Hi Ernie,
I'll use the built in mtcars dataset for demonstrative purposes.
You have some condition, which can be used to create an index
## show data frame
mtcars
## create index based on your condition
i - which(mtcars$carb == 1)
## set those rows of mtcars in your index
## to the index - 1
On 07/07/2012 03:23 AM, Greeknovice wrote:
Hi,
I 'm a novice user of R statistics and my hands-on experience with it is
minimal.
I want to create a table for my MBA course assignment that looks like the
ones that SPSS and MS Excel produces ,the data that the table has to include
are the
Hi,
Try this:
dat1-data.frame(var1=15:25)
dat1$var2-NA
dat1$var2[2:11]-dat1$var1[1:10]
dat1
var1 var2
1 15 NA
2 16 15
3 17 16
4 18 17
5 19 18
6 20 19
7 21 20
8 22 21
9 23 22
10 24 23
11 25 24
You can also do the same within the
Hi,
I am a very occasional user of R, and will be grateful for some help in
constructing a regression across groups.
Here is an example:
library(MASS)
attach(cats)
Sex[120:144]-factor(TG) #Renaming some males to transgender, to create 3
groups, male, female and transgender
guRus!
I have a function f = exp(x^2-y+(1/z))
Also, x can take values from 1 to 37, y from 2 to 20 and Z from -13 to 51.
How can I find the maximum of f using any of the optimization functions
please?
Is there a way to store the possible values of x, y and Z in a single
variable like in a List
Hello,
Em 08-07-2012 03:00, Peter Ehlers escreveu:
On 2012-07-07 14:56, YTP wrote:
Hi Rui,
Thanks for responding. I did not write raw=raw, and I'm not sure why R
would return such a misleading error message. Indeed, the same error
message
comes up when I run the 2nd part of your code:
m -
Hello,
You don't need an optimzation routine to know that the maximum of this
function is +Inf. It's attained at z = 0+ (when z converges to zero by
positive values).
This breaks the R function optim(), by the way. It
needs finite values of 'fn'
Hope this helps,
Rui Barradas
Em
Hello,
There are several optimization functions in R. There's even a group
dedicated to the field. See the CRAN Task View: Optimization and
Mathematical Programming.
To use optim(), you could do something like
f - function(x, y, z) (x^2 - y - z^2/2) # I've changed the function
negf -
Good day R list
I want to transform an autoregressive distributed lag (ARDL) to a
long-run equation
(reparametrization of the (ARDL). How could i do that?
This equation is displayed in this link
https://docs.google.com/file/d/0B4dAkTAHpGBDSjA4RmlnbkxoLVU/edit
Many thanks in advance
On Jul 8, 2012, at 4:11 AM, Suresh Krishna wrote:
Hi,
I am a very occasional user of R, and will be grateful for some
help in constructing a regression across groups.
Here is an example:
library(MASS)
attach(cats)
Sex[120:144]-factor(TG) #Renaming some males to transgender, to
create
Hello,
when I use list.files with recursive = TRUE and all.files = TRUE, R returns
a list of strings/paths.
From all those strings I want to keep only the ones starting with a .
I tried using grep to achieve that. However, the problem is that because of
the recursive list.files parameter,
for
On 08.07.2012 14:47, syrvn wrote:
Hello,
when I use list.files with recursive = TRUE and all.files = TRUE, R returns
a list of strings/paths.
From all those strings I want to keep only the ones starting with a .
I tried using grep to achieve that. However, the problem is that because of
the
On 08/07/2012 14:35, Uwe Ligges wrote:
On 08.07.2012 14:47, syrvn wrote:
Hello,
when I use list.files with recursive = TRUE and all.files = TRUE, R
returns
a list of strings/paths.
From all those strings I want to keep only the ones starting with a .
I tried using grep to achieve that.
Works perfectly. Thank you very much indeed.
John Kane
Kingston ON Canada
-Original Message-
From: dwinsem...@comcast.net
Sent: Sat, 7 Jul 2012 21:45:58 -0400
To: jrkrid...@inbox.com
Subject: Re: [R] Splitting a character vector.
