Hi R-helpers,
Can someone help me with this function
prepArr - function(CA) {
if(CA$CD_ACCRUAL_FLAG == 'AY' ){
if(!is.na(CA_AMT_PAYBACK ){
CA$IND_COLLECTION[(CA$TOT_PAID=CA$TOT_ARREAR_BEG|
CA$TOT_PAID=CA_AMT_PAYBACK)] - 1L
Hi,
At the 3rd line, a bracket is missing, to close the if statement.
HTH
Pascal
On Thu, Jul 3, 2014 at 3:29 PM, Abhinaba Roy abhinabaro...@gmail.com wrote:
Hi R-helpers,
Can someone help me with this function
prepArr - function(CA) {
if(CA$CD_ACCRUAL_FLAG == 'AY' ){
Hi,
The 'if' statement closes
CA$IND_COLLECTION[CA$TOT_PAID=
=0] - 5L}
On Thu, Jul 3, 2014 at 12:12 PM, Pascal Oettli kri...@ymail.com wrote:
Hi,
At the 3rd line, a bracket is missing, to close the if statement.
HTH
Pascal
On Thu, Jul 3, 2014 at 3:29 PM, Abhinaba Roy
I am a new convert to R (from SAS). I am a research scientist and most of
my
use of SAS was in data analysis. Recently, I have been wanting to use R to
create a simple, reliable way to summarize a dataset of student demographics
for a university.
The spreadsheet has a row for every student
R Version : 2.14.1 x64
Running on Windows 7
Connecting to a database on a remote Microsoft SQL Server 2012
The short form of my problem is the following.
I have an unordered vectors of names, say:
names-c(A, B, A, C,C)
each of which have an id in a table in my db. I need to convert the names
Dear R Help list,
I have data in a comma delimited format with an unequal number of lines
per case, ranging from 1 to 5. Each line contains that individual's rating of
a televised conference they observed. I'm interested in the influence of group
size on ratings.
My questions:
Hi A.K
-
library(XML)
URL -
http://money.securebank.in/index.php?option=com_dashboardview=historyItemid=56startdate=01/01/2013enddate=6/9/2014exchange=MCXsid=1;
doc - htmlParse(URL)
tableNodes - getNodeSet(doc, //table)
dat1 - readHTMLTable(tableNodes[[4]],
Hello, I am trying to install package BayesTree on R 3.0.1 for Windows, but
I am getting a compilation error: compilation failed for package
'BayesTree'.
Here is what I am doing:
I installed Rstudio for windows from binary file.
On Rstudio, I go to Tools-Install Packages.
I select 'Install from
3rd line:
if(!is.na(CA_AMT_PAYBACK ){
^^ ^
Two brackets opened, only one closed. You must close the second one.
HTH
Pascal
On Thu, Jul 3, 2014 at 4:03 PM, Abhinaba Roy abhinabaro...@gmail.com wrote:
Hi,
The 'if' statement closes
Got it..Thanks :)
On Thu, Jul 3, 2014 at 12:44 PM, Pascal Oettli kri...@ymail.com wrote:
3rd line:
if(!is.na(CA_AMT_PAYBACK ){
^^ ^
Two brackets opened, only one closed. You must close the second one.
HTH
Pascal
On Thu, Jul 3, 2014 at 4:03 PM,
Hi
You shall consult
?aggregate
to get summaries for groups.
And you shall also consult R-intro manual to learn some basic facts about
objects structure and manipulation with them.
And finally you shal also have a look into Posting guide how to construct
questions
Regards
Petr
Hi
Hm. Cooperation of R with excel can be probably done by Rexcel package.
Without more detailed information how do you want to use R in connection with
Excel you probably do not get more precise answer.
For summaries use
?aggregate or maybe ?sapply
For counting item occurance
?table, ?xtabs
Hi
What is the problem?
some comments in line
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Brian Willis
Sent: Wednesday, July 02, 2014 1:33 PM
To: r-help@r-project.org
Subject: Re: [R] Dataframes and text identifier
Hi
Why are you doing duplicate queries to the database (two As and Cs in your
names vector)?
Why do 5 simultaneously connection to the database server? Woukld you do 500
connections?
