On 02/06/2012 08:23 AM, Henry wrote:
New to R - rookie question.
I'm a mechanical engineer and enjoying using R to make high quality graphs.
I've searched.
I want to put text notation on graph plot areas and have the text background
box white to cover over the grid lines.
my command so
Hi,
I am not sure about your data structure, but if you do not alter those
often from third-party programs, then storing the information in R's native
file formats (like RData) might give you some performance boost against
always querying MySQL. Of course this depends on data structure and
Le jeudi 12 janvier 2012 à 15:18 -0800, plecto a écrit :
Thanks!
I read your shoer term solution and thanks to it was able to make stemming
working in R for Mac OS X.
I actually used Sys.setenv(NOAWT=TRUE) instead of Sys.setenv(NOAWT,
true), as the latter produces the following error
On 05.02.2012 23:17, Matyas Sustik wrote:
Hi Uwe,
1. I don't believe you really need all the flags from above. If so, within a
package, use a Makevars file.
2. R CMD SHLIB QUIC.cpp shoudl do the trick already, perhaps some linker
flags are required for blas that can be specified in the same
On Mon, 6 Feb 2012, James Annan wrote:
I am trying to use lm for a simple linear fit with weights. The results
I get from IDL (which I am more familiar with) seem correct and
intuitive, but the lm function in R gives outputs that seem strange to
me.
Unweighted case:
x-1:4
y-(1:4)^2
Dear all,
I have tried to create a diagonal matrix of size diag(65536)
I am getting the message that the array function can not create so big array as
the value I ask is larger than the
environment: namespace:base
.Machine$integer
[1] 2147483647
as you will see my .Machine$integer is the
On Feb 6, 2012, at 10:57 , Achim Zeileis wrote:
On Mon, 6 Feb 2012, James Annan wrote:
The summary() shows under Residuals the contributions to the objective
function, i.e. sqrt(1/w) (y - x'b) in the notation above.
However, by using the residuals extractor function you can get the
On Feb 6, 2012, at 11:15 , Alaios wrote:
Dear all,
I have tried to create a diagonal matrix of size diag(65536)
I am getting the message that the array function can not create so big array
as the value I ask is larger than the
environment: namespace:base
.Machine$integer
[1]
Dear R-helpers,
I have got a vector which looks like the following:
apkz - c(1,2,3,4,5,6,1,1,2,1,2,3,4)
now I am trying to find a way to automatically create several vectors,
each starting with the number 1, namely:
First vector
1 2 3 4 5 6
Second vector
1
Thrid vector
1 2
Fourth
Hi,
This piece of R code does the trick:
do.call(c, sapply(c(6,1,2,4), seq, from = 1))
regards,
Paul
On 02/06/2012 11:15 AM, Marion Wenty wrote:
Dear R-helpers,
I have got a vector which looks like the following:
apkz - c(1,2,3,4,5,6,1,1,2,1,2,3,4)
now I am trying to find a way to
Hi
Dear R-helpers,
I have got a vector which looks like the following:
apkz - c(1,2,3,4,5,6,1,1,2,1,2,3,4)
now I am trying to find a way to automatically create several vectors,
each starting with the number 1, namely:
First vector
1 2 3 4 5 6
Second vector
1
Some typo in my question below:
I am *attempting* to...not stempting...
Regards
Mamush
-- Forwarded message --
From: mamush bukana mamushbuk...@gmail.com
Date: Sun, Feb 5, 2012 at 12:13 AM
Subject: fractional cointegration
To: r-help@r-project.org
Dear folk,
I am
Hi there,
can somebody give me a guide as to how to generate data from weibull
distribution with censoring
for example, the code below generates only failure data, what do i add to
get the censored data, either right or interval censoring
q-rweibull(100,2,10).
Thank you
Grace Kam
student,
Dear all,
I would like to ask you if it would be possible to install R enterprise in
opensuse.
Actually it seems that there are only Red Hat packages and I was wondering if
their source code is available so one to try and compile it.
