Re: [R] [FORGED] p-value=0 running log-rank test

This is not an R question. Your question indicates that you really need to learn some statistics. To answer the very last part: > pchisq(430,3,lower=FALSE) [1] 7.020486e-93 And if that is not 0 to all intents and purposes, then God help us all. cheers, Rolf Turner On 19/05/17 12:48, Anne

[R] p-value=0 running log-rank test

Dear all, I have a question concerning the p-value. When running log-rank test I get a p-value = 0. What is it mean? Can this be true? Why aren´t there decimal points? Is there a way to find out the exact p-value? Here is the output: > survdiff(Surv(tempo2,status)~tphist, data=base,rho=0) Call:

Re: [R] Question about change the length of a string.

Hi Jeff, Thank you a lot! Best, Yen -Original Message- From: Jeff Newmiller [mailto:jdnew...@dcn.davis.ca.us] Sent: Thursday, May 18, 2017 11:11 PM To: r-help@r-project.org; Yen Lee Subject: Re: [R] Question about change the length of a string.

Re: [R] Question about change the length of a string.

http://stackoverflow.com/questions/2261079/how-to-trim-leading-and-trailing-whitespace-in-r -- Sent from my phone. Please excuse my brevity. On May 18, 2017 8:57:51 PM PDT, Yen Lee wrote: >Hello everyone, > > > >I have a question and I need your precious kind help. > >

[R] Question about change the length of a string.

Hello everyone, I have a question and I need your precious kind help. I am working on matching two string. However, the length of the two strings is different. For example, one is "example" (nchar=7), the other one is "example " (nchar=10). The R considers them as different strings but

[R-es] me parece interesante

Estimados Hay un sitio con recursos en varios lenguajes, entre estos R, puede ser bueno como fuente de recursos y hay unos datos que me parecieron interesantes de R (muy resumido como curiosidad). https://libraries.io/languages/R Javier Rubén Marcuzzi [[alternative HTML version

Re: [R] RCommander issue

Hi Thambu, Try downloading the package from CRAN. For example, I just tried this with the rgdal package as I need to use it. The package (rgdal_1.2-7.zip) is saved on the local hard disk. Then find out where your R executable is. For me it is: E:\jim\R\R-3.3.3\bin\x64\R.exe Now open a "Command

[R] S4 Question; show generic method

Hello, I changed the name of a function, and updated my R packages with update.packages(ask=FALSE), and I have had a curious (to me) change in show method. I am developing a package, and a generic show method I defined for my S4 class is not autocalled when I type the object name - object_name;

Re: [R] Extracting metadata information to corresponding dissimilarity matrix

Brilliant, David, thank you so much! Cheers, Rune > 16. mai 2017 kl. 18.44 skrev David L Carlson : > > Fixing a typo in the original, adding a simplification, and using > dissimilarity instead of similarity: > > set.seed(42) > dta <- data.frame(ID=1:7,

Re: [R] Randomly select one row by group from a matrix

You can modify your original code to get what you want: do.call(rbind, lapply(split(data.frame(test), test[,c("id")]), function(x) as.matrix(x[sample(nrow(x), 1), ]))) # xcor ycor id # 146 1 # 242 2 But Bert's way is simpler: indx <- tapply(seq_along(test[, "id"]), test[,

Re: [R-es] PLOTEO DEL DATO MENSUAL DESDE EL ACUMULADO

Hola, En ese caso, lo que tienes que usar en la función "lag()", que está en el paquete base, aunque trate sobre series temporales. O puedes utilizar funciones equivalentes en los varios paquetes que tratan series temporales (forecast, xts...). Gracias, Carlos Ortega www.qualityexcellence.es El

Re: [R-es] Crear GUIDES con R

Si, busca/mira "Shiny"... Saludos, Carlos Ortega WWE.qualityexcellence.es El El jue, may. 18, 2017 a las 6:55 PM, WILMER CONTRERAS SEPULVEDA < wilme...@ufps.edu.co> escribió: > Hola Buenos días. Quisiera saber si existe un paquete en R para crear un > GUIDE como se hace facilmente en Matlab.

Re: [R] Randomly select one row by group from a matrix

If I understand corrrectly, this is easily accomplished in base R via ?tapply and indexing. e.g. set.seed(1234) ## for reproducibility grp <- sample.int(5,size = 30,rep = TRUE) ## a grouping vector ## Could be just a column of your matrix or frame indx <- tapply(seq_along(grp),grp, sample,size

Re: [R-es] PLOTEO DEL DATO MENSUAL DESDE EL ACUMULADO

Estimado Javier Valdes Cantallopts Entonces sus datos son distintos, es una fecha mensual y a esa fecha tiene asociada la cantidad de precipitaciones mensuales correspondientes a ese mes más la suma de los meses anteriores, por lo cual en diciembre tiene el acumulado anual, que en sus datos

