On 25/06/2013 20:35, Ned Harding wrote:
Just to clarify: The encoding didn't come through in the email.
print(éíôåëëåãåâáè) is meant to be a bunch of random greek characters.
In that case the message is likely correct. You failed to give us the
'at a minimum information' required by the
On Jun 25, 2013, at 21:51 , Rui Barradas wrote:
Hello,
Your data has commas as decimal points, R uses the period. So the data is
read in as strings, not numbers. You can change this by using argument 'dec'
of read.table:
?read.table
read.table(...etc..., dec = ,)
Or you can
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of bett kimutai
Sent: Wednesday, June 26, 2013 3:17 AM
To: Law, Jason; r-help@r-project.org
Subject: Re: [R] Loops
Thanks for you response. The issue is that I need to run a
Hi all,
What would be an efficient way to match rows of a matrix to a vector?
ex:
m-matrix(1:9, nrow=3)
m [,1] [,2] [,3]
[1,]147
[2,]258
[3,]369
#
which(m==c(2,5,8))# I want this to return 2
##
Hi,
I'd like to get mean values for the margins of my casted data.frame.
For the casting I am using dcast() from reshape2. However, when I set
the margins parameter (margins=c(grand\_row)) I get following error
concerning
an unrecognized escape character '\_'. So what is the correct command
to
On 26-06-2013, at 10:03, Sachinthaka Abeywardana sachin.abeyward...@gmail.com
wrote:
Hi all,
What would be an efficient way to match rows of a matrix to a vector?
ex:
m-matrix(1:9, nrow=3)
m [,1] [,2] [,3]
[1,]147
[2,]258
[3,]369
I suggest using vectorization :
find_row - function(m,v) { which(!(abs(rowSums(m - rep(v, each = nrow(m)))
)) 0) }
The function matroweqv mentioned above would give any row with the first
element equal to the first element in vector v.
The function find_row matches each row of the matrix as a
Hi,
I am trying to calculated various summary statistics using the dcast
function
of reshape2. This works perfectly for getting the mean, sum, length, sd. But
when I want to calculate the median I get an error. I tried it with and
without removing
NAs:
my_median - function(x) median(x, na.rm =
I uploaded the data here: http://uploadeasy.net/upload/p4d81.rar
As I said, I know my color example is wrong, that's why I am looking for a
correct solution,
also, I would be interested in how I can get a better axis, as I described the
problem.
Thanks a lot for your help,
Ivanov
-
On 26-06-2013, at 10:30, Yuliya Matveyeva yuliya.rm...@gmail.com wrote:
I suggest using vectorization :
find_row - function(m,v) { which(!(abs(rowSums(m - rep(v, each = nrow(m)))
)) 0) }
The function matroweqv mentioned above would give any row with the first
element equal to the first
On Jun 26, 2013, at 00:33 , Simon Kiss wrote:
Hello: I'm trying to construct a biplot from the psych package. The
underlying data frame looks just like sample.data, below. I turned it into a
polychoric correlation matrix sample.cor, below, as it is derived from a
series of Likert
-Original Message-
It may be helpful not to worry about the technical details,
just to look at the source code defining the function: if it
is defined in a place where a variable can be seen, it can
see that variable.
I too find R's lexical scoping rules straightforward.
Hi Johannes,
I think the documentation is wrong. The Readme at
https://github.com/hadley/reshape says grand_row and grand_col have
been dropped. You should submit a bug report at
https://github.com/hadley/reshape/issues describing the documentation
problem.
Best,
Ista
On Wed, Jun 26, 2013 at
On 13-06-26 6:57 AM, S Ellison wrote:
-Original Message-
It may be helpful not to worry about the technical details,
just to look at the source code defining the function: if it
is defined in a place where a variable can be seen, it can
see that variable.
