On 02/16/2012 10:39 PM, Hey, Kirsty wrote:
Dear all,
I am wanting to plot points that have a defined absolute size relative
to the scale of the axis.
For example, the following gives me a plot with sizes relative to the
defined size variable but are not of the specified absolute size
(relative
On 17/02/2012 05:39, R. Michael Weylandt wrote:
Looks like its in the CRAN archives here --
http://cran.r-project.org/src/contrib/Archive/rimage/ -- then the
steps for doing a source install are well documented (and easily
googleable) but (unstated) OS specific.
Yes, but the package was
On Thu, 16-Feb-2012 at 07:30AM +, Prof Brian Ripley wrote:
| Try read.S in package foreign. It was written back in the days of
| that S-PLUS format.
Great. Knows all about big-endian and does exactly what I needed very
simply. All that time I've known about the foreign package and never
Hi
My data looks like this
data is a vector
data=var1 var2 var3
100 120 130
i want to put it in an XML
xmlOutput=NULL
xmlOutput- newXMLNode(results)
for( i in 1 : length(data))
{
newXMLNode(variable,attrs=c(name =names(data)[i] ), value =
data[i]), parent =
Hi Alex,
I cannot say how to implement such constraints with fPortfolio, but in
general you can use heuristics to solve such problems. An example for
selecting a number of assets from a larger universe is given in a
vignette of the NMOF package (of which I am the author) and in the code
On 02/17/2012 06:42 AM, Jordan Patricia Sinclair wrote:
Hello all.
I need to graph multiple lines of different lengths on the same graph. When I
try to add lines I get an error due to different lengths. The only thing I
could find when reading up on it was that 'if the data are inputted
Hi,
Is there any function available to do stepwise selection of variables in
Conditional(matched) logistic regression( clogit)? step, stepwise etc are
failing in case of conditional logistic regression. Please help.
Thanks
P.T. Subha
[[alternative HTML version deleted]]
On Wed, Feb 15, 2012 at 08:12:32PM -0500, Gabor Grothendieck wrote:
On Tue, Feb 14, 2012 at 11:17 PM, Redding, Matthew
matthew.redd...@deedi.qld.gov.au wrote:
I've been trawling through the documentation and listserv archives on this
topic -- but
as yet have not found a solution. I'm
Thanks it worked
-
Thanks in Advance
Arun
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Hello,
Let us convert a vector to a time series object starting in 1978Q1:
FRW-ts(FRW0, frequency=4, start=c(1978,1))
FRW[3:6] represents the data from 1978Q3 to 1979Q2. Could we access the
data by the time (1978Q3 to 1979Q2) instead of FRW[3:6]?
Thanks,
miao
[[alternative
Dear expert,
Given such data:
#Cutpoint SN (1-PPV)
5 0.560.01
7 0.780.19
9 0.910.58
How can I plot ROC curve with R that produce similar result like the
attached file?
I know ROCR package but it doesn't take such input.
- GV
Hi everyone / poLCA gurus,
I'm facing a problem regarding conditional dependence and poLCA.
Using a few data sets composed of only 1's and 2's, i'm able to do a latent
class analysis for independent data columns using poLCA.
The commands I use to do this are something like,
bcs =
Hi, Micheal,
Are you talking about the recode for eliminating \ problem?
I think I am looking for how to eliminate it when I import the data file...
THAnks.
VD.
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Hello, I'm struggling with understanding the output on the ancestral.pars()
command from the phangorn package, I'm new to doing phylogenetic analyses
using R.
I used it on nucleotide data, and it works fine, I'm just not sure how to
read the output.
The output is phyDat class, and outputs a
Dear List,
I will appreciate any advice regarding how to convert the following numbers
[I got in return by taxondive()] in numeric integers without the e.g.
6.4836e+01
abbreviations.
Thank you very much in advance,
Gian
taxa_dive
Species Delta Delta* Lambda+
Please ask your Netezza support. I now they are proud on their R support
and will certainly help.