On Jul 7, 2012, at 5:37 PM, John Kane wrote:
It's all documented in ?regexp. . is a regex metacharacter.
Metacharacters have to be escaped via \\.
In particular, note:
The fundamental building blocks are the regular expressions that match a
single character. Most characters, including all letters and digits, are
regular expressions that
I would like to thank all of you for spending your precious time in ordrer to
help me out.
I really appreciate the fact that experienced R users replied to my
newbie post.
Regards,
Spiros Gkolfinopoulos
--
View this message in context:
Hi
I am working on co-expression analysis of rice dataset with the help of
wgcna and R but now I am at one point which is showing error as shown below
:
dissTOM = 1-TOMsimilarityFromExpr(datExpr, power = 8);
Error: cannot allocate vector of size 2.8 Gb
In addition: Warning messages:
1: In
Hi, Thanks for the reply.
Sex[120:144]-factor(TG) #Renaming some males to transgender, to
create 3 groups, male, female and transgender
Sorry, that should have been
Sex[120:144]-factor('TG')
The original line did not have the quotes.
I'm getting the sense that this is homework. You
hi all,
Prior to this post I asked a question how to deal with binary clustered data
when the crosstab by variables shows an empty cell. I figured out later that
such an empty cell corresponds to what is called separation. Fortunately,
R package logistf is developed to handle such a problem
Hello
I am an Ubuntu 11.04 and R version 2.12 user. I am using Rkward as a GUI
for R . Some of the packages I need were build on 2.14. Therefore i need to
upgrade to 2.14. Rkward needs version 2.14 or less. but the version name
cant be with suffix like natty (as far as I understand). Is there
Below is R code that successfully reads the first line of a JSON file
(attached).
However, it is supposed to read 5 lines of the file, not just one. What is the
wrong?
library(rjson)
json_file - /Users/smcintyremobile/Google Drive/AAShelby/CORRESP/Services
Thanks Peter.
We had a look at both Hab and habitat. These are integers representing
habitat types.
habitat - read.csv(Ungulate_vegetation.csv)
habitat - habitat[,3]
habitat
[1] 3 3 4 3 3 3 4 4 3 3 3 3 3 4 2 3 2 3 2 3
Hab - cbind(seq(1,20),habitat)
Hab
habitat
[1,] 1 3
[2,]
Hello, I am running Win XP in a notebook IEEE, I have R-2-15.0 and R-2.15.1. In
a subdirectory Cran I
have the packages I downloaded from CRAN (all), after last update when I type
library()
Error in .readRDS(pfile) : unknown input format
a very old R-2.4.0 sitting in a corner and not used for a
This looks like a homework trap set up to catch those trying to use facilities
like Rhelp.
f = exp(x^2-y+z^(-1))= exp(x^2) * exp(1/z)/exp(y)
To maximize clearly needs biggest x (37), smallest y (2) and a z that
makes exp(1/z) big -- 0. Except that you'll get Inf etc.
Actually, several of the
On 08.07.2012 14:08, hanansela wrote:
Hello
I am an Ubuntu 11.04 and R version 2.12 user. I am using Rkward as a GUI
for R . Some of the packages I need were build on 2.14. Therefore i need to
upgrade to 2.14. Rkward needs version 2.14 or less. but the version name
cant be with suffix like
On 08.07.2012 13:02, deeksha.malhan wrote:
Hi
I am working on co-expression analysis of rice dataset with the help of
wgcna and R but now I am at one point which is showing error as shown below
:
dissTOM = 1-TOMsimilarityFromExpr(datExpr, power = 8);
Error: cannot allocate vector of size
On 08.07.2012 16:51, R Heberto Ghezzo, Dr wrote:
Hello, I am running Win XP in a notebook IEEE, I have R-2-15.0 and R-2.15.1. In
a subdirectory Cran I
have the packages I downloaded from CRAN (all), after last update when I type
library()
Error in .readRDS(pfile) : unknown input format
On Jul 8, 2012, at 7:55 AM, SKrishna wrote:
Hi, Thanks for the reply.