I too find R's lexical
Dear R users,
I am using a big data matrix and need to transpose rows (formatting of
input matrix). I would like write a general code for this example.
for example: my input file is dta
dput(dta)
structure(list(id = structure(c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L,
2L, 2L, 3L, 3L, 3L, 3L), .Label =
dta[,3]-as.numeric(as.character(gsub(,,.,dta[,3])))
library(reshape2)
dcast(dta,id~name,value.var=value)
# id AreaCycl AreaEmer AreaMax HeightMax nrfilledseed
#1 TN00016-003A -1.3998944 -3.2771509 -3281.077 8.434493 1.825
#2 TN00016-014A -0.5843794 -0.8428928
Hi,
Please check this link:
http://stackoverflow.com/questions/4835202/error-with-custom-aggregate-function-for-a-cast-call-in-r-reshape2
A.K.
- Original Message -
From: Johannes Radinger johannesradin...@gmail.com
To: R help r-help@r-project.org
Cc:
Sent: Wednesday, June 26, 2013
reshape(dta, idvar=id, timevar=name, direction=wide)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Nico Met
Sent: Mittwoch, 26. Juni 2013 13:38
To: R help
Subject: [R] Transpose of the rows
Dear R users,
I am using a big data
Shaun,
See the help on contrasts ...
?contr.treatment
Jean
On Tue, Jun 25, 2013 at 7:07 PM, Shaun Jackman sjack...@gmail.com wrote:
Hi,
I've used `lm` to create a linear model of a continuous variable
against a factor variable with four levels using an example R data set
(see
Bree,
See StackOverflow for my response ...
http://stackoverflow.com/questions/17244824/calculating-an-index-of-colocation-for-a-large-dataset-r/17299168#17299168
Jean
On Tue, Jun 25, 2013 at 5:00 PM, Bree W bree.wittev...@alaska.edu wrote:
My apologies for cross-posting and for failing to
Dear List,
I have replicated an experiment 100 times. Each experiment lasts for 15
iteration. Thus I have collected results into a data.frame with 100 columns
(one column for each experiment) and 15 rows (one row for each iteration).
I would like to plot mean values at each iteration using
It is always better when dealing with R to use plain text. HTML messes things
up badly sometimes and it is also a good idea to reply to the R-help list
rather than individual respondents. You can get more responses if the problem
continues and if either of us were away then it might be weeks
Hello,
I would like some help with my Generalised Linear Model in R-Studio
I am a little confused about what family to use and for my data
My outcome variable (response) is categories 0,1,2,3 but my data i dont have
any individuals that have fallen into the top group 3
What i have read about
Hello everybody,
I have a question concerning the work with my dataframe and i hope some of
you can help me out:
I have A data frame called WWA that looks like the testframe
underneath:
Additionally, i have a testvector, containing coordinate IDs:
testvector -c(503146,551154,557154)
I have x, y, z data. The x, y fields dont change but Z does. How do I add a
very small number onto the end of each x, y data point.
For example:
Original (X) Original (Y) Original (Z)
15 20 30
15
Hi,
Using your testframe and testvector (and thank you for the convenient
reproducible example):
# I used NA instead of to be assigned
testframe - data.frame(testframe, landuse = NA, stringsAsFactors=FALSE)
# checks membership in testvector
testframe[testframe$testcoordID %in% testvector,
The formula in plotmeans compares vectors. This should work:
data - unlist(data)
times - rep(1:15, 100)
plotmeans(data~times)
Best,
Nello
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Simone Gabbriellini
Sent: Mittwoch, 26.
Hi all
I'm trying to create a matrix, A, with an unknown variable delta. The code I
have so far is:
D-c(-1, -2/3, -1/3, 0, 1/3, 2/3, 1)
A-matrix(NA,nrow=7,ncol=7)
for (i in 1:7)
{
for (j in 1:7)
{
A[i,j]-exp(-((D[i]-D[j])/delta)^2)
}
}
Of course, R comes up with an error message
You have to define a function. For instance:
Afct - function(delta){
D - c(-1, -2/3, -1/3, 0, 1/3, 2/3, 1)
Dmat - matrix(D, nrow=7, ncol=7)
Smat - Dmat-t(Dmat)
A - exp(-(Smat/delta)^2)
return(A)
}
Afct(2)
Also try to avoid loops...