I would like to thank you in advance for your reply
Regards
Making sure you have the most recent version of rms, try
require(rms)
dd - datadist(catroj, month); options(datadist='dd')
f - lrm(catroj ~ month)
contrast(f, list(month=2:12), list(month=1), conf.type='simultaneous')
The actual coding will depend on how month is defined. The contrast above
In answer to the several questions:
1. Variance of the random effect: Your example is not reproducable
since you didn't give the random number seed. Instead I'll use one of
the data sets that comes with the survival package.
library(coxme)
fit - coxme(Surv(tstart, tstop, status) ~ treat +
Thanks Bill,
In France, there is a famous joke about politician: Tell me what you need,
I will explain you how to do without... But in my specific case, I can not
use the classical - and [, it is why I ask my question.
More precisely, my fonction fooBis can be very long to end. So I want to
Dear Alex,
By Enterprise R, do you mean Revolution R? I can also only find red hat
packages. You could send them an e-mail to ask for sources. They
probably want to help you, especially when you pay. But why do you need
RevoR and not standard R.
Paul
On 02/06/2012 12:55 PM, Alaios wrote:
Dear
peter dalgaard pdalgd at gmail.com writes:
On Feb 6, 2012, at 11:15 , Alaios wrote:
Dear all,
I have tried to create a diagonal matrix of size diag(65536)
[snip ...]
Well, it means what it says. Indexing is limited by the size of a
32-bit integer and (2^16)^2 is too big for
Thanks for the explanation !
Happy to know there is no problem with my models.
Have a good day,
Arnaud
2012/2/3 Simon Wood s.w...@bath.ac.uk
It is completely safe to ignore this. Here is what is going on...
mgcv routine 'mroot' is calling R routine 'chol' to find the *pivoted*
Choleski
SHAILLY MEHROTRA shaillymehrotra at gmail.com writes:
I am using nlme to fit a pharmacokinetic model. The base model is
parameterized in terms of CL, V1, V2 and Q.
basemodel-nlme(Conc ~TwoCompModel(CL,Q,V1,V2,Time,ID),
data = data2, fixed=list(CL+Q+V1+V2~1),
random = pdDiag(CL+V1+V2~1),
Actually, I would like to speed up matrix multiplication
which is really too slow.
MatrixA %*% MatrixB (each one is a [128,128] table) is running four hours
now... and just imagine that I want to calculate many of those.
Which other alternative do I have?
Regards
Alex
Are you sure?
I just ran
N - 128
system.time(matrix(rnorm(N^2),N) %*% matrix(rnorm(N^2),N))
and it took less than 0.044s on my (old-ish) laptop while doing other
things (and that includes the expensive rng calls). There might be
some other issues in play here. Even N - 1280 takes 5 seconds
On Mon, 6 Feb 2012, Alaios wrote:
Actually, I would like to speed up matrix multiplication which is really
too slow.
I believe that R supports openmp during configuration. This is the
multi-processor library that allows threads to run on different cores or
processors.
In addition to Red
I am looking for R packages that can make a Logistic Regression model
with parameter estimation by Maximum Likelihood Estimation.
Many thanks for helping out.
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
6-02-2012, 06:29 (-0800); Alaios escriu:
Actually, I would like to speed up matrix multiplication
which is really too slow.
MatrixA %*% MatrixB (each one is a [128,128] table) is running four hours
now... and just imagine that I want to calculate many of those.
It doesn't seem normal to
My bad..
these are the real matrices
G-DiagonalGaussian( NumberOfImagePixels,sd=Gsd)
str(G)
num [1:16384, 1:16384] 1400 0 0 0 0 ...
S-PointSamplingMatrix(EffectiveSensors,NumberOfImagePixels)
str(S)
num [1:10650, 1:16384] 0 0 0 0 0 0 0 0 0 0 ...
A-S %*% G
Hi,
On Mon, Feb 6, 2012 at 10:08 AM, Ana rrast...@gmail.com wrote:
I am looking for R packages that can make a Logistic Regression model
with parameter estimation by Maximum Likelihood Estimation.
