Hello everyone,
There is another message that is popping up in RExcel that goes: Microsoft
Excel is waiting for another application to complete an OLE action. What
does this mean? I have attached a document here that shows the message in
detail:
Dear Richard,
I know I should be posting this question on the list (I´ve already submited
the question on RExcel´s list and still wating for approval) but I am going
to send you the question here also,
Please take a look at the document I am attaching, as you can see the Menu
Options in RExcel
Hi -- I am wondering why the time to solve (invert) a block diagonal matrix
created with bdiag() from the Matrix package does not scale with the number of
blocks [all of the same size]. Or, what I am doing wrong. The code / output
below creates a series of block diagonal matrices with 4x4
Dear Jim,
I am sorry to write you directly instead of sending a user forum mail.
I have been trying to plot a Taylor diagram but get confronting the
following error message:
taylor.diagram(ref,model_D1,pos.cor=FALSE)
Error in text.default(1.05 * maxray * i, 1.05 * maxray * sqrt(1 -
Hello,
I need density function so that I can find expected value (using
integration). I use density():
f= density(data)
but f isn't a function and I can't get values and integrate it
This is very urget, so please help.
Greetings
Peter
--
View this message in context:
Hi List,
I have a raster and a polygon with attribute ID and Class.
I want to have the fraction of each class present in each pixel of raster. I
have use the raster::extract to get the value and weights as below.
ex-extract(raster,polygon,weighted=TRUE)
this gives me
[[1]]
value weight
Hi List,
I am hoping some of you have experience with the spdep package.
I have had success with lm.morantest and lm.LMtests.
I am trying to run a spatial error model and I keep getting the following
error
Error in res[i, listw$neighbours[[i]]] - listw$weights[[i]] :
NAs
Hi,
I'm receiving an error when I am trying to install rJava. I have posted the
error below.
RHive_0.0-6.tar.gz rJava_0.9-3.tar.gz RJDBC_0.2-0.tar.gz
Rserve_0.6-8.tar.gz
[root@localhost Package]# R CMD INSTALL rJava_0.9-3.tar.gz
* installing to library ‘/usr/local/lib64/R/library’
*
Hi,
Is there a function that emulates cp -f on Unix, in that existing but
non-writable destination files are removed first?
I thought file.copy(src, dst, overwrite = TRUE) did that, but it doesn't: it
will not copy to non-writable dst. To be sure, this behavior is consistent
with the
Hello
I want to know Is this possible to connect R with PHP ? I am using
operating system-windows 7
there is a R-php software but it is not working for windows 7 OS...
Can any body help me?
Shruti Bansal
--
View this message in context:
On Wed, 27 Jun 2012 16:58:29 +1200
Rolf Turner rolf.tur...@xtra.co.nz wrote:
On 27/06/12 08:54, arun wrote:
Hi,
The error is due to less than 5 observations in some cells.
NO, NO, NO It's not the observations that matter, it is
the ***EXPECTED COUNTS***. These must
Hello,
And what is your system? Do you have root privileges?
Regards
Le 27/06/2012 13:01, mmka...@uwaterloo.ca a écrit :
Dear Jim,
I am sorry to write you directly instead of sending a user forum mail. I
have been trying to plot a Taylor diagram but get confronting the
following error
Thank you for all the advice! After mailing the question, I actually found a
function called multhist (plotrix package) that plots two data sets (in single
list) on a single histogram.
The script is as follows:
#I listed to two data sets in âlongâ format in a .csv file
input -
On Tue, 26-Jun-2012 at 10:54PM -0500, Erin Hodgess wrote:
| Dear R People:
|
| I have dates as factors in the following:
|
| poudel.df$DATE
| [1] 1/2/2011 1/4/2011 1/4/2011 1/4/2011 1/6/2011 1/7/2011 1/8/2011
| [8] 1/9/2011 1/10/2011
| Levels: 1/10/2011 1/2/2011 1/4/2011 1/6/2011
Hi
is there a command that calculates the correct adjusted R-squared, when
I work without intercept? (The R-squared from lm without intercept is
false.)
