Dear R forum,
I have a data.frame as defied below -
df = data.frame(names = c(C, A, A, B, C, B, A, B, C), dates =
c(4/15/2013, 4/13/2013, 4/15/2013, 4/13/2013, 4/13/2013, 4/15/2013,
4/14/2013, 4/14/2013,4/14/2013 ),values = c(10, 31, 31, 17, 11, 34, 102,
47, 29))
df
names dates
Dear all,
Given the following vector:
(z - c('R project', 'hello world', 'something Else'))
[1] R project hello worldsomething Else
I know how to obtain all capitals or all lower case letters:
tolower(z)
[1] r project hello worldsomething else
toupper(z)
[1] R PROJECT
Hi,
There is an example of how to do do what you are looking for in ?toupper
Regards,
Pascal
On 04/15/2013 03:50 PM, Liviu Andronic wrote:
Dear all,
Given the following vector:
(z - c('R project', 'hello world', 'something Else'))
[1] R project hello worldsomething Else
I know how
See for instance capitalize() in the R.utils package.
Henrik
On Apr 14, 2013 11:51 PM, Liviu Andronic landronim...@gmail.com wrote:
Dear all,
Given the following vector:
(z - c('R project', 'hello world', 'something Else'))
[1] R project hello worldsomething Else
I know how to
On Apr 15, 2013, at 08:50 , Liviu Andronic wrote:
Dear all,
Given the following vector:
(z - c('R project', 'hello world', 'something Else'))
[1] R project hello worldsomething Else
I know how to obtain all capitals or all lower case letters:
tolower(z)
[1] r project hello
The examples in ?order show a method that could be applied if you avoid the
decreasing argument and instead convert the Date to numeric for purposes of
sorting.
---
Jeff NewmillerThe .
I have a data set with 10 variables, and about 8000 instances (or
objects/rows/samples). In addition I have one more ('class') variable that
I have about 10 instances for, but for which I wish to impute values for.
I am a little confused how to go about doing this, mostly as I'm not
well-versed
Dear Liviu,
I have just updated tocamel to have a new argument, so the development
version of the package would produce:
tocamel(z, upper = TRUE, sep = ' ')
[1] R Project Hello WorldSomething Else
Best,
Gergely
PS #1: to install the dev branch you might give a try to the devtools
Hi there,
I have seen this post.
https://stat.ethz.ch/pipermail/r-help/2007-June/133606.html
have odbc installed in my machine. Now I have the following message:
channel2 - odbcDriverConnect(test.mdb)Warning messages:1: In
odbcDriverConnect(test.mdb) :
[RODBC] ERROR: state IM002, code 0,
Hi Eva,
you're right, it works with 50 variables. Then, how could I change this
variable limit in the lm function?
Thank you very much for your help.
Julien.
--
View this message in context:
http://r.789695.n4.nabble.com/model-frame-and-formula-mismatch-in-model-matrix-tp4664093p4664226.html
On 15/04/2013 07:12, Aileen Lin wrote:
Hi there,
I have seen this post.
https://stat.ethz.ch/pipermail/r-help/2007-June/133606.html
have odbc installed in my machine. Now I have the following message:
channel2 - odbcDriverConnect(test.mdb)Warning messages:1: In
odbcDriverConnect(test.mdb) :
Dear R-user,
Is there a way in R to locate the nearest 5 indices to a station, based on
distances in a distance matrix. In other words i want to have nearest stations
based on the distances in the matrix. The distance matrix, i have, has
dimension 44*44.
Thankyou very much in advance
Elisa
Dear Eliza,
If you have the coordinates of the stations you can use the nnwhich() function
from the spatstat package.
Best regards,
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie Kwaliteitszorg / team Biometrics Quality
Hi all,
I would like to ask you for advice. I did a dotplot - using dotchart
function.
There are two localites (loc) with values 75 or 56 in my data ZZ.
The f column has 4 levels: P1, S1, S8, R6.
