try:
install.packages(ROCR,dep=T)
M.O
On to., 2012-11-22 at 16:02 +1000, Philip Robinson wrote:
I have tried installing the package (ROCR) with this command:
Install.packages(ROCR)
And with this command on the command line
R CMD INSTALL ROCR_1.0-4.tar.gz
But
It's hard to answer these questions without knowing what the errors are and
how they can be reproduced.
Best, Ingmar
On Thu, Nov 22, 2012 at 1:03 AM, KitKat katherinewri...@trentu.ca wrote:
Thanks, I have been trying that site and another one
(http://www.statmethods.net/advstats/cluster.html)
My version is:
Linux bioinform08 2.6.32-33-generic #70-Ubuntu SMP Thu Jul 7 21:13:52 UTC
2011 x86_64 GNU/Linux
Ubuntu 10.04.3 LTS
R version 2.10.1 (2009-12-14)
Philip
-Original Message-
From: Pascal Oettli [mailto:kri...@ymail.com]
Sent: Thursday, 22 November 2012 4:20 PM
To: Philip
Hi Mohammed,
This didn't work either:
Error in setMethod(plot, signature(x = performance, y = missing), :
no existing definition for function plot
Error : unable to load R code in package 'ROCR'
ERROR: lazy loading failed for package ‘ROCR’
* removing
Very old version. Maybe you should try again after upgrading your
version of R (current is 2.15.2).
Pascal
Le 22/11/2012 18:11, Philip Robinson a écrit :
My version is:
Linux bioinform08 2.6.32-33-generic #70-Ubuntu SMP Thu Jul 7 21:13:52 UTC
2011 x86_64 GNU/Linux
Ubuntu 10.04.3 LTS
R
Dear All,
Some of the functions in Linkcomm return an error:
unused argument(s) (v = V(x$igraph))
Although I follow the guidance in the manual a number of the functions
return this error. The igraph vector is an edgelist.
Many thanks for any guidance.
Best,
Nick
Hello,
I am using the mda package and in particular the fda routine to
classify/predict in terms of color to a set of 20 samples for which i don´t
know the color.
I preformed a flexible discriminant analysis (FDA) using a set of 147
samples for which i know all the information.
My script
Thanks.
--
View this message in context:
http://r.789695.n4.nabble.com/Stepwise-analysis-with-fixed-variables-tp4650015p4650419.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
Hello,
I am trying to install RPostgreSQL, but without success at the moment, getting
an errormessage - see below.
My OS is Fedora 17, R version 2.15.2, PostgreSQL 9.2.1 with Postgis 2.0.1
spatial extension.
Thank You for any help, advice or hint in advance.
Regards
Tomas
Hello,
I try to increase the distance between tick labels and ticks in a lattice
wireframe plot. Here's a minimal example:
## Minimal example
x - y - z - c(1,2,3)
df - data.frame(x, y, z)
wireframe(z ~ x*y, df, scales = list(arrows = FALSE, col = black, font = 1,
tck=0.6))
I tried the
Hi,
I m working on R and read one image with russian font using readjpeg()
function and write it on pdf (using grid). But russian text is not visible
on pdf. How can i fix my pblm?
Regards http://r.789695.n4.nabble.com/file/n4650417/pointer.jpg
library(JPEG)
library(grid)
pdf(out.pdf , width =
I found this code through internet and I have a one doubt about this example,
which is
Here you take a 70% random sample considering all the values but what I want is
if the selected sample contains p1,p2 then I want all records of p1,p2 and also
remaining data in some other data frame...like
Hello,
Do you have the shared libraries required by PostgreSQL installed on
your machine (libpq)?
Regards,
Pascal
Le 22/11/2012 18:45, lanc...@t-zones.sk a écrit :
Hello,
I am trying to install RPostgreSQL, but without success at the moment, getting
an errormessage - see below.
My OS is
On 11/22/2012 05:15 AM, Rosario Scandurra wrote:
Hi,
I want to generate an histogram and plot on the y axis the percentage of a
categorical variable and on the x axis a nominal variable. I want to move
the origin to have 2 categories below 0. Hope somebody could help me.
Thanks.
Hi Rosario,
Hello,
I'm glad it helped.
You should have kept this in the list, the odds of getting more answers
are bigger.
