On 04/05/2012 00:43, William Dunlap wrote:
class(10)
[1] numeric
class(10L)
[1] integer
class(10i)
[1] complex
Why not 10I for integer? Perhaps because I and l
look too similar, perhaps because i and I sound
too similar. The L does not mean long: integers
are 4 bytes
If i am not mistaking the quantile function and percentile function and the
same other than the way they are expressed in R. I think where I am losing
it is just how to express the function.
myvec- c(5,4,3,2,1,10,9,8,7,6)
PercentileFinder- function (vec,p){
sortedlist- sort(vec)
count-
If a run a LOESS model and then produce a smoothed surface: Is there any
way to determine the coordinates of the local maxima on the surface?
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Dear R gurus,
I am trying to overload some operators in order to let these work with the
ff package by registering the S3 objects from the ff package and
overloading the operators as shown below in a reproducible example where
the * operator is overloaded.
require(ff)
Hello,
I have a vector wherein the cases are either uniform or mixed-strings (so
AAA vs ABABABABA). Different parts of the vector apply to
different users, so [1:29] is one guy, [30:50] is another, and [51:70] is
another. There are about
100,000 users, and I have an object that
Thanks for that - too bad there isn't a simple workaround!
greetings
Remko
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Sent from the R help mailing list archive at Nabble.com.
Hello,
Hui Du wrote
Hi All,
Suppose I have the following codes:
x = data.frame(A = rnorm(20), B = rnorm(20), C = rnorm(20))
a = list()
a[[1.1]] = x
a[[1.2]] = x
b = list()
b[[1.1]] = c(A, B)
b[[1.2]] = c(B, C)
Now I want to apply b to a like this, for each element of 'a',
Hi,
I am working on a capacity planning task for a socket server. As
part of the research I read Quickly Generating Billion-Record
Synthetic Databases which is about benchmarking databases. I understand
from that paper that there are specific datasets with statistics
properties that can
Dear all,
I open a bmp device by the bmp() function in the png package, but I
don't know how to write color pixel by pixel into the file? Any help or hint?
What I want to do is to create a 512*512 bmp file with certain dots
being red and others black. I have all the pixel
Hi,
For some reason I have been unable to use the predict function when I
desire the standard error to be calculated too. For example, when I try
the following:
l- loess(d~x+y, span=span, se=TRUE)
p- predict(l, se=TRUE)
I get the following error message:
Error in vector(double, length) :
Dear R users,
I am applying the augmented-Dickey-Fuller Unit Root Test
(ur.df function of the urca package) to a time series of
approximately 50 values.
To be sure I understood what was going on with the ur.df
function, I checked the critical values of the 3 test
statistics (tau, phi2 and phi3
Hi,
I have a tab seperated file with 206 rows and 30 columns.
I read in the file into R using read.table() function. I checked the dim()
of the data frame created in R, it had only 103 rows (exactly half), 30
columns. Then I tried reading in the file using read.delim() function and
this time the
This is correct , now working. I did not have the preceeding comma in
Data2[,i] . . .
Thanks very much! Very much appreciated. Ben Neal
-Original Message-
From: Peter Ehlers [mailto:ehl...@ucalgary.ca]
Sent: Thu 5/3/2012 3:04 PM
To: Ben Neal
Cc: Jim Lemon; r-help@r-project.org
Subject:
(1) There's something funny about the data that you present below.
At least in my mailer (Thunderbird) what looks like a space between
the X and Y values turns into a NULL character when I try to copy
and paste.
(2) Create a data frame, say M with the X and Y values as given
in your email.
(3)
Dear Experienced R Practitioners,
I have 4GB .txt data called dataset.txt and have attempted to use *ff,
bigmemory, filehash and sqldf *packages to import it, but have had no
success. The readLines output of this data is:
readLines(dataset.txt,n=20)
[1]
Dear All,
I am using the LIMMA package to create 2 contrasts for my data and then
calculating the vennCounts of the decideTests from the contrast.fit to be able
to create venn Diagrams.
