Hi
Posting in HTML results in scrambled mail.
Maybe you want
?aggregate
Regards
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Rewarp
Sent: Thursday, February 13, 2014 12:55 AM
To: r-help@r-project.org
Subject: [R]
Hi
?lm
?summary
?-
Regards
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of frankreynolds
Sent: Wednesday, February 12, 2014 8:22 PM
To: r-help@r-project.org
Subject: [R] simple linear regression
okay so how do you
Sorry if the email became messed up. I have written the full thing on
pastebin.
pastebin.com/AXvGstaR
Thanks for the suggestion. I will play test with aggregate!
*--Bitmessage http://bitmessage.org/ me*
*BM-2D97QV3Y4VRfjayrWahqE61XKuQw6dJvj6*
On 13 February 2014 06:51, PIKAL Petr
Le 12/02/2014 20:22, frankreynolds a écrit :
okay so how do you run a simple linear regression, obtain the summary of
that, and then put it in an object?
Generally, it is just being polite to add: Please, thanks... these
little words could help a lot.
You should learn to use google. There
Hi
I want to search for multiple pattern as grep is doing for a single
pattern, but this obviously not work:
grep(an, month.name)
[1] 1
grep(em, month.name)
[1] 9 11 12
grep(eb, month.name)
[1] 2
grep(c(an, em, eb), month.name)
[1] 1
Warning message:
In grep(c(an, em, eb), month.name) :
On 12.02.2014 15:55, ben1983 wrote:
Hi All,
I've been trying to write my own code for LDA (linear discrim) so I
can modify it to be weighted LDA since some of my groups are outliers.
However, the code I write for standard LDA gives me slightly different
results to those from R
Hi
Maybe I am missing something but isn't this
which(letters %in% c(a, x))
what you want?
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Rainer M Krug
Sent: Thursday, February 13, 2014 3:43 PM
To:
On Feb 13, 2014, at 8:43 AM, Rainer M Krug rai...@krugs.de wrote:
Hi
I want to search for multiple pattern as grep is doing for a single
pattern, but this obviously not work:
grep(an, month.name)
[1] 1
grep(em, month.name)
[1] 9 11 12
grep(eb, month.name)
[1] 2
grep(c(an, em, eb),
I can do this in multiple steps with summarise, joins, etc., but can't
help thinking it can be accomplished in one plyr call.
Here's a small example:
require(plyr)
require(lubridate)
data - data.frame(
+ date = rep(as.Date(ymd(20140101 + (0:3) * 100)), 2),
+ state = rep(c(A, B), each =
Hello,
I'm looking for a function that groups elements below a certain distance
threshold, based on a distance matrix. In other words, I'd like to group
samples without using a standard clustering algorithm on the distance matrix.
For example, let the distance matrix be :
A B C
sir/mam
may i know how to install RHadoop on windows?
Mansi
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
I have the parameters of a gamma distribution that I am trying to plot. The
parameters are shape = 2, scale = 5.390275 and the minimum value x0 is
65.44945.
Since the gamma is shifted by x0, we have
Mean = shape*scale + x0 = 76.23
My question is, how can I do it in r?
use the | in regular expressions:
grep(c(an|em|eb, month.name)
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Thu, Feb 13, 2014 at 9:43 AM, Rainer M Krug rai...@krugs.de wrote:
Hi
I want to search
You need to re-think. What you said is nonsense. Use an appropriate
clustering algorithm.
(a can be near b; b can be near c; but a is not near c, using near =
closer than threshhold)
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information
On 02/13/14, 17:23 , jim holtman wrote:
use the | in regular expressions:
grep(c(an|em|eb, month.name http://month.name/)
Thanks - again a reason to learn regexp.
Cheers,
Rainer
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you
ddply(data, state, function(x) x[x$date == max(x$date), ])$value
On Thu, Feb 13, 2014 at 11:13 AM, Dan Murphy chiefmur...@gmail.com wrote:
I can do this in multiple steps with summarise, joins, etc., but can't
help thinking it can be accomplished in one plyr call.
Here's a small example:
Hi,
Try ?which.max() # unique values for the combination.
ddply(data,.(state),summarize,max_date=value[which.max(date)])[,2]
#or
ddply(data,.(state),summarize,max_date=value[date == max(date)])[,2]
A.K.