Uwe Ligges
On 16.02.2012 00:36, rusernetezza wrote:
We've recently installed a Netezza server and I am trying to integrate the R
GUI with this server and run functions using the server itself.
On 02/16/2012 01:35 AM, agent dunham wrote:
Dear community,
I've plotted data and coloured depending on the factor variable v3.
In the legend, I'd like to assign properly the same colors than in the
factor (the factor has 5 levels).
I've been trying this but it doesn't work.
plot(var1,
On 16-02-2012, at 09:01, Petr Savicky wrote:
Hi.
There were several solutions in this thread. Their speed differs
quite significantly. Here is a comparison.
patrn - 1:4
exmpl - sample(1:4, 1, replace=TRUE)
occur1 - function(patrn, exmpl)
{
m - length(patrn)
n -
On 16.02.2012 01:42, Duncan Murdoch wrote:
On 12-02-15 5:26 PM, wpcmba wrote:
Issue: Connecting to a computer in a network.
I would like to connect to a file on a computer on my internal network
that
has a different password. I have tried download.file and read.csv to no
avail.
When use
On Thu, Feb 16, 2012 at 10:17:09AM +0100, Gian Maria Niccolò Benucci wrote:
Dear List,
I will appreciate any advice regarding how to convert the following numbers
[I got in return by taxondive()] in numeric integers without the e.g.
6.4836e+01
abbreviations.
Thank you very much in advance,
Hi
We've found that when using parse_args(..., positional_arguments=FALSE), it
is permissible to invoke our script with either --myfoo=bar or --myfoo
bar; that is, whether or not the equals sign is present makes no
difference, and in fact both usage forms are demonstrated in the optparse
On 02/16/2012 05:22 AM, Colin Wahl wrote:
Thank you,
Its looking like your package will work for me. I have two questions.
First, how do I rotate the plot 90 degrees so the group labels are on
the x axis and the response value on the y axis?
Second, I'm having trouble with the group labels. I
ACM Software Copyright and License Agreement
I have often seen the use of routines from the ACM Collected Algorithms, i.e.
netlib.org/toms/ (CALGO, or Trans. On Math. Software, TOMS), in Open Source
programs, maybe also in some R packages --- and sometimes these programs are
distributed under the
Hello people,
I have got a question concerning reading spss files into R:
I used the package foreign and the following command:
read.spss(C:/Eigene Dateien/myspssfile.sav,to.data.frame=T)
I have read two different files into R (several times) and always got the
following two warning messages:
On 02/16/2012 08:08 AM, jpm miao wrote:
FRW-ts(FRW0, frequency=4, start=c(1978,1))
Please make your example reproducible, we do not have FRW0.
cheers,
Paul
--
Paul Hiemstra, Ph.D.
Global Climate Division
Royal Netherlands Meteorological Institute (KNMI)
Wilhelminalaan 10 | 3732 GK | De Bilt |
Hi Mj,
did you get a solution for this? I am having the same error
Error in odbcUpdate(channel, query, mydata, coldata[m, ], test = test, :
missing columns in 'data'
I would appreciate if you can share the solution with me.
Kind regards,
Taby
From:
Hi vd,
The answer to the first part of your question is reorder. To continue the
learnr example:
df.m - transform(df.m, Period = reorder(Period, -1*value))
ggplot(df.m, aes(x = Period, y = value/1e+06, fill = Region)) +
geom_bar(stat = identity, position = stack)
For the second question:
Hello Rolf,
thank you for your advice!
Though, I find there is no need to get personal about my stage of
devolopment in R.
Cheers,
Marion
2012/2/15 Rolf Turner rolf.tur...@xtra.co.nz
On 16/02/12 03:59, Marion Wenty wrote:
SNIP
Thank you for your answers!
Jeff, thanks very much for
Hi,
On Wednesday, February 15, 2012 08:02:44 AM Nerak wrote:
Hi all,
I was wondering if there is a function kind of similar that splits a
dataframe, applies a function to each row and returns in a data frame. I
know ddply but this one isn’t useful in this situation.