Why not do one query and let the database server do the job for you?
Try this:
options(useFancyQuotes =
Your question is vague. You say you have code that does what you want it to,
yet do not share an example of it as a starting point, or explain what you have
not been able to do. It is the nature of the Internet that you have to be
precise in describing your problems and desired solutions.
When
I want to compare two tables, but the format on the time stamps are
different. Both had the same format in Excel, but when I read those into R,
the times have changed in the following way:
00:00 = 0:00, that is, the smallest dataset has the original time stamp, the
largest has a new format. The
Warning in install.packages :
package âdplyrâ is not available (for R version 2.15.3)
Is there any alternate way to sorting data.frame datewise in a
descending order?.(not using dplyr)
On Thu, Jul 3, 2014 at 12:48 PM, Velappan Periasamy veepsi...@gmail.com
wrote:
Hi A.K
I modified
Hi A.K
I modified and got the results
thanks A.K
library(XML)
URL -
http://money.securebank.in/index.php?option=com_dashboardview=historyItemid=56startdate=01/01/2014enddate=02/07/2014exchange=MCXsid=1
doc - htmlParse(URL)
tableNodes - getNodeSet(doc, //table)
l=length(tableNodes)
dat1 -
Hi
Are you sure that In Excel your times have same formating? There can be many
sources of quirks from Excel itself through automatic csv conversion performed
by Pearl to reading this csv to R. I presume that the timestamp is not actually
in POSIX format (check with str) so if it is consistent
On Wed, 2 Jul 2014 09:33:12 PM Barry Lambert wrote:
I am a new convert to R (from SAS). I am a research scientist and
most of
my
use of SAS was in data analysis. Recently, I have been wanting to
use R to
create a simple, reliable way to summarize a dataset of student
demographics
for a
On 02/07/2014, 10:33 PM, Barry Lambert wrote:
I am a new convert to R (from SAS). I am a research scientist and most of
my
use of SAS was in data analysis. Recently, I have been wanting to use R to
create a simple, reliable way to summarize a dataset of student demographics
for a
Hi
If you have problems with dates in Excel copy and paste the date column into
a text editor and see if there are any peculiarities.
Remember what is shown on the screen may be totally different from what is
stored.
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Jim Lemon
Sent: Thursday, July 03, 2014 12:17 PM
To: r-help@r-project.org
Cc: Barry Lambert
Subject: Re: [R] Help with tables in R
snip
Hi Barry,
If I understand the
Thanks for the suggestions Jeff. I have added some text below that will
hopefully clarify my question and more closely follow the guidelines.
Barry
--
Sorry for the confusing first post. I have edited for clarity and included
some sample data.
Clarified summary of problem: I have an excel
Hi Mark
Thank you for the response. The problem is biologically I can’t really avoid
using the irregular time step (daily samples taken at irregular intervals)
I guess generally I’m not really doing time series analysis (my model is a
multiple regression), I just wanted to use time series
At the expense of extra bandwidth
Remember Excel is a workbook or worksheet not a database
caveat emptor or such ilk
Duncan
From: Marte Hansen [mailto:hansen_ma...@hotmail.com]
Sent: Thursday, 3 July 2014 22:06
To: Duncan Mackay; R
Subject: RE: [R] Comparing two times with different
At 08:04 03/07/2014, Javier wrote:
Hello, I am trying to install package BayesTree on R 3.0.1 for Windows, but
I am getting a compilation error: compilation failed for package
'BayesTree'.
Here is what I am doing:
I installed Rstudio for windows from binary file.
On Rstudio, I go to
Hi
Maybe you can find something in Hmisc package from Frank Harrel. Especially
summary.formula first example is probably close to what you want.
And also this seems to be quite convenient.
http://cran.r-project.org/web/packages/stargazer/vignettes/stargazer.pdf
Regards
Petr
-Original
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] Im
Auftrag von Katharina Mersmann
Gesendet: Dienstag, 1. Juli 2014 16:22
An: r-help@r-project.org
Betreff: [R] (PLM- package) Residual-Plotting and missing Values
Dear R-Community,
I tried
Hello all,
I have a problem with the connection to a Postgresql database in R.