The dataframe is ordered by N value, pchloc value is assign to use pch in
plot.
head(ZZ)
loc f
On Mon, Apr 15, 2013 at 9:25 AM, Henrik Bengtsson h...@biostat.ucsf.edu wrote:
See for instance capitalize() in the R.utils package.
Unfortunately this also fails when NA values are present:
z - c(R project, hello world, something Else, NA)
R.utils::capitalize(z)
[1] R project Hello world
On Mon, Apr 15, 2013 at 9:20 AM, Pascal Oettli kri...@ymail.com wrote:
There is an example of how to do do what you are looking for in ?toupper
Unfortunately this fails when NA values are present:
z - c(R project, hello world, something Else, NA)
tocapwords(z)
[1] R Project Hello World
On Mon, Apr 15, 2013 at 10:10 AM, Gergely Daróczi gerg...@snowl.net wrote:
Dear Liviu,
I have just updated tocamel to have a new argument, so the development
version of the package would produce:
tocamel(z, upper = TRUE, sep = ' ')
[1] R Project Hello WorldSomething Else
Thanks
Liviu Andronic landronim...@gmail.com writes:
On Mon, Apr 15, 2013 at 9:25 AM, Henrik Bengtsson h...@biostat.ucsf.edu
wrote:
See for instance capitalize() in the R.utils package.
Unfortunately this also fails when NA values are present:
z - c(R project, hello world, something Else, NA)
On 15 April 2013 14:10, Liviu Andronic landronim...@gmail.com wrote:
On Mon, Apr 15, 2013 at 10:10 AM, Gergely Daróczi gerg...@snowl.net
wrote:
Dear Liviu,
I have just updated tocamel to have a new argument, so the development
version of the package would produce:
tocamel(z, upper
Dear R users,Sorry for such a basic question. I really need to know that how
can i pick the indices of 5 lowest values from each row of a matrix with
dimensions 12*12??Thank you very much in advance
Elisa
[[alternative HTML version deleted]]
On Sun, Apr 7, 2013 at 7:40 AM, Anton Lebedevich mab...@gmail.com wrote:
Hello.
I've got many (5-20k) files with time series in a text format like this:
1359635460 2.006747
1359635520 1.886745
1359635580 3.066988
1359635640 3.633578
1359635700 2.140082
1359635760
On Apr 15, 2013, at 14:27 , eliza botto wrote:
Dear R users,Sorry for such a basic question. I really need to know that how
can i pick the indices of 5 lowest values from each row of a matrix with
dimensions 12*12??Thank you very much in advance
Something like this?
m
[,1] [,2]
On Mon, Apr 15, 2013 at 2:22 PM, Gergely Daróczi gerg...@snowl.net wrote:
I have added an extra check in the function for NA values before applying
`paste` at
https://github.com/Rapporter/rapport/compare/34ca6a35fb...a04abc8b21
Alex might not like it :)
Example:
tocamel(z, upper = TRUE,
library(plyr)
arrange(df,names,desc(dates))
# names dates values
#1 A 4/15/2013 31
#2 A 4/14/2013 102
#3 A 4/13/2013 31
#4 B 4/15/2013 34
#5 B 4/14/2013 47
#6 B 4/13/2013 17
#7 C 4/15/2013 10
#8 C 4/14/2013 29
#9 C 4/13/2013
You can also use:
df[order(df$names,-xtfrm(df$dates),decreasing=FALSE),]
# names dates values
#3 A 4/15/2013 31
#7 A 4/14/2013 102
#2 A 4/13/2013 31
#6 B 4/15/2013 34
#8 B 4/14/2013 47
#4 B 4/13/2013 17
#1 C 4/15/2013 10
#9 C
Hi,
set.seed(25)
myFile1-as.data.frame(matrix(sample(1:40,50,replace=TRUE),nrow=10))
row.names(myFile1)- LETTERS[1:10]
groups - rep (0:1, c(3,2))
kruskal-apply(myFile1,1,kruskal.test,groups)
p_kruskal - sapply(kruskal, function(x) x$p.value)
p_kruskal
# A B C
One statistical point beyond A.K.'s well done response. As you should well
know, Kruskal-Wallis is a non-parametric equivalent of ANOVA. However, you
only have two groups and do not require an ANOVA approach. You could
simply use a Mann-Whitney U (aka.. independent Wilcoxon) test using
I want to plot two scdf-plots in the same graph.