The code works fine but the summary(results) shows zeros for all i.e. no gene
were up regulated or
Hello,
In zoo package, if I would like the time frame to be 1981M01 to 1982M12,
then I code
time_0-as.yearmon(1981-01)+(0:23)/12
However, if the time frame of interest becomes 1981M01 to 2011M12, it is
relatively hard to calculate the number of months. Is there any faster way
to do it?
On Thu, May 03, 2012 at 09:07:39PM -0400, li li wrote:
Hi all,
I have a 100 by 100 matrix and I divided this matrix into 100 groups,
each is a
10 by 10 submatrix. I want find out the means of each group.
I know we can use apply function for mean by margins. Is there a
function in R
On Thu, May 03, 2012 at 07:32:46PM -0400, brwin338 wrote:
Good Evening
We have been searching through the R documentation manuals without success on
this one.
What is the purpose or result of the L in the following?
n=10
and
n=10L
or
c(5,10)
versus
c(5L,10L)
Hi.
The help page
I have the following:
Time A1 A1 B1 B1 C1 C2
x y x y x y
0 5 6 6 7 7 9
1 3 4 4 3 9 9
2 5 2 6 4 7 4
I want to change it to the following:
On 05/04/2012 12:04 AM, Ben Neal wrote:
Jim, thanks for the reply. I tried what you recommend, but I still get an error
when running it, just as I did with the similar loops I was trying. Here is the
error:
Error in xy.coords(x, y) : 'x' and 'y' lengths differ
That comes from this code:
Hello to R people
This is not a question. Just found a beautiful summary dated back in
2004. Hope this will be useful for your work
Thanks to Gudrun Jonasdottir gudrunj_at_math.su.se
mailto:gudrunj_at_math.su.se?Subject=Re:%20[R]%20convert%20strings%20to%20object%20names:%20SUMMARY
In summary:
On Fri, May 4, 2012 at 2:47 AM, jpm miao miao...@gmail.com wrote:
Hello,
In zoo package, if I would like the time frame to be 1981M01 to 1982M12,
then I code
time_0-as.yearmon(1981-01)+(0:23)/12
However, if the time frame of interest becomes 1981M01 to 2011M12, it is
relatively hard
read.table imports the company name GREAT FALLS GAS CO as four
separate columns. I think that needs to be one column. I can imagine
that further one in your file you will have another company name that
does not consist of four words which would cause the error you
observed. From your
read.delim calls read.table so any differences between the two are
caused by differences in the default values of some of the parameters.
Take a look at the help file ?read.table
read.table uses white space as separator; read.delim tabs
read.table uses and ' as quotes; read.delim just
On May 4, 2012, at 08:16 , Rameswara Sashi Kiran Challa wrote:
Hi,
I have a tab seperated file with 206 rows and 30 columns.
I read in the file into R using read.table() function. I checked the dim()
of the data frame created in R, it had only 103 rows (exactly half), 30
columns. Then I
On Thu, May 03, 2012 at 07:36:45PM -0700, marc212 wrote:
I have the following:
Time A1 A1 B1 B1 C1 C2
x y x y x y
0 5 6 6 7 7 9
1 3 4 4 3 9 9
2 5 2 6
Could someone help me on this please?
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Dwaipayan Dasgupta
Sent: Thursday, May 03, 2012 1:43 PM
To: r-help@r-project.org
Subject: [R] Validation of logistic models in R 2.12
Hi
Hello,
I'm writing a piece of code where I need to compare multiple same length
vectors.
I've gone through the basic functions like identical() or all(), but they
only work for comparing 2 vectors. From 3 vectors on, it doesn't work .
Example: Assuming
vec1 - c (1,2,3,4,5)
vec2 -
Hi,
I am trying to query a Sybase database on my new windows 7 machine. I am
using native sybase driver Adaptive server Enterprise following is example
code
conn - sprintf(driver=Adaptive server
Enterprise;server=PHKSESMD01;database=smd_live;uid=temp_user;password=temp_pass;port=2301)
chan
Hi all,
I want to plot the outcome of my PCA analysis (done with prcomp()), but I
have so many variables that plotting them obscures the whole plot. How do
I suppress the plotting of variables in a biplot? I only want to see the
units.