As for your problem with NAs, what do you want to do with them? Should
they count as within range?
Rui Barradas
Em 22-11-2012 10:18, Helene Frigstad escreveu:
Hi,
yes, that is a
On Thu, Nov 22, 2012 at 4:01 AM, Sam Steingold s...@gnu.org wrote:
Hi,
* arun fznegcvax...@lnubb.pbz [2012-11-21 14:04:36 -0800]:
Are you looking for some other function (difftime2string)
ot just remove the quotes from the printed output?
I am wondering what others do when they want to see
Dear members,
I have a series of values in a vector and some value are missing and
replaced with NA.
For example:
a - c(27, 25, NA, NA, 24, 26, 27, NA, 26)
I would like to replace the NAs with the value taken from the previous
value that is non-NA. The output would be in this case:
27 25 25
Take a look at
na.locf()
in the zoo package. (LOCF = last observation carried forward)
RMW
On Thu, Nov 22, 2012 at 12:56 PM, Marc Girondot marc_...@yahoo.fr wrote:
Dear members,
I have a series of values in a vector and some value are missing and
replaced with NA.
For example:
a - c(27,
Dear Marc,
Try
require(zoo)
na.locf(a)
HTH,
Jorge.-
On Thu, Nov 22, 2012 at 11:56 PM, Marc Girondot wrote:
Dear members,
I have a series of values in a vector and some value are missing and
replaced with NA.
For example:
a - c(27, 25, NA, NA, 24, 26, 27, NA, 26)
I would like to
Hi again,
I was thinking that the interval would stop when there was a NA, ignore
subsequent NAs and only start a new interval when there was a new value. So
in the example below, the interval would stop at row 320, and a new interval
started at row 334.
head (D, 20)
Salt time
319
Dear BioConductor and R fellow users
I apologize in advance for double posting, but I am not sure which list would
actually be best fit for this message.
I am experiencing a weird error with my R installation on Ubuntu 10.04.4 (LTS)
64bit:
When I run R on the terminal everything goes
Hello,
I would appreciate if someone could help me resolve the following:
1. df1[!is.na( X1 | X2 | X3 | X4 | X5),][,1:5] # This does not work
2. Is these message harmful? The following object(s) are masked from 'df1
(position 3)':
X1, X2, X3, X4, X5
Thanks,
Pradip Muhuri
#Reproducible
Hello mrzung,
it depends on several factors.
First of all: do your clients use RApache for computations in separate
sessions (possible which computations does not build on the previous ones)
or do they need a stateful application?
The first would be pretty easy to resolve, just clean the R
Hi,
is.na( X1 | X2 | X3 | X4 | X5)
isn't a valid construct.
You'd need
!(is.na(X1) | is.na(X2) etc )
Or more elegantly
df1[apply(df1, 1, function(x)all(!is.na(x))), ]
Sarah
On Thursday, November 22, 2012, Muhuri, Pradip (SAMHSA/CBHSQ) wrote:
Hello,
I would appreciate if someone could help
Hi
do you want this?
df1[complete.cases(df1),]
X1 X2 X3 X4 X5
2 8 8 3 2 10
6 8 6 7 10 1
11 4 5 5 10 8
12 6 1 7 8 4
17 5 7 3 1 3
18 10 7 3 8 7
19 7 5 3 5 6
20 10 5 2 4 6
Regards
Petr
-Original Message-
From: r-help-boun...@r-project.org
Dear all,
i try to plot with ggplot2. Therefor I have an matrix with 3 colums. With cbind
I add an additional column called col. I need this column col because in a
later step and want to specify here some plot details which I will get from
another analysis
If I want to plot with this code, I
Your questions are all but unanswerable. Read the posting guide and
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
---
Jeff NewmillerThe . .
On 22-11-2012, at 15:11, Muhuri, Pradip (SAMHSA/CBHSQ) wrote:
Hello,
I would appreciate if someone could help me resolve the following:
1. df1[!is.na( X1 | X2 | X3 | X4 | X5),][,1:5] # This does not work
2. Is these message harmful? The following object(s) are masked from 'df1
Unnecessarily complicated. ?na.omit (linked from ?complete.cases)
df - na.omit(df)
-- Bert
On Thu, Nov 22, 2012 at 6:49 AM, Berend Hasselman b...@xs4all.nl wrote:
On 22-11-2012, at 15:11, Muhuri, Pradip (SAMHSA/CBHSQ) wrote:
Hello,
I would appreciate if someone could help me resolve
Petr,
You have shown a solution that is the simplest.
