Hello,
The following will probably not solve the problem but I would
1. use pattern = "\\.wma$" in list.files;
2. use sub, not gsub, in
sub("\\.wma$", ".mp3", i)
Hope this helps,
Rui Barradas
Às 05:29 de 20/04/21, Jim Lemon escreveu:
Hi John,
If the program is still running, I can only
Hi John,
If the program is still running, I can only guess that the function is
not exiting properly. If this happened to me, I would run "top" in a
terminal window and see if that process number was actually doing
anything or had gone zombie.
Jim
On Tue, Apr 20, 2021 at 11:28 AM John wrote:
>
Just some thoughts I am considering about the issue of how to make giant
objects in memory without making them giant or all in memory.
As stupid as this sounds, when things get really big, it can mean not only
processing your data in smaller amounts but using other techniques than asking
Hi,
I tried to convert all wma file to mp3 by av library and then I delete
the wma file. Even after all files are converted to mp3, the program is
still running. Is there anything wrong in this program?
library(av)
all_files <- list.files(path = ".", pattern = '*.wma',
On Mon, 19 Apr 2021 17:01:11 -0500
Ana Marija wrote:
> Hello,
>
> I have this code, and when I run it:
> > kbpowerf()
> Error in n * rvec : non-numeric argument to binary operator
>
> this is the code:
>
> function (){
> #USER SPECIFICATION PORTION
> alpha=0.05 #DESIGNATED ALPHA
> g=3
Hello,
I have this code, and when I run it:
> kbpowerf()
Error in n * rvec : non-numeric argument to binary operator
this is the code:
function (){
#USER SPECIFICATION PORTION
alpha=0.05 #DESIGNATED ALPHA
g=3 #NUMBER OF GROUPS
nvec=c(25,10,15) #GROUP SIZES
Hello,
If you want to process the data by rows, then maybe you should consider
a custom function that divides the problem in small chunks and process
one chunk at a time.
But even so, at 8 bytes per double, 100^10 rows is
(100^10*8)/(1024^4) # Tera bytes
#[1] 727595761
It will take you a
Hi
Actually expand.grid produces data frame and not vector. And dimension of
the data frame is "big"
> dim(A)
[1] 1 4
> str(A)
'data.frame': 1 obs. of 4 variables:
$ Var1: num 0.001 0.002 0.003 0.004 0.005 0.006 0.007 0.008 0.009 0.01 ...
$ Var2: num 1e-04 1e-04
Dear All,
I would like to know that is there any problem in *expand.grid* function or
it is a limitation of this function.
I am trying to create a combination of elements using expand.grid function.
A <- expand.grid(
c(seq(0.001, 0.1, length.out = 100)),
c(seq(0.0001, 0.001, length.out = 100)),
> Deepayan Sarkar
> on Mon, 19 Apr 2021 09:56:58 +0530 writes:
> On Sat, Apr 17, 2021 at 9:08 PM Martin Maechler
> wrote:
>>
>> > Deepayan Sarkar > on Fri, 16 Apr 2021 11:34:20
>> +0530 writes:
>>
>> > I get what I initially thought was
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