How are you looking? Did you perhaps try Google
Dear All!!
I am also new in R
and trying to write my results into a file I post here..hopefully is the
proper place
To be more secific I have this loop
counter = 0
for (i in 1:nrow(y))
{
for (j in 1:ncol(y))
{
if (y[i,j]==Func_0005634) {
counter = counter + 1 }
Hi,
I,ve a run a model like this
mcrm-glm(catroj~month,binomial)
being catroj a binary response variable with two levels (infected and
non infected)
anova(mcrm3,test=Chisq)
Df Deviance Resid. Df Resid. Dev P(|Chi|)
NULL 520 149.81
mes 3
Hi everybody, I would like to compare using the Akaike Information Criteria
(AIC) a quadratic model and a piecewise fitted model.
Is it correct to use AIC to compare this models with such a different structure?
Thanks in advance
Angel
# A simple example
a-1
b-2
xx-seq(-15,15,length=50) #
i have two variable
pyar
[1] M 12 34 13
gita
[1] U 22 33 44
want to append gita object below pyar object as
want to take in anther variable
M 12 34 13
U 22 33 44
write it in table fashion inside file
--
View this message in context:
Hi All
I would like to know how to access the values of the variable
lambda.mu and and see what abs(lambdas[1])
does since lambdas is not a keyword.
Snippet of the code:
scoreFunction - function(lambdas)
{
lambda.mu - abs(lambdas[1])
sme.em(yi,tmei,Xi,Ni,G,lambda.mu,lambda.v)$AICc
hi all, i am new to r , i am trying to run data mining algorithms using map
reduce framework.. *
*i have few basic doubts*
*1. can i give file in hdfs to kmeans( ) ? ?I tried as
file1 = hdfs.file(testdata/synthetic_control.data)
isf = hdfs.read(lsf,5242880,0)
l = kmeans(isf,2,10)
its not
Dear professors and collegues
I need to perform a analysis of dates from a nested experimental design.
From
Bioestatical Analysis of Zar
Bimetry of Sokal Rohlf
Design and Analysis of Experiments of Montgomery
I have:
Sum (mean(x)_i - mean(x)_T)2 / (a-1) - var(epsilon) + n sigma2_B + n b
Hello all,
I am wiriting here to look for help!!!
I am running a mixed-model effect lmer() relating the total species richnees
observed in one place with some landscape indicators depending on three
positions at field scale (Boundary, edge, centre) nested to the location
where the survey was
The last model is:
AnovaModel.4 - lmer(VR ~ trat+(1|patient:trat), data=Mesures)
Sorry.
El 06/02/12 13:43, José Trujillo Carmona escribió:
Dear professors and collegues
I need to perform a analysis of dates from a nested experimental design.
From
Bioestatical Analysis of Zar
Bimetry
I am trying to use the optim command to get the MLEs for a number of
parameters based on some data. Is it possible to write a program that
maximizes the likelihood and stores the parameters (many times)? I need to
do this a lot of times, each time the data will be updated with more entries
(rows).
Hi all. I want to generate a sequence of n plots and save them into a single
PDF file, one plot per page. From the R docs and other sources I gather the
basic way to do this is save plot 1 into a file then append the 2:n plots to
the same file.
This code shows my basic approach, but for some
Hi everyone.
I have a vector like this:
x =
c(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2)
I would like to associate a colour to each of these entry. For example, I
could use /topo.colors(3)/ (since I have 3 groups).
I know it is easy to do this with
Hi, I am new to this list.
I have a question regarding including both spatial and temporal random
factors in lmer. These two are not nested, and an example of model I
try to fit is
model1-lmer(Richness~Y+Canopy+Veg_cm+Treatment+(1|Site/Block/Plot)+(1|Year),
family=poisson, REML=FALSE),
where
On Feb 6, 2012, at 10:17 AM, Alaios wrote:
My bad..
these are the real matrices
G-DiagonalGaussian( NumberOfImagePixels,sd=Gsd)
str(G)
num [1:16384, 1:16384] 1400 0 0 0 0 ...