Greetings
Chrsitof
__
R-help@r-project.org mailing list
On 27.06.2012 09:33, Christof Kluß wrote:
Hi
is there a command that calculates the correct adjusted R-squared, when
I work without intercept? (The R-squared from lm without intercept is
false.)
Then we need your definition of your version of correct - we know the
definition of your
Hi
How could I select the rows of a dataset that have the maximum value in
one variable and to do this nested in another variable. It is a
dataframe
in long format with repeated measures per subject.
I was not successful using aggregate, because one of the columns has
You could do it
On 06/27/2012 10:33 AM, Christof Kluß wrote:
Hi
is there a command that calculates the correct adjusted R-squared, when
I work without intercept? (The R-squared from lm without intercept is
false.)
Hi! This answer in R-FAQ might help you:
On Jun 27, 2012, at 09:33 , Christof Kluß wrote:
Hi
is there a command that calculates the correct adjusted R-squared, when
I work without intercept? (The R-squared from lm without intercept is
false.)
When people say that, they are usually implying that a correct R-squared can
be
for example the same model with intercept R² = 0.6, without intercept R²
= 0.9 and higher. In my definition of R², R² has to be equal or less
without intercept
I do not know what R shows, but in the summary of the model without
intercept it does not show the R² of the regression line.
When I
Hello,
I'm afraid you're wrong, this has nothing to do with leading zeros. Just
see:
x - c(1/2/2011, 1/4/2011, 1/4/2011, 1/4/2011, 1/6/2011,
1/7/2011,
1/8/2011, 1/9/2011, 1/10/2011)
as.Date(x, %m/%d/%Y)
y - factor(x)
str(y)
as.Date(as.character(y), %m/%d/%Y)
Note that the
Hi,
I am looking for some assistance with these requirements. We
are trying to simulate web requests to hit a web applications. Let's
assume I have a url to hit that requires a username and password.
1. These web requests should have exponential inter arrival times.
2.
Hello,
My guess would be that solve() does not take advantage of the
special structure of the matrix and that you may want a sparse matrix
representation.
Take care
Oliver
On Tue, Jun 26, 2012 at 1:56 PM, Paul Rathouz rath...@biostat.wisc.edu wrote:
Hi -- I am wondering why
Hello,
Homework?
There's a no homework rule but see inline.
Em 27-06-2012 10:20, Mohan Radhakrishnan escreveu:
Hi,
I am looking for some assistance with these requirements. We
are trying to simulate web requests to hit a web applications. Let's
assume I have a url to hit that
Hello,
Maybe the link below is of some use.
http://stats.stackexchange.com/questions/14061/area-under-the-pdf-in-kernel-density-estimation-in-r
Hope this helps,
Rui Barradas
Em 27-06-2012 01:13, pilaw escreveu:
Hello,
I need density function so that I can find expected value (using
Hello,
Here's a solution using aggregate and merge. I've kept it in two steps
for clarity.
d - read.table(text=
subjecttime.ms V3
1 1 stringA
1 12 stringB
1 22 stringC
2 1stringB
2 14 stringC
2 25 stringA
, header=TRUE)
ag -
Homework ? You mean the question is at a high level.
I use R. It is just the simulation part that I am investigating. Several
papers on Capacity Planning that I am working on are useful for
analyzing log traffic using R for GOF tests etc. But I am not able to
find many papers on using R or r-java
Hello, R-help,
does anybody have already a work-around for the problem that the formula
version of sunflowerplot() throws an error when provided with a value for
xlab (or ylab) different from NULL:
sunflowerplot( Sepal.Length ~ Sepal.Width, data = iris, xlab = A)
Error in
On 27.06.2012 10:36, Christof Kluß wrote:
for example the same model with intercept R² = 0.6, without intercept R²
= 0.9 and higher. In my definition of R², R² has to be equal or less
without intercept
I do not know what R shows, but in the summary of the model without
intercept it does not
Hi R-users,
I'm trying to repeat the same procedure to 1000 data set. I know this is
very easy, but I got stuck finding the right and fastest way in running it.
