Appreciate your thoughts on this Uwe.
If I make any progress with it I will post back.
On Wed, Jun 11, 2014 at 1:43 AM, Uwe Ligges lig...@statistik.tu-dortmund.de
wrote:
On 10.06.2014 16:32, Aidan Corcoran wrote:
thanks Uwe. I have tried a few mirrors, it makes no difference.
I don't
Dear all,
I have a fresh install of R on a virtual desktop running Win 7 64 bit and
when I try to install packages it is extremely slow.
I typed
install.packages(ggplot2,dependencies=TRUE)
and it takes about 1 minute for the mirror select box to open. After that I
waited about 20 minutes for
on a very slow drive (such as a network
connected location).
Best,
Uwe Ligges
On 10.06.2014 15:52, Aidan Corcoran wrote:
Dear all,
I have a fresh install of R on a virtual desktop running Win 7 64 bit and
when I try to install packages it is extremely slow.
I typed
install.packages
/ 3 levels Price,Yield,..: 1 1 1 2 2 2 3 3 3
$ value : num 86.78 86.04 86.44 9.74 9.54 ...
You haven't turned the Date variable into an actual date yet. Try:
g$Date - as.Date(g$Date)
Hadley
On Fri, Jan 6, 2012 at 9:12 AM, Aidan Corcoran
aidan.corcora...@gmail.com wrote:
Dear all
Dear all,
ggplot gives me an error when trying to plot time series data using a
date variable as the x axis.
g-structure(list(Date = c(2011-12-23, 2011-12-30, 2012-01-06,
2011-12-23, 2011-12-30, 2012-01-06, 2011-12-23, 2011-12-30,
2012-01-06), variable = structure(c(1L, 1L, 1L, 2L, 2L, 2L,
3L,
(pdflatex onepager.tex)
(I didn't know about this system command before you mentioned it).
thanks for your help!
Aidan
On Wed, Dec 7, 2011 at 8:07 PM, Duncan Murdoch murdoch.dun...@gmail.com wrote:
On 07/12/2011 12:24 PM, Aidan Corcoran wrote:
Hi Duncan,
thanks for your help. Unfortunately
Dear all,
I'm trying to remove some text after the period (a decimal point) in
the data frame 'hi', below. This is one step in formatting a table. So
I would like e.g.
2.0 to become 2
and 5.3 to be 5.3,
where the variable digordered contains the number of digits after the
decimal that I would
Dear all,
I was hoping someone may know a way of running texi2dvi while ignoring
bibtex errors, or any other work around (such as not running bibtex at
all, if possible).
The context is that I have an R program that does some calculations
and writes a table into various folders, one per country
a more flexible way too; I'd be interested to see it.
Unfortunately I don't think sprintf() has a way to insert a thousands
separator,
or that would be a one-step solution.
Sarah
On Wed, Dec 7, 2011 at 6:05 AM, Aidan Corcoran
aidan.corcora...@gmail.com wrote:
Dear all,
I'm trying to remove
] 10,000. 5.3 1.1
sub(\\.$, , intermediate)
[1] 10,000 5.3 1.1
Sarah
On Wed, Dec 7, 2011 at 8:20 AM, Aidan Corcoran
aidan.corcora...@gmail.com wrote:
Hi Sarah,
apologies for the excess. A smaller example:
f-structure(list(c(GDP per capita (LCU), Ratio to EZ GDP Per Cap
), `2005
:
On 07/12/2011 6:47 AM, Aidan Corcoran wrote:
Dear all,
I was hoping someone may know a way of running texi2dvi while ignoring
bibtex errors, or any other work around (such as not running bibtex at
all, if possible).
The context is that I have an R program that does some calculations
Dear all,
I was hoping someone could help with a ggplot question. I would like
to generate a faceted bar chart, but missing data are causing
problems.
g-structure(list(Date = structure(c(11322, 11687, 12052, 11322,
11687, 12052, 11322, 11687, 12052, 11322, 11687, 12052), class = Date),
= c('red', 'blue')) +
geom_text(aes(x = as.Date('2001-3-31'), y = 1, label = 'NA'),
size = 6) +
opts(legend.position = c(0.87, 0.88),
legend.background = theme_rect(fill = 'white'))
HTH,
Dennis
On Wed, Nov 16, 2011 at 1:55 AM, Aidan Corcoran
aidan.corcora
Dear list,
I encounter an error when I try to use ddply to generate means as follows:
fun3-structure(list(sector = structure(list(gics_sector_name = c(Financials,
Financials, Materials, Materials)), .Names = gics_sector_name,
row.names = structure(c(UBSN VX Equity,
LLOY LN Equity, AI FP Equity,
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