Dear Paul,
Thank you for helping. This works great.
I then tried to put in a grid (via grid()). Why does that fail?
Cheers,
Marius
require(grid)
require(gridBase)
pdf(file=Rplot.pdf, width=8, height=8, onefile=FALSE)
## set up the grid layout
plot.new() # start (empty) new page with
ggpairs() from GGally is fantastic, but I'm stuck trying to change the diagonal
labels and increase the size of the font in the diagonal axis plots.
I thought using ggally_diagAxis(... labelSize) would work, but it doesn't
appear to. I've tried the following three approaches, all of which
Dear Jeff,
Thanks for helping.
I thought that gridBase would take care of using simple 'graphics' and grid
plots (?)
I tried grid.grill, but it's not so trivial to set it up such that the grid is
drawn at the axis ticks.
Cheers,
Marius
Jeff Newmiller jdnew...@dcn.davis.ca.us writes:
Same
Le lundi 24 septembre 2012 à 13:22 +1000, Chintanu a écrit :
Hi,
I have two dataframes (Dataframe_A, Dataframe_B) with the same no. of
columns. The first column of both the dataframes contains unique names.
I wish to have Dataframe_A with the rows that are NOT common to
Dataframe_B.
So you
Le lundi 24 septembre 2012 à 11:25 +0530, Vignesh Prajapati a écrit :
Hello all,
I am new to R, I am learning regression and logistic modeling
with categorical predictor variables, when there is only one predictor
categorical variable i can use as.numeric() but when more than two
Hi Michelle,
Please cc the list on your replies so others (far more knowledgeable
than I) can answer.
On Mon, Sep 24, 2012 at 12:12 AM, Michelle Cipullo mlcip...@ncsu.edu wrote:
I am doing some extreme value analysis on model output (WRF) which have the
following dimensions:
Hello
I have a list of POSIXct objects, from which I want to extract those
values that match a specific date, keeping them in POSIXct format. For a
specific date there is 0-2 matching values.
As an example (the actual list and objects are much longer):
x-list()
Same reason.
grid() is part of base graphics, which are incompatible with grid graphics.
Perhaps you want grid.grill(), which you could find out about in the grid
graphics vignette mentioned earlier.
---
Jeff Newmiller
What is it you think as.numeric accomplishes for you? A reproducible example as
requested in the posting guide might clarify.
Making factors and leaving them that way seems more productive.
---
Jeff Newmiller
Hello,
It is pretty basic, and it is deceptively simple. The worst of all :)
When you index a matrix 'x' by another matrix 'z' the index can be a
logical matrix of the same dimensions or recyclable to the dims of 'x',
it can be a matrix with only two columns, a row numbers column and a
column
Hi everyone,
I have a problem to assign a value with tcl/tk
ths is the code ( it should be simple to understand) :
library(tcltk)
valA-tclVar(0)
valB-tclVar(0)
valC-tclVar(0)
id-A
out-1
out2-2
print(paste(tclvalue(val,id,),sep=)) # ok
print(as.name(paste(tclvalue(val,id,),sep=))) #ok
On Sep 24, 2012, at 10:27 , vincent guyader wrote:
Hi everyone,
I have a problem to assign a value with tcl/tk
Not really. You'll get into the same sort of trouble if you try other kinds of
complex assignments:
a - 1:2
eval(as.name(a))[[1]]
[1] 1
eval(as.name(a))[[1]] - 3
Error in
Hi
before you can use predict you need to do lm(whatever.). If you used
lm(whatever., na.action=na.exclude)
predict will give you results with correctly placed NA values.
Regards
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
Hi,
I have a scatter plot of the variables GNI and Lifeexp (Gross National
Income and Life Expectancy, both metric). So I plotted them and I want to
add a regression line and a lowess line. I use lowess and not loess because
I have missing values. My code:
plot(GNI,Lifeexp)
abline(lm(Lifeexp~GNI),
Note, trait richness would be 5 and not 4 at site 1 perfectly
demonstrating why I want to create a script rather than manually count!