I appreciate both data constitute a biplot, so alternatively
Thanks Peter.
In my case specifying the quote=\ worked out fine with read.table().
-Sashi
On Fri, May 4, 2012 at 1:53 PM, peter dalgaard pda...@gmail.com wrote:
On May 4, 2012, at 08:16 , Rameswara Sashi Kiran Challa wrote:
Hi,
I have a tab seperated file with 206 rows and 30 columns.
I have a list ( in my real problem a double list y[[1:24]][[1:15]] but I
think the solution would be the same)
m - matrix(1:3, 3, 3)
x - list(m, m+3, m+6)
and as I want to have the sum of elements I use Reduce(`+`, x)
having as result
Reduce(`+`, x)
[,1] [,2] [,3]
[1,] 12 12 12
Hi all,
how would you test if a sample mean of integers with range -inf;inf is
different from zero:
# my sample of integers:
c - c(-3, -1, 0, 1, 0, 3, 4, 10, 12)
# is mean of c 0?:
mean(c)
Thanks,
Kay
[[alternative HTML version deleted]]
See package pixmap, for example.
Uwe Ligges
On 04.05.2012 03:10, ZHANG Yingqi wrote:
Dear all,
I open a bmp device by the bmp() function in the png package, but I
don't know how to write color pixel by pixel into the file? Any help or hint?
What I want to do is to create a
On Fri, May 04, 2012 at 12:53:12AM -0700, aaurouss wrote:
Hello,
I'm writing a piece of code where I need to compare multiple same length
vectors.
I've gone through the basic functions like identical() or all(), but they
only work for comparing 2 vectors. From 3 vectors on, it doesn't
rakeshnb rakeshn...@gmail.com writes:
I am using pls package but how is scaling done in R?
That is documented in the help pages:
library(pls)
?plsr
[snip]
scale: numeric vector, or logical. If numeric vector, X is scaled
by dividing each variable with the corresponding element
or
identical(vec1, vec2) identical(vec2, vec3)
Jan
Petr Savicky savi...@cs.cas.cz schreef:
On Fri, May 04, 2012 at 12:53:12AM -0700, aaurouss wrote:
Hello,
I'm writing a piece of code where I need to compare multiple same length
vectors.
I've gone through the basic functions like
mean(c) != 0
But if you mean in a statistical sense... t.test() is one possibility.
Michael
On Fri, May 4, 2012 at 5:29 AM, Kay Cichini kay.cich...@gmail.com wrote:
Hi all,
how would you test if a sample mean of integers with range -inf;inf is
different from zero:
# my sample of
On Fri, May 04, 2012 at 11:29:51AM +0200, Kay Cichini wrote:
Hi all,
how would you test if a sample mean of integers with range -inf;inf is
different from zero:
# my sample of integers:
c - c(-3, -1, 0, 1, 0, 3, 4, 10, 12)
# is mean of c 0?:
mean(c)
Hi.
It is better to use a name
quantile(myvec, 0.9)
See ?quantile for the 9 different empirical quantile methods provided.
Michael
On Thu, May 3, 2012 at 2:20 PM, Drew Duckett dducket...@gmail.com wrote:
If i am not mistaking the quantile function and percentile function and the
same other than the way they are expressed
Inelegant, but this is one way:
Reduce(function(e1, e2){e1[is.na(e1)] - 0; e2[is.na(e2)] - 0; (e1 + e2)}, x)
I.e., set the NAs to 0 before adding in the reduce function.
Michael
On Fri, May 4, 2012 at 5:19 AM, Evgenia ev...@aueb.gr wrote:
I have a list ( in my real problem a double list
Hi,
I'm plotting PDFs and have a problem. If I have more than 8 sources of data the
colours are repeated. These plots are used to remove poor data from the sets so
it would be helpful if I could expand the colour range. Is there any way to do
this?
