I would appreciate it if you would follow the Posting Guide and give a
reproducible example and post all messages using plain text.
Try
m1 - matrix(sample(0:999,2*1057837,TRUE),ncol=2)
m2 - matrix(sample(0:999,2*951980,TRUE),ncol=2)
df1 - as.data.frame(m1)
df2 - as.data.frame(m2)
library(sqldf)
Hello,
There's a bug in the line
for (i in 1:length(dim(somdata.xyf$codes$X)[2]))
length() is always 1, you can use simply 1:dim(...)[2] or even simpler
for(i in 1:ncol(somdata.xyf$codes$X))
As for a way without a loop, you could use ?sapply:
sapply(1:ncol(somdata.xyf$codes$X), function(i)
I have 500 ids ; i want to take out even and odd ids separately and store it
another data files.
How can it be done in R by using *If and for loop* ??
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Hi Jim,
close(filedescriptors$cpufiledescriptors[[1]])
close(filedescriptors$cpufiledescriptors[[2]])
close(filedescriptors$cpufiledescriptors[[3]])
I might be doing something wrong. Error is
Error in UseMethod(close) :
no applicable method for 'close' applied to an object of
Hi all,
I think this should be an easy question for the guru's out here.
I have this large data frame (2.500.000 rows, 15 columns) and I want to add
a column named SEGMENT to it.
The first 5% rows (first 125.000 rows) should have the value Top 5% in the
SEGMENT column
Then the rows from 5% to
Dear R helper,
I have a statistic question.
I have a vector of 500 values for which I need to assess the statistical
significance of occurrence
real.dist - realValues
For that, I sampled from my data large data pool 1000 other vectors of 500
values each.
I then run ks.test with my real vec vs
Dear all,
I'm running a model with one fixed factor which has four groups called
species, and a clustering factor called nest. My dependent variable
(timeto) is ttm (time to moult) which is number of days
Hei,
i have a species abundance data set CommData, with n (samples)=40 and p
(species)=107.
Sample Species A Species B Species C Species D ….
411_201040 20 0 0
412_201030 20 0 0
413_20100 0
Hello,
Who told you you need a loop or an if?
even - function(x) x %% 2 == 0
x - 1:50
idx - even(x)
x[idx]
Hope this helps,
Rui Barradas
Em 31-07-2013 08:46, ravi.raghava1 escreveu:
I have 500 ids ; i want to take out even and odd ids separately and store it
another data files.
How can
Hello,
Combine quantile() with findInterval(). Something like the following.
# sample data
x - rnorm(100)
val - c(Bottom 50, 20 to 50, 5 to 20, Top 5%)
qq - quantile(x, probs = c(0, 0.50, 0.70, 0.95, 1))
idx - findInterval(x, qq)
val[idx]
Hope this helps,
Rui Barradas
Em 31-07-2013
Hi,
May be this helps:
set.seed(24)
dat1- data.frame(ID=1:500,value=rnorm(500))
res- split(dat1,dat1$ID%%2)
A.K.
- Original Message -
From: ravi.raghava1 ravi.ragh...@classle.co.in
To: r-help@r-project.org
Cc:
Sent: Wednesday, July 31, 2013 3:46 AM
Subject: [R] Using If loop in R how
Hi,
May be this helps:
set.seed(24)
dat1- data.frame(ID=1:500,value=rnorm(500))
indx-round(quantile(as.numeric(row.names(dat1)),probs=c(0.05,0.20,0.50,1)))
indx1-findInterval(row.names(dat1),indx,rightmost.closed=TRUE)
dat1$SEGMENT- as.character(factor(indx1,labels=c(Top 5%,5 to 20,20 to
50,
Would anyone of the more experienced r-users explain to me the
behaviour of the scale parameter in the heatmap function.
different options for scale (R 3.0.1) do change only the colors but do
not affect the dendrograms. Please see for yourself executing the
following code:
d -
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,
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Hi,
set.seed(24)
dat1- data.frame(ID=1:500,value=rnorm(500))
dat1 - dat1[order(-dat1$value),]
row.names(dat1)-1:nrow(dat1)
indx-round(quantile(as.numeric(row.names(dat1)),probs=c(0.05,0.20,0.50,1)))
indx1-findInterval(row.names(dat1),indx,rightmost.closed=TRUE)
dat1$SEGMENT-
Dear list,
I have a matrix showing the species presence-absence on a map.