--
View this message in context:
http://r.789695.n4.nabble.com/Script-to-count-unique-values-from-two-linked-matricies-tp4643979p4643980.html
Sent from
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Niklas Fischer
Sent: Thursday, September 20, 2012 11:13 PM
To: r-help@r-project.org
Subject: [R] creating new variable
Dear R-helper
I have a data which is about
Hi Petr,
Please see the attached .csv files - perhaps these will help,
Thanks,
Ben Gillespie
Research Postgraduate
School of Geography
University of Leeds
Leeds
LS2 9JT
Tel: +44(0)113 34 33345
Mob: +44(0)770 868 7641
http://www.geog.leeds.ac.uk/
From:
Please see the attached .csv files for further info,
Thanks guys,
Ben Gillespie
Research Postgraduate
School of Geography
University of Leeds
Leeds
LS2 9JT
Tel: +44(0)113 34 33345
Mob: +44(0)770 868 7641
http://www.geog.leeds.ac.uk/
From: PIKAL Petr
Hi guys,
It would be great if you could help me with this one...
I'm looking to create a script to convert a matrix of species abundance e.g:
http://r.789695.n4.nabble.com/file/n4643978/species_matrix.jpg
into two vectors e.g:
http://r.789695.n4.nabble.com/file/n4643978/communitylist.jpg
Hello,
I have a vector (numeric) v- c(a,b,c,d,e) and I want to create the vector
n-c(b-a,c-b,d-c,e-d). How can I do that?
Thank you
Hermann
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
I hope you can help with this one.
I have two matricies:
1. A species abundance matrix:
http://r.789695.n4.nabble.com/file/n4643979/2species_matrix.jpg
2. A species trait score matrix:
http://r.789695.n4.nabble.com/file/n4643979/2trait_matrix.jpg
The trait matrix lists trait scores for
Hello,
Try diff(v)
Hope this helps,
Rui Barradas
Em 24-09-2012 12:00, Hermann Norpois escreveu:
Hello,
I have a vector (numeric) v- c(a,b,c,d,e) and I want to create the vector
n-c(b-a,c-b,d-c,e-d). How can I do that?
Thank you
Hermann
[[alternative HTML version deleted]]
On our local cluster, users relatively routinely crash the head node
by doing simple and silly things that inadvertently eat all memory and
crash the head node. I read a bit about memory limits, but I am still
a bit unclear as to whether memory limits can be imposed a the R level
under linux.
Hi
Your attachment came scrambled. Something wrong with dput?
anyway
having
mat-matrix(1:6, 3,2)
df-as.data.frame(mat)
df$species-letters[1:3]
df
V1 V2 species
a 1 4 a
b 2 5 b
c 3 6 c
library(reshape)
melt(df, id=species)
species variable value
1 a
Hi
I suppose you want
diff(v)
Regards
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Hermann Norpois
Sent: Monday, September 24, 2012 1:01 PM
To: r-help@r-project.org
Subject: [R] serial subtraction within a vector
?diff
HTH,
Jorge.-
On Mon, Sep 24, 2012 at 9:00 PM, Hermann Norpois hnorp...@googlemail.comwrote:
Hello,
I have a vector (numeric) v- c(a,b,c,d,e) and I want to create the vector
n-c(b-a,c-b,d-c,e-d). How can I do that?
Thank you
Hermann
[[alternative HTML version deleted]]
Hello,
See also ?setdiff
Hope this helps,
Rui Barradas
Em 24-09-2012 08:30, Milan Bouchet-Valat escreveu:
Le lundi 24 septembre 2012 à 13:22 +1000, Chintanu a écrit :
Hi,
I have two dataframes (Dataframe_A, Dataframe_B) with the same no. of
columns. The first column of both the dataframes
Hello everyone,
at the moment I'm using the tgp package for modelling a nonstationary
data set on a two dimensional area D and I'm interested in the
prediction and the estimated covariance matrix. For this purpose I'm
using the function btgp. As far as I understand, btgp uses a MCMC
Instead of attachments, put the out
On 24 September 2012 01:58, Maximilian Lklweryc maxlklwe...@gmail.comwrote:
Hi,
I have a scatter plot of the variables GNI and Lifeexp (Gross National
Income and Life Expectancy, both metric). So I plotted them and I want to
add a regression line and a
Hi
I do not understand your point.
actually
lm(y~x) is the same as lm(y~x+1)
You can specify a model without intercept by
lm(y~x-1)
you can even do
lm(y~log(x))
But log(intercept) does not have sense. You will get an intercept which is a
number and you can consider it
log(intercept)
Hi Arun,
I've just run through that - thanks so much, it worked perfectly. Learnt lots
of new commands too :)
Thanks for all your help - awesome!
ps. the only thing I changed was to remove the '0' from the first line after
'paste'.
