Hi all:
I have two curve models:
model1-nls(result ~ exp(b0 + b1*(time)), start = list(b0 = 0, b1 =
5),trace=TRUE,data=data1)
model2-nls(result ~ exp(b0 + b1*(time)), start = list(b0 = 0, b1 =
5),trace=TRUE,data=data2)
I wanna compare the two models to find out whether the difference
v1-c(a,b,c,d)
v2-c(a,b,e)
v3-c(a,f,g)
I want to get the intersection of v1,v2,v3,ie a
How can I do then?
What I know is only for 2 vectors via intersect function,but don't know how
to deal with multiple vectors.
Many thanks
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Many thanks for your elaborated explaina.
At 2012-01-13 11:34:51,R. Michael Weylandt michael.weyla...@gmail.com wrote:
As Jorge noted, the fix is to use %in%: a fuller explanation of why
`==` didn't work is that it implicitly used vector recycling: look at
with(data, id == c(a, c))
Thanks£¡
ÔÚ 2012-01-13 10:51:14£¬Jorge I Velez jorgeivanve...@gmail.com дµÀ£º
Hi,
Use %in% instead of ==.
HTH,
Jorge.-
On Thu, Jan 12, 2012 at 9:36 PM, ÃÏÐÀ wrote:
Hi all
I have a question about subset function.
dat
id x1 x2 x3
1 a 1 11 111
2 b 2 22 222
3 c 3 33 333
4 d
Hi all
I have a question about subset function.
dat
id x1 x2 x3
1 a 1 11 111
2 b 2 22 222
3 c 3 33 333
4 d 4 44 444
subset(dat,id==c(a,c))
id x1 x2 x3
1 a 1 11 111
subset(dat,id==c(a,d))
id x1 x2 x3
1 a 1 11 111
4 d 4 44 444
From the above, if I choose id=a,c, the
Thanks
At 2012-01-11 16:55:32,Jeff Newmiller jdnew...@dcn.davis.ca.us wrote:
You cannot install 64-bit R on 32-bit OS, but you can install a 32-bit R on a
64-bit OS, and you can later install 64-bit R as well. That is, installing
32-bit R does not interfere with your option to later install
Hi all:
My OS is 32bit winxp,but I wanna install 64bit R2.14.1.
From the following website,it says You can also go back and add 64-bit
components to a 32-bit install, or vice versa
Yes£¬I find out later.
rev is only reverse the order.
What I use is !
Thanks
At 2012-01-06 16:07:11,Petr PIKAL petr.pi...@precheza.cz wrote:
Hi
[R] question about rev
Hi,all:
I have a vector,and wanna get the opposite value via rev function.
a
[1] FALSE FALSE TRUE TRUE
Hi,all:
I have a vector,and wanna get the opposite value via rev function.
a
[1] FALSE FALSE TRUE TRUE TRUE
rev(a)
[1] TRUE TRUE TRUE FALSE FALSE
I don't know why the 3rd TRUE has not been reversed,while all other values
are reversed?
Thanks
My best
[[alternative
Sorry for some typo last mail.
I corrected it,and resent.Sorry for it.
Sir:
I find out that for 2 level factor, if I set it to factor, then I'll get
error reply.
For the instance last mail, if I use:
result1-glm(y ~ factor(gender),family = binomial);#gender has 2 levels
Hi all:
My data has 3 variables:
age(3levels : 30y=1 30-50y=2, 50y=3)
gender(Male=0, Female=1)
CD4 cell count(raw lab measurement)
y(1:death 0:alive)
I perform logistic regression to find out the factors that influence y.
result-glm(y ~ factor(age) + factor(gender) + CD4,family = binomial)
Hi sir:
I follow your suggestion:
result-glm(y ~ factor(age) + factor(gender) + CD4,family = binomial)
logistic.display(result)
Error in coeff[, 1] : incorrect number of dimensions
At 2011-12-14 01:59:36,Jorge I Velez jorgeivanve...@gmail.com wrote:
Hi there,
Try
According to the example of logistic.display:
model0 - glm(case ~ induced + spontaneous, family=binomial, data=infert)
summary(model0)
logistic.display(model0)
induced: 3levels 0,1,2
spontaneous: 3levels 0,1,2
So if 0 is reference, we should get 2 OR for induced1, induced2,
spontaneous1,
Yes,I¡¡understand.