Thanks and regards,
Pradip Muhuri
Beginner useR
From: PIKAL Petr [petr.pi...@precheza.cz]
Sent: Thursday, November 22, 2012 9:33 AM
To: Muhuri, Pradip (SAMHSA/CBHSQ); r-help@r-project.org
Subject:
Hi Bert,
Your solution is similar to Petr's.
Thanks and regards,
Pradip Muhuri
BeginneR UseR
From: Bert Gunter [gunter.ber...@gene.com]
Sent: Thursday, November 22, 2012 10:20 AM
To: Berend Hasselman
Cc: Muhuri, Pradip (SAMHSA/CBHSQ);
Hi Berend,
You have compared all 3 ways. ... very nicely evaluated.
Thanks and regards,
Pradip Muhuri
Beginner UseR
From: Berend Hasselman [b...@xs4all.nl]
Sent: Thursday, November 22, 2012 9:49 AM
To: Muhuri, Pradip (SAMHSA/CBHSQ)
Cc:
HI Madhu,
I guess you got your solution from Rui:
dat1-data.frame(x=c(1,1,2,2,2,3,4,4,4),y=c(23,45,87,46,78,12,87,79,76))
s-sample(unique(dat1[,1]),length(unique(dat1[,1]))*0.8)
s
#[1] 3 4 2
You can have a list containing both the dataframes
list1-list(dat1[dat1$x%in%s,],dat1[!dat1$x%in%s,])
Hi Sarah,
I am glad you have precisely caught where I made the mistake. Thank you so
much.
regards,
Pradip Muhuri
From: Sarah Goslee [sarah.gos...@gmail.com]
Sent: Thursday, November 22, 2012 9:21 AM
To: Muhuri, Pradip (SAMHSA/CBHSQ)
Cc:
On 22-11-2012, at 16:50, Muhuri, Pradip (SAMHSA/CBHSQ) wrote:
Hi Berend,
You have compared all 3 ways. ... very nicely evaluated.
Bert's solution is indeed nice and simple. But Petr's solution is still the
quickest:
N - 10
set.seed(13)
df -
a) Don't crosspost. Read the posting guide(s) for more cautions. This question
is probably more appropriate on the ggplot Google Group than either of these
two mailing lists.
b) Post reproducible examples.
c) Use data frames with ggplot, not matrices. The read.csv or read.table
functions
Hi Berend,
I see you are one of the contributors to the rbecnhmark package.
I am sorry that I am bothering you again. I have tried to run your code
(slightly tweaked) involving the benchmark function, and I am getting the
following error message. What am I doing wrong?
Error in
Hello all,
I am trying to fit a gee model using repolr and I get a warning message
that Results suspect.
Warning message:
Note: In ogee(formula, data = , id =., : Cgee had an error (code=
104). Results suspect.
I checked the source code as Prof. Ripley advice in 2007 but the
Berend et. al:
1, Except you did not use my solution. It is not what you have but
instead:
f4 - function(df)na.omit.df
wrapping the return in data.frame() is both unnecessary and inefficient.
2. But my point is not to be the speediest nor even to show how clever I am
-- using a built-in
On 22-11-2012, at 18:20, Muhuri, Pradip (SAMHSA/CBHSQ) wrote:
Hi Berend,
I see you are one of the contributors to the rbecnhmark package.
I am sorry that I am bothering you again. I have tried to run your code
(slightly tweaked) involving the benchmark function, and I am getting the
* R. Michael Weylandt zvpunry.jrlyn...@tznvy.pbz [2012-11-22 12:11:55
+]:
I now think that what I want is
--8---cut here---start-8---
difftime.summary - function (v) {
s - summary(as.numeric(v))
r -
On Nov 21, 2012, at 11:21 PM, Manish Gupta wrote:
Hi,
I m working on R and read one image with russian font using readjpeg()
function and write it on pdf (using grid). But russian text is not
visible
on pdf. How can i fix my pblm?