Ben Gillespie
Research Postgraduate
School of Geography
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of benrgillespie
Sent: Monday, September 24, 2012 1:20 PM
To: r-help@r-project.org
Subject: [R] List creation based on matrix
Hi guys,
It would be great if you could help
Hi
I have no access to Nabble so it is difficult to understand what do you want.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of benrgillespie
Sent: Monday, September 24, 2012 1:47 PM
To: r-help@r-project.org
Subject: [R]
Dear R-users,
I am trying to add some text in a textbox to all panels in the following
example file. Using the panel-function, I can add a white rectangle with
panel.rect but then I have to fit in the text into the box by hand and it
will not automatically be centered. Does anyone know how to add
Hello,
Like this your data example is unusable, how can we reproduce it?
Please use dput() to post data. Example:
# Make up some data.
x - data.frame(A = letters[1:5], X = 1:5)
# Paste the output of this in a post
dput(x)
structure(list(A = structure(1:5, .Label = c(a, b, c, d,
e), class =
Richness should look like this:
http://r.789695.n4.nabble.com/file/n4644004/trait_richness.jpg
--
View this message in context:
http://r.789695.n4.nabble.com/Script-to-count-unique-values-from-two-linked-matricies-tp4643979p4644004.html
Sent from the R help mailing list archive at
To whom I concern,
I am a recent user of program R
I do not know how to explain this but after I installed the program the
words on the scrpit does R console does not appear clear
but something square(?)/Cube(?) which seems like the words are broken
More suprisingly, the squared words are
HI,
Try this:
dat1-do.call(data.frame,x)
dat1-data.frame(ID=letters[1:4],dat1)
dat1
# ID first second
#1 a 2011-08-27 10:45:00 2011-08-27 11:00:00
#2 b 2011-10-30 15:45:00 2011-10-30 15:30:00
#3 c 2011-10-30 16:00:00 2011-10-30 15:45:00
#4 d 2012-06-22 09:30:00
Hi,
#Just to add:
v-c(3,5,8,4,9)
diff(v)
#[1] 2 3 -4 5
#if it is a dataframe,
v1-as.data.frame(v)
lapply(v1,diff)
apply(v1,2,diff)
A.K.
- Original Message -
From: Jorge I Velez jorgeivanve...@gmail.com
To: Hermann Norpois hnorp...@googlemail.com
Cc: r-help@r-project.org
Sent:
Hi,
Try this:
set.seed(1)
Dataframe_A-data.frame(x=sample(1:10,5,replace=TRUE),y=rnorm(5,15))
set.seed(1)
Dataframe_B-data.frame(x=sample(3:15,6,replace=TRUE),z=rnorm(6,10))
Dataframe_A[!Dataframe_A[[1]] %in% Dataframe_B[[1]],] # Milan's code had
...B[[2]]
#or
Hi,
Couldn't find your attachment.
But, from Nabble, I saw the data.
Try
this:dat1-data.frame(Species=paste0(Species,1:6),Site1=c(5,NA,4,NA,3,NA),Site2=c(4,NA,4,4,NA,4),Site3=c(NA,5,NA,NA,NA,NA),Site4=c(NA,NA,NA,6,5,NA))
dat2-melt(dat1)
dat3-dat2[!is.na(dat2$value),]
dat3-dat3[,1:2]
Dear R experts,
I got help to build a loop but there is a bug inside it that causes
one part of the mechanism to fail.
It should grow once, but if keep growing on rows where $ti_all is not NA.
Here is a wall of code that very crudely demonstrates the problem,
there is a couple of dim() outputs
A.K., many thanks for your reply.
I have realised there was a mistake in my code, and that the example
could have been clearer; my apologies for this, the corrected code is below:
x-list()
x[[a]]-as.POSIXct(c(2011-08-27 10:45:00 GMT, 2011-10-30
15:45:00 GMT, 2011-10-30 16:00:00 GMT,
Hi Team,
Need your guidance in building SPDF objects from Latitude, Longitude
Information available.
I am using package plotGoogleMaps which is really awesome but it requires
SPDF objects to build the maps.
