On Sat, Mar 11, 2017 at 2:11 PM, Mohammad Tanvir Ahamed via R-help
wrote:
> Thanks for reply.
> as I said , the function in the package is like
> myplot <- function(x,y) { plot(x,y) }
>
> not like
> myplot <- function(x,y) { plot(x,y,...) }
>
> And I cant change the function
You can't. You can skip the package and roll your own functions if the package
functions are not written to use ...
--
Sent from my phone. Please excuse my brevity.
On March 11, 2017 2:11:39 PM PST, Mohammad Tanvir Ahamed via R-help
wrote:
>Thanks for reply.
>as I said
On 12/03/17 11:11, Mohammad Tanvir Ahamed wrote:
Thanks for reply.
as I said , the function in the package is like
myplot <- function(x,y) { plot(x,y) }
not like
myplot <- function(x,y) { plot(x,y,...) }
And I cant change the function inside the package!!
So , in this case how to solve the
You will get this error if 'df' does not have columns named "X" and
"Y", so df$X or df$Y is NULL. E.g.,
> df <- data.frame(One=1:3, Two=11:13)
> df$Three <- df$One + df$noSuchColumn
Error in `$<-.data.frame`(`*tmp*`, "Three", value = numeric(0)) :
replacement has 0 rows, data has 3
Thanks for reply.
as I said , the function in the package is like
myplot <- function(x,y) { plot(x,y) }
not like
myplot <- function(x,y) { plot(x,y,...) }
And I cant change the function inside the package!!
So , in this case how to solve the problem ?
Tanvir Ahamed
Göteborg, Sweden |
Copy one statement at a time into a new R session. When you get an error you
will know what you need to look at more closely. RStudio makes this easy with
the Start New R Session menu option and using Ctrl-Enter in the editor.
--
Sent from my phone. Please excuse my brevity.
On March 11, 2017
On 12/03/17 10:26, Mohammad Tanvir Ahamed via R-help wrote:
Hi!,
Lets I have a function form a package.
The function is, as an example,
myplot <- function(x,y) { plot(x,y) }
Now I can use the function according to function's defined argument.
x<- sort(runif(200))
y<- 1:200
myplot(x,y)
Now
Dear Mohammad Tanvir Ahamed,
Re:
> Hi!,
>
> Lets I have a function form a package.
> The function is, as an example,
>
> myplot <- function(x,y) { plot(x,y) }
>
>
> Now I can use the function according to function's defined argument.
>
> x<- sort(runif(200))
> y<- 1:200
> myplot(x,y)
Hi!,
Lets I have a function form a package.
The function is, as an example,
myplot <- function(x,y) { plot(x,y) }
Now I can use the function according to function's defined argument.
x<- sort(runif(200))
y<- 1:200
myplot(x,y)
Now I want to input extra argument or override default value
I think this is the problem. How to solve then?
On Sat, Mar 11, 2017 at 12:18 PM, Bert Gunter
wrote:
> Typo, should be:
>
> 3. A guess: You are sourcing the entire script in the editor panel
> into R, and there is something screwed up there.
>
> -- Bert
>
>
> Bert Gunter
Typo, should be:
3. A guess: You are sourcing the entire script in the editor panel
into R, and there is something screwed up there.
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his
Thanks for your reply. I thought anything about R questions can be posted
here.
About your third point, what does it mean? I did the same thing before for
other scripts, but this one does not work. Thanks again.
On Sat, Mar 11, 2017 at 12:12 PM, Bert Gunter
wrote:
> 1.
1. Not reproducible, hence impossible to say.
2. This is r-help. RStudio is totally separate and its own support page.
3. A guess: Use are sourcing the entire script in the editor panel
into R, and there is something screwed up there.
Cheers,
Bert
Bert Gunter
"The trouble with having an open
More specifically, it shows the following when I typed traceback():
3: stop(sprintf(ngettext(N, "replacement has %d row, data has %d",
"replacement has %d rows, data has %d"), N, nrows), domain = NA)
2: `$<-.data.frame`(`*tmp*`, "Z", value = numeric(0))
1: `$<-`(`*tmp*`, "Z", value =
Hi R users,
I have a problem about using R studio. For example, there is a dataframe
that has many columns. I want to aggregated column X and column Y into
column Z. Column Z does not exist before the aggregation. I use the code
below:
df$Z = df$X + df$Y
However, it does not work in the top left
Thank you both, indeed combining two solutions fixed my problem :
> which(sapply(mylist, mycompare,find))
[1] 2
I admit list of lists is not the optimal design, it's out of my control but is
there is not much data in it, so performance is not an issue.