Best,
Nello
Your data is probably not arranged correctly. See if this works for
your data:
# Creating a reproducible example
set.seed(42)
dat - matrix(rnorm(100*15, 5, 5)+rep(1:15, each=100), 15, 100,
byrow=TRUE)
str(dat)
num [1:15, 1:100] 12.85 13 -2 8.98 16.67 ...
require(gplots)
# Rearranging dat
mm - 1:10
nn - mm + .001
John Kane
Kingston ON Canada
-Original Message-
From: careys...@gmail.com
Sent: Wed, 26 Jun 2013 16:48:34 +0100
To: r-help@r-project.org
Subject: [R] XYZ data
I have x, y, z data. The x, y fields dont change but Z does. How do I add
a
very small
John,
That still leaves a string of identical numbers in the vector.
Shane,
?jitter
perhaps jitter(X,1,0.0001)
Clint
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE:
I have used ifelse in count variables to count the number of times in a
simulation the values of a vector of logprice fall within mutually exclusive
ranges. However, there is a double count in the result i.e. i am getting output
indicating values falling in mutually exclusive ranges. Here is
Another approach passing both D and delta:
Afct - function(D, delta) exp(-(outer(D, D, -)/delta)^2)
D - c(-1, -2/3, -1/3, 0, 1/3, 2/3, 1)
Delta - 2
Afct(D, delta)
-
David L Carlson
Associate Professor of Anthropology
Texas AM University
College Station, TX
Nope, neither work. :-(
On Wed, Jun 26, 2013 at 5:16 PM, Clint Bowman cl...@ecy.wa.gov wrote:
John,
That still leaves a string of identical numbers in the vector.
Shane,
?jitter
perhaps jitter(X,1,0.0001)
Clint
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air
So just to clarify - there is no way to use R CMD BATCH on windows with
Unicode? Any advice of how to use R in a batch mode with Unicode inputs and
outputs?
Ned.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Prof Brian Ripley
perhaps
x-x+0.1*seq(1,length(x))
Clint BowmanINTERNET: cl...@ecy.wa.gov
Air Quality Modeler INTERNET: cl...@math.utah.edu
Department of Ecology VOICE: (360) 407-6815
PO Box 47600FAX:(360) 407-7534
Hi,
Not sure whether there is any pattern in adding the small number.
dat1- read.table(text=
X Y Z
15 20 30
15 20 40
,sep=,header=TRUE)
On 26/06/2013 11:40 AM, Neville O'Reilly wrote:
I have used ifelse in count variables to count the number of times in a
simulation the values of a vector of logprice fall within mutually exclusive
ranges. However, there is a double count in the result i.e. i am getting output
indicating
On Jun 26, 2013, at 17:40 , Neville O'Reilly wrote:
I have used ifelse in count variables to count the number of times in a
simulation the values of a vector of logprice fall within mutually exclusive
ranges. However, there is a double count in the result i.e. i am getting
output
Just because the subject mentions R doesn't mean it is on topic here. This is
more related to Windows than R. I recommend studying windows documentation for
awhile. A quick search turned up a number of discussions on the web, including
I don't see that you have set up mutually exclusive ranges. If we
modify your code so save the maxlogP and minlogP values:
niter = 1e5 # number of iterations is 10^5
CountLoss = rep(0,niter)
CountProf = rep (0,niter)
maxlogP - rep(0, ninter)
minlogP - rep(0, ninter)
set.seed(2009) # enables
You are right, I inadvertently deleted part of the script - so I ended up with
non-mutually exclusive regions. My apologies
Neville O'Reilly, Ph.D
Associate Director, Financial Statistics Risk Management,
Rm 479 Hill Center, Rutgers University, 110 Freylinghuysen Rd.,
Piscataway, NJ 08854.
I have no problems with the windows command line. I don't need any Unicode
there. It really is an internal R question because of the way R is reading and
writing the input and output files.
Ned.
-Original Message-
From: Jeff Newmiller [mailto:jdnew...@dcn.davis.ca.us]
Sent:
Hi,
First: i have looked through previous posts but could get one related to my
problem!
I am trying to fit a negative gompertz curve in my data seems alright but
the curve doesn't bend at the left (max asymptote)...see graph attached.
Here is my code;
EProb=read.table(ProbF.txt,header=TRUE)
Hi!