You are working with two different plotting paradigms.
On 11/22/2012 03:23 AM, Manca Marco (PATH) wrote:
Dear BioConductor and R fellow users
I apologize in advance for double posting, but I am not sure which list would
actually be best fit for this message.
It helps to narrow the problem down. It looks like the problem occurs when
chol2inv is
Hi,
First post here. Grateful for any help you can give. I have data which looks
like this:
idtimex
1 12:015
1 12:02 14
1 12:03 6
1 12:04 3
2 12:01 98
2 12:02 23
2 12:03 1
2 12:04 4
3 12:01 5
3 12:02 65
3 12:03 23
3 12:04 23
But I want
HI,
If it is possible to remove those NA values:
dat$time - as.Date(dat$time,format=%Y-%m-%d)
newdat-dat[complete.cases(dat),]
change-cumsum(c(FALSE,abs(diff(newdat$Salt))0.05)) #Rui's solution
split(newdat,change)
A.K.
- Original Message -
From: Hefri helenefrigs...@hotmail.com
Dear All,
I am trying to plot four diagnostic plots for my lm in one window.
Here is some random data for an example:
a = rnorm(20, mean=2, sd=0.2)
b = rnorm(20, mean=1, sd=0.4)
model=lm(a~b)
When I set the page as:
par(mfrow=c(1,1), oma=c(1,0,2,0))
and plot my model:
plot(model)
Hi,
I'm trying to make a partial plot with package randomForest in R. After I
perform my random forest object I type
partialPlot(data.rforest, pred.data=act2, x.var=centroid, C)
where data.rforest is my randomforest object, act2 is the original dataset,
centroid is one of the predictor and C is
My name is Giovanna and I am a PhD student in Norway.
I am a beginner with statistics and R, hence my ignorance. Apologies from
now.
I have been collecting data on time performances of 5 subjects using a 1:3
scale tower yarder. The task was consisting in yarding 5 small logs placed on
These are the errors I've been having. I have been trying 3 different things
1- Mclust:
This is the example I have been following:
# Model Based Clustering
library(mclust)
fit - Mclust(mydata)
plot(fit, mydata) # plot results
print(fit) # display the best model
What I have done:
fit -
Hi all,
does anyone know why the area under the curve (AUC) is negative?
I'm using ROC function with a logistic regression, package Epi.
First time it happens...
Thanks a lot!
Bruno
--
View this message in context:
http://r.789695.n4.nabble.com/ROC-Curve-negative-AUC-tp4650469.html
Sent
transform(d, cumsumXById = ave(x, id, FUN=cumsum))
id time x cumsumXById
1 1 12:01 5 5
2 1 12:02 14 19
3 1 12:03 6 25
4 1 12:04 3 28
5 2 12:01 98 98
6 2 12:02 23 121
7 2 12:03 1 122
8 2 12:04 4 126
9
Hi Berend,
Thank you very much for pointing out the mistake and for your patience. I have
corrected the the script, which has worked fine.
regards,
Pradip Muhuri
From: Berend Hasselman [b...@xs4all.nl]
Sent: Thursday, November 22, 2012 12:42 PM
To:
On 22-11-2012, at 18:08, TheRealJimShady wrote:
Hi,
First post here. Grateful for any help you can give. I have data which looks
like this:
idtimex
1 12:015
1 12:02 14
1 12:03 6
1 12:04 3
2 12:01 98
2 12:02 23
2 12:03 1
2 12:04 4
3
wrong direction for ranking
On Thu, Nov 22, 2012 at 1:58 PM, brunosm brunos...@gmail.com wrote:
the area under the curve (AUC) is negative?
I'm using ROC function with a logistic regression, package Epi.
First time it happens...
Thanks a lot!
Bruno
--
==
On Fri, Nov 23, 2012 at 7:58 AM, brunosm brunos...@gmail.com wrote:
Hi all,
does anyone know why the area under the curve (AUC) is negative?
I'm using ROC function with a logistic regression, package Epi.
First time it happens...
Have you looked at the ROC curve?