Sex[120:144]-factor(TG) #Renaming some males to transgender, to
create 3 groups, male, female and transgender
Sorry, that should have been
Sex[120:144]-factor('TG')
The original line did not have the quotes.
I
In general, you should try to keep your version of R current rather than
lagging behind. If you would just search the Web yourself for keywords like
install R Ubuntu 11.04
you would find many discussions of this topic. A key file to read is [1]
[1]
Hello everyone,
I have a dataframe with 1 column and I'd like to replace that column
with a moving average.
Example:
library('zoo')
mydat - seq_len(10)
mydat
[1] 1 2 3 4 5 6 7 8 9 10
df - data.frame(V1 = mydat)
df
V1
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
10 10
On Jul 8, 2012, at 9:31 AM, Stathis Kamperis ekamp...@gmail.com wrote:
Hello everyone,
I have a dataframe with 1 column and I'd like to replace that column
with a moving average.
Example:
library('zoo')
mydat - seq_len(10)
mydat
[1] 1 2 3 4 5 6 7 8 9 10
df - data.frame(V1
On Jul 8, 2012, at 16:52 , John C Nash wrote:
This looks like a homework trap set up to catch those trying to use
facilities like Rhelp.
f = exp(x^2-y+z^(-1))= exp(x^2) * exp(1/z)/exp(y)
To maximize clearly needs biggest x (37), smallest y (2) and a z that
makes exp(1/z) big -- 0.
On 2012-07-08 06:57, fabiano wrote:
Thanks Peter.
We had a look at both Hab and habitat. These are integers representing
habitat types.
habitat - read.csv(Ungulate_vegetation.csv)
habitat - habitat[,3]
habitat
[1] 3 3 4 3 3 3 4 4 3 3 3 3 3 4 2 3 2 3 2 3
Hab - cbind(seq(1,20),habitat)
Hab
Your
On Sun, Jul 8, 2012 at 12:22 PM, Stathis Kamperis ekamp...@gmail.com wrote:
2012/7/8 Michael Weylandt michael.weyla...@gmail.com:
On Jul 8, 2012, at 9:31 AM, Stathis Kamperis ekamp...@gmail.com wrote:
Hello everyone,
I have a dataframe with 1 column and I'd like to replace that
Hello, All:
I think therefore I R, according to the header on several
R-Tutorials by William B. King, PhD, Coastal Carolina University
(http://ww2.coastal.edu/kingw/statistics/R-tutorials).
Might this be appropriate for fortunes?
Spencer
--
Spencer Graves, PE, PhD
On Sat, Jul 07, 2012 at 01:12:34PM +0100, Ted Harding wrote:
I had thought of also (as well as my numerical routing) suggesting
a gsub() type solution like Joshua's below, but held back because
the result could depend on how the number arose (keyboard input,
file input, or from computation
On Sun, 8 Jul 2012, Spencer Graves wrote:
Hello, All:
I think therefore I R, according to the header on several R-Tutorials
by William B. King, PhD, Coastal Carolina University
(http://ww2.coastal.edu/kingw/statistics/R-tutorials).
Might this be appropriate for fortunes?
Dear R People:
I'm starting to think that I should just install from the binary, but
here is my latest effort to install from source on a Windows 7 64 bit:
c:\R64\R-patchedcd src
cd src
c:\R64\R-patched\srccd gnuwin32/
cd gnuwin32/
c:\R64\R-patched\src\gnuwin32set TMPDIR=c:\temp
set
On Sun, Jul 08, 2012 at 11:39:22AM -0700, arun wrote:
Hi Petr,
I think sprintf and formatC are identical as it can round 22 decimal places
as opposed to print and signif
print(pi,digits=35)
Hi Arun:
Thank you for pointing this out. Funtion formatC()
is easier to use and uses the same C
On Sat, Jul 07, 2012 at 11:52:35AM +0300, Martin Ivanov wrote:
Dear R users,
I need a function that gets a number and returns its number of actual decimal
places.