Why not? Sounds like a
On 12-02-15 11:58 PM, Ben quant wrote:
Thank you Duncan. Interesting. I find it strange that you can't get a list
of the environments. But I'll deal with it...
I'd advise thinking really carefully about this, because I think it
indicates you've got a mental model of R internals that isn't a
2012/2/15 gab gis...@libero.it
Errore in scale(newdata[, object$scaled, drop = FALSE], center =
object$x.scale$scaled:center, :
(subscript) indice logicol troppo lungo
I'm pretty sure the problem is with your data frame. Maybe if you share the
result of
dput(training[1:10, ])
# (make sure
Hello,
I'm working with a series (30+) of hydrologic metrics and 10 vegetation
communities and I need to determine which of the metrics provide the best
separability for each of the vegetation communities. The hydrologic
metrics are highly correlated, therefore the need to reduce the number
Dear Steve,
It's not obvious to me what you want to do. If you want ellipsoids for
MeanAnnualDepth, Hydroperiod, and MedianWet, which sound as if they are
numeric variables, separately for each VegtypeID, which is presumably a
factor with several sets of measurements for each value, then
?window may help.
Michael
On Thu, Feb 16, 2012 at 3:08 AM, jpm miao miao...@gmail.com wrote:
Hello,
Let us convert a vector to a time series object starting in 1978Q1:
FRW-ts(FRW0, frequency=4, start=c(1978,1))
FRW[3:6] represents the data from 1978Q3 to 1979Q2. Could we access the
John,
I would like ellipsoids to represent the distributions relative to each of
the vegetation types.
I tried your approach thinking that it would work as well, but I'm getting
an error
scatter3d(MADep2004 ~ Dhydro2004 + MedWet2004 | VegtypeID, ellipsoid=TRUE.
data= CSSS)
Error in sprintf
No I'm talking about changing the order (the first part of your
question). What you see as dates on the axis aren't actually Dates
(in the sense of the R class of that name) but rather factors. To R
they are just labelled categories so it just uses an arbitrary order
to plot them: if you
After one month of struggle, I lost confidence on Spotfire, it's totally
not user-friendly. Yes it is very good for certain data presentation, but
you still need do heavy lifting on data processing by other software. For
me, R is the perfect tool and has best user supporting group. I send this
On 16-02-2012, at 12:31, Hans W Borchers wrote:
ACM Software Copyright and License Agreement
I have often seen the use of routines from the ACM Collected Algorithms, i.e.
netlib.org/toms/ (CALGO, or Trans. On Math. Software, TOMS), in Open Source
programs, maybe also in some R packages
I
Dear Steve,
I'm very busy this morning, so will reply briefly: the error message is
self-explanatory (though the error message itself has an error in it, which
prevented the numbers from being printed as intended): you have to define
more colours -- one for each level of VegtypeID; if you want to
Achim Zeileis-4 wrote
The reason for the various approaches is that efp() was always confined to
the linear model and gefp() then extended it to arbitrary estimating
function-based models. And for the linear model this provides the option
of treating the variance of a nuisance
On Feb 16, 2012, at 12:31 , Hans W Borchers wrote:
ACM Software Copyright and License Agreement
I have often seen the use of routines from the ACM Collected Algorithms, i.e.
netlib.org/toms/ (CALGO, or Trans. On Math. Software, TOMS), in Open Source
programs, maybe also in some R packages
On Thu, 16 Feb 2012, buehlerman wrote:
Achim Zeileis-4 wrote
The reason for the various approaches is that efp() was always confined to
the linear model and gefp() then extended it to arbitrary estimating
function-based models. And for the linear model this provides the option
of treating
I'm thoroughly stumped. I've been playing with RODBC and wanted to see if I
could retrieve data from text files using this package as well (for the most
part, this is an intellectual exercise, but occasionally I do get data files
large enough in CSV format RODBC could be helpful) .
I set up a
Hi Petr,
You advice options(scipen=20) gave me the expected result and fix the
problem.