At first, some system information:
Fedora 2.0,
R 3.1.0 compiled from source,
Postgresql 9.2
I installed the RPostgreSQL package in R with all the dependencies
also.
When I'm trying to connect to the database
Dear R users,
I have a question regarding accounting for spatioautocorrelation in the
residuals of gls models. I would like the error term of my GLS model (in
the nlme package) to account/control for spatialautocorrelation among my
sample units. So I use a model that looks something along the
Hi
I tried plm and it seems that na.exclude does not work. Try to connect
maintainer directly.
maintainer(plm)
[1] Yves Croissant yves.croiss...@univ-reunion.fr
The only workaround I can think about is to give NAs to proper places in
residual vector. In your example it is simple
Generating tables from your sample data like the ones you attached is simple
using the ftable() function:
(CCxT - ftable(College+Campus~Term, mydata))
College COBA COE COLFA
Campus M O S M O S M O S
Term
Fall 2010
I need to analyze multiple T1 contrast enhanced MRI studies from different
patients. They are all in DICOM format. I see that there are different
packages for loading individual studies in DICOM format, however I have had
limited luck so far researching how the different studies can be tranformed
There is a very good example system in
http://censix.com/download/
-Original Message-
From: jeeth ghambole [jeethghamb...@gmail.com]
Date: 07/01/2014 10:59 AM
To: r-help@r-project.org
Subject: [R] Order Book details in R Interactive Brokers Package
Hello All,
I am working on project
Thank you for the suggestion
What seems to work is assigning out_put$Case - Inp_dat$Case
that is
for(i in 1:4)
{
...
Case- Inp_dat$Case[i]
…
out_put[i,]-data.frame(Case, stdL, stdPP, stdSE, L, PP, PP_SE)
}
out_put$Case - Inp_dat$Case
out_put
What I don't understand is
On Thu, 2014-07-03 at 11:09 -0500, John McKown wrote:
On Thu, Jul 3, 2014 at 9:49 AM, Tomas Lanczos lanc...@fns.uniba.sk wrote:
Hello all,
I have a problem with the connection to a Postgresql database in R.
At first, some system information:
Fedora 2.0,
R 3.1.0 compiled from
What I'm trying to do should be simple enough, but I've been having some
trouble - hence this post.
I am attempting to output a tsv file directly from R but for some reason the
write.table function is outputting the vector number for each set of values
and thus offsetting all of my tab
Hi,
I'm new to using R and would like to use Vennerable to process my data and
make Venn diagrams. However I cannot seem to install the package. If I enter
the command
install.packages(Vennerable, repos=http://R-Forge.R-project.org;)
I get the following message:
package ‘Vennerable’ is available
Fine bug that Excel provides. I had hoped that it would not require editing in
Excel, but... It works now! Thank you so much!
From: dulca...@bigpond.com
To: r-help@r-project.org; hansen_ma...@hotmail.com
Subject: RE: [R] Comparing two times with different format
Date: Thu, 3 Jul 2014
Thank you Jim for your answer.Ok alpha( it is the speed of the boat) is a
range of number from 0.5 to 10 like 0.5,1,1.5,2, I would like to have
the mean of x and y base on each value of alpha, because I have like ten
numbers of x for each value of speed, thats why I want the mean of that and
Setting row.names = FALSE?
Br. Frede
Sendt fra Samsung mobil
Oprindelig meddelelse
Fra: dstrick1
Dato:03/07/2014 19.02 (GMT+01:00)
Til: r-help@r-project.org
Emne: [R] How to hide the vector number output in write.table function?
What I'm trying to do should be simple
Dear R-Community,
I need to change the punctuation of the reported weights, effect sizes
and confidence intervals in a forest plot created with the
forest()-function in the metafor-package.
Midline decimal means that it looks like this (23·6) rather than that
(23.6).
Do I need to change
Hi,
Try:
res1 - aggregate(PROFIT~DATE, data=dat, FUN=sum)
res1[rev(order(as.Date(res1$DATE, format=%d/%m/%Y))),]
# DATE PROFIT
#2 02/07/2014 -1350
#1 01/07/2014 9400
#4 30/06/2014 11325
#3 27/06/2014 6850
#if you don't wanted another column in the original dataset with `sum`
res2
Can't believe I missed that. Thank you!
