It is a little more complex than that.
readTiff is not part of R. It is in an unstated package, and there are
instances in packages biOps and rtiff.
There are also readTIFF in packages tiff and beadArray. It is
tiff::readTIFF that I would recommend. Its help says it can read 32-bit
Tiago V. Pereira tiago.pereira at mbe.bio.br writes:
I am trying to double integrate the following expression:
# expression
(1/(2*pi))*exp(-y2/2)*sqrt((y1/(y2-y1)))
for y2y10.
I am trying the following approach
# first attempt
library(cubature)
fun - function(x) {
Prof Brian Ripley ripley at stats.ox.ac.uk writes:
Basically Remote Desktop restricts the number of colours when connecting
to a Windows Server machine, and interpolating rasters needs a lot of
colours.
Hi Brain,
I looked into this further and have a solution.
1. On the server launch
Dear all,
Could someone please point me to the definitive list of valid
characters that are allowed in object names in R? I believe that the
following list covers them:
_.abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
but I would like to make sure.
Thank you,
Liviu
--
Do you
Hello,
(Apologies for the repost, but it appears that the original text was
garbled.)
I have recently discovered the modeest library, and am trying to understand
how to use it with non-numeric data (e.g. determining the most common last
name, or analysing customer demographics by zip code).
I
Hi
Quick question. I am running a multiple regression function for each column of
two data sets. That means as a result I get several coefficients. I have a
problem because data that I use for regression contains NA. How can I ignore NA
in lm function. I use the following code for regression:
On 13-07-27 7:36 AM, Liviu Andronic wrote:
Dear all,
Could someone please point me to the definitive list of valid
characters that are allowed in object names in R? I believe that the
following list covers them:
_.abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789
but I would like
On Sat, Jul 27, 2013 at 3:08 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
Your question is a little ambiguous. All characters are allowed in object
names, but the parser will only recognize some of them if they are quoted in
backticks.
The ones it recognizes without the backticks are
So, I downloaded the source files of Hmisc and changed in the file latex.s line
688 'rotate' to 'sideways'. This does the work for landscape ctables in Latex.
I also wrote an email to the package maintainer. I consider this thread as
solved.
Best
Simon
On Jul 26, 2013, at 5:34 PM, Simon
I did indeed install the r-base-dev.
However, I did not send to the Debian mailing list.
Thanks,
Erin
On Sat, Jul 27, 2013 at 12:27 AM, David Winsemius dwinsem...@comcast.netwrote:
On Jul 26, 2013, at 9:45 PM, Erin Hodgess wrote:
Hello!
I have just installed R on an Ubutnu machine
HI,
set.seed(28)
dat1- as.data.frame(matrix(sample(c(NA,1:20),100,replace=TRUE),ncol=10))
set.seed(49)
dat2- as.data.frame(matrix(sample(c(NA,40:80),100,replace=TRUE),ncol=10))
lapply(seq_len(ncol(dat1)),function(i) {lm(dat2[,i]~dat1[,i])}) #works bcz the
default setting removes NA
Regarding
I have not tried anything like that but have a look at
I have searched the r-help archive and saw only one unanswered post related
to mine.
My design is as follows.
- y is Bernoulli response
- x1 is continuous variable
- x2 is categorical (factor) variable with two levels
The experiment is completely within subjects. That is, each subject
Stanislav Aggerwal stan.aggerwal at gmail.com writes:
I have searched the r-help archive and saw only one
unanswered post related
to mine.
Take a look at the r-sig-mixed-models (@r-project.org)
mailing list and archive ...
My design is as follows.
- y is Bernoulli response
-
Hi
Thanks for your hints. I would like to describe my problem better and give an
examle of the data that I use.
I conduct the event study and I need to create abnormal returns for the daily
stock prices. I have for each stock returns from time period of 8 years. For
some days I don't have the
HI,
I couldn't get any error message with the data you provided.
return- read.table(text=
ATI AMU
-1 0.734 9.003
0 0.999 2.001
1 3.097 -1.003
2 NA NA
3 NA 3.541
,sep=,header=TRUE)
median- read.table(text=
ATI AMU
-1 3.224
Hi.
I've been puzzling about how to replace the nested loops below. The idea
is that the B dataframe has rows with a posix datetime and the C
dataframes has posix Start and End times. I want to assign a value to
the observations in B based in intersecting the appropriate
time-interval in C.
Dear R-helpers,
I compared various programs for cubic spline smoothing, and it appeared
that smooth.spline ( stats version 3.0.1) seems to behave surprisingly.
For enough long series and low values of lambda (or spar), the results
of smooth.spline seem to be different from those of sreg (
On 13-07-27 2:50 PM, Jean-Luc Dupouey wrote:
Dear R-helpers,
I compared various programs for cubic spline smoothing, and it appeared
that smooth.spline ( stats version 3.0.1) seems to behave surprisingly.
For enough long series and low values of lambda (or spar), the results
of smooth.spline
Perhaps: ?findInterval
(you may need to do some type conversion first)
-- Bert
On Sat, Jul 27, 2013 at 3:28 PM, John Helly hel...@ucsd.edu wrote:
Hi.
I've been puzzling about how to replace the nested loops below. The idea is
that the B dataframe has rows with a posix datetime and the C
Dear all,,
thank you all for your help..Its been such a help but its not really
exactly what I am looking for. Apparently I havent explained the condition
very clearly. I hope this can works.
If the data on column product is duplicated from the previous row, (its
applied for response==buy and
HI,
May be this is what you wanted.
#using tt1
indx-which(tt1$response==buy)
tt1$newcolumn-0
tt1[unique(unlist(lapply(seq_along(indx),function(i){x1-if(i==length(indx))
seq(indx[i],nrow(tt1)) else if((indx[i+1]-indx[i])==1) indx[i] else
seq(indx[i]+1,indx[i+1]-1);x2-
If you wanted to wrap it in a function:
fun1- function(dat,colName,newColumn){
indx- which(dat[,colName]==buy)
dat[,newColumn]-0
dat[unique(unlist(lapply(seq_along(indx),function(i){
x1- if(i==length(indx)){
seq(indx[i],nrow(dat))
}
All,
What is the current method for installing tikzDevice in R version 3.0.1? I'd
like to use it with knitr and RStudio.
Thanks.
D.
--
View this message in context:
http://r.789695.n4.nabble.com/tikzDevice-tp4672523.html
Sent from the R help mailing list archive at Nabble.com.
It seems I can still install from source under Ubuntu:
install.packages('tikzDevice', repos='http://r-forge.r-project.org',
type='source')
If you are under Windows, I think you have to install RTools.
I'm cc'ing its author to see if there is still hope to get it back to
CRAN, or if someone else
I am using a MacBook Pro, 10.6.8, R version 3.0.1. and RStudio 0.97.551. I
entered your command in the Console Window in RStudio and got the following
reply:
install.packages('tikzDevice', repos='http://r-forge.r-project.org',
type='source')
Warning in install.packages :
package ‘tikzDevice’
The following minimal example Sweave file compiled properly in RStudio.
\documentclass{article}
\begin{document}
Example text outside R code here; we know the value of pi is \Sexpr{pi}.
my-label, eval=TRUE, dev='tikz'=
set.seed(1213) # for reproducibility
x = cumsum(rnorm(100))
mean(x) # mean
Dear Vanessa,
Glad to know that it works.
Sorry, I misunderstood ur question initially because there were no duplicates
for product from response==buy in your initial dataset (tt).
Regarding the code: what i did in brief is:
1. Find the rows with response==buy
indx- which(dat[,colName]==buy)
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