For the sake of R's honour I didn't
Since the offered solution already checks each top level element using the
"identical" function, you just need a different comparison function, like
perhaps:
mycompare <- function( x, y ) {
identical( x[[ "a" ]], y[[ "a" ]] ) && identical( x[[ "b" ]], y[[ "b" ]] )
}
Note that your decision
Given that nls() often gives failures of the "singular gradient" type, you may want to give package nlsr a try with the
nlxb() function. It should be able to use analytic gradients on this expression, has bounds, and uses a Marquardt
stabilized solver. It can still fail, but is more robust than
Have you read the docs? Is this some kind of homework? -- this list
does not do homework. We expect minimal efforts at least on the part
of posters. We do not do tutorials here. I think you need to do some
reading on your own before posting further. Try posting on the
r-sig-mixed-models list to
Dear list,
I want to apply the same nls function to different subsets of a larger
dataset. These subsets are defined as unique combinations of two
(categorical) variables, each one with two levels, so I should obtain 4
sets of parameters after fitting.
I have managed to do it in a loop,
Sorry I rejoiced too soon. In fact original list is more complex like :
mylist <- list(list(a=10,b="x",c=1),list(a=11,b="y",c=2),list(a=12,b="z",c=5))
and I still need to find index of where a = 11 and b = "y" and I have no c
value ,
-Original Message-
From: "ce"
Dear r-help group
I have a text file which is a data dump of a pdf form as given below..
I want it to be converted into a data frame with field name as column names
and the field value as the row value for each field.
I might have different pdf forms with different field name value pairs to
Exactly. Thanks a lot, I was trying sapply with to result.
-Original Message-
From: "Rui Barradas" [ruipbarra...@sapo.pt]
Date: 03/11/2017 10:06 AM
To: "ce" , r-help@r-project.org
Subject: Re: [R] find index in a list of list
Hello,
Something like this?
find <-
Hello,
Something like this?
find <- list(a=11,b="y")
which(sapply(mylist, identical, find))
Hope this helps,
Rui Barradas
Em 11-03-2017 14:59, ce escreveu:
Hi all,
I have a list of lists like this :
mylist <- list(list(a=10,b="x"),list(a=11,b="y"),list(a=12,b="z"))
I want to find the
Hi all,
I have a list of lists like this :
mylist <- list(list(a=10,b="x"),list(a=11,b="y"),list(a=12,b="z"))
I want to find the index of list in mylist where a = 11 and b = "y" , so I
want to get 2 as a result
Thanks in advance
__
Dear R Help:
What does "lmer(responce ~ factor1*factor2 + (factor1*factor2 | group1) +
(factor1*factor2| group2), data)" mean?
And
"lmer(responce ~ factor1*factor2 + (factor1*factor2 | group1) +
(factor1*factor2| group2), data)" vs. "lmer(responce ~ factor1*factor2 +
(factor1+factor2 | group1)
Also, the OP's FUN1 is NOT a function. It's the result of a function
call. A function would be
FUN1 <- function(x) EM_mixture_copula(...)
Hope this helps,
Rui Barradas
Em 11-03-2017 10:29, Michael Hannon escreveu:
I think Bert's advice is sound. Let me add a few, miscellaneous comments:
I think Bert's advice is sound. Let me add a few, miscellaneous comments:
(1) Some people find "by" easier than "tapply".
(2) The "apply" function can, as I'm sure you (Bert) know, iterate
over a matrix.
(3) Hadley probably has better ways to do all of this (it's hard to keep up).
-- Mike
On
You need to set the aesthetic 'group' to something meaningful, probably ID
in this case.
HTH
Ulrik
On Fri, 10 Mar 2017, 19:30 Rayt Chiruka, wrote:
> i am trying to convert a dataset from wide to long format using package
> tidyr- (seems to have been done)
>
> wen in try
I don't know if there's a pure R option, but i believe pdftk can extract
the form data which you can then manipulate in R.
Best
Ulrik
On Sat, 11 Mar 2017, 05:14 Vijayan Padmanabhan, <
padmanabhan.vija...@gmail.com> wrote:
> Dear R-Help group
> Is there any way that I can programmatically
Also, this is from a package. Which? (AFAIR, there are at least two
possibilities). What is is the docs? Does it even allow an append= argument?
-pd
> On 10 Mar 2017, at 14:49 , Michael Dewey wrote:
>
> Dear Paul
>
> Have you defined a variable T or F somewhere?
>
Thank you David for your answer.
If I understood the relative positions of variable arrows don't reflect the
coefficient of correlation of the original variables. In fact these
positions change if I use different PC axes.
But in some manual about PCA in R I read: "Pairs of variables that form
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