[R-es] Crear GUIDES con R

Hola Buenos días. Quisiera saber si existe un paquete en R para crear un GUIDE como se hace facilmente en Matlab. Muchas gracias. Wilmer Contreras S. [[alternative HTML version deleted]] ___ R-help-es mailing list R-help-es@r-project.org

Re: [R-es] PLOTEO DEL DATO MENSUAL DESDE EL ACUMULADO

Interesante. Cada uno de los valores de mi tabla tiene asociada una fecha. Se le podría asignar un tipo de “break” ,para que le “diff” sea asociado a cada mes? Por ejemplo? [Descripción: FIRMA3] De: Carlos Ortega [mailto:c...@qualityexcellence.es] Enviado el: jueves, 18 de mayo de 2017 12:35

Re: [R-es] PLOTEO DEL DATO MENSUAL DESDE EL ACUMULADO

Hola, Hay una función en "R" que permite hacer ese cálculo "diff()". #- > DF <- read.table(textConnection(val_cum), as.is = TRUE) > DF V1 11 25 38 4 10 5 20 6 30 7 50 8 80 9 120 10 125 11 200 12 250 > diff(DF$V1, 1) [1] 4 3 2 10 10 20 30 40 5

Re: [R] Randomly select one row by group from a matrix

Hi Marine, your manipulation of the matrix is quite convoluted, and it helps to expand a bit: test_lst <- split(test, test[,c("id")]) test_lst$`1` after splitting, your matrix has gone back to be a plain vector, which makes the sampling fail. The reason is that, a matrix - behind the scenes -

Re: [R-es] PLOTEO DEL DATO MENSUAL DESDE EL ACUMULADO

Hola Solo extraer los montos correspondientes a cada mes. Solo tengo la serie acumulada anual. [Descripción: FIRMA3] De: Javier Marcuzzi [mailto:javier.ruben.marcu...@gmail.com] Enviado el: jueves, 18 de mayo de 2017 11:14 Para: Javier Valdes Cantallopts (DGA); Carlos Ortega

[R] Randomly select one row by group from a matrix

Hello, I would like to randomly select one row by group from a matrix. Here is an example where there is one row by group. The code gives an error message: test <- matrix(c(4,4, 6,2, 1,2), nrow = 2, ncol = 3, dimnames = list(NULL, c("xcor", "ycor", "id"))) do.call(rbind, lapply(split(test,

Re: [R-es] PLOTEO DEL DATO MENSUAL DESDE EL ACUMULADO

Estimado Javier Valdes Cantallopts Hay algo que no comprendo, usted dice que desea extraer los datos mensuales desde el acumulado. ¿Sería algo como, el año 2000 llovió 2300 ml? A partir de esto conocer las precipitaciones en enero, febrero, etc. Ahora tengo mis dudas, si usted tiene los datos

[R-es] PLOTEO DEL DATO MENSUAL DESDE EL ACUMULADO

Hola estimados: He tratado de encontrar la mejor forma de automatizar un proceso de "datos mensuales de precipitación". El tema es que tengo solo la serie acumulada anual de Pp. Por ende, busco una forma de plotear un gráfico, extrayendo "los datos mensuales desde el acumulado" Ejemplo; ene feb

Re: [R] violin plot help

> On 16 May 2017, at 17:06, Abdelrahman, Omar (RER) > wrote: > > I am trying to produce multiple violin plots by 3 categorical variables, each > violin representing 1 year worth of data. The variables are: > > Watershed (7 levels: county canals) > > Geography

Re: [R] violin plot help

Many thanks Jeff! I knew it would require a loop approach, so I will now explore that with the code you suggested. -Original Message- From: Jeff Newmiller [mailto:jdnew...@dcn.davis.ca.us] Sent: Wednesday, May 17, 2017 5:19 PM To: Abdelrahman, Omar (RER)

Re: [R] Help on reducing multiple loops

Data? It's difficult to do anything without some test data.See How to make a great R reproducible example? or http://adv-r.had.co.nz/Reproducibility.html  with particular reference to the use of dput() as the best way to provide sample data. | | | | || | | | | |

Re: [R] converting each column of a data frame into a matrix with n rows

Thanks David! It worked! On 17 May 2017 at 23:39, David Winsemius wrote: > >> On May 17, 2017, at 1:01 PM, Davide Piffer wrote: >> >> Thanks! This gets closer to the solution but a small problem remains. >> I get 2 rows and only one column,

[R-es] 9 Jornadas R Granada. C4P

Hola. Os paso información sobre las próximas jornadas de usuarios de R en Granada. La Asociación R-Hispano tiene el placer de anunciar la celebración de las IX Jornadas de Usuarios de R. En esta ocasión, será la Universidad de Granada , en la ETS de Ingenierías Informática y de Telecomunicación