I have a data frame which have Latitude and Longitude information and
wanted to convert it
Great, thanks,
Ben Gillespie
Research Postgraduate
School of Geography
University of Leeds
Leeds
LS2 9JT
Tel: +44(0)113 34 33345
Mob: +44(0)770 868 7641
http://www.geog.leeds.ac.uk/
From: Jeff Newmiller [jdnew...@dcn.davis.ca.us]
Sent: 24 September 2012
You might wish to post on the R-sig-geo list instead if you are
involved with spatial data.
-- Bert
On Mon, Sep 24, 2012 at 8:02 AM, Bhupendrasinh Thakre
vickytha...@gmail.com wrote:
Hi Team,
Need your guidance in building SPDF objects from Latitude, Longitude
Information available.
I am
On 24.09.2012 18:40, Gyanendra Pokharel wrote:
What is the newest version of package knnFinder? because it was removed
from the CRAN repository.
Actually it has been archived. There are typically reasons for it (e.g.
not passing the checks any more).
Try this; does away with the 'for', but have to convert back to
POSIXct since sapply strips off the class:
x-list()
x[[a]]-as.POSIXct(c(2011-08-27 10:45:00 GMT, 2011-10-30 15:45:00 GMT,
2011-10-30 16:00:00 GMT, 2012-06-22 09:30:00 GMT, 2012-06-22 10:00:00
GMT))
Dear useRs,
does anyonw now how to avoid [ reached getOption(max.print) -- omitted 138
rows]. i read from the R forum that it can be avoided by increasing the
'max.print' option as much as i like, but i dnt know, how??
need your help on it.
regards
eliza
Hi everyone,
want to use R in our company but have to complete an intern questionnaire
first. Can anyone help? Thanks in advance!
Here the questions Im not sure about:
1. Is R a Clientsoftware / Serversoftware / Systemsoftware?
2. Does R need a chellenge-response treatment for
Thanks Rui Barrudas and Peter Alspach,
I understand better now:
x-matrix(c(1,0,0,0,2,0,0,0,2),nrow=3)
y-matrix(c(7,8,9,1,5,10,1,1,0),nrow=3)
z-matrix(c(0,1,0,0,0,0,6,0,0),nrow=3)
x[z]-y[z]
viewData(x)
produces an x matrix
7 0 0
0 2 0
0 10 2
which makes sense the first
I am one half of the RCE podcast (www.rce-cast.com). We would like to feature
R on the show,
We would like a dev or two for about an hour on the phone or skype to chat
about R its history and general information for an HPC/RC focused crowed.
Feel free to contact me off list if you would like
Hi Martin,
did you ever find a solution? I have the a similar problem because I want to
do a regression where the independent and dependent variables are matrices
of measurements. I can run loops to make each matrix one very long vector,
but I m looking for a more elegant solution.
Thank you!
Thanks - not sure why it came through scrambled.
This has now been solved - thanks for your help,
Ben Gillespie
Research Postgraduate
School of Geography
University of Leeds
Leeds
LS2 9JT
Tel: +44(0)113 34 33345
Mob: +44(0)770 868 7641
http://www.geog.leeds.ac.uk/
?options will tell you how to access and set the max.print option, and
all the other options that R has.
Sarah
On Mon, Sep 24, 2012 at 1:08 PM, eliza botto eliza_bo...@hotmail.com wrote:
Dear useRs,
does anyonw now how to avoid [ reached getOption(max.print) -- omitted 138
rows]. i read
I have a table with approximately 1000 actual stock returns and forecasted
stock returns per month. I want to calculate rolling correlations for
rolling 12-month periods. All of the rolling correlation solutions I've
seen are for cases where there is just one row per time period. How can I
do
thnx sarah,
it was
options(max.print=100)
regards
eliza
Date: Mon, 24 Sep 2012 13:14:30 -0400
Subject: Re: [R] [ reached getOption(max.print) -- omitted 138 rows]
From: sarah.gos...@gmail.com
To: eliza_bo...@hotmail.com
CC: r-help@r-project.org
?options will tell you how to
Hi,
Upon running your code, the y I am getting is:
y
# ID first second
#1 a 1320003900 1320004800
#2 b 1320003000 1320003900
This you can convert back by:
within(y,{first-as.POSIXct(first,origin=1970-01-01);second-as.POSIXct(second,origin=1970-01-01)})
# ID first
Hi,
In my research I am studying the marginal models, where the main goal is on
the structure of the association.