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-hide-the-vector-number-output-in-write-table-function-tp4693469p4693478.html
Sent from the R help mailing list archive at Nabble.com.
__
Important note for package binaries: R-Forge provides these binaries only
for the *most recent version of R*, but not for older versions. In order to
successfully install the packages provided on R-Forge, you have to switch
to the most recent version of R or, alternatively, install from the
Hi all,
A bit stumped here.
z - seq(.05,.85,by=.1)
z==.05 #good
[1] TRUE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE
z==.15 #huh
[1] FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE
More generally:
sum(z==.25)
[1] 1
sum(z==.35)
[1] 0
sum(z==.45)
[1] 1
sum(z==.55)
[1] 1
On Jul 3, 2014, at 1:28 PM, Matthew Keller mckellerc...@gmail.com wrote:
Hi all,
A bit stumped here.
z - seq(.05,.85,by=.1)
z==.05 #good
[1] TRUE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE
z==.15 #huh
[1] FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE FALSE
More
FAQ 7.31
Sent from my Verizon Wireless 4G LTE Smartphone
div Original message /divdivFrom: Matthew Keller
mckellerc...@gmail.com /divdivDate:07/03/2014 11:28 (GMT-08:00)
/divdivTo: r help r-help@r-project.org /divdivSubject: [R] odd
behavior of seq() /divdiv
/divHi all,
A
Precision, precision, precision...
z[2]-0.15
[1] 2.775558e-17
My solution:
z - signif(seq(.05,.85,by=.1), 5)
z[2] - 0.15
[1] 0
z[2]==0.15
[1] TRUE
Peter
On Thu, Jul 3, 2014 at 11:28 AM, Matthew Keller mckellerc...@gmail.com wrote:
Hi all,
A bit stumped here.
z - seq(.05,.85,by=.1)
thanks all!
On Thu, Jul 3, 2014 at 12:38 PM, Peter Langfelder
peter.langfel...@gmail.com wrote:
Precision, precision, precision...
z[2]-0.15
[1] 2.775558e-17
My solution:
z - signif(seq(.05,.85,by=.1), 5)
z[2] - 0.15
[1] 0
z[2]==0.15
[1] TRUE
Peter
On Thu, Jul 3, 2014 at
I get inconsistent results from [.data.frame. I've so far been
unable to create a simple, replicable example nor a workaround. With
debug, I traced the problem to rows - rows[i], line 131 in
[.data.frame: In this example, rows = 1:45, and rows[1:3] = 1:3, as
we expect. However with
I see that others have answered the question much better than I could.
However assumng you are getting the data in the layout you want you may also
want to look at the xtable package in R as a very handy alternative to
stargazer if you want to produce some good-loking tables in some flavour of
On 03/07/2014 2:55 PM, Spencer Graves wrote:
I get inconsistent results from [.data.frame. I've so far been
unable to create a simple, replicable example nor a workaround. With
debug, I traced the problem to rows - rows[i], line 131 in
[.data.frame: In this example, rows = 1:45, and
Hi,
Is there any way to access an element of a list without looping over the list
nor using unlist? Just to avoid parsing a very long list.
For ex, how to find a vector of a length 2 in a list without using a loop?
l = list (c(1), c(2,3), c(1,2,3))
for (i in 1:length(l))
Hi, Duncan:
On 7/3/2014 12:25 PM, Duncan Murdoch wrote:
On 03/07/2014 2:55 PM, Spencer Graves wrote:
I get inconsistent results from [.data.frame. I've so far
been
unable to create a simple, replicable example nor a workaround. With
debug, I traced the problem to rows - rows[i],
You could use
which( sapply(l, length) == 2 )
but that still uses a loop internally.