I have two input tables with one column each:
Targets - read.table(/media/, sep=, header=T)
NonTargets - read.table(/media/..., sep=, header=T)
head(Targets)
V1
1 3.160514
2 6.701948
3 4.093844
4 1.992014
5 1.604751
6 2.076802
hey there
can i email questions to this address to get help with using R
thanks sam
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hi, I'm trying to decide between doing a FA or PCA and would appreciate some
pointers. I've got a questionnaire with latent items which the participants
answered on a Likert scale, and all I want to do at this point is to explore
the data and extract a number of factors/components. Would FA or PCA
Dear List,
I am using both the clm() and clmm() functions from the R package
'ordinal'.
I am fitting an ordinal dependent variable with 5 categories to 9
continuous predictors, all of which have been normalised (mean
subtracted then divided by standard deviation), using a probit link
HI,
You could use:
gsub((^|\\s+)([a-z]),\\1\\U\\2,z,perl=TRUE)
#[1] R Project Hello World Something Else
#or
gsub(\\b([a-z]),\\U\\1,z,perl=TRUE)
#[1] R Project Hello World Something Else
A.K.
- Original Message -
From: Liviu Andronic landronim...@gmail.com
To: r-help
Yes, but do read:
http://www.R-project.org/posting-guide.html
first.
Sarah
On Mon, Apr 15, 2013 at 2:09 AM, sam tingey sam.ting...@gmail.com wrote:
hey there
can i email questions to this address to get help with using R
thanks sam
__
Hi Guilherme,
On Sun, Apr 14, 2013 at 11:48 PM, Guilherme Ferraz de Arruda
gu...@yahoo.com.br wrote:
Hi,
I need to classify, using Naive Bayes and Bayes Networks, and estimate
their performance using cross validation.
How can I do this?
I tried the bnlearn package for Bayes Networks,
Hi,
TRy this:
set.seed(30)
mat1- matrix(sample(1:50,12*12,replace=TRUE),ncol=12)
mat1
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12]
[1,] 5 28 13 4 47 3 30 16 3 39 42 9
[2,] 25 44 15 21 9 5 32 5 4 33 30 21
Sam tingey wrote:
can i email questions to this address to get help with using R
Sarah Goslee replied;
Yes, but do read:
http://www.R-project.org/posting-guide.html
Dieter Menne thought:
Catch 42. When you are so good that you can create a reproducible example
without using R, you only will
On Apr 15, 2013, at 14:30 , ilovestats wrote:
Hi, I'm trying to decide between doing a FA or PCA and would appreciate some
pointers. I've got a questionnaire with latent items which the participants
answered on a Likert scale, and all I want to do at this point is to explore
the data and
Hi,
Try:
x- c(2/26/13 11:59 PM, 2/25/13 10:25 AM)
strptime(x,%m/%d/%y %I:%M %p)
#[1] 2013-02-26 23:59:00 2013-02-25 10:25:00
#or
library(lubridate)
parse_date_time(x,%m/%d/%y %I:%M %p)
# 2 parsed with %m/%d/%y %I:%M %p
#[1] 2013-02-26 23:59:00 UTC 2013-02-25 10:25:00 UTC
A.K.
I'm a newbie to
I would like to simulate some SARIMA models, e.g. a SARIMA (1,0,1)(1,0,1)[4]
process.
I installed the package 'forecast', where the function simulate.Arima should do
what I am trying to do.
I am not able to understand how it works
Could somebody help me with an example?
thank you
Stefano Sofia
Hi.
I am a R studio user and would like to use RCommander within R studio. Each
time I try to install and use Rcommander, I see the following message:
Loading Tcl/Tk interface ... Error : .onLoad failed in loadNamespace() for
'tcltk', details:
call: dyn.load(file, DLLpath = DLLpath, ...)