S-PointSamplingMatrix(EffectiveSensors,NumberOfImagePixels)
str(S)
num [1:10650, 1:16384] 0 0 0 0 0 0 0 0 0 0
That was my bad. (doing two things at same time)
I am not out of memory by no means it is just that it only runs at one
core. IF somehow R was able to see the many cores in my system.
Regards
Alex
From: David Winsemius dwinsem...@comcast.net
Cc: R.
On Feb 6, 2012, at 9:40 AM, Filoche wrote:
Hi everyone.
I have a vector like this:
x =
c
(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2
)
I would like to associate a colour to each of these entry. For
example, I
could use /topo.colors(3)/ (since I have 3
On Feb 6, 2012, at 6:29 AM, sagarnikam123 wrote:
i have two variable
pyar
[1] M 12 34 13
gita
[1] U 22 33 44
want to append gita object below pyar object as
want to take in anther variable
You could make a character matrix:
cmat - matrix(c(pyar,gita), nrow=2, byrow=T)
M 12 34 13
On Mon, 6 Feb 2012, Filoche wrote:
Hi everyone.
I have a vector like this:
x =
c(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2)
I would like to associate a colour to each of these entry. For example, I
could use /topo.colors(3)/ (since I have 3 groups).
I
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Alaios
Sent: Monday, February 06, 2012 3:11 AM
To: peter dalgaard
Cc: R-help@r-project.org
Subject: Re: [R] R's memory capabilities
Thanks a lot for your answer :)
actually I
Have you tried Bioconductor (www.bioconductor.org
http://www.bioconductor.org/)? Spencer
On 2/5/2012 10:36 PM, MLSC wrote:
Hi all,
I need your opinion about using R-Rapache to build a knowlegde base to
bioinformatics field.
I have copious amount of genotype information (some few million
The interrupt issue is somewhat orthogonal to the SV4/scoping issue
you asked about. Trying to put things in the callers frame is
very tricky. E.g., SV4 methods can insert new frames between
your code and the caller. Perhaps you could try the following
sort of construct, in which your desired
I love it. I hope you are planning a talk at the UseR!2012 in Nashville.
Do remember the history that one of the origins of punchcards is the
Jaquard loom.
Rich
On Thu, Feb 2, 2012 at 5:54 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
I thought some of you might be amused by this.
In my
Thanks. How do you suggest I use the reference population? Sorry, I'm new
to R and just don't see it. If i can get a plot that is counts or density
relative to my reference data it would be ideal.
On Mon, Feb 6, 2012 at 1:12 AM, David Winsemius dwinsem...@comcast.netwrote:
On Feb 5, 2012,
Doug,
dev.copy2pdf closes the connection after it's done, so onefile is
meaningless. To look at each plot before copy to a single pdf, you
could open a pdf(...) but revert between it and your graphic device:
graphics.off()
plot(1:7, 1:7)
x11c- dev.cur() # your current graphics device
On 02/06/2012 03:08 PM, Ana wrote:
I am looking for R packages that can make a Logistic Regression model
with parameter estimation by Maximum Likelihood Estimation.
Many thanks for helping out.
__
R-help@r-project.org mailing list
On Feb 6, 2012, at 12:23 PM, Francis Keyes wrote:
Thanks. How do you suggest I use the reference population? Sorry,
I'm new to R and just don't see it. If i can get a plot that is
counts or density relative to my reference data it would be ideal.
It is difficult to specify how when we
You can modify the function and add either a print() statement or a
browser() call as make sense for your purposes.
Type the name of the function to get the source: copy and edit it as
desired, and then run something like
funcName - newSource
Now when you run funcName it will run your new
Use the Matrix package which provides easy access to sparse matrices.
I think (unchecked) there's even easy provision for a diagonal sparse
matrix.