Thanks a lot!
Gian
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PLEASE do read
Am just feeling my way into the grid library, and cannot figure out how to
define the plot limits. 3/5 of the example polygons below plot in the
default 0-1 range viewport. But when I try to redefine the viewport the
polygons plot in the same places. I also get the same result without
employing
Hi David,
What an good solution. It works perfectly and it's really simple.
(I only removed the 1+ in ncol=1+max(j), it already has 6 columns)
My result has been:
df - read.table(file=df.txt, head=T, sep=\t)
df
i j k
1 1 2 5.2
2 1 3 9.1
3 1 4 8.0
4 1 5 2.3
5 1 6 8.4
6 2 3 6.6
7 2
Hi Michael,
Your answer was very interesting, thank you!
However, I tried it and the result was:
df - read.table(file=df.txt, head=T, sep=\t)
df
i j k
1 1 2 5.2
2 1 3 9.1
3 1 4 8.0
4 1 5 2.3
5 1 6 8.4
6 2 3 6.6
7 2 4 7.4
8 2 5 7.1
9 2 6 5.5
10 3 4 4.1
11 3 5 3.9
12 3 6 9.2
13 4 5
Hi Rui,
Thank you very much for your idea. It works!!!
I converted my dataframe into a vector (I first removed the header and the
first and second column) and then tried your solution:
data - as.vector(as.matrix(read.table(file=data.txt, head=F,
sep=\t)[-c(1,2)]))
data
[1] 5.2 9.1 8.0 2.3
Problem solved.
Many many thanks for your ideas!!
(this site is very stimulant) :)
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Hi again,
I just realized that in this solution there is something funny on the
position the values in the matrix, they don't really correspond to the
position indicated in the subscripts... However, David Winsemius has given a
valid solution.
Thank you for all your ideas!
--
View this message
Dear all,
I am wanting to plot points that have a defined absolute size relative
to the scale of the axis.
For example, the following gives me a plot with sizes relative to the
defined size variable but are not of the specified absolute size
(relative to the axis)
coords -
I figured it out:
you have to pass the mar-argument to the plot function and than you may
position the legend via inset.
Have a nice day!
From: David Zastrau
Sent: Thursday, February 16, 2012 12:50 PM
To: r-help@R-project.org
Subject: Legend vanishes when placed outside the graph
Hello
Hello everyone,
iâve got a problem with my diagramâs legend. I know i should be able to
figure it out by reading the âplotâ and âlegendâ reference. However
nothing works so it would be kind if anyone could point me to the necessary
parameters.
The problem is that iâm moving the
hi,
I have a question regarding cp values in rpart(). When I use plotcp() I get
a figure with cp values on the x-axsis, but then I use printcp() the cp
values in that list are different from the values in the figure by
plotcp(). Does someone know why?
Silje
[[alternative HTML version
Dear R-users,
How can I extract the weighting values (w-values) for each feature from a
rvm-object of the kernlab package?
I can access the relevance vectors but how can I get the weighting values of
each feature?
example code:
# create data
x1 - rnorm(401,sd=1.10)
x2 - rnorm(401,sd=1.10)
x3
Dear R experts,
I am having difficulty using loops productively and would like to please
ask for advice. I have a dataframe of ids and groups. I would like to
break down the dataframe into groups, find the unique sets of ids, then
reassemble. My thought was to use a loop, but I have been unable
Dear r-helpers,
I read a .csv file into R
with the following command:
A-read.csv2(file=Mappe3.csv)
It worked fine, except that I would like to get rid of the points between
the words and get spaces instead like I have got in the .csv file.
At the moment it looks like the following:
Hello everybody!
I have again another newbie-question. I was trying to plot three curves
within one single
plot: Crime development (relative frequencies) according to the hours of tv
consume per week (high/low/all together).
Here are the data:
par(mfrow=c(1,1))
# Data input
check.names=FALSE
but it's discouraged because it will make it hard to refer to column
names inside R.