Thanks for your help.
At 2011-12-14 13:53:21,Virasakdi Chongsuvivatwong cvira...@gmail.com wrote:
logistic.display need a rather tidy model ie all independent variables must be
the original name not any function of a variable in the dataset of the model.
If data1 is your
Yes,it works well.
Thanks for your help.
At 2011-12-14 13:06:14,Jorge I Velez jorgeivanve...@gmail.com wrote:
Hi lm_mengxin,
If that's the case, just use as.factor():
fit - glm(case ~ as.factor(induced) + as.factor(spontaneous),
family=binomial, data=infert)
logistic.display(fit)
Sir:
I find out that for 2 level factor, if I set it to factor, then I'll get
error reply.
For the instance last mail, if I use:
result1-glm(y ~ gender,family = binomial);#gender has 2 levels
logistic.display(result1)
Error in coeff[, 1] : incorrect number of dimensions
if I use:
Hi all:
I perform the linear mixed model for 300 persons, y is CD4 count,x is time.
I randomized slope and intercept,so I can get 300 slopes and 300 intercepts.Now
I wanna test wheter the variance of 300 slopes and 300 intercepts differs from
zero. If the variance of 300 slopes(or intercepts)
Hello sir:
I have a question about the axis label of scatterplot3d function.
The data is in the attachment.
If I use the command:
scatterplot3d(x,y,z,type=h)
I want the plot's x-axis lab to be 1,2,3,...,13, y-axis lab to be 1,2,3,...11
But if I use the command:
Hi all:
I've 2 groups of data,which are measured at:
1990,1991,1992,...2000.
I wanna know whether the trend of 2 groups are same or not.
Maybe time series analysis is suitable,but I don't know which index is fit for
my purpose,and how to get the index from function of time series analysis
As the attachement,I wanna draw multi group plot.
But I can only use :
plot(x,y...)
points(...)
It's a heavy work to use these command if there're too many groups to be drawn
because I have to use point() for many times.
I wanna know wheter there's command which can draw the multigroup
Hi all:
As to the heatmap function, the default style is red and yellow,and red
refers to low level and yellow refers to high level.
How can I change the style to the contrary: red refers to high level and yellow
refers to low level?
Thanks a lot!
My best
[[alternative HTML version
Hi all:
I am a user of JM package.
Here's the problem of sample size.
The warning is:
Error in jointModel(fitLME, fitSURV_death, timeVar = time, method =
piecewise-PH-GH) :
sample sizes in the longitudinal and event processes differ.
According to the suggestion of missing data,I use the
Hell sir:
I'm a user of JM and have a quesion.
As to JM: An R Package for the Joint Modelling of Longitudinal and
Time-to-Event Data, on page14:
fitSURV - coxph(Surv(Time, death) ~ drug, data = aids.id, x = TRUE)
I don't understand why use the dataset aids.id, but notaids as follow:
fitSURV -
Hi all:
I have a question about the command followup.plot of epicale package.
As to the demo data Orthodont, the command followup.plot works well.But if
I delete some rows of data(delete Male data,and keep Female data only, for
instance),the command can't work,and the warning is In
Hi all:
In the growth model (Ref.Multilevel Modeling in R (2.3)),I have a question
about the variance:
On p.73, it says:To model decreasing variance one can use the varExp option.
In cases where variance increases can use the varFixed option (see Pinheiro
Bates, 2000 for details).
My
Hi all:
In the expression:
lme(y~1,random=~1|time)
What ~1 stands for?
Thanks a lot!
[[alternative HTML version deleted]]
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PLEASE do read the posting guide
Hello all:
I've read the document named A Brief Introduction to R, the multilevel package
and the nlme package.
At p68, one can transform the dataset to the required format by using
make.univ.
I wanna know,how the new variable MULTDV is calculated(can you show me the
formula if possible
Hi all:
I finished cox analysis like this:
fit_cox-coxph(Surv(dat$Time, dat$death) ~ dat$CD4 +
strata(dat$gender),data=dat);
fit_cox
Call:
coxph(formula = Surv(data_ori$Time, data_ori$death) ~ data_ori$drug +
strata(data_ori$gender), data = data_ori)
coef exp(coef)
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