On Mon, Apr 15, 2013 at 2:50 AM, Liviu Andronic landronim...@gmail.com wrote:
Dear all,
Given the following vector:
(z - c('R project', 'hello world', 'something Else'))
[1] R project hello worldsomething Else
I know how to obtain all capitals or all lower case letters:
tolower(z)
Dear Helene,
I don't think that your problem has anything to do with RStudio. I suspect that
you haven't installed Tcl/Tk for X-Windows on your Mac, as is required by the
tcltk package for versions of R on the Mac prior to 3.0.0. Please read the
Rcmdr installation instructions at
On Mon, Apr 15, 2013 at 10:56 AM, Gabor Grothendieck
ggrothendi...@gmail.com wrote:
On Mon, Apr 15, 2013 at 2:50 AM, Liviu Andronic landronim...@gmail.com
wrote:
Dear all,
Given the following vector:
(z - c('R project', 'hello world', 'something Else'))
[1] R project hello world
Dear Arun,
Thankyou very much. it worked out
:D
Elisa
Date: Mon, 15 Apr 2013 07:19:40 -0700
From: smartpink...@yahoo.com
Subject: Re: [R] Indices of lowest values in matrix
To: eliza_bo...@hotmail.com
Hi Elisa,
I am not sure how you got that values for the first rows of mat1. Is it from
On 13.04.2013 08:22, Jeff Newmiller wrote:
R CMD build
will only work on Windows if you have Rtools installed. Visit your local CRAN
mirror and read... this is not exactly trivial.
Not exactly true:
pure R code / data packages typically R CMD build and R CMD INSTALL
without those tools
Hi,
Is it possible to create Dual y axes with ggplot2 package? If so, is
there any sample codes that reaches (or partially) this goal?
The author of the package, Dr Hadley Wickham, seem to discourage the
dual axes, but some remedies were provided by other users (If I am wrong,
please
What if more generally that the group name doest have anything to do with
the ID, eg. for ID=AL1 and AL2, I want to name the group as Key1, how can
I approach that?
Thanks,
On Thu, Apr 11, 2013 at 11:54 AM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
Try the following.
dat -
On Apr 14, 2013, at 11:01 PM, Katherine Gobin wrote:
Dear R forum,
I have a data.frame as defied below -
df = data.frame(names = c(C, A, A, B, C, B, A, B, C), dates
= c(4/15/2013, 4/13/2013, 4/15/2013, 4/13/2013, 4/13/2013,
4/15/2013, 4/14/2013, 4/14/2013,4/14/2013 ),values = c(10,
HI
I am trying to analyse data which is left-censored (i.e. has values below the
detection limit). I have been using the NADA package of R to derive summary
statistics and do some regression. I am now trying to carry out regression on
paired data where both my X and Y have left-censored data
Dear all,
I had a question around how to manually construct latent variables. I'll
provide a little background….
Basically I have a SEM with 17 items, 6 latent variables and 615 rows of data.
I have all my model data (loadings, t values etc.) from lavaan, as well as
correlation matrices.
I
Hello All,
Below is some sample survival analysis code. I'd like to able to get the
results from print(gehan.surv) into a matrix or data frame, so I can manipulate
them and then create a table using odfWeave. Trouble is, I'm not quite sure how
make such a conversion using the results from a
Yes, that would be because she converted to Date on the fly in her example, and
so apparently did not need this reminder.
---
Jeff NewmillerThe . . Go Live...
On Apr 15, 2013, at 11:31 AM, Paul Miller pjmiller...@yahoo.com wrote:
Hello All,
Below is some sample survival analysis code. I'd like to able to get the
results from print(gehan.surv) into a matrix or data frame, so I can
manipulate them and then create a table using odfWeave. Trouble
Hi Marc,
Oh, yes. That is quite simple. Silly me for not recognizing this. Thanks very
much for your help.