The plots are coloured by defining a vector
How many colors are you looking for? There are limits to how many the
eye can make out, but perhaps the RColorBrewer package would be a
place to start. Also check out: http://colorbrewer2.org/
To see all the builtin colors, you can simply use the colors()
function, but your viewer won't be able
Hi,
Thanks for the help. Extending the palette to 16 or 20 would be a big help. The
largest number of files I've had to handle in a single group is 42 and I
wouldn't expect it to get much bigger than that.
I'll take a look at RColorBrewer.
Cheers,
Gavin.
-Original Message-
From: R.
I'm not sure you'll be able to come up with 42 categorial colors:
perhaps facetting / small-multiples here? Colorspace (on CRAN) will
let you make palettes manually, so perhaps that's worth looking at.
Michael
On Fri, May 4, 2012 at 7:49 AM, Gavin Blackburn
gavin.blackb...@strath.ac.uk wrote:
Hi
One option for substantial distinguishable range of colours is jet.colors
from matlab package.
Regards
Petr
Hi,
Thanks for the help. Extending the palette to 16 or 20 would be a big
help. The largest number of files I've had to handle in a single group
is
42 and I wouldn't expect
Ok great, thanks for the help. I don't mind sectioning data off into smaller
groups in this early stage, but the more I can get in one group the better.
Cheers,
Gavin.
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: 04 May 2012 13:04
To: Gavin
Thanks Petr, I'll take a look at that as well.
Cheers,
Gavin.
-Original Message-
From: Petr PIKAL [mailto:petr.pi...@precheza.cz]
Sent: 04 May 2012 13:09
To: Gavin Blackburn
Cc: r-help@r-project.org
Subject: Re: [R] colours in a pdf
Hi
One option for substantial distinguishable range
Hi,
I have two variables ranging both from 0 to 1 (n=500 each).
Now I am interested in plotting them both in one plot (using ggplot2).
So far I used ecdf() (from an example I found with google) to get
values for the cumulatice distribution function which gives a relative
curve. I also want to do
On 12-05-04 12:41 AM, Spencer Graves wrote:
On 5/3/2012 9:28 PM, Joshua Wiley wrote:
How are you using R? Any special front ends that might be causing
this? Can you try it in unsuffered consequences?
I'm running R 1.15.0; sessionInfo() appears below. I get this
from Rgui i386 and
Which version of gam are you using (i.e. which package and version number?)
prediction with fitted gam objects should call predict.gam, and I'm not
quite sure why this is not happening here (you do have the mgcv or gam
loaded while trying to predict, I suppose?).
On 03/05/12 22:56, Ben quant
simply change the specification in the subset command to 0
John Kane
Kingston ON Canada
-Original Message-
From: shankarla...@gmail.com
Sent: Thu, 3 May 2012 16:51:50 -0400
To: jrkrid...@inbox.com
Subject: Re: [R] Identifying the particular X or Y in a sorted
Hi,
it is easiest to explain what I want to do by an example:
lets assume there are two factors/variables:
A - c(1,2,3)
B - c(1,3,3)
Now I would like to generate a list of strings that should look like
(A1_B1,A1_B2,A2_B1,A2_B2). So actually the string
contains all possible combinations of A and
do.call(function(x,y) paste0(A,x,_,B,y),expand.grid(x = A,y = B))
seems to be a place to start. Robust generalization seems a hair
tricky -- I'll mull on it.
Michael
On Fri, May 4, 2012 at 9:10 AM, Johannes Radinger jradin...@gmx.at wrote:
Hi,
it is easiest to explain what I want to do by an
Am I correct in assuming that the output below essentially translates to
Males have a mean time that is significantly lower than Females? Is this
the correct way to interpret the fact that the coefficient is negative?
Assume the variale sex is treated as a factor with Female =0 and Male=1.
Hi -
So when I run the following, I get a strange formatting output with MikTeX, and
I am unsure if the behavior is due to R, Hmisc, or MikTeX or both:
dfr - data.frame(x=rnorm(400),y=sample(c('male','female'),400,TRUE))
latex(describe(dfr))
What happens is that the x column is summarized in
Solution: have package mgcv loaded when you predict...not just for the fit.