IID50=Riidf[1:50,1:1000] #where IID50 is a dataframe consist of 1000 time
series(as column) and 50 time scales (row).
#what I tried to
you will have to check what function pargev() returns as a result. I
would guess that is probably a list. In any case, you could use
something like the following:
estIID50 - lapply(IID50, function (m) pargev(lmom.ub(m)))
I hope it helps.
Best,
Dimitris
On 6/27/2012 1:31 PM, Al Ehan wrote:
Hello,
Try the following.
estIID50 - apply( IID50, 2, function(x) pargev(lmom.ub(x)) )
And see ?apply
Hope this helps,
Rui Barradas
Em 27-06-2012 12:31, Al Ehan escreveu:
Hi R-users,
I'm trying to repeat the same procedure to 1000 data set. I know this is
very easy, but I got stuck
It's working I am excited than ever!!
Thank you so much
On Wed, Jun 27, 2012 at 12:45 PM, Dimitris Rizopoulos
d.rizopou...@erasmusmc.nl wrote:
you will have to check what function pargev() returns as a result. I would
guess that is probably a list. In any case, you could use something
p-value 0.05 means that the 95% confidence intervals span zero.
Use confint to get the CI. It is described in ?model.avg.
cheers,
kamil
Dnia 2012-06-27 12:00, Robertson, Andrew pisze:
Dear R users,
Recent changes to the MuMIn package now means that the model averaging command
(model.avg)
Sorry, one more simple question. how do I pick, from the generated lapply,
the $para for each X. say here I have 2 generated list from previous
function. how do I take only the $para for each X?
Thank you so much for your kindness.
$X1
$X1$type
[1] gev
$X1$para
xi alpha
try this:
sapply(estIID50, [[, 'para')
Best,
Dimitris
On 6/27/2012 2:17 PM, Al Ehan wrote:
Sorry, one more simple question. how do I pick, from the generated
lapply, the $para for each X. say here I have 2 generated list from
previous function. how do I take only the $para for each X?
On Jun 27, 2012, at 13:15 , Uwe Ligges wrote:
1 - crossprod(residuals(model)) / crossprod(y - mean(y))
And the reason why that is not used in R:
y- rnorm(100,10,1)
x - 1:100
model - lm(y~x-1)
1 - crossprod(residuals(model)) / crossprod(y - mean(y))
[,1]
[1,] -27.60012
--
Hi Xi,
Maybe you should try to parallelize your calculations.
See package parallel.
http://stat.ethz.ch/R-manual/R-devel/library/parallel/doc/parallel.pdf
Arnaud
On Mon, Jun 25, 2012 at 8:07 PM, Xi amzhan...@gmail.com wrote:
Dear All,
I have been searching online for help increasing my R
-Original Message-
From: mb...@sun.ac.za
Sent: Wed, 27 Jun 2012 08:32:24 +0200
To: jrkrid...@inbox.com, ke...@math.montana.edu
Subject: RE: [R] plotting two histograms on one plot with hist function
Thank you for all the advice! After mailing the question, I actually
On Wed, Jun 27, 2012 at 4:36 AM, Christof Kluß ckl...@email.uni-kiel.de wrote:
for example the same model with intercept R² = 0.6, without intercept R²
= 0.9 and higher. In my definition of R², R² has to be equal or less
without intercept
I do not know what R shows, but in the summary of the
It would be difficult for me to give the package.
Can you explain me what does this error
/usr/lib/R/bin/INSTALL: line 34: 9964 Done echo 'tools:::.install_packages()'
9965 Segmentation fault | R_DEFAULT_PACKAGES= LC_COLLATE=C ${R_HOME}/bin/R
$myArgs --slave --args ${args}
generally mean.
The
On 27/06/2012 15:17, Mayank Bansal wrote:
It would be difficult for me to give the package.
Then, following the posting guide, you need to find an example you can give.
Can you explain me what does this error
/usr/lib/R/bin/INSTALL: line 34: 9964 Done echo 'tools:::.install_packages()' 9965
Dear R-help list,
Part of a program I wrote seem to take a significant amount of time,
therefore I am looking for an alternative approach.