For example f(3.14) should return 2, f(3.142) should return 3, f(3.1400)
should also return 2
and so on. Is such function
On Sun, Jul 8, 2012 at 2:32 AM, Diana Marcela Martinez Ruiz
dianamm...@hotmail.com wrote:
Hello,
I would like to know how to test the assumption of proportional odds or
parallel lines or slopes for an ordinal logistic regression with svyolr
I wouldn't, but if someone finds a clear reference
Should this not be attributed to DescaRtes?
Ted.
On 08-Jul-2012 18:41:17 Achim Zeileis wrote:
On Sun, 8 Jul 2012, Spencer Graves wrote:
Hello, All:
I think therefore I R, according to the header on several R-Tutorials
by William B. King, PhD, Coastal Carolina University
On 12-07-08 3:23 PM, Erin Hodgess wrote:
Dear R People:
I'm starting to think that I should just install from the binary, but
here is my latest effort to install from source on a Windows 7 64 bit:
It looks as though your path is messed up. You shouldn't have mingw32
tools on it.
The
The message concerning readline is common in compiling console mode
programs. If you search on readline, you'll learn what it does. Since
you are compiling source, the header files for the appropriate
libraries need to available in the path. You need to install the
readline and readline.h files
On Fri, 6 Jul 2012 21:13:32 +0530
umesh khatri khatriumes...@gmail.com wrote:
Dear everyone
I'm dealing with a problem related to Poisson Ridge Regression. If
anyone can help me in this regard by telling if any changes in the
source code of glm.fit may help
You've posted this problem
Hi,
As the error says, the replacements should have equal number of rows.
You can either do it adding NAs,
df$V1-c(NA,rollapply(df$V1,3,mean),NA)
df
V1
1 NA
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
10 NA
#or,
#use any of these
#as Michael suggested
df2-rollapply(df,3,mean,fill=NA)
Hi Petr,
I think sprintf and formatC are identical as it can round 22 decimal places as
opposed to print and signif
print(pi,digits=35)
Error in print.default(pi, digits = 35) : invalid 'digits' argument
signif(pi,digits=22)
[1] 3.141593
a-sprintf(%.35f,pi)
a
[1]
Thank you very much Professor. David L Carlson .. This method saves my time!!
--
View this message in context:
http://r.789695.n4.nabble.com/Declaring-a-density-function-with-for-loop-tp4635699p4635795.html
Sent from the R help mailing list archive at Nabble.com.
Hi,
I have great difficulty in simulation the a dataset based in a loading
matrix [c(1,1,1,2,3,3,3,4,4,3,2,2,1,1), 7, 2) and an error covariance matrix
is 2*I. I have to simulate a dataset with 7 variables and 50 rows. I search
a lot and did find some information on this, for example, using
Hello,
I'm coming straight to the point:
I have 65 .txt-Files named XYZ_1.txt to XYZ_65.txt (each number
represents a test subject).
I have to open them in Microsoft Excel to see the exact structure.
In each of those .txt-files there are reaction time values (in milliseconds)
from line 15,
Since you did not provide an example of the file, I will take a guess
at the content and show to to extract the values and take the mean of
all of them since you did not say if you want the mean of each file,
or a single means.
myData - do.call(c, lapply(1:65, function(.file){
x -
Dear useRs
I need to do graphs with dates in different languages on Ubuntu.
In Windows the following will plot the date axis labels in Spanish:
random.dates - as.Date(2001/1/1) + 70*sort(stats::runif(100))
language - Spanish
Sys.setlocale(LC_TIME, language)
plot(random.dates, 1:100, xaxt=n)
Hi,
I want using zero-inflated negative binomial regression model to
classify data(a vector of data), that is I want know each observed value is
more likely belong to the zero or count distribution(better with
relative probability). My data is some like:
count site samp
1290911
Hello:
What is the recommended method for retaining the tzone attributes
when concatonating POSIXct objects?
(d1 - ISOdate(1970,1,1)) # Sets the tzone attribute = GMT
[1] 1970-01-01 12:00:00 GMT
(d1.2 - c(d1, d1)) # c(..) strips the tzone attribute, displays in
the time zone of
54 matches
Mail list logo