:) Silly mistake...
Thanks Simon!
Ben
On Thu, May 3, 2012 at 3:56 PM, Ben quant ccqu...@gmail.com wrote:
Hello,
I don't understand what went wrong or how to fix this. How do I set
qr=TRUE for gam?
When I produce
Dear Users!
I encountered with some problem in data reading while I challenged R (and
me too) in a validation point of view.
In this issue, I tried to utilize some reference datasets (
http://www.itl.nist.gov/div898/strd/index.html).
And the result departed a bit from my expectations. This
Hi Istvan,
That's most unusual, and quite unlikely (and much larger than the
usual floating-point rounding errors).
Please provide a reproducible example. I assume you got the data from here:
http://www.itl.nist.gov/div898/strd/anova/SmLs07.dat
What did you do with it then? How did you delete
Em 4/5/2012 06:39, Bjørn-Helge Mevik escreveu:
rakeshnbrakeshn...@gmail.com writes:
[snipped]
When in doubt, read the documentation. :)
An obvious candidate for a fortune entry!
__
R-help@r-project.org mailing list
Hi Istvan,
Your OS and version of R (eg sessionInfo() ) would also be useful, as
would sending your reply to the R-help list and not just to me.
Sarah
-- Forwarded message --
From: Istvan Nemeth furgeu...@gmail.com
Date: Fri, May 4, 2012 at 10:20 AM
Subject: Re: [R] read-in,
On May 3, 2012, at 6:09 PM, Diego Rojas wrote:
If a run a LOESS model and then produce a smoothed surface: Is there
any
way to determine the coordinates of the local maxima on the surface?
?predict# it has a loess method.
[[alternative HTML version deleted]]
--
David
On May 3, 2012, at 7:10 PM, Saurav Pathak wrote:
Hi,
For some reason I have been unable to use the predict function when
I desire the standard error to be calculated too. For example, when
I try the following:
l- loess(d~x+y, span=span, se=TRUE)
p- predict(l, se=TRUE)
I don't know
On May 4, 2012, at 1:34 AM, iliketurtles wrote:
Dear Experienced R Practitioners,
I have 4GB .txt data called dataset.txt and have attempted to use
*ff,
bigmemory, filehash and sqldf *packages to import it, but have had no
success. The readLines output of this data is:
Ther alignment of
On 05/04/2012 10:39 AM, David Winsemius wrote:
On May 3, 2012, at 7:10 PM, Saurav Pathak wrote:
Hi,
For some reason I have been unable to use the predict function when I
desire the standard error to be calculated too. For example, when I
try the following:
l- loess(d~x+y, span=span,
On May 4, 2012, at 2:38 AM, Alok Jadhav wrote:
Hi,
I am trying to query a Sybase database on my new windows 7 machine. I am
using native sybase driver Adaptive server Enterprise following is example
code
conn - sprintf(driver=Adaptive server
?outer
Bert
Sent from my iPhone -- please excuse typos.
On May 4, 2012, at 6:25 AM, R. Michael Weylandt michael.weyla...@gmail.com
wrote:
do.call(function(x,y) paste0(A,x,_,B,y),expand.grid(x = A,y = B))
seems to be a place to start. Robust generalization seems a hair
tricky -- I'll mull
You didn't mention it, but did you use something like
options(digits=20)
before displaying that data? In any case,
1.4000244 == 1.4
[1] TRUE
because R uses the IEEE-754 double precision floating point
arithmetic that all modern computers support. That gives
you
Dear Sweave users,
Could you help me to find a way to place Sweave output files in a subdirectory
of the currentfolder without giving them a subname?
If the option prefix.string=foo/ is used, all files are placed in this
folder, but begin with an hyphen-minus, which makes it difficult to work
On May 4, 2012, at 9:43 AM, wwreith wrote:
Am I correct in assuming that the output below essentially
translates to
Males have a mean time that is significantly lower than Females?
Is this
the correct way to interpret the fact that the coefficient is
negative?
I wouldn't be using
I agree with you. I used this trick to take the desired results but I
posted wondering If there was any other solution.