In order to explain what is does:
- the input is a sorted vector of integer numbers
- some higher numbers may be derived (using a mathematical formula)
from
On Jun 27, 2012, at 6:58 AM, Mohan Radhakrishnan wrote:
Homework ? You mean the question is at a high level.
I use R. It is just the simulation part that I am investigating.
Several
papers on Capacity Planning that I am working on are useful for
analyzing log traffic using R for GOF tests
How about
dates - as.factor(c(1/2/2011, 1/4/2011, 1/4/2011, 1/4/2011,
1/6/2011, 1/7/2011, 1/8/2011, 1/9/2011, 1/10/2011))
dates
[1] 1/2/2011 1/4/2011 1/4/2011 1/4/2011 1/6/2011 1/7/2011 1/8/2011
[8] 1/9/2011 1/10/2011
Levels: 1/10/2011 1/2/2011 1/4/2011 1/6/2011 1/7/2011 1/8/2011
am trying to produce two dot plot figures in ggplot2. So far the first one
(p) in the program below is working fine.
However when I want to move to a faceted plot (p1) I seem to lose my ordering
or, more likely, I'm just getting an ordering I am not expecting and I always
have trouble
On 2012-06-26 23:02, John wrote:
On Wed, 27 Jun 2012 16:58:29 +1200
Rolf Turnerrolf.tur...@xtra.co.nz wrote:
On 27/06/12 08:54, arun wrote:
Hi,
The error is due to less than 5 observations in some cells.
NO, NO, NO It's not the observations that matter, it is
the
It seems to be a bug when you specify an x-label.
# No xlab= works fine, but uses variable names to label x and
# y axes
sunflowerplot(Sepal.Length~Sepal.Width, data=iris)
# These all throw the error message
sunflowerplot(Sepal.Length~Sepal.Width, data=iris, xlab=A)
Or just avoid the formula version:
with(iris, sunflowerplot(Sepal.Width, Sepal.Length, xlab=A))
--
David L Carlson
Associate Professor of Anthropology
Texas AM University
College Station, TX 77843-4352
-Original Message-
From:
One place to start is to use Rprof to see where time is being spent.
I used the sample you sent and this is what I got:
0 16.7 root
1. 16.2 system.time
2. . 16.1 testfoo
3. . . 16.1 setdiff
4. . . .8.2 as.vector
5. . . . .8.2 findSubsets
6. . . . . .6.4 increment
Hello,
No, the Ljung-Box test wouldn't be inappropriate in that case. First you
detrend the series and then test for serial independence. It's even
usual to do so. I would use the default values for lag and fitdf. But
use type=Ljung, the Box-Pierce test is nowadays seldom used in
pratice, if
Hi Jim,
On Wed, Jun 27, 2012 at 7:27 PM, jim holtman jholt...@gmail.com wrote:
One place to start is to use Rprof to see where time is being spent.
I used the sample you sent and this is what I got:
0 16.7 root
1. 16.2 system.time
2. . 16.1 testfoo
3. . . 16.1 setdiff
4. . .
I have the following matrix operation
A %*% B %*% A
Where these matrices have the following dimensions and class attributes.
dim(A)
[1] 5764 5764
class(A)
[1] dgCMatrix
attr(,package)
[1] Matrix
dim(B)
[1] 5764 5764
class(B)
[1] dgCMatrix
attr(,package)
[1] Matrix
Now, when I do just
Hello Xi,
Have you tried replacing the for loop by an apply construct, e.g., lapply or
sapply? In my experience these functions are more efficient than for. At any
rate, if you succeed with, say, lapply, there are some R packages that support
parallel processing versions. I believe the
On Wed, Jun 27, 2012 at 05:36:08PM +0300, Adrian Duşa wrote:
Dear R-help list,
Part of a program I wrote seem to take a significant amount of time,
therefore I am looking for an alternative approach.