My practical example has cluster with up to 600 observations and with this
database, the function geese() return me the following message:
This application has requested the
Is GNI sorted? if not then the lines function plots the line segments
to the points in the order given and that would explain part of the
strangeness (the png file did not make it through). Are there gaps
between the GNI values? even if GNI is sorted, your code below will
just draw line
Hi Dr. Lumley, you're obviously correct about all of that. Thank you for
cluing me into it! And sorry for overlooking that part of the
documentation.
I'm unfortunately still struggling with matching numbers exactly, and I
foolishly provided a dataset without a weight variable - thinking there
Hi,
You can also try this:
x1-list(a=data.frame(x[[a]]),b=data.frame(x[[b]]))
library(plyr)
x2-do.call(rbind.fill,x1)
colnames(x2)-c(a,b)
x2first-subset(x2,format(a,%Y-%m-%d)==2011-10-30 )
x2second-subset(x2,format(b,%Y-%m-%d)==2011-10-30 )
Hello,
Inline.
Em 24-09-2012 15:31, Bazman76 escreveu:
Thanks Rui Barrudas and Peter Alspach,
I understand better now:
x-matrix(c(1,0,0,0,2,0,0,0,2),nrow=3)
y-matrix(c(7,8,9,1,5,10,1,1,0),nrow=3)
z-matrix(c(0,1,0,0,0,0,6,0,0),nrow=3)
x[z]-y[z]
viewData(x)
produces an x matrix
7 0
Good evening to all.
I find myself trying to create some Thiessen Polygons, in order to finish a
meteorology research.
This is the script I found to create the Polygons:
*
*
*voronoipolygons - function(x) {*
* require(deldir)*
* if (.hasSlot(x, 'coords')) {*
*crds - x@coords *
*} else
Hi,
I'm looking to install ‘R’ on an application server which we can give
plenty of resource to, and actually run the program from a terminal server.
Do you know if this is possible, and if so are there any special
installation instructions required?
Many thanks,
D
--
View this message in
Hi
On 24/09/12 18:06, Marius Hofert wrote:
Dear Paul,
Thank you for helping. This works great.
I then tried to put in a grid (via grid()). Why does that fail?
Because grid() is used to add lines to an existing plot; just put the
grid() call AFTER the plot() call and it should work ok.
I've just reread my answer and it's not very clear. Not at all. Inline.
Em 24-09-2012 18:34, Rui Barradas escreveu:
Hello,
Inline.
Em 24-09-2012 15:31, Bazman76 escreveu:
Thanks Rui Barrudas and Peter Alspach,
I understand better now:
x-matrix(c(1,0,0,0,2,0,0,0,2),nrow=3)
Dear R People:
I'm working on a project that will pass a matrix from an R function to
a C subroutine.
I tried to write the following:
#includeR.h
#includeRinternals.h
void lu1(int *n, float *a, float *b, float *ab)
{
int i,k,j,p,na=*n+10;
float sum, l[200][200],u[200][200]z[200];
Hello,
I am making a boxplot of 13 boxes.
I tried to color the box using 13 colors but failed.
Only red and brown were displayed.
Green, blue, and grey disappeared.
Please kindly advise modification after checking the code below.
Thank you in advance.
Elaine
R code
# data input
dataN
Erin,
you seem to confuse R and C syntax a bit, among other things. See below.
On Mon, Sep 24, 2012 at 3:03 PM, Erin Hodgess erinm.hodg...@gmail.com wrote:
Dear R People:
I'm working on a project that will pass a matrix from an R function to
a C subroutine.
I tried to write the following:
Is anyone familiar with a way to test for differences in the x-intercepts (not
y-intercepts) of two simple linear regression lines in R? I'm familiar with a
method to calculate standard error estimates of the x-intercept
(http://www.mail-archive.com/r-help@r-project.org/msg50241.html), and
Hi Elaine,
Without a reproducible example it's impossible to say, but I'd take a
hard look at:
table(obs.group)
If that doesn't give you some insight, a small reproducible example
included in your email using dput() would allow us to answer you more
effectively.