Paul
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Dear R Helpers,
I did a search for deleting rows based on conditions but wasn't able to
find an example that addressed the error that I am getting. I am hoping
that this is a simple syntax phenomenon that somebody else knows off the
top of their head. My apologies for not providing a
On Apr 15, 2013, at 9:33 AM, Jeff Newmiller wrote:
Yes, that would be because she converted to Date on the fly in her example,
and so apparently did not need this reminder.
I apologize, Iobviously missed that. So the answer was simply to put a minus
sign in front of the as.Date()
On Apr 15, 2013, at 9:58 AM, Sparks, John James wrote:
Dear R Helpers,
I did a search for deleting rows based on conditions but wasn't able to
find an example that addressed the error that I am getting. I am hoping
that this is a simple syntax phenomenon that somebody else knows off the
Hi,
May be this helps:
ZZ-
Hi,
In addition:
You can subset based on time or date:
ZZ1['2006']
# Open High Low Close Volume Adjusted
#2006-04-07 17.5 18.2 17.3 17.5 23834500 16.8
#2006-04-08 17.6 17.6 16.8 16.8 2916000 16.2
ZZ1['2007-01/2008-01']
# Open High Low Close Volume Adjusted
Hi,
You could do this:
dat1- read.table(text=
ID Value
AL1 1
AL2 2
CA1 3
CA4 4
,sep=,header=TRUE,stringsAsFactors=FALSE)
lst1-split(dat1,gsub(\\d+,,dat1$ID))
res-do.call(rbind,lapply(seq_along(lst1),function(i) {x1-lst1[[i]];
x1$group- paste0(Key,i);x1}))
res
# ID Value group
#1 AL1
I would probably start with maximum likelihood estimation.
I suppose you could impute X and Y separately using ros() from the NADA
package, and then run you ordinary regression on the imputed values.
Obviously, this ignores any relationship between X and Y, since each is
imputed independently of
On Apr 15, 2013, at 8:55 AM, Laura MacCalman wrote:
HI
I am trying to analyse data which is left-censored (i.e. has values below the
detection limit). I have been using the NADA package of R to derive summary
statistics and do some regression. I am now trying to carry out regression on
Hello fellow R users, I need to perform Guttman's Smallest Space Analysis,
which is a type of Non-metric Multidimensional Scaling. Not wanting to
reinvent the wheel i decided to look for a package which may have an
implementation of it, but no success at all. Do you guys know of any
package that
Hi,
vec1- letters
vec1[!grepl(b|r|x,alp)]
# [1] a c d e f g h i j k l m n o p q s t
u
#[20] v w y z
vec1[!vec1%in% c(b,r,x) ]
# [1] a c d e f g h i j k l m n o p q s t
u
#[20] v w y z
alp-lapply(seq_along(vec1),function(i) vec1[i])
res-alp[!grepl(b|r|x,alp)]
unlist(res)
# [1] a c d e f g h i
R version : 2.15.2
Windows: 7 32-bit
Hello,
I was trying to load a saved workspace image from the working directory.
I issued the command load('image_name') in R console. It did not throw any
error, but then it returned the prompt. I want to view the commands (or
history) I typed there, how do
I have been trying many ways to match 2 separate fields in a matrix. Here is
a simplified version of the matrix:
site1 depth1 year1 site2 depth2 year2
10 30 1860NA NA NA
NA NA NA 50 30 1860
Basically I am trying to identify the sites
Hello,
I have the same problem on my mac and it doesn't work to load Rcmdr..
library(Rcmdr)
Error : .onAttach failed in attachNamespace() for 'Rcmdr', details:
call: structure(.External(.C_dotTclObjv, objv), class = tclObj)
error: [tcl] invalid command name image.
Error: package or
On Apr 15, 2013, at 2:30 PM, arun wrote:
Hi,
vec1- letters
alp - as.list(letters) would have constructed the vector that was described.
vec1[!grepl(b|r|x,alp)]
# [1] a c d e f g h i j k l m n o p q s t
u
#[20] v w y z
vec1[!vec1%in% c(b,r,x) ]
# [1] a c d e f g h i j k l m n o p q s
On Apr 15, 2013, at 1:51 PM, Ludwig Asam wrote:
Hello,
I have the same problem on my mac and it doesn't work to load Rcmdr..
library(Rcmdr)
Error : .onAttach failed in attachNamespace() for 'Rcmdr', details:
call: structure(.External(.C_dotTclObjv, objv), class = tclObj)
error:
Presumably --- based on the question she actually *asked* --- she does
NOT have the coordinates of the stations; only the distance matrix.