Thanks
Evgenia
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Sent from the R help mailing list
On May 4, 2012, at 10:52 AM, Saurav Pathak wrote:
On 05/04/2012 10:39 AM, David Winsemius wrote:
On May 3, 2012, at 7:10 PM, Saurav Pathak wrote:
Hi,
For some reason I have been unable to use the predict function
when I desire the standard error to be calculated too. For
example,
dear Szymon,
it is a bug (in the new version), thanks. It depends on the flat
underlying relationship you are trying to estimate with a small sample..
I will correct it as soon as possible. Meanwhile you can use
o1-glm(gpp ~ temp)
os1-segmented(o1, seg.Z=~temp, psi=15,
I guess that is hard-coded in Sweave, so you probably cannot control
it unless you (partially) rewrite the driver. And just FYI, you can
try the knitr package, which does not add the hyphen for you, but the
name of the option 'prefix.string' has been changed to 'fig.path'
You cannot avoid the hyphen I think, but if you say (for example):
prefix.string=foo/x
then your files start with 'x-' (so 'graph' becomes 'foo/x-graph') which may be
better for you than the hyphen at the beginning of the file name.
Rgds,
Rainer
On Friday 04 May 2012 17:23:58
...
as in:
outer(paste(A,A,sep=),paste(B.B,sep=), FUN =paste,sep=_)
-- Bert
On Fri, May 4, 2012 at 7:59 AM, Bert Gunter bgun...@gene.com wrote:
?outer
Bert
Sent from my iPhone -- please excuse typos.
On May 4, 2012, at 6:25 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
Em 04-05-2012 11:00, jeff6868 geoffrey_kl...@etu.u-bourgogne.fr escreveu:
Date: Thu, 3 May 2012 06:45:59 -0700 (PDT)
From: jeff6868geoffrey_kl...@etu.u-bourgogne.fr
To:r-help@r-project.org
Subject: [R] add an automatized linear regression in a function
Here is a working snippet.
library(epitools)
mat - matrix(c(10,15,60,25,98, 12,10,70,28,14, 9,11,68,10,12
,8,13,20,11,58) ,ncol=2)
colnames(mat) - c(treatmentA,treatmentB)
row.names(mat) - paste(Cond,rep(1:10,1))
dimnames(mat) - list(Condition = row.names(mat), instrument =
colnames(mat))
Jan, thank you.
table(line_sizes)
line_sizes
01 97 256
1430 2860 46869069 1430
-
Isaac
Research Assistant
Quantitative Finance Faculty, UTS
--
View this message in context:
one solution is to set NAs to 0, e.g.,
m - matrix(1:3, 3, 3)
x - list(m, m+3, m+6)
x[[1]][1] - NA
x. - lapply(x, function (x) {x[is.na(x)] - 0; x} )
Reduce(+, x.)
I hope it helps.
Best,
Dimitris
On 5/4/2012 11:19 AM, Evgenia wrote:
I have a list ( in my real problem a double list
When I try to adjust a mixed model with random effects I can make this order
without problem
lm.FA-lme(absFA~trait*condition,random=~1|individual)
But if I try to fit a model in which the response (absFA) is not the same in
all individuals at different levels of trait factor , but varies
Dear R-help,
I'm trying to apply machine learning methods, such as Random Forest,
Boosted Trees or Multivariate Adaptive Regression Splines for supervised
classification issues.
In a epidemiological study, i'm dealing with high dimensional
cluster-correlated data, each cluster corresponding
Dear community,
I'd like to fix a mixed model. I have unbalance data, what should i use:
lme in nlme package , or lmer in lme4.
Thanks, u...@host.com as u...@host.com
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Sent from the R
I have two datasets, the first has this shape (each word is a column)
Name address phone .. ..
The second one has the following shape
Name request
I need a contingency table with for example phone and request.