That said, if you are always working with diagonal matrices, couldn't
you just keep the diagonals as vectors since the formulas for matrix
hi,
Does factanal() force the user to use the formula interface if they wish to
specify an na.action?
v1 - c(1,1,1,1,1,1,1,1,NA,1,3,3,3,3,3,4,5,6)
v2 - c(1,2,1,1,1,1,2,1,2,1,3,NA,3,3,3,4,6,5)
v3 - c(3,3,3,3,3,1,1,1,1,1,1,1,1,1,1,5,4,6)
v4 - c(3,3,4,NA,3,1,1,2,1,1,1,1,2,NA,1,5,6,4)
v5 -
I think there is some support for multi-processor matrix
multiplication (google around for it) but in your case, it might
suffice to use an optimized BLAS and R's builtin parallel facilities.
As I said in your other thread -- if you are working with
diagonal/sparse matrices, it's also possible to
You don't say how you are writing to a file, but some methods have an
append = TRUE option that might be helpful.
Your code looks really inefficient as well: I don't have time to look
at it fully now, but it seems to me that you can vectorize the inner
loops quite directly:
for(j in ncol(y)){
At 04:06 06/02/2012, Joshua Wiley wrote:
Hi Tom,
I don't believe there is a standard location. You can set variables
or have functions run (say to source other functions in) in your
.Rprofile file. That way, you always have them. Once you get more
than a handful of functions, it is
Hi everyone,
i've been trying to make a special plot with ggplot2, but I can't get it to
fill the polygon I'd like to see filled so very very much.
I want to display the difference or change in the distribution of the
modified Rankin Scale between two groups. mRS is a scale for disability or
Hello,
I have a vector like this:
x =
c(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2)
I would like to associate a colour to each of these entry. For example, I
could use topo.colors(3) (since I have 3 groups).
I know it is easy to do this with if/else
trying to change the locale like this
* Sys.setlocale(Macintosh HD)*
failed with the following error:
*Error in Sys.setlocale(Macintosh HD) : invalid 'category' argument*
--
View this message in context:
http://r.789695.n4.nabble.com/UTF8-tp873280p4361803.html
Sent from the R help mailing
Hi there.
I should have thought about that myself (/shame).
Thank you very much for your time.
Phil
--
View this message in context:
http://r.789695.n4.nabble.com/Colors-vector-based-on-group-tp4361425p4361686.html
Sent from the R help mailing list archive at Nabble.com.
As far as I can see it, those are two problems. The default locale and the
language problem. I have exactly the same, I am using Mac OSX 10.6.8.
I have also tried installation of packages. When installing a package I get
a related error message:
*tar: Failed to set default locale*
if I enter
Hello,
I am trying to estimate a 2-stage selection Model where the first probit stage
is whether the customer bought (0/1) and the second stage is given that the
customer bought, how much did they spend (revenue).
However, in my data, customers are nested within customer service agents and
On Mon, Feb 6, 2012 at 5:14 PM, Richard M. Heiberger r...@temple.edu wrote:
I love it. I hope you are planning a talk at the UseR!2012 in Nashville.
Maybe we'll have hand-woven R-logo lanyards for our conference
badges? Get weaving Sarah!
Barry
__
Dear all,
I am trying to disable the contrast statement in the lme function of the
package nlme. Is there a way to do this? This is needed as I have only
one group.
Thank you so much in advance,
Saskia Freytag
--
Saskia Freytag
Department of Genetic Epidemiology
Georg-August University
On Feb 6, 2012, at 11:26 AM, Norma wrote:
trying to change the locale like this
* Sys.setlocale(Macintosh HD)*
failed with the following error:
*Error in Sys.setlocale(Macintosh HD) : invalid 'category' argument*
You are confused about what the locale setting is used for. They are
for
Hello all,
I would like to plan and analyse a study with k treatments (one of which
is a control), with some binary outcome, in order to find the best
treatment (e.g: the one with a high number of successes).
If this was done with a fixed sample size, the analysis is well known.