In order to explain what is does:
- the input is a sorted vector of integer numbers
-
On Wed, Jun 27, 2012 at 8:11 PM, jim holtman jholt...@gmail.com wrote:
If you look, half of the time is spent in the 'findSubsets function
and the other half in determining where the differences are in the
sets. Is there a faster way of doing what findSubsets does since it
is the biggest time
Here are 2 approaches:
Use logspline density estimates (logspline package) rather than kernel
density estimates, this can give you a function to pass to integrate
or other tools, the estimates may be a little different from the
kernel density estimates.
If you need to use kernel density
Hello R users,
I have used the package adehabitat to create a brownian bridge for my
radio-tracked data from one animal (using the kernelbb function). I have worked
through page 17 of the manual using the code:
data - kernelbb(x, sig1 = 6.23, sig2 = 58, grid = 100)
image(data)
This produces a
Hi,
I am trying to estimate a multivariate P-GARCH model for two factors xy. I
have selected p-garch to study the leverage effects. Is there any toolkit in
R that can help me do this?
Thanks,
Andy
--
View this message in context:
Hi to all,
I am trying to run breakpoints() on a fairly large sample (10.000
observations). The process is very slow, any idea on how to speed this up? I
have tried the hpc=foreach parameter, but this didn't work at all when I
tried to run it on a smaller sample.
breakpoints(x ~ x.l1 + x.l2 +
I have the following error message when I try to install RBloomberg.
Les packages binaires téléchargés sont dans
C:\Users\bloom\AppData\Local\Temp\RtmpktX4UK\downloaded_packages
Message d'avis :
packages ‘quantstrat’, ‘RBloomberg’, ‘rsproxy’, ‘VaR’ are not available (for
R version 2.15.1)
Well at this point I have what I need (rough plot for data exploration) but
the simplicity of the first approach is quite elegant and it has become a
learning project. I have succeeded in formatting the overall plot OK but
have not been able to solve the problem of titles or any kind of
On Wed, 27 Jun 2012, Cand2d wrote:
Hi to all,
I am trying to run breakpoints() on a fairly large sample (10.000
observations). The process is very slow, any idea on how to speed this
up? I have tried the hpc=foreach parameter, but this didn't work at
all when I tried to run it on a smaller
Hello,
Probably you should try this (thanks Google):
install.packages(Rbbg, repos = http://r.findata.org;)
Regards
Le 27/06/2012 22:54, yoda55 a écrit :
I have the following error message when I try to install RBloomberg.
Les packages binaires téléchargés sont dans
hi ,
I am reading a series of files by the command shown as below.
cop_x_data-read.table(flnm(i)
,skip=2,allowEscapes=TRUE,blank.lines.skip=TRUE)
the first two line of the files are headfile and I skip them by skip=2.
and sometimes the data file is null and there is no any data
in the file except
why cann't you use 'try'?
you can get the size of the file with 'file.info' and then make a decision to
read or not.
Sent from my iPad
On Jun 27, 2012, at 23:02, Jie Tang totang...@gmail.com wrote:
hi ,
I am reading a series of files by the command shown as below.
Not being the expert I have looked at papers like 'simpleR { Using R for
Introductory Statistics' by John Verzani. Some sample Code is in these
papers. Looks like I have to search for ideas to code a programming
language like Java by taking input from R(r-java). Can R be used
directly to hit web
I would like to compare the incidence rates of three groups. They are
supposed to have different risks so I would like to test whether there is a
increasing trend in the incidence rates. Does R or any packages provide a
trend test for incidence rates? I checked epiR and epitools. It seems they
do
for example the same model with intercept R² = 0.6, without intercept R²
= 0.9 and higher. In my definition of R², R² has to be equal or less
without intercept
I do not know what R shows, but in the summary of the model without
intercept it does not show the R² of the regression line.
When I
Hi Petr,
Appreciate your feedback and sorry for the delay in responding. The
following is the description of problem from start:-
We have a set of sensors in XY plane arranged in more or less a rectangular
grid and we know their (x,y) co-ordinate. Now these sensors send data and
from that data
Hello
In (survfit(Surv(Time,Status)~1))
I want to have status=0 as Failure and status=1 as Censore.