Michael
On Thu, Feb 16, 2012 at 11:18 AM, Marion Wenty marion.we...@gmail.com wrote:
Dear r-helpers,
I read a .csv file into R
with the following command:
A-read.csv2(file=Mappe3.csv)
Is this close to what you want:
example - data.frame(id=rep(
+ ( abs(round(rnorm(50,mean=500,sd=250),digits=0)))
+ ,3), group=rep(1:15,10))
example -example[with(example,order(id,group)),]
uniqueIDs - do.call(rbind
+ , lapply(split(example, example$group), function(.grp){
+
If you want a row for each unique item:
example - data.frame(id=rep(
+ ( abs(round(rnorm(50,mean=500,sd=250),digits=0)))
+ ,3), group=rep(1:15,10))
example -example[with(example,order(id,group)),]
uniqueIDs - do.call(rbind
+ , lapply(split(example, example$group), function(.grp){
+
David, thanks for the tips, though, I tried these arguments but it didn'
work.
Michael, thanks for your advice which worked, so far. I am using my object
to create a barplot afterwards, which automatically puts the colnames
besides the bars. Maybe this is still a good solution for my purpose as I
If you don't need to refer to colnames you should be fine.
If you do need to subset by colnames, you can still do it with `[`,
but you'll have trouble if you want to use the $ trick, unless you use
back-ticks. Don't worry about these things if they aren't troubling
you now though.
Michael
On
Dear All,
I am pretty new to R and thus my question may sound silly.
Is there a way to automatically generate a series of separate vectors
(so not arranged in a matrix), without typing and changing every time
the values, and store them as separate *xlsx file, where the * is
replaced by the
hello mailing list!
i still consider myself an R beginner, so please bear with me if my
questions seems strange.
i'm in the field of biology, and have done consecutive hydraulic
conductivity measurements in three parallels (Sample), resulting in three
sets of conductivity values (PLC for percent
Dear R users
I'd like to hear from someone if there is a function to do a repeated k-fold
cross-validation for a lm object and get the predicted values for every
observation. The situation is as follows:
I had a data set composed by 174 observations from which I sampled randomly
a subset composed
Hello,
I'm glad it helped.
The difference in the ordering is due to the fact that R defaults to
column-first ordering.
David's solution uses row-first (which is what you wanted).
Rui Barradas
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View this message in context:
Hello,
I read a .csv file into R
with the following command:
A-read.csv2(file=Mappe3.csv)
It worked fine, except that I would like to get rid of the points between
the words and get spaces instead like I have got in the .csv file.
Try
gsub('\\.', ' ', A)
(And see ?regexpr and
Read the Details section in ?viewport carefully. You are treating
xscale/yscale as if they are xlim/ylim in base graphics. They are not.
It may take some trial and error on your part to figure out how
exactly this works, in general you are setting the size and location
of each polygon relative to
On Thu, Feb 16, 2012 at 10:12 AM, Nutter, Benjamin nutt...@ccf.org wrote:
I'm thoroughly stumped. I've been playing with RODBC and wanted to see if I
could retrieve data from text files using this package as well (for the most
part, this is an intellectual exercise, but occasionally I do get
Dear list,
Let's say I have data
a=c(37.961,38.214,57.68)
b=c(77.56,61.875,67.683)
wilcox.test(a,b)
the wilcoxon test only gives me a p value with one decimal place. Is this
normal? Thanks.
Jun
[[alternative HTML version deleted]]
__
Hey,
You could also use (after initializing x):
x[lower.tri(x)] - data$k
x - t(x)
Cheers,
Tsjerk
On Feb 16, 2012 6:59 PM, Rui Barradas rui1...@sapo.pt wrote:
Hello,
I'm glad it helped.
The difference in the ordering is due to the fact that R defaults to
column-first ordering.
David's
On Thu, Feb 16, 2012 at 10:15 AM, Jun Shen jun.shen...@gmail.com wrote:
Dear list,
Let's say I have data
a=c(37.961,38.214,57.68)
b=c(77.56,61.875,67.683)
wilcox.test(a,b)
the wilcoxon test only gives me a p value with one decimal place. Is this
normal?