However, I would
On Feb 6, 2012, at 11:18 AM, Norma wrote:
As far as I can see it, those are two problems. The default locale
and the
language problem. I have exactly the same, I am using Mac OSX 10.6.8.
I have also tried installation of packages. When installing a
package I get
a related error message:
Hi , everybody
Does R has some package is able genetic based search for optimal decision
tree model
Thanks,
Nissim
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PLEASE
Hi all
For the data below, I would like to return a logical value indicating
differences in the data.
#Create data
Data..-data.frame(a=rep(1,10),b=c(rep(1,9),2),c=c(rep(1,8),2,2))
a b c
1 1 1 1
2 1 1 1
3 1 1 1
4 1 1 1
5 1 1 1
6 1 1 1
7 1 1 1
8 1 1 1
9 1 1 2
10 1 2 2
So what I want
maybe I could keep each line (having the strings)
in a file or somewhere and then
call a print function that prints them all together
from where I saved them?
Please let me know as soon as Possible!!
thank you!
--
View this message in context:
Hello R-users,
I have a data frame whose names of columns I don't know a priori, but the
user of my code will know them. The user is supposed to save the name of the
column that will need some reordering of the levels of the factor later on. The
name of the column will be saved in an object
How bout:
apply(Data..,1, function(vec) !all(vec==vec[1]))
[1] FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE TRUE TRUE
On Mon, Feb 6, 2012 at 10:34 AM, LCOG1 jr...@lcog.org wrote:
Hi all
For the data below, I would like to return a logical value indicating
differences in the data.
Hi Josh,
How about
apply(Data, 1, function(row) sd(row) == 0)
?
Best,
Ista
On Mon, Feb 6, 2012 at 1:34 PM, LCOG1 jr...@lcog.org wrote:
Hi all
For the data below, I would like to return a logical value indicating
differences in the data.
#Create data
Hi Judith,
You should use double brackets, like this:
df[[variab]]-factor(df[[variab]], levels=c(A2B,B31,C33))
see ?[ for details, noting that the help page assumes that you know
data.frames are list-like objects.
Best,
Ista
On Mon, Feb 6, 2012 at 2:03 PM, Judith Flores jur...@yahoo.com
Hey Guys
I want to divide(numerically) all the columns of a data frame by
different numbers. Here is what I am doing but getting a weird error.
The values in each column are not getting divided by the corresponding
value in the denominator vector instead by the alternative values. I
am sure I am
duplicated(Data..)
On Mon, Feb 6, 2012 at 11:34 AM, LCOG1 jr...@lcog.org wrote:
Hi all
For the data below, I would like to return a logical value indicating
differences in the data.
#Create data
Data..-data.frame(a=rep(1,10),b=c(rep(1,9),2),c=c(rep(1,8),2,2))
a b c
1 1 1 1
2 1 1 1
On Feb 6, 2012, at 2:22 PM, Abhishek Pratap wrote:
Hey Guys
I want to divide(numerically) all the columns of a data frame by
different numbers. Here is what I am doing but getting a weird error.
The values in each column are not getting divided by the corresponding
value in the denominator
Thanks Elai, that did it! I never considered using any X11 options, as I'm on
Windows, and in the docs I read it sounded like X11 options only pertained to
the OSX/Linux/.. world. Thanks for your help, Doug
--- On Mon, 2/6/12, ilai ke...@math.montana.edu wrote:
From: ilai
On 06-02-2012, at 20:22, Abhishek Pratap wrote:
Hey Guys
I want to divide(numerically) all the columns of a data frame by
different numbers. Here is what I am doing but getting a weird error.
I don't think you are getting an error.
You are getting an unexpected result (you think).
The
Hey Folks,
I am looking for a R course in New York or Washington DC, please email me any
course announcement you know of for these dates.
Best - Eugene
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Ah. That's the one. Thank you.
-Original Message-
From: Ista Zahn [mailto:istaz...@gmail.com]
Sent: Monday, February 06, 2012 11:12 AM
To: ROLL Josh F
Cc: r-help@r-project.org
Subject: Re: [R] I bet apply has a solution
Hi Josh,
How about
apply(Data, 1, function(row) sd(row) ==
Hi.