Changing above formula to (survfit(Surv(Time,Status)~0)) doesnot help!!
What should i do?
Thank You.
_
Best Regards
Niloofar.Javanrouh
MSc Of BioStatistics
Hi I am new with R
I Have to build a binary tree with R. I'm very confused was wondering if
anyone had any R sample code they would share. I've come across a lot of C++
code(nothing in R) and this is not helping.
Any bady can help me?
Bye
Giuseppe
--
View this message in context:
Hi List,
I am hoping some of you have experience with the spdep package.
I have had success with lm.morantest and lm.LMtests.
I am trying to run a spatial error model and I keep getting the following
error
Error in res[i, listw$neighbours[[i]]] - listw$weights[[i]] :
NAs
Hi I am new with R
I Have to build a binary tree with R. I'm very confused was wondering if
anyone had any R sample code they would share.
Any bady can help me?
Bye
Giuseppe
--
View this message in context:
http://r.789695.n4.nabble.com/binary-tree-tp4634593.html
Sent from the R help
Thanks Pablo for your answer, it was very insightful, but I guess I got
something wrong.
I formed a survey design as:
library(survey)
mydesign - svydesign(ids=~vill_neigh_code+clust, strata=~strat,
weights=~sweight, data=mydata)
where
strat: stratum (urban or (sub-county) rural).
clust:
Hello,
I seem to be having a similar problem, but with glmer models. Here,
model.avg() doesn't return anything but coefficient values:
fl19-glmer( corrFLEDGE ~ INFECTION * rsLD * bin.age + (1 | year) + (1 |
RINGNO),data=corrmalaria,family=poisson)
fledglings-dredge(fl19)
top.fledglings -
I can make kurtosis but now skewness curve. How can I do that? I have used
the following code.
x-(1:601-301)/50
x
dt3-dt(x,3)
pt3-pt(x,3)
# t distribution has mean 0; variance f/(f-2); skewness 0; excess kurtosis
6/(f-4)
dn01-dnorm(x,0,1)
pn01-pnorm(x,0,1)
dlogis-dlogis(x,0,1)
Hi,
I can see the mistake in the code as $ before Y.
dat1-as.factor(c(1/2/2011,1/4/2011,1/4/2011))
dat1
[1] 1/2/2011 1/4/2011 1/4/2011
Levels: 1/2/2011 1/4/2011
as.Date(as.character(dat1), %m/%d/%Y)
[1] 2011-01-02 2011-01-04 2011-01-04
as.Date(as.character(dat1),%m/%d/$Y)
[1] NA NA NA
Hi Gerrit
I did the following: access the function via
graphics:::sunflowerplot.formula, and then commented some lines to see,
where the problem lies. I guess that it is the chunk with mf - eval(m,
parent.frame()), but to be honest, I do not know why. My workaround is as
follows:
How can I make a reference i this case? I want to make a reference to
'Artikel XXX'
For example
In The Artikel '' there is two tables.
..
Litterature
Artikel XXX
--
View this message in context:
http://r.789695.n4.nabble.com/Make-a-reference-tp4634611.html
Sent from the R help mailing
Hi,
I'm wondering if I can do this in R. I have a data set with questions
(x-value) and respondents (y-value). If the respondent answered the
question they get a 1 and if the respondent didn't answer the question they
have a 0. Is there anyway where I can graph something similar to a grid
where
that's an old thread but checkout the colorout package - it is awesome and it
does exactly what you're asking for !
http://cran.r-project.org/web/packages/colorout/
--
View this message in context:
HI,
Try this:
dat1 - read.table(text=
subject time.ms V3
1 1 stringA
1 12 stringB
1 22 stringC
2 1 stringB
2 14 stringC
2 25 stringA
, sep=,header=TRUE)
dat2-aggregate(dat1$time.ms,list(dat1$subject),max)
colnames(dat2)-c(subject,time.ms)
t - TheWeatherIsVeryNice
How do I extract the upper case letters? - TWIVN
Thanks!
--
View this message in context:
http://r.789695.n4.nabble.com/Extract-upper-case-letters-tp4634664.html
Sent from the R help mailing list archive at Nabble.com.
