julien described.
The key is
David
1. The last line of the code should have been ...
Output = as.data.frame(do.call(rbind,nn))
# Output
Node Connect.up Connect.down
11 NULL 2, 3
22 1 4, 5
33 NULL 2, 3
44 1 4, 5
Apologies for any confusion
2.
On 04/02/2012 18:52, mails wrote:
Hello,
I am not exactly sure but I think the version which is installed on that
windows computer is 2.13.x
So it looks like that the people who developed that function recently
updated it.
Not 'recently': it was a new feature in 2.14.0, released last October
i want to select June, July and August data from the 3D array (`ssta_sst`,
360*180*362).
the loop works but the output of ssta_winter has the identical values for
`ssta_winter[,,i]`.seen below. I have set it up as an array of (360,180,29).
I think the problem is the variable `temp`, i want to
Dear folk,
I am stempting to estimate a vector error correction model using a
seemingly fractionally integrated multivariate time series. The
*fracdiff *package
provides tools to estimate degree of fractional integration. But
*fracdiff *can't
help me to:
1. test equality of two degrees of
Hello list!
I am trying to project the fitted surface to a 3d plot of the data,
similar to figures 13.7 or 6.5 in Deepayan Sarkar's Lattice,
Multivariate Data Visualization with R, but replace the contour/map
lines with levelplot. Problem is I can't get the color regions to
line up after the
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