No, it's discrete :-)
On 16-Feb-2012 Bert Gunter wrote:
On Thu, Feb 16, 2012 at 10:15 AM, Jun Shen jun.shen...@gmail.com wrote:
Dear list,
Let's say I have data
_a=c(37.961,38.214,57.68)
_b=c(77.56,61.875,67.683)
the wilcoxon test only gives me a p value with one decimal place. Is this
normal?
No, it's
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Jun Shen
Sent: Thursday, February 16, 2012 10:16 AM
To: R-help
Subject: [R] Wilcoxon test p value with one decimal place
Dear list,
Let's say I have data
The default units of polygonGrob are npc, I think you want native instead.
Try the following,
library(grid)
d = data.frame(x=rnorm(100, 10), y=rnorm(100, -100))
v = dataViewport(xData=d$x, yData=d$y)
grid.points(d$x,d$y, default.units=native, vp=v)
HTH,
b.
On 17 February 2012 02:47,
I think this is what you are getting at. Hope this helps.
#index data to determine what low and high levels of tvHrs are (I said
anything over 15 hours is considered 'high')
index=which(tvHrs 15)
#Plot the first plot, which is the 'high', only using values from crimeDvp
that are in 'index'
Hello all.
I need to graph multiple lines of different lengths on the same graph. When I
try to add lines I get an error due to different lengths. The only thing I
could find when reading up on it was that 'if the data are inputted separately
they must be of the same length'.
Could someone
VictorDelgado wrote
gsa - function(m, n, preference.row, preference.col, first)
{
# m: number of rows (men)
# n: number of columns (women)
# first 1 for row (men); and 2 for column (women)
#
# Two Auxiliary functions:
# 1:
min.n - function(x,n,value=TRUE){
s - sort(x,
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
On Thu, Feb 16, 2012 at 12:42 PM, Jordan Patricia Sinclair
al8...@wayne.edu wrote:
Hello all.
I need to graph multiple lines of different lengths on
On 16-02-2012, at 12:31, Hans W Borchers wrote:
ACM Software Copyright and License Agreement
I have often seen the use of routines from the ACM Collected Algorithms, i.e.
netlib.org/toms/ (CALGO, or Trans. On Math. Software, TOMS), in Open Source
programs, maybe also in some R packages ---
To whom it may concern:
Please take my off the mailing list for R related emails. Thanks.
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PLEASE do read the posting guide
On Feb 16, 2012, at 3:53 AM, Gundala Viswanath wrote:
Dear expert,
Given such data:
#Cutpoint SN (1-PPV)
5 0.560.01
7 0.780.19
9 0.910.58
How can I plot ROC curve with R that produce similar result like the
attached file?
I know ROCR package but it
On Thu, Feb 16, 2012 at 05:32:15PM +0100, Nino Pierantonio wrote:
Dear All,
I am pretty new to R and thus my question may sound silly.
Is there a way to automatically generate a series of separate vectors
(so not arranged in a matrix), without typing and changing every time
the values,
Ah, yes. If you can't find the answer to your question, ask a different
question!
sqldf does, indeed, do what I want. Thank you
Benjamin Nutter | Biostatistician | Quantitative Health Sciences
Cleveland Clinic | 9500 Euclid Ave. | Cleveland, OH 44195 | (216)
445-1365
I didn't think through mine all the way -- you do need the cbind()
call to do the indexing like I was thinking -- so mine when corrected
just turns into David's.
Michael
On Thu, Feb 16, 2012 at 5:26 AM, nymphita
sandrablazquezcabr...@gmail.com wrote:
Hi Michael,
Your answer was very
Also look at the zapsmall function. A useful but often overlooked tool.