__
A very important thing is home game or guest game. Why did I mention Almeria
- Sevilla earlier? Almeria are heroes at home. At least, they were in
2009/2010. They scored almost in every home game, no matter who is there at
the other end of it - Barcelona or Real Madrid.
hi
i try to do a graph who shows 2 time series at the same time
thanks!
--
View this message in context:
http://r.789695.n4.nabble.com/graph-with-two-different-arithmetic-scales-tp4634672.html
Sent from the R help mailing list archive at Nabble.com.
Please help:
I am using qplot as below and want to specify a different color scheme for race
but dont know how, can someone show me.
Thanks in advance
Code and input file below:
library(ggplot2)
library(gridExtra)
d-read.table(results, header=TRUE, fill=TRUE)
I need to look through a dataset with two factor variables, and depending
on certain criteria, create a new variable containing the data from one of
those other variables.
The problem is, R keeps making my new variable an integer and saving the
data as a 1 or 2 (I believe the levels of the
Dear R Users:
I'm a STATA user converting to R, and I'd like to be to do the following.
#Assign var_1 and var_2 a value
10-var1
20-var2
#Now I'd like to print the values of var_1 and var_2 by looping through
var_1 and var_2 in such a manner:
while(y3){
print(var_y)
y+1-y
}
In STATA, the y
How do you want your output? If you want a character vector of
lowercase letters, just use gsub([^::A-Z::],, t) to substitute
for all non-uppercase characters. strsplit() can lead you to a vector
of the single-letter upper case letters.
Best,
Michael
On Wed, Jun 27, 2012 at 2:15 PM, mdvaan
Hello,
I am running cluster analysis, and am attempting to create a graph of my
clusters. I keep on getting an error that says that my figure margins are too
large.
d - file.choose()
d - read.csv(d,header=TRUE)
mydataS - scale(d, center = TRUE, scale=TRUE)
#Converts mydataS from a
Dear R-help,
I am writing some simulation code to create multiple sets of time-to-event
clinical trial data (for use in meta-analysis). Within each trial, I want to
apply censoring via simulation of uniform variables (with minimum zero and
maximum the median outcome time for that particular
take a look at
library(zoo)
example(plot.zoo)
which shows one way to do this,
Best,
Michael
On Wed, Jun 27, 2012 at 6:50 PM, denissearchundia
denissearchun...@yahoo.com.mx wrote:
hi
i try to do a graph who shows 2 time series at the same time
thanks!
--
View this message in context:
Hello,
I have R script my_script.R . It loads a large input file data.txt and
then outputs a large matrix out. (the command of running it on cluster
using my.cmd is put at the end)
Now I have 30 different input files data1.txt, data2.txt ... and
data30.txt and want to generate and save 30 output
Hello all,
Please consider the following
library(lattice)
Colors. -rep(brewer.pal(7, Dark2),2)
color - 1
Data.X.. - data.frame(UnitArea = c(rnorm(1000), rnorm(1000)), Type =
c(rep(Base,1000),rep(Log,1000)))
histogram( ~ UnitArea | Type, data =
You can use main = unique(d$Subject) to solve this problem.
HTH,
b.
On 27 June 2012 08:49, Marcel Curlin cemar...@u.washington.edu wrote:
Well at this point I have what I need (rough plot for data exploration) but
the simplicity of the first approach is quite elegant and it has become a
Dear all!
Thanks for clarification.
OV
To: Rolf Turner rolf.tur...@xtra.co.nz
Sent: Wednesday, June 27, 2012 1:33 PM
Subject: Re: [R] chisq.test
Hi Rolf,
Thanks for spotting the mistake.
A.K.
- Original Message -
From: Rolf Turner
Hi David,
I believe you left out saying what color scheme you would prefer, so
it's hard to help, but you might be a start by looking at the
appropriate parts of Hadley's website here: http://had.co.nz/ggplot2/,
particularly the scales section.
Best,
Michael
On Wed, Jun 27, 2012 at 11:07 AM,
98 matches
Mail list logo