Its rows are map locations, represented by GridCellID, such as GID1 and GID
5.
Its columns are species ID, such as D0989, D9820, and D5629.
The matrix is as followed.
Now I want to merge the GridCellID according to
HI,
Please use ?dput()
mat1- as.matrix(read.table(text=
D0989 D9820 D5629 D4327 D2134
GID_1 1 0 0 1 0
GID_2 0 1 1 0 0
GID_4 0 0 1 0 0
GID_5 1 1 0 0 0
GID_7 0 1 0 0
Hi All,
I am new at R so any help would be appreciate.
Below my current R-code/script:
initial.dir-getwd()
setwd('/Users/jurgens/VirtualEnv/venv/Projects/QTLS/Resaved_Results')
dataset - read.table(LWxANNA_FinalReport_resaved_spwc.csv, header=TRUE,
sep=\t )
n - length(dataset$X..No.Call)
x -
Dear R-Users and R-Devels,
I have a problem when using knitr in combination with Hmisc. I generate a
data.frame which has mixed scientific and non-scientific numbers inside. In my
Latex Table I just want to have non-scientific format, so I call
latex(myDataFrame,
file = '',
cdec = c(0, rep(4,
Errata:
it must say:
latex(myDataFrame,
file = '',
cdec = c(0, rep(4, NCOL(myDataFrame) - 1))
)
But this does not work. Scientific notation is very robust :)
Apologize
Simon
On Jul 31, 2013, at 5:05 PM, Simon Zehnder szehn...@uni-bonn.de wrote:
Dear R-Users and R-Devels,
I have a
Hi,
May be this helps:
set.seed(25)
mt1- matrix(sample(c(NA,1:40),20*200,replace=TRUE),ncol=200)
set.seed(487)
mt2- matrix(sample(c(NA,1:80),20*200,replace=TRUE),ncol=200)
res- sapply(seq_len(ncol(mt1)),function(i)
cor(mt1[,i],mt2[,i],use=complete.obs,method=pearson))
A.K.
Hello, I've
In your example all of the values are drawn from the same
distribution so there will not be substantial differences (row
means/variances and column means/variances will be
approximately the same).
set.seed(42)
d - matrix(rnorm(100),nrow=20)
# Start with your example and modify the row/col means
Hello,
Sorry, that should be 0.80, not 0.70.
qq - quantile(x, probs = c(0, 0.50, 0.80, 0.95, 1))
Rui Barradas
Em 31-07-2013 12:22, Rui Barradas escreveu:
Hello,
Combine quantile() with findInterval(). Something like the following.
# sample data
x - rnorm(100)
val - c(Bottom 50, 20 to
On Jul 29, 2013, at 11:52 AM, Rapsomaniki, Eleni wrote:
Dear R helpers,
Is there a way to display mathematical notations (e.g. greek characters,
subscripts) properly in study (studlab) and group (byvar) labels in a forest
plot created using the meta package?
#Example:
library(meta)
It's a bit difficult to know what you are doing without any data. Would you
supply some data please.
See ?dput for the easiest way to supply it. Also have a look at
https://github.com/hadley/devtools/wiki/Reproducibility and/or
Hi Stavros
xmlToDataFrame() is very generic and so doesn't know anything
about the particulars of the XML it is processing. If you know
something about the structure of the XML, you should be able to leverage that
for performance.
xmlToDataFrame is also not optimized as it is just a convenience
Our Hmisc package summary.formula function and its latex methods can
make some fairly advanced tables. But the tables have to be regular.
For example, all rows of the tables are based on the same data frame.
I'm thinking that what is needed is a ggplot2-like set of functions for
building a
On 13-07-31 4:03 PM, Frank Harrell wrote:
Our Hmisc package summary.formula function and its latex methods can
make some fairly advanced tables. But the tables have to be regular.
For example, all rows of the tables are based on the same data frame.
I'm thinking that what is needed is a
Hello R community,
I am creating some network representations using the qgraph package (big
thanks to Sacha Epskamp for developing it!). The package is very well
documented, but I am unable to find how to create a legend (scale) for edge
thickness. In one of his qgraph examples, Sacha shows such
Hello,
I am trying to geocode an address using the Google API and R. So far, I have
used the following code:
location-c('120 Avenue de la Republique, 92120 Montrouge, France')
location - gsub(' ', '+', location)
sensor-c('FALSE')
sensor4url - paste('sensor=', tolower(as.character(sensor)), sep =
Could anyone tell me how,from a pool of 1002 observations (one variable), can
I resample 1000 samples of 20 observations?