On Thu, Jul 3, 2014 at 1:35 PM, carol white wht_...@yahoo.com wrote:
Hi,
Is there any way to access an element of a list without looping over the list
nor using unlist? Just to avoid parsing a very long
I have a matrix 'dd' defined as below:
dd - t(matrix(c(153.0216306, 1, 7.578366e-35,
13.3696538, 1, 5.114571e-04,
0.8476713, 1, 7.144239e-01,
1.2196050, 1, 5.388764e-01,
2.6349405, 1, 2.090719e-01,
6.0507714, 1, 2.780045e-02), nrow=3, ncol=6))
dimnames(dd)[[2]] - c('# Chisq', 'DF',
On Jul 3, 2014, at 2:35 PM, carol white wht_...@yahoo.com wrote:
Hi,
Is there any way to access an element of a list without looping over the list
nor using unlist? Just to avoid parsing a very long list.
For ex, how to find a vector of a length 2 in a list without using a loop?
l =
Not elegant, but it works:
term - dimnames(dd)[[1]]
dd1 - dd
dimnames(dd1)[[1]] - rep(, 6)
dd2 - capture.output(dd1)
cat(paste(dd2,, c(Term, term)), fill=48)
# Chisq DF Pr(Chisq) Term
153.0216306 1 7.578366e-35 # Sex
13.3696538 1 5.114571e-04 # Volume
R base function glm() uses Fishers Scoring for MLE, while the glmnet uses the
coordinate descent method to solve the same equation ? Coordinate descent is
more time efficient than Fisher Scoring as fisher scoring calculates the
second order derivative matrix and some other matrix operation which
Hello all,
I think this should be a relatively easy solution involving par but I can't
figure it out, involving subplot:
I'm making a three-figure plot, each with a subplot. Here's simple
reproducible code below. But each plot seems to call the original par
setting and
I am trying to optimize code for speed and readability for a fairly complex
function inside an MCMC sampler. As of now I have a bunch of variables inside a
function that get iteratively reset inside a loop. Something like this:
set.seed(1)
K - 10
v1 - rnorm(K)
v2 - rnorm(K)
v3 - rnorm(K)
steps
Paul, I happen to be working on the exact same problem. If you found a
solution somewhere, please let me know. I will do the same if I stumble onto
a solution first.
Rich - cost information can be collected prospectively but be censored due
to incomplete follow-up or some other similar reason.
On Jul 3, 2014, at 4:40 AM, gktahon wrote:
Hi,
I'm new to using R and would like to use Vennerable to process my data and
make Venn diagrams. However I cannot seem to install the package. If I enter
the command
install.packages(Vennerable, repos=http://R-Forge.R-project.org;)
I get the
On Jul 3, 2014, at 12:45 PM, Cory Champagne wrote:
Hello all,
I think this should be a relatively easy solution involving par but I can't
figure it out, involving subplot:
I'm making a three-figure plot, each with a subplot. Here's simple
reproducible code below. But each
Hi,
May be this helps:
nC - max(nchar(row.names(dd)))
term - formatC(row.names(dd), width=-nC)
#or
term - sprintf(%-11s, row.names(dd))
dd1 - setNames(data.frame(unname(dd), term,stringsAsFactors=F),
c(colnames(dd), formatC(term,width=-nC)))
dd1
# # Chisq DF Pr(Chisq) term
#1
Hola Eric,
Me incliniaria mas por un problema de enconding. Intenta agregando
enconding = 'latin1' al final de read.csv()
A lo mejor enviandonos tu sessionInfo() podriamos ayudarte un poco mas.
Saludos,
Jorge.-
2014-07-03 5:32 GMT+10:00 neo ericconchamu...@gmail.com:
Estimada comunidad,
Hola Javier, los archivos los genero yo mismo, asi es que en principio
al menos, no hay demasiadas cosas raras, son solo simples calculos de
planilla electronica.
Gracias por sus sugerencias. Las probare.
Eric.
On 02/07/14 16:08, Marcuzzi, Javier Rubén wrote:
Estimado Eric
Una forma que
Tengo una consulta, alguien tiene algun script en R para hacer graficos de
anomalias estandarizadas (precipitacion, temperatura, etc) y que me permita
pintar de rojo anomalias positivas y azules las negativas,
âMuchas gracias de antemanoâ
--
Luis Alfonso LOPEZ ALVAREZ
MSc- Meteorologia -
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