Thank you both for your advice! The z <- readLines(gzcon(url("
https://tcga.xenahubs.net/download/TCGA.GBMLGG.sampleMap/HumanMethylation450.gz;)),
) command worked out nicely
On Thu, Aug 1, 2019 at 6:47 PM William Dunlap wrote:
> By the way, instead of saying only that there were warnings, it
By the way, instead of saying only that there were warnings, it would be
nice to show some of them. E.g.,
> z <- readLines("
https://tcga.xenahubs.net/download/TCGA.GBMLGG.sampleMap/HumanMethylation450.gz
")
[ Hit control-C or Esc to interrupt, or wait a long time ]
There were 50 or more warnings
These are gzipped files, I assume. So see ?gzfile and associated info
for how to open a gzip connection and read from it. You may also
prefer to search (e.g. at rseek.org) on "read a gzipped file" or
similar for possible alternatives.
Of course, if they're not gzipped files, then ignore the
Good evening,
I am attempting to load the following Xena dataset
https://tcga.xenahubs.net/download/TCGA.GBMLGG.sampleMap/HumanMethylation450.gz
I am trying to unpack the dataset and read it into R as a table, but due to
the size of the file, I am having some trouble. The following are the
Does fa function in psych package consider only complete cases when
missing=FALSE?
Why do I get slightly different results when I restrict my data to complete
cases compared to the whole data with the default missing=FALSE?
--
Sent from: http://r.789695.n4.nabble.com/R-help-f789696.html
I need to run 3.6 on debian stretch - I followed the instructions here:
https://cran.r-project.org/bin/linux/debian/
and I was able to install it. But 2 packages I need, r-cran-caret and
r-cran-ggplot2 will not install:
# apt-get install r-cran-ggplot2
Reading package lists... Done
Building
Dear Larry,
yes, because of various factors the r-cran-* packages from the stable and
especially the oldstable distribution are often not compatible with the
backported r-base packages provided on CRAN. At current, buster is not
affected, but your case shows that using stretch gives this
Hello,
On Thu, Aug 01, 2019 at 11:17:30PM +1200, Richard O'Keefe wrote:
2(N-1)/N = 2 - 2/N.
So one way to get exactly that mean is to make all the numbers
2 except for two of them which are 1.
N < 2 : can't be done.
N = 2 : only [1,1] does the job.
N = 3 : the sum of the three numbers must be
I don't know why I thought you wanted a *random* sequence..
The 'rep' function can do more than you realise.
generate_k <- function (N, n3) rep(1:3, c(n3+2, N-2-n3*2, n3))
On Thu, 1 Aug 2019 at 22:48, Lorenzo Isella
wrote:
> Yes, you are right (and yours is one of the possible cases).
> I
2(N-1)/N = 2 - 2/N.
So one way to get exactly that mean is to make all the numbers
2 except for two of them which are 1.
N < 2 : can't be done.
N = 2 : only [1,1] does the job.
N = 3 : the sum of the three numbers must be 4, so none of them
can be 3, so [1,1,2] [1,2,1] [2,1,1] are the
Yes, you are right (and yours is one of the possible cases).
I think this works (I resorted to pen and paper for once)
generate_k <- function(N, n3){
n1 <- 2+n3
n2 <- N-n1-n3
out <- c(rep(1, n1), rep(2, n2), rep(3, n3))
return(out)
}
where N is the length of the sample, n3 is
n_1 + ... + n_N = 2(N-1) is requested for integers n_i >= 1.
What about c(rep(2, N-2), 1, 1))?
but I'm afraid that this was not what you really wanted. ;-)
However, you didn't say if your sample should be random. :-)
Best regards -- Gerrit
Dear All,
I cannot unfortunately provide any R code, otherwise I would not need to post
this in the first place.
I need to generate a sample of N positive non-zero integers such that their
mean is *exactly* 2(N-1)/N, i.e. the mean depends on the length of the sample.
For a start, we can assume
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