That should tell you
I have a dataframe (x) and I'm plotting the 5th column vs the index. I also
have a vector (v) with a few select points that I want to emphasize with a
dot for those points
head(x)
period AP EU LA NA
1 Jan 2007 0.18 0.45 0.19 3.19
2 Feb 2007 0.14 0.48 0.36 3.55
3 Mar 2007 0.14 0.42
Hello everyone,
I have estimated a VEC using functions of package urca. Now I need to
simulate several trajectories of the variables of the model based in the
information of the model. To do that first I converted the VEC to a VAR
using vec2var (from package vars) and then I converted de VAR to
Thanks, it worked without quotation marks.
--
View this message in context:
http://r.789695.n4.nabble.com/ifelse-numeric-tp4650390p4650482.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
try this
# you need to provide sample data
x - runif(10)
v - c(2, 4, 7)
plot(x, type = 'l')
# highlight points
points(v, x[v], pch = 19)
On Thu, Nov 22, 2012 at 2:22 PM, eric ericst...@aol.com wrote:
I have a dataframe (x) and I'm plotting the 5th column vs the index. I also
have a
Hello,
I estimated a model using SEM package in R, which was fit to a raw moment
matrix, and includes an intercept term. The only goodness of fit statistics
that are output are Model Chisquare, AIC, AICc, BIC, CAIC, and normalized
residuals.
How can I get the other goodness of fit statistics,
Why are you using jpeg to create files with a .png extension? wouldn't it
make more sense to use the png function?
There are a couple of options, you could plot using the matplot function
(with different subsets in the loop).
Or you can start an initial empty plot and use lines to add to it,
frespider wrote
Hi,
is there a way I can calculate a summary statistics for a columns matrix
let say we have this matrix
x - matrix(sample(1:8000),nrow=100)
colnames(x)- paste(Col,1:ncol(x),sep=)
if I used summary
summary(x)
i get the output for each column but I need the output
Hello,
I have a table that was constructed in a wrong way (dput data on bottom -
wrong data-frame):
Local Mês Dia Colonia X6h X7h X8h X9hX10hX11h
X12hX13hX14hX15hX16hX17h
1 Conceição Junho 1 3 2.16137 2.20412 2.08991 1.72428 1.69897
On 2012-11-22 01:16, Felix Schönbrodt wrote:
Hello,
I try to increase the distance between tick labels and ticks in a lattice
wireframe plot. Here's a minimal example:
## Minimal example
x - y - z - c(1,2,3)
df - data.frame(x, y, z)
wireframe(z ~ x*y, df, scales = list(arrows = FALSE, col =
Hi everyone,
I made some tests with Rcmdr, to add a function with default parameters :
For example (very simple):
myfunction-function(var=314){
print(hello)
print(var)
}
if I run myfunction() directly i see :
myfunction()
[1] hello
[1] 314
it's ok.
But if i edit de Rcmdr-menu.txt (in
The 'reshape2' package is your friend:
require(reshape2)
x - melt(wrong, id = c(Local, Mês, Dia, Colonia), variable.name =
Hora)
# remove X from Hora
x$Hora - as.character(substring(x$Hora, 2))
head(x) # not in the right order
Local Mês Dia Colonia Hora value
1 Conceição Junho
Dear expeRts,
I would like to download a time series of historical data from the ticker with
symbol ROG.VX. Interestingly, I obtain constant values (138.3 for each day in
the chosen period) although the yahoo.finance website tells me that the time
series is not at all constant. What's wrong?
I also don't like to use split function because I have like around 800 columns
Date: Thu, 22 Nov 2012 18:08:54 -0800
From: ml-node+s789695n4650496...@n4.nabble.com
To: frespi...@hotmail.com
Subject: RE: Summary statistics for matrix columns
Hi,
How about this:
Hi,
is there a way I can calculate a summary statistics for a columns matrix
let say we have this matrix
x - matrix(sample(1:8000),nrow=100)
colnames(x)- paste(Col,1:ncol(x),sep=)
if I used summary
summary(x)
i get the output for each column but I need the output to be in matrix with
Hi peter,
but this doesn't give me them in the order I want.
Is there a better approach
Thanks
--
View this message in context:
http://r.789695.n4.nabble.com/Summary-statistics-for-matrix-columns-tp4650489p4650492.html
Sent from the R help mailing list archive at Nabble.com.