Iâve just learned about the water crisis and thought you would be interested
to check out this story:
https://waterforward.charitywater.org/et/FF0wBx00
Let me know what you think!
Thanks,
bett
--
Sent via WaterForward, an initiative of charity: water
WaterForward, 387 Tehama
Hi,
Try:
roweqv- function(m,v)
which(!is.na(match(interaction(as.data.frame(m),drop=TRUE),paste(v,collapse=.
v- c(2,5,8)
roweqv(m,v)
#[1] 2
set.seed(24)
m1-matrix(sample(1:15,3e5,replace=TRUE),ncol=3)
v1- c(10,12,4)
system.time(res- roweqv(m1,v1))
# user system elapsed
#0.132
This might also work:
roweqv2- function(m,v){indx-1+Reduce(+,lapply(seq_len(ncol(m)),function(i)
(2^i)*(m[,i]==v[i])))
which(indx==max(indx))}
roweqv2(m,v)
#[1] 2
system.time(res2-roweqv2(m1,v1))
# user system elapsed
#0.008 0.000 0.008
identical(res,res2)
#[1]
I want to paste the contents of the first column of a dataframe
with all the columns of the same dataframe.
What is a good way to do this, perhaps something more elegant than
what I have below. (My actual dataframe has ~400 columns and ~35000
rows.)
example1:
mydf - data.frame(
Given the size of my dataframe (400 columns, 35000 rows), I should
have clarified that speed and efficiency is perhaps as important as
elegance, and I'd like to use the examples to learn about any
corrections and improvements I can make in the examples I provided.
Thanks for any help you can
Anika:
1. You do realize that all columns of your result will be character
(even if they started out as numeric).
2. That being the case, all your data frame columns can be considered
to be character to begin with.
3. That being the case, convert your data frame to a matrix: mdf -
as.matrix(df)
On Jun 25, 2013, at 11:52 AM, Rong lI Li wrote:
Hi, all,
Recently, I met one issue when using socket between R C++ to transmit R
object. Would you pls help give me some suggestions? Many thanks!
[Background]:
I create a socket connection between R C++ binary first, and then, want
to
for plotting purposes, I typically jitter() the x's and y's to see the
otherwise overlapping data points
-Aaron
On Wed, Jun 26, 2013 at 12:29 PM, Shane Carey careys...@gmail.com wrote:
Nope, neither work. :-(
On Wed, Jun 26, 2013 at 5:16 PM, Clint Bowman cl...@ecy.wa.gov wrote:
John,
On Jun 26, 2013, at 5:04 PM, Aaron Mackey wrote:
for plotting purposes, I typically jitter() the x's and y's to see the
otherwise overlapping data points
That is one method for relatively sparse data. Also availble are the use of
transparent colors, 2d-density estimators, and binned hex
I ran into a similar problem and wrote a basic package that uses force field
simulation to adjust object location. While much improvement is possible,
including integration with ggplot, etc. it seems to get the task
accomplished. The following illustrates the functionality. If someone runs
into
Hi,
I've been looking for Image Processing packages without success. I am mainly
interested in image Gray Level Co-occurrence Matrix (GLCM) parameters like
Contrast, Correlation, Energy, Homogeneity.
Is there a package that can do it? Any ideas, comments, etc are welcome.
Thanks.
--
Hello everyone,
I try without success to install the package rPython
I get the message
---
* installing *source* package rPython ...
could not locate python-config
ERROR: configuration failed for package rPython
* removing
This has bounced back twice already - would help if anybody cna remove me from
the list and close my account. I have been deleting 100s of emails daily from
my yahoo inbox becaue i cannot get them to stop, even after i canceld my
account.
my currnet status is that i have an account, but have
On Jun 26, 2013, at 7:37 PM, dinesh wadhwani wrote:
This has bounced back twice already - would help if anybody cna remove me
from the list and close my account. I have been deleting 100s of emails daily
from my yahoo inbox becaue i cannot get them to stop, even after i canceld
my
Hello,
You need to install python-devel.
Regards,
Pascal
On 27/06/2013 12:24, Kaptue Tchuente, Armel wrote:
Hello everyone,
I try without success to install the package rPython
I get the message
---
* installing *source*
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