On Thu, Feb 16, 2012 at 2:54 AM, Petr Savicky savi...@cs.cas.cz wrote:
On Thu, Feb 16, 2012 at 10:17:09AM +0100, Gian Maria Niccolò Benucci wrote:
Dear List,
I will appreciate any advice regarding how to convert the
On Feb 16, 2012, at 6:50 AM, David Zastrau wrote:
Hello everyone,
i’ve got a problem with my diagram’s legend. I know i should be able
to figure it out by reading the ‘plot’ and ‘legend’ reference.
However nothing works so it would be kind if anyone could point me
to the necessary
# All days in years 2006 to 2009 by month in 48 (12x4) files.
days - seq(as.Date(2006/1/1), as.Date(2009/12/31),by=day) # one
long vector
out - paste(rep(format(days,'%d%m%y'),each=2),c('aaa','bbb'),sep='_')
# reformat to style
month - factor(rep(format(days,'%B%y'),each=2)) # group by
On Feb 16, 2012, at 11:43 AM, protoplast wrote:
hello mailing list!
i still consider myself an R beginner, so please bear with me if my
questions seems strange.
i'm in the field of biology, and have done consecutive hydraulic
conductivity measurements in three parallels (Sample), resulting
Hi Taby,
i could not work out how to add to a table, so what i did was to kill
the old one and write a new one --
here is a snippet of my code:
# delete the old table
sqlDrop(con, sqtable=__mytable__) # note this will hang if the table
cannot be found
# insert the new table
On Feb 16, 2012, at 2:42 PM, Jordan Patricia Sinclair wrote:
Hello all.
I need to graph multiple lines of different lengths on the same graph.
?segments
When I try to add lines I get an error due to different lengths.
The only thing I could find when reading up on it was that 'if the
Folks,
I want to automate some graphing using ggplot.
Here is my code
graphChargeOffs2-function(coffs) {
ggplot(coffs, aes(levels))
dataNames-names(coffs)[!names(coffs) == levels]
for(i in dataNames) {
thisData-coffs[[i]]
last_plot() + geom_line(aes(y = thisData, colour = i))
}
It's been a long time since this topic was posted, but I recently had
occasion to use stats::reshape again. This time, I looked closer at the
code for the function so I could understand what was going on.
I now realize that if the argument varying is a vector of names (as I
had) rather than a
ggplot is looking for thisData as a column of coffs. the most
'ggplotesque' way of doing this would be:
# melt your data to a long format:
coffs.melt - melt(coffs, id.vars = 'levels')
# plot using colour aes parameter:
ggplot(coffs.melt, aes(x=levels, y=value, colour=variable)) + geom_line() +
Newbie question - mechanical engineer trying to learn R
I've had success with plotting time series data and even made a heat map
using R Graphs Cookbook by Mittal.
I have a new problem - I need to align a number of time series data
columns to the desired regular exact time stamp vector. The target
Please see my question from a few minutes ago - I wanted to improve the
title.
--
View this message in context:
http://r.789695.n4.nabble.com/time-series-interpolation-zoo-approx-spline-what-to-use-tp4395975p4395975.html
Sent from the R help mailing list archive at Nabble.com.
Sir,
On 16 February 2012 16:55, Henry hcco...@lbl.gov wrote:
Please see my question from a few minutes ago - I wanted to improve the
title.
xts über alles -- H
--
Sent from my mobile device
Envoyait de mon portable
__
R-help@r-project.org mailing
Thank you very much for your reply. The command window does help.
a1-11:22 a1ts-ts(a1, frequency=4, start=c(1978,1)) a1tsw-window(a1ts,
c(1978,3), c(1979,2) ) a1tsw Qtr1 Qtr2 Qtr3 Qtr4
1978 13 14
1979 15 16 a1tsw[2:3][1] 14 15
2012/2/16 R. Michael Weylandt
On Thu, Feb 16, 2012 at 7:31 PM, Henry hcco...@lbl.gov wrote:
Newbie question - mechanical engineer trying to learn R
I've had success with plotting time series data and even made a heat map
using R Graphs Cookbook by Mittal.
I have a new problem - I need to align a number of time series data
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