There is still missing some statistics,
like sd and IQR and I prefer the output to be matrix
Thanks
Date: Thu, 22 Nov 2012 18:00:20 -0800
From: ml-node+s789695n4650493...@n4.nabble.com
To: frespi...@hotmail.com
Subject: Re: Summary statistics for matrix columns
HI,
You could try
HI,
but Sd and IQR not in the order I want ,
Thanks
Date: Thu, 22 Nov 2012 18:08:57 -0800
From: ml-node+s789695n4650496...@n4.nabble.com
To: frespi...@hotmail.com
Subject: RE: Summary statistics for matrix columns
Hi,
How about this:
Hi,
it is possible. but don't you think it will slow the code if you convert to
data.frame?
Thanks
Date: Thu, 22 Nov 2012 18:31:35 -0800
From: ml-node+s789695n4650500...@n4.nabble.com
To: frespi...@hotmail.com
Subject: RE: Summary statistics for matrix columns
HI,
Is it possible
Hi,
If you wanted to emphasize the select points from the 5th column:
You could try:
plot(x[,5], type='l')
points(dat2[c(2,4,7),5],pch=19)
A.K.
- Original Message -
From: eric ericst...@aol.com
To: r-help@r-project.org
Cc:
Sent: Thursday, November 22, 2012 2:22 PM
Subject: [R]
I have s data set where 2 of the columns give the coded versions of the
factors A and B. Factor A is coded with 1, 2, 3. Factor B is coded with 1,2.
How do use the factor function to convert these variables into factors, and
also use the labels= command to give them a more informative name?
Hi,
No problem.
One more method if you wanted to try:
library(data.table)
dat2-data.table(dat1)
dat2[,list(x,time,Cumsum=cumsum(x)),list(id)]
# id x time Cumsum
#1: 1 5 12:01 5
#2: 1 14 12:02 19
#3: 1 6 12:03 25
#4: 1 3 12:04 28
#5: 2 98 12:01 98
#6: 2 23
I am trying to optimize custom likelyhood with nlminb()
Arguments h and f are meant to be fixed.
example.R:
compute.hyper.log.likelyhood - function(a, h, f) {
a1 - a[1]
a2 - a[2]
l - 0.0
for (j in 1:length(f)) {
l - l + lbeta(a1 + f[j], a2 + h - f[j]) - lbeta(a1, a2)
}
return(l)
hi guys and gals ... How are you all ...
i have to do something in robust regression by R programm , and i have some
problems as following:
*the first :*
suppose
w(r) =1/(1 r^2) and r - c(7.01,2.07,7.061,5.607,8.502,54.909,12.222)
and i want to exclude some values from r so that (abs(r)4.9
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Hi,
May be this helps:
library(reshape)
dat1 # data that needs to be converted
res-melt(dat1,id=c(Local,Mês,Dia,Colonia))
names(res)[5:6]-c(Hora,N)
res1-res[order(res$Dia),]
row.names(res1)-1:nrow(res1)
res1$Hora-gsub([X],,res1$Hora)
head(res1)
# Local Mês Dia Colonia Hora N
#1
I know if I have a dataframe with columns y, x1, x2 and I wish to have y as my
y value and x1 and x2 as x values I can do:
y ~ x1 + x2
or
y ~.
but can someone explain what . actually is or what its transposed into?
I searched for this with no success, reading the formula manual pages.
Brian
How do I get gvarbrowser to display the contents of data.frame named, say
atab1? That is modify the Filter by: entries to only show data.frame
Also, how do I turn off the selection pull down box, given that I know the
name of the data.frame variable? Basically, I will like to browse the
How do I get gvarbrowser to display only data.frame named, say atab1 or
atab2 or atab*?
Also, how do I turn off the selection pull down box?
#I tried:
mydefaultclasses - list(Data sets1=c(data.frame) )
#
# Then
v - gvarbrowser( container =gwindow(Object broser),
Hi,
I'm trying to plot stacked barplot with lines on it. Here is the data.
emp days val1 val2 score
1 21 1 0 1200
2 35 1 1 na
3 42 na na 3000
4 53 2 1 2100
5 64 1 0 na
6 73 na na 1400
My X-axis is days. I'm looking to plot val1,val2 as stacked bars and score
as lines with different y-axis. I
84 matches
Mail list logo