The people registered in these datasets are present in both datasets, BUT in
the
Hi,
I tried to use naivebayes in package 'e1071'.
when I use following parameter, only one predictor, there is an error.
m- naiveBayes(iris[,1], iris[,5])
table(predict(m, iris[,1]), iris[,5])
Error in log(sapply(attribs, function(v) { :
Non-numeric argument to mathematical function
Here is a working snippet.
library(epitools)
mat - matrix(c(10,15,60,25,98, 12,10,70,28,14, 9,11,68,10,12
,8,13,20,11,58) ,ncol=2)
colnames(mat) - c(treatmentA,treatmentB)
row.names(mat) - paste(Cond,rep(1:10,1))
dimnames(mat) - list(Condition = row.names(mat), instrument =
colnames(mat))
I have the same problem installing R on a new machine, my codes are nor
working anymore (same error message as you had).
Unfortunately, I do not understand what you mean by R patched and especially
updating R-patched and google cannot help me this time... May you explain
what I have to do?
Here is a working snippet.
library(epitools)
mat - matrix(c(10,15,60,25,98, 12,10,70,28,14, 9,11,68,10,12
,8,13,20,11,58) ,ncol=2)
colnames(mat) - c(treatmentA,treatmentB)
row.names(mat) - paste(Cond,rep(1:10,1))
dimnames(mat) - list(Condition = row.names(mat), instrument =
colnames(mat))
Hello,
lunarossa wrote
I have two datasets, the first has this shape (each word is a column)
Name address phone .. ..
The second one has the following shape
Name request
I need a contingency table with for example phone and request.
The people registered in these datasets are
Hello R users,
I want to export to an xls or .csv some predictions I produced with the
auto.arima and forecast functions.
A detail of all my work is presented below. I loaded a package called
dataframes2xls and tried to use the function write.xls without any success.
Can anybody help me figure
You should to download this package and install it:
http://cran.r-project.org/bin/windows/base/R-2.15.0patched-win.exe
You can find it in R website Download R for Windows base Other builds
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Hi, i'm a new r user and I will take you a simple (not for me)question.
I have a r script file like this:
text - c(ARCHIVIO name definition)
I have a csv file like:
NAME
alfa
beta
gamma
how can I replace with a loop statment metadata name of script file with
the values
Hi David,
I've tried using sep=\t but it doesn't work, unfortunately.
Thanks for your help.
-
Isaac
Research Assistant
Quantitative Finance Faculty, UTS
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Sent from the R
Hello, I tried to do a 'sem' analysis for data of how blueberry consumption
by birds is influenced by a pollution gradient, using distance and
vegetation structural and composition variables, but I got the following
error message:
Error in sem.default(ram = ram, S = S, N = N, param.names = pars,
Hi,
I have a data set with 999 observations, for each of them I have data on
four variables:
site, colony, gender (quite a few NA values), and cohort.
This is how the data set looks like:
str(dispersal)
'data.frame': 999 obs. of 4 variables:
$ site : Factor w/ 2 levels 1,2: 1 1 1 1 1 1 1 1
Hello,
diegogiri wrote
Hi, i'm a new r user and I will take you a simple (not for me)question.
I have a r script file like this:
text - c(ARCHIVIO name definition)
I have a csv file like:
NAME
alfa
beta
gamma
how can I replace with a loop statment
Hi,
I need to create a data frame containing the results of a number of ANOVA's
but I'm having some trouble setting it up (some being enough for me to spend
3 days trying with no progress and be left staring in to the abyss which
some people call a weekend, and what I will call 2 quiet days in the
Em 04-05-2012 11:00, jeff6868 geoffrey_kl...@etu.u-bourgogne.fr escreveu:
Date: Thu, 3 May 2012 06:45:59 -0700 (PDT)
From: jeff6868geoffrey_kl...@etu.u-bourgogne.fr
To:r-help@r-project.org
Subject: [R] add an automatized linear regression in a function
Hi Folks,
I'm running 32-bit R 2.14 in RStudio on my Win 7 x64 system with 8GB
RAM. I'm getting memory problems as R wants to swallow more than the
4GB limit.
I think I'm stuck at 4GB as I have to use 32-bit R for a number of
packages (ODBC, etc). However, I doubt I really need to be using
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