I attempted to use RODBC and decided to execute all the tests provided in
Test.r under the unpacked package RODBC folder.
Beginning with the following:
library(RODBC)
library(MASS)
USArrests[1,2] - NA
hills - hills[1:15,]
row.names(hills)[12] - Dollar ('$')
set.seed(1)
# MySQL
## testdb3
Hi all,
Let's say that you have a 3-group categorical predictor x that has the
orthogonal contrasts c1 and c2. I am trying to create a function that,
given x, c1, and c2, creates a normally-distributed y such that c1 and
c2 have effect sizes r1 and r2 specified by the user.
For example, let's
Hello useRs
I am looking for a function that can give the list of lines that were evaluated
or used to generatethe last output from any function, whether an error message
was generated or not. For example, let's say I have a function like this:
foo - function( x ){ if(
6-02-2012, 11:03 (-0800); Judith Flores escriu:
The name of the column will be saved in an object called:
variab
the data frame is called df.
If I try to the do following:
df[variab]-factor(df[variab], levels=c(A2B,B31,C33))
it won't work because df[variab] is a data frame.
I
Hello all,
First I have done extensive searches on this forum and others and nothing
seems to work. So I decided to post thinking someone could point me to the
write post or give me some help.
I have drawn a 100 samples from a fictitious population (N=1000), and then
randomly selected 25% of
On Feb 6, 2012, at 2:51 PM, Doug Hill wrote:
Thanks Elai, that did it! I never considered using any X11 options,
as I'm on Windows, and in the docs I read it sounded like X11
options only pertained to the OSX/Linux/.. world. Thanks for your
help, Doug
You are confused about the
2. It's more flexible to construct the language object as a language object,
rather than pasting something together and parsing it. For one thing, that
allows non-syntactic variable names; I think it's also easier to read. So
your code
txt- paste(tabular(value*v*, LEFT , ~ ,RIGHT ,, data =
Hi,
I am running a MacBook Pro with OS X 10.6.8. When I try to load library(cem)
and run any function, R crashes. Any suggestions as to why this is? Thanks in
advance. I think the problem is that I don't have all the infrastructure I
need to run CEM, but I have no clue what to do either...
On Mon, Feb 06, 2012 at 12:29:53PM -0800, RKinzer wrote:
Hello all,
First I have done extensive searches on this forum and others and nothing
seems to work. So I decided to post thinking someone could point me to the
write post or give me some help.
I have drawn a 100 samples from a
Thank for your answer.
Problem solved.
Regards,
Phil
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Hi,
Why do you need to merge them? c.one contains what I think you want,
and then you want to randomly select 25 rows from that without replacement:
c.one - cbind(c.one, a.qtr = sample(c(rep(TRUE, 25), rep(FALSE, 75
head(c.one)
unique length age a.qtr
649649 71 4 TRUE
200
Hi everyone.
I have have a dataset with daily measurement from January 1st of 1966 up to
December 31th of 2011.
Here's the first part of the data:
DateSLEV
1/1/19661.086
1/2/19661.079
1/3/19661.133
1/4/19661.261
1/5/19661.391
1/6/19661.571
The documentation doesn't say what you think it says:
The value of argument ‘frequency’ is used when the series is
sampled an integral number of times in each unit time interval.
For example, one could use a value of ‘7’ for ‘frequency’ when the
data are sampled daily, and the
Hi David,
I have 2 tables, each with several columns and rows of data. I am
only interested in the data from column 6, which contains values in
the range -PI to PI. I want to plot the data from tableD with the y
axis denoting percentage with respect to tableR. So if data points in
the break 2
Saskia Freytag saskia.freytag at med.uni-goettingen.de writes:
I am trying to disable the contrast statement in the lme function of the
package nlme. Is there a way to do this? This is needed as I have only
one group.
Can you be more specific please? My first interpretation of this
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