And then calculate the mean and standard deviation between 2, 3, 4, ..., 1000
samples and plot them?
Thank you!
_
Rita Gamito
Centro de
Hi
First of all, thanks for this service, it is being very useful for me. I am new
in R so I have a lot of doubts.
I have to do imputation in a data set, this is a sample of my data set which
looks like:
NUMERO Data1 Data2 IE.2003 IE.2004 IE.2005 IE.2006 IE.2007 IE.2008
IE.2009
Hello,
I am a little bit lost on my search for a solution and idea. I would like
to split my time serie in blocks of night. V1 indicates if its night or
not.
How can i split this kind of cases?
Best regards,
str(ou[,c(1,3,8)])
'data.frame': 863 obs. of 3 variables:
$ Fecha: POSIXct,
Works like a charm, thanks a lot!
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Sent from the R help mailing list archive at Nabble.com.
Hi all,
I experienced some unmatched result using mean function in ffbase package
and cannot figure out what's wrong.
I have a simulated ff vector with 10 numbers inside and want to
calculate its mean. But the results are quite different.
With mean( ) function in ffbase package, the
Hello, I've got the following problem.
I have to matrices each containing 200 time series.
Now I want to calculate the correlation of the first time series of each of
the matrices.
I use the following command:
cor(mts1[,1],mts2[,1], use=complete.obs, method=c(pearson))
cor(mts1[,2],mts2[,2],
Hi Arun Kirshna,
I have tested your method and it will work for me.
I only run into one problem. Before I want to do this operation I have
sorted my data frame so my rownumbers ar not subsequent.
You can see if you first order your example data frame like:
dat1 - dat1[order(-dat1$value),]
Hi.
See ?sample, ?replicate,?colMeans, ?plot..
Here is the simple example:
sample(1:1000,20)
replicate(5, sample(1:1000,20))
colMeans(replicate(5, sample(1:1000,20)))
Andrija
On Wed, Jul 31, 2013 at 1:23 PM, Rita Gamito rslo...@fc.ul.pt wrote:
Could anyone tell me how,from a pool of 1002
A Q for Canadians who have filled out the new Canadian common CV for
grant applications: is there
any way to cite research contributions of software such as R packages,
aside from published journal
articles? If so, where/how in the online application can they be entered?
For example, under
sapply(1:200, function(x) cor(mts1[,x], mts2[,x],
use=complete.obs, method=c(pearson)))
-
David L Carlson
Associate Professor of Anthropology
Texas AM University
College Station, TX 77840-4352
-Original Message-
From: r-help-boun...@r-project.org
Dear Arun
Thank you for the very useful help.
However, please kindly explain the code below.
row.names(mat1)- gsub([_], ,row.names(mat1))
1. what does [_] mean?
2. what doesmean?
3. what does row.names(mat1) mean?
I checked ?gsub but still did not get the idea.
Thank you again
Elaine
On
Enter
?help
at the prompt to learn how to use R's (extensive) Help system to
answer questions like this.
For this question:
?split ## what else?
Also ?tapply, ?ave, ?aggregate, ?by
may be relevant.
Also, read AN Introduction to R if you haven't already done so to
start learning about R's many
Time to do some homework, Elaine:
?regexp
There are also numerous online tutorials on regular expressions that
you can use to educate yourself.
Cheers,
Bert
On Wed, Jul 31, 2013 at 2:07 PM, Elaine Kuo elaine.kuo...@gmail.com wrote:
Dear Arun
Thank you for the very useful help.
However,
Hi-
I have a 37 X 473971 character matrix that I am trying to convert into a
numeric matrix. When I use the code:
class(matrix) = numeric
I end up with something called a double matrix whose dimensions are still
37 X 473971
I have also tried
new = apply(matrix,2, as.numeric) and got
Duncan,
I had read your excellent tables package vignette at
http://cran.r-project.org/web/packages/tables/vignettes/tables.pdf when
it first came out. It is extremely impressive. I'm glad to be reminded
to give it another look.
Is there a way to make the special symbols n and 1 refer to
What are the entries in your matrix? If they are something that won't coerce
to numeric, you need to backtrack. Note how R distinguishes types of characters.
as.numeric(a)
[1] NA
Warning message:
NAs introduced by coercion
as.character(2)
[1] 2
as.numeric(2)
[1] 2
On Jul 31, 2013, at 1:47
In R, double is a synonym for numeric.