On Thursday, February 13, 2014 11:15 AM, Dan Murphy chiefmur...@gmail.com
wrote:
I can
On 13/02/2014 16:25, Rainer M Krug wrote:
On 02/13/14, 17:23 , jim holtman wrote:
use the | in regular expressions:
grep(c(an|em|eb, month.name http://month.name/)
Thanks - again a reason to learn regexp.
Note though that is an *extended* regex. They are the default in R, but
not for
On 13-Feb-2014 15:30:43 Rodrigo Cesar Silva wrote:
I have the parameters of a gamma distribution that I am trying to plot.
The parameters are shape = 2, scale = 5.390275 and the minimum value
x0 is 65.44945.
Since the gamma is shifted by x0, we have
Mean = shape*scale + x0
It is not hard to write your own function:
dsgamma - function(x, x0=0, ...) {
dgamma(x-x0,...)
}
and similar for the other functions.
You might also want to look at ?curve for plotting (your plotting is
fine, curve is just another option).
On Thu, Feb 13, 2014 at 8:30 AM, Rodrigo Cesar Silva
One place to look is:
http://www.burns-stat.com/documents/tutorials/impatient-r/
This gives basic information on using R, and if that doesn't
suffice, gives some hints about asking questions.
Welcome to the R world.
Pat
On 13/02/2014 02:01, Kei_Takeuchi wrote:
Dear R users,
Hello, this is
I appreciate the several replies.
efac = 2 had already been set in the forest call.
Adding lwd = 2 in the forest call has improved the visibility of the
credibility interval.
Nathan
-Original Message-
From: Viechtbauer Wolfgang (STAT)
wolfgang.viechtba...@maastrichtuniversity.nl
Redefining methods of a refClass does not change the methods for
existing instances. I found this somewhat surprising, and also pretty
inconvenient for debugging.
The documentation for reference classes does say that their methods
should be minimalist, which I suppose is partly because of
If R changes from 3.0.1 to 3.0.2, or more generally from m.n.p to m.n.q,
is it necessary to refresh libraries to match the version, e.g., with
update.packages(checkBuilt=TRUE, ask=FALSE)? The R Windows FAQ 2.8 says
For those with a personal library (folder R\win-library\x.y of your
home
Dear all,
I am working with glmnet but the problem arises also in all other Lasso
implementations:
It is ususally recommended to standardize the variables / use intercept and
this works well with the implemented options:
x - matrix(rnorm(1), ncol=50)
y - rnorm(200)
Hello there,
I am new to R and have no previous experience using any other statistics
software. Can someone send me basic R notes to help me start off for the
very first time?
*With Kind regards,*
* God bless you*
* Shikami K. Akweyu Manager; Fisheries ComponentKenya Coastal Development
On 13/02/2014 15:51, Marc Schwartz wrote:
On Feb 13, 2014, at 8:43 AM, Rainer M Krug rai...@krugs.de wrote:
Hi
I want to search for multiple pattern as grep is doing for a single
pattern, but this obviously not work:
grep(an, month.name)
[1] 1
grep(em, month.name)
[1] 9 11 12
grep(eb,
Thanks for the suggestion, Jeff! As it turned out, the automatic Java
update installed the 32-bit version of Java for me. Installing the
64-bit version fixed this.
Regards,
Yury
On 2/12/2014 7:10 PM, Jeff Newmiller wrote:
Have you investigated the suggestion in the error message yet?
Dear Shikami,
R comes with excellent material, look for it in your /doc/manual folder, start
with R-intro.pdf.
Have fun on your hopfully long journey with R!
daniel
Feladó: r-help-boun...@r-project.org [r-help-boun...@r-project.org] ;
meghatalmaz#243;:
HI Farnoosh,
You can use ?dcast()
library(plyr)
dcast(DataA,ID~Var1,value.var=Var2)
# ID A B
#1 1 100 50
#2 2 200 100
A.K.
On Thursday, February 13, 2014 2:59 PM, farnoosh sheikhi
farnoosh...@yahoo.com wrote:
Hi Arun,
I hope all is well. I need to aggregate a data like below:
Sorry, the library should be
library(reshape2)
On Thursday, February 13, 2014 4:27 PM, arun smartpink...@yahoo.com wrote:
HI Farnoosh,
You can use ?dcast()
library(plyr)
dcast(DataA,ID~Var1,value.var=Var2)
# ID A B
#1 1 100 50
#2 2 200 100
A.K.