I believe that the following will do the job: Let M be the distance matrix.
diag(M) - Inf
nn5 -
Trying re-send as plain text.
I have a data set with 10 variables, and about 8000 instances (or
objects/rows/samples). In addition I have one more ('class') variable
that I have about 10 instances for, but for which I wish to impute
values for.
I am a little confused how to go about doing this,
There was a bit of cranial wind-passing in my previous message.
(A bit of redundancy.)
My solution should have read:
diag(M) - Inf
nn5 - apply(M,1,function(x){order(x)[1:5]})
What I wrote gave the right answer; there was just a bunch of
unnecessary ring-around-the-rosy playing in it.
On 15.04.2013 21:53, Sourabh Sinha wrote:
R version : 2.15.2
Windows: 7 32-bit
Hello,
I was trying to load a saved workspace image from the working directory.
I issued the command load('image_name') in R console. It did not throw any
error, but then it returned the prompt. I want to view
worked it out. Thank you. misunderstood the post earlier.
Aileen
On 15 April 2013 20:17, Prof Brian Ripley rip...@stats.ox.ac.uk wrote:
On 15/04/2013 07:12, Aileen Lin wrote:
Hi there,
I have seen this post.
Hi there,
I tried the command in https://stat.ethz.ch/**pipermail/r-help/2007-June/**
133606.html https://stat.ethz.ch/pipermail/r-help/2007-June/133606.html
In R, it works OK. In Rstudio, there seems to be a problem:
library(RODBC)ch - odbcDriverConnect(Driver={Microsoft Access Driver
Dear Lugwig,
Have you followed the steps in the Rcmdr installation notes at
http://socserv.socsci.mcmaster.ca/jfox/Misc/Rcmdr/installation-notes.html? In
particular, have you installed X-Windows? Mac OS X Mountain Lion does not come
with X-Windows installed.
Best,
John
You missed that this is not the RStudio support forum.
You probably also missed that R comes in both 32-bit and 64-bit flavors in the
Windows binary distribution, and you have to use the one that matches the ODBC
drivers you want to use. You can specify which version RStudio is to use.
You can use na.strings= in read.table() or read.csv()
library(stringr)
vec1-unlist(str_split(readLines(textConnection(3,7,11,,12,14,15,,17,18,19)),,))
vec1[vec1==]- NA
vec1
# [1] 3 7 11 NA 12 14 15 NA 17 18 19
#or
scan(text=3,7,11,,12,14,15,,17,18,19,sep=,)
#Read 11 items
#[1] 3 7
Hi,
May be this helps you.
#Using
set.seed(12345)
S=10
simdata - replicate(S, generate(250))
lstpshat-lapply(seq_len(ncol(simdata)),function(i)
HI,
May be this helps:
dat1- read.table(text=
site1 depth1 year1 site2 depth2 year2
10 30 1860 NA NA NA
NA NA NA 50 30 1860
10 20 1850 11 20 1850
11 25 1950 12 25 1960
10 NA 1870 12 30 1960
11 25 1880 15 22 1890
14 22 1890 14 25 1880
,sep=,header=TRUE,stringsAsFactors=FALSE)
Hi,
I am having difficulties estimating the parameters of a HMM using the HMM
package. I have simulated a sequence of observations from a known HMM. When
I estimate the parameters of a HMM using these simulated observations the
parameters are not at all close to the known ones. I realise the
Hello!
I am working with a procedure where I need to draw one observation at a time
from dagum distribution. I used the function defined in the VGAM library.
when I did,
rdagum(n=1, 0.2,1,4.5))
it says: Error in qdagum(runif(n), shape1.a = shape1.a, scale = scale, shape2.p
=
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