Please see
?numeric
The details section of ?numeric begins with
Details:
'numeric' is identical to 'double' (and 'real'). It creates a
double-precision vector of the specified length with each element
equal to '0'.
Rich
On Wed, Jul 31,
Hello,
double and numeric are the same. From the help page for ?double,
section Note on names
It is a historical anomaly that R has two names for its floating-point
vectors, double and numeric (and formerly had real).
Apparently you are successfully converting characters to double
It is hard to understand that your R code will not work with a
double matrix since double is just short for double precision
floating point matrix. Your only alternative would be integer.
From ?numeric
It is a historical anomaly that R has two names for its
floating-point vectors, double and
I'm trying to build a data.frame row-by-row like so:
df - data.frame(rbind(list('a',1), list('b', 2), list('c', 3)))
I was surprised to see that the columns of the resulting data.frame
are stored in lists rather than vectors.
str(df)
'data.frame': 3 obs. of 2 variables:
$ X1:List of 3
..$ :
In R double and numeric mean essentially the same thing. I think
you are fine. (What called the result a double matrix?)
z - cbind(c(11, 12), c(3.14, 2.718))
str(z)
chr [1:2, 1:2] 11 12 3.14 2.718
class(z)
[1] matrix
class(z) - numeric
str(z)
num [1:2, 1:2] 11 12 3.14
Hello,
The best way seems to be ?replicate.
set.seed(3997) # make it reproducible
x - rnorm(1002) # make up some data
sim - replicate(1000, sample(x, 20))
colSds - function(x, na.rm = FALSE) apply(x, 2, sd, na.rm = na.rm)
mu - colMeans(sim)
sigma - colSds(sim)
Hope this helps,
Rui
May be this helps:
l1- list('a',1)
l2- list('b',2)
l3- list('c',3)
df1-data.frame(mapply(`c`,l1,l2,l3,SIMPLIFY=FALSE),stringsAsFactors=FALSE)
colnames(df1)-paste0(X,1:2)
str(df1)
#'data.frame': 3 obs. of 2 variables:
# $ X1: chr a b c
# $ X2: num 1 2 3
A.K.
- Original Message
Hi Elaine,
In that case:
Do you have GID in the IslandA and IslandBs?
IslandA-c(GID 1, GID 5)
IslandB- c(GID 2, GID 4, GID 7)
If there is no change in the two Islands, then using the same dataset:
mat1- as.matrix(read.table(text=
D0989 D9820 D5629 D4327 D2134
GID_1 1 0 0
Hi,
Not clear about your desired output.
source(ou.txt)
split(ou,ou$V1) #split based on values of V1 (1 and 0)
#or
#may be you wanted 1 followed by 0 in one block, again 1 followed by 0 in
second block etc..
#In that case:
lst1-split(ou,cumsum(c(TRUE,diff(ou$V1)==1)))
A.K.
On Wed, Jul 31,
Hi,
In that case:
lst1-split(ou,cumsum(c(TRUE,diff(ou$V1)==1)))
lst2-lapply(lst1,function(x) x[x$V1==1,])
A.K.
From: Dominic Roye dominic.r...@gmail.com
To: arun smartpink...@yahoo.com
Sent: Wednesday, July 31, 2013 7:17 PM
Subject: Re: [R] Split in
R and S+ Courseshttp://www.solutionmetrics.com.au/
Brisbane, Melbourne Sydneyhttp://www.solutionmetrics.com.au/
Hi,
Apologies for cross-posting
SolutionMetrics is presenting R and S+ courses in Brisbane, Melbourne Sydney
- August September, 2013
To book, please email
On 07/31/2013 10:03 PM, Mª Teresa Martinez Soriano wrote:
Hi
First of all, thanks for this service, it is being very useful for me. I am new
in R so I have a lot of doubts.
I have to do imputation in a data set, this is a sample of my data set which
looks like:
NUMERO Data1
Hello,
I have a basic panel of histograms as follows, whose current colors don't
matter:
binsize=diff(range(thing$Rate))/64
ggplot(thing, aes(x=Rate, fill=Series)) + geom_histogram(binwidth=binsize) +
facet_grid(Series~.,scales=free)+
labs(fill=Index) +
xlab(Growth Rate (%)) +
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