On Thursday, February 13, 2014
Readers,
A csv file was created:
column1,column2,column3,column4
1,10,3,2
2,20,6,4
3,30,12,16
4,40,24,256
The csv was imported:
testcsv-read.csv('/path/to/test.csv')
testsum-testcsv[2,2]+testcsv[2,3]+testcsv[2,4]
What is the correct syntax to abbreviate the following command using
the
The official documentation is at
http://cran.r-project.org/manuals.html
There are also many introductory guides that have been
written by R users at
http://cran.r-project.org/other-docs.html
Including for example:
Using R for Data Analysis and Graphics by John Maindonald
R for Beginners by
On 14/02/14 10:46, e-letter wrote:
Readers,
A csv file was created:
column1,column2,column3,column4
1,10,3,2
2,20,6,4
3,30,12,16
4,40,24,256
The csv was imported:
testcsv-read.csv('/path/to/test.csv')
testsum-testcsv[2,2]+testcsv[2,3]+testcsv[2,4]
What is the correct syntax to abbreviate
Hi Farnoosh,
If I understand it correctly,
dat -read.table(text=Var1
Great5
great
'less great2'
'approx great11',sep=,header=TRUE,stringsAsFactors=FALSE)
dat$Var1 - gsub(.*(great).*,\\L\\1,dat$Var1,ignore.case=TRUE,perl=TRUE)
dat$Var1
#[1] great great great great
A.K.
On Thursday, February
I was trying to understand the boxcox function in MASS to get a better
understanding of where and how the log-Likelihood values are calculated.
By using debug(boxcox) I found this code while running the examples:
m - length(lambda)
object - lm(object, y = TRUE, qr = TRUE, ...)
Thanks:)
Regards, Farnoosh Sheikhi
On Thursday, February 13, 2014 1:29 PM, arun smartpink...@yahoo.com wrote:
Sorry, the library should be
library(reshape2)
On Thursday, February 13, 2014 4:27 PM, arun smartpink...@yahoo.com wrote:
HI Farnoosh,
You can use ?dcast()
library(plyr)
Hi,
I'm printing a bunch of summary tables to a latex file using latexVerbatim
from the Hmisc package.
An example looks like this...
x
Visit N Min. 1st Qu. Median Mean 3rd Qu. Max. NAs
[1,] 1 92 25 27.28 29.05 29.47 31.75 34.8 0
And I'm using commands like this...
Perfect. Thank you so much.
Regards, Farnoosh Sheikhi
On Thursday, February 13, 2014 2:16 PM, arun smartpink...@yahoo.com wrote:
Hi Farnoosh,
If I understand it correctly,
dat -read.table(text=Var1
Great5
great
'less great2'
'approx great11',sep=,header=TRUE,stringsAsFactors=FALSE)
On 13/02/2014, Rolf Turner r.tur...@auckland.ac.nz wrote:
What you've written is simply not (anything like!) R syntax. You should
learn to speak R if you are going to use R.
Agree; was reviewing the help text examples invoked by '?with'.
In this particular instance
testsum -
Have you tried:
?NextMethod
?
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
H. Gilbert Welch
On Thu, Feb 13, 2014 at 2:17 PM, Gene Leynes gleyne...@gmail.com wrote:
I
Hi great that was easy I feel like a bit of a fool for not figuring this
out.
TO LOAD ALL SAVED MODELS AT ONCE:
library(biomod2)
# change directory to where you stored you’re original models (my documents
is default if you did not specify). Go into the file models
*# TO LOAD ALL SAVED MODELS
Hi,
I am trying to produce a ggplot graph using specific characters in the
labels, but ggplots doesn't seem to support certain symbols.
For example, when I type:
print(\u25E9)
it shows a square which is half black, but when I try to use it in ggplot
it doesn't print.
I am using facet_wrap, but
There is no contrast() function in R itself, but this seems to be about
contrasts().
On 14/02/2014 04:35, jimj wrote:
I have been asked to see if there is a linear trend in 3 groups of data (5
points each) by using ANOVA and linear contrasts. The 3 groups represent
data collected in 2010,2011
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