Sarah
On Mon, Sep 24, 2012 at
## I would do this in lattice using the panel.bwplot.intermediate.hh
## function from the HH package.
## install.packages(HH) ## if necessary
library(HH)
dataN - data.frame(GE_distance=rnorm(260),
Diet_B=factor(rep(1:13, each=20)))
Diet.colors - c(forestgreen,
I am working with some large text files (up to 16 GBytes). I am interested
in extracting the words and counting each time each word appears in the
text. I have written a very simple R program by following some suggestions
and examples I found online.
If my input file is 1 GByte, I see that R
Dear Paul,
Thanks for helping. Is there a way to call grid() first? The problem seems to be
that everything drawn before grid() is overplotted.
Cheers,
Marius
require(grid)
require(gridBase)
pdf(file=Rplot.pdf, width=8, height=8, onefile=FALSE)
## set up the grid layout
plot.new() # start
Hello,
Also, R uses doubles, not floats.
Hope this helps,
Rui Barradas
Em 24-09-2012 23:27, Peter Langfelder escreveu:
Erin,
you seem to confuse R and C syntax a bit, among other things. See below.
On Mon, Sep 24, 2012 at 3:03 PM, Erin Hodgess erinm.hodg...@gmail.com wrote:
Dear R People:
Hi
On 25/09/12 11:50, Marius Hofert wrote:
Dear Paul,
Thanks for helping. Is there a way to call grid() first? The problem seems to be
that everything drawn before grid() is overplotted.
No, but you can redraw the points ...
require(grid)
require(gridBase)
pdf(file=Rplot.pdf, width=8,
Hi
Here's a panel function that does what I think you want (NOTE that you
need to load 'grid' for this to work) ...
library(grid)
panel.tpop - function(x,y,...){
panel.grid(h=length(agegrs),v=5,col=lightgrey,lty=1)
ls1 - list(...)
y - y
iFrame - iEduDat[ls1$subscripts,]
In the first and third examples it looks as though confint(svymean())
matches the totals and svyciprop(method=logit) matches the
proportions, which is what Stata says
(http://www.stata.com/statalist/archive/2006-10/msg01127.html). The
agreement isn't perfect for the counts in the first example,
Hello Richard,
Your answer is a great help to my problem.
The boxplot of 13 colors is very beautiful :)
By the way, I have three subsequent questions of your code
1. the meaning of pch=rep(|,13)
I read the R manual but could not interpret the part.
pch means the point type in plot, but here
Hello Sarah,
Thanks for the suggestion of
table(obs.group).
I checked it and found no problems of the obs.group.
As for using dput(),
please kindly share some examples to display the colored graph in r-help.
In fact, some colors were assigned to all types of diets, like
A=red1
B=red2
C=green1
Does the function parallel work for windows ?
Tjun Kiat
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
Hello,
I want to draw a boxplot using 13 colors for 13 boxes.
Each box represents a type of diet of birds.
Y axis is the breeding range of the birds.
I checked the previous r-help and found a possible solution.
However, it did not work by showing error in ncol(Diet_B), Diet_B not
found.
Please
See ?panel.bwplot for pch=|.
That explains that pch=| puts horizontal lines instead of dots at the
median(and also at the
outliers).
The rep makes it into a vector to be indexed by panel.bwplot.intermediate.hh
in each of its calls to panel.bwplot
The names under each plot are the levels of the
Dear R users,
Which test is most appropriate in glm when the family is Gamma?
In the help page of anova.glm, I found the following
“For models with known dispersion (e.g., binomial and Poisson fits) the
chi-squared test is most appropriate, and for those with dispersion estimated
by moments
Hello all,
I don't understand a strange behavior in data frame manipulation.
data_frame1 = data.frame(Site = c(S1, S2, S3, S4, L1, L2,
L3, L4),
Number = c(1, 3, 5, 2, 1, 1, 2, 1))
data_frame2 = data_frame1 [data_frame1$Site != S1, ]
dput (data_frame2)
Le 25/09/12 05:35, Tjun Kiat Teo a écrit :
Does the function parallel work for windows ?
Tjun Kiat
Try to reproduce these exemples and you will have your answer:
http://max2.ese.u-psud.fr/epc/conservation/Girondot/Publications/Blog_r/Entrees/2012/8/25_